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Tugas Akhir Geometri Transformasi
Dosen Pengampu: Drs. Suhito, M.Pd.
Oleh Kelompok 7
1. Akhmad Faid Murtadlo 4101415012
2. Rena Yuliantika Shora 4101415028
3. Fauzi Badar Bagaskara 4101415050
4. Melati Eka Putri 4101415125
5. Ragil Yunitasari 4101415087
Diketahui :
1. ๐พ๐ฟ sembarang,
2. Garis t sembarang,
3. ๐‘ƒ๐‘„ โˆ•โˆ• ๐‘ก
4. ๐‘’ โŠฅ ๐‘“, ๐‘’ โˆฉ ๐‘“ = {๐ต}
5. ๐‘” โˆฉ โ„Ž = {๐ด}, ๐‘š โˆ ๐‘”, โ„Ž =
1
2
๐œ‘1
K
L
P
Q
B
A
1
2
๐œ‘1
Diketahui
๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘† ๐ต โˆ˜ ๐บ ๐‘ƒ๐‘„ โˆ˜ ๐‘€๐‘ก โˆ˜ ๐บ ๐พ๐ฟ (โ–ณ ๐‘‹๐‘Œ๐‘)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘† ๐ต โˆ˜ ๐บ ๐‘ƒ๐‘„ โˆ˜ ๐‘€๐‘ก (โ–ณ ๐‘‹1 ๐‘Œ1 ๐‘1)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘† ๐ต (โ–ณ ๐‘‹3 ๐‘Œ3 ๐‘3)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘  (โ–ณ ๐‘‹4 ๐‘Œ4 ๐‘4)
= ๐‘… ๐ด,๐œ‘1
(โ–ณ ๐‘‹5 ๐‘Œ5 ๐‘5)
=โ–ณ ๐‘‹6 ๐‘Œ6 ๐‘6
Bukti Langsung
GAMBAR BUKTI LANGSUNG
K
L
๐‘‹
๐‘Œ
๐‘
๐‘‹1
๐‘Œ1
๐‘1
๐‘‹2
๐‘Œ2
๐‘2
P
Q
๐‘‹3
๐‘Œ3 ๐‘3
B
๐‘5
๐‘Œ5
๐‘‹5
๐‘4
๐‘Œ4
๐‘‹4
A
๐‘6
๐‘Œ6
๐‘‹6
1
2
๐œ‘1
Diketahui :
1. ๐‘Ž// ๐‘, ๐‘Ž โŠฅ ๐พ๐ฟ, ๐‘‘ ๐‘Ž,๐‘ =
1
2
๐พ๐ฟ
2. ๐‘//๐‘‘, ๐‘ โŠฅ ๐‘ƒ๐‘„, ๐‘ก//๐‘ƒ๐‘„, ๐‘‘ ๐‘,๐‘‘ =
1
2
๐‘ƒ๐‘„
3. ๐‘’ โŠฅ ๐‘“, ๐‘’ โˆฉ ๐‘“ = {๐ต}
4. ๐‘” โˆฉ โ„Ž = {๐ด}, ๐‘š โˆ ๐‘”, โ„Ž =
1
2
๐œ‘1
K
L
๐‘Ž ๐‘
P
Q
f
B
A
1
2
๐œ‘1
Diketahui
Bukti Tak Langsung
๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘† ๐ต โˆ˜ ๐บ ๐‘ƒ๐‘„ โˆ˜ ๐‘€๐‘ก โˆ˜ ๐บ ๐พ๐ฟ
= ๐‘€โ„Ž โˆ˜ ๐‘€๐‘” โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘€๐‘“ โˆ˜ ๐‘€๐‘’ โˆ˜ ๐‘€ ๐‘‘ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘€๐‘ก โˆ˜ ๐‘€ ๐‘ โˆ˜ ๐‘€ ๐‘Ž __(1)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘€๐‘“ โˆ˜ ๐‘€๐‘’ โˆ˜ ๐‘€ ๐‘‘ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘€๐‘ก โˆ˜ ๐‘€ ๐‘ โˆ˜ ๐‘€ ๐‘Ž______(2)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘… ๐ถ,๐œ‘2
โˆ˜ ๐‘… ๐ท,๐œ‘3
โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘… ๐ธ,๐œ‘4
โˆ˜ ๐‘€ ๐‘Ž_______________(2)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€๐‘— โˆ˜ ๐‘€๐‘— โˆ˜ ๐‘€ ๐‘˜ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘… ๐ธ,๐œ‘4
โˆ˜ ๐‘€ ๐‘Ž_________(3)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘– โˆ˜ ๐ผ โˆ˜ ๐‘€ ๐‘˜ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘… ๐ธ,๐œ‘4
โˆ˜ ๐‘€ ๐‘Ž________________(3)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€ ๐‘˜ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘… ๐ธ,๐œ‘4
โˆ˜ ๐‘€ ๐‘Ž_________________(4)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘… ๐บ,๐œ‘5
โˆ˜ ๐‘… ๐ธ,๐œ‘4
โˆ˜ ๐‘€ ๐‘Ž____________________(4)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€๐‘™ โˆ˜ ๐‘€ ๐‘š โˆ˜ ๐‘€ ๐‘š โˆ˜ ๐‘€ ๐‘› โˆ˜ ๐‘€ ๐‘Ž_____________(5)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€๐‘™ โˆ˜ ๐ผ โˆ˜ ๐‘€ ๐‘› โˆ˜ ๐‘€ ๐‘Ž_____________________(5)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€๐‘™ โˆ˜ ๐‘€ ๐‘› โˆ˜ ๐‘€ ๐‘Ž ____________________(6)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘… ๐ป,๐œ‘6
โˆ˜ ๐‘…๐ฝ,๐œ‘7
__________________________(6)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€ ๐‘œ โˆ˜ ๐‘€ ๐‘ โˆ˜ ๐‘€ ๐‘ โˆ˜ ๐‘€ ๐‘ž ____(7)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€ ๐‘œ โˆ˜ ๐ผ โˆ˜ ๐‘€ ๐‘ž____________(7)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘€ ๐‘œ โˆ˜ ๐‘€ ๐‘ž ____________(8)
= ๐‘… ๐ด,๐œ‘1
โˆ˜ ๐‘… ๐‘€,๐œ‘8
________________(8)
= ๐‘€๐‘Ÿ โˆ˜ ๐‘€ ๐‘ข โˆ˜ ๐‘€ ๐‘ข โˆ˜ ๐‘€๐‘ฃ _________(9)
= ๐‘€๐‘Ÿ โˆ˜ ๐ผ โˆ˜ ๐‘€๐‘ฃ________________(9)
= ๐‘€๐‘Ÿ โˆ˜ ๐‘€๐‘ฃ_________________(10)
= ๐‘… ๐‘,๐œ‘9
___________________(10)
Syarat pada Bukti Tak Langsung
1) ๐‘Ž// ๐‘, ๐‘Ž โŠฅ ๐พ๐ฟ, ๐‘‘ ๐‘Ž,๐‘ =
1
2
๐พ๐ฟ
๏‚— ๐‘//๐‘‘, ๐‘ โŠฅ ๐‘ƒ๐‘„, ๐‘ก//๐‘ƒ๐‘„, ๐‘‘ ๐‘,๐‘‘ =
1
2
๐‘ƒ๐‘„
๏‚— ๐‘’ โŠฅ ๐‘“, ๐‘’ โˆฉ ๐‘“ = {๐ต}
๏‚— ๐‘” โˆฉ โ„Ž = {๐ด}, ๐‘š โˆ ๐‘”, โ„Ž =
