Use arrays to store data for analysis. Use functions to perform the .pdf
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Use arrays to store data for analysis. Use functions to perform the analysis described below. All output is to be written to an output file. Solution import java.util.Scanner; import java.util.ArrayList; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.io.ObjectInputStream; import java.io.ObjectOutputStream; import java.util.ArrayList; public class DNA{ private String dna; public DNA(){ } public void read_store(String filename){ /*try { Scanner in; //in = new Scanner(new FileReader(filename)); dna = in.next(); }catch(IOException e){ System.out.println(\"file not there \" + e); return; }*/ } public char compliment_base(char c){ if(c == \'A\') return \'T\'; if(c == \'T\') return \'A\'; if(c == \'G\') return \'C\'; if(c == \'C\') return \'G\'; return \' \'; } public void DrawDNA(String seq){ System.out.println(\"---+-----+------+------+------\"); for (char c : seq.toCharArray() ) { System.out.print(c + \" \"); } System.out.println(\"DNA Sequence \"); System.out.println(\"................................\"); for (char c : seq.toCharArray() ) { System.out.print(compliment_base(c) + \" \"); } System.out.println(\" Complement \"); System.out.println(\"---+-----+------+------+------\"); System.out.println(\"\"); } public void Prefix(int n, String base){ String output = base.substring(0,n); DrawDNA(output); } public static void main(String[] args) { DNA d = new DNA(); d.DrawDNA(\"ATGC\"); d.Prefix(4,\"ACGTTGCA\"); } } ---+-----+------+------+------ A T G C DNA Sequence ................................ T A C G Complement ---+-----+------+------+------ ---+-----+------+------+------ A C G T DNA Sequence ................................ T G C A Complement ---+-----+------+------+------.
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![if(c == 'C') return 'G';
return ' ';
}
public void DrawDNA(String seq){
System.out.println("---+-----+------+------+------");
for (char c : seq.toCharArray() ) {
System.out.print(c + " ");
}
System.out.println("DNA Sequence ");
System.out.println("................................");
for (char c : seq.toCharArray() ) {
System.out.print(compliment_base(c) + " ");
}
System.out.println(" Complement ");
System.out.println("---+-----+------+------+------");
System.out.println("");
}
public void Prefix(int n, String base){
String output = base.substring(0,n);
DrawDNA(output);
}
public static void main(String[] args) {
DNA d = new DNA();
d.DrawDNA("ATGC");
d.Prefix(4,"ACGTTGCA");
}
}
---+-----+------+------+------
A T G C DNA Sequence](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
Write a Java program that opens the file, reads all the Grade from t.pdf
Write a Java program that opens the file, reads all the Grade from the file, and using a method
calculates and displays the following A) Displays the grades with their letter values (80 - B) B)
the sum of the Grades in the file C) the average of the Grades in the file
Solution
GradeRead.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class GradeRead {
public static void main(String[] args) throws FileNotFoundException {
Scanner scan1 = new Scanner(System.in);
System.out.print(\"Enter the file name: \");
String fileName = scan1.next();
File file = new File(fileName);
if(file.exists()){
Scanner scan = new Scanner(file);
calculateGradeDetail(scan);
}
else{
System.out.println(\"Input does not exist\");
}
}
public static void calculateGradeDetail(Scanner scan){
int sum = 0;
int count = 0;
char gradeLetter = \'\\0\';
while(scan.hasNextInt()){
count++;
int n = scan.nextInt();
sum = sum + n;
if(n >=90 && n<=100){
gradeLetter = \'A\';
}
else if(n >=80 && n<90){
gradeLetter = \'B\';
}
else if(n >=70 && n<80){
gradeLetter = \'C\';
}
else if(n >=60 && n<=70){
gradeLetter = \'D\';
}
else {
gradeLetter = \'E\';
}
System.out.println(\"Grade: \"+gradeLetter+\" - \"+n);
}
System.out.println(\"The sum of the Grades in the file: \"+sum);
double average = sum/(double)count;
System.out.println(\"the average of the Grades in the file: \"+average);
System.out.println();
}
}
Output:
Enter the file name: D:\\\\grade.txt
Grade: D - 60
Grade: C - 70
Grade: B - 80
Grade: A - 90
Grade: A - 100
Grade: E - 40
Grade: E - 50
Grade: D - 60
The sum of the Grades in the file: 550
the average of the Grades in the file: 68.75
Grade.txt
60
70
80
90
100
40
50
60.
Not sure why my program wont run.Programmer S.Villegas helper N.pdf
Not sure why my program wont run.
//Programmer: S.Villegas helper Noah
//File name: PP88ArrayList.java
//Description:
//****************************
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class PP88ArrayList
{
public static void main(String[]args)
{
ArrayList persons = new ArrayList(25);
String fileName = \"Zips.dat\";
int i;
Scanner filescasnner = null;
try
{
filescasnner=new Scanner(new File(fileName));
for(i=0;i persons)
{
for (int i = 0; i < persons.size(); i++)
{
for (int j = 0; j < persons.size()-1; j++)
{
if((persons.get(j).getFirstName().compareTo(persons.get(j+1).getFirstName()))>0)
{
Person temp= persons.get(j);
persons.set(j, persons.get(j+1));
persons.set(j+1, temp);
}
}
}
}
public static void sortByZipCode(ArrayList persons)
{
for (int i = 0; i < persons.size(); i++)
{
for (int j = 0; j < persons.size()-1; j++)
{
if(persons.get(j).getZipCode()>persons.get(j+1).getZipCode())
{
Person temp= persons.get(j);
persons.set(j, persons.get(j+1));
persons.set(j+1, temp);
}
}
}
}
}
//Programmer: S.Villegas helper Noah
//File name: PersonList.java
//Description:
//******************************
public class PersonList
{
private String firstName, lastName;
private int Zip;
public PersonList(String firstName,String lastName, int Zip)
{
this.firstName = firstName;
this.lastName = lastName;
this.Zip = Zip;
}
public String getFirstName()
{
return firstName;
}
public int getZipCode()
{
return Zip;
}
public String toString()
{
return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip);
}
}
Solution
//File name: PersonList.java
public class PersonList
{
private String firstName, lastName;
private int Zip;
public PersonList(String firstName,String lastName, int Zip)
{
this.firstName = firstName;
this.lastName = lastName;
this.Zip = Zip;
}
public String getFirstName()
{
return firstName;
}
public int getZipCode()
{
return Zip;
}
public String toString()
{
return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip);
}
}
//File name: PP88ArrayList.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class PP88ArrayList
{
public static void main(String[]args)
{
ArrayList persons = new ArrayList(25);
String fileName = \"Zips.dat\";
int i;
Scanner filescasnner = null;
try
{
filescasnner=new Scanner(new File(fileName));
while(filescasnner.hasNextLine())
{
String firstName = filescasnner.next();
String lastName = filescasnner.next();
int Zip = filescasnner.nextInt();
persons.add(new PersonList(firstName, lastName, Zip));
}
filescasnner.close();
}
catch (FileNotFoundException e)
{
System.out.println(e.getMessage());
}
System.out.println(\"\ List of names and zip codes: \");
System.out.printf(\"%-15s%-15s%-15s\ \",\"First Name\",\"Last Name\",\"Zip\");
for (int j = 0; j < persons.size(); j++)
{
System.out.println(persons.get(j));
}
System.out.println(\"\ List of names sort by first name\");
sortByNa.
Please I am trying to get this code to output in -txt file- I need you.pdf
Please I am trying to get this code to output in .txt file:
I need your help:
import java.io.File; // Import the File class
import java.io.FileNotFoundException; // Import this class to handle errors
// Import the Scanner class to read text files
import java.util.*;
import java.io.*;
public class KMeans {
List<double []> clusterCentroids;
Map<Integer,List<Double>> dataMatrix;
List<double[]> data;
Integer numClusters;
public void writeFile(List<Double> value, File filename) {
try {
FileWriter myWriter = new FileWriter(filename);
myWriter.write(value.toString());
myWriter.close();
System.out.println("Successfully wrote to the file.");
} catch (IOException e) {
System.out.println("An error occurred.");
e.printStackTrace();
}
}
public KMeans() {
data = new ArrayList<double []>();
dataMatrix = new LinkedHashMap<>();
}
void readData(String filePath, int n, List<Double> c) {
numClusters = n;
try {
BufferedReader br = new BufferedReader(new FileReader(new File(filePath)));
String line;
int i = 0;
while((line = br.readLine()) != null) {
String [] elem = line.split("\\s+");
int j = 0;
for(String d : elem) {
if(isCentroid(j, c)) {
this.clusterCentroids.get(i)[j] = ((Double.valueOf(d)));
}
//data.get(i)[j] = ((Double.valueOf(d)));
System.out.println(data.get(j)[i]);
}
System.out.println();
i++;
}
br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
private boolean isCentroid(int j, List<Double> c) {
for(int i = 0; i < c.size(); i++) {
if(j == c.get(i)) {
return true;
}
}
return false;
}
public static void main(String [] args) {
Scanner sc = new Scanner(System.in);
List<Double> centroids = new ArrayList<>();
String filePath = ("C:\\Users\\mamdo\\eclipse-
workspace\\K_project\\src\\synthetic_control_data.txt");
int n = 6;
for(int i=0;i<n;i++) {
Random r = new Random();
centroids.add((double)r.nextInt(600)+1);
}
System.out.println("Initial Clusters Centroids : " + centroids);
KMeans km = new KMeans();
//km.readData(filePath,n,centroids);
//km.calc();
}
}
.
