You have mated a phenotypically wild-type female of the genotype Xy+w+Xyw to a male with the genotype XywY. You counted 2205 total F1 progeny and found 17 flies with gray bodies and white eyes and 12 flies that had yellow body and red eyes. What is the distance between these genes controlling body color and eye color on the X chromosome? rev: 10_27_2012 A. 0.78 map units B. 1.32 map units C. 2.63 map units D. 98.7 map units Solution In this problem total progeny is 2205. Among them recombinant individuals are 17 flies with gray body and white eyes; 12 flies with yellow body and red eyes. Then % of Recombination = No. Of Recombinant Individuals x 100 / Total progeny = (17 + 12) x 100 / 2205 = 29 x 100 / 2205 = 1.32 % or 1.32 mU.