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Describing Motion
• Motion :- Motion is the change in position
of a body with time.
• Motion can be described in terms of the (i)
distance moved or the (ii)displacement
(i)Distance moved is the actual length of the
path travelled by a body.
(ii)Displacement is the length of the shortest
path travelled by a body from initial
position to it’s final position.
Example of the motion
The average speed
of bullet train is
320km/hrs
A car is in
motion.
Motion of the
Ball Downward.
• i) Uniform motion :- If a body
travels equal distances in equal
intervals of time, it is said to be in
uniform motion.
• ii) Non uniform motion :- If a
body travels unequal distances in
equal intervals of time, it is said to
be in non uniform motion.
Uniform motion and Non
uniform motion
Example
The movement of
clock’s hand and
movement of
pendulum is the
example of uniform
motion
A movement of a asteroid
and the bouncing of ball
is the example of non
uniform motion.
• Speed :- of a body is the distance travelled
by the body in unit time.
Speed =Distance/Time
• If a body travels a distance s in time t
then its speed v is v= s/t
• The SI unit of speed is meter per second
m/s or ms -1 . Since speed has only
magnitude it is a scalar quantity.
Example
The red car is at the speed of
30m/s
And,
The gray car is at the speed of
40m/s
Average speed
Average speed :- is the
ratio of the total distance
travelled to the total time
taken.
Example Problems
Q. A car travels 85km from point A to B , then 45km
from point B to C . The total time took was 1.3 hrs.
What was the average speed of the Car?
Solution of the problem
Total distance=Distance covered i)A to B + ii)B to C
85km + 45km= 130km
Total Time = 1.3 hrs
Average speed = Total Distance Covered/Total time
=> 130/1.3 km/hrs
=> 100km/hrs
The quantity which specifies both
the direction of motion and speed
is velocity.
• Velocity of a body is the
displacement of the body per unit time.
Velocity =Displacement/time taken
• Since velocity has both magnitude and
direction, it is a vector quantity.
Example
Speed with
Direction is known
as Velocity
Average Velocity
• Average velocity :- is the ratio of the
total displacement to the total time taken.
• Average velocity =Total Displacement/Total
Time.
• Average velocity is also the
mean of the initial
velocity u and final velocity v.
• Average velocity= (initial velocity + finial
velocity)/2
or
(u+v)/2
• Speed and velocity have the same units m/s
Example Problem
Q. If a car changes its speed from 10m/s to
20m/s in just 5 sec. What is the average
velocity of the car?
Sol. u = 10m/s time taken
v = 20m/s = 5sec
Average velocity = (u + v)/2
(20m/s + 10m/s)/2
30m/s/2
15m/s
The quantity which specifies
changes in velocity is
acceleration.
• Acceleration :- is the
rate of change of
velocity.
• Acceleration = (Final
velocity – initial velocity) /
2
•If the velocity of a body
changes from initial value u
to final value v
in time t, then acceleration a
Example
Four different ways to accelerate a
car.
Distance –Time Graph
• Motion can be represented on the
distance time graph.
• In the graph distance is taken on the y –
axis and time is taken on the x – axis.
• The distance time graph for uniform
speed is a straight line.
• This is because in uniform speed a body
travels equal distances in equal intervals
of time.
Example
Uniform Motion
Derivation of three formula of
motion
• Let a body is moving with initial velocity ‘u’
with uniform acceleration ‘a’ it’s velocity
become ‘v’ in time ‘t’ sec. In the meantime it
covers the distance ‘s’
• The term would be in
1. Acceleration -> m/s2
2. Initial and final velocity -> m/s
3. Time -> sec
4. Distance -> m
1st Equation of motion
• Acceleration = (v – u)/t
a = (v - u)/t
 at = v – u
 u + at = v 1st
equation
of motion
2nd Equation of motion
• Average velocity = (v + u)/2
• Distance Travelled = Av. Velocity + time
s = (v + u)/2 x t
Put v = u + at
 s = (u + at + u)/2 x t
 s = (2u+at)/2 x t
 s = (2ut + at2) /2
s = ut + ½ at2 2nd
Equation of
motion
3rd Equation of motion
• We know that v = u + at
v – u = at
 (v - u)/a =t
• Put t = (v – u)/a in eq. s = ut + ½ at2
s = u{(v – u)/a} + ½a {(v-u)/2} 2
s = (uv - u2)/a + ½a{(v2 + u2 -2uv)/a2}
 s = (uv - u2)/a + ½(v2 + u2 -2uv)/a
 s = (uv - u2)/a + (v2 + u2 -2uv)/2a
s = (2uv - 2u2 + v2 + u2 -2uv)/2a
s = (v2 - u2 )/2a
 2as = v2 - u2 3rd
Equation
of motion
Circular motion
• The motion of a body in a circular path is called
circular motion.
• Uniform circular motion :- If a body
moves in a circular path with uniform speed, its
motion is called uniform circular motion.
• Uniform circular motion is accelerated motion
because in a circular motion a body continuously
changes its direction.
• The circumference of a circle of radius r is
given by 2лr. If a body takes time t to go once
around the circular path, then the velocity v is
given by
v = 2лr/2
Example
law of motion PPT.pptx

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law of motion PPT.pptx

  • 1.
