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Similar to Ch3 z53 stoich
Similar to Ch3 z53 stoich (20)
Ch3 z53 stoich
- 39. CO 2 is absorbed H 2 O is absorbed Sample is burned completely to form CO 2 and H 2 O Pure O 2 in
- 40. Figure 3.5 Schematic Diagram of the Combustion Device Used to Analyze Substances for Carbon and Hydrogen
- 46. Balancing equations pp CH 4 + O 2 CO 2 + 2 H 2 O Reactants Products C 1 1 O 2 3 H 4 2 4
- 47. Balancing equations pp CH 4 + O 2 CO 2 + 2H 2 O Reactants Products C 1 1 O 2 3 H 4 2 4 4
- 48. Balancing equations pp CH 4 + 2 O 2 CO 2 + 2H 2 O Reactants Products C 1 1 O 2 3 H 4 2 4 4 4
- 50. Example pp H 2 + H 2 O O 2 Need twice as much O in the product R P H O 2 2 2 1
- 51. Example pp H 2 + H 2 O O 2 Changes the O R P H O 2 2 2 1 2
- 52. Example pp H 2 + H 2 O O 2 Also changes the H R P H O 2 2 2 1 2 2
- 53. Example pp H 2 + H 2 O O 2 Need twice as much H in the reactant R P H O 2 2 2 1 2 2 4
- 54. Example pp H 2 + H 2 O O 2 Recount R P H O 2 2 2 1 2 2 4 2
- 55. Example pp H 2 + H 2 O O 2 The equation is balanced, has the same number of each kind of atom on both sides R P H O 2 2 2 1 2 2 4 2 4
- 56. Example H 2 + H 2 O O 2 This is the answer R P H O 2 2 2 1 2 2 4 2 4 Not this
- 63. 2Fe + 3CuSO 4 Fe 2 (SO 4 ) 3 + 3Cu pp 0.181 mol Fe 2 mol Fe 3 mol Cu = 0.272 mol Cu 0.272 mol Cu 1 mol Cu 63.55 g Cu = 17.3 g Cu
- 64. Could have done it via “spider” pp 10.1 g Fe 55.85 g Fe 1 mol Fe 2 mol Fe 3 mol Cu 1 mol Cu 63.55 g Cu = 17.3 g Cu