IO Streams, Serialization, de-serialization, autoboxing
In computer science, a stream is a sequence of data elements made available over time. A stream can be thought of as items on a conveyor belt being processed one at a time rather than in large batches.
Streams are processed differently from batch data :
*Normal functions cannot operate on streams as a whole, as they have potentially unlimited data, and formally
*Streams are codata (potentially unlimited), not data (which is finite).
Recommended
Write a Java program that opens the file, reads all the Grade from t.pdf
Write a Java program that opens the file, reads all the Grade from the file, and using a method
calculates and displays the following A) Displays the grades with their letter values (80 - B) B)
the sum of the Grades in the file C) the average of the Grades in the file
Solution
GradeRead.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class GradeRead {
public static void main(String[] args) throws FileNotFoundException {
Scanner scan1 = new Scanner(System.in);
System.out.print(\"Enter the file name: \");
String fileName = scan1.next();
File file = new File(fileName);
if(file.exists()){
Scanner scan = new Scanner(file);
calculateGradeDetail(scan);
}
else{
System.out.println(\"Input does not exist\");
}
}
public static void calculateGradeDetail(Scanner scan){
int sum = 0;
int count = 0;
char gradeLetter = \'\\0\';
while(scan.hasNextInt()){
count++;
int n = scan.nextInt();
sum = sum + n;
if(n >=90 && n<=100){
gradeLetter = \'A\';
}
else if(n >=80 && n<90){
gradeLetter = \'B\';
}
else if(n >=70 && n<80){
gradeLetter = \'C\';
}
else if(n >=60 && n<=70){
gradeLetter = \'D\';
}
else {
gradeLetter = \'E\';
}
System.out.println(\"Grade: \"+gradeLetter+\" - \"+n);
}
System.out.println(\"The sum of the Grades in the file: \"+sum);
double average = sum/(double)count;
System.out.println(\"the average of the Grades in the file: \"+average);
System.out.println();
}
}
Output:
Enter the file name: D:\\\\grade.txt
Grade: D - 60
Grade: C - 70
Grade: B - 80
Grade: A - 90
Grade: A - 100
Grade: E - 40
Grade: E - 50
Grade: D - 60
The sum of the Grades in the file: 550
the average of the Grades in the file: 68.75
Grade.txt
60
70
80
90
100
40
50
60.
Not sure why my program wont run.Programmer S.Villegas helper N.pdf
Not sure why my program wont run.
//Programmer: S.Villegas helper Noah
//File name: PP88ArrayList.java
//Description:
//****************************
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class PP88ArrayList
{
public static void main(String[]args)
{
ArrayList persons = new ArrayList(25);
String fileName = \"Zips.dat\";
int i;
Scanner filescasnner = null;
try
{
filescasnner=new Scanner(new File(fileName));
for(i=0;i persons)
{
for (int i = 0; i < persons.size(); i++)
{
for (int j = 0; j < persons.size()-1; j++)
{
if((persons.get(j).getFirstName().compareTo(persons.get(j+1).getFirstName()))>0)
{
Person temp= persons.get(j);
persons.set(j, persons.get(j+1));
persons.set(j+1, temp);
}
}
}
}
public static void sortByZipCode(ArrayList persons)
{
for (int i = 0; i < persons.size(); i++)
{
for (int j = 0; j < persons.size()-1; j++)
{
if(persons.get(j).getZipCode()>persons.get(j+1).getZipCode())
{
Person temp= persons.get(j);
persons.set(j, persons.get(j+1));
persons.set(j+1, temp);
}
}
}
}
}
//Programmer: S.Villegas helper Noah
//File name: PersonList.java
//Description:
//******************************
public class PersonList
{
private String firstName, lastName;
private int Zip;
public PersonList(String firstName,String lastName, int Zip)
{
this.firstName = firstName;
this.lastName = lastName;
this.Zip = Zip;
}
public String getFirstName()
{
return firstName;
}
public int getZipCode()
{
return Zip;
}
public String toString()
{
return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip);
}
}
Solution
//File name: PersonList.java
public class PersonList
{
private String firstName, lastName;
private int Zip;
public PersonList(String firstName,String lastName, int Zip)
{
this.firstName = firstName;
this.lastName = lastName;
this.Zip = Zip;
}
public String getFirstName()
{
return firstName;
}
public int getZipCode()
{
return Zip;
}
public String toString()
{
return String.format(\"%-15s%-15s%-10d\",firstName,lastName,Zip);
}
}
//File name: PP88ArrayList.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class PP88ArrayList
{
public static void main(String[]args)
{
ArrayList persons = new ArrayList(25);
String fileName = \"Zips.dat\";
int i;
Scanner filescasnner = null;
try
{
filescasnner=new Scanner(new File(fileName));
while(filescasnner.hasNextLine())
{
String firstName = filescasnner.next();
String lastName = filescasnner.next();
int Zip = filescasnner.nextInt();
persons.add(new PersonList(firstName, lastName, Zip));
}
filescasnner.close();
}
catch (FileNotFoundException e)
{
System.out.println(e.getMessage());
}
System.out.println(\"\ List of names and zip codes: \");
System.out.printf(\"%-15s%-15s%-15s\ \",\"First Name\",\"Last Name\",\"Zip\");
for (int j = 0; j < persons.size(); j++)
{
System.out.println(persons.get(j));
}
System.out.println(\"\ List of names sort by first name\");
sortByNa.
Please I am trying to get this code to output in -txt file- I need you.pdf
Please I am trying to get this code to output in .txt file:
I need your help:
import java.io.File; // Import the File class
import java.io.FileNotFoundException; // Import this class to handle errors
// Import the Scanner class to read text files
import java.util.*;
import java.io.*;
public class KMeans {
List<double []> clusterCentroids;
Map<Integer,List<Double>> dataMatrix;
List<double[]> data;
Integer numClusters;
public void writeFile(List<Double> value, File filename) {
try {
FileWriter myWriter = new FileWriter(filename);
myWriter.write(value.toString());
myWriter.close();
System.out.println("Successfully wrote to the file.");
} catch (IOException e) {
System.out.println("An error occurred.");
e.printStackTrace();
}
}
public KMeans() {
data = new ArrayList<double []>();
dataMatrix = new LinkedHashMap<>();
}
void readData(String filePath, int n, List<Double> c) {
numClusters = n;
try {
BufferedReader br = new BufferedReader(new FileReader(new File(filePath)));
String line;
int i = 0;
while((line = br.readLine()) != null) {
String [] elem = line.split("\\s+");
int j = 0;
for(String d : elem) {
if(isCentroid(j, c)) {
this.clusterCentroids.get(i)[j] = ((Double.valueOf(d)));
}
//data.get(i)[j] = ((Double.valueOf(d)));
System.out.println(data.get(j)[i]);
}
System.out.println();
i++;
}
br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
private boolean isCentroid(int j, List<Double> c) {
for(int i = 0; i < c.size(); i++) {
if(j == c.get(i)) {
return true;
}
}
return false;
}
public static void main(String [] args) {
Scanner sc = new Scanner(System.in);
List<Double> centroids = new ArrayList<>();
String filePath = ("C:\\Users\\mamdo\\eclipse-
workspace\\K_project\\src\\synthetic_control_data.txt");
int n = 6;
for(int i=0;i<n;i++) {
Random r = new Random();
centroids.add((double)r.nextInt(600)+1);
}
System.out.println("Initial Clusters Centroids : " + centroids);
KMeans km = new KMeans();
//km.readData(filePath,n,centroids);
//km.calc();
}
}
.
IO Streams, Serialization, de-serialization, autoboxing
In computer science, a stream is a sequence of data elements made available over time. A stream can be thought of as items on a conveyor belt being processed one at a time rather than in large batches.
Streams are processed differently from batch data :
*Normal functions cannot operate on streams as a whole, as they have potentially unlimited data, and formally
*Streams are codata (potentially unlimited), not data (which is finite).
