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Chapter 10: Nuclear Magnetic
Resonance (NMR) Spectroscopy
What is spectroscopy?
Molecular response to radiative stimulus is
quantized (“geared”). (Molecule = nuclei + electrons).
Excitation:
1. Electronic (UV-visible spectra)
2. Vibrational (IR)
3. Rotation (microwave)
4. Nuclear spin orientation in magnet (NMR)
Spectrometer scans ν to find ΔE : The spectrum
ΔE = hν ν = c/λ
Excitation causes
an “absorption”, a
peak in a graph
A General Spectrometer
kcal mol-1
What is ∆E in NMR? Nuclei
behave as tiny magnets (random
orientation).
In a magnetic field H0, they
organize with (α, lower energy) or
against (β, higher energy) the field.
∆E = hν0 resonance frequency:
The frequency that matches
exactly the energy difference.
Protons as Tiny Magnets Line Up With
and Against an External Magnetic
Filed
Ratio α:β ~ 1:1
Absorption of Light, Spin Flip, and
Resonance  Spectral Line
ν0 is proportional to H0.
(ν0 is specific for element/isotope)
For 1H: at H0 = 21,150 gauss, ν0 = 90 MHz.
∆E (300 MHz) ~ 10-5 kcal mol-1.
Nα/Nβ = 1.000004
NMR “active” nuclei: 1H and 13C (not 12C)
At H0 = 70500 gauss, ν0 = 300 MHz.
H0 (earth): 0.7 gauss!
A Hypothetical NMR Spectrum:
Active Elements Absorb at
Differing Frequencies
The NMR Spectrometer
Solvents: CDCl3, CD2Cl2, THF-d8, etc.
High Resolution NMR!
Why are there two peaks? The Chemical Shift
Causes shielding, i.e.,
Peak moves to the right
Electrons in Vicinity of Nucleus Affect ν
Consider H+: No e, no shielding, peak
furthest to the left.
But:
When we add an e-withdrawing group:
e.g., CH3 Cl, causes deshielding (to left).
Chemical shift provides a finely tuned picture
of electronic environment around each H.
C HH
H
H
+ -
Electrons cause shielding:
Peak moves upfield (to right).
If we substitute with e-negative groups, shielding of
observed nucleus is diminished; or nucleus is
“deshielded” (relatively).
One e-poor
neighbor
Two e-poor
neighbors
The Chemical Shift δ
The position of peak relative to an
internal standard. Most common is
Tetramethylsilane: (CH3)4Si or “TMS”,
the “zero” point in the spectrum.
=
ν (from TMS) Hz
RF (e.g., 300 MHz)
ppm,
is independent of machine (90, 300 MHz, etc.)
δ
Distance from
TMS in Hz/300
MHz in ppm
266 Hz
0.89 ppm
541 Hz
1.80 ppm
978 Hz
3.26 ppm
Application of δ
CH3 CH3 CH3CH2Br
Br2
hυ
+ CH3CHBr2 + BrCH2CH2Br
EPM of 1-bromopropane
2 signals
2 signals
1 signal
Most deshielded
of all
1-2
2+
3-4
Variable
Chemically equivalent Hs: same δs. Use
symmetry operations: rotation, mirror planes.
“Fast” processes, such as methyl
rotation, equilibrate Hs:
For calibration: A B
Ea
k
Ea ~ 20 kcal mol-1, k ~ 10-2 sec-1, t1/2 = 1 min
Ea ~ 25 kcal mol-1, k ~ 10-6 sec-1, t1/2 = 66 h
NMR time scale < 1 sec.
Recall: Ea = 10.8 kcal mol-1.
To “freeze” ring flip on the NMR time scale:
we need to cool to -90ºC (Jensen)
Integration
Area under peak = relative # of
associated Hs. Computer-automated.
e.g. (CH3)3CCH2OH 9:2:1
CH3OCH2CH2OCH3 3:2
Helps in peak assignments.
Spin-Spin Splitting
(N+1) Rule
N equivalent adjacent hydrogens
(i.e. on neighboring carbons) give
rise to (N+1) peaks.
e.g., doublet (d), triplet (t),
quartet (q), quintet (quin), etc.
Why ?
Hbα strengthens H0 around Ha : deshielding
Hbβ weakens H0 around Ha : shielding
Result: two lines (1:1 ratio, d) instead of one.
Distance between them in Hz is the
coupling constant J.
Cl C C O CH2 CH3
Ha
OCH2CH3Cl
Hb
d d
q t
Ha “sees” two types of Hb neighbors
(through bond): Hbα and Hbβ
In a magnetic field, all
Hs exist as Hα:Hβ ~ 1:1.
