what are ethical implications of not paying your fair share of tax.pdf

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what are ethical implications of not paying your fair share of tax Solution Tax avoidance is obviously is a deceptive conduct of substance or people, yet tax shirking is gives an obscured picture. The nation anticipates that organizations will pay \"what\'s coming to them\" of tax so open products can be accessible for general society to utilize. Ethically and morally, two ideas come in light of our human instinct, is it wrong to lie or is it wrong to take. All as a whole have diverse view on this and it depend circumstance in which we are taking a gander at this ideas. Some can say is it wrong to stay away from tax on the off chance that we know we have to pay tax and is it wrong to avoid tax. Organization chiefs contend, nonetheless, that their duty is to expand the esteem that they convey for their investors and that incorporates keeping tax expenses to a base inside the domains of what is lawful. Beside company tax, organizations ought to be recognized as adding to the economy in different ways..

what are ethical implications of not paying your fair share of tax
Solution
Tax avoidance is obviously is a deceptive conduct of substance or people, yet tax shirking is
gives an obscured picture. The nation anticipates that organizations will pay "what's coming to
them" of tax so open products can be accessible for general society to utilize. Ethically and
morally, two ideas come in light of our human instinct, is it wrong to lie or is it wrong to take.
All as a whole have diverse view on this and it depend circumstance in which we are taking a
gander at this ideas. Some can say is it wrong to stay away from tax on the off chance that we
know we have to pay tax and is it wrong to avoid tax. Organization chiefs contend, nonetheless,
that their duty is to expand the esteem that they convey for their investors and that incorporates
keeping tax expenses to a base inside the domains of what is lawful. Beside company tax,
organizations ought to be recognized as adding to the economy in different ways.

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LOS At the time of her death on September 4, 2015, Alicia held the following assets. Bonds of Emerald Tool Corporation Stock in Drab Corporation Insurance policy (face amount of $400,000) Fair Market Value $ 900,000 1,100,000 on the life of her father, Mitch Traditional IRAs *Cash surrender value. 80,000* 300,000 Alicia was also the life tenant of a trust (fair market value of $2 million) created by her late husband Bert. (The executor of Bert\'s estate had made a QTIP election.) In October, Alicia\'s estate received an interest payment of $11,500 ($6,000 accrued before September 4, 2015) paid by Emerald and a cash dividend of $9,000 from Drab. The Drab dividend was declared on August 19 and was payable to date of re- cord shareholders on September 3, 2015. Although Mitch survives Alicia, she is the designated beneficiary of the policy. The IRAs are distributed to Alicia\'s children. What amount is included in Alicia\'s gross estate? Solution Alicia’s Gross Estate:- Bonds of Emrald Tool Corporation - 900,000 Interest on Emrald Tool Bonds – 11,500…………..(accrued interest is to be included ) Stock in Drab Corporation - 1,100,000 Cash Dividend – 9,000 Insurance Policy – 80,000 ……….( Cash surrender value) Traditional IRA – 300,000 Value of Trust – 2,000,000 Thus, Total asset – 4,400,500.

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JAVA...W\'i\'t\'h N.E.T_B.E.A.N.S_______________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________ ____________________________________________________ ***********Product********************* package rooster.nest; import java.text.NumberFormat; public class Product { private long id; private String code; private String description; private double price; public long getId() { return id; } public void setId(long id) { this.id = id; } public String getCode() { return code; } public void setCode(String code) { this.code = code; } public String getDescription() { return description; } public void setDescription(String name) { this.description = name; } public double getPrice() { return price; } public void setPrice(double price) { this.price = price; } public String getPriceFormatted() { NumberFormat currencyFormatter = NumberFormat.getCurrencyInstance(); return currencyFormatter.format(getPrice()); } } ********DBException************ package crows.foot; /* * This is just a wrapper class so we can throw a common exception for * the UI to catch without tightly coupling the UI to the database layer. */ public class DBException extends Exception { DBException() {} DBException(Exception e) { super(e); } } *******DBUtil************ package crows.foot; import java.sql.Connection; import java.sql.DriverManager; import java.sql.SQLException; public class DBUtil { private static Connection connection; private DBUtil() {} public static synchronized Connection getConnection() throws DBException { if (connection != null) { return connection; } else { try { // set the db url, username, and password String url = \"jdbc:mysql://localhost:3306/mma\"; String username = \"mma_user\"; String password = \"sesame\"; // get and return connection connection = DriverManager.getConnection( url, username, password); return connection; } catch (SQLException e) { throw new DBException(e); } } } public static synchronized void closeConnection() throws DBException { if (connection != null) { try { connection.close(); } catch (SQLException e) { throw new DBException(e); } finally { connection = null; } } } } *************ProductDB************** package crows.foot; import java.sql.Connection; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; import java.util.ArrayList; import java.util.List; import rooster.nest.Product; public class ProductDB { private static Product getProductFromRow(ResultSet rs) throws SQLException { int productID = rs.getInt(1); String code = rs.getString(2); String description = rs.getString(3); double price = rs.getDouble(4); String note = rs.getString(5); Product p = new Product(); p.setId(productID); p.setCode(code); p.setDescription(description); p.setPrice(price); return p; } public static List getAll() throws DBException { String sql = \"SELECT * FROM Product.

