DisplayBook.java import java.io.File; import java.io.FileInput.pdf
•
0 likes•2 views
DisplayBook.java import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.util.Scanner; public class DisplayBook { public static void main(String[] args) throws IOException { // TODO Auto-generated method stub Scanner scan = new Scanner(System.in); File file = new File(\"D:\\\\books.txt\"); if(file.exists()){ System.out.println(\"File exists\"); FileInputStream fis = new FileInputStream(file); int content; while ((content = fis.read()) != -1) { System.out.print((char) content); } fis.close(); } else{ System.out.println(\"File does not exist\"); String titles = \"\"; FileOutputStream fop = new FileOutputStream(file); while(true){ System.out.println(\"Enter Book Title (none to exit):\"); String title = scan.nextLine(); if(title.equalsIgnoreCase(\"none\")){ break; } else{ titles = titles + title +\"\ \"; } } byte[] contentInBytes = titles.getBytes(); fop.write(contentInBytes); fop.flush(); fop.close(); } } } Output: File does not exist Enter Book Title (none to exit): Physics Enter Book Title (none to exit): Chemistry Enter Book Title (none to exit): Science Enter Book Title (none to exit): Maths Enter Book Title (none to exit): none -------------------------------------- File exists Physics Chemistry Science Maths Solution DisplayBook.java import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.util.Scanner; public class DisplayBook { public static void main(String[] args) throws IOException { // TODO Auto-generated method stub Scanner scan = new Scanner(System.in); File file = new File(\"D:\\\\books.txt\"); if(file.exists()){ System.out.println(\"File exists\"); FileInputStream fis = new FileInputStream(file); int content; while ((content = fis.read()) != -1) { System.out.print((char) content); } fis.close(); } else{ System.out.println(\"File does not exist\"); String titles = \"\"; FileOutputStream fop = new FileOutputStream(file); while(true){ System.out.println(\"Enter Book Title (none to exit):\"); String title = scan.nextLine(); if(title.equalsIgnoreCase(\"none\")){ break; } else{ titles = titles + title +\"\ \"; } } byte[] contentInBytes = titles.getBytes(); fop.write(contentInBytes); fop.flush(); fop.close(); } } } Output: File does not exist Enter Book Title (none to exit): Physics Enter Book Title (none to exit): Chemistry Enter Book Title (none to exit): Science Enter Book Title (none to exit): Maths Enter Book Title (none to exit): none -------------------------------------- File exists Physics Chemistry Science Maths.
Report
Share
Report
Share
Download to read offline
![DisplayBook.java
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Scanner;
public class DisplayBook {
public static void main(String[] args) throws IOException {
// TODO Auto-generated method stub
Scanner scan = new Scanner(System.in);
File file = new File("D:books.txt");
if(file.exists()){
System.out.println("File exists");
FileInputStream fis = new FileInputStream(file);
int content;
while ((content = fis.read()) != -1) {
System.out.print((char) content);
}
fis.close();
}
else{
System.out.println("File does not exist");
String titles = "";
FileOutputStream fop = new FileOutputStream(file);
while(true){
System.out.println("Enter Book Title (none to exit):");
String title = scan.nextLine();
if(title.equalsIgnoreCase("none")){
break;
}
else{
titles = titles + title +" ";
}](https://image.slidesharecdn.com/displaybook-230408100812-5dc3778a/85/DisplayBook-java-import-java-io-File-import-java-io-FileInput-pdf-1-320.jpg)
![}
byte[] contentInBytes = titles.getBytes();
fop.write(contentInBytes);
fop.flush();
fop.close();
}
}
}
Output:
File does not exist
Enter Book Title (none to exit):
Physics
Enter Book Title (none to exit):
Chemistry
Enter Book Title (none to exit):
Science
Enter Book Title (none to exit):
Maths
Enter Book Title (none to exit):
none
--------------------------------------
File exists
Physics
Chemistry
Science
Maths
Solution
DisplayBook.java
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
Create a text file named lnfo.txt. Enter the following informatio.pdf
Create a text file named \"lnfo.txt\". Enter the following information using Linked List (any
method). Name rightarrow String Address rightarrow String Phone rightarrow String There
should be continues loop which will ask the above information and write down in the TEXT File.
When user inputs Exit in Name Field then program should be ended.
Solution
package sample;
import java.io.*;
public class ReadWrite {
public static void main(String[] args) {
BufferedReader reader = null;
try {
reader = new BufferedReader(new InputStreamReader(System.in));
File file = new File(\"C:\\\\Temp\\\\Info.txt\");
// creates the file
file.createNewFile();
// creates a FileWriter Object
FileWriter writer = new FileWriter(file);
while (true) {
System.out.print(\"Enter Name : \");
String name = reader.readLine();
if (\"Exit\".equals(name)) {
System.out.println(\"Exit!\");
writer.flush();
writer.close();
System.exit(0);
}
System.out.print(\"Enter Address : \");
String address = reader.readLine();
System.out.print(\"Enter Phone : \");
String phone = reader.readLine();
// Writes the content to the file
writer.write(\"\ \ -----------\");
writer.write(\"\ Name : \"+name);
writer.write(\"\ Address : \"+address);
writer.write(\"\ Phone : \"+phone);
writer.write(\"\ -----------\");
System.out.println(\"Added Below Record Successfully \");
System.out.println(\"-----------\ \");
System.out.println(\"Name : \"+name);
System.out.println(\"Address : \"+address);
System.out.println(\"Phone : \"+phone);
System.out.println(\"-----------\ \");
}
} catch (IOException ex) {
ex.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
}
}
package sample;
import java.io.*;
public class ReadWrite {
public static void main(String[] args) {
BufferedReader reader = null;
try {
reader = new BufferedReader(new InputStreamReader(System.in));
File file = new File(\"C:\\\\Temp\\\\Info.txt\");
// creates the file
file.createNewFile();
// creates a FileWriter Object
FileWriter writer = new FileWriter(file);
while (true) {
System.out.print(\"Enter Name : \");
String name = reader.readLine();
if (\"Exit\".equals(name)) {
System.out.println(\"Exit!\");
writer.flush();
writer.close();
System.exit(0);
}
System.out.print(\"Enter Address : \");
String address = reader.readLine();
System.out.print(\"Enter Phone : \");
String phone = reader.readLine();
// Writes the content to the file
writer.write(\"\ \ -----------\");
writer.write(\"\ Name : \"+name);
writer.write(\"\ Address : \"+address);
writer.write(\"\ Phone : \"+phone);
writer.write(\"\ -----------\");
System.out.println(\"Added Below Record Successfully \");
System.out.println(\"-----------\ \");
System.out.println(\"Name : \"+name);
System.out.println(\"Address : \"+address);
System.out.println(\"Phone : \"+phone);
System.out.println(\"-----------\ \");
}
} catch (IOException ex) {
ex.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOExcept.
