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Abaqus/CFD – Sample Problems
Abaqus 6.10
Contents
1. Oscillatory Laminar Plane Poiseuille Flow
2. Flow in Shear Driven Cavities
3. Buoyancy Driven Flow in Cavities
4. Turbulent Flow in a Rectangular Channel
5. Von Karman Vortex Street Behind a Circular Cylinder
6. Flow Over a Backward Facing Step
2
This document provides a set of sample problems that can be used
as a starting point to perform rigorous verification and validation
studies. The associated Python scripts that can be used to create
the Abaqus/CAE database and associated input files are provided.
1. Oscillatory Laminar Plane Poiseuille
Flow
Oscillatory Laminar Plane Poiseuille Flow
Overview
This example compares the prediction of the time-dependent velocity profile in a channel
subjected to an oscillatory pressure gradient to the analytical solution.
Problem description
A rectangular 2-dimensional channel of width = 1m and length = 2m is considered. An
oscillatory pressure gradient (with zero mean) is imposed at the inlet. The analysis is carried
out in two steps. In the first analysis step, a constant pressure gradient is prescribed for the
first 5 seconds of the simulation to initialize the velocity field to match that of the analytical
steady-state solution. In the second analysis step, the flow is subjected to an oscillatory
pressure gradient. A 40x20 uniform mesh is used for this problem. Two dimensional
geometry is modeled as three dimensional with one element in thickness direction.
2 m
1 m
x
z
Schematic of the geometry used
Wall boundary condition
Outlet
Wall boundary condition
Time-dependent inlet pressure
0 cos( ( ))
o
dP
P t t
dx

 
Inlet pressure profile
Oscillatory Laminar Plane Poiseuille Flow
Features
Laminar flow
Time-dependent pressure inlet
Multi-step analysis
Boundary conditions
Pressure inlet
t < to : p = 7.024
t > to : p = 10*Cos((t-to)) ; to = 5,  = p/5
Pressure outlet (p = 0)
No-slip wall boundary condition on top and bottom (V = 0)
Analytical solution
References
Fluid Mechanics, Second Edition: Volume 6 (Course of Theoretical Physics), Authors: L. D. Landau,
E.M. Lifshitz
5













 


)
cos(
)
cos(
1
2
Re
)
,
(
2
h
h
z
e
i
P
t
y
u t
i
s
o









i


t
i
e
P
dx
dP 
0




2

s

• h is the half-channel width
• Po is the amplitude of
pressure gradient oscillation
•  is the circular frequency
Oscillatory Laminar Plane Poiseuille Flow
Files
ex1_oscillatory_planeflow.py
ex1_oscillatory_planeflow_mesh.inp
6
Results
Velocity profile: Comparison with analytical solution
T= 5 sec
T= 10 sec
2. Flow in Shear Driven Cavities
7
Flow in Shear Driven Cavities
Overview
This sample problem compares the prediction of velocity profiles in shear-driven cavities of
different shapes. 2-dimensional 900, 450 and 150 cavities are considered. Shear driven flow
in a cubical box is also presented. Velocity profiles in each of these cases are compared
against numerical results available in literature.