We will be making 4 classes Main - for testing the code Hi.pdf
/*
We will be making 4 classes:
Main - for testing the code
HighscoreManager - to manage the high-scores
HighscoreComparator - I will explain this when we get there
Score - also this I will explain later
all this classes will be in the package \"highscores\"/*
//The Score Class
package highscores;
import java.io.Serializable;
public class Score implements Serializable {
private int score;
private String naam;
public int getScore() {
return score;
}
public String getNaam() {
return naam;
}
public Score(String naam, int score) {
this.score = score;
this.naam = naam;
}
}/*This class makes us able to make an object (an arraylist in our case) of the type Score that
contains the name and score of a player.
We implement serializable to be able to sort this type./*
//The ScoreComparator Class
package highscores;
import java.util.Comparator;
public class ScoreComparator implements Comparator {
public int compare(Score score1, Score score2) {
int sc1 = score1.getScore();
int sc2 = score2.getScore();
if (sc1 > sc2){
return -1;
}else if (sc1 < sc2){
return +1;
}else{
return 0;
}
}
}
/*This class is used to tell Java how it needs to compare 2 objects of the type score.
-1 means the first score is greater than the 2nd one, +1 (or you can just put 1) means it\'s smaller
and 0 means it\'s equal./*
//The HighscoreManager Class
/*First we will be making the HighscoreManager Class, this class will do the most important part
of the high-score system.
We will be using this as our base for the class:/*
package highscores;
import java.util.*;
import java.io.*;
public class HighscoreManager {
// An arraylist of the type \"score\" we will use to work with the scores inside the class
private ArrayList scores;
// The name of the file where the highscores will be saved
private static final String HIGHSCORE_FILE = \"scores.dat\";
//Initialising an in and outputStream for working with the file
ObjectOutputStream outputStream = null;
ObjectInputStream inputStream = null;
public HighscoreManager() {
//initialising the scores-arraylist
scores = new ArrayList();
}
}
/*I have added comments to explain what\'s already in the class.
We will be using a binary file to keep the high-scores in, this will avoid cheating.
To work with the scores we will use an arraylist. An arraylist is one of the great things that java
has and it\'s much better to use in this case than a regular array.
Now we will add some methods and functions./*
public ArrayList getScores() {
loadScoreFile();
sort();
return scores;
}
/*This is a function that will return an arraylist with the scores in it. It contains calls to the
function loadScoreFile() and sort(), these functions will make sure you have the scores from your
high-score file in a sorted order. We will be writing these functions later on./*
private void sort() {
ScoreComparator comparator = new ScoreComparator();
Collections.sort(scores, comparator);
}
/*This function will create a new object \"comparator\" from the class ScoreComparator.
the Colle.
stateDatabuild.xml Builds, tests, and runs the project.docx
stateData/build.xml
Builds, tests, and runs the project stateData.
stateData/manifest.mf
Manifest-Version: 1.0
X-COMMENT: Main-Class will be added automatically by build
stateData/nbproject/build-impl.xml
Must set src.dir
Must set test.src.dir
Must set build.dir
Must set dist.dir
Must set build.classes.dir
Must set dist.javadoc.dir
Must set bui.
Main class --------------------------import java.awt.FlowLayout.pdf
Main class :-
-------------------------
import java.awt.FlowLayout;
import java.awt.Graphics;
import java.awt.GridLayout;
import java.awt.Insets;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JTextField;
public class Main {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
final InfixExperssionEvaluator ie = new InfixExperssionEvaluator();
JFrame frame = new JFrame(\"FrameDemo\");
frame.setSize(600,200);
frame.setLayout(new FlowLayout());
JPanel main = new JPanel(new GridLayout(3, 1));
JPanel panel1 = new JPanel(new GridLayout(1, 2));
panel1.setSize(500, 250);
panel1.add(new JLabel(\"Enter Infix Expression\"));
final JTextField field1 = new JTextField();
field1.setSize(150,100);
panel1.add(field1);
main.add(panel1);
JPanel panel2 = new JPanel(new GridLayout(1, 1));
panel1.setSize(300, 150);
JButton button = new JButton();
button.setSize(200, 100);
button.setText(\"Submit\");
panel2.add(button);
main.add(panel2);
JPanel panel3 = new JPanel(new GridLayout(1, 2));
panel3.add(new JLabel(\"Value : \"));
final JLabel lbl = new JLabel();
panel3.add(lbl);
main.add(panel3);
frame.getContentPane().add(main);
frame.setVisible(true);
button.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
// TODO Auto-generated method stub
if (\"Submit\".equals(e.getActionCommand())) {
String expr = field1.getText();
lbl.setText(Double.toString(ie.infixToValue(expr)));
}
}
});
button.setActionCommand(\"Submit\");
String expr = \"((2*5)+(6/2))\";
System.out.println(\"value is ::\"+ ie.infixToValue(expr));
}
}
Class for Evaluate methods :-
-----------------------------------------
import java.util.ArrayDeque;
import java.util.HashMap;
import java.util.Map;
import java.util.Stack;
import java.util.StringTokenizer;
public class InfixExperssionEvaluator {
Stack expressionStack = new Stack();
Stack valueStack = new Stack(); //to hold only non-decimal values
public static final String OPERATORS=\"+-/*()\"; //ignore the \"(\" as an operator
//Map For Operator precedence Key(+,-,*,/) , value 0/1/2/3..
Map operator_levels = new HashMap();
public InfixExperssionEvaluator(){
operator_levels.put(\")\", 0);
operator_levels.put(\"*\", 1);
operator_levels.put(\"/\", 1);
operator_levels.put(\"+\", 2);
operator_levels.put(\"-\", 2);
operator_levels.put(\"(\", 3);
}
double infixToValue(String inputExpression) {
String eachNumber=\"\"; //to hold multiple digit values. lame idea, i know, but can\'t
think of anything else at 2 AM
int totalCharInInput = inputExpression.length();
inputExpression.replaceAll(\"\\\\s+\",\"\");
//Devide String to Tokens
StringTokenizer tokens = new StringTokenizer(inputExpression, \"{}()*/+-\", true);
//Loop through each Token
while(tokens.hasMoreTokens()){
String eachChar = tokens.nextToken();
if (isValidOperator(eachCh.
Soundreader.classpathSoundreader.project Soundre.docx
Soundreader/.classpath
Soundreader/.project
Soundreader
org.eclipse.jdt.core.javabuilder
org.eclipse.jdt.core.javanature
Soundreader/.settings/org.eclipse.jdt.core.prefs
eclipse.preferences.version=1
org.eclipse.jdt.core.compiler.codegen.inlineJsrBytecode=enabled
org.eclipse.jdt.core.compiler.codegen.targetPlatform=1.8
org.eclipse.jdt.core.compiler.codegen.unusedLocal=preserve
org.eclipse.jdt.core.compiler.compliance=1.8
org.eclipse.jdt.core.compiler.debug.lineNumber=generate
org.eclipse.jdt.core.compiler.debug.localVariable=generate
org.eclipse.jdt.core.compiler.debug.sourceFile=generate
org.eclipse.jdt.core.compiler.problem.assertIdentifier=error
org.eclipse.jdt.core.compiler.problem.enumIdentifier=error
org.eclipse.jdt.core.compiler.source=1.8
Soundreader/bin/ArrayStack.classpublicsynchronizedclass ArrayStack {
private Object[] data;
private int size;
public void ArrayStack();
public boolean isEmpty();
protected boolean isFull();
public Object peek();
public Object pop();
public void push(Object);
protected void stretch();
}
Soundreader/bin/DStack.classpublicabstractinterface DStack {
publicabstract boolean isEmpty();
publicabstract void push(double);
publicabstract double pop();
publicabstract double peek();
}
Soundreader/bin/gtd/stack/ListStackNode.classpackage gtd.stack;
publicfinalsynchronizedclass ListStackNode {
privatestaticfinal EpsilonStackNode EMPTY;
privatefinal String nodeName;
privatefinal AbstractStackNode[] children;
privatefinal AbstractStackNode emptyChild;
public void ListStackNode(int, int, AbstractStackNode, String, boolean);
private void ListStackNode(ListStackNode, int);
AbstractStackNode[] generateChildren(AbstractStackNode);
private AbstractStackNode generateEmptyChild();
public String getName();
public AbstractStackNode getCleanCopy(int);
public AbstractStackNode[] getChildren();
public boolean canBeEmpty();
public AbstractStackNode getEmptyChild();
public String toString();
}
Soundreader/bin/ListStack.classpublicsynchronizedclass ListStack {
private ListNode topOfStack;
public void ListStack();
public boolean isEmpty();
public void makeEmpty();
public void push(Object);
public void pop();
public Object top();
public Object topAndPop();
}
Soundreader/bin/Reverse.classpublicsynchronizedclass Reverse {
public void Reverse();
publicstatic void main(String[]);
}
Soundreader/Screenshot (14).png
Soundreader/Screenshot (15).png
Soundreader/Screenshot (16).png
Soundreader/src/ArrayStack.javaSoundreader/src/ArrayStack.javaimport java.util.EmptyStackException;
publicclassArrayStack<E>implementsDStack<E>{
/** Array of items in this Stack. */
private E[] data;
/** Number of items currently in this Stack. */
privateint size;
/** The Stack is initally empty. */
publicArrayStack(){
data =(E[])(newOb.