Session 23 - JDBC
In this session you will learn:
1. File IO Continued
2. Intro to JDBC (Java Database Connectivity)
JDBC
In this core java training session, you will learn Examples of File IO &
Introduction to JDBC. Topics covered in this session are:
• File IO Continued
• Intro to JDBC (Java Database Connectivity)
For more information about this course visit on this link: https://www.mindsmapped.com/courses/software-development/learn-java-fundamentals-hands-on-training-on-core-java-concepts/
import required package file import java.io.File; The Filed.pdf
// import required package file
import java.io.File;
// The Filedetails class
public class FileDetails {
// Constructor that performs the action
public FileDetails(String filename)
{
// File object to get details
File file=new File(filename);
// printing obsolute path
System.out.println(\"Absolute path of file:\"+file.getAbsolutePath());
// printing file size in bytes
System.out.println(\"File Size in bytes:\"+file.length());
// Checking if file is readable
if(file.canRead())
System.out.println(\"The file is readable\");
else
System.out.println(\"The file is not readable\");
// checking if file is writable
if(file.canWrite())
System.out.println(\"The file is writable\");
else
System.out.println(\"The file is not writable\");
}
// main method goes here
public static void main(String[] args) {
// TODO Auto-generated method stub
// object instantiation
FileDetails fd=new FileDetails(\"anyfile.doc\"); // You should give exact path and file name
here
}
}
// Importing required packages
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
// the writestring class
public class WriteString {
// Writestring class
public WriteString(String filename,String text) throws FileNotFoundException
{
// File object
File file=new File(filename);
// Printsteam class that connects file using file output stream
PrintStream ps=new PrintStream(new FileOutputStream(file));
// using println method to write to the file
ps.println(text);
}
// main method to execute the code
public static void main(String[] args) throws FileNotFoundException
{
// the writestring class instantiation
WriteString ws=new WriteString(\"f1.txt\",\"Hello World\"); // You should give exact path
and file name here
}
}
// importing packages
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
// The writints class
public class WriteInts {
// the constructor to instantiate
public WriteInts(String filename,int[] myArr) throws FileNotFoundException
{
// File object
File file=new File(filename);
// Using print stream to write integers
PrintStream ps=new PrintStream(new FileOutputStream(file));
//Looping through array elements to write every element
for(int i=0;i
Solution
// import required package file
import java.io.File;
// The Filedetails class
public class FileDetails {
// Constructor that performs the action
public FileDetails(String filename)
{
// File object to get details
File file=new File(filename);
// printing obsolute path
System.out.println(\"Absolute path of file:\"+file.getAbsolutePath());
// printing file size in bytes
System.out.println(\"File Size in bytes:\"+file.length());
// Checking if file is readable
if(file.canRead())
System.out.println(\"The file is readable\");
else
System.out.println(\"The file is not readable\");
// checking if file is writable
if(file.canWrite())
System.out.println(\"The file is writable\");
else
System.out.println(\"The file.
Recommended
Create a text file named lnfo.txt. Enter the following informatio.pdf
Create a text file named \"lnfo.txt\". Enter the following information using Linked List (any
method). Name rightarrow String Address rightarrow String Phone rightarrow String There
should be continues loop which will ask the above information and write down in the TEXT File.
When user inputs Exit in Name Field then program should be ended.
Solution
package sample;
import java.io.*;
public class ReadWrite {
public static void main(String[] args) {
BufferedReader reader = null;
try {
reader = new BufferedReader(new InputStreamReader(System.in));
File file = new File(\"C:\\\\Temp\\\\Info.txt\");
// creates the file
file.createNewFile();
// creates a FileWriter Object
FileWriter writer = new FileWriter(file);
while (true) {
System.out.print(\"Enter Name : \");
String name = reader.readLine();
if (\"Exit\".equals(name)) {
System.out.println(\"Exit!\");
writer.flush();
writer.close();
System.exit(0);
}
System.out.print(\"Enter Address : \");
String address = reader.readLine();
System.out.print(\"Enter Phone : \");
String phone = reader.readLine();
// Writes the content to the file
writer.write(\"\ \ -----------\");
writer.write(\"\ Name : \"+name);
writer.write(\"\ Address : \"+address);
writer.write(\"\ Phone : \"+phone);
writer.write(\"\ -----------\");
System.out.println(\"Added Below Record Successfully \");
System.out.println(\"-----------\ \");
System.out.println(\"Name : \"+name);
System.out.println(\"Address : \"+address);
System.out.println(\"Phone : \"+phone);
System.out.println(\"-----------\ \");
}
} catch (IOException ex) {
ex.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
}
}
package sample;
import java.io.*;
public class ReadWrite {
public static void main(String[] args) {
BufferedReader reader = null;
try {
reader = new BufferedReader(new InputStreamReader(System.in));
File file = new File(\"C:\\\\Temp\\\\Info.txt\");
// creates the file
file.createNewFile();
// creates a FileWriter Object
FileWriter writer = new FileWriter(file);
while (true) {
System.out.print(\"Enter Name : \");
String name = reader.readLine();
if (\"Exit\".equals(name)) {
System.out.println(\"Exit!\");
writer.flush();
writer.close();
System.exit(0);
}
System.out.print(\"Enter Address : \");
String address = reader.readLine();
System.out.print(\"Enter Phone : \");
String phone = reader.readLine();
// Writes the content to the file
writer.write(\"\ \ -----------\");
writer.write(\"\ Name : \"+name);
writer.write(\"\ Address : \"+address);
writer.write(\"\ Phone : \"+phone);
writer.write(\"\ -----------\");
System.out.println(\"Added Below Record Successfully \");
System.out.println(\"-----------\ \");
System.out.println(\"Name : \"+name);
System.out.println(\"Address : \"+address);
System.out.println(\"Phone : \"+phone);
System.out.println(\"-----------\ \");
}
} catch (IOException ex) {
ex.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOExcept.
Session 23 - JDBC
In this session you will learn:
1. File IO Continued
2. Intro to JDBC (Java Database Connectivity)
JDBC
In this core java training session, you will learn Examples of File IO &
Introduction to JDBC. Topics covered in this session are:
• File IO Continued
• Intro to JDBC (Java Database Connectivity)
For more information about this course visit on this link: https://www.mindsmapped.com/courses/software-development/learn-java-fundamentals-hands-on-training-on-core-java-concepts/
import required package file import java.io.File; The Filed.pdf
// import required package file
import java.io.File;
// The Filedetails class
public class FileDetails {
// Constructor that performs the action
public FileDetails(String filename)
{
// File object to get details
File file=new File(filename);
// printing obsolute path
System.out.println(\"Absolute path of file:\"+file.getAbsolutePath());
// printing file size in bytes
System.out.println(\"File Size in bytes:\"+file.length());
// Checking if file is readable
if(file.canRead())
System.out.println(\"The file is readable\");
else
System.out.println(\"The file is not readable\");
// checking if file is writable
if(file.canWrite())
System.out.println(\"The file is writable\");
else
System.out.println(\"The file is not writable\");
}
// main method goes here
public static void main(String[] args) {
// TODO Auto-generated method stub
// object instantiation
FileDetails fd=new FileDetails(\"anyfile.doc\"); // You should give exact path and file name
here
}
}
// Importing required packages
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
// the writestring class
public class WriteString {
// Writestring class
public WriteString(String filename,String text) throws FileNotFoundException
{
// File object
File file=new File(filename);
// Printsteam class that connects file using file output stream
PrintStream ps=new PrintStream(new FileOutputStream(file));
// using println method to write to the file
ps.println(text);
}
// main method to execute the code
public static void main(String[] args) throws FileNotFoundException
{
// the writestring class instantiation
WriteString ws=new WriteString(\"f1.txt\",\"Hello World\"); // You should give exact path
and file name here
}
}
// importing packages
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
// The writints class
public class WriteInts {
// the constructor to instantiate
public WriteInts(String filename,int[] myArr) throws FileNotFoundException
{
// File object
File file=new File(filename);
// Using print stream to write integers
PrintStream ps=new PrintStream(new FileOutputStream(file));
//Looping through array elements to write every element
for(int i=0;i
Solution
// import required package file
import java.io.File;
// The Filedetails class
public class FileDetails {
// Constructor that performs the action
public FileDetails(String filename)
{
// File object to get details
File file=new File(filename);
// printing obsolute path
System.out.println(\"Absolute path of file:\"+file.getAbsolutePath());
// printing file size in bytes
System.out.println(\"File Size in bytes:\"+file.length());
// Checking if file is readable
if(file.canRead())
System.out.println(\"The file is readable\");
else
System.out.println(\"The file is not readable\");
// checking if file is writable
if(file.canWrite())
System.out.println(\"The file is writable\");
else
System.out.println(\"The file.
