AnswerMean Mean is an average of a group of numbers or data poin.pdf

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Answer: Mean: Mean is an average of a group of numbers or data points. With a group of numbers, the mean is obtained by adding them and dividing by the number of numbers in the group. Median: The median is the middle number in a given sequence of numbers, taken as the average of the two middle numbers when the sequence has an even number of numbers Mode: The mode is the value that appears most often in a set of numbers or data. a). Given set of data is 3 1 2 4 2 2 4 1 4 4 1 1 1 1. Sum of the data points is 3+1+2+4+2+2+4+1+4+4+1+1+1+1=31 Number of data points is 14 By the definition mean=(sum of the numbers)/(number of data points) =(31/14) =2.214 Therefore mean is 2.214 2). To find median of given data first we heve to write the in ascending order. So , the given data in ascending order is as follows 1 1 1 1 1 1 2 2 2 3 4 4 4 4. Since the data has 14(even) number of points , so, we take average of the middle of the two numbers . So the madian is (2+2)/2 =2 Therefore the median is 2 3). In the given data 1 is repaeated more number of times when compared with the other numbers in the data . so, mode of the data is 1. Solution Answer: Mean: Mean is an average of a group of numbers or data points. With a group of numbers, the mean is obtained by adding them and dividing by the number of numbers in the group. Median: The median is the middle number in a given sequence of numbers, taken as the average of the two middle numbers when the sequence has an even number of numbers Mode: The mode is the value that appears most often in a set of numbers or data. a). Given set of data is 3 1 2 4 2 2 4 1 4 4 1 1 1 1. Sum of the data points is 3+1+2+4+2+2+4+1+4+4+1+1+1+1=31 Number of data points is 14 By the definition mean=(sum of the numbers)/(number of data points) =(31/14) =2.214 Therefore mean is 2.214 2). To find median of given data first we heve to write the in ascending order. So , the given data in ascending order is as follows 1 1 1 1 1 1 2 2 2 3 4 4 4 4. Since the data has 14(even) number of points , so, we take average of the middle of the two numbers . So the madian is (2+2)/2 =2 Therefore the median is 2 3). In the given data 1 is repaeated more number of times when compared with the other numbers in the data . so, mode of the data is 1..

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a). Given set of data is
3 1 2 4 2 2 4 1 4 4 1 1 1 1.
Sum of the data points is 3+1+2+4+2+2+4+1+4+4+1+1+1+1=31
Number of data points is 14
By the definition mean=(sum of the numbers)/(number of data points)
=(31/14)
=2.214
Therefore mean is 2.214
2). To find median of given data first we heve to write the in ascending order.
So , the given data in ascending order is as follows
1 1 1 1 1 1 2 2 2 3 4 4 4 4.
Since the data has 14(even) number of points , so, we take average of the middle of the two
numbers .
So the madian is (2+2)/2 =2
Therefore the median is 2
3). In the given data 1 is repaeated more number of times when compared with the other numbers
in the data .
so, mode of the data is 1.

Program 1 public class QueueUsingArray { private static final i.pdf

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PrimeRange.java import java.util.Scanner; public class PrimeRange { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner scan = new Scanner(System.in); System.out.println(\"Enter low range:\"); int low = scan.nextInt(); System.out.println(\"Enter high range:\"); int high = scan.nextInt(); for(int i=low; i<=high; i++){ if(isPrime(i)) System.out.print(i+\" \"); } } public static boolean isPrime(int n){ for (int f = 2; f < n / 2; f++) { if (n % f == 0) { return false; } } return true; } } Output: Enter low range: 10 Enter high range: 30 11 13 17 19 23 29 Solution PrimeRange.java import java.util.Scanner; public class PrimeRange { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner scan = new Scanner(System.in); System.out.println(\"Enter low range:\"); int low = scan.nextInt(); System.out.println(\"Enter high range:\"); int high = scan.nextInt(); for(int i=low; i<=high; i++){ if(isPrime(i)) System.out.print(i+\" \"); } } public static boolean isPrime(int n){ for (int f = 2; f < n / 2; f++) { if (n % f == 0) { return false; } } return true; } } Output: Enter low range: 10 Enter high range: 30 11 13 17 19 23 29.