Same value
Ha and Hb are said to “split” each other with a J of 7 Hz.
J is field independent: Same at
90, 300, etc. MHz
Range: 1-18 Hz.
For more than one neighbor : H “sees”
all α, β combinations of neighbors. Thus,
two neighboring Hs:
αα, αβ, βα , ββ: 1:2:1 triplet
ααα, ααβ, αβα, βαα , αββ, βαβ, ββα , βββ
1:3:3:1 quartet
Three neighboring Hs:
Summary Points
1. Equivalent protons show no splitting.
2. J is independent of H0.
3. Nonadjacent Hs J ~ 0.
4. (N+1) Rule. Ratio from Pascal’s triangle.
5. Splitting is mutual. If there is one split peak,
there has to be (at least) one other.
C X C
HH
1:6:15:20:15:6:1
(CH3)3CH
decet
t
d
tridecet
All –CH2- hydrogens are
equivalent:
s
Four mirror planes
t
quintet
OO
H
A 3.427 B 1.679 ppm
http://www.aist.go.jp/RIODB/SDBS/cgi-bin/cre_index.cgi
CH3CH3 CH3CH2Br + CH3CHBr2 + BrCH2CH2Br
Br2
h
t q d q singlet
A 5.842 B 2.458 ppm
A 3.654 ppm
Problem:
3 H
2 H
1 H
4 H
3 H
3 H
2 H
1 H
1 H
The two butanols:
CH3CH2CH2CH2OH
CH3CH2CHCH3
Which is which?
OH
Complex Splitting Patterns
[N+1] rule holds strictly only when:
1. Js to all neighbors equal, and
2. ∆ν >> J : first order patterns.
3. Otherwise complex signals: non-first order
multiplets.
δ (Heq) > δ (Hax)
1
1
4
2
3
Multiplets are typical of alkyl chains: all δs similar.
e.g.,
One solution: stronger magnet higher field spectra
For example, what might be non-first-order
at 90 MHz, may resolve into a first-order
pattern at 300 or 500 MHz.
(Recall ν ~ H0 ), “spreads out” spectrum,
but Js stay same (field independent).
90 MHz
500 MHz
Ribonuclease A, 40 MHz
Ribonuclease A
“Sequential” [N+1] Rule
1st Order patterns can be analyzed
for neighbors with differing Js.
Js should differ for non-equivalent
neighbors.
CH3 C C Cl
ClCl
Hb Ha
c
Jab = 3.6 Hz
Jbc = 6.8 Hz
Apply split sequentially
CH3 C C Cl
ClCl
Hb Ha
c
Jab = 3.6 Hz
Jbc = 6.8 Hz
CH3—CH2—CH2—Br
(J2)
t
?(J1)t
J1 > J2 :
J1 < J2 :
J1
J2
J2
J1
qt
or
tq
Quartet of triplets or triplet of
quartets or….. ?
Jab = Jbc  N + 1 Rule
If Js accidentally the same: [N+1] rule
Sextet
Sextet
Stereocenters and Methylene Groups
H Bonded/Acidic Protons:
OH, SH, N H
Recall CH2 O H
Why? Fast H+ exchange
(Hα and Hβ trade places)
“decouples” hydrogens.
Variable

s !
Variable  (concentration and moisture-dependent)
and no coupling !
Coupling is restored on cooling, because proton
exchange is “frozen” (on the NMR time scale).
CH3OH
OH peak often broad; disappears on addition
of D2O to the sample (H/D exchange).
13C NMR Spectroscopy
Only 1% 13C in nature: No 13C—13C
splitting, since chances of finding two
13C adjacent are small (~0.01%).
(For the same reason: No 13C—H seen in 1H NMR.
99% of sample is 12C).
Large Js 13C H J ~ 100-150 Hz
13C C H J ~ 5-10 Hz
But: 13C—H visible in 13C NMR.
Triplet of
quartets
Quartet of
triplets
Coupling to H can be removed by
“broad band” irradiation of all Hs
Hence: all lines are singlets !
averages Hα/β
Symmetry
C7H14 isomers
Number of Cs: 5 5
4 4 3 1 7
Chemical shift range : 200 ppm (1H: 10 ppm)
Rules for deshielding same as in 1H NMR
(multiply by a factor of 10-20)
Chemical Shift Range
Advanced Techniques
Distortionless polarization transfer
(“DEPT”) 13C NMR spectrum. Tells us
whether the carbon is attached to 3, 2,
1 or no hydrogen, i.e. CH3, CH2, CH, or C.