The Java Program for the above given isimport java.io.File;impo.pdf
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}
Solution
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}.
2. Write a program which will open an input file and write to an out.pdf
2. Write a program which will open an input file and write to an output file. Use exception
handling (try & Catch to display appropriate error handling).
Solution
herer is code:
import java.io.*;
public class Copytxt{
public static void main (String[] args)throws IOException {
int i;
FileInputStream fin;
FileOutputStream fout;
try {
// open input file
try {
fin = new FileInputStream(\"input.txt\"); // pass the input location file here
}
catch (FileNotFoundException e) { // if file not found
System.out.println(\"Input File Not Found\");
return;
}
// open output file
try {
fout = new FileOutputStream(\"output.txt\"); // pass the output location file here
}
catch (FileNotFoundException e) { // if file not found
System.out.println(\"Error Opening Output File\");
return;
}
}
catch (ArrayIndexOutOfBoundsException e) {
System.out.println(\"Usage: CopyFile From To\");
return;
}
// Copy File
try {
byte[] buffer = new byte[1024];
int length;
/*copying the contents from input stream to
* output stream using read and write methods
*/
while ((length = fin.read(buffer)) > 0){
fout.write(buffer, 0, length);
}
}
catch (IOException e) {
System.out.println(\"File Error\");
}
fin.close();
fout.close();
}
}.
I can not get my code to comply it gets mad that I have run declare mo.docx
I can not get my code to comply it gets mad that I have run declare more than once. Please help me figure out how to get this to work
package projectOne;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
import java.util.*;
import java.io.*;
public class Main
{ public static void main(String[] pArgs){
Main mainObject = new Main();
mainObject.run();
} private void run() {
public FileReader readFile() throws FileNotFoundException {
FileReader file = new FileReader(\"p01-in.txt\");
return file;
}
public ArrayList<Integer> getData(FileReader file) throws FileNotFoundException {
Scanner data_read = new Scanner(new BufferedReader(file));
ArrayList<Integer> data = new ArrayList<Integer>();
while (data_read.hasNext()) {
int item = data_read.nextInt();
data.add(item);
}
return data;
}
public ArrayList<Integer> calcRuns(ArrayList<Integer> data) {
ArrayList<Integer> runs = new ArrayList<Integer>();
Iterator<Integer> i_data = data.iterator();
int run = 0;
int temp = i_data.next();
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp < t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
i_data = data.iterator();
temp = i_data.next();
run = 0;
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp > t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
return runs;
}
public void writeOutput(ArrayList<Integer> runs) throws IOException {
PrintWriter out = new PrintWriter(new File(\"p01-runs.txt\"));
ArrayList<Integer> run_count = new ArrayList<Integer>();
int i = 0;
int r_count = Collections.frequency(run_count, i);
while (i < 100) {
run_count.add(r_count);
i++;
r_count = Collections.frequency(runs, i);
}
Iterator<Integer> i_runs = run_count.iterator();
i = 0;
while (i_runs.hasNext()) {
int run = i_runs.next();
String line = \"run_\" + i + \" ,\" + run;
i++;
out.println(line);
}
}
public void run() throws Exception {
FileReader fin = this.readFile();
ArrayList<Integer> data = this.getData(fin);
ArrayList<Integer> runs = this.calcRuns(data);
this.writeOutput(runs);
}
}
Solution
In your program you have to change the syntax errors at method declaration.so your not getting output.
.
5. Ввод-вывод, доступ к файловой системе
5.1 Доступ к файловой системе
5.2 Потоки байт
5.3 Потоки символов
5.4 Продвинутые возможности
Know how to redirect input and output- and know how to append to an ex.docx
Know how to redirect input and output, and know how to append to an existing file. Example: run/usr/local/task with input redirected from blah.txt. and the output appended to file tylk.data
Solution
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStreamReader;
class Main {
public static void main(String[] args) throws IOException {
File dir = new File(\"run/user/local/task.\");
String source = dir.getCanonicalPath() + File.separator + \"blah.txt\";
String dest = dir.getCanonicalPath() + File.separator + \"tylk.data\";
File fin = new File(source);
FileInputStream fis = new FileInputStream(fin);
BufferedReader in = new BufferedReader(new InputStreamReader(fis));
FileWriter fstream = new FileWriter(dest, true);
BufferedWriter out = new BufferedWriter(fstream);
String aLine = null;
while ((aLine = in.readLine()) != null) {
out.write(aLine);
out.newLine();
}
// do not forget to close the buffer reader
in.close();
// close buffer writer
out.close();
}
}
.
Change the code in Writer.java only to get it working. Must contain .pdf
Change the code in Writer.java only to get it working. Must contain methods: logReverse() ,
logMax(), logDuplicates(),
This lab is going to focus on File Output, which you will find is somewhat similar to console
output.
FileMain.java
import java.io.IOException;
import java.util.ArrayList;
import java.util.Scanner;
public class FileMain {
public static void main(String[] args) throws IOException{
Scanner scnr = new Scanner(System.in);
System.out.print("Please enter the name of the file you would like to read: ");
String fileName = scnr.next();
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents(fileName);
System.out.println("Please enter a name for your new file: ");
String newFileName = scnr.next();
Writer fileOut = new Writer(newFileName);
fileOut.logReverse(fileContents);
fileOut.logMax(fileContents);
fileOut.logDuplicates(fileContents);
fileOut.closeWriter();
scnr.close();
}
}
Filetester.java
import java.io.IOException;
import java.util.ArrayList;
public class FileTester {
public static boolean testLogReverse(ArrayList contents) throws IOException {
Writer writer = new Writer("logReverseTest.txt");
writer.logReverse(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Reversed file contents: ");
expected.add("58");
expected.add("12");
expected.add("19");
expected.add("42");
expected.add("12");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logReverseTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogMax(ArrayList contents) throws IOException {
Writer writer = new Writer("logMaxTest.txt");
writer.logMax(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("The largest number in the file is: 58");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logMaxTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogDuplicates(ArrayList contents) throws IOException {
Writer writer = new Writer("logDuplicatesTest.txt");
writer.logDuplicates(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Duplicates found: true");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logDuplicatesTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static void main(String[] args) throws IOException {
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents("nums.txt");
System.out.println("logReverse test passed? " + testLogReverse(fileContents));
System.out.println("logMax test passed? " + testLogMax(fileContents));
System.out.println("logDuplicates test passed? " + testLogDuplicates(fileContents));
}
}
Reader.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Sca.
