This document contains calculations for 4 exercises involving voltage dividers and current dividers. In the first exercise, it calculates the total resistance, input current, and currents through each resistor in a voltage divider circuit. The second exercise calculates the total resistances and currents for two voltage divider circuits connected in series. The third exercise uses voltage divider equations to calculate the voltages at each resistor in a 3 resistor voltage divider. The fourth exercise calculates the total resistance, input current, and currents through each resistor for a current divider circuit.

1. Republica Bolivariana de Venezuela
I.U.P “Santiago Mariño”
Extensión Maturín
Ing. Sistemas
Ejercicios de divisores de tensión -divisores de corriente
Bachiller:
Miguel Gil
CI: 25926204

2. EJERCICIO #1
Req = 1 = 4.61Ω
1/10 + 1/20 + 1/15
I = E/Req = 100 V/4.61 ohm = 22A
I1= E/R1 = 100 V/10 Ω = 10 A
I2 = E/R2 = 100 V/20 Ω = 5A
I3 = E/R3 = 100 V/15 Ω = 7A

3. EJERCICIO #2
R12 = 1 = 10Ω
1/20 + 1/20
R34 = 1 = 20Ω
1/40 + 1/40
Rt = 10 * 20 = 6.66Ω
10+20
I = 100 V = 15.01A
6.66 Ω
I1 = 20 * 15.01A = 10A
10+20
I2 = 10 * 15.01A = 5A
10+20

4. EJERCICIO #3
Rt = 70Ω + 35Ω + 100Ω = 205Ω
Aplicando divisor de tension:
𝑉1 = 70𝛺 ∗
100𝑉
205𝛺
𝑉1 =
1400
41
𝑉
𝑉2 = 35𝛺 ∗
100𝑉
205𝛺
𝑉2 =
700
41
𝑉
𝑉3 = 100𝛺 ∗
100𝑉
205𝛺
𝑉1 =
2000
41
𝑉

5. EJERCICIO #4
R3,4 = 35 + 55 = 90𝛺
RT=
1
1
100
+
1
50
+
1
90
= 24,32𝛺
𝐼𝑡
100
24,32
= 4,11𝐴
𝐼1 =
24,32
100
∗ 4,11𝐴 = 0.99𝛺
𝐼2 =
24,32
50
∗ 4,11𝐴 = 1,99𝛺
𝐼34 =
24,32
90
∗ 4,11𝐴 = 1,11𝛺