Problem description
The following cavity configurations and Reynolds’ numbers are presented
900 Cavity: Reynolds number = 100, 3200; Mesh: 129x129x1
450 Cavity: Reynolds number = 100; Mesh: 512x512x1
150 Cavity: Reynolds number = 100; Mesh: 256x256x1
Cubical box: Reynolds number = 400; Mesh: 32x32x32
(d) Cubical box
(a) 900 Cavity
1 m
1 m
(b) 450 Cavity
1 m
1 m
(c) 150 Cavity
1 m
1 m
1 m
1 m
1 m
Flow in Shear Driven Cavities
Features
Laminar shear driven flow
Boundary conditions
Specified velocity at top plane to match flow Reynolds’ number
No-slip at all other planes (V = 0)
Hydrostatic mode is eliminated by setting reference pressure to zero at a single node
References
1. “High-Re Solutions for Incompressible Flow Using the Navier-Stokes Equations and a Multigrid Method”
U. Ghia, K. N. Ghia, and C. T. Shin
Journal of Computational Physics 48, 387-411 (1982)
2. “Numerical solutions of 2-D steady incompressible flow in a driven skewed cavity”
Ercan Erturk∗ and Bahtiyar Dursun
ZAMM · Z. Angew. Math. Mech. 87, No. 5, 377 – 392 (2007)
3. "Flow topology in a steady three-dimensional lid-driven cavity"
T.W.H. Sheu, S.F. Tsai, Computers & Fluids, 31, 911–934 (2002)
9
Flow in Shear Driven Cavities
Results
Velocities along horizontal and vertical centerlines
10
900 Cavity
Re = 3200
Re = 100
Flow in Shear Driven Cavities
Results
Velocities along horizontal and vertical centerlines
11
Skew Cavity (450 and 150)
150
450
Flow in Shear Driven Cavities
Results
12
Cubical Box
Velocity vectors
Velocities along horizontal and vertical centerlines
Flow in Shear Driven Cavities
Files
ex2_sheardriven_cavity.py
ex2_cavity15deg_mesh.inp
ex2_cavity45deg_mesh.inp
ex2_cubicalbox_mesh.inp
ex2_sqcavity_mesh.inp
13
3. Buoyancy Driven Flow in
Cavities
14
Buoyancy Driven Flow in Cavities
Overview
This sample problem compares the prediction of velocity profiles due to buoyancy driven flow
in square and cubical cavities. The cavities are differentially heated to obtain a temperature
gradient. Velocity profiles in each of these cases are compared against numerical results
available in the literature.
Problem description
The material properties are chosen to match the desired Rayleigh number, Ra
Square Cavity: Rayleigh number = 1e3, 1e6
Cubical Cavity: Rayleigh number = 1e4
T = 1.0 T = 0.0
q = 0.0
q = 0.0
x = 0, T = 1.0 x = 1.0, T = 1.0
All other faces are
adiabatic
3
,Kinematic viscosity
,Thermal diffusivity
,Thermal expansion coefficient
g, Acceleration due to gravity
g L T
Ra







Buoyancy Driven Flow in Cavities
Features
Buoyancy driven flow
Boussinesq body forces
Boundary conditions
No-slip velocity boundary condition on all the planes (V = 0)
Specified temperatures
Hydrostatic mode is eliminated by setting reference pressure to zero at a single node
References
1. “Natural Convection in a Square Cavity: A Comparison Exercise”
G. de Vahl Davis and I. P. Jones
International Journal for Numerical Methods in Fluids, 3, 227-248, (1983)
2. "Benchmark solutions for natural convection in a cubic cavity using the high-order time–space method"
Shinichiro Wakashima, Takeo S. Saitoh
International Journal of Heat and Mass Transfer, 47, 853–864, (2004)
16
Buoyancy Driven Flow in Cavities
Results
17
2D Square Cavity
Ra = 1000, Pr = 0.71
Temperature Velocity
T = 1.0 T = 0.0
q = 0.0
q = 0.0
Temperature Velocity
Present Benchmark
(de Vahl Davis)
u 3.695 3.697
x 0.1781 0.178
Present Benchmark
(de Vahl Davis)
u 3.654 3.649
x 0.8129 0.813
Present Benchmark
(de Vahl Davis)
u 219.747 219.36
x 0.0375 0.0379
Present Benchmark
(de Vahl Davis)
u 65.9 64.63
x 0.85 0.85
Ra = 1.0e6 , Pr = 0.71
Buoyancy Driven Flow in Cavities
Results
18
Cubical Box
Ra = 1.0e4, Pr = 0.71
Temperature contours at the mid plane
(y=0.5)
Benchmark Present
Vorticity contours at the mid plane (y=0.5)
Benchmark Present
Benchmark
(Wakashima &
Saitoh (2004))
1.1018 0.1984
(z = 0.8250)
0.2216
(x = 0.1177)
Abaqus/CFD 1.1017 0.1986 0.2211
Error -0.009% 0.1% 0.2%
)
0
,
0
,
0
(
2
 )
,
5
.
0
,
5
.
0
(
max
1 z
U )
5
.
0
,
5
.