Requires running the spectrum in three
different ways (using specific laser
pulse sequences).
Example : Limonene.
Normal spectrum
DEPT-90 spectrum: only CH
DEPT-135 spectrum: CH and CH3 positive
CH2 negative peaks
Two Dimensional NMR
Correlated spectroscopy (COSY).
H/H or H/C
1H NMR
1H
NMR
10 ppm0
10
Coupled
Hs
1H
13C
0 10
200 C—H
connectivity
MRI : Magnetic Resonance
Imaging
Based on “relaxation” times β α, “T1”
T1 values differ with tissue
(environment)
Whole body NMR
MRI of Human Abdomen
spleenkidneys
liver
MRI, median sagittal section: cervicodorsal syringomyelia. This
condition is characterized by the presence of fluid-filled cavities
in the spinal cord substance.
Brain Tumor About to be
Zapped
A French Brain
My Brain
This spiral
represents the 23
stages occurring in
the first trimester
of pregnancy and
every two weeks of
the second and
third trimesters.
Stage 1
Fertilization
1 Oocyte, 300 Million
Sperm, 24 hours
0.1 - 0.15 mm
1 day post-ovulation
Fertilization begins
when a sperm
penetrates an oocyte
(an egg) and it ends with
the creation of the
zygote. The fertilization
process takes
about 24 hours.
Stage 5
Implantation
Complete,
Placental
Circulation
System Begins
0.1 – 0.2 mm
7-12 days post-
ovulation
Stage 2
Stage 10
Cleavage
First Cell Division,
Blastomeres,
Mitotic division
0.1-0.2 mm
1.5-3 days post-
ovulation
Neural Folds Begin
to Fuse, Heart
Tube Fuses
1.5-3.0 mm
21-23 days post-
ovulation
Cross Sections of 3-D
Image
… of a human
embryo, 44
days after
conception.
Roughly the
size of a navy bean, it still
has webbed fingers and
toes, but is already
developing a brain with two
hemispheres, the precursors
of vertebrae (dashlike
structures in right slice) and
internal organs.
Stage 15
Stage 23
(6 to 8 weeks post fertilization)
Lens vesicle, nasal pit, hand plate;
trunk widens; future cerebral
hemispheres distinct
Head and neck
(approximately 56-57
postovular days)
Essential external and
internal structures complete

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NMR Spectroscopy Explained

  • 1. Chapter 10: Nuclear Magnetic Resonance (NMR) Spectroscopy
  • 2. What is spectroscopy? Molecular response to radiative stimulus is quantized (“geared”). (Molecule = nuclei + electrons). Excitation: 1. Electronic (UV-visible spectra) 2. Vibrational (IR) 3. Rotation (microwave) 4. Nuclear spin orientation in magnet (NMR) Spectrometer scans ν to find ΔE : The spectrum ΔE = hν ν = c/λ
  • 6.
  • 7. What is ∆E in NMR? Nuclei behave as tiny magnets (random orientation). In a magnetic field H0, they organize with (α, lower energy) or against (β, higher energy) the field. ∆E = hν0 resonance frequency: The frequency that matches exactly the energy difference.
  • 8. Protons as Tiny Magnets Line Up With and Against an External Magnetic Filed Ratio α:β ~ 1:1
  • 9. Absorption of Light, Spin Flip, and Resonance  Spectral Line
  • 10. ν0 is proportional to H0. (ν0 is specific for element/isotope) For 1H: at H0 = 21,150 gauss, ν0 = 90 MHz. ∆E (300 MHz) ~ 10-5 kcal mol-1. Nα/Nβ = 1.000004 NMR “active” nuclei: 1H and 13C (not 12C) At H0 = 70500 gauss, ν0 = 300 MHz. H0 (earth): 0.7 gauss!
  • 11.
  • 12. A Hypothetical NMR Spectrum: Active Elements Absorb at Differing Frequencies
  • 13. The NMR Spectrometer Solvents: CDCl3, CD2Cl2, THF-d8, etc.
  • 14.
  • 15.
  • 17. Why are there two peaks? The Chemical Shift
  • 18. Causes shielding, i.e., Peak moves to the right Electrons in Vicinity of Nucleus Affect ν
  • 19. Consider H+: No e, no shielding, peak furthest to the left. But: When we add an e-withdrawing group: e.g., CH3 Cl, causes deshielding (to left). Chemical shift provides a finely tuned picture of electronic environment around each H. C HH H H + - Electrons cause shielding: Peak moves upfield (to right).