  • 2. Describing Motion • Motion :- Motion is the change in position of a body with time. • Motion can be described in terms of the (i) distance moved or the (ii)displacement (i)Distance moved is the actual length of the path travelled by a body. (ii)Displacement is the length of the shortest path travelled by a body from initial position to it’s final position.
  • 3. Example of the motion The average speed of bullet train is 320km/hrs A car is in motion. Motion of the Ball Downward.
  • 4. • i) Uniform motion :- If a body travels equal distances in equal intervals of time, it is said to be in uniform motion. • ii) Non uniform motion :- If a body travels unequal distances in equal intervals of time, it is said to be in non uniform motion. Uniform motion and Non uniform motion
  • 5. Example The movement of clock’s hand and movement of pendulum is the example of uniform motion A movement of a asteroid and the bouncing of ball is the example of non uniform motion.
  • 6. • Speed :- of a body is the distance travelled by the body in unit time. Speed =Distance/Time • If a body travels a distance s in time t then its speed v is v= s/t • The SI unit of speed is meter per second m/s or ms -1 . Since speed has only magnitude it is a scalar quantity.
  • 7. Example The red car is at the speed of 30m/s And, The gray car is at the speed of 40m/s
  • 8. Average speed Average speed :- is the ratio of the total distance travelled to the total time taken.
  • 9. Example Problems Q. A car travels 85km from point A to B , then 45km from point B to C . The total time took was 1.3 hrs. What was the average speed of the Car? Solution of the problem Total distance=Distance covered i)A to B + ii)B to C 85km + 45km= 130km Total Time = 1.3 hrs Average speed = Total Distance Covered/Total time => 130/1.3 km/hrs => 100km/hrs
  • 10. The quantity which specifies both the direction of motion and speed is velocity. • Velocity of a body is the displacement of the body per unit time. Velocity =Displacement/time taken • Since velocity has both magnitude and direction, it is a vector quantity.
  • 11. Example Speed with Direction is known as Velocity
  • 12. Average Velocity • Average velocity :- is the ratio of the total displacement to the total time taken. • Average velocity =Total Displacement/Total Time. • Average velocity is also the mean of the initial velocity u and final velocity v. • Average velocity= (initial velocity + finial velocity)/2 or (u+v)/2 • Speed and velocity have the same units m/s
  • 13. Example Problem Q. If a car changes its speed from 10m/s to 20m/s in just 5 sec. What is the average velocity of the car? Sol. u = 10m/s time taken v = 20m/s = 5sec Average velocity = (u + v)/2 (20m/s + 10m/s)/2 30m/s/2 15m/s
  • 14. The quantity which specifies changes in velocity is acceleration. • Acceleration :- is the rate of change of velocity. • Acceleration = (Final velocity – initial velocity) / 2 •If the velocity of a body changes from initial value u to final value v in time t, then acceleration a
  • 15. Example Four different ways to accelerate a car.
  • 16. Distance –Time Graph • Motion can be represented on the distance time graph. • In the graph distance is taken on the y – axis and time is taken on the x – axis. • The distance time graph for uniform speed is a straight line. • This is because in uniform speed a body travels equal distances in equal intervals of time.
  • 18. Derivation of three formula of motion • Let a body is moving with initial velocity ‘u’ with uniform acceleration ‘a’ it’s velocity become ‘v’ in time ‘t’ sec. In the meantime it covers the distance ‘s’ • The term would be in 1. Acceleration -> m/s2 2. Initial and final velocity -> m/s 3. Time -> sec 4. Distance -> m
  • 19. 1st Equation of motion • Acceleration = (v – u)/t a = (v - u)/t  at = v – u  u + at = v 1st equation of motion
  • 20. 2nd Equation of motion • Average velocity = (v + u)/2 • Distance Travelled = Av. Velocity + time s = (v + u)/2 x t Put v = u + at  s = (u + at + u)/2 x t  s = (2u+at)/2 x t  s = (2ut + at2) /2 s = ut + ½ at2 2nd Equation of motion
  • 21. 3rd Equation of motion • We know that v = u + at v – u = at  (v - u)/a =t • Put t = (v – u)/a in eq. s = ut + ½ at2 s = u{(v – u)/a} + ½a {(v-u)/2} 2 s = (uv - u2)/a + ½a{(v2 + u2 -2uv)/a2}  s = (uv - u2)/a + ½(v2 + u2 -2uv)/a  s = (uv - u2)/a + (v2 + u2 -2uv)/2a s = (2uv - 2u2 + v2 + u2 -2uv)/2a s = (v2 - u2 )/2a  2as = v2 - u2 3rd Equation of motion
  • 22. Circular motion • The motion of a body in a circular path is called circular motion. • Uniform circular motion :- If a body moves in a circular path with uniform speed, its motion is called uniform circular motion. • Uniform circular motion is accelerated motion because in a circular motion a body continuously changes its direction. • The circumference of a circle of radius r is given by 2лr. If a body takes time t to go once around the circular path, then the velocity v is given by v = 2лr/2