Write a java program that allows the user to input the name of a fil.docx
Write a java program that allows the user to input the name of a fil
Write a java program that allows the user to input the name of a file.docx
Write a java program that allows the user to input the name of a file that contains positive integers (one integer per line) The number of integers in the file The program should find all odd and even numbers and write the odd numbers to a file \"odd.txt\" and write the even numbers to another file \"even.txt\"
Solution
package expertques;
import java.io.File;
import java.io.PrintWriter;
import java.util.Scanner;
public class evenoddwithfile {
public static void main(String[] args) throws Exception {
File in;//file input
File even = new File(\"f://even.txt\");//creates file even
File odd = new File(\"f://odd.txt\");//creates file odd
Scanner s = new Scanner(System.in);//reads input from console or user
System.out.println(\"Enter the file name with path: \");
in = new File(s.nextLine());
System.out.println(\"Enter the number of integers n the file: \");
int n = s.nextInt();
if (in.exists()) {//checks if input file exist or not
Scanner ins = new Scanner(in);//reads input file
PrintWriter pe = new PrintWriter(even);//write to even file
PrintWriter po = new PrintWriter(odd);//writes to odd file
for (int i = 0; i < n; i++) {//loop till the numbers exists
int x = ins.nextInt();//reads from input file
if (x % 2 == 0) {//checks for even or odd
pe.println(x);//if even writes in even file
} else {
po.println(x);//if odd writes in odd file
}
}
pe.close();//closes even file very important else nothing will be written in the file
po.close();//closes odd file very important else nothing will be written in the file
System.out.println(\"File successfully written with odds and evens\");
} else {
System.out.println(\"Error file not found at specified path\");//if file not exist
}
}
}
output
run:
Enter the file name with path:
f://integers.txt
Enter the number of integers n the file:
8
File successfully written with odds and evens
BUILD SUCCESSFUL (total time: 6 seconds)
.
Application-Specific Models and Pointcuts using a Logic Meta Language
Application-Specific Models and Pointcuts using a Logic Meta Language, Johan Brichau, Andy Kellens Kris Gybels, Kim Mens, ESUG 2006, Prague
Step1 Equivalents of NaOH= .1146 x[19.25-.55]x10^.pdf
Step1 Equivalents of NaOH= .1146 x[19.25-.55]x10^-3 =2.14302x10^-3 Step2
Equivalents of acid = .225/E ; E be the equivalent eight of acid Step3 .225/E = 2.14302x10^-3
or E=105
Solution
Step1 Equivalents of NaOH= .1146 x[19.25-.55]x10^-3 =2.14302x10^-3 Step2
Equivalents of acid = .225/E ; E be the equivalent eight of acid Step3 .225/E = 2.14302x10^-3
or E=105.
More Related Content
Similar to DisplayBook.java import java.io.File; import java.io.FileInput.pdf
The Java Program for the above given isimport java.io.File;impo.pdf
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}
Solution
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}.
2. Write a program which will open an input file and write to an out.pdf
2. Write a program which will open an input file and write to an output file. Use exception
handling (try & Catch to display appropriate error handling).
Solution
herer is code:
import java.io.*;
public class Copytxt{
public static void main (String[] args)throws IOException {
int i;
FileInputStream fin;
FileOutputStream fout;
try {
// open input file
try {
fin = new FileInputStream(\"input.txt\"); // pass the input location file here
}
catch (FileNotFoundException e) { // if file not found
System.out.println(\"Input File Not Found\");
return;
}
// open output file
try {
fout = new FileOutputStream(\"output.txt\"); // pass the output location file here
}
catch (FileNotFoundException e) { // if file not found
System.out.println(\"Error Opening Output File\");
return;
}
}
catch (ArrayIndexOutOfBoundsException e) {
System.out.println(\"Usage: CopyFile From To\");
return;
}
// Copy File
try {
byte[] buffer = new byte[1024];
int length;
/*copying the contents from input stream to
* output stream using read and write methods
*/
while ((length = fin.read(buffer)) > 0){
fout.write(buffer, 0, length);
}
}
catch (IOException e) {
System.out.println(\"File Error\");
}
fin.close();
fout.close();
}
}.
I can not get my code to comply it gets mad that I have run declare mo.docx
I can not get my code to comply it gets mad that I have run declare more than once. Please help me figure out how to get this to work
package projectOne;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
import java.util.*;
import java.io.*;
public class Main
{ public static void main(String[] pArgs){
Main mainObject = new Main();
mainObject.run();
} private void run() {
public FileReader readFile() throws FileNotFoundException {
FileReader file = new FileReader(\"p01-in.txt\");
return file;
}
public ArrayList<Integer> getData(FileReader file) throws FileNotFoundException {
Scanner data_read = new Scanner(new BufferedReader(file));
ArrayList<Integer> data = new ArrayList<Integer>();
while (data_read.hasNext()) {
int item = data_read.nextInt();
data.add(item);
}
return data;
}
public ArrayList<Integer> calcRuns(ArrayList<Integer> data) {
ArrayList<Integer> runs = new ArrayList<Integer>();
Iterator<Integer> i_data = data.iterator();
int run = 0;
int temp = i_data.next();
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp < t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
i_data = data.iterator();
temp = i_data.next();
run = 0;
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp > t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
return runs;
}
public void writeOutput(ArrayList<Integer> runs) throws IOException {
PrintWriter out = new PrintWriter(new File(\"p01-runs.txt\"));
ArrayList<Integer> run_count = new ArrayList<Integer>();
int i = 0;
int r_count = Collections.frequency(run_count, i);
while (i < 100) {
run_count.add(r_count);
i++;
r_count = Collections.frequency(runs, i);
}
Iterator<Integer> i_runs = run_count.iterator();
i = 0;
while (i_runs.hasNext()) {
int run = i_runs.next();
String line = \"run_\" + i + \" ,\" + run;
i++;
out.println(line);
}
}
public void run() throws Exception {
FileReader fin = this.readFile();
ArrayList<Integer> data = this.getData(fin);
ArrayList<Integer> runs = this.calcRuns(data);
this.writeOutput(runs);
}
}
Solution
In your program you have to change the syntax errors at method declaration.so your not getting output.
.
5. Ввод-вывод, доступ к файловой системе
5.1 Доступ к файловой системе
5.2 Потоки байт
5.3 Потоки символов
5.4 Продвинутые возможности
Know how to redirect input and output- and know how to append to an ex.docx
Know how to redirect input and output, and know how to append to an existing file. Example: run/usr/local/task with input redirected from blah.txt. and the output appended to file tylk.data
Solution
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStreamReader;
class Main {
public static void main(String[] args) throws IOException {
File dir = new File(\"run/user/local/task.\");
String source = dir.getCanonicalPath() + File.separator + \"blah.txt\";
String dest = dir.getCanonicalPath() + File.separator + \"tylk.data\";
File fin = new File(source);
FileInputStream fis = new FileInputStream(fin);
BufferedReader in = new BufferedReader(new InputStreamReader(fis));
FileWriter fstream = new FileWriter(dest, true);
BufferedWriter out = new BufferedWriter(fstream);
String aLine = null;
while ((aLine = in.readLine()) != null) {
out.write(aLine);
out.newLine();
}
// do not forget to close the buffer reader
in.close();
// close buffer writer
out.close();
}
}
.
Change the code in Writer.java only to get it working. Must contain .pdf
Change the code in Writer.java only to get it working. Must contain methods: logReverse() ,
logMax(), logDuplicates(),
This lab is going to focus on File Output, which you will find is somewhat similar to console
output.