(JAVA NetBeans) Write a Java program able to perform selection sort-So.docx
(JAVA NetBeans) Write a Java program able to perform selection sort.
Solution
import java.util.Scanner;
/**
* @author
*
*/
public class SelectionSort {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int arr[] = setArray();
System.out.println(\"\ Before Sorting:\");
printArray(arr);
arr = selectionSort(arr);
System.out.println(\"\ After Sorting:\");
printArray(arr);
}
/**
* reads and stores the data in the one-dimensional array
*/
/**
* @return
*/
public static int[] setArray() {
int arr[] = new int[12];
System.out.println(\"Enter 12 integers.\");
Scanner scanner = new Scanner(System.in);
for (int i = 0; i < arr.length; i++) {
arr[i] = scanner.nextInt();
}
return arr;
}
/**
* prints the data in the one-dimensional array
*/
public static void printArray(int[] arr) {
System.out.println();
for (int i = 0; i < arr.length; i++) {
System.out.print(arr[i] + \" \");
}
System.out.println();
}
/**
* method will sort the array in ascending order
*/
public static int[] selectionSort(int[] arr) {
for (int i = 0; i < arr.length - 1; i++) {
int index = i;
for (int j = i + 1; j < arr.length; j++)
if (arr[j] < arr[index])
index = j;
int smallerNumber = arr[index];
arr[index] = arr[i];
arr[i] = smallerNumber;
}
return arr;
}
}
OUTPUT:
Enter 12 integers.
4 23 65 34 84 37 12 17 24 36 82 51
Before Sorting:
4 23 65 34 84 37 12 17 24 36 82 51
After Sorting:
4 12 17 23 24 34 36 37 51 65 82 84
.
Java Program I keep receiving the following error in my code- Can you.pdf
Java Program
I keep receiving the following error in my code. Can you please fix this error and test to make
sure it does not show a error? I've placed bracets but keep receiving the error "reached end of file
while parsing private static void displayStudent()" See below
Error:
sh -c javac -classpath .:target/dependency/* -d . $(find . -type f -name '*.java')
./Main.java:121: error: reached end of file while parsing
private static void displayStudent()
^
1 error
exit status 1
------------------------------------------
Code:
import java.util.Scanner;
import java.io.File;
import java.io.FileWriter;
import java.io.IOException;
public class StudentCourseProgram {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int choice;
do {
System.out.println("Please choose an option:");
System.out.println("1. Add student");
System.out.println("2. Add course");
System.out.println("3. Display student");
System.out.println("4. Display course");
System.out.println("5. Exit");
choice = input.nextInt();
switch (choice) {
case 1:
addStudent();
break;
case 2:
addCourse();
break;
case 3:
displayStudent();
break;
case 4:
displayCourse();
break;
case 5:
System.out.println("Exiting program...");
break;
default:
System.out.println("Invalid option. Please try again.");
}
} while (choice != 5);
}
private static void addStudent() {
Scanner input = new Scanner(System.in);
System.out.println("Adding a student...");
System.out.print("Enter student ID: ");
int id = input.nextInt();
System.out.print("Enter student first name: ");
String firstName = input.next();
System.out.print("Enter student last name: ");
String lastName = input.next();
System.out.print("Enter student address: ");
String address = input.next();
System.out.print("Enter student city: ");
String city = input.next();
System.out.print("Enter student state: ");
String state = input.next();
System.out.print("Enter student zip code: ");
int zip = input.nextInt();
try {
FileWriter writer = new FileWriter("student.txt", true);
Scanner reader = new Scanner(new File("student.txt"));
while (reader.hasNextLine()) {
String line = reader.nextLine();
String[] parts = line.split(",");
if (Integer.parseInt(parts[0]) == id) {
System.out.println("Error: Student with that ID already exists.");
return;
}
}
writer.write(id + "," + firstName + "," + lastName + "," + address + "," + city + "," + state + "," +
zip + "\n");
System.out.println("Student added successfully.");
reader.close();
writer.close();
} catch (IOException e) {
System.out.println("Error: " + e.getMessage());
}
}
private static void addCourse() {
Scanner input = new Scanner(System.in);
System.out.println("Adding a course...");
System.out.print("Enter course ID: ");
int id = input.nextInt();
System.out.print("Enter course name: ");
String name = input.next();
System.out.print("Enter course description: ");
String description = input.next();
try {
FileWriter writer = new FileWriter("course.txt", true);
Scanner reader = new Scanner(new Fil.
I can not get my code to comply it gets mad that I have run declare mo.docx
I can not get my code to comply it gets mad that I have run declare more than once. Please help me figure out how to get this to work
package projectOne;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
import java.util.*;
import java.io.*;
public class Main
{ public static void main(String[] pArgs){
Main mainObject = new Main();
mainObject.run();
} private void run() {
public FileReader readFile() throws FileNotFoundException {
FileReader file = new FileReader(\"p01-in.txt\");
return file;
}
public ArrayList<Integer> getData(FileReader file) throws FileNotFoundException {
Scanner data_read = new Scanner(new BufferedReader(file));
ArrayList<Integer> data = new ArrayList<Integer>();
while (data_read.hasNext()) {
int item = data_read.nextInt();
data.add(item);
}
return data;
}
public ArrayList<Integer> calcRuns(ArrayList<Integer> data) {
ArrayList<Integer> runs = new ArrayList<Integer>();
Iterator<Integer> i_data = data.iterator();
int run = 0;
int temp = i_data.next();
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp < t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
i_data = data.iterator();
temp = i_data.next();
run = 0;
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp > t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
return runs;
}
public void writeOutput(ArrayList<Integer> runs) throws IOException {
PrintWriter out = new PrintWriter(new File(\"p01-runs.txt\"));
ArrayList<Integer> run_count = new ArrayList<Integer>();
int i = 0;
int r_count = Collections.frequency(run_count, i);
while (i < 100) {
run_count.add(r_count);
i++;
r_count = Collections.frequency(runs, i);
}
Iterator<Integer> i_runs = run_count.iterator();
i = 0;
while (i_runs.hasNext()) {
int run = i_runs.next();
String line = \"run_\" + i + \" ,\" + run;
i++;
out.println(line);
}
}
public void run() throws Exception {
FileReader fin = this.readFile();
ArrayList<Integer> data = this.getData(fin);
ArrayList<Integer> runs = this.calcRuns(data);
this.writeOutput(runs);
}
}
Solution
In your program you have to change the syntax errors at method declaration.so your not getting output.
.
Write a program in Java that reads a set of doubles from a file, sto.pdf
will you give your wife your money
Solution
Yes, after marriage the couple is a family, and every individual in the family has basic needs
which can be fulfilled only by money. Even when only the husband earns, the income is meant
for the family, as he is equally responsible for each and every member of the family. However it
is better, if every individual in the family earns independently..
The Java Program for the above given isimport java.io.File;impo.pdf
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}
Solution
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}.
In java , I want you to implement a Data Structure known as a Doubly.pdf
In java , I want you to implement a Data Structure known as a Doubly-Ended-Queue. it is a
“fair” data structure in that it implements a FIFO (First In First Out ) behavior. As such, it is
often used to implement various wait lists in computer systems. For example, jobs waiting to use
the CPU, jobs waiting for a printer, jobs waiting to be placed into RAM for execution. In short,
whenever we want a fair strategy for waiting we use queues.
A DEQUE (Doubly-ended-queue) is a related data structure. Although similar to a Queue, it
differs in that it allows for insertions AND deletions from either end of the list (both the front
and the rear).
Your implementation MUST use a doubly-linked-list implementation. You may not use a static
array implementation.
Thus, a Deque is a List but it is one which only concerns itself with the first and last positions for
any insertion or deletion. The 6 operations supported are :
public void insertFront( int item ) - insert the given item (as a node) into the first position of the
Deque.
public void insertRear( int item ) - insert the given item (as a node) into the last position of the
Deque.
public int deleteFront( ) - delete and return the element stored in the first node of the Deque.
public int deletRear( ) – delete and return the element stored in the last node of the Deque.
public boolean isempty( ) - returns true if the Deque is currently empty or false if it is not.
public void printDeque( ) - print the integers from the list, one per line, from the first element
through to the last in order.