0
,
(
max
3 x
U
Buoyancy Driven Flow in Cavities
Files
ex3_buoyancydriven_flow.py
ex3_sqcavity_mesh.inp
ex3_cubicbox_mesh.inp
19
4. Turbulent Flow in a
Rectangular Channel
20
Turbulent Flow in a Rectangular Channel
Overview
This example models the turbulent flow in a rectangular channel at a friction Reynolds
number = 180 and Reynolds number (based on mean velocity) = 5600. The one equation
Spalart-Allmaras turbulence model is used. The results are compared with direct numerical
simulation (DNS) results available in the literature as well as experimental results.
Abaqus/CFD results at a friction Reynolds number = 395 and Reynolds number (based on
mean velocity) = 13750 are also presented.
Problem description
A rectangular 2-dimensional channel of width = 1 unit and length = 10 units is considered. A
pressure gradient is imposed along the length of the channel by means of specified pressure
at the inlet and zero pressure at the outlet. The pressure gradient is chosen to impose the
desired friction Reynolds number for the flow.
Outlet
H = 1
L = 10
Wall boundary condition
Wall boundary condition
Inlet
Turbulent Flow in a Rectangular Channel
Problem description (cont’d)
The Reynolds number is defined as Re = rUavH/m
The friction Reynolds number is defined as Ret = rut(H/2)/m , where ut is the friction
velocity defined as
Features
Turbulent flow
Spalart-Allmaras turbulence model
Boundary conditions
No-slip velocity boundary condition on channel walls(V = 0)
Set through thickness velocity components to zero
Distance function = 0, Kinematic turbulent viscosity = 0 at No-slip velocity boundary condition
Mesh
Mesh – 50 (Streamwise) X 91 (Normal) X 1 (Through thickness)
y+ at first grid point ~ 0.046
22
w
ut
t
r
 tw = wall shear stress
Turbulent Flow in a Rectangular Channel
References
1. “Turbulence statistics in fully developed channel flow at low Reynolds number”
J. Kim, P. Moin and R. Moser
Journal of Fluid Mechanics, 177, 133-166, (1987)
2. “The structure of the viscous sublayer and the adjacent wall region in a turbulent channel flow”
H. Eckelmann
Journal of Fluid Mechanics, 65, 439, (1974)
23
Turbulent Flow in a Rectangular Channel
Results
“Law of the wall”
24
,
u y
U
u y
u
t
t 
 
 
• Results are presented at Ret  180
• Abaqus/CFD results at Ret  395 is
also presented
Turbulent Flow in a Rectangular Channel
Results
25
Velocity profile
Turbulent Flow in a Rectangular Channel
Files
ex4_turb_channelflow.py
ex4_turb_channelflow_mesh.inp
Note
Abaqus/CFD results at a friction Reynolds number ~ 395 and Reynolds number
(based on mean velocity) ~ 13750 can be obtained by setting a pressure
gradient of 0.0573
26
5. Von Karman Vortex Street
Behind a Circular Cylinder
27
Von Karman Vortex Street Behind a Circular Cylinder
Overview
This example simulates the Von Karman vortex street behind a circular cylinder at a flow
Reynolds number of 100 based on the cylinder diameter. The frequency of the vortex
shedding is compared with results available in the literature.
Problem description
The computational domain for the vortex shedding calculations consists of an interior square
region (-4 < x < 4; -4 < y < 4) surrounding a cylinder of unit diameter. The domain is
extended in the wake of cylinder up to x = 20 units
H = 8
D = 1
H = 20
Inlet Outlet
“Tow-tank” condition
Von Karman Vortex Street Behind a Circular Cylinder
Features
Unsteady laminar flow
Reynolds number = rUinlet D/m
Fluid Properties
Density = 1 unit
Viscosity = 0.01 units
Boundary conditions
Tow tank condition at top and bottom walls:
U = 1, V = 0
Inlet velocity: Uinlet = 1, V = 0
Set through thickness velocity components to zero
Outlet: P = 0
Cylinder surface: No-slip velocity boundary condition (V = 0)
29
Von Karman Vortex Street Behind a Circular Cylinder
References
1. Transient flow past a circular cylinder: a benchmark solution”,
M. S. Engelman and M. A. Jamnia
International Journal for Numerical Methods in Fluids, 11, 985-1000, (1990)
30
Von Karman Vortex Street Behind a Circular Cylinder
The results are consistent with the Strouhal numbers reported in the reference
(0.172-0.173)
The frequency of the vortex shedding is obtained as the half of the peak frequency
obtained by a FFT of kinetic energy plot (from t = 200 sec to 300 sec)
31
Results
Total number
of element
Strouhal Number* t
Coarse 1760 0.1749 0.03
Fine 28160 0.1735 0.0075
* St = fD/Uinlet , f is the frequency of vortex shedding
Von Karman Vortex Street Behind a Circular Cylinder
Kinetic energy
32
Results
Von Karman Vortex Street Behind a Circular Cylinder
33
Results
Velocity contour plot at t = 300 sec
Pressure line plot at t = 300 sec
6. Flow Over a Backward
Facing Step
34
Flow Over a Backward Facing Step
Overview
This example simulates the laminar flow over a backward facing step at a Reynolds number
of 800 based on channel height. The results are compared with numerical as well as
experimental results available in literature.
