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- 1. THREE EQUATION’S OF MOTIONNAME :- ASHWANI KUMARSUBJECT:-PHYSICS PROJECT(EQUATION OF MOTION)
- 2. •First Equation of MotionThe first equation of motion is v=u + at. It gives the velocity acquired by a body in time t.Consider a body having initial velocity ‘u’. Suppose it is subjected to a uniform acceleration ‘a’ so that after time ‘t’ its final velocity becomes ‘v’. Now, from the definition of acceleration we know that;—> Acceleration=Change in velocity Time taken—> Acceleration=Final velocity –Initial velocity Time taken—> a=v - u t—> at=v - u—> v=u + at
- 3. •Second Equation of MotionThe second equation of motion is s=ut + 1at. It gives 2 the distance traveled by a body in time t.Consider a body having initial velocity ‘u’ and a uniform acceleration ‘a’ for time ‘t’ so that its final velocity becomes ‘v’. .Let the distance traveled by the body in this time ‘s’. The distance travelled by a moving body in time ‘t’ can be found out by considering its average velocity. Since the initial velocity of the body is ‘u’ and its final; velocity is ‘v’ ,the average velocity is given by:—> Average velocity=Initial velocity+ final velocity 2—> Average velocity=u + v 2
- 4. Distance travelled= average velocity x Time—> S=(u + v) x t …………………….(1) 2 From the first equation of motion we have ,v=u + at. Putting the value of v in equation (1), we get—> S=(u+ u+ at) x t 2—> S=(2u+at) x t 2—> S=2ut+ at2 2—> S= ut+1at2 2
- 5. •Third Equation of MotionThe third equation of motion is v=u+2as. It gives the velocity acquired by a body in traveling a distance ‘s’Consider a body having initial velocity ‘u’ and a uniform acceleration ‘a’ for time ‘t’ so that its final velocity becomes ‘v’. .Let the distance traveled by the body in this time ‘s’. The distance travelled by a moving body in time ‘t’ can be found out by considering its average velocity. Since the initial velocity of the body is ‘u’ and its final; velocity is ‘v’ ,the average velocity is given by:The third equation of motion can be obtained by eliminating t between the first two equation of motion.From second equation of motion we have;S=ut+1at 2 ……………..(1)
- 6. And from the first equation of motion we have;—> v=u + at This can be rearranged and written as—> at=v - u—> t=v - u a Putting the value of tin equation (1)we get;—> S=u (v-a)+1a(v-u/a) 2—> S=uv-u+a(v+u-2uv) a 2a—> S=2uv-2u+v+u-2uv 2a—> 2as= v – u—> V=u+2as
- 7. THEEND

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thanks a lot

thanks alot.