Please explain your answer. Thanks! In order to determine the overal.pdf

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Please explain your answer. Thanks! In order to determine the overall chromosome map for a new wild type strain of E. coli, three Hfr strains were obtained by independent insertions of the F factor. The start times of transfer of several genes were determined during conjugation matings between each Hfr strain and an F recipient carrying six auxotrophic mutations. Using the times taken to begin transfer of each marker, draw a unified chromosome map of the chromosome of this strain of E. coli, showing its total length in minutes of transfer and the order and relative distances between these markers. Show the position and orientation of the F factor in each Hfr strain. Solution A. Hfr 1: Ade--Bio----His--Met-----Ile Hfr 2: Met-His-----Bio-Ade Hfr 3: Bio-Ade-----------Lys--Ile B. Hfr 1: F factor-Ade-------> Hfr 2: F factor-Met-------> Hfr 3: F-factor-Bio------->.

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In the following list, which term is least related to the others? tripled monosomic aneuploid trisomic Solution triploid is the answer. Aneuploidy is the presence of an abnormal number of chromosomes in a cell.It can be monosomic or disomic or trisomic. Monosomy is lack of one chromosome of the normal complement.Monosomy of the sex chromosomes(45,X) causes Turner syndrome. Trisomy is the presence of three copies,instead of the normal two,of a particular chromosome.The presence of an extra chromosome 21,which is found in Down syndrome. Triploid is having three homologous sets of chromosomes..

In the following list, which term is least related to the others tr.pdf

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If your organization is going to apply for a grant, when do you think, if ever, it would be appropriate to make the application public? What would be the benefits and drawbacks of doing it before the application is submitted? What about after? Solution Answer ) Grants in general term conside as money awards to organization to take care or start a social project .In real life, grant may be given in kinds other than cash ( travel expenses, data collection supports ,software, time off the job). and occasionally, mainly for research, it can be made to individuals. An organization apply for grant for many reason , like, times when we don\'t have much money to do excellent community work,Government is ready to give special funding for some unique projects, organization are asked to get some community work .and organization is well aware about its capability to meet the eligibility standards for such awards. If my organization is going to apply for a grant, it would be appropriate to make the application public once the purposal of grant get accepted by granting agencies . The schedule of disbursement of fund is out. Drawbacks of making public before application is submitted Benefits Diclosing after getting approved : Drawback s Benefits.

If your organization is going to apply for a grant, when do you thin.pdf

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If the characteristic followed in the pedigree is x-linked recessive allele, what is III-1\'s genotype? a. Hemizygous for a dominant allele b. Hemizygous for a recessive allele c. Definitely heterozygous d. dominant e. Either heterozygous or homozygous dominant Solution 1st generation parents 1,2 though are normal but must be heterozygotes (Pp) since their children are affected i.e. 2nd generation males 1,3. Since 1st generation male 3 is affected (pp) and 4 is normal but regardless if 4 in 1st generation is PP or Pp their children will be either 4 Pp i.e. heterozygote or 2 affected pp and 2 heterozygotes Pp. But the 2nd generation 4, 5 female are normal but heterozygotes Pp. So the cross between a 2nd generation affected male 3(pp) and a normal but heterozygote female 4(Pp) would have a normal male child only if hemizygous for a dominant allele condition exists. Hemizygous is a condition in which only one gene copy/DNA sequence exists in diploid cells. Males are hemizygous for most genes on sex chromosomes since they have only one X and one Y chromosome unlike two X for females. A recessive X-linked gene requires two mutant alleles to affect the female phenotype. Rules followed here are.

If the characteristic followed in the pedigree is x-linked recessive .pdf

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I want to know the purpose of parting line Solution A parting line is the border in which draft angles change direction. It is also the line, which splits the part into core and cavity halves. Parting line can be a starting point for the mould parting surface, but not necessarily. In other words we can say that Parting line in actual seperates Cope and Drag of a mould and hence plays an important role in determining various properties, shapes and surface finish of Cast..

I want to know the purpose of parting lineSolutionA parting li.pdf

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HTML5 & JqueryJavascriptI am trying to code a image slider and I.pdf

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How to access this window in ANSYS (Picture 1 contains analysis s.pdf

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How and when do we learn ethics? How and when do we learn ethics? Solution Ethics is actually a branch of philosphy. It guides us about right conduct and wrong conduct. Directly or indirectly everyone is learning ethics from childhood. Children are taught to avoid doing wrongs by parents from very tender age onwards. General ethics should be started from early ages so as to make the child behave in the society in a presentable manner. Professional ethics, conduct to certain profession or group can be learnt after selecting that profession..

How and when do we learn ethicsHow and when do we learn ethics.pdf

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How does a dominant culture differ from a subculture? In your answer be sure to define both terms. Solution Organizations are, in a way, small or large ecosystems, within which its members interact under certain codes of conduct. Organizational culture is then all these formal and informal rules which take the members of the organization to establish and accepted behaviors that generate disapproval, and in general, the expected behavior of each of the members. Recent studies have found that, generally, there is a culture that is identified as dominant, because most of the members of the organization accept and follow it. However, it is also true that the dominant culture is not homogeneously accepted by all members, some of them create rules and codes as a reaction to it, thus forming more specific subcultures. Thus, the dominant culture revolves around the core values of the organization or that group of people in particular, and are widely shared. Instead, subcultures go around problems, experiences or specific realities of a smaller group of people, values are not massive, but share few people in response to specific situations, such as a high school subculture or Latinos African Americans. In the dominant culture deprive the philosophical values that inspire the masses, in the subculture specific needs of this group are imposed, it is more pragmatic, that is a fundamental difference..

How does a dominant culture differ from a subculture In your answer.pdf

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Help with implementing the four function the first is an example thanks def inorder(T,f): if not is_bst(T): return if not T: return inorder(T[1],f) f(T[0]) inorder(T[2],f) # programming project: provide implementations for the functions below # and add tests for these functions to the code in the block # that starts \"if __name__ == \'__main__\'\" def preorder(T,f): pass def postorder(T,f): pass def tree_height(T): pass def balance(T): # returns the height of the left subtree of T # minus the height of the right subtree of T pass Solution class Node: def _init_(self,val): self.value=val self.leftChild=None self.rightChild=None def preorder(self): if self: print(str(self.value)) if self.leftChild: self.leftChild. preorder() if self.rightChild: self. rightChild. preorder() def postorder(self): if self: if self.leftChild: self.leftChild. postorder () if self.rightChild: self. rightChild. postorder () print(str(self.value)) def inorder(self): if self: if self.leftChild: self.leftChild. inorder () print(str(self.value)) if self.rightChild: self. rightChild. inorder () def height(self,root): if root is None: reture 0 else: return max(self.height(root.left),self.height(root.right))+1 det balance(self,root): if root is None: return 0 else: leftHeight= height(root.left) rightHeight= height(root.right) if leftHeight- rightHeight<=1 : return 1 else: return 0 class Tree: def _init_(self): self.root=None def preorder(self): print(“Preorder)” self.root.preorder() def postorder(self): print(“Postorder)” self.root. postorder () def inorder(self): print(“Inorder)” self.root. inorder () bst=Tree() bst.preorder() bst.postorder() bst.inorder() print(\"Height of tree is \" (height (bst))) if (balance(bst): print (“Tree is balance”) else print (“Tree is not balance”).

Help with implementing the four function the first is an exampleth.pdf

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Encrypt the message \" HALT \" by translating the letters into numbers (via A=0,B=1,C=2,D=3,E=4,F=5,G=6,H=7,I=8, J=9,K=10,L=11,M=12,N=13,O=14,P=15,Q=16,R=17, S=18,T=19,U=20,V=21,W=22,X=23,Y=24,Z=25 ) and then applying the encryption function given, and then translating the numbers back into letters. (a) f(p)=(p+5) mod 26 _____________ (b) f(p)=(p+12) mod 26 _______________ (c) f(p)=(p+4) mod 26 ______________ Solution Encrypt message as : A=0,B=1,C=2,D=3,E=4,F=5,G=6,H=7,I=8, J=9,K=10,L=11,M=12,N=13,O=14,P=15,Q=16,R=17, S=18,T=19,U=20,V=21,W=22,X=23,Y=24,Z=25 and given encryption function :a) f(p)=(p+5)mod26 if p=Z=25 f(25)=(25+5)mod26 =30mod26=4 f(25)=E and f(p)=(p+5)mod26 if p=15 f(15)=(15+5)mod26 =20mod26=20 f(15)=U b) f(p)=(p+12)mod26 f(p)=(p+12)mod26 if p=Z=25 f(25)=(25+12)mod26 =37mod26=11 f(25)=L and for f(p)=(p+12)mod26 if p=15 f(15)=(15+12)mod26 =27mod26=1 f(15)=B c)f(p)=(p+4)mod26 f(p)=(p+4)mod26 if p=Z=25 f(25)=(25+4)mod26 =29mod26=3 f(25)=D and for f(p)=(p+4)mod26 if p=15 f(15)=(15+4)mod26 =19mod26=19 f(15)=T.

Encrypt the message HALT by translating the letters into numbe.pdf

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Each letter in the word Massachusetts is written on a card. The cards are placed in a basket. What is the probability of selecting two S\'s if the first card is replaced before selecting the second card? Solution It\'s a probability of 16 out of 169. There are 13 letters in MASSACHUSETTS. 4 of the 13 are the letter S, so there is a 4 in 13 chance to draw an S. Since the first card is replaced, there is still a 4 in 13 chance of drawing another S. So the combined probability is 4/13 x 4/13 = 16/169.

Each letter in the word Massachusetts is written on a card. The card.pdf

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Below is the question I need help with. It need to be done in Java. I need help making the priority queue part of the assignment, if you can add the GUI it will be helpful. You are to simulate a dispatcher using a priority queue system. New processes are to be entered using a GUI with priority included (numbering should be automatic). Processes are also to be terminated by GUI command. Context switches are to be by command with the cause of the switch being immaterial. Assume only one CPU. Priorities and numbers of processes can be kept small, just big enough to demonstrate the below listed functionality. You may pre-populate the queues initially from a data file. I am looking at the mechanism as you are NOT creating actual processes, just simulating them. Functionality to be provided by you: 1. Priority based Ready Queue(s). 2. Blocked list. 3. Output of complete system status after every context switch showing ready, blocked, and running processes. Solution import java.awt.Container; import java.awt.Dimension; import java.awt.FlowLayout; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.util.PriorityQueue; import java.util.Queue; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JLabel; import javax.swing.JTextArea; import javax.swing.JTextField; class dispatcher extends JFrame implements ActionListener { static int processNo = 0; static Process currentlyRunning; static Queue readyQueue; static Queue blockedQueue; static JButton newProcess; static JButton contextSwitch; static JTextField priority; static JTextArea Queues; private static Process newProcess(int i, int i0, String running) { throw new UnsupportedOperationException(\"Not supported yet.\"); } dispatcher() { Container cp = getContentPane(); cp.setLayout(new FlowLayout()); Queues = new JTextArea(5, 15); Queues.setPreferredSize(new Dimension(500, 400)); cp.add(Queues); cp.add(new JLabel(\"Priority\")); priority = new JTextField(6); newProcess = new JButton(\"Create Process\"); newProcess.addActionListener(this); cp.add(priority); cp.add(newProcess); contextSwitch = new JButton(\"Context Switch\"); contextSwitch.addActionListener(this); cp.add(contextSwitch); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); setTitle(\"Dispatcher\"); setSize(600, 500); setVisible(true); } public static void main(String args[]) { dispatcher d = new dispatcher(); readyQueue = new PriorityQueue<>(); blockedQueue = new PriorityQueue<>(); Process p1 = newProcess(processNo++, 2, \"Running\"); Process p2 = newProcess(processNo++, 1, \"Blocked\"); Process p3 = newProcess(processNo++, 4, \"Ready\"); Process p4 = newProcess(processNo++, 3, \"Ready\"); Process p5 = newProcess(processNo++, 5, \"Ready\"); Process p6 = newProcess(processNo++, 8, \"Blocked\"); readyQueue.add(p3); readyQueue.add(p4); readyQueue.add(p5); blockedQueue.add(p6); blockedQueue.add(p2); currentlyRunning = p1; contextSwitch(); } static void createProcess(int priority) { readyQueue.add.

Below is the question I need help with. It need to be done in Java. .pdf

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Css code for a awoko newspaper html website which provides business and finance, editorial, entertainment.,features and sport. Css code for a awoko newspaper html website which provides business and finance, editorial, entertainment.,features and sport. Solution //Name this css file as style.css @charset \"utf-8\"; /* General */ body { margin:0px; font-size:12px; background-color:#ffffea; } body * { outline:none; } .float { float:left; } body form { margin:0px; } #page { width:100%; background-image:url(images/body_bg2.png); background-repeat:repeat-x; } #wrapper { width:966px; margin:0px auto 0px auto; } #left { width:12px; height:219px; background-image:url(images/left_effect.png); background-repeat:no-repeat; background-position:0px 157px; } #center { width:942px; } #right { width:12px; height:219px; background-image:url(images/right_effect.png); background-repeat:no-repeat; background-position:0px 157px; } /* Header */ #header { padding:2px 0px 2px 0px; } #search { width:50%; float:left; } .search_field { height:18px; border:1px solid #e3c6c4; } #top_links { width:40%; float:right; margin:4px 0px 4px 0px; font-family:Georgia, Arial, Helvetica, sans-serif; } #top_links * a { color:#FFF; text-decoration:none; } #top_links ul { padding:0px; margin:0px; float:right; } #top_links ul li { list-style:none; margin-left:15px; float:left; } #logo { width:222px; margin-right:16px; margin-top:15px; font-family:Georgia, \"Times New Roman\", Times, serif; color:#000; line-height:25px; text-align:center; } #logo a { background-image:url(images/logo.png); background-repeat:no-repeat; width:202px; height:72px; margin-right:auto; margin-left:auto; display:block; } #top_ad { width:374px; margin-right:21px; margin-top:15px; height:90px; } #today_quote { width:309px; margin-top:15px; } #quote { width:219px; text-align:right; margin-right:5px; padding:5px; font-size:14px; } /*Middle*/ #middle { border-top:1px solid #df202d; border-left:1px solid #df202d; border-right:1px solid #df202d; } .scroller { background-color:#fef407; height:22px; width:auto; color:#959595; font-family:Georgia, \'Times New Roman\', Times, serif; line-height:22px; padding:0px 5px 0px 5px; } #main_menu { width:100%; font-family:Georgia, Arial, Helvetica, sans-serif; line-height:29px; font-size:12px; text-transform:uppercase; background-image:url(images/body_bg2.png); background-repeat:repeat-x; background-position:top; background-color:#c0010e; height:30px; } #main_menu * a { color:#FFF; text-decoration:none; } #main_menu ul { padding:0px; margin:0px; width:100%; text-align:center; } #main_menu ul li { list-style:none; margin:0px 10px; display:inline-block; } /*Three Columns*/ /* column container */ .colmask { position:relative; /* This fixes the IE7 overflow hidden bug */ clear:both; float:left; width:100%; /* width of whole page */ overflow:hidden; /* This chops off any overhanging divs */ } /* common column settings */ .colright, .colmid, .colleft { float:left; width:100%; /* width of .

Css code for a awoko newspaper html website which provides busines.pdf

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Case study: Job Satisfaction in the Banking Industry: Or the logistical nightmare of conducting large scale quantitative research Job characteristics are believed to have an impact on stress and well-being at work (Karasek& Theorell, 1990). The demands of the job on the one hand and theextentto which you have control over your own activities (decision latitude) on the other, are two factors which together define how stressful a job is. Those jobs which are high demand, but offer limited control, are considered to be high-strain and carry an increased risk of job dissatisfaction, stress and burnout. Based on this theoretical framework, the Union of Belgian Banks sent out a research call to several institutions, with a bidding process based on criteria such as quality of the proposal, timing, and – above all – budget. The aim of the research was to carry out quantitative research to measure the relationship between job characteristics and job satisfaction in all Belgian banks (seeCambréet al., forthcoming). But in order to do this effectively, several methodological issues needed to be resolved during the research process. First of all, aresearch consortiumwas selected to conduct the research, or more precisely, the two highest ranked bidders were asked to jointly undertake the research. This was the outcome of a political decision by the banks (see also p. 142, ‘Affiliation and conflicts of interest’),since the employers preferred one partner and the unions (employee representatives) preferred the other. The two competing research institutes, a private company specialising in stress at work and theKatholiekeUniversiteitLeuven (Belgium), were required to co-operate and develop a level of trust in order to conduct the research. For example, both research institutes had different ideas as to which scale should be used in the questionnaire. They could not just combine the scales or include both scales, simply because they are supposed to measure the same concept. Furthermore, this would also make the questionnaire too complex. Therefore, the research institutes had to combine their knowledge, look for compromises and jointly work on a shared vision, which is, to say the least, rather time consuming. A second obstacle that needed to be overcome was thesample(see Chapter 7). Intotal, 69,000 employees work for Belgian banks and it was decided that questioning all employees would be too complicated and too expensive. Therefore the research committee, consisting of representatives of the banks, the unions and the research consortium, opted for a cross-sectional design (p. 45) with a fixed sample of 15,000 employees (roughly 21%; see p. 187 ‘Absolute and relative sample size’). In this sample, the small banks were over-represented in order to be able to make conclusions at the level of each bank. Within each bank, the respondents were selected at random with no particular quota for gender, age or employee level. In the postal survey (see p.231 ‘Self- co.

Case study Job Satisfaction in the Banking Industry Or the logisti.pdf

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You are constructing working models of the heart for extra credit Your first attempt failed because the cells separated from each other during beating. What structures did you omit, and why did this allow the heart to fall apart? You omitted the gap junctions in your second attempt How would a real heart fail to function normally without gap junctions? Solution Ans. In first attempet the page maker is missing. In the heart, crevice intersections assume a vital part in motivation conduction. Concentrates in the course of the most recent decade have uncovered that hole intersections are encoded by a multigene family known as the connexins. Crevice intersection correspondence (GJC) interceded by connexins is basic for heart function.Heart will get to obtaine these capacity and quit working..

You are constructing working models of the heart for extra credit You.pdf

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why does countercurrent flow yields greater oxygen uptake than concurrent flow? Mention diffusion. Solution Answer: The orientation of medium is perpendicular to the flow of blood in countercurrent flow so that it is leading to higher efficiency of oxygen diffusion to medium flow at differential points whereas in concurrent flow, medium is synchronous and parallel to the flow of blood so that the rate of diffusion from the alveoli to blood capillaries are lower. The both bloodstreams are going to move in a similar or simultaneous pathway. The concurrent flow yields intermediate in transfer efficiency with multivillous oxygen diffusion main found in humans and sheep.

why does countercurrent flow yields greater oxygen uptake than concu.pdf

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Wind Shear can be defined in the horizontal plane as well as the vertical plane (True/False) Solution True Wind shear, sometimes referred to as wind gradient, is a difference in wind speed and/or direction over a relatively short distance in the atmosphere. Atmospheric wind shear is normally described as either vertical or horizontal wind shear. Horizontal Plane :Horizontal wind shear is a change in wind speed with change in lateral position for a given altitude. Vertical Plane :Vertical wind shear is a change in wind speed or direction with change in altitude..

Wind Shear can be defined in the horizontal plane as well as the vert.pdf

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While hiking on some small islands in Lake Superior, you stumble across a small frog. Thinking about your respective evolutionary histories, what is a likely homology between you and this animal: Number of limbs External fertillization Amniotic egg Four-chambered heart Live birth Solution ANS: A. Number of limbs. Explanation: According to the evolution, comparative anatomy of limb bone structure (pentadactyl ,5 digit) is same in most vertebrates. It is called homology. Homologies clearly indicate the phenomenon of common ancestry. Like humans frogs also contains same bone structure. They are…. Arms: Like Human arms, frog front leg bones are called as humerus, radius and ulna (radius and ulna are fused into one bone). Legs: Like Human legs, frog femur supports its upper leg and lower leg bone (tibia and fibula, are fused). And also frog contains two scapulae (shoulder blades), and clavicles (collarbones) like human..

While hiking on some small islands in Lake Superior, you stumble acr.pdf

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Which phyla have megaphylls Bryophyta Monilophyta Coniferophyta .pdf

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Where do endocyotic vesicles come from? A. Plasma membrance B. Nuclear membrance C. Smooth ER D. Lysosome Solution Answer: A. plasma membrane Reason: Cells are going to ingest fluid, molecules, and waste particles Clathrin mediated endocytosis result in internalization of the receptor further leading these receptors to be degraded by lysosomal endosome formation when there is not ligand to bound. This endocytosis process is going to produce endocytic vesicles from localized regions of the plasma membrane through invagination.

Where do endocyotic vesicles come fromA. Plasma membranceB. Nuc.pdf

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