Problem description
The computational domain for the flow calculations consists of an rectangular region (0 < x <
30; -0.5 < y < 0.5). The flow enters the solution domain from 0< y < 0.5 while -0.5 < y < 0.0
represents the step. A parabolic velocity profile is specified at the inlet.
Re av
V H
r
m

H = 1
L = 30
Vx(y) = 24y(0.5 – y)
Vav = 1.0 Outlet
P = 0
No-slip
No-slip
No-slip
Flow Over a Backward Facing Step
Features
Steady laminar flow
Fluid Properties
Density = 1 unit
Viscosity = 0.00125 units (the viscosity is chosen so as to set the flow Reynolds
number to 800)
Boundary conditions
Set through thickness velocity components to zero
No-slip velocity boundary condition at top and bottom walls
Vx = 0, Vy = 0
Inlet velocity: Parabolic velocity profile - Vx = f(y)
Vy = 0
Outlet: P = 0
No-slip velocity boundary condition at the step boundary
Vx = 0, Vy = 0
36
Flow Over a Backward Facing Step
References
“A test problem for outflow boundary conditions – Flow over a backward-facing step”
D. K. Gartling, International Journal for Numerical Methods in Fluids
Vol 11, 953-967, (1990)
37
Flow Over a Backward Facing Step
38
Results
Mesh
(Across the channel x along
the channel length)
L1
Length from the step face to the
lower re-attachment point
L2
Length from the step
face to upper
separation point
L3
Length of the upper
separation bubble
Gartling (1990) 40x800 6.1 4.85 10.48
Abaqus/CFD Fine
80x1200x1 (Zone 1)
80x832x1 (Zone 2)
5.9919 4.9113 10.334
Abaqus/CFD Medium
40x600x1 (Zone 1)
40x416x1 (Zone 2)
5.7471 4.8379 10.101
Abaqus/CFD Coarse
20x300x1 (Zone 1)
20x208x1 (Zone 2)
4.5018 3.9659 8.7748
Elements used by Gartling (1990) were biquadratic in velocity and linear discontinuous pressure elements. In
contrast, the fluid elements in Abaqus/CFD use linear discontinuous in velocity and linear continuous in
pressure.
Zone 1 (0 < x < 15)
Uniform mesh
x, y
Zone 2 (15 < x < 30)
Graded mesh
x  2x, y = constant
L2
L3
L1
Flow Over a Backward Facing Step
39
Results
Pressure line plot (0 < x < 30)
Velocity line plot (0 < x < 15)
Out of plane vorticity (0 < x < 30)
Flow Over Backward Facing Step
Horizontal velocity at x = 7 & x = 15
40
Results
Flow Over Backward Facing Step
Vertical velocity at x = 7 & x = 15
41
Results
Flow Over Backward Facing Step
Files
ex6_backwardfacingstep.py
ex6_backwardfacingstep_coarse.inp
ex6_backwardfacingstep_medium.inp
ex6_backwardfacingstep_fine.inp
coarse_parabolic_inlet_velocity.inp
medium_parabolic_inlet_velocity.inp
fine_parabolic_inlet_velocity.inp
Note
The models require a parabolic velocity profile at the inlet. This needs to be
manually included as boundary condition in the generated input file.