Classes
Your program must implement the following 3 classes. public class dequeDriver
This class will contain your program’s main method. It will need to declare a deque object and
process input as indicated below.
Your program should prompt the user for the path of an input file. It should open the file for
input and process it line by line. Each line of the input file will have one of the following forms.
PR
IF
IR
DF
DR
The meanings of each input is as follows:
PR - print the current contents of the deque from front to rear using the printDeque( ) method of
the deque object.
IF - insert the given int value into the front of the deque.
IR - insert the given int value into the rear of the deque.
DF - delete the front value from the deque.
DR – delete the rear element of the deque.
Below is an example input file that your program should be able to process.
PR
IF 4
IF 5
IF 6
IR 7
PR
DR
PR
DF
PR
The output for the input file shown above is :
EMPTY DEQUE
----- Front -----
6
5
4
7
----- Rear -----
----- Front -----
6
5
4
----- Rear -----
----- Front -----
5
4
----- Rear -----
public class dequeNode
This class will implement the linked nodes that will be used to implement the deque itself.
It should have the following protected data members.
protected dequeNode next; // next pointer to next node
protected dequeNode prev; // previous pointer to previous node
protected int val; // the integer value stored within the dequeNod.
IN JAVA Write a program to create a binary data file named RandomInt.pdf
IN JAVA Write a program to create a binary data file named RandomInt.dat that consists of 10
random integer numbers using DataOutputStream. Use DataInputStream to read the integers
from RandomInt.dat just created and print them on the console in the same program.
Solution
DataInputStreamTest.java
import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Random;
public class DataInputStreamTest {
public static void main(String[] args) {
String strFilePath = \"D:\\\\RandomInt.dat\";
Random r = new Random();
try
{
FileOutputStream outputStr = new FileOutputStream(strFilePath);
DataOutputStream outputStrData = new DataOutputStream(outputStr);
for(int i=0; i<10; i++){
outputStrData.writeInt(r.nextInt(100)+1);
outputStrData.writeChar(\'\\t\');
}
outputStrData.flush();
outputStrData.close();
outputStr.close();
FileInputStream inputStr = new FileInputStream(strFilePath);
DataInputStream inputStrData = new DataInputStream(inputStr);
int count = 0;
while(count<10){
int i = inputStrData.readInt();
inputStrData.readChar();
count++;
System.out.println( i);
}
outputStrData.flush();
inputStrData.close();
outputStrData.close();
}
catch(FileNotFoundException fe)
{
System.out.println(\"FileNotFoundException : \" + fe);
}
catch(IOException ioe)
{
System.out.println(\"IOException : \" + ioe);
}
}
}
Output:
65
8
95
69
1
77
16
97
85
1.
Describe 3 functions of the cellular membrane and how are these func.pdf
Describe 3 functions of the cellular membrane and how are these functions accomplished by the
chemical make up of the membrane.
Solution
The main functions of the cell membrane are:to maintain the physical integrity of the cell,that is
to mechanically enclose the contents of the cell,also to control the movement of particles e.g.
ions or molecules,into and out of the cell.It also isolates the cytoplasm from the external
environment.
The hydrophilic head and hydrophobic tails of the phospholipid molecules that form the
phospholipid bilayer of the cell membrane forming its physical/mechanical structure.The ion
channels responsible for the selective permeability of the cell membrane.Membrane pumps that
enable active transport of specific molecules across the cell membrane.Carrier proteins and
receptor proteins that transport specific substance across the cell membrane and receive
(chemical) signals from outside the cell that tell the cell to take a specific
action,respectively.Cholesterol molecules and carbohydrate chains that support the structure of
the membrane and its attachment to other tissues,respectively.Surface protein markers that
identify the cell.Membrane proteins acts as a recptor to combine with specific substance such as
hormones while some form narrow passage ways or channels through which various molecules
and ions can cross the cell membrane.Enzymatic proteins carry out metabolic reactions..
Discuss the three main types of intellectual capitalSolutionth.pdf
Discuss the three main types of intellectual capital
Solution
the main types of intellectual capitals are: Copy rights, patents, trade marks and trade secrets.
copy rights: gives the right to the inventor or author or a book or artistick work to his invention.
book publishing and movie distribution comes under this example.
patents: gives the inventor to sell the right to use his invention for commercial and for that he
will charge something from the user. the user will get licence to use it and will be benefited.
manufacturing of McDonald and Dominos pizzas comes under this action.
trademark: is facilitate the seller or producer to differentitate his prodcut from his competitors
product and will be benefited. is like giving licence to sell the products in a region for a
particular period. the producer will allows the seller to sell the product and will get some benefit..
More Related Content
Similar to Use arrays to store data for analysis. Use functions to perform the .pdf
We will be making 4 classes Main - for testing the code Hi.pdf
/*
We will be making 4 classes:
Main - for testing the code
HighscoreManager - to manage the high-scores
HighscoreComparator - I will explain this when we get there
Score - also this I will explain later
all this classes will be in the package \"highscores\"/*
//The Score Class
package highscores;
import java.io.Serializable;
public class Score implements Serializable {
private int score;
private String naam;
public int getScore() {
return score;
}
public String getNaam() {
return naam;
}
public Score(String naam, int score) {
this.score = score;
this.naam = naam;
}
}/*This class makes us able to make an object (an arraylist in our case) of the type Score that
contains the name and score of a player.
We implement serializable to be able to sort this type./*
//The ScoreComparator Class
package highscores;
import java.util.Comparator;
public class ScoreComparator implements Comparator {
public int compare(Score score1, Score score2) {
int sc1 = score1.getScore();
int sc2 = score2.getScore();
if (sc1 > sc2){
return -1;
}else if (sc1 < sc2){
return +1;
}else{
return 0;
}
}
}
/*This class is used to tell Java how it needs to compare 2 objects of the type score.
-1 means the first score is greater than the 2nd one, +1 (or you can just put 1) means it\'s smaller
and 0 means it\'s equal./*
//The HighscoreManager Class
/*First we will be making the HighscoreManager Class, this class will do the most important part
of the high-score system.
We will be using this as our base for the class:/*
package highscores;
import java.util.*;
import java.io.*;
public class HighscoreManager {
// An arraylist of the type \"score\" we will use to work with the scores inside the class
private ArrayList scores;
// The name of the file where the highscores will be saved
private static final String HIGHSCORE_FILE = \"scores.dat\";
//Initialising an in and outputStream for working with the file
ObjectOutputStream outputStream = null;
ObjectInputStream inputStream = null;
public HighscoreManager() {
//initialising the scores-arraylist
scores = new ArrayList();
}
}
/*I have added comments to explain what\'s already in the class.
We will be using a binary file to keep the high-scores in, this will avoid cheating.
To work with the scores we will use an arraylist. An arraylist is one of the great things that java
has and it\'s much better to use in this case than a regular array.
Now we will add some methods and functions./*
public ArrayList getScores() {
loadScoreFile();
sort();
return scores;
}
/*This is a function that will return an arraylist with the scores in it. It contains calls to the
function loadScoreFile() and sort(), these functions will make sure you have the scores from your
high-score file in a sorted order. We will be writing these functions later on./*
private void sort() {
ScoreComparator comparator = new ScoreComparator();
Collections.sort(scores, comparator);
}
/*This function will create a new object \"comparator\" from the class ScoreComparator.
the Colle.
stateDatabuild.xml Builds, tests, and runs the project.docx
stateData/build.xml
Builds, tests, and runs the project stateData.
stateData/manifest.mf
Manifest-Version: 1.0
X-COMMENT: Main-Class will be added automatically by build
stateData/nbproject/build-impl.xml
Must set src.dir
Must set test.src.dir
Must set build.dir
Must set dist.dir
Must set build.classes.dir
Must set dist.javadoc.dir
Must set bui.
