Include time header file#includetime.hWrite main method like t.pdf

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Include time header file #include Write main method like this : int main(){ time_t start_t, end_t; double diff_t; time(&start_t); // capturing start time int n; printf(\"Enter number of stuents (<=30): \"); scanf(\"%d\", &n); GradeBook *students = (GradeBook *)malloc(sizeof(GradeBook)*n); int i,j; // taking n entries for(i=0; i Solution Include time header file #include Write main method like this : int main(){ time_t start_t, end_t; double diff_t; time(&start_t); // capturing start time int n; printf(\"Enter number of stuents (<=30): \"); scanf(\"%d\", &n); GradeBook *students = (GradeBook *)malloc(sizeof(GradeBook)*n); int i,j; // taking n entries for(i=0; i.

$Include time header file #include Write main method like this : int main(){ time_t start_t, end_t; double diff_t; time(&start_t); // capturing start time int n; printf("Enter number of stuents (<=30): "); scanf("%d", &n); GradeBook *students = (GradeBook *)malloc(sizeof(GradeBook)*n); int i,j; // taking n entries for(i=0; i Solution Include time header file #include Write main method like this : int main(){ time_t start_t, end_t; double diff_t; time(&start_t); // capturing start time int n; printf("Enter number of stuents (<=30): "); scanf("%d", &n); GradeBook *students = (GradeBook *)malloc(sizeof(GradeBook)*n); int i,j; // taking n entries for(i=0; i$

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import java.awt.Color; import java.awt.Insets; import java.awt.Container; import java.awt.GridBagLayout; import java.awt.GridBagConstraints; import javax.swing.JMenu; import javax.swing.JFrame; import javax.swing.JPanel; import javax.swing.JLabel; import javax.swing.JButton; import javax.swing.JMenuBar; import javax.swing.JMenuItem; import javax.swing.JTextArea; import javax.swing.JScrollBar; import javax.swing.JScrollPane; import javax.swing.BorderFactory; /* *Class Steganography_View */ public class Steganography_View extends JFrame { //size variables for window private static int WIDTH = 500; private static int HEIGHT = 400; //elements for JPanel private JTextArea input; private JScrollBar scroll,scroll2; private JButton encodeButton,decodeButton; private JLabel image_input; //elements for Menu private JMenu file; private JMenuItem encode; private JMenuItem decode; private JMenuItem exit; /* *Constructor for Steganography_View class *@param name Used to set the title on the JFrame */ public Steganography_View(String name) { //set the title of the JFrame super(name); //Menubar JMenuBar menu = new JMenuBar(); JMenu file = new JMenu(\"File\"); file.setMnemonic(\'F\'); encode = new JMenuItem(\"Encode\"); encode.setMnemonic(\'E\'); file.add(encode); decode = new JMenuItem(\"Decode\"); decode.setMnemonic(\'D\'); file.add(decode); file.addSeparator(); exit = new JMenuItem(\"Exit\"); exit.setMnemonic(\'x\'); file.add(exit); menu.add(file); setJMenuBar(menu); // display rules setResizable(true);//allow window to be resized: true?false setBackground(Color.lightGray); /background color of window: Color(int,int,int) setLocation(100,100); //location on the screen to display window setDefaultCloseOperation(EXIT_ON_CLOSE);//what to do on close operation: exit, do_nothing, etc setSize(WIDTH,HEIGHT); //set the size of the window setVisible(true); //show the window: true?false } /* *@return The menu item \'Encode\' */ public JMenuItem getEncode() { return encode; } /* *@return The menu item \'Decode\' */ public JMenuItem getDecode() { return decode; } /* *@return The menu item \'Exit\' */ public JMenuItem getExit() { return exit; } /* *@return The TextArea containing the text to encode */ public JTextArea getText() { return input; } /* *@return The JLabel containing the image to decode text from */ public JLabel getImageInput() { return image_input; } /* *@return The JPanel displaying the Encode View */ public JPanel getTextPanel() { return new Text_Panel(); } /* *@return The JPanel displaying the Decode View */ public JPanel getImagePanel() { return new Image_Panel(); } /* *@return The Encode button */ public JButton getEButton() { return encodeButton; } /* *@return The Decode button */ public JButton getDButton() { return decodeButton; } /* *Class Text_Panel */ private class Text_Panel extends JPanel { /* *Constructor to enter text to be encoded */ public Text_Panel() { //setup GridBagLayout GridBagLayout layout = new GridBagLayout(); GridBagConstraints l.