The parabolic velocity profile required is provided in files
coarse_parabolic_inlet_velocity.inp, medium_parabolic_inlet_velocity.inp and
fine_parabolic_inlet_velocity.inp for coarse, medium and fine meshes,
respectively.
42

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Abaqus CFD-Sample Problems

  • 1. Abaqus/CFD – Sample Problems Abaqus 6.10
  • 2. Contents 1. Oscillatory Laminar Plane Poiseuille Flow 2. Flow in Shear Driven Cavities 3. Buoyancy Driven Flow in Cavities 4. Turbulent Flow in a Rectangular Channel 5. Von Karman Vortex Street Behind a Circular Cylinder 6. Flow Over a Backward Facing Step 2 This document provides a set of sample problems that can be used as a starting point to perform rigorous verification and validation studies. The associated Python scripts that can be used to create the Abaqus/CAE database and associated input files are provided.
  • 3. 1. Oscillatory Laminar Plane Poiseuille Flow
  • 4. Oscillatory Laminar Plane Poiseuille Flow Overview This example compares the prediction of the time-dependent velocity profile in a channel subjected to an oscillatory pressure gradient to the analytical solution. Problem description A rectangular 2-dimensional channel of width = 1m and length = 2m is considered. An oscillatory pressure gradient (with zero mean) is imposed at the inlet. The analysis is carried out in two steps. In the first analysis step, a constant pressure gradient is prescribed for the first 5 seconds of the simulation to initialize the velocity field to match that of the analytical steady-state solution. In the second analysis step, the flow is subjected to an oscillatory pressure gradient. A 40x20 uniform mesh is used for this problem. Two dimensional geometry is modeled as three dimensional with one element in thickness direction. 2 m 1 m x z Schematic of the geometry used Wall boundary condition Outlet Wall boundary condition Time-dependent inlet pressure 0 cos( ( )) o dP P t t dx    Inlet pressure profile
  • 5. Oscillatory Laminar Plane Poiseuille Flow Features Laminar flow Time-dependent pressure inlet Multi-step analysis Boundary conditions Pressure inlet t < to : p = 7.024 t > to : p = 10*Cos((t-to)) ; to = 5,  = p/5 Pressure outlet (p = 0) No-slip wall boundary condition on top and bottom (V = 0) Analytical solution References Fluid Mechanics, Second Edition: Volume 6 (Course of Theoretical Physics), Authors: L. D. Landau, E.M. Lifshitz 5                  ) cos( ) cos( 1 2 Re ) , ( 2 h h z e i P t y u t i s o          i   t i e P dx dP  0     2  s  • h is the half-channel width • Po is the amplitude of pressure gradient oscillation •  is the circular frequency
  • 6. Oscillatory Laminar Plane Poiseuille Flow Files ex1_oscillatory_planeflow.py ex1_oscillatory_planeflow_mesh.inp 6 Results Velocity profile: Comparison with analytical solution T= 5 sec T= 10 sec
  • 7. 2. Flow in Shear Driven Cavities 7
  • 8. Flow in Shear Driven Cavities Overview This sample problem compares the prediction of velocity profiles in shear-driven cavities of different shapes. 2-dimensional 900, 450 and 150 cavities are considered. Shear driven flow in a cubical box is also presented. Velocity profiles in each of these cases are compared against numerical results available in literature. Problem description The following cavity configurations and Reynolds’ numbers are presented 900 Cavity: Reynolds number = 100, 3200; Mesh: 129x129x1 450 Cavity: Reynolds number = 100; Mesh: 512x512x1 150 Cavity: Reynolds number = 100; Mesh: 256x256x1 Cubical box: Reynolds number = 400; Mesh: 32x32x32 (d) Cubical box (a) 900 Cavity 1 m 1 m (b) 450 Cavity 1 m 1 m (c) 150 Cavity 1 m 1 m 1 m 1 m 1 m
