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2. PARTE EXPERIMENTAL
3.1. Material y Equipos
3.1.1. Soporte Universal
3.1.2. Pipeta volumétrica R: 10 mL A ± 1 mL
3.1.3. Pera de succión
3.1.4. Vasos de precipitación R: 1000 mL A ± 100 mL
3.1.5. Agitador
3.1.6. Fuente de poder de 12 VDC
3.1.7. Reactor electroquímico V=250ml
3.1.8. Cronómetro R: 900 s A ± 1 s
3.1.9. Pie de Rey R:170 mm A ± 0.1 mm
3.1.10. Espectrofotómetro HACH DR 900
3.2. Sustancias y reactivos
3.2.1. Electrodos de Acero alcarbón
3.2.2. Reactivo HACH Chlorhyde
3.2.3. Agua destilada H2O(l)
3.2.4. Suero de solución salina
3.3. Procedimiento
3.3.1. Armar el equipo
3.3.2. Llenar el reactor electroquímico
3.3.3. Introducir los electrodos de grafito
3.3.4. Introducir y encender el agitador
3.3.5. Regular el caudal de entrada y de salida de tal modo que el flujo a la entrada y a la
salida del reactor sea el mismo.
3.3.6. Conectar los electrodos a la fuente.
3.3.7. Regular la fuente a 9.2 V y 0.45 A
3.3.8. Esperar 15 minutos, tomar una muestra de 10 ml, diluirla en 300 ml, posteriormente
medir en el equipo HACH.
3.3.9. Repetir el paso 3.3.9. durante 6 veces.
3.3.10. Apagar la fuente, desconectar los electrodos, desarmar el equipo.
3.3.11. Tomar las medidas del área mojada de los electrodos, con la ayuda del pie de rey.
4. DATOS
4.1. Datos Experimentales
Tabla 4.1-1. Datos experimentales
Variable Valor Unidad
Qv 0.216 L/h
Co(NaCl) 0.9 %
L (electrodo 1) 59.41 mm
Diámetro (electrodo 1) 6.7 mm
L (electrodo 2) 49.48 mm
Diámetro (electrodo 2) 6.74 mm
Diámetro agitador 22.44 mm
Velocidad del agitador 70 rpm
Tabla 4.1-2. Datos Obtenidos
Tiempo Concentración Intensidad Voltaje
min mg/L A V
Salida
15 3 0.45 9.2
30 2.9 0.47 9.2