import java.awt.Color;import java.awt.Insets;import java.awt.Con.pdf

import java.awt.Color;import java.awt.Insets;import java.awt.Con.pdf

import java.awt.Color;import java.awt.Insets;import java.awt.Con.pdf

Identify the computer fraud and abuse technique by: This computer fraud and abuse technique is called phishing. Its purpose is to get the information need to commit identity theft. The perpetrator probably also used brand spoofing of Big Bank’s web site Actuvally the problem of This case is based on an actual attack. The solution represents the actual events of the attack and the hospital\'s response a. What could the hospital do to stop the attack and contain the damage? By Monday afternoon, IT figured out which malware the bots were installing and wrote a script, which was pushed out hourly, directing computers to remove the bad code. The script helped to slow the bots down a bit. The problem does not state how the problem was finally fixed. What actually happened is that on Tuesday the hospital\'s antivirus vendor figured out which malware the hackers had used to get into the network and wrote a virus signature that blocked new code from coming in. Together with the code the internal IT staff wrote, the hospital was able to clean up its computers. All of the infected computers had to have their hard drives wiped clean and their software reinstalled, at an estimated cost of $150,000. b. Which computer fraud and abuse technique did the hackers use in their attack on the hospital? The primary attack used was a Zero-day attack that exploited a newly found weakness in Microsoft’s operating system that did not yet have a patch written to correct the weakness. The perpetrators hacked into the hospital\'s network and used various forms of malware, including adware (pop-up ads) and worms. c. What steps should the hospital have taken to prevent the damage caused by the attack? The hospital\'s network is now protected by Computer Associate\'s Pest Patrol, which blocks adware and spyware, and Cisco MARS, an intrusion detection system. Northwest\'s I.T. staffers no longer wait for vendors, particularly Microsoft, to certify software patches before applying fixes—they evaluate and test patches themselves. In the case of the attack, the Windows flaw that the attack slipped through had not yet been patched on the hospital\'s PCs. Fortunately, the hospital\'s servers escaped the attack because they had been patched Solution Identify the computer fraud and abuse technique by: This computer fraud and abuse technique is called phishing. Its purpose is to get the information need to commit identity theft. The perpetrator probably also used brand spoofing of Big Bank’s web site Actuvally the problem of This case is based on an actual attack. The solution represents the actual events of the attack and the hospital\'s response a. What could the hospital do to stop the attack and contain the damage? By Monday afternoon, IT figured out which malware the bots were installing and wrote a script, which was pushed out hourly, directing computers to remove the bad code. The script helped to slow the bots down a bit. The problem does not state how the problem was finally.

Identify the computer fraud and abuse technique byThis computer f.pdf

Identify the computer fraud and abuse technique byThis computer f.pdf

Identify the computer fraud and abuse technique byThis computer f.pdf

Given : A fund that starts with a zero balance with time zero. Fund accumulates with a varying force of interest. The formula for the function is given: A $100,000 is deposited at time 2. To find: No. of years from the time of deposit for the fund to double. Solution :In case of a fixed rate of interest, it gradually decreases in relation to its value as time increases. The interest on interest is also accumulated. With the given function, t>0 and deposit is made at time 2. i.e when t=1. Substitute the value of t in the function, we get, Del(t)= 2*(1)/((1^2 + 1) =1 No of years for fund to double is 1 year..