  • 9. Flow in Shear Driven Cavities Features Laminar shear driven flow Boundary conditions Specified velocity at top plane to match flow Reynolds’ number No-slip at all other planes (V = 0) Hydrostatic mode is eliminated by setting reference pressure to zero at a single node References 1. “High-Re Solutions for Incompressible Flow Using the Navier-Stokes Equations and a Multigrid Method” U. Ghia, K. N. Ghia, and C. T. Shin Journal of Computational Physics 48, 387-411 (1982) 2. “Numerical solutions of 2-D steady incompressible flow in a driven skewed cavity” Ercan Erturk∗ and Bahtiyar Dursun ZAMM · Z. Angew. Math. Mech. 87, No. 5, 377 – 392 (2007) 3. "Flow topology in a steady three-dimensional lid-driven cavity" T.W.H. Sheu, S.F. Tsai, Computers & Fluids, 31, 911–934 (2002) 9
  • 10. Flow in Shear Driven Cavities Results Velocities along horizontal and vertical centerlines 10 900 Cavity Re = 3200 Re = 100
  • 11. Flow in Shear Driven Cavities Results Velocities along horizontal and vertical centerlines 11 Skew Cavity (450 and 150) 150 450
  • 12. Flow in Shear Driven Cavities Results 12 Cubical Box Velocity vectors Velocities along horizontal and vertical centerlines
  • 13. Flow in Shear Driven Cavities Files ex2_sheardriven_cavity.py ex2_cavity15deg_mesh.inp ex2_cavity45deg_mesh.inp ex2_cubicalbox_mesh.inp ex2_sqcavity_mesh.inp 13
  • 14. 3. Buoyancy Driven Flow in Cavities 14
  • 15. Buoyancy Driven Flow in Cavities Overview This sample problem compares the prediction of velocity profiles due to buoyancy driven flow in square and cubical cavities. The cavities are differentially heated to obtain a temperature gradient. Velocity profiles in each of these cases are compared against numerical results available in the literature. Problem description The material properties are chosen to match the desired Rayleigh number, Ra Square Cavity: Rayleigh number = 1e3, 1e6 Cubical Cavity: Rayleigh number = 1e4 T = 1.0 T = 0.0 q = 0.0 q = 0.0 x = 0, T = 1.0 x = 1.0, T = 1.0 All other faces are adiabatic 3 ,Kinematic viscosity ,Thermal diffusivity ,Thermal expansion coefficient g, Acceleration due to gravity g L T Ra       
  • 16. Buoyancy Driven Flow in Cavities Features Buoyancy driven flow Boussinesq body forces Boundary conditions No-slip velocity boundary condition on all the planes (V = 0) Specified temperatures Hydrostatic mode is eliminated by setting reference pressure to zero at a single node References 1. “Natural Convection in a Square Cavity: A Comparison Exercise” G. de Vahl Davis and I. P. Jones International Journal for Numerical Methods in Fluids, 3, 227-248, (1983) 2. "Benchmark solutions for natural convection in a cubic cavity using the high-order time–space method" Shinichiro Wakashima, Takeo S. Saitoh International Journal of Heat and Mass Transfer, 47, 853–864, (2004) 16
  • 17. Buoyancy Driven Flow in Cavities Results 17 2D Square Cavity Ra = 1000, Pr = 0.71 Temperature Velocity T = 1.0 T = 0.0 q = 0.0 q = 0.0 Temperature Velocity Present Benchmark (de Vahl Davis) u 3.695 3.697 x 0.1781 0.178 Present Benchmark (de Vahl Davis) u 3.654 3.649 x 0.8129 0.813 Present Benchmark (de Vahl Davis) u 219.747 219.36 x 0.0375 0.0379 Present Benchmark (de Vahl Davis) u 65.9 64.63 x 0.85 0.85 Ra = 1.0e6 , Pr = 0.71
  • 18. Buoyancy Driven Flow in Cavities Results 18 Cubical Box Ra = 1.0e4, Pr = 0.71 Temperature contours at the mid plane (y=0.5) Benchmark Present Vorticity contours at the mid plane (y=0.5) Benchmark Present Benchmark (Wakashima & Saitoh (2004)) 1.1018 0.1984 (z = 0.8250) 0.2216 (x = 0.1177) Abaqus/CFD 1.1017 0.1986 0.2211 Error -0.009% 0.1% 0.2% ) 0 , 0 , 0 ( 2  ) , 5 . 0 , 5 . 0 ( max 1 z U ) 5 . 0 , 5 . 0 , ( max 3 x U
  • 19. Buoyancy Driven Flow in Cavities Files ex3_buoyancydriven_flow.py ex3_sqcavity_mesh.inp ex3_cubicbox_mesh.inp 19
  • 20. 4. Turbulent Flow in a Rectangular Channel 20
