1. CEE-312
Structural Analysis and Design
Sessional-I
(1.0 credit)
Lecture: 4
Bijit Kumar Banik
Assistant Professor, CEE, SUST
Room No.: 115 (“C” building)
bijit_sustbd@yahoo.com
Department of Civil and Environmental Engineering
2. Analysis and design of an Industrial roof truss system
(4.41) (4.41) (3.53) (3.53) (4.41) (4.41)
(- 5.05)
(- 4.04)
(- 3.03) (- 3.03)
(- 4.04)
(- 5.05)
6@6 ft = 36 ft
L0
L1 L2 L3 L4 L5
L6
U1
U2
U3
U4
U5
2.94 k2.94 k
(.18)
(0.67)
(0.67)
(.18)
(2.14)
(-1.32)
(- 1.01)
(-1.32)
(- 1.01)
3. Analysis and design of an Industrial roof truss system
P = (0.07*29.05-2.1)*25.6 = -1.7 psf
For windward surface
For leeward surface
P = -0.7*25.6 = -17.92 psf
We already calculated in lecture-2
Once again what –ve sign means? Suction/Uplift
Wind load calculations
4. Wind Load Analysis
6@6 ft = 36 ft
10 ft
L0
L1 L2 L3 L4 L5
L6
U1
U2
U3
U4
U5
R1
R2
H
3@6.86 ft
Wind blows from left to right
Windward side joint loads (U1 & U2)= 1.7*20*6.86 = 0.23k
End joint loads [ L0 & (U3)left ] = 0.23/2 = 0.12k
Leeward side joint loads (U4 & U5)=17.92*20*6.86 = 2.46k
End joint loads [ L6 & (U3)right ] = 2.46/2 = 1.23k
0.23k
0.23k
0.12k
0.12k
2.46k
2.46k
1.23k
1.23k