Name the Standard that defines and sets the rules for Geometric Dimen.pdf

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My question is how they got kL=1 The table says kl =10 If they got it from the figure please explain Solution If you can see the figure as the values of Kl decreases exponentially as the gate is fully open. But there will always be a minor loss hence they have approximated the value as 1 from the graph. And the table gives you r=the values based on various conditions like global fully open or angle fully open. Since any of those conditions are not specified in the question we take the value from graph..

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Name the Standard that defines and sets the rules for Geometric Dimensioning and Tolerancing.
Include the specific year.
Solution
The international standard that defines geometrical dimensioning and tolerancing is ISO
1101(2012 E). ISO 1101 was prepared by ISO/Technical Committee 213.The latest revised
version was released on year 2012.

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You are conducting a study to see if students do better when they study all at once or in intervals. One group of 12 participants took a test after studying for one hour continuously. The other group of 12 participants took a test after studying for three twenty minute sessions. The first group had a mean score of75 and a variance of 120. The second group had a mean score of 86 and a variance of 100. a. What is the calculated t value? Are the mean test scores of these two groups significantly different at the .05 level? b. What would the t value be if there were only 6 participants in each group? Would the scores be significant at the .05 level? Solution A) Formulating the null and alternative hypotheses, Ho: u1 - u2 = 0 Ha: u1 - u2 =/ 0 At level of significance = 0.05 As we can see, this is a two tailed test. Calculating the means of each group, X1 = 75 X2 = 86 Calculating the standard deviations of each group, s1 = 10.95445115 s2 = 10 Thus, the standard error of their difference is, by using sD = sqrt(s1^2/n1 + s2^2/n2): n1 = sample size of group 1 = 12 n2 = sample size of group 2 = 12 Thus, df = n1 + n2 - 2 = 22 Also, sD = 4.281744193 Thus, the t statistic will be t = [X1 - X2 - uD]/sD = -2.569046516 [ANSWER, T VALUE] ******************************** b) Calculating the means of each group, X1 = 75 X2 = 86 Calculating the standard deviations of each group, s1 = 10.95445115 s2 = 10 Thus, the standard error of their difference is, by using sD = sqrt(s1^2/n1 + s2^2/n2): n1 = sample size of group 1 = 6 n2 = sample size of group 2 = 6 Also, sD = 6.055300708 Thus, the t statistic will be t = [X1 - X2 - uD]/sD = -1.816590212 [ANSWER] For part A, the P value is p = 0.01750305 For part B, the P value is p = 0.099328388 Hence, Part A would be significant, but part B wouldn\'t. [ANSWER] ********************************** ***************************************************** Hi! If you use another method/formula in calculating the degrees of freedom in this t-test, please resubmit this question together with the formula/method you use in determining the degrees of freedom. That way we can continue helping you! Thanks! ********************************************.

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Name the Standard that defines and sets the rules for Geometric Dimen.pdf

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