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Let us roll a die twice. The number from the first throw is denoted by X1 and the number from the second throw is denoted by X2. Let us define a new variable Y by Y(x1+x2-5)^2. * Make a table that shows all cases of Y with their probabilities. * What is the expectation value of Y, i.e. E[Y]? * Obtain the variance of Y, V[Y]. Solution Let us roll a die twice. The number from the first throw is denoted by X1 and the number from the second throw is denoted by X2. Let us define a new variable Y by Y(x1+x2-5)^2. * Make a table that shows all cases of Y with their probabilities. * What is the expectation value of Y, i.e. E[Y]? * Obtain the variance of Y, V[Y]. We can use the following: Sum of two die Probability 2 1/36 3 2/36 = 1/18 4 3/36 = 1/12 5 4/36 = 1/9 6 5/36 7 6/36 = 1/6 8 5/36 9 4/36 = 1/9 10 3/36 = 1/12 11 2/36 = 1/18 12 1/36 Total 36/36 sum of dice y p y^2 y*p y^2*p 2 9 1/36 81 0.25 2.25 3 4 1/18 16 0.222222 0.888889 4 1 1/12 1 0.083333 0.083333 5 0 1/9 0 0 0 6 1 5/36 1 0.138889 0.138889 7 4 1/6 16 0.666667 2.666667 8 9 5/36 81 1.25 11.25 9 16 1/9 256 1.777778 28.44444 10 25 1/12 625 2.083333 52.08333 11 36 1/18 1296 2 72 12 49 1/36 2401 1.361111 66.69444 sums: 1 9.833333 236.5 To get the y column, subtract 5 from the sum column and then square. The second column and the third column of this table show the possible values of y and their probabilities. E(Y) and V(Y) are calculated using the sums in the last row of this table. E(Y) = 9.8333 Sum of two die Probability 2 1/36 3 2/36 = 1/18 4 3/36 = 1/12 5 4/36 = 1/9 6 5/36 7 6/36 = 1/6 8 5/36 9 4/36 = 1/9 10 3/36 = 1/12 11 2/36 = 1/18 12 1/36 Total 36/36.

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calderoncasto9163

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calderoncasto9163

Describe the difference between a. The pulmonary and systemic circulation b. An artery and a vein c. An atrium and a ventricle Solution a. Pulmonary and systemic circulation The cardiovascular system comprise of two circulatory pathsways namely pulmonary and sytemic circulation.The pulmonary circulation circuits through the lungs carrying the oxygenated blood whereas the systemic circulation circuit through the rest of the body to provide oxygenated blood to various body parts. In the pulmonary circulation, blood travels through capillaries on the alveoli, air sacs in the lungs allowing the gas exchange. Here, as blood flows, the size of the vessel decreases from artery to arteriole, from vein to venuleand finally to capillaries,which serve as vessels for gas and nutrient exchange.In the systemic circulation,the movement of blood takes place from the heart through the body providing oxygen and nutrients to the tissues of the body while bringing back the deoxygenated to the heart. Systemic and pulmonary circulation transition to the opposite to each other. Systemic circulation is a much larger and higher pressure system than pulmonary circulation. Thus systemic circulation is the larger path that blood takes on, routing oxygenated blood around the tissues of the body and deoxygenated blood from them back to the heart , while pulmonary circulation is the smaller loop that blood takes in the lungs. b. An artery and a Vein Blood is circulated in the body through arteries, veins and capillaries in a closed circulatory system. All blood vessels leading from heart carrying oxygenated blood (except pulmonary artery) to various organs of the body are called as arteries. Whereas, vessels which carry deoxygenated blood (except pulmonary vein) from various organs of the body to the heart are called as veins. Arteries have thick elastic muscular walls and valves are absent, whereas, Veins have thin non- elastic valves and valves are present to prevent bacl flow of blood. c. An atrium and a Ventricle There are 4 chambers in the heart; the atria refer to the upper chambers while the ventricles refer to the lower chambers. Atria (atrium) refers to the upper chambers of the heart that receive the impure blood from the veins to send it to the ventricles. Ventricles are small cavities or chambers that are present within the left chamber of the heart that accepts blood from the arteries (left atrium) and then contracts to force into the aorta. Both right and the left part of our heart has an atrium and one ventricle. The walls of the ventricles are thicker, while that of the atria are thinner. They ventricles contain valves to pump the blood in and out of the heart..

