Calculate the capacitance of a lipid vesicle, 1 uM in diameter. Show assumptions Solution Approximately there are 5*106 lipid molecule in 1 m *1 m area The capacitance of a lipid vescicle can be written as C={E0*A}/d, ie ={(8.85*10- 2F/m)*4*3.14*(0.5*10-6m)}2/8*10-9m =0.35*10-11F,=3.5pF Here E(read as epsilon ) radius is 1/2 of diameter so 0.5m d= Charge separation of lipid molecules in a bilayered structure(around 8 nm). Vescicle taken as a sphere therefore area is 4(pi)r2 (in equation * indicates multiplication, ).