  • 21. Turbulent Flow in a Rectangular Channel Overview This example models the turbulent flow in a rectangular channel at a friction Reynolds number = 180 and Reynolds number (based on mean velocity) = 5600. The one equation Spalart-Allmaras turbulence model is used. The results are compared with direct numerical simulation (DNS) results available in the literature as well as experimental results. Abaqus/CFD results at a friction Reynolds number = 395 and Reynolds number (based on mean velocity) = 13750 are also presented. Problem description A rectangular 2-dimensional channel of width = 1 unit and length = 10 units is considered. A pressure gradient is imposed along the length of the channel by means of specified pressure at the inlet and zero pressure at the outlet. The pressure gradient is chosen to impose the desired friction Reynolds number for the flow. Outlet H = 1 L = 10 Wall boundary condition Wall boundary condition Inlet
  • 22. Turbulent Flow in a Rectangular Channel Problem description (cont’d) The Reynolds number is defined as Re = rUavH/m The friction Reynolds number is defined as Ret = rut(H/2)/m , where ut is the friction velocity defined as Features Turbulent flow Spalart-Allmaras turbulence model Boundary conditions No-slip velocity boundary condition on channel walls(V = 0) Set through thickness velocity components to zero Distance function = 0, Kinematic turbulent viscosity = 0 at No-slip velocity boundary condition Mesh Mesh – 50 (Streamwise) X 91 (Normal) X 1 (Through thickness) y+ at first grid point ~ 0.046 22 w ut t r  tw = wall shear stress
  • 23. Turbulent Flow in a Rectangular Channel References 1. “Turbulence statistics in fully developed channel flow at low Reynolds number” J. Kim, P. Moin and R. Moser Journal of Fluid Mechanics, 177, 133-166, (1987) 2. “The structure of the viscous sublayer and the adjacent wall region in a turbulent channel flow” H. Eckelmann Journal of Fluid Mechanics, 65, 439, (1974) 23
  • 24. Turbulent Flow in a Rectangular Channel Results “Law of the wall” 24 , u y U u y u t t      • Results are presented at Ret  180 • Abaqus/CFD results at Ret  395 is also presented
  • 25. Turbulent Flow in a Rectangular Channel Results 25 Velocity profile
  • 26. Turbulent Flow in a Rectangular Channel Files ex4_turb_channelflow.py ex4_turb_channelflow_mesh.inp Note Abaqus/CFD results at a friction Reynolds number ~ 395 and Reynolds number (based on mean velocity) ~ 13750 can be obtained by setting a pressure gradient of 0.0573 26
  • 27. 5. Von Karman Vortex Street Behind a Circular Cylinder 27
  • 28. Von Karman Vortex Street Behind a Circular Cylinder Overview This example simulates the Von Karman vortex street behind a circular cylinder at a flow Reynolds number of 100 based on the cylinder diameter. The frequency of the vortex shedding is compared with results available in the literature. Problem description The computational domain for the vortex shedding calculations consists of an interior square region (-4 < x < 4; -4 < y < 4) surrounding a cylinder of unit diameter. The domain is extended in the wake of cylinder up to x = 20 units H = 8 D = 1 H = 20 Inlet Outlet “Tow-tank” condition
  • 29. Von Karman Vortex Street Behind a Circular Cylinder Features Unsteady laminar flow Reynolds number = rUinlet D/m Fluid Properties Density = 1 unit Viscosity = 0.01 units Boundary conditions Tow tank condition at top and bottom walls: U = 1, V = 0 Inlet velocity: Uinlet = 1, V = 0 Set through thickness velocity components to zero Outlet: P = 0 Cylinder surface: No-slip velocity boundary condition (V = 0) 29
  • 30. Von Karman Vortex Street Behind a Circular Cylinder References 1. Transient flow past a circular cylinder: a benchmark solution”, M. S. Engelman and M. A. Jamnia International Journal for Numerical Methods in Fluids, 11, 985-1000, (1990) 30