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calderoncasto9163

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calderoncasto9163

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Choose a deployment platform that allows for the implementation of SOA. Describe the architectural layers that are included in the platform and analyze the flexibility of the platform for supporting different types of services. Determine whether this platform supports loose coupling or if it is strongly implementation dependent. Choose a deployment platform that allows for the implementation of SOA. Describe the architectural layers that are included in the platform and analyze the flexibility of the platform for supporting different types of services. Determine whether this platform supports loose coupling or if it is strongly implementation dependent. Solution Service-oriented architectures (SOA) are based on the software services, which are high-level software components that include web services like (Rest , Soap). Implementation of an SOA requires tools and run-time infrastructure software. This is collectively referred to as a service- oriented architecture implementation framework or (SOAIF). Application development and deployment : In the traditional software development process, translating the requirements into working distributed systems is time-consuming and difficult, requiring several stages of manual development and then its deployment. This complex, error-friendlytask can be effectively done using a higher-level, component-based SOAIF. The SOAIF incorporates tools that let processes that are developed, using standards such as Business Process Execution Language (BPEL), can be easily translated into distributed, high-level services, which are easy to develop, manipulate, and debug and hence more effecient . These services are easily composed of implementation- level data flows without the user or developer having to track complex middleware concepts, such as topics or queues. Further, the implementation-level services can run on any machine across the network due to the built-in dynamic deployment support SOAIF provides. Architectural Layers Enterprise service bus :core infrastructure of an SOAIF is typically provided by an enterprise service bus (ESB), which points out the challenges in composing, deploying, and managing distributed, service-based enterprise applications. The ESB incorporates systems connectivity using web services, Java EE, .NET Framework, and other standards also ESB also do not provide any guaranty of loose coupling to meet evolving Service-oriented needs . Implementing ESB to meet SOA requirements require the addition of extra functionality to compose for business Services and provide secure Service interactions. Business process management : Business process management (BPM) considers systems and IT assets as activities or tasks that participate in well-coordinated and centrally organised Business processes. Traditionally, the challenge of BPM is that while it is possible to construct any processes that achieve integration goals, enterprises typically use BPM tools only at the time of designing , modeling.