1
2
๐œ‘1
2) ๐‘ โˆฉ ๐‘ก = {๐ธ}, ๐‘š โˆ ๐‘, ๐‘ก =
1
2
๐œ‘4
๏‚— ๐‘‘ โˆฉ ๐‘’ = ๐ท , ๐‘š โˆ ๐‘‘, ๐‘’ =
1
2
๐œ‘3
๏‚— ๐‘“ โˆฉ ๐‘  = {๐ถ}, ๐‘š โˆ ๐‘, ๐‘ก =
1
2
๐œ‘2
3) ๐‘— โˆฉ ๐‘– = {๐ถ}, ๐‘š โˆ ๐‘—, ๐‘– =
1
2
๐œ‘2
๏‚— ๐‘˜ โˆฉ ๐‘— = ๐ท , ๐‘š โˆ ๐‘˜, ๐‘— =
1
2
๐œ‘3
4) ๐‘ โˆฉ ๐‘˜ = ๐บ , ๐‘š โˆ ๐‘, ๐‘˜ =
1
2
๐œ‘5
5) ๐‘š โˆฉ ๐‘™ = {๐บ}, ๐‘š โˆ ๐‘š, ๐‘™ =
1
2
๐œ‘5
๏‚— ๐‘› โˆฉ ๐‘š = ๐ธ , ๐‘š โˆ ๐‘š, ๐‘› =
1
2
๐œ‘4
6) ๐‘™ โˆฉ ๐‘– = {๐ป}, ๐‘š โˆ ๐‘™, ๐‘– =
1
2
๐œ‘6
๏‚— ๐‘Ž โˆฉ ๐‘› = ๐ฝ , ๐‘š โˆ ๐‘Ž, ๐‘› =
1
2
๐œ‘7
7) ๐‘ โˆฉ ๐‘œ = {๐ป}, ๐‘š โˆ ๐‘, ๐‘œ =
1
2
๐œ‘6
๏‚— ๐‘ž โˆฉ ๐‘ = ๐ฝ , ๐‘š โˆ ๐‘ž, ๐‘ =
1
2
๐œ‘7
8) ๐‘ž โˆฉ ๐‘œ = ๐‘€ , ๐‘š โˆ ๐‘ž, ๐‘œ =
1
2
๐œ‘8
โ€ข g โˆฉ โ„Ž = ๐ด , ๐‘š โˆ ๐‘”, โ„Ž =
1
2
๐œ‘1
9) ๐‘ข โˆฉ ๐‘Ÿ = {๐ด}, ๐‘š โˆ ๐‘ข, ๐‘Ÿ =
1
2
๐œ‘1
๏‚— ๐‘ฃ โˆฉ ๐‘ข = ๐‘€, ๐‘š โˆ ๐‘ฃ, ๐‘ข =
1
2
๐œ‘8
8) ๐‘ฃ โˆฉ ๐‘Ÿ = {๐‘}, ๐‘š โˆ ๐‘ฃ, ๐‘Ÿ =
1
2
๐œ‘9
GAMBAR BUKTI TAK LANGSUNG
K
L
๐‘‹
๐‘Œ
๐‘
๐‘‹1
๐‘Œ1
๐‘1
๐‘Ž ๐‘
๐‘‹2
๐‘Œ2
๐‘2
P
Q
๐‘‹3
๐‘Œ3 ๐‘3
f
B
๐‘5
๐‘Œ5
๐‘‹5
๐‘4
๐‘Œ4
๐‘‹4
A
๐‘6
๐‘Œ6
๐‘‹6
1
2
๐œ‘1
1
2
๐œ‘5
K
L
๐‘‹
๐‘Œ
๐‘
๐‘Ž ๐‘
P
Q
f
B
A
๐‘6
๐‘Œ6
๐‘‹6
E
D
C
i
G
JH
o
1
2
๐œ‘7
M
1
2
๐œ‘1
N
Proses
Bukti Tak
Langsung
TERIMA KASIH

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  • 1.
  • 2. Tugas Akhir Geometri Transformasi Dosen Pengampu: Drs. Suhito, M.Pd.
  • 3. Oleh Kelompok 7 1. Akhmad Faid Murtadlo 4101415012 2. Rena Yuliantika Shora 4101415028 3. Fauzi Badar Bagaskara 4101415050 4. Melati Eka Putri 4101415125 5. Ragil Yunitasari 4101415087
  • 4. Diketahui : 1. ๐พ๐ฟ sembarang, 2. Garis t sembarang, 3. ๐‘ƒ๐‘„ โˆ•โˆ• ๐‘ก 4. ๐‘’ โŠฅ ๐‘“, ๐‘’ โˆฉ ๐‘“ = {๐ต} 5. ๐‘” โˆฉ โ„Ž = {๐ด}, ๐‘š โˆ ๐‘”, โ„Ž = 1 2 ๐œ‘1
  • 6. ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘† ๐ต โˆ˜ ๐บ ๐‘ƒ๐‘„ โˆ˜ ๐‘€๐‘ก โˆ˜ ๐บ ๐พ๐ฟ (โ–ณ ๐‘‹๐‘Œ๐‘) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘† ๐ต โˆ˜ ๐บ ๐‘ƒ๐‘„ โˆ˜ ๐‘€๐‘ก (โ–ณ ๐‘‹1 ๐‘Œ1 ๐‘1) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘† ๐ต (โ–ณ ๐‘‹3 ๐‘Œ3 ๐‘3) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘  (โ–ณ ๐‘‹4 ๐‘Œ4 ๐‘4) = ๐‘… ๐ด,๐œ‘1 (โ–ณ ๐‘‹5 ๐‘Œ5 ๐‘5) =โ–ณ ๐‘‹6 ๐‘Œ6 ๐‘6 Bukti Langsung
