3. ESSENTIAL QUESTIONS
• How do you find perimeters and areas of
parallelograms?
• How do you find perimeters and areas of
triangles?
• How do you find areas of trapezoids?
• How do you find areas of rhombi and kites?
4. VOCABULARY
1. Base of a Parallelogram:
2. Height of a Parallelogram:
3. Base of a Triangle:
4. Height of a Triangle:
5. Height of a Trapezoid:
5. VOCABULARY
1. Base of a Parallelogram:
2. Height of a Parallelogram:
3. Base of a Triangle:
4. Height of a Triangle:
5. Height of a Trapezoid:
Can be any side of a parallelogram
6. VOCABULARY
1. Base of a Parallelogram:
2. Height of a Parallelogram:
3. Base of a Triangle:
4. Height of a Triangle:
5. Height of a Trapezoid:
Can be any side of a parallelogram
The perpendicular distance between
any two parallel bases of a parallelogram
7. VOCABULARY
1. Base of a Parallelogram:
2. Height of a Parallelogram:
3. Base of a Triangle:
4. Height of a Triangle:
5. Height of a Trapezoid:
Can be any side of a parallelogram
The perpendicular distance between
any two parallel bases of a parallelogram
Can be any side of a triangle
8. VOCABULARY
1. Base of a Parallelogram:
2. Height of a Parallelogram:
3. Base of a Triangle:
4. Height of a Triangle:
5. Height of a Trapezoid:
Can be any side of a parallelogram
The perpendicular distance between
any two parallel bases of a parallelogram
Can be any side of a triangle
The length of a segment perpendicular to a
base to the opposite vertex
9. VOCABULARY
1. Base of a Parallelogram:
2. Height of a Parallelogram:
3. Base of a Triangle:
4. Height of a Triangle:
5. Height of a Trapezoid:
Can be any side of a parallelogram
The perpendicular distance between
any two parallel bases of a parallelogram
Can be any side of a triangle
The length of a segment perpendicular to a
base to the opposite vertex
The perpendicular distance between bases
12. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
13. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
14. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
15. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh
16. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
17. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
a2
+122
= 202
18. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
a2
+122
= 202
a2
+144 = 400
19. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
a2
+122
= 202
a2
+144 = 400
−144 −144
20. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
a2
+122
= 202
a2
+144 = 400
−144 −144
a2
= 256
21. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
a2
+122
= 202
a2
+144 = 400
−144 −144
a2
= 256
a2
= 256
22. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
a2
+122
= 202
a2
+144 = 400
−144 −144
a2
= 256
a2
= 256
a = 16
23. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
a2
+122
= 202
a2
+144 = 400
−144 −144
a2
= 256
a2
= 256
a = 16
h = 16
24. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
a2
+122
= 202
a2
+144 = 400
−144 −144
a2
= 256
a2
= 256
a = 16
h = 16
A = 32(16)
25. EXAMPLE 1
Find the perimeter and area of .!RSTU
P = 2l + 2w
P = 2(32) + 2(20)
P = 64 + 40
P = 104 in.
A = bh a2
+ b2
= c2
a2
+122
= 202
a2
+144 = 400
−144 −144
a2
= 256
a2
= 256
a = 16
h = 16
A = 32(16)
A = 512 in2
26. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
27. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
28. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
29. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
30. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
35.5
3
31. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
35.5
3
≈ 11.83
32. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
35.5
3
≈ 11.83 Matt needs 12 boards.
33. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
35.5
3
≈ 11.83
A = 1
2
bh
Matt needs 12 boards.
34. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
35.5
3
≈ 11.83
A = 1
2
bh
Matt needs 12 boards.
A = 1
2
(12)(9)
35. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
35.5
3
≈ 11.83
A = 1
2
bh
Matt needs 12 boards.
A = 1
2
(12)(9)
A = 54 ft2
36. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
35.5
3
≈ 11.83
A = 1
2
bh
Matt needs 12 boards.
A = 1
2
(12)(9)
A = 54 ft2
54
9
37. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
35.5
3
≈ 11.83
A = 1
2
bh
Matt needs 12 boards.
A = 1
2
(12)(9)
A = 54 ft2
54
9
= 6
38. EXAMPLE 2
Matt Mitarnowski needs to buy enough boards to make the frame
of the triangular sandbox shown and enough sand to cover the
bottom. If one of the boards is 3 feet long and one bag of sand
covers 9 square feet of the sandbox, how many boards and bags
does he need to buy?