  • 20. If we substitute with e-negative groups, shielding of observed nucleus is diminished; or nucleus is “deshielded” (relatively).
  • 22. The Chemical Shift δ The position of peak relative to an internal standard. Most common is Tetramethylsilane: (CH3)4Si or “TMS”, the “zero” point in the spectrum. = ν (from TMS) Hz RF (e.g., 300 MHz) ppm, is independent of machine (90, 300 MHz, etc.) δ
  • 23. Distance from TMS in Hz/300 MHz in ppm 266 Hz 0.89 ppm 541 Hz 1.80 ppm 978 Hz 3.26 ppm
  • 24. Application of δ CH3 CH3 CH3CH2Br Br2 hυ + CH3CHBr2 + BrCH2CH2Br EPM of 1-bromopropane 2 signals 2 signals 1 signal Most deshielded of all
  • 26. Chemically equivalent Hs: same δs. Use symmetry operations: rotation, mirror planes.
  • 27. “Fast” processes, such as methyl rotation, equilibrate Hs: For calibration: A B Ea k Ea ~ 20 kcal mol-1, k ~ 10-2 sec-1, t1/2 = 1 min Ea ~ 25 kcal mol-1, k ~ 10-6 sec-1, t1/2 = 66 h NMR time scale < 1 sec.
  • 28. Recall: Ea = 10.8 kcal mol-1. To “freeze” ring flip on the NMR time scale: we need to cool to -90ºC (Jensen)
  • 29. Integration Area under peak = relative # of associated Hs. Computer-automated. e.g. (CH3)3CCH2OH 9:2:1 CH3OCH2CH2OCH3 3:2 Helps in peak assignments.
  • 30.
  • 31.
  • 33. (N+1) Rule N equivalent adjacent hydrogens (i.e. on neighboring carbons) give rise to (N+1) peaks. e.g., doublet (d), triplet (t), quartet (q), quintet (quin), etc.
  • 34. Why ? Hbα strengthens H0 around Ha : deshielding Hbβ weakens H0 around Ha : shielding Result: two lines (1:1 ratio, d) instead of one. Distance between them in Hz is the coupling constant J. Cl C C O CH2 CH3 Ha OCH2CH3Cl Hb d d q t Ha “sees” two types of Hb neighbors (through bond): Hbα and Hbβ In a magnetic field, all Hs exist as Hα:Hβ ~ 1:1.
  • 35.
  • 36. Same value Ha and Hb are said to “split” each other with a J of 7 Hz.
  • 37. J is field independent: Same at 90, 300, etc. MHz Range: 1-18 Hz. For more than one neighbor : H “sees” all α, β combinations of neighbors. Thus, two neighboring Hs: αα, αβ, βα , ββ: 1:2:1 triplet ααα, ααβ, αβα, βαα , αββ, βαβ, ββα , βββ 1:3:3:1 quartet Three neighboring Hs:
  • 38.
  • 39.
  • 40.
  • 41. Summary Points 1. Equivalent protons show no splitting. 2. J is independent of H0. 3. Nonadjacent Hs J ~ 0. 4. (N+1) Rule. Ratio from Pascal’s triangle. 5. Splitting is mutual. If there is one split peak, there has to be (at least) one other. C X C HH
  • 42.
  • 43.
  • 44.
  • 46. (CH3)3CH decet t d tridecet All –CH2- hydrogens are equivalent: s Four mirror planes t quintet OO H
  • 47. A 3.427 B 1.679 ppm http://www.aist.go.jp/RIODB/SDBS/cgi-bin/cre_index.cgi CH3CH3 CH3CH2Br + CH3CHBr2 + BrCH2CH2Br Br2 h t q d q singlet
  • 48. A 5.842 B 2.458 ppm
  • 50. Problem: 3 H 2 H 1 H 4 H 3 H 3 H 2 H 1 H 1 H The two butanols: CH3CH2CH2CH2OH CH3CH2CHCH3 Which is which? OH
  • 51. Complex Splitting Patterns [N+1] rule holds strictly only when: 1. Js to all neighbors equal, and 2. ∆ν >> J : first order patterns. 3. Otherwise complex signals: non-first order multiplets. δ (Heq) > δ (Hax) 1 1 4 2 3
  • 52. Multiplets are typical of alkyl chains: all δs similar. e.g., One solution: stronger magnet higher field spectra For example, what might be non-first-order at 90 MHz, may resolve into a first-order pattern at 300 or 500 MHz. (Recall ν ~ H0 ), “spreads out” spectrum, but Js stay same (field independent).