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// Average.java import java.util.Scanner; public class Average{ public static void main(String[] args){ Scanner input = new Scanner(System.in); double averageMale = 0, averageFemale = 0; int countMale = 0, countFemale = 0; char mf; double average; System.out.println(\"How many Students? \"); int n = input.nextInt(); for (int i = 1; i <= n; i++ ) { System.out.println(\"Is Student \" + i + \" male or female? \"); mf = input.next().charAt(0); if(mf == \'m\'){ countMale++; System.out.println(\"What is Student\'s \" + i + \"\'s average? \"); average = input.nextDouble(); averageMale = averageMale + average; } else{ countFemale++; System.out.println(\"What is Student\'s \" + i + \"\'s average? \"); average = input.nextDouble(); averageFemale = averageFemale + average; } } System.out.println(\"The \" + countMale + \" male Students average is \" + averageMale/countMale); System.out.println(\"The \" + countFemale + \" male Students average is \" + averageFemale/countFemale); } } /* output: How many Students? 5 Is Student 1 male or female? m What is Student\'s 1\'s average? 85 Is Student 2 male or female? m What is Student\'s 2\'s average? 91 Is Student 3 male or female? f What is Student\'s 3\'s average? 95 Is Student 4 male or female? f What is Student\'s 4\'s average? 80 Is Student 5 male or female? m What is Student\'s 5\'s average? 88 The 3 male Students average is 88.0 The 2 male Students average is 87.5 */ Solution // Average.java import java.util.Scanner; public class Average{ public static void main(String[] args){ Scanner input = new Scanner(System.in); double averageMale = 0, averageFemale = 0; int countMale = 0, countFemale = 0; char mf; double average; System.out.println(\"How many Students? \"); int n = input.nextInt(); for (int i = 1; i <= n; i++ ) { System.out.println(\"Is Student \" + i + \" male or female? \"); mf = input.next().charAt(0); if(mf == \'m\'){ countMale++; System.out.println(\"What is Student\'s \" + i + \"\'s average? \"); average = input.nextDouble(); averageMale = averageMale + average; } else{ countFemale++; System.out.println(\"What is Student\'s \" + i + \"\'s average? \"); average = input.nextDouble(); averageFemale = averageFemale + average; } } System.out.println(\"The \" + countMale + \" male Students average is \" + averageMale/countMale); System.out.println(\"The \" + countFemale + \" male Students average is \" + averageFemale/countFemale); } } /* output: How many Students? 5 Is Student 1 male or female? m What is Student\'s 1\'s average? 85 Is Student 2 male or female? m What is Student\'s 2\'s average? 91 Is Student 3 male or female? f What is Student\'s 3\'s average? 95 Is Student 4 male or female? f What is Student\'s 4\'s average? 80 Is Student 5 male or female? m What is Student\'s 5\'s average? 88 The 3 male Students average is 88.0 The 2 male Students average is 87.5 */.

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The short answer is no. The reason why you cant predict acid/base properties based on O/H is because many very strong acids and bases dont contain O or H. That being said the bronsted-lowry definition of acid and bases says that an acid is a substance that donates protons and a base is a substance that donates electron. According to that definition there is a very very weak correlation between having Hs to donate as protons and acid strength and conversely having Os and being a base (O- ions are a good proton acceptors because they are highly electronegative). Acids and bases are really better described by their electron donating and accepting capabilities of the compound as described by the lewis acid/base theory. An acid is really a compound that accepts electrons and a base is a compound which donates electrons. An H+ ion then is a compound which readily accepts electrons while O- ions readily donate electrons. However the H+ and O- ability to donate and accept electrons depends on many complicated factors of the compound as a whole and even its surrounding environment than just its quantity of Hs and Os. Try using wikipedia to gain a basic understanding of lewis acids. Solution The short answer is no. The reason why you cant predict acid/base properties based on O/H is because many very strong acids and bases dont contain O or H. That being said the bronsted-lowry definition of acid and bases says that an acid is a substance that donates protons and a base is a substance that donates electron. According to that definition there is a very very weak correlation between having Hs to donate as protons and acid strength and conversely having Os and being a base (O- ions are a good proton acceptors because they are highly electronegative). Acids and bases are really better described by their electron donating and accepting capabilities of the compound as described by the lewis acid/base theory. An acid is really a compound that accepts electrons and a base is a compound which donates electrons. An H+ ion then is a compound which readily accepts electrons while O- ions readily donate electrons. However the H+ and O- ability to donate and accept electrons depends on many complicated factors of the compound as a whole and even its surrounding environment than just its quantity of Hs and Os. Try using wikipedia to gain a basic understanding of lewis acids..