Main class --------------------------import java.awt.FlowLayout.pdf
Main class :-
-------------------------
import java.awt.FlowLayout;
import java.awt.Graphics;
import java.awt.GridLayout;
import java.awt.Insets;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JTextField;
public class Main {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
final InfixExperssionEvaluator ie = new InfixExperssionEvaluator();
JFrame frame = new JFrame(\"FrameDemo\");
frame.setSize(600,200);
frame.setLayout(new FlowLayout());
JPanel main = new JPanel(new GridLayout(3, 1));
JPanel panel1 = new JPanel(new GridLayout(1, 2));
panel1.setSize(500, 250);
panel1.add(new JLabel(\"Enter Infix Expression\"));
final JTextField field1 = new JTextField();
field1.setSize(150,100);
panel1.add(field1);
main.add(panel1);
JPanel panel2 = new JPanel(new GridLayout(1, 1));
panel1.setSize(300, 150);
JButton button = new JButton();
button.setSize(200, 100);
button.setText(\"Submit\");
panel2.add(button);
main.add(panel2);
JPanel panel3 = new JPanel(new GridLayout(1, 2));
panel3.add(new JLabel(\"Value : \"));
final JLabel lbl = new JLabel();
panel3.add(lbl);
main.add(panel3);
frame.getContentPane().add(main);
frame.setVisible(true);
button.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
// TODO Auto-generated method stub
if (\"Submit\".equals(e.getActionCommand())) {
String expr = field1.getText();
lbl.setText(Double.toString(ie.infixToValue(expr)));
}
}
});
button.setActionCommand(\"Submit\");
String expr = \"((2*5)+(6/2))\";
System.out.println(\"value is ::\"+ ie.infixToValue(expr));
}
}
Class for Evaluate methods :-
-----------------------------------------
import java.util.ArrayDeque;
import java.util.HashMap;
import java.util.Map;
import java.util.Stack;
import java.util.StringTokenizer;
public class InfixExperssionEvaluator {
Stack expressionStack = new Stack();
Stack valueStack = new Stack(); //to hold only non-decimal values
public static final String OPERATORS=\"+-/*()\"; //ignore the \"(\" as an operator
//Map For Operator precedence Key(+,-,*,/) , value 0/1/2/3..
Map operator_levels = new HashMap();
public InfixExperssionEvaluator(){
operator_levels.put(\")\", 0);
operator_levels.put(\"*\", 1);
operator_levels.put(\"/\", 1);
operator_levels.put(\"+\", 2);
operator_levels.put(\"-\", 2);
operator_levels.put(\"(\", 3);
}
double infixToValue(String inputExpression) {
String eachNumber=\"\"; //to hold multiple digit values. lame idea, i know, but can\'t
think of anything else at 2 AM
int totalCharInInput = inputExpression.length();
inputExpression.replaceAll(\"\\\\s+\",\"\");
//Devide String to Tokens
StringTokenizer tokens = new StringTokenizer(inputExpression, \"{}()*/+-\", true);
//Loop through each Token
while(tokens.hasMoreTokens()){
String eachChar = tokens.nextToken();
if (isValidOperator(eachCh.
Soundreader.classpathSoundreader.project Soundre.docx
Soundreader/.classpath
Soundreader/.project
Soundreader
org.eclipse.jdt.core.javabuilder
org.eclipse.jdt.core.javanature
Soundreader/.settings/org.eclipse.jdt.core.prefs
eclipse.preferences.version=1
org.eclipse.jdt.core.compiler.codegen.inlineJsrBytecode=enabled
org.eclipse.jdt.core.compiler.codegen.targetPlatform=1.8
org.eclipse.jdt.core.compiler.codegen.unusedLocal=preserve
org.eclipse.jdt.core.compiler.compliance=1.8
org.eclipse.jdt.core.compiler.debug.lineNumber=generate
org.eclipse.jdt.core.compiler.debug.localVariable=generate
org.eclipse.jdt.core.compiler.debug.sourceFile=generate
org.eclipse.jdt.core.compiler.problem.assertIdentifier=error
org.eclipse.jdt.core.compiler.problem.enumIdentifier=error
org.eclipse.jdt.core.compiler.source=1.8
Soundreader/bin/ArrayStack.classpublicsynchronizedclass ArrayStack {
private Object[] data;
private int size;
public void ArrayStack();
public boolean isEmpty();
protected boolean isFull();
public Object peek();
public Object pop();
public void push(Object);
protected void stretch();
}
Soundreader/bin/DStack.classpublicabstractinterface DStack {
publicabstract boolean isEmpty();
publicabstract void push(double);
publicabstract double pop();
publicabstract double peek();
}
Soundreader/bin/gtd/stack/ListStackNode.classpackage gtd.stack;
publicfinalsynchronizedclass ListStackNode {
privatestaticfinal EpsilonStackNode EMPTY;
privatefinal String nodeName;
privatefinal AbstractStackNode[] children;
privatefinal AbstractStackNode emptyChild;
public void ListStackNode(int, int, AbstractStackNode, String, boolean);
private void ListStackNode(ListStackNode, int);
AbstractStackNode[] generateChildren(AbstractStackNode);
private AbstractStackNode generateEmptyChild();
public String getName();
public AbstractStackNode getCleanCopy(int);
public AbstractStackNode[] getChildren();
public boolean canBeEmpty();
public AbstractStackNode getEmptyChild();
public String toString();
}
Soundreader/bin/ListStack.classpublicsynchronizedclass ListStack {
private ListNode topOfStack;
public void ListStack();
public boolean isEmpty();
public void makeEmpty();
public void push(Object);
public void pop();
public Object top();
public Object topAndPop();
}
Soundreader/bin/Reverse.classpublicsynchronizedclass Reverse {
public void Reverse();
publicstatic void main(String[]);
}
Soundreader/Screenshot (14).png
Soundreader/Screenshot (15).png
Soundreader/Screenshot (16).png
Soundreader/src/ArrayStack.javaSoundreader/src/ArrayStack.javaimport java.util.EmptyStackException;
publicclassArrayStack<E>implementsDStack<E>{
/** Array of items in this Stack. */
private E[] data;
/** Number of items currently in this Stack. */
privateint size;
/** The Stack is initally empty. */
publicArrayStack(){
data =(E[])(newOb.
(JAVA NetBeans) Write a Java program able to perform selection sort-So.docx
(JAVA NetBeans) Write a Java program able to perform selection sort.
Solution
import java.util.Scanner;
/**
* @author
*
*/
public class SelectionSort {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int arr[] = setArray();
System.out.println(\"\ Before Sorting:\");
printArray(arr);
arr = selectionSort(arr);
System.out.println(\"\ After Sorting:\");
printArray(arr);
}
/**
* reads and stores the data in the one-dimensional array
*/
/**
* @return
*/
public static int[] setArray() {
int arr[] = new int[12];
System.out.println(\"Enter 12 integers.\");
Scanner scanner = new Scanner(System.in);
for (int i = 0; i < arr.length; i++) {
arr[i] = scanner.nextInt();
}
return arr;
}
/**
* prints the data in the one-dimensional array
*/
public static void printArray(int[] arr) {
System.out.println();
for (int i = 0; i < arr.length; i++) {
System.out.print(arr[i] + \" \");
}
System.out.println();
}
/**
* method will sort the array in ascending order
*/
public static int[] selectionSort(int[] arr) {
for (int i = 0; i < arr.length - 1; i++) {
int index = i;
for (int j = i + 1; j < arr.length; j++)
if (arr[j] < arr[index])
index = j;
int smallerNumber = arr[index];
arr[index] = arr[i];
arr[i] = smallerNumber;
}
return arr;
}
}
OUTPUT:
Enter 12 integers.
4 23 65 34 84 37 12 17 24 36 82 51
Before Sorting:
4 23 65 34 84 37 12 17 24 36 82 51
After Sorting:
4 12 17 23 24 34 36 37 51 65 82 84
.
Java Program I keep receiving the following error in my code- Can you.pdf
Java Program
I keep receiving the following error in my code. Can you please fix this error and test to make
sure it does not show a error? I've placed bracets but keep receiving the error "reached end of file
while parsing private static void displayStudent()" See below
Error:
sh -c javac -classpath .:target/dependency/* -d . $(find . -type f -name '*.java')
./Main.java:121: error: reached end of file while parsing
private static void displayStudent()
^
1 error
exit status 1
------------------------------------------
Code:
import java.util.Scanner;
import java.io.File;
import java.io.FileWriter;
import java.io.IOException;
public class StudentCourseProgram {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int choice;
do {
System.out.println("Please choose an option:");
System.out.println("1. Add student");
System.out.println("2. Add course");
System.out.println("3. Display student");
System.out.println("4. Display course");
System.out.println("5. Exit");
choice = input.nextInt();
switch (choice) {
case 1:
addStudent();
break;
case 2:
addCourse();
break;
case 3:
displayStudent();
break;
case 4:
displayCourse();
break;
case 5:
System.out.println("Exiting program...");
break;
default:
System.out.println("Invalid option. Please try again.");
}
} while (choice != 5);
}
private static void addStudent() {
Scanner input = new Scanner(System.in);
System.out.println("Adding a student...");
System.out.print("Enter student ID: ");
int id = input.nextInt();
System.out.print("Enter student first name: ");
String firstName = input.next();
System.out.print("Enter student last name: ");
String lastName = input.next();
System.out.print("Enter student address: ");
String address = input.next();
System.out.print("Enter student city: ");
String city = input.next();
System.out.print("Enter student state: ");
String state = input.next();
System.out.print("Enter student zip code: ");
int zip = input.nextInt();
try {
FileWriter writer = new FileWriter("student.txt", true);
Scanner reader = new Scanner(new File("student.txt"));
while (reader.hasNextLine()) {
String line = reader.nextLine();
String[] parts = line.split(",");
if (Integer.parseInt(parts[0]) == id) {
System.out.println("Error: Student with that ID already exists.");
return;
}
}
writer.write(id + "," + firstName + "," + lastName + "," + address + "," + city + "," + state + "," +
zip + "\n");
System.out.println("Student added successfully.");
reader.close();
writer.close();
} catch (IOException e) {
System.out.println("Error: " + e.getMessage());
}
}
private static void addCourse() {
Scanner input = new Scanner(System.in);
System.out.println("Adding a course...");
System.out.print("Enter course ID: ");
int id = input.nextInt();
System.out.print("Enter course name: ");
String name = input.next();
System.out.print("Enter course description: ");
String description = input.next();
try {
FileWriter writer = new FileWriter("course.txt", true);
Scanner reader = new Scanner(new Fil.