P = a + b + c
P = 12+16 + 7.5
P = 35.5 ft
35.5
3
≈ 11.83
A = 1
2
bh
Matt needs 12 boards.
A = 1
2
(12)(9)
A = 54 ft2
54
9
= 6
Matt needs 6 bags of
sand.
42. EXAMPLE 3
Find the area of the trapezoid.
A = 1
2
h(b1
+ b2
)
A = 1
2
(1)(3 + 2.5)
43. EXAMPLE 3
Find the area of the trapezoid.
A = 1
2
h(b1
+ b2
)
A = 1
2
(1)(3 + 2.5)
A = 1
2
(5.5)
44. EXAMPLE 3
Find the area of the trapezoid.
A = 1
2
h(b1
+ b2
)
A = 1
2
(1)(3 + 2.5)
A = 1
2
(5.5)
A = 2.75 cm2
45. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
46. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
47. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
48. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
49. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
−16 −16
50. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
−16 −16
b2
= 9
51. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
−16 −16
b2
= 9
b2
= 9
52. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
−16 −16
b2
= 9
b2
= 9 b = 3
53. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
−16 −16
b2
= 9
b2
= 9 b = 3
b1
= 9; b2
= 9 − 3 = 6
54. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
−16 −16
b2
= 9
b2
= 9 b = 3
b1
= 9; b2
= 9 − 3 = 6
A = 1
2
h(b1
+ b2
)
55. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
−16 −16
b2
= 9
b2
= 9 b = 3
b1
= 9; b2
= 9 − 3 = 6
A = 1
2
h(b1
+ b2
)
A = 1
2
(4)(6 + 9)
56. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
−16 −16
b2
= 9
b2
= 9 b = 3
b1
= 9; b2
= 9 − 3 = 6
A = 1
2
h(b1
+ b2
)
A = 1
2
(4)(6 + 9)
A = (2)(15)
57. EXAMPLE 4
Fuzzy Jeff designed a deck shaped like the trapezoid shown. Find
the area of the deck.
a2
+ b2
= c2
42
+ b2
= 52
16 + b2
= 25
−16 −16
b2
= 9
b2
= 9 b = 3
b1
= 9; b2
= 9 − 3 = 6
A = 1
2
h(b1
+ b2
)
A = 1
2
(4)(6 + 9)
A = (2)(15)
A = 30 ft2
64. EXAMPLE 5
Find the area of each rhombus or kite.
A = 1
2
d1
d2
A = 1
2
(14)(18)
65. EXAMPLE 5
Find the area of each rhombus or kite.
A = 1
2
d1
d2
A = 1
2
(14)(18)
A = 126 in2
66. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
67. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
68. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
69. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
d2
= 1
2
x
70. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
d2
= 1
2
x
64 = 1
2
(x)(1
2
x)
71. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
d2
= 1
2
x
64 = 1
2
(x)(1
2
x)
64 = 1
4
x2
72. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
d2
= 1
2
x
64 = 1
2
(x)(1
2
x)
64 = 1
4
x2
4(64) = ( 1
4
x2
)4
73. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
d2
= 1
2
x
64 = 1
2
(x)(1
2
x)
64 = 1
4
x2
4(64) = ( 1
4
x2
)4
256 = x2
74. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
d2
= 1
2
x
64 = 1
2
(x)(1
2
x)
64 = 1
4
x2
4(64) = ( 1
4
x2
)4
256 = x2
256 = x2
75. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
d2
= 1
2
x
64 = 1
2
(x)(1
2
x)
64 = 1
4
x2
4(64) = ( 1
4
x2
)4
256 = x2
256 = x2
x = 16
76. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
d2
= 1
2
x
64 = 1
2
(x)(1
2
x)
64 = 1
4
x2
4(64) = ( 1
4
x2
)4
256 = x2
256 = x2
x = 16
d1
= 16 in.
77. EXAMPLE 6
One diagonal of a rhombus is half as long as the other diagonal. If
the area of the rhombus is 64 square inches, what are the lengths
of the diagonals?
A = 1
2
d1
d2
d1
= x
d2
= 1
2
x
64 = 1
2
(x)(1
2
x)
64 = 1
4
x2
4(64) = ( 1
4
x2
)4
256 = x2
256 = x2
x = 16
d1
= 16 in.
d2
= 8 in.