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First, let\'s start with naming binary ionic compounds. A binary ionic compound has one metal and one nonmetal present in the compound. Let\'s consider my username (rubidium.chloride) as an example. Rubidium chloride, or RbCl, is a binary ionic compound. The metal here is Rb (rubidium, group 1A) and the nonmetal is Cl (chlorine, group 7A). When you name binary ionic compounds, you mention the cation (positively charged ion) first (usually metals, those elements that appear on the left side of the periodic table have the tendency to form positively-charged ions). Then mention the anion (negatively charged ion). The cation is rubidium (Rb). We mention it thus: Rubidium The anion is chlorine. When we write the name of the anion [alongside with the cation], we drop the ending -ine (or whatever ending it may have) and replace it with -ide. So chlorine now becomes chlor + ide = chloride. Therefore, the name of the compound is Rubidium Chloride. When you write the formulas of binary ionic compounds, you use the criss-cross method. Here\'s how it works: Rubidium has a charge of +1. Chlorine has a charge of -1. You interchange the charges of both ions. These charges, when interchanged, become the subscripts of the elements in the compound. Hence, the compound now looks Rb1Cl1. Since the subscripts are all 1, we can remove them and write the formula as RbCl. Here\'s another example: Give the formula of the compound magnesium chloride. Mg has a charge of +2. Chlorine has a charge of -1. When you interchange the respective charges of magnesium and chlorine, we get the following formula: Mg1Cl2 We simplify this as MgCl2. A list of the common cations and ions is found at the back page or on the chapter of naming chemical compounds of your chemistry book. Take time to know them by heart. But what if... you\'ve got a compound named sodium nitrate. Ok. The formula is NaNO3. How did I know? Sodium nitrate is an example of a ternary ionic compound. A ternary ionic compound has two or more elements present in it. In this case, there are 3 (Na, N and O). The naming system of ternary ionic compounds is the same as that of binary ionic compounds. Let\'s name the participating ions: Na+ NO3- NO3- is the formula for the polyatomic ion (two or more elements joined together sharing a common charge; they act as one unit when they combine with other elements) nitrate. We interchange the charges of sodium and nitrate. Interchanging them gives us the formula NaNO3 To name this formula, just combine the name of the cation and anion together. In this case, it is sodium nitrate. What if we have a formula like this? Ba(OH)2 Don\'t worry. This is just barium hydroxide. Let\'s analyze why this came about. The charge of Ba is +2 and hydroxide (OH-) is -1. When you combine them together by interchanging subscripts, we get the following: BaOH2 Wait. The formula doesn\'t make sense. H is not the only atom having two of its kind, but O too. So we put parentheses around hydroxide to i.

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Answer: 1. Since it requires an internal namespace and external, we must deploy both an internal and an external DNS namespace, both of which needs to be managed separately. The combination can be created by either of the 2 ways : By making the internal domain a subdomain of the external domain or By making use of different names for the internal and external domains. 2. We can use an Internal DNS root. If we use the DNS root, as it is no exposed to the internet. It can host the private root zone in the namespace. Then we can use the internal subdomain as a parent for additional child domains that we go onto create in order to manage divisions within our organization. A contiguous namespace is used. We have to use short internal DNS namespaces to run more levels. We create name conventions and do not use abbreviations. Basics are the uppercase characters, lower case characters and numericals. 3. By default, the DNS client never goes into a dynamic update of top-level domain zones. To configure for automatic updates, we have to use the Update Top Level Domain Zones policy setting or we can even modify the registry. 4. These servers must be in the configured domain name obviously.The servers in the perimeter network should possess a FQDNs (Fully Qualified Domain Name) consisting of host names in the second-level domain name assigned. Solution Answer: 1. Since it requires an internal namespace and external, we must deploy both an internal and an external DNS namespace, both of which needs to be managed separately. The combination can be created by either of the 2 ways : By making the internal domain a subdomain of the external domain or By making use of different names for the internal and external domains. 2. We can use an Internal DNS root. If we use the DNS root, as it is no exposed to the internet. It can host the private root zone in the namespace. Then we can use the internal subdomain as a parent for additional child domains that we go onto create in order to manage divisions within our organization. A contiguous namespace is used. We have to use short internal DNS namespaces to run more levels. We create name conventions and do not use abbreviations. Basics are the uppercase characters, lower case characters and numericals. 3. By default, the DNS client never goes into a dynamic update of top-level domain zones. To configure for automatic updates, we have to use the Update Top Level Domain Zones policy setting or we can even modify the registry. 4. These servers must be in the configured domain name obviously.The servers in the perimeter network should possess a FQDNs (Fully Qualified Domain Name) consisting of host names in the second-level domain name assigned..