  • 31. Von Karman Vortex Street Behind a Circular Cylinder The results are consistent with the Strouhal numbers reported in the reference (0.172-0.173) The frequency of the vortex shedding is obtained as the half of the peak frequency obtained by a FFT of kinetic energy plot (from t = 200 sec to 300 sec) 31 Results Total number of element Strouhal Number* t Coarse 1760 0.1749 0.03 Fine 28160 0.1735 0.0075 * St = fD/Uinlet , f is the frequency of vortex shedding
  • 32. Von Karman Vortex Street Behind a Circular Cylinder Kinetic energy 32 Results
  • 33. Von Karman Vortex Street Behind a Circular Cylinder 33 Results Velocity contour plot at t = 300 sec Pressure line plot at t = 300 sec
  • 34. 6. Flow Over a Backward Facing Step 34
  • 35. Flow Over a Backward Facing Step Overview This example simulates the laminar flow over a backward facing step at a Reynolds number of 800 based on channel height. The results are compared with numerical as well as experimental results available in literature. Problem description The computational domain for the flow calculations consists of an rectangular region (0 < x < 30; -0.5 < y < 0.5). The flow enters the solution domain from 0< y < 0.5 while -0.5 < y < 0.0 represents the step. A parabolic velocity profile is specified at the inlet. Re av V H r m  H = 1 L = 30 Vx(y) = 24y(0.5 – y) Vav = 1.0 Outlet P = 0 No-slip No-slip No-slip
  • 36. Flow Over a Backward Facing Step Features Steady laminar flow Fluid Properties Density = 1 unit Viscosity = 0.00125 units (the viscosity is chosen so as to set the flow Reynolds number to 800) Boundary conditions Set through thickness velocity components to zero No-slip velocity boundary condition at top and bottom walls Vx = 0, Vy = 0 Inlet velocity: Parabolic velocity profile - Vx = f(y) Vy = 0 Outlet: P = 0 No-slip velocity boundary condition at the step boundary Vx = 0, Vy = 0 36
  • 37. Flow Over a Backward Facing Step References “A test problem for outflow boundary conditions – Flow over a backward-facing step” D. K. Gartling, International Journal for Numerical Methods in Fluids Vol 11, 953-967, (1990) 37
  • 38. Flow Over a Backward Facing Step 38 Results Mesh (Across the channel x along the channel length) L1 Length from the step face to the lower re-attachment point L2 Length from the step face to upper separation point L3 Length of the upper separation bubble Gartling (1990) 40x800 6.1 4.85 10.48 Abaqus/CFD Fine 80x1200x1 (Zone 1) 80x832x1 (Zone 2) 5.9919 4.9113 10.334 Abaqus/CFD Medium 40x600x1 (Zone 1) 40x416x1 (Zone 2) 5.7471 4.8379 10.101 Abaqus/CFD Coarse 20x300x1 (Zone 1) 20x208x1 (Zone 2) 4.5018 3.9659 8.7748 Elements used by Gartling (1990) were biquadratic in velocity and linear discontinuous pressure elements. In contrast, the fluid elements in Abaqus/CFD use linear discontinuous in velocity and linear continuous in pressure. Zone 1 (0 < x < 15) Uniform mesh x, y Zone 2 (15 < x < 30) Graded mesh x  2x, y = constant L2 L3 L1
  • 39. Flow Over a Backward Facing Step 39 Results Pressure line plot (0 < x < 30) Velocity line plot (0 < x < 15) Out of plane vorticity (0 < x < 30)
  • 40. Flow Over Backward Facing Step Horizontal velocity at x = 7 & x = 15 40 Results
  • 41. Flow Over Backward Facing Step Vertical velocity at x = 7 & x = 15 41 Results
  • 42. Flow Over Backward Facing Step Files ex6_backwardfacingstep.py ex6_backwardfacingstep_coarse.inp ex6_backwardfacingstep_medium.inp ex6_backwardfacingstep_fine.inp coarse_parabolic_inlet_velocity.inp medium_parabolic_inlet_velocity.inp fine_parabolic_inlet_velocity.inp Note The models require a parabolic velocity profile at the inlet. This needs to be manually included as boundary condition in the generated input file. The parabolic velocity profile required is provided in files coarse_parabolic_inlet_velocity.inp, medium_parabolic_inlet_velocity.inp and fine_parabolic_inlet_velocity.inp for coarse, medium and fine meshes, respectively. 42