  • 9. Diketahui : 1. ๐‘Ž// ๐‘, ๐‘Ž โŠฅ ๐พ๐ฟ, ๐‘‘ ๐‘Ž,๐‘ = 1 2 ๐พ๐ฟ 2. ๐‘//๐‘‘, ๐‘ โŠฅ ๐‘ƒ๐‘„, ๐‘ก//๐‘ƒ๐‘„, ๐‘‘ ๐‘,๐‘‘ = 1 2 ๐‘ƒ๐‘„ 3. ๐‘’ โŠฅ ๐‘“, ๐‘’ โˆฉ ๐‘“ = {๐ต} 4. ๐‘” โˆฉ โ„Ž = {๐ด}, ๐‘š โˆ ๐‘”, โ„Ž = 1 2 ๐œ‘1
  • 11. Bukti Tak Langsung ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘† ๐ต โˆ˜ ๐บ ๐‘ƒ๐‘„ โˆ˜ ๐‘€๐‘ก โˆ˜ ๐บ ๐พ๐ฟ = ๐‘€โ„Ž โˆ˜ ๐‘€๐‘” โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘€๐‘“ โˆ˜ ๐‘€๐‘’ โˆ˜ ๐‘€ ๐‘‘ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘€๐‘ก โˆ˜ ๐‘€ ๐‘ โˆ˜ ๐‘€ ๐‘Ž __(1) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘  โˆ˜ ๐‘€๐‘“ โˆ˜ ๐‘€๐‘’ โˆ˜ ๐‘€ ๐‘‘ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘€๐‘ก โˆ˜ ๐‘€ ๐‘ โˆ˜ ๐‘€ ๐‘Ž______(2) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘… ๐ถ,๐œ‘2 โˆ˜ ๐‘… ๐ท,๐œ‘3 โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘… ๐ธ,๐œ‘4 โˆ˜ ๐‘€ ๐‘Ž_______________(2) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€๐‘— โˆ˜ ๐‘€๐‘— โˆ˜ ๐‘€ ๐‘˜ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘… ๐ธ,๐œ‘4 โˆ˜ ๐‘€ ๐‘Ž_________(3) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘– โˆ˜ ๐ผ โˆ˜ ๐‘€ ๐‘˜ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘… ๐ธ,๐œ‘4 โˆ˜ ๐‘€ ๐‘Ž________________(3) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€ ๐‘˜ โˆ˜ ๐‘€๐‘ โˆ˜ ๐‘… ๐ธ,๐œ‘4 โˆ˜ ๐‘€ ๐‘Ž_________________(4) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘… ๐บ,๐œ‘5 โˆ˜ ๐‘… ๐ธ,๐œ‘4 โˆ˜ ๐‘€ ๐‘Ž____________________(4) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€๐‘™ โˆ˜ ๐‘€ ๐‘š โˆ˜ ๐‘€ ๐‘š โˆ˜ ๐‘€ ๐‘› โˆ˜ ๐‘€ ๐‘Ž_____________(5) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€๐‘™ โˆ˜ ๐ผ โˆ˜ ๐‘€ ๐‘› โˆ˜ ๐‘€ ๐‘Ž_____________________(5) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€๐‘– โˆ˜ ๐‘€๐‘™ โˆ˜ ๐‘€ ๐‘› โˆ˜ ๐‘€ ๐‘Ž ____________________(6) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘… ๐ป,๐œ‘6 โˆ˜ ๐‘…๐ฝ,๐œ‘7 __________________________(6) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€ ๐‘œ โˆ˜ ๐‘€ ๐‘ โˆ˜ ๐‘€ ๐‘ โˆ˜ ๐‘€ ๐‘ž ____(7) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€ ๐‘œ โˆ˜ ๐ผ โˆ˜ ๐‘€ ๐‘ž____________(7) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘€ ๐‘œ โˆ˜ ๐‘€ ๐‘ž ____________(8) = ๐‘… ๐ด,๐œ‘1 โˆ˜ ๐‘… ๐‘€,๐œ‘8 ________________(8) = ๐‘€๐‘Ÿ โˆ˜ ๐‘€ ๐‘ข โˆ˜ ๐‘€ ๐‘ข โˆ˜ ๐‘€๐‘ฃ _________(9) = ๐‘€๐‘Ÿ โˆ˜ ๐ผ โˆ˜ ๐‘€๐‘ฃ________________(9) = ๐‘€๐‘Ÿ โˆ˜ ๐‘€๐‘ฃ_________________(10) = ๐‘… ๐‘,๐œ‘9 ___________________(10)
  • 12. Syarat pada Bukti Tak Langsung 1) ๐‘Ž// ๐‘, ๐‘Ž โŠฅ ๐พ๐ฟ, ๐‘‘ ๐‘Ž,๐‘ = 1 2 ๐พ๐ฟ ๏‚— ๐‘//๐‘‘, ๐‘ โŠฅ ๐‘ƒ๐‘„, ๐‘ก//๐‘ƒ๐‘„, ๐‘‘ ๐‘,๐‘‘ = 1 2 ๐‘ƒ๐‘„ ๏‚— ๐‘’ โŠฅ ๐‘“, ๐‘’ โˆฉ ๐‘“ = {๐ต} ๏‚— ๐‘” โˆฉ โ„Ž = {๐ด}, ๐‘š โˆ ๐‘”, โ„Ž = 1 2 ๐œ‘1 2) ๐‘ โˆฉ ๐‘ก = {๐ธ}, ๐‘š โˆ ๐‘, ๐‘ก = 1 2 ๐œ‘4 ๏‚— ๐‘‘ โˆฉ ๐‘’ = ๐ท , ๐‘š โˆ ๐‘‘, ๐‘’ = 1 2 ๐œ‘3 ๏‚— ๐‘“ โˆฉ ๐‘  = {๐ถ}, ๐‘š โˆ ๐‘, ๐‘ก = 1 2 ๐œ‘2 3) ๐‘— โˆฉ ๐‘– = {๐ถ}, ๐‘š โˆ ๐‘—, ๐‘– = 1 2 ๐œ‘2 ๏‚— ๐‘˜ โˆฉ ๐‘— = ๐ท , ๐‘š โˆ ๐‘˜, ๐‘— = 1 2 ๐œ‘3 4) ๐‘ โˆฉ ๐‘˜ = ๐บ , ๐‘š โˆ ๐‘, ๐‘˜ = 1 2 ๐œ‘5 5) ๐‘š โˆฉ ๐‘™ = {๐บ}, ๐‘š โˆ ๐‘š, ๐‘™ = 1 2 ๐œ‘5 ๏‚— ๐‘› โˆฉ ๐‘š = ๐ธ , ๐‘š โˆ ๐‘š, ๐‘› = 1 2 ๐œ‘4 6) ๐‘™ โˆฉ ๐‘– = {๐ป}, ๐‘š โˆ ๐‘™, ๐‘– = 1 2 ๐œ‘6 ๏‚— ๐‘Ž โˆฉ ๐‘› = ๐ฝ , ๐‘š โˆ ๐‘Ž, ๐‘› = 1 2 ๐œ‘7 7) ๐‘ โˆฉ ๐‘œ = {๐ป}, ๐‘š โˆ ๐‘, ๐‘œ = 1 2 ๐œ‘6 ๏‚— ๐‘ž โˆฉ ๐‘ = ๐ฝ , ๐‘š โˆ ๐‘ž, ๐‘ = 1 2 ๐œ‘7 8) ๐‘ž โˆฉ ๐‘œ = ๐‘€ , ๐‘š โˆ ๐‘ž, ๐‘œ = 1 2 ๐œ‘8 โ€ข g โˆฉ โ„Ž = ๐ด , ๐‘š โˆ ๐‘”, โ„Ž = 1 2 ๐œ‘1 9) ๐‘ข โˆฉ ๐‘Ÿ = {๐ด}, ๐‘š โˆ ๐‘ข, ๐‘Ÿ = 1 2 ๐œ‘1 ๏‚— ๐‘ฃ โˆฉ ๐‘ข = ๐‘€, ๐‘š โˆ ๐‘ฃ, ๐‘ข = 1 2 ๐œ‘8 8) ๐‘ฃ โˆฉ ๐‘Ÿ = {๐‘}, ๐‘š โˆ ๐‘ฃ, ๐‘Ÿ = 1 2 ๐œ‘9
  • 13. GAMBAR BUKTI TAK LANGSUNG