Think of the X and Y as totally different events. The expected value for X will be the middle of the interval because all the points are equally weighted. E(X) = 0.5 The same goes for Y. E(Y) = 0.5 The triangle (0, 0.5) (0.5, 0) (0,0) has base=0.5 and height = 0.5 A = (1/2)(BH) = (1/2)(0.5)(0.5) = 0.125 = 1/8 Solution Think of the X and Y as totally different events. The expected value for X will be the middle of the interval because all the points are equally weighted. E(X) = 0.5 The same goes for Y. E(Y) = 0.5 The triangle (0, 0.5) (0.5, 0) (0,0) has base=0.5 and height = 0.5 A = (1/2)(BH) = (1/2)(0.5)(0.5) = 0.125 = 1/8.

1. Think of the X and Y as totally different events. The expected value for X will be the middle of
the interval because all the points are equally weighted.
E(X) = 0.5
The same goes for Y.
E(Y) = 0.5
The triangle (0, 0.5) (0.5, 0) (0,0) has base=0.5 and height = 0.5
A = (1/2)(BH) = (1/2)(0.5)(0.5) = 0.125 = 1/8
Solution
Think of the X and Y as totally different events. The expected value for X will be the middle of
the interval because all the points are equally weighted.
E(X) = 0.5
The same goes for Y.
E(Y) = 0.5
The triangle (0, 0.5) (0.5, 0) (0,0) has base=0.5 and height = 0.5

2. A = (1/2)(BH) = (1/2)(0.5)(0.5) = 0.125 = 1/8