I can not get my code to comply it gets mad that I have run declare mo.docx
I can not get my code to comply it gets mad that I have run declare more than once. Please help me figure out how to get this to work
package projectOne;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
import java.util.*;
import java.io.*;
public class Main
{ public static void main(String[] pArgs){
Main mainObject = new Main();
mainObject.run();
} private void run() {
public FileReader readFile() throws FileNotFoundException {
FileReader file = new FileReader(\"p01-in.txt\");
return file;
}
public ArrayList<Integer> getData(FileReader file) throws FileNotFoundException {
Scanner data_read = new Scanner(new BufferedReader(file));
ArrayList<Integer> data = new ArrayList<Integer>();
while (data_read.hasNext()) {
int item = data_read.nextInt();
data.add(item);
}
return data;
}
public ArrayList<Integer> calcRuns(ArrayList<Integer> data) {
ArrayList<Integer> runs = new ArrayList<Integer>();
Iterator<Integer> i_data = data.iterator();
int run = 0;
int temp = i_data.next();
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp < t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
i_data = data.iterator();
temp = i_data.next();
run = 0;
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp > t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
return runs;
}
public void writeOutput(ArrayList<Integer> runs) throws IOException {
PrintWriter out = new PrintWriter(new File(\"p01-runs.txt\"));
ArrayList<Integer> run_count = new ArrayList<Integer>();
int i = 0;
int r_count = Collections.frequency(run_count, i);
while (i < 100) {
run_count.add(r_count);
i++;
r_count = Collections.frequency(runs, i);
}
Iterator<Integer> i_runs = run_count.iterator();
i = 0;
while (i_runs.hasNext()) {
int run = i_runs.next();
String line = \"run_\" + i + \" ,\" + run;
i++;
out.println(line);
}
}
public void run() throws Exception {
FileReader fin = this.readFile();
ArrayList<Integer> data = this.getData(fin);
ArrayList<Integer> runs = this.calcRuns(data);
this.writeOutput(runs);
}
}
Solution
In your program you have to change the syntax errors at method declaration.so your not getting output.
.
Write a program in Java that reads a set of doubles from a file, sto.pdf
will you give your wife your money
Solution
Yes, after marriage the couple is a family, and every individual in the family has basic needs
which can be fulfilled only by money. Even when only the husband earns, the income is meant
for the family, as he is equally responsible for each and every member of the family. However it
is better, if every individual in the family earns independently..
The Java Program for the above given isimport java.io.File;impo.pdf
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}
Solution
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}.
In java , I want you to implement a Data Structure known as a Doubly.pdf
In java , I want you to implement a Data Structure known as a Doubly-Ended-Queue. it is a
“fair” data structure in that it implements a FIFO (First In First Out ) behavior. As such, it is
often used to implement various wait lists in computer systems. For example, jobs waiting to use
the CPU, jobs waiting for a printer, jobs waiting to be placed into RAM for execution. In short,
whenever we want a fair strategy for waiting we use queues.
A DEQUE (Doubly-ended-queue) is a related data structure. Although similar to a Queue, it
differs in that it allows for insertions AND deletions from either end of the list (both the front
and the rear).
Your implementation MUST use a doubly-linked-list implementation. You may not use a static
array implementation.
Thus, a Deque is a List but it is one which only concerns itself with the first and last positions for
any insertion or deletion. The 6 operations supported are :
public void insertFront( int item ) - insert the given item (as a node) into the first position of the
Deque.
public void insertRear( int item ) - insert the given item (as a node) into the last position of the
Deque.
public int deleteFront( ) - delete and return the element stored in the first node of the Deque.
public int deletRear( ) – delete and return the element stored in the last node of the Deque.
public boolean isempty( ) - returns true if the Deque is currently empty or false if it is not.
public void printDeque( ) - print the integers from the list, one per line, from the first element
through to the last in order.
Classes
Your program must implement the following 3 classes. public class dequeDriver
This class will contain your program’s main method. It will need to declare a deque object and
process input as indicated below.
Your program should prompt the user for the path of an input file. It should open the file for
input and process it line by line. Each line of the input file will have one of the following forms.
PR
IF
IR
DF
DR
The meanings of each input is as follows:
PR - print the current contents of the deque from front to rear using the printDeque( ) method of
the deque object.
IF - insert the given int value into the front of the deque.
IR - insert the given int value into the rear of the deque.
DF - delete the front value from the deque.
DR – delete the rear element of the deque.
Below is an example input file that your program should be able to process.
PR
IF 4
IF 5
IF 6
IR 7
PR
DR
PR
DF
PR
The output for the input file shown above is :
EMPTY DEQUE
----- Front -----
6
5
4
7
----- Rear -----
----- Front -----
6
5
4
----- Rear -----
----- Front -----
5
4
----- Rear -----
public class dequeNode
This class will implement the linked nodes that will be used to implement the deque itself.
It should have the following protected data members.
protected dequeNode next; // next pointer to next node
protected dequeNode prev; // previous pointer to previous node
protected int val; // the integer value stored within the dequeNod.
IN JAVA Write a program to create a binary data file named RandomInt.pdf
IN JAVA Write a program to create a binary data file named RandomInt.dat that consists of 10
random integer numbers using DataOutputStream. Use DataInputStream to read the integers
from RandomInt.dat just created and print them on the console in the same program.
Solution
DataInputStreamTest.java
import java.io.DataInputStream;
import java.io.DataOutputStream;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Random;
public class DataInputStreamTest {
public static void main(String[] args) {
String strFilePath = \"D:\\\\RandomInt.dat\";
Random r = new Random();
try
{
FileOutputStream outputStr = new FileOutputStream(strFilePath);
DataOutputStream outputStrData = new DataOutputStream(outputStr);
for(int i=0; i<10; i++){
outputStrData.writeInt(r.nextInt(100)+1);
outputStrData.writeChar(\'\\t\');
}
outputStrData.flush();
outputStrData.close();
outputStr.close();
FileInputStream inputStr = new FileInputStream(strFilePath);
DataInputStream inputStrData = new DataInputStream(inputStr);
int count = 0;
while(count<10){
int i = inputStrData.readInt();
inputStrData.readChar();
count++;
System.out.println( i);
}
outputStrData.flush();
inputStrData.close();
outputStrData.close();
}
catch(FileNotFoundException fe)
{
System.out.println(\"FileNotFoundException : \" + fe);
}
catch(IOException ioe)
{
System.out.println(\"IOException : \" + ioe);
}
}
}
Output:
65
8
95
69
1
77
16
97
85
1.
Similar to Use arrays to store data for analysis. Use functions to perform the .pdf (20)
We will be making 4 classes Main - for testing the code Hi.pdf
We will be making 4 classes Main - for testing the code Hi.pdf
stateDatabuild.xml Builds, tests, and runs the project.docx
stateDatabuild.xml Builds, tests, and runs the project.docx
Main class --------------------------import java.awt.FlowLayout.pdf
Main class --------------------------import java.awt.FlowLayout.pdf
Soundreader.classpathSoundreader.project Soundre.docx
Soundreader.classpathSoundreader.project Soundre.docx
(JAVA NetBeans) Write a Java program able to perform selection sort-So.docx
(JAVA NetBeans) Write a Java program able to perform selection sort-So.docx
Java Program I keep receiving the following error in my code- Can you.pdf
Java Program I keep receiving the following error in my code- Can you.pdf
I can not get my code to comply it gets mad that I have run declare mo.docx
I can not get my code to comply it gets mad that I have run declare mo.docx
Write a program in Java that reads a set of doubles from a file, sto.pdf
Write a program in Java that reads a set of doubles from a file, sto.pdf
The Java Program for the above given isimport java.io.File;impo.pdf
The Java Program for the above given isimport java.io.File;impo.pdf
In java , I want you to implement a Data Structure known as a Doubly.pdf
In java , I want you to implement a Data Structure known as a Doubly.pdf
IN JAVA Write a program to create a binary data file named RandomInt.pdf
IN JAVA Write a program to create a binary data file named RandomInt.pdf
More from footworld1
Describe 3 functions of the cellular membrane and how are these func.pdf
Describe 3 functions of the cellular membrane and how are these functions accomplished by the
chemical make up of the membrane.