Choose a deployment platform that allows for the implementation o.pdf

Choose a deployment platform that allows for the implementation o.pdf

Choose a deployment platform that allows for the implementation o.pdf

calderoncasto9163

Abstract Base Class (C++ Program) Create an abstract base class called Animal which has the following pure virtual member functions: talk( ), move( ) and the following attribute: animalType (which is a pointer to a dynamically allocated string.) Then create the following derived classes (from the animal class): reptile, bird, and mammal. Here are the concrete classes: From the reptile class derive lizard and snake. From bird derive eagle and chicken. From mammal derive bear, hyena and lion. Each concrete class needs to override the talk() and move() functions. Also each concrete class will have the operator<<( ) defined. The output of cout << smokey; (assuming smokey is a bear) will be the animalType , the sound he makes (talk( ) ) and how he moves ( move( )). Here is an example: int main() { bear smokey; // using the concrete class cout << smokey // prints out: bear, growl, walk animal *aptr = new bear; // I could have used an animal pointer cout << *aptr; // prints the same results: bear, growl, walk return 0; } Create an array of animal pointers called zoo. Make it 10 in size. Here is what the menu should look like: ----Zoo Cages---- 1 [empty] 2 [empty] 3 [empty] 4 [snake] 5 [eagle] 6 [bear] 7 [empty] 8 [empty] 9 [lion] 10 [hyena] ----Menu---- 1) Add 2) Remove 3) Display all animals 4) Display animal count 5) Exit If the user selects 1) then ask for a cage number and the animal he wishes to put in that cage. Be sure to check the cage for an existing animal first. The user cannot put an animal in a cage that is already occupied. If the user selects 2) then ask for the cage number and remove the animal from that cage (use the destructor). If there is no animal in the cage, issue an error to the user. If the user selects 3) then display the contents of each cage. The display function will show each cage number as well as the animalType of the animal, the sound it makes and how it moves, in other words, use the operator<<( ). All this information must be on a single screen. The output screen is up to you. If the user selects 4) then display the count of the number of animals in your zoo. In the above example, you will have 5. You should use a static data member in the animal class to keep track of the number of animals. You should increase that count each time the animal constructor is called and decrease the count when the animal destructor is called. ***Use Virtual Functions and the animal base class MUST be abstract Solution main.cpp #include //input output #include //strings #include //Randoms #include //Randoms #include //For input #include \"lizard.h\" #include \"snake.h\" #include \"chicken.h\" #include \"eagle.h\" #include \"hyena.h\" #include \"bear.h\" #include \"lion.h\" using namespace std; //declare our static variable from the animal class int animal::numAnimals; int main() { //array of animal pointers animal *zoo[10] = { NULL }; //initialize our static variable to zero animal::numAnimals = 0; //To test if cage is empty, it is nu.

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calderoncasto9163

A range of values estimated to have a high probably of containing the population value is called: Point estimate Standard error of the mean Confidence interval Standard deviation Point estimate Standard error of the mean Confidence interval Standard deviation Solution It is OPTION C: CONFIDENCE INTERVAL. [ANSWER] *********** The confidence interval is the range of values in which the true population parameter value is there..

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calderoncasto9163

A thrown lump of clay hits a block in mid air and sticks to it. what happens to the total kinetic energy of the ball+clay system during this inetraction, ignoring gravity? Solution As the lump of clay sticks to th block, it is an example of inelasti collision. During the inelastic collision, the momentum will be conserved for ball+clay system but Kinetic energy will not. Total Kinetic Energy of ball+clay system will decrease during the interaction..

A thrown lump of clay hits a block in mid air and sticks to it. what.pdf

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calderoncasto9163

Answer die following questions with short answers: Explain the difference between stream ciphers and block cipher. Explain the difference between passive and active attacks. Describe the difference between authentication and non-repudiation Explain the difference between a MAC and message digest. Give one advantage and one disadvantage of public-key cryptography over symmetric-key cryptogra Why is CBC mode considered preferable to ECB mode? Solution a) stream cipher and block cipher differ in whitch the plain text is encoded and decoded. the basic difference is how the logic used for the encryption and decryption. the idea of block cipher is partition the plain text into relatively larger blocks and further each block will be encoded. and same key is used for both encryption and decryption.example DES,IDEA the idea of stream cipher is plain text is encrypted and transfered bit by bit.but key property of stream cipher is different key is generated for each block or bit.example -ISAAC,FISH b) passive attack is indirect attack.the attacked host is completely unaware about the attack. hence it is called passive attack like some body listens the packet transformation or observing the host in network. active attack is direct attack.its nothing but the attacked one gets aware of the attack. like somebody listens the id and password and stop the services(denial of service) or logic bomb. both are harmful. c) authentication and non repudiation are two different things. authentication verifies the who you are(user-id).where the non-repudiation verifies the what you did(messages). authentication is done through a central instance where non repudiation can done by anyone d) message digest is a hash of a message.its output of a cryptographic hash function appilied to input data it refered to as message. mac is a piece of information that proves the integrity of a message. message digest is take only single input and produces a message digest(aka hash) if the message change it produce different hash code. mac (message authentication code) is take input and security code to check the integrity of message. HMAC is one of this kind. e) advantage of public key cryptography over the symmetric key cryptography is increased security and convenience. and no need of key distribution(transmitted to anyone).and it provide digital signatures that cannot be repudiated. the disadvantage of public key cryptography over symmetric cryptography is speed.they are many symmetic key methods runs faster than the public key cryptography. f) the reason why cbc is considered better than ecb has nothing to do with situations involving an attacker with partial cipher text. problem with ECB is that it leaks the information like when two blocks have same plain text then the corresponding cipher blocks also be same where in case of the CBC it randomly independent of plain text to produce the cipher text..

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