45 3.6 0.45 9.2
60 3.8 0.46 9.2
75 4.4 0.46 9.2
90 5.3 0.39 9.2
5. CÁLCULOS
5.1.Cálculo de la concentración inicial de Cloro. (mg/l) Nota: partir de 0.9% de
NaCl o 154 mEq Cl-
𝑚𝐸𝑞 =
𝑃𝑀
𝐸𝑞
0,9
𝑚𝑔
𝐿
𝑁𝑎𝐶𝑙
%
𝑃
𝑃
=
𝑀𝑎𝑠𝑎 𝑠𝑜𝑙𝑢𝑡𝑜
𝑀𝑎𝑠𝑎 𝑑𝑒 𝑠𝑜𝑙𝑢𝑐𝑖ó𝑛
∗ 100 (1)
9 ∗ 10−3
=
𝑀𝑎𝑠𝑎 𝑠𝑜𝑙𝑢𝑡𝑜
25𝑂 𝑚𝐿
𝑀𝑠𝑜𝑙𝑢𝑡𝑜 = 2,25 𝑔 𝑁𝑎𝐶𝑙 ≈ 2250 𝑚𝑔 𝑁𝑎𝑐𝑙
𝐶𝐴𝐸 =
2250 𝑚𝑔
0,25 𝐿
𝐶𝐴𝐸 = 9000
𝑚𝑔
𝐿
𝐶𝐴𝐸 = 9000
𝑚𝑔
𝐿
1000𝐿
1 𝑚3 = 9000000
𝑚𝑔
𝑚3
5.2.Cálculo de área total de electrodo (m2)
 Área Electrodo 1
𝐴1 = 𝜋 ∗ 𝑙 ∗ 𝑟 (2)
𝐴1 = 𝜋 ∗ 0,05941 𝑚 ∗ 0,03525𝑚
𝐴1 = 6,5791 𝑥 10−3
𝑚2
 Área Electrodo 2
𝐴2 = 𝜋 ∗ 𝑙 ∗ 𝑟
𝐴2 = 𝜋 ∗ 0,04948 𝑚 ∗ 0,03567 𝑚
𝐴2 = 5,5447 𝑥 10−3
𝑚2
 Área Total
𝐴𝑡𝑜𝑡𝑎𝑙 = 𝐴1 + 𝐴2 (3)
𝐴𝑡𝑜𝑡𝑎𝑙 = (6,5791 𝑥 10−3
𝑚2) + (5,5447 𝑥 10−3
𝑚2
)
𝐴𝑡𝑜𝑡𝑎𝑙 = 0,01212𝑚2
5.3.Cálculo kd prom (m/s)
𝐶𝐴𝑆−𝑝𝑟𝑜𝑚𝑒𝑑𝑖𝑜 = CAS1+CAS2+CAS3+CAS4+CAS5+CAS6
6
(4)
𝐶𝐴𝑆−𝑝𝑟𝑜𝑚𝑒𝑑𝑖𝑜 = 3+2,9+3,6+3,8+4,4+5,3
6
𝐶𝐴𝑆−𝑝𝑟𝑜𝑚𝑒𝑑𝑖𝑜 = 3,8333
𝑚𝑔
𝐿
𝐶𝐴𝑆−𝑝𝑟𝑜𝑚𝑒𝑑𝑖𝑜 = 3833,33
𝑚𝑔
𝑚3
𝐾𝑑
̅̅̅̅ =
𝑄𝑉 ∗(𝐶𝐴𝐸 −𝐶𝐴𝑆 )
𝐴𝑒∗𝐶𝐴𝑆
(5)
𝐾𝑑
̅̅̅̅ =
(0,216
𝐿
ℎ
∗
1ℎ
3600 𝑠
∗
1 𝑚3
103 𝐿
)∗(9000000 −3833 ,33)
𝑚𝑔
𝑚3
0,01212 𝑚2 ∗3833,33
𝑚𝑔
𝑚3
𝐾𝑑
̅̅̅̅ = 0,01162
𝑚
𝑠
5.4.Cálculo Xa
𝑋𝐴 = 1 − [
1
1+
𝐾𝑑
̅̅̅̅̅∗ 𝐴𝑒
𝑄𝑉
] (6)
𝑋𝐴 = 1 −
[
1
1+
0,01162
𝑚
𝑠
∗0,01212𝑚2
(0,216
𝐿
ℎ
∗
1ℎ
3600 𝑠
∗
1 𝑚3
103
)
]
𝑋𝐴 = 0,99957
5.5. Cálculo rendimiento farádico Rf
(7)
𝑅𝑓 =
𝐾𝑑
̅̅̅̅̅∗ 𝐴𝑒∗𝐶𝐴𝑆 ∗𝑉𝑒∗𝐹
|𝐼|
𝑅𝑓 =
0,01162
𝑚
𝑠
∗ 0,01212𝑚2
∗(3833,33
𝑚𝑔
𝑚3∗
1 𝑚𝑜𝑙 𝑁𝑎𝐶𝑙
58500 𝑚𝑔
)∗2∗96500
𝐶
𝑚𝑜𝑙
9,2
𝐶
𝑠
𝑅𝑓 = 0,19359
6. RESULTADOS
Tabla 6.1-1. Resultados
Concentración
inicial
CAE,
mg
L
Área total
m2
Coeficiente de
transporte de masa
Kd
̅̅̅̅,
m
s
Tasa de
conversión
XA
Rendimiento
farádico
Rf
9000 1,149 x 10−3 m2 0,123 0,99957 0,19359
Fuente. Grupo 10, Universidad Central del Ecuador, Faculta de Ingeniería Química,
Laboratorio de Electroquímica

