In this project, we are required to group in six and choose a house of 3 storey high to do structural framing. We have to determine the positioning of beams and columns in the house. Then from the group of 6, we are divided into 2 persons in a group to make the extension to the house of which the extension could not be more that one third of the house. After this, we are required to calculate the load acting on the beams and columns based on the framing we have designed for the extension.

1. BUILDING STRUCTURE (ARC 2552/2523)
PROJECT 2: EXTENSION OF A R.C BUNGALOW
(Individual Proposal)
NAME: CHUAH SAY YIN
STUDENT ID: 0315301
LECTURER: MS. ANN

2. *The type of floor slab and beam installed in the extension is of concrete, whereas wall is brick wall
(exterior and partitions) and glass wall (partitions).
DEAD LOAD
One-Way Slab
24kN/m³x 0.15m = 3.6kN/m²
3.6kN/m²x Lx/2
(L=shorter length)
Two Way Slab
Load transferred in trapezoidal way
24kN/m³x 0.15m = 3.6kN/m²
3.6kN/m²x Lx/2
(Lx=shorter length)
Load transferred in triangular way (apply factor of 2/3)
24kN/m³x 0.15m = 3.6kN/m²
3.6kN/m²x Lx/2 x 2/3
(Lx=shorter length)
Brick Wall
19kN/m³x 3.5m x 0.15m = 9.98kN/m
COMPONENT THICKNESS
(m)
Slab 0.15
Ground Beam 0.45
First Floor Beam 0.30
Roof Beam 0.30
Column 3.5
MATERIALS DENSITY
(kN/m³)
Concrete 24
Brick 19
Glass 0.17

3. Beam
Ground Beam
24kN/m³x 0.15m x 0.45m= 1.62kN/m
First Floor Beam & Roof Beam
24kN/m³x 0.15m x 0.3m= 1.08kN/m
Glass Wall
0.17 kN/m³x 0.05m x 3.5m = 0.03 kN/m
LIVE LOAD
One-way Slab
Load Factor x Lx/2
(Lx=shorter length)
Two-way Slab
Load transferred in trapezoidal form
Load Factor x Lx/2
(Lx=shorter length)
Load transferred in triangular form, apply factor of 2/3
Load Factor x Lx/2 x 2/3
(Lx=shorter length)
SPACES LOAD FACTOR
(kN/m²)
Gym 4.0
Spa 4.0
Library 2.5
Studio 2.0
Balcony 1.5
Roof (Dead Load) 1.0
Roof (Live Load) 0.5