PrimeRange.java import java.util.Scanner;public class PrimeRan.pdf

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opps no format is there...Solutionopps no format is there....pdf

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Note: Given Code modified as required and required methods added. Code: // class node class Node { // declare the required variable String data; Node next; // constructor Node(){} // constructor with arguments Node(String data) { this.data = data; next = null; } // method to get the data public String getData() { return data; } // method to set the data public void setData(String data) { this.data = data; } // method to get the next data public Node getNext() { return next; } // method to set the next data public void setNext(Node next) { this.next = next; } } // class for a linked list class MyLInkedList { Node head;alue into a list // method to add the v public void add(String num) { if (head == null) { head = new Node(num); } else{ Node temp = new Node(num); Node current = head; if (current != null) { while (current.getNext() != null) { current = current.getNext(); } current.setNext(temp); } } } // method to search a value from a list public void search(String num) { Node current = head; boolean flag=true; if (current != null) { while (current != null) { if(current.getData() == num) { System.out.println(\"Search value \"+ current.getData()+\" is available\"); flag=false; } current = current.getNext(); } if (flag==true) { System.out.println(\"Search value \"+ current.getData()+\" is not available\"); } } else { System.out.println(\"Linked list is empty\"); } } // method to delete a value from a list public void delete(String num) { //Node current = head; boolean flag=true; if (head == null) { System.out.println(\"Can\'t Delete, Linked list is empty\"); return; } if(head.getData() == num) { head=head.getNext(); return; } Node temp = new Node(num); Node cr = head; Node prev=null; while ((cr != null) && !(cr.getData() == num)) { prev=cr; cr = cr.getNext(); } prev.setNext(cr.getNext()); } // method to print the list public void print() { Node current = head; if (current != null) { while (current != null) { System.out.println(current.getData()); current = current.getNext(); } } } } // method to test the class public class MyLInkedListTester { // main method to perform the linked list operatrions public static void main(String args[]) { MyLInkedList llist = new MyLInkedList(); // insert the values into list llist.add(\"1\"); llist.add(\"2\"); llist.add(\"3\"); llist.add(\"4\"); // print the list values llist.print(); // sear the values in a list llist.search(\"1\"); llist.print(); // delete the value from a list llist.delete(\"4\"); System.out.println(\"List after deletion:\"); llist.print(); } } Result: 1 2 3 4 Search value 1 is available 1 2 3 4 List after deletion: 1 2 3 Solution Note: Given Code modified as required and required methods added. Code: // class node class Node { // declare the required variable String data; Node next; // constructor Node(){} // constructor with arguments Node(String data) { this.data = data; next = null; } // method to get the data public String getData() { return data; } // method to set the data public void se.

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AnswerMean Mean is an average of a group of numbers or data poin.pdf

1. Answer: Mean: Mean is an average of a group of numbers or data points. With a group of numbers, the mean is obtained by adding them and dividing by the number of numbers in the group. Median: The median is the middle number in a given sequence of numbers, taken as the average of the two middle numbers when the sequence has an even number of numbers Mode: The mode is the value that appears most often in a set of numbers or data. a). Given set of data is 3 1 2 4 2 2 4 1 4 4 1 1 1 1. Sum of the data points is 3+1+2+4+2+2+4+1+4+4+1+1+1+1=31 Number of data points is 14 By the definition mean=(sum of the numbers)/(number of data points) =(31/14) =2.214 Therefore mean is 2.214 2). To find median of given data first we heve to write the in ascending order. So , the given data in ascending order is as follows 1 1 1 1 1 1 2 2 2 3 4 4 4 4. Since the data has 14(even) number of points , so, we take average of the middle of the two numbers . So the madian is (2+2)/2 =2 Therefore the median is 2 3). In the given data 1 is repaeated more number of times when compared with the other numbers in the data . so, mode of the data is 1. Solution Answer: Mean: Mean is an average of a group of numbers or data points. With a group of numbers, the mean is obtained by adding them and dividing by the number of numbers in the group. Median: The median is the middle number in a given sequence of numbers, taken as the average of the two middle numbers when the sequence has an even number of numbers Mode: The mode is the value that appears most often in a set of numbers or data.

2. a). Given set of data is 3 1 2 4 2 2 4 1 4 4 1 1 1 1. Sum of the data points is 3+1+2+4+2+2+4+1+4+4+1+1+1+1=31 Number of data points is 14 By the definition mean=(sum of the numbers)/(number of data points) =(31/14) =2.214 Therefore mean is 2.214 2). To find median of given data first we heve to write the in ascending order. So , the given data in ascending order is as follows 1 1 1 1 1 1 2 2 2 3 4 4 4 4. Since the data has 14(even) number of points , so, we take average of the middle of the two numbers . So the madian is (2+2)/2 =2 Therefore the median is 2 3). In the given data 1 is repaeated more number of times when compared with the other numbers in the data . so, mode of the data is 1.

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