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Cálculos 2

  • 1. 2. PARTE EXPERIMENTAL 3.1. Material y Equipos 3.1.1. Soporte Universal 3.1.2. Pipeta volumétrica R: 10 mL A ± 1 mL 3.1.3. Pera de succión 3.1.4. Vasos de precipitación R: 1000 mL A ± 100 mL 3.1.5. Agitador 3.1.6. Fuente de poder de 12 VDC 3.1.7. Reactor electroquímico V=250ml 3.1.8. Cronómetro R: 900 s A ± 1 s 3.1.9. Pie de Rey R:170 mm A ± 0.1 mm 3.1.10. Espectrofotómetro HACH DR 900 3.2. Sustancias y reactivos 3.2.1. Electrodos de Acero alcarbón 3.2.2. Reactivo HACH Chlorhyde 3.2.3. Agua destilada H2O(l) 3.2.4. Suero de solución salina 3.3. Procedimiento 3.3.1. Armar el equipo 3.3.2. Llenar el reactor electroquímico 3.3.3. Introducir los electrodos de grafito 3.3.4. Introducir y encender el agitador 3.3.5. Regular el caudal de entrada y de salida de tal modo que el flujo a la entrada y a la salida del reactor sea el mismo. 3.3.6. Conectar los electrodos a la fuente. 3.3.7. Regular la fuente a 9.2 V y 0.45 A 3.3.8. Esperar 15 minutos, tomar una muestra de 10 ml, diluirla en 300 ml, posteriormente medir en el equipo HACH. 3.3.9. Repetir el paso 3.3.9. durante 6 veces. 3.3.10. Apagar la fuente, desconectar los electrodos, desarmar el equipo. 3.3.11. Tomar las medidas del área mojada de los electrodos, con la ayuda del pie de rey. 4. DATOS
  • 2. 4.1. Datos Experimentales Tabla 4.1-1. Datos experimentales Variable Valor Unidad Qv 0.216 L/h Co(NaCl) 0.9 % L (electrodo 1) 59.41 mm Diámetro (electrodo 1) 6.7 mm L (electrodo 2) 49.48 mm Diámetro (electrodo 2) 6.74 mm Diámetro agitador 22.44 mm Velocidad del agitador 70 rpm Tabla 4.1-2. Datos Obtenidos Tiempo Concentración Intensidad Voltaje min mg/L A V Salida 15 3 0.45 9.2 30 2.9 0.47 9.2 