Solution
The main functions of the cell membrane are:to maintain the physical integrity of the cell,that is
to mechanically enclose the contents of the cell,also to control the movement of particles e.g.
ions or molecules,into and out of the cell.It also isolates the cytoplasm from the external
environment.
The hydrophilic head and hydrophobic tails of the phospholipid molecules that form the
phospholipid bilayer of the cell membrane forming its physical/mechanical structure.The ion
channels responsible for the selective permeability of the cell membrane.Membrane pumps that
enable active transport of specific molecules across the cell membrane.Carrier proteins and
receptor proteins that transport specific substance across the cell membrane and receive
(chemical) signals from outside the cell that tell the cell to take a specific
action,respectively.Cholesterol molecules and carbohydrate chains that support the structure of
the membrane and its attachment to other tissues,respectively.Surface protein markers that
identify the cell.Membrane proteins acts as a recptor to combine with specific substance such as
hormones while some form narrow passage ways or channels through which various molecules
and ions can cross the cell membrane.Enzymatic proteins carry out metabolic reactions..
Discuss the three main types of intellectual capitalSolutionth.pdf
Discuss the three main types of intellectual capital
Solution
the main types of intellectual capitals are: Copy rights, patents, trade marks and trade secrets.
copy rights: gives the right to the inventor or author or a book or artistick work to his invention.
book publishing and movie distribution comes under this example.
patents: gives the inventor to sell the right to use his invention for commercial and for that he
will charge something from the user. the user will get licence to use it and will be benefited.
manufacturing of McDonald and Dominos pizzas comes under this action.
trademark: is facilitate the seller or producer to differentitate his prodcut from his competitors
product and will be benefited. is like giving licence to sell the products in a region for a
particular period. the producer will allows the seller to sell the product and will get some benefit..
Describer in detail the innate immune response to both an intercellu.pdf
Describer in detail the innate immune response to both an intercellular infection and an
extracellular infection.
Solution
Innate immunity is the type of immunity which is developed by birth..! The defense against the
extracellur infection are from the barrier which are present on the body like skin, hairs in the
nose, tears which contain lisozymes in them, phagocyotic cells like neutrophils etc which kills
the outer cells..!
Then the intra cellular immunity like cytokines, inflammatory barriers like histamine which
produces inflammation due to the infection, complement protein...
Describe the difference between tropic and non-tropic hormones.S.pdf
Describe the difference between tropic and non-tropic hormones.
Solution
TROPIC HORMONES : Tropic hormones are those hormones which act on other endocrine
hormonesthey are named as respective tropin.
Ex: adreno cartico tropic hormone (acth) is a tropic hormone which acts on the cells of adrenal
cortex and stimulate the synthesis of glucocorticoid hormones.similarly,Thyroid stimulating
Hormone (TSH) and Leutinising hormone(LH) and Follicle stimulating hormone (FSH) also act
on specific tissues or hormones and stimulate the synthesis of other hormones.
NON-TROPIC HORMONES : these are the hormones that act directly on the specialised tissues
or cells and induce the effect.they play a vital role in many metabolic functions.
Ex: cartisol is a non topic hormone which is a result of many chain reactions that are induced due
to ACTH (tropic hormone).testosterone,estrogen,vassopressin,epinep[hrine and non-epinephrine
are some of the examples of non-tropic hormones.
both tropic and non-tropic hormones are crucial in proper endocrine functions.
for example if ACTH is inhibited, release of cortisol is inhibited due to interruption of chain
reactions.
Most of the hormones released from endocrine glands like pancreas,gonads,pituatary galnds are
non-tropic..
C++ ProgrammingGivenWrite a closest Pair FunctionDeliverable.pdf
C++ Programming
Given:
Write a closest Pair Function:
Deliverables
ClosestPair.h
ClosestPair.cpp
Solution
code:
Pair Closest_Pair( Point P[ ], int n)
{
float min = FLT_MAX;
int indexone=0;
int indextwo=0;
for (int i = 0; i < n; ++i)
for (int j = i+1; j < n; ++j)
if (dist(P[i], P[j]) < min)
{
min = dist(P[i], P[j]);
indexone=i;
indextwo=j;
}
Struct Pair st ;
st.indexPointOne = indexone;
st.indexPointTwo = indextwo;
return min;
}
float dist(Point p1, Point p2)
{
return sqrt( (p1.x - p2.x)*(p1.x - p2.x) +
(p1.y - p2.y)*(p1.y - p2.y)
);
}.
Can someone explain to me what the learning curve equation (Tn=T1n^.pdf
Can someone explain to me what the learning curve equation (Tn=T1*n^b) is and how you get
this equation? What is the relationship between the variables?
Solution
The learning curve equation is defined as follows : -
Tn = T1 nb
Tn is the production time for the nth unit
T1 is the production time for the first unit
n = number of units
b is slope of the learning curve and is defined as b = log(learning rate) / log2
Lr , the learning rate , is expressed as a decimal , eg ., Lr = 80% = 0.8.
Both influenza virus and (IFV), and Measles Virus (MV) are envel.pdf
Both influenza virus and (IFV), and Measles Virus (MV) are enveloped viruses with class I
fusion glycoproteins. Experimental exposure to low pH (5.5) buffer will inactivate IFV, but not
MV. Based on this information, What can you infer about the entry pathways and mechanisms of
two viruses?
Both influenza virus and (IFV), and Measles Virus (MV) are enveloped viruses with class I
fusion glycoproteins. Experimental exposure to low pH (5.5) buffer will inactivate IFV, but not
MV. Based on this information, What can you infer about the entry pathways and mechanisms of
two viruses?
Both influenza virus and (IFV), and Measles Virus (MV) are enveloped viruses with class I
fusion glycoproteins. Experimental exposure to low pH (5.5) buffer will inactivate IFV, but not
MV. Based on this information, What can you infer about the entry pathways and mechanisms of
two viruses?
Solution
Influenza virus is an enveloped, single-stranded negative-sense RNA virus belonging to the
Orthomyxoviridae family. Influenza A virions have three integral membrane proteins: an ion
channel protein (M2) and two glycoproteins, hemagglutinin (HA), required for entry into host
cells, and neuraminidase (NA), involved in the release of progeny virions from the host cell.
Underneath the membrane, most virions have a layer of M1 matrix protein enclosing the viral
ribonucleoprotein complexes (RNPs). On exposure to low pH of around 5 the viral RNP\'s are
released. It is followed by the M2-mediated pumping of protons into the virion, this induces the
change in the intermolecular interactions of the M1 matrix protien and its binding to the viral
membrane, this leads to membrane fusion and conformational changes in the hemagglutinin
causing them to be inactive because this conformational change causes exposure of a
hydrophobic part of the molecule. Fusion of the virion with target membrane occurs at low pH
where a transition from a relaxed conformation to an active conformation of HA occurs, this
transition at low pH in absence of a target membrane leads to inactivation.
The measles virus is a paramyxovirus, is 120–250 nm in diameter, with a core of single-stranded
RNA. It has Two membrane envelope proteins are important in pathogenesis. They are the F
(fusion) protein, responsible for fusion of virus and host cell membranes, viral penetration, and
hemolysis, and the H (hemagglutinin) protein, which is responsible for adsorption of virus to
cells. measles virus could not be inactivated at pH range of 5.5 to 9.0. It is inactivated at pH of
<3 or >7Attachmentnt to host cell happens through binding of virus to the cellular receptor and
fusion of the viral and cellular membranes. MV enters cell in a pH independent manner and fuses
directly to the plasma membrane. At around pH 5 there is no conformational change that occurs
in the multifaceted strucuture of MV..
All of the following are characteristic to fatigue fracture surfaces.pdf
All of the following are characteristic to fatigue fracture surfaces, except A. Clamshell marks. B.
Beach marks. C. Dimples. D. Striations.
Solution
STRIATIONS
Striations means a series of ridges, furrows or linear marks, and is used in several ways: Glacial
striation. Striation (geology), a striation as a result of a geological fault..
A cancer biology topic Describte how ChIP (chromatin immunoprecipit.pdf
A cancer biology topic: Describte how ChIP (chromatin immunoprecipitation), DNA
methylation array, and gene expression arrays are performed. What are the similarities?
Solution
DNA methylation is main epigenetic mechanism of gene expression regulation.Alteration in this
leads to tumor. Various stimulant factors stimulate DNA methylation leads to generation of
canceroua cells.
DNA methylation process do down regulation of gene.
Methylation of CpG sites blocks the binding of regulatory proteins resulting