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Khulna University of Engineering and Technology
Course No: TE 4109
Course Title: Fabric Structure and Design - II
Prepared by
Swaraz Mollick
Roll 1421008
Dept. of Textile Engineering
Calculation of different parameters in Knitting from given notation
diagram
Needle Arrangement: 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 ......
Find out the following parameters:
1) Total no of Needle
2) No of active and inactive needle
3) Total no of cam box
4) No of active and inactive cam box
5) Total no of cam
6) No of knit, tuck and miss cam
Where the machine is 8 truck machine and the machine diameter is (a) 29” (b)
39” (c) 49”
Solution
(a) For 29” machine dia
M/C dia D = 29”
Gauge = 24 needle/inch
Total no of needle = πDG
= π × 29 × 24
= 2186.54 ≈ 2187
No of active needle and inactive needle = 2187/8 = 273 × 8 + 3
Active needle = 273 × 8 = 2184
Inactive needle = 3
Total no of cam box = 3D = 3 × 29 = 87
Now cam box repeat = 87/3 = 29
No of active cam box = 3 × 29 = 87
No of inactive cam box = 0
Total no of cam = no of cam box × truck
= 87 × 8
= 696
No of knit cam = 18 × 29 = 522
No of Tuck cam = 6 × 29 = 174
No of miss cam = 0
(b)For 39” machine dia
M/C dia D = 39”
Gauge = 24 needle/inch
Total no of needle = πDG
= π × 39 × 24
= 2940.53 ≈ 2941
No of active needle and inactive needle = 2941/8 = 367 × 8 + 5
Active needle = 367 × 8 = 2936
Inactive needle = 5
Total no of cam box = 3D = 3 × 39 = 117
Now cam box repeat = 117/3 = 39
No of active cam box = 3 × 39 = 117
No of inactive cam box = 0
Total no of cam = no of cam box × truck
= 117 × 8
= 936
No of knit cam = 18 × 39 = 702
No of Tuck cam = 6 × 39 = 234
No of miss cam = 0
(c) For 49” machine dia
M/C dia D = 49”
Gauge = 24 needle/inch
Total no of needle = πDG
= π × 49 × 24
= 3694.51 ≈ 3695
No of active needle and inactive needle = 3695/8 = 461 × 8 + 7
Active needle = 461 × 8 = 3688
Inactive needle = 7
Total no of cam box = 3D = 3 × 49 = 147
Now cam box repeat = 147/3 = 49
No of active cam box = 3 × 49 = 147
No of inactive cam box = 0
Total no of cam = no of cam box × truck
= 147 × 8
= 1176
No of knit cam = 18 × 49 = 882
No of Tuck cam = 6 × 49 = 284
No of miss cam = 0

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Calculation of different parameters from notation diagram in weft knitting

  • 1. Khulna University of Engineering and Technology Course No: TE 4109 Course Title: Fabric Structure and Design - II Prepared by Swaraz Mollick Roll 1421008 Dept. of Textile Engineering
  • 2. Calculation of different parameters in Knitting from given notation diagram Needle Arrangement: 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 ...... Find out the following parameters: 1) Total no of Needle 2) No of active and inactive needle 3) Total no of cam box 4) No of active and inactive cam box 5) Total no of cam 6) No of knit, tuck and miss cam Where the machine is 8 truck machine and the machine diameter is (a) 29” (b) 39” (c) 49” Solution (a) For 29” machine dia
  • 3. M/C dia D = 29” Gauge = 24 needle/inch Total no of needle = πDG = π × 29 × 24 = 2186.54 ≈ 2187 No of active needle and inactive needle = 2187/8 = 273 × 8 + 3 Active needle = 273 × 8 = 2184 Inactive needle = 3 Total no of cam box = 3D = 3 × 29 = 87 Now cam box repeat = 87/3 = 29 No of active cam box = 3 × 29 = 87 No of inactive cam box = 0 Total no of cam = no of cam box × truck = 87 × 8 = 696 No of knit cam = 18 × 29 = 522 No of Tuck cam = 6 × 29 = 174 No of miss cam = 0 (b)For 39” machine dia M/C dia D = 39” Gauge = 24 needle/inch Total no of needle = πDG = π × 39 × 24
  • 4. = 2940.53 ≈ 2941 No of active needle and inactive needle = 2941/8 = 367 × 8 + 5 Active needle = 367 × 8 = 2936 Inactive needle = 5 Total no of cam box = 3D = 3 × 39 = 117 Now cam box repeat = 117/3 = 39 No of active cam box = 3 × 39 = 117 No of inactive cam box = 0 Total no of cam = no of cam box × truck = 117 × 8 = 936 No of knit cam = 18 × 39 = 702 No of Tuck cam = 6 × 39 = 234 No of miss cam = 0 (c) For 49” machine dia M/C dia D = 49” Gauge = 24 needle/inch Total no of needle = πDG = π × 49 × 24 = 3694.51 ≈ 3695 No of active needle and inactive needle = 3695/8 = 461 × 8 + 7 Active needle = 461 × 8 = 3688
  • 5. Inactive needle = 7 Total no of cam box = 3D = 3 × 49 = 147 Now cam box repeat = 147/3 = 49 No of active cam box = 3 × 49 = 147 No of inactive cam box = 0 Total no of cam = no of cam box × truck = 147 × 8 = 1176 No of knit cam = 18 × 49 = 882 No of Tuck cam = 6 × 49 = 284 No of miss cam = 0