45 3.6 0.45 9.2 60 3.8 0.46 9.2 75 4.4 0.46 9.2 90 5.3 0.39 9.2 5. CÁLCULOS 5.1.Cálculo de la concentración inicial de Cloro. (mg/l) Nota: partir de 0.9% de NaCl o 154 mEq Cl- 𝑚𝐸𝑞 = 𝑃𝑀 𝐸𝑞 0,9 𝑚𝑔 𝐿 𝑁𝑎𝐶𝑙 % 𝑃 𝑃 = 𝑀𝑎𝑠𝑎 𝑠𝑜𝑙𝑢𝑡𝑜 𝑀𝑎𝑠𝑎 𝑑𝑒 𝑠𝑜𝑙𝑢𝑐𝑖ó𝑛 ∗ 100 (1) 9 ∗ 10−3 = 𝑀𝑎𝑠𝑎 𝑠𝑜𝑙𝑢𝑡𝑜 25𝑂 𝑚𝐿 𝑀𝑠𝑜𝑙𝑢𝑡𝑜 = 2,25 𝑔 𝑁𝑎𝐶𝑙 ≈ 2250 𝑚𝑔 𝑁𝑎𝑐𝑙 𝐶𝐴𝐸 = 2250 𝑚𝑔 0,25 𝐿 𝐶𝐴𝐸 = 9000 𝑚𝑔 𝐿 𝐶𝐴𝐸 = 9000 𝑚𝑔 𝐿 1000𝐿 1 𝑚3 = 9000000 𝑚𝑔 𝑚3
  • 3. 5.2.Cálculo de área total de electrodo (m2)  Área Electrodo 1 𝐴1 = 𝜋 ∗ 𝑙 ∗ 𝑟 (2) 𝐴1 = 𝜋 ∗ 0,05941 𝑚 ∗ 0,03525𝑚 𝐴1 = 6,5791 𝑥 10−3 𝑚2  Área Electrodo 2 𝐴2 = 𝜋 ∗ 𝑙 ∗ 𝑟 𝐴2 = 𝜋 ∗ 0,04948 𝑚 ∗ 0,03567 𝑚 𝐴2 = 5,5447 𝑥 10−3 𝑚2  Área Total 𝐴𝑡𝑜𝑡𝑎𝑙 = 𝐴1 + 𝐴2 (3) 𝐴𝑡𝑜𝑡𝑎𝑙 = (6,5791 𝑥 10−3 𝑚2) + (5,5447 𝑥 10−3 𝑚2 ) 𝐴𝑡𝑜𝑡𝑎𝑙 = 0,01212𝑚2 5.3.Cálculo kd prom (m/s) 𝐶𝐴𝑆−𝑝𝑟𝑜𝑚𝑒𝑑𝑖𝑜 = CAS1+CAS2+CAS3+CAS4+CAS5+CAS6 6 (4) 𝐶𝐴𝑆−𝑝𝑟𝑜𝑚𝑒𝑑𝑖𝑜 = 3+2,9+3,6+3,8+4,4+5,3 6 𝐶𝐴𝑆−𝑝𝑟𝑜𝑚𝑒𝑑𝑖𝑜 = 3,8333 𝑚𝑔 𝐿 𝐶𝐴𝑆−𝑝𝑟𝑜𝑚𝑒𝑑𝑖𝑜 = 3833,33 𝑚𝑔 𝑚3 𝐾𝑑 ̅̅̅̅ = 𝑄𝑉 ∗(𝐶𝐴𝐸 −𝐶𝐴𝑆 ) 𝐴𝑒∗𝐶𝐴𝑆 (5) 𝐾𝑑 ̅̅̅̅ = (0,216 𝐿 ℎ ∗ 1ℎ 3600 𝑠 ∗ 1 𝑚3 103 𝐿 )∗(9000000 −3833 ,33) 𝑚𝑔 𝑚3 0,01212 𝑚2 ∗3833,33 𝑚𝑔 𝑚3 𝐾𝑑 ̅̅̅̅ = 0,01162 𝑚 𝑠 5.4.Cálculo Xa 𝑋𝐴 = 1 − [ 1 1+ 𝐾𝑑 ̅̅̅̅̅∗ 𝐴𝑒 𝑄𝑉 ] (6)
  • 4. 𝑋𝐴 = 1 − [ 1 1+ 0,01162 𝑚 𝑠 ∗0,01212𝑚2 (0,216 𝐿 ℎ ∗ 1ℎ 3600 𝑠 ∗ 1 𝑚3 103 ) ] 𝑋𝐴 = 0,99957 5.5. Cálculo rendimiento farádico Rf (7) 𝑅𝑓 = 𝐾𝑑 ̅̅̅̅̅∗ 𝐴𝑒∗𝐶𝐴𝑆 ∗𝑉𝑒∗𝐹 |𝐼| 𝑅𝑓 = 0,01162 𝑚 𝑠 ∗ 0,01212𝑚2 ∗(3833,33 𝑚𝑔 𝑚3∗ 1 𝑚𝑜𝑙 𝑁𝑎𝐶𝑙 58500 𝑚𝑔 )∗2∗96500 𝐶 𝑚𝑜𝑙 9,2 𝐶 𝑠 𝑅𝑓 = 0,19359 6. RESULTADOS Tabla 6.1-1. Resultados Concentración inicial CAE, mg L Área total m2 Coeficiente de transporte de masa Kd ̅̅̅̅, m s Tasa de conversión XA Rendimiento farádico Rf 9000 1,149 x 10−3 m2 0,123 0,99957 0,19359 Fuente. Grupo 10, Universidad Central del Ecuador, Faculta de Ingeniería Química, Laboratorio de Electroquímica