  • 55. Ribonuclease A, 40 MHz Ribonuclease A
  • 56. “Sequential” [N+1] Rule 1st Order patterns can be analyzed for neighbors with differing Js. Js should differ for non-equivalent neighbors. CH3 C C Cl ClCl Hb Ha c Jab = 3.6 Hz Jbc = 6.8 Hz Apply split sequentially
  • 57.
  • 58. CH3 C C Cl ClCl Hb Ha c Jab = 3.6 Hz Jbc = 6.8 Hz
  • 59. CH3—CH2—CH2—Br (J2) t ?(J1)t J1 > J2 : J1 < J2 : J1 J2 J2 J1 qt or tq Quartet of triplets or triplet of quartets or….. ?
  • 60. Jab = Jbc  N + 1 Rule If Js accidentally the same: [N+1] rule Sextet
  • 63. H Bonded/Acidic Protons: OH, SH, N H Recall CH2 O H Why? Fast H+ exchange (Hα and Hβ trade places) “decouples” hydrogens. Variable  s ! Variable  (concentration and moisture-dependent) and no coupling !
  • 64. Coupling is restored on cooling, because proton exchange is “frozen” (on the NMR time scale). CH3OH OH peak often broad; disappears on addition of D2O to the sample (H/D exchange).
  • 65. 13C NMR Spectroscopy Only 1% 13C in nature: No 13C—13C splitting, since chances of finding two 13C adjacent are small (~0.01%). (For the same reason: No 13C—H seen in 1H NMR. 99% of sample is 12C). Large Js 13C H J ~ 100-150 Hz 13C C H J ~ 5-10 Hz But: 13C—H visible in 13C NMR.
  • 67. Coupling to H can be removed by “broad band” irradiation of all Hs Hence: all lines are singlets ! averages Hα/β
  • 68. Symmetry C7H14 isomers Number of Cs: 5 5 4 4 3 1 7
  • 69. Chemical shift range : 200 ppm (1H: 10 ppm) Rules for deshielding same as in 1H NMR (multiply by a factor of 10-20)
  • 71.
  • 72. Advanced Techniques Distortionless polarization transfer (“DEPT”) 13C NMR spectrum. Tells us whether the carbon is attached to 3, 2, 1 or no hydrogen, i.e. CH3, CH2, CH, or C. Requires running the spectrum in three different ways (using specific laser pulse sequences). Example : Limonene.
  • 73. Normal spectrum DEPT-90 spectrum: only CH DEPT-135 spectrum: CH and CH3 positive CH2 negative peaks
  • 74. Two Dimensional NMR Correlated spectroscopy (COSY). H/H or H/C 1H NMR 1H NMR 10 ppm0 10 Coupled Hs 1H 13C 0 10 200 C—H connectivity
  • 75.
  • 76.
  • 77. MRI : Magnetic Resonance Imaging Based on “relaxation” times β α, “T1” T1 values differ with tissue (environment) Whole body NMR
  • 78. MRI of Human Abdomen spleenkidneys liver
  • 79. MRI, median sagittal section: cervicodorsal syringomyelia. This condition is characterized by the presence of fluid-filled cavities in the spinal cord substance.
  • 80. Brain Tumor About to be Zapped
  • 83. This spiral represents the 23 stages occurring in the first trimester of pregnancy and every two weeks of the second and third trimesters.
  • 84. Stage 1 Fertilization 1 Oocyte, 300 Million Sperm, 24 hours 0.1 - 0.15 mm 1 day post-ovulation Fertilization begins when a sperm penetrates an oocyte (an egg) and it ends with the creation of the zygote. The fertilization process takes about 24 hours. Stage 5 Implantation Complete, Placental Circulation System Begins 0.1 – 0.2 mm 7-12 days post- ovulation Stage 2 Stage 10 Cleavage First Cell Division, Blastomeres, Mitotic division 0.1-0.2 mm 1.5-3 days post- ovulation Neural Folds Begin to Fuse, Heart Tube Fuses 1.5-3.0 mm 21-23 days post- ovulation
  • 85. Cross Sections of 3-D Image … of a human embryo, 44 days after conception. Roughly the size of a navy bean, it still has webbed fingers and toes, but is already developing a brain with two hemispheres, the precursors of vertebrae (dashlike structures in right slice) and internal organs.
  • 86. Stage 15 Stage 23 (6 to 8 weeks post fertilization) Lens vesicle, nasal pit, hand plate; trunk widens; future cerebral hemispheres distinct Head and neck (approximately 56-57 postovular days) Essential external and internal structures complete