There is a water container separated by a semipermeable membrane in the middle. KCl (40mM) has been dissolved in a half [Side I] of the container. Given that this membrane is permeable to K+ and Cl. What are concentrations of K+ and Cl^- in the other half [Side II] of the container at the equilibrium? If 10mM KA, a potassium salt, is added to Side I, what are concentrations of K+, Cl^- in both sides? Given that the membrane is non-permeable to ionized A- proteins. What is this phenomenon called? Also define it with your own words. Solution Please find the answers below: Part a) According to the information, the membrane is permeable to potassium and chloride ions. This suggests that addition of 40mM of KCl on one side of the containes will lead to slow movement of ions towards the other side of the container as well owing to permeability of membrane to these ions. Thus, movement of ions from side I will take place to the side II until the concentration of ions reaches equilibrium to both sides. The concentrations of K+ and Cl- will be similar on both sides of teh container at equilibrium. Part b) Since the membrane is impermeable to A- ions, they will not move in the container from side I to side II and remain trapped in side I only. However, since the membrane is permeable to K+ ions, they will again move from side I of the container to side II until equilibrium is achieved with respect to K+ ions on both sides of the container. Part c) It can be clearly seen from the data that the membrane is permeable to some materials but not to others. However, since equilibrium is achieved after some time of addition of the ions, it also suggests that movement of solute takes place freely across this membrane. This phenomenon is called OSMOSIS. Technically, osmosis is defined as movement of particles across a semi-permeable membrane to achieve equilibrium of solutes across the containers..