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An overview is presented of gas chromatography/mass spectrometry (GC/MS) and liquid chromatography/mass spectrometry (LC/MS), the two major hyphenated techniques employed in metabolic profiling that complement direct Solution An overview is presented of gas chromatography/mass spectrometry (GC/MS) and liquid chromatography/mass spectrometry (LC/MS), the two major hyphenated techniques employed in metabolic profiling that complement direct.

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4. a. Koch. Robert Koch is the founder of modern bacteriology, he is known for his role in identifying the specific causative agents of tuberculosis, cholera, and anthrax and for giving experimental support for the concept of infectious disease. 5. d. transmission electron microscopy. 6. a. differential stain. 7.d. streptobacilli. Rod shaped bacteria arranged in the form of chains. 8.D. posess a nucleus. Prokaryotic cell lack well developed nucleus. 10.a. prevent phagocytosis. The capsule is considered a virulence factor because it enhances the ability of bacteria to cause disease by preventing bacteria from phagocytosis. The capsule can protect cells from engulfment by eukaryotic cells, such as macrophages. 11.D. production of cellular energy in the form of ATP. Cellular respiration in which energy is produced in the form of ATP is a catabolic process. 12.D. glycolysis. Glycolysis is the common pathway for both aerobic and anaerobic respiration. 13.b. aerobic respiration. Aerobic respiration produces most of the energy as ATP as food gets completely oxidised in this type of respiration. Solution 4. a. Koch. Robert Koch is the founder of modern bacteriology, he is known for his role in identifying the specific causative agents of tuberculosis, cholera, and anthrax and for giving experimental support for the concept of infectious disease. 5. d. transmission electron microscopy. 6. a. differential stain. 7.d. streptobacilli. Rod shaped bacteria arranged in the form of chains. 8.D. posess a nucleus. Prokaryotic cell lack well developed nucleus. 10.a. prevent phagocytosis. The capsule is considered a virulence factor because it enhances the ability of bacteria to cause disease by preventing bacteria from phagocytosis. The capsule can protect cells from engulfment by eukaryotic cells, such as macrophages. 11.D. production of cellular energy in the form of ATP. Cellular respiration in which energy is produced in the form of ATP is a catabolic process. 12.D. glycolysis. Glycolysis is the common pathway for both aerobic and anaerobic respiration. 13.b. aerobic respiration. Aerobic respiration produces most of the energy as ATP as food gets completely oxidised in this type of respiration..

4. a. Koch.Robert Koch is the founder of modern bacteriology, he i.pdf

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A buffer is a system of a weak acid and its conjugate base or a weak base and its conjugate acid. In the case of HCN, it is a weak acid and it\'s conjugate base would be CN-. You can make a buffer by adding a salt of the conjugate base such as KCN or NaCN to HCN. When an acid is added, it reacts with the CN- ion (the conjugate base) and forms HCN (the weak acid). H+ + CN- --> HCN When a base is added, it reacts with the HCN (the weak acid) and forms the CN- ion (the conjugate base). OH- + HCN --> CN- + H2O This shows how the buffer takes advantage of the common ion effect because since the CN- anion is in both the weak acid and the conjugate base salt, when either component of the buffer reacts, it generates more of the non- reacting component. Solution A buffer is a system of a weak acid and its conjugate base or a weak base and its conjugate acid. In the case of HCN, it is a weak acid and it\'s conjugate base would be CN-. You can make a buffer by adding a salt of the conjugate base such as KCN or NaCN to HCN. When an acid is added, it reacts with the CN- ion (the conjugate base) and forms HCN (the weak acid). H+ + CN- --> HCN When a base is added, it reacts with the HCN (the weak acid) and forms the CN- ion (the conjugate base). OH- + HCN --> CN- + H2O This shows how the buffer takes advantage of the common ion effect because since the CN- anion is in both the weak acid and the conjugate base salt, when either component of the buffer reacts, it generates more of the non- reacting component..

A buffer is a system of a weak acid and its conju.pdf

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