FileMain.java
import java.io.IOException;
import java.util.ArrayList;
import java.util.Scanner;
public class FileMain {
public static void main(String[] args) throws IOException{
Scanner scnr = new Scanner(System.in);
System.out.print("Please enter the name of the file you would like to read: ");
String fileName = scnr.next();
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents(fileName);
System.out.println("Please enter a name for your new file: ");
String newFileName = scnr.next();
Writer fileOut = new Writer(newFileName);
fileOut.logReverse(fileContents);
fileOut.logMax(fileContents);
fileOut.logDuplicates(fileContents);
fileOut.closeWriter();
scnr.close();
}
}
Filetester.java
import java.io.IOException;
import java.util.ArrayList;
public class FileTester {
public static boolean testLogReverse(ArrayList contents) throws IOException {
Writer writer = new Writer("logReverseTest.txt");
writer.logReverse(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Reversed file contents: ");
expected.add("58");
expected.add("12");
expected.add("19");
expected.add("42");
expected.add("12");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logReverseTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogMax(ArrayList contents) throws IOException {
Writer writer = new Writer("logMaxTest.txt");
writer.logMax(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("The largest number in the file is: 58");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logMaxTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogDuplicates(ArrayList contents) throws IOException {
Writer writer = new Writer("logDuplicatesTest.txt");
writer.logDuplicates(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Duplicates found: true");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logDuplicatesTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static void main(String[] args) throws IOException {
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents("nums.txt");
System.out.println("logReverse test passed? " + testLogReverse(fileContents));
System.out.println("logMax test passed? " + testLogMax(fileContents));
System.out.println("logDuplicates test passed? " + testLogDuplicates(fileContents));
}
}
Reader.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Sca.
Write a java program that allows the user to input the name of a fil.docx
Write a java program that allows the user to input the name of a fil
Write a java program that allows the user to input the name of a file.docx
Write a java program that allows the user to input the name of a file that contains positive integers (one integer per line) The number of integers in the file The program should find all odd and even numbers and write the odd numbers to a file \"odd.txt\" and write the even numbers to another file \"even.txt\"
Solution
package expertques;
import java.io.File;
import java.io.PrintWriter;
import java.util.Scanner;
public class evenoddwithfile {
public static void main(String[] args) throws Exception {
File in;//file input
File even = new File(\"f://even.txt\");//creates file even
File odd = new File(\"f://odd.txt\");//creates file odd
Scanner s = new Scanner(System.in);//reads input from console or user
System.out.println(\"Enter the file name with path: \");
in = new File(s.nextLine());
System.out.println(\"Enter the number of integers n the file: \");
int n = s.nextInt();
if (in.exists()) {//checks if input file exist or not
Scanner ins = new Scanner(in);//reads input file
PrintWriter pe = new PrintWriter(even);//write to even file
PrintWriter po = new PrintWriter(odd);//writes to odd file
for (int i = 0; i < n; i++) {//loop till the numbers exists
int x = ins.nextInt();//reads from input file
if (x % 2 == 0) {//checks for even or odd
pe.println(x);//if even writes in even file
} else {
po.println(x);//if odd writes in odd file
}
}
pe.close();//closes even file very important else nothing will be written in the file
po.close();//closes odd file very important else nothing will be written in the file
System.out.println(\"File successfully written with odds and evens\");
} else {
System.out.println(\"Error file not found at specified path\");//if file not exist
}
}
}
output
run:
Enter the file name with path:
f://integers.txt
Enter the number of integers n the file:
8
File successfully written with odds and evens
BUILD SUCCESSFUL (total time: 6 seconds)
.
Application-Specific Models and Pointcuts using a Logic Meta Language
Application-Specific Models and Pointcuts using a Logic Meta Language, Johan Brichau, Andy Kellens Kris Gybels, Kim Mens, ESUG 2006, Prague
Similar to DisplayBook.java import java.io.File; import java.io.FileInput.pdf (20)
The Java Program for the above given isimport java.io.File;impo.pdf
The Java Program for the above given isimport java.io.File;impo.pdf
2. Write a program which will open an input file and write to an out.pdf
2. Write a program which will open an input file and write to an out.pdf
I can not get my code to comply it gets mad that I have run declare mo.docx
I can not get my code to comply it gets mad that I have run declare mo.docx
Know how to redirect input and output- and know how to append to an ex.docx
Know how to redirect input and output- and know how to append to an ex.docx
Change the code in Writer.java only to get it working. Must contain .pdf
Change the code in Writer.java only to get it working. Must contain .pdf
Write a java program that allows the user to input the name of a fil.docx
Write a java program that allows the user to input the name of a fil.docx
Write a java program that allows the user to input the name of a file.docx
Write a java program that allows the user to input the name of a file.docx
Application-Specific Models and Pointcuts using a Logic Meta Language
Application-Specific Models and Pointcuts using a Logic Meta Language
More from sudheerforce
Step1 Equivalents of NaOH= .1146 x[19.25-.55]x10^.pdf
Step1 Equivalents of NaOH= .1146 x[19.25-.55]x10^-3 =2.14302x10^-3 Step2
Equivalents of acid = .225/E ; E be the equivalent eight of acid Step3 .225/E = 2.14302x10^-3
or E=105
Solution
Step1 Equivalents of NaOH= .1146 x[19.25-.55]x10^-3 =2.14302x10^-3 Step2
Equivalents of acid = .225/E ; E be the equivalent eight of acid Step3 .225/E = 2.14302x10^-3
or E=105.
step 1 Br2 under UV light step 2 NMe3 Solu.pdf
step 1: Br2 under UV light step 2: NMe3
Solution
step 1: Br2 under UV light step 2: NMe3.
Since column chromatography substances are separa.pdf
Since column chromatography substances are separated on the basis of their
movement. As impurity atoms are less adsorbed in solution so their movement is less and we get
separated solution form impurity
Solution
Since column chromatography substances are separated on the basis of their
movement. As impurity atoms are less adsorbed in solution so their movement is less and we get
separated solution form impurity.
Oh group is removed by Br yes ther can be two ty.pdf
Oh group is removed by Br yes ther can be two types of isomers Br can be above
the plane or below the plane of ring
Solution
Oh group is removed by Br yes ther can be two types of isomers Br can be above
the plane or below the plane of ring.
Moles of Na2O2 = 2578=0.32 Moles of H2O = 12.11.pdf
Moles of Na2O2 = 25/78=0.32 Moles of H2O = 12.1/18=0.6722 Since Na2O2 is
the limiting reagent Heat released = 0.32*126 =40.32 kj
Solution
Moles of Na2O2 = 25/78=0.32 Moles of H2O = 12.1/18=0.6722 Since Na2O2 is
the limiting reagent Heat released = 0.32*126 =40.32 kj.
Is this a reduction oxidation reaction If so, wh.pdf
Is this a reduction oxidation reaction? If so, what you use is the periodic table.
Hydrogen will always have a +1 charge associated with it and Br and F are both halogens which
have a -1 charge associated with them. For your reaction, Hydrogen is staying constant at +1
while Br is going from -1 to 0 and F is going from 0 to -1. When atoms are bound to other atoms,
they display a charge. When they are not bound or in their natural state, the associated charge is
0. Since Br and F are both diatomic (2 atoms=natural state), their charges are 0. So hydrogen is
staying constant, Br is being oxidized and F is being reduced. Hope this helps!
Solution
Is this a reduction oxidation reaction? If so, what you use is the periodic table.
Hydrogen will always have a +1 charge associated with it and Br and F are both halogens which
have a -1 charge associated with them. For your reaction, Hydrogen is staying constant at +1
while Br is going from -1 to 0 and F is going from 0 to -1. When atoms are bound to other atoms,
they display a charge. When they are not bound or in their natural state, the associated charge is
0. Since Br and F are both diatomic (2 atoms=natural state), their charges are 0. So hydrogen is
staying constant, Br is being oxidized and F is being reduced. Hope this helps!.
HNO3========= H+ (aq) + NO3-(aq) [H+] = 0.0578 .pdf
HNO3=========> H+ (aq) + NO3-(aq) [H+] = 0.0578 M [H+][OH-] =1.0*10^-
14 [OH-] = (1.0*10^-14)/[H+]= (1.0*10^-14)/0.0578 = 1.73*10^-13 pH = -log[H+] = -
log(0.0578)=1.238=1.24 pH+pOH=14 pOH=14-pH=14-1.24=12.76
Solution
HNO3=========> H+ (aq) + NO3-(aq) [H+] = 0.0578 M [H+][OH-] =1.0*10^-
14 [OH-] = (1.0*10^-14)/[H+]= (1.0*10^-14)/0.0578 = 1.73*10^-13 pH = -log[H+] = -
log(0.0578)=1.238=1.24 pH+pOH=14 pOH=14-pH=14-1.24=12.76.
Valley fever is the initial form of coccidioidomycosis infection. Th.pdf
Valley fever is the initial form of coccidioidomycosis infection. This initial, acute illness can
develop into a more serious disease, including chronic and disseminated coccidioidomycosis.
Microrganism is Coccidioides immitis
Acute coccidioidomycosis (valley fever)
The initial, or acute, form of coccidioidomycosis is often mild, with few, if any, symptoms.
When signs and symptoms do occur, they appear one to three weeks after exposure. They tend to
resemble those of the flu, and can range from minor to severe, including:
The rash that sometimes accompanies valley fever is made up of painful red bumps that may
later turn brown. The rash mainly appears on your lower legs, but sometimes on your chest, arms
and back. Others may have a raised red rash with blisters or eruptions that look like pimples.
If you don\'t become ill from valley fever, you may only find out you\'ve been infected when you
later have a positive skin or blood test or when small areas of residual infection (nodules) in the
lungs show up on a routine chest X-ray. Although the nodules typically don\'t cause problems,
they can look like cancer on X-rays.
If you do develop symptoms, especially severe ones, the course of the disease is highly variable.
It can take months to fully recover, and fatigue and joint aches can last even longer. The severity
of the disease depends on several factors, including your overall health and the number of fungus
spores you inhale.
Chronic coccidioidomycosis
If the initial coccidioidomycosis infection doesn\'t completely resolve, it may progress to a
chronic form of pneumonia. This complication is most common in people with weakened
immune systems.
Signs and symptoms include:
Disseminated coccidioidomycosis
The most serious form of the disease, disseminated coccidioidomycosis, occurs when the
infection spreads (disseminates) beyond the lungs to other parts of the body. Most often these
parts include the skin, bones, liver, brain, heart, and the membranes that protect the brain and
spinal cord (meninges).
The signs and symptoms of disseminated disease depend on which parts of your body are
affected and may include:
Solution
Valley fever is the initial form of coccidioidomycosis infection. This initial, acute illness can
develop into a more serious disease, including chronic and disseminated coccidioidomycosis.
Microrganism is Coccidioides immitis
Acute coccidioidomycosis (valley fever)
The initial, or acute, form of coccidioidomycosis is often mild, with few, if any, symptoms.
When signs and symptoms do occur, they appear one to three weeks after exposure. They tend to
resemble those of the flu, and can range from minor to severe, including:
The rash that sometimes accompanies valley fever is made up of painful red bumps that may
later turn brown. The rash mainly appears on your lower legs, but sometimes on your chest, arms
and back. Others may have a raised red rash with blisters or eruptions that look like pimples.
If you don\'t become ill from .
Yes,The interthalamic adhesion (also known as the mass intermedia or.pdf
Yes,The interthalamic adhesion (also known as the mass intermedia or middle commissure) is a
flattened band of tissue that connects both parts of the thalamus at their medial surfaces. The
medial surfaces form the upper part of the lateral wall to the third ventricle.
Solution
Yes,The interthalamic adhesion (also known as the mass intermedia or middle commissure) is a
flattened band of tissue that connects both parts of the thalamus at their medial surfaces. The
medial surfaces form the upper part of the lateral wall to the third ventricle..
Think of the X and Y as totally different events. The expected value.pdf
Think of the X and Y as totally different events. The expected value for X will be the middle of
the interval because all the points are equally weighted.
E(X) = 0.5
The same goes for Y.
E(Y) = 0.5
The triangle (0, 0.5) (0.5, 0) (0,0) has base=0.5 and height = 0.5
A = (1/2)(BH) = (1/2)(0.5)(0.5) = 0.125 = 1/8
Solution
Think of the X and Y as totally different events. The expected value for X will be the middle of
the interval because all the points are equally weighted.
E(X) = 0.5
The same goes for Y.
E(Y) = 0.5
The triangle (0, 0.5) (0.5, 0) (0,0) has base=0.5 and height = 0.5
A = (1/2)(BH) = (1/2)(0.5)(0.5) = 0.125 = 1/8.
There are two source terms in Maxwell’s equations, the static charge.pdf
There are two source terms in Maxwell’s equations, the static charge density and the dynamic
current density J.
Solution
There are two source terms in Maxwell’s equations, the static charge density and the dynamic
current density J..
The xenate ion, [HXeO4]-, slowly decomposes in alkaline solution to .pdf
The xenate ion, [HXeO4]-, slowly decomposes in alkaline solution to give perxentate (XeO64-)
2HXeO4- + 2OH- = XeO64- + Xe + O2 + 2H2O
Solution
The xenate ion, [HXeO4]-, slowly decomposes in alkaline solution to give perxentate (XeO64-)
2HXeO4- + 2OH- = XeO64- + Xe + O2 + 2H2O.
The strengths of the Indian Parliamentary System of governanace1..pdf
The strengths of the Indian Parliamentary System of governanace:
1.Smooth functioning of the government through the legislature and administration when the
party enjoys majority in the Parliament.
2. Decision making is quick - Majority of the ruling party in the Parliament facilitates speedy
decision making and implementation of policies.
3. Flexible system - can quickly adapt to changing situations. During grave situations the
leadership can be changed without harassment like during the \"emergency\" period.
4. Transparent Administration - Executive remains ever vigilant to secure its future electoral
prospects and the Parliament controls the executive through the requirement of the party have the
confidence of the house and through the financial powers vested in the Parliament.This controls
the executive from misuse of power and funds.
5. A nation with so many varied groups get an opportunity for representation.
6. The executive and legislature are not totally separated and thus while the executive wing has
the freedom to act on policies and yet it is accountable to the Parliament for its actions.
Disadvantages:
1. Absolute majority in the Parliament brings about a tendency of the ruling party to be
dictatorial and engenders the possibilities of corruption.
2. Politicization of the administration as decision making takes into account the political
ramifications more than the merits of the decision.
3. Unsuitable for multi-party system as coalition governments bring about logjams and much
delayed decision making in the Parliament. The bureaucracy too lacks direction and leadership in
those times and the policy making and implemntation thereof \'crawls\' during such periods.
4. Unsuitable for managing crisis situations rapidly as the PM and his Council of Ministers have
the political ramifications weighing over them more so than the criticality of the situation that
they have to respond to.
The above is from data from the Net and personal experience.
Solution
The strengths of the Indian Parliamentary System of governanace:
1.Smooth functioning of the government through the legislature and administration when the
party enjoys majority in the Parliament.
2. Decision making is quick - Majority of the ruling party in the Parliament facilitates speedy
decision making and implementation of policies.
3. Flexible system - can quickly adapt to changing situations. During grave situations the
leadership can be changed without harassment like during the \"emergency\" period.
4. Transparent Administration - Executive remains ever vigilant to secure its future electoral
prospects and the Parliament controls the executive through the requirement of the party have the
confidence of the house and through the financial powers vested in the Parliament.This controls
the executive from misuse of power and funds.
5. A nation with so many varied groups get an opportunity for representation.
6. The executive and legislature are not totally separated and thus while .
Pulse code modulationPulse code modulation is a digital sign of a.pdf
Pulse code modulation:
Pulse code modulation is a digital sign of an analog signal that takes samples of the amplitude of
the analog signal at usual intervals. The sampled analog data is changed and then represented in
the form of binary data
Solution
Pulse code modulation:
Pulse code modulation is a digital sign of an analog signal that takes samples of the amplitude of
the analog signal at usual intervals. The sampled analog data is changed and then represented in
the form of binary data.
PFA JAVA programimport java.io.; import java.util.; import .pdf
PFA JAVA program:
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Bus {
static int[] applyPulse(String registers, String pulses)
{
int[] register=new int[4];
int[] pulse=new int[3];
int i=0;
StringTokenizer st = new StringTokenizer(registers,\" \");
while (st.hasMoreElements()) {
register[i++]=Integer.parseInt(st.nextElement().toString());
}
i=0;
st = new StringTokenizer(pulses,\" \");
while (st.hasMoreElements()) {
pulse[i++]=Integer.parseInt(st.nextElement().toString());
}
//Now ewe have, register [0] is A, register [1] is AB,register [3] is C and register [4] is D
if(pulse[0]==1) // if L=1
{
register[1]=register[0];
register[2]=register[0];
}
if(pulse[0]==1) // if M=1
{
register[0]=register[3];
}
if(pulse[0]==1) // if N=1
{
register[1]=register[2];
register[3]=register[2];
}
return register;
}
public static void main(String[] args) {
Scanner sc= new Scanner(System.in);
System.out.println(\"Enter initial values of four regisers A B C D seperated by spaces\");
String registers=sc.nextLine();
System.out.println(\"Ener value of Clock Pulse L M N seperated by spaces\");
String pulses=sc.nextLine();
System.out.println(\"Values of registers A B C D respectively after applying pulse:\");
int[] arr=applyPulse(registers,pulses);
for(int i=0;i<4;i++)
{
System.out.print(arr[i]+\" \");
}
}
}
Solution
PFA JAVA program:
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Bus {
static int[] applyPulse(String registers, String pulses)
{
int[] register=new int[4];
int[] pulse=new int[3];
int i=0;
StringTokenizer st = new StringTokenizer(registers,\" \");
while (st.hasMoreElements()) {
register[i++]=Integer.parseInt(st.nextElement().toString());
}
i=0;
st = new StringTokenizer(pulses,\" \");
while (st.hasMoreElements()) {
pulse[i++]=Integer.parseInt(st.nextElement().toString());
}
//Now ewe have, register [0] is A, register [1] is AB,register [3] is C and register [4] is D
if(pulse[0]==1) // if L=1
{
register[1]=register[0];
register[2]=register[0];
}
if(pulse[0]==1) // if M=1
{
register[0]=register[3];
}
if(pulse[0]==1) // if N=1
{
register[1]=register[2];
register[3]=register[2];
}
return register;
}
public static void main(String[] args) {
Scanner sc= new Scanner(System.in);
System.out.println(\"Enter initial values of four regisers A B C D seperated by spaces\");
String registers=sc.nextLine();
System.out.println(\"Ener value of Clock Pulse L M N seperated by spaces\");
String pulses=sc.nextLine();
System.out.println(\"Values of registers A B C D respectively after applying pulse:\");
int[] arr=applyPulse(registers,pulses);
for(int i=0;i<4;i++)
{
System.out.print(arr[i]+\" \");
}
}
}.
D) four s bonds Pi bonds are double bonds as carb.pdf
D) four s bonds Pi bonds are double bonds as carbon cannot support them...four
valence electrons,
Solution
D) four s bonds Pi bonds are double bonds as carbon cannot support them...four
valence electrons,.
out of Africa hypothesis out of Africa hypothesis is about .pdf
\"out of Africa hypothesis\": \"out of Africa hypothesis\" is about the origin of human beings
from africa. this theory is highly acceptedby various researchers because of the strong evidence
of
Solution
\"out of Africa hypothesis\": \"out of Africa hypothesis\" is about the origin of human beings
from africa. this theory is highly acceptedby various researchers because of the strong evidence
of.
Leukocytes or WBC They are of two typesGranulocytes Neutrophils.pdf
Leukocytes or WBC: They are of two types:
Granulocytes: Neutrophils, eosinohils, and basophils
Agranulocytes: Monocytes and lymphocytes
Neutrophils: MOst numberous of all the WBC, make 60 - 80% of WBC. Upon Giemsa staining,
the granules take up both eosin red and methylene blue, thus appear purple color. The cytoplasm
stains blue with multilobed nucleus. Their number increases in pathological conditions like
infectionss.
Eosinophils: upto 6% of total WBC, their granules take up Eosin red and appear red to pink
colored, due to eosinophilic cationic protein that binds the dye. Cytoplasm stains blue, bilobed
nucleus. The number increases with conditions like parasitic manifestations and viral infections.
Basophils: Generally absent or rarely found in healthy people. Their granules take up methylene
blue due to negatively charged molecles like heparin present in them. They are responsible for
certian types of hypersensitivities. Their number increaes during allergies.
Monocytes: They have a slightly indented nucleus that occupies about half of the cell. They are
larger than other cells. The cytoplasm shows granules but are not conspicuously stained. They
are cells that have the function of phagocytosis, next to neutrophils.
Lymphocytes: Large nucleus that occupies most of the cell leaving a thin rim of cytoplasm. They
produce antibodies.Nucleus stains purple and cytoplasm blue. Their number increases in
conditions like leukemia.
Solution
Leukocytes or WBC: They are of two types:
Granulocytes: Neutrophils, eosinohils, and basophils
Agranulocytes: Monocytes and lymphocytes
Neutrophils: MOst numberous of all the WBC, make 60 - 80% of WBC. Upon Giemsa staining,
the granules take up both eosin red and methylene blue, thus appear purple color. The cytoplasm
stains blue with multilobed nucleus. Their number increases in pathological conditions like
infectionss.
Eosinophils: upto 6% of total WBC, their granules take up Eosin red and appear red to pink
colored, due to eosinophilic cationic protein that binds the dye. Cytoplasm stains blue, bilobed
nucleus. The number increases with conditions like parasitic manifestations and viral infections.
Basophils: Generally absent or rarely found in healthy people. Their granules take up methylene
blue due to negatively charged molecles like heparin present in them. They are responsible for
certian types of hypersensitivities. Their number increaes during allergies.
Monocytes: They have a slightly indented nucleus that occupies about half of the cell. They are
larger than other cells. The cytoplasm shows granules but are not conspicuously stained. They
are cells that have the function of phagocytosis, next to neutrophils.
Lymphocytes: Large nucleus that occupies most of the cell leaving a thin rim of cytoplasm. They
produce antibodies.Nucleus stains purple and cytoplasm blue. Their number increases in
conditions like leukemia..
More from sudheerforce (20)
Step1 Equivalents of NaOH= .1146 x[19.25-.55]x10^.pdf
Step1 Equivalents of NaOH= .1146 x[19.25-.55]x10^.pdf
Since column chromatography substances are separa.pdf
Since column chromatography substances are separa.pdf
Oh group is removed by Br yes ther can be two ty.pdf
Oh group is removed by Br yes ther can be two ty.pdf
Moles of Na2O2 = 2578=0.32 Moles of H2O = 12.11.pdf
Moles of Na2O2 = 2578=0.32 Moles of H2O = 12.11.pdf
Is this a reduction oxidation reaction If so, wh.pdf
Is this a reduction oxidation reaction If so, wh.pdf
HNO3========= H+ (aq) + NO3-(aq) [H+] = 0.0578 .pdf
HNO3========= H+ (aq) + NO3-(aq) [H+] = 0.0578 .pdf
Valley fever is the initial form of coccidioidomycosis infection. Th.pdf
Valley fever is the initial form of coccidioidomycosis infection. Th.pdf
Yes,The interthalamic adhesion (also known as the mass intermedia or.pdf
Yes,The interthalamic adhesion (also known as the mass intermedia or.pdf
Think of the X and Y as totally different events. The expected value.pdf
Think of the X and Y as totally different events. The expected value.pdf
There are two source terms in Maxwell’s equations, the static charge.pdf
There are two source terms in Maxwell’s equations, the static charge.pdf
The xenate ion, [HXeO4]-, slowly decomposes in alkaline solution to .pdf
The xenate ion, [HXeO4]-, slowly decomposes in alkaline solution to .pdf
The strengths of the Indian Parliamentary System of governanace1..pdf
The strengths of the Indian Parliamentary System of governanace1..pdf
Pulse code modulationPulse code modulation is a digital sign of a.pdf
Pulse code modulationPulse code modulation is a digital sign of a.pdf
PFA JAVA programimport java.io.; import java.util.; import .pdf
PFA JAVA programimport java.io.; import java.util.; import .pdf
D) four s bonds Pi bonds are double bonds as carb.pdf
D) four s bonds Pi bonds are double bonds as carb.pdf
out of Africa hypothesis out of Africa hypothesis is about .pdf
out of Africa hypothesis out of Africa hypothesis is about .pdf
Leukocytes or WBC They are of two typesGranulocytes Neutrophils.pdf
Leukocytes or WBC They are of two typesGranulocytes Neutrophils.pdf
Recently uploaded
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
The Roman Empire A Historical Colossus.pdf
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
How to Make a Field invisible in Odoo 17
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
Unit 2- Research Aptitude (UGC NET Paper I).pdf
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
Sectors of the Indian Economy - Class 10 Study Notes pdf
The Indian economy is classified into different sectors to simplify the analysis and understanding of economic activities. For Class 10, it's essential to grasp the sectors of the Indian economy, understand their characteristics, and recognize their importance. This guide will provide detailed notes on the Sectors of the Indian Economy Class 10, using specific long-tail keywords to enhance comprehension.
For more information, visit-www.vavaclasses.com
1.4 modern child centered education - mahatma gandhi-2.pptx
Child centred education is an educational approach that priorities the interest, needs and abilities of the child in the learning process.
How to Break the cycle of negative Thoughts
We all have good and bad thoughts from time to time and situation to situation. We are bombarded daily with spiraling thoughts(both negative and positive) creating all-consuming feel , making us difficult to manage with associated suffering. Good thoughts are like our Mob Signal (Positive thought) amidst noise(negative thought) in the atmosphere. Negative thoughts like noise outweigh positive thoughts. These thoughts often create unwanted confusion, trouble, stress and frustration in our mind as well as chaos in our physical world. Negative thoughts are also known as “distorted thinking”.
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Andreas Schleicher presents at the OECD webinar ‘Digital devices in schools: detrimental distraction or secret to success?’ on 27 May 2024. The presentation was based on findings from PISA 2022 results and the webinar helped launch the PISA in Focus ‘Managing screen time: How to protect and equip students against distraction’ https://www.oecd-ilibrary.org/education/managing-screen-time_7c225af4-en and the OECD Education Policy Perspective ‘Students, digital devices and success’ can be found here - https://oe.cd/il/5yV
The Challenger.pdf DNHS Official Publication
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
Synthetic Fiber Construction in lab .pptx
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
for studentd in cabridge board
The Art Pastor's Guide to Sabbath | Steve Thomason
What is the purpose of the Sabbath Law in the Torah. It is interesting to compare how the context of the law shifts from Exodus to Deuteronomy. Who gets to rest, and why?
Introduction to Quality Improvement Essentials
This is a presentation by Dada Robert in a Your Skill Boost masterclass organised by the Excellence Foundation for South Sudan (EFSS) on Saturday, the 25th and Sunday, the 26th of May 2024.
He discussed the concept of quality improvement, emphasizing its applicability to various aspects of life, including personal, project, and program improvements. He defined quality as doing the right thing at the right time in the right way to achieve the best possible results and discussed the concept of the "gap" between what we know and what we do, and how this gap represents the areas we need to improve. He explained the scientific approach to quality improvement, which involves systematic performance analysis, testing and learning, and implementing change ideas. He also highlighted the importance of client focus and a team approach to quality improvement.
Supporting (UKRI) OA monographs at Salford.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Recently uploaded (20)
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
Sectors of the Indian Economy - Class 10 Study Notes pdf
Sectors of the Indian Economy - Class 10 Study Notes pdf
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
Digital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and Research
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Basic phrases for greeting and assisting costumers
Basic phrases for greeting and assisting costumers
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
The Art Pastor's Guide to Sabbath | Steve Thomason
The Art Pastor's Guide to Sabbath | Steve Thomason
DisplayBook.java import java.io.File; import java.io.FileInput.pdf
- 1. DisplayBook.java import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.util.Scanner; public class DisplayBook { public static void main(String[] args) throws IOException { // TODO Auto-generated method stub Scanner scan = new Scanner(System.in); File file = new File("D:books.txt"); if(file.exists()){ System.out.println("File exists"); FileInputStream fis = new FileInputStream(file); int content; while ((content = fis.read()) != -1) { System.out.print((char) content); } fis.close(); } else{ System.out.println("File does not exist"); String titles = ""; FileOutputStream fop = new FileOutputStream(file); while(true){ System.out.println("Enter Book Title (none to exit):"); String title = scan.nextLine(); if(title.equalsIgnoreCase("none")){ break; } else{ titles = titles + title +" "; }
- 2. } byte[] contentInBytes = titles.getBytes(); fop.write(contentInBytes); fop.flush(); fop.close(); } } } Output: File does not exist Enter Book Title (none to exit): Physics Enter Book Title (none to exit): Chemistry Enter Book Title (none to exit): Science Enter Book Title (none to exit): Maths Enter Book Title (none to exit): none -------------------------------------- File exists Physics Chemistry Science Maths Solution DisplayBook.java import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException;
- 3. import java.util.Scanner; public class DisplayBook { public static void main(String[] args) throws IOException { // TODO Auto-generated method stub Scanner scan = new Scanner(System.in); File file = new File("D:books.txt"); if(file.exists()){ System.out.println("File exists"); FileInputStream fis = new FileInputStream(file); int content; while ((content = fis.read()) != -1) { System.out.print((char) content); } fis.close(); } else{ System.out.println("File does not exist"); String titles = ""; FileOutputStream fop = new FileOutputStream(file); while(true){ System.out.println("Enter Book Title (none to exit):"); String title = scan.nextLine(); if(title.equalsIgnoreCase("none")){ break; } else{ titles = titles + title +" "; } } byte[] contentInBytes = titles.getBytes(); fop.write(contentInBytes); fop.flush(); fop.close(); }
- 4. } } Output: File does not exist Enter Book Title (none to exit): Physics Enter Book Title (none to exit): Chemistry Enter Book Title (none to exit): Science Enter Book Title (none to exit): Maths Enter Book Title (none to exit): none -------------------------------------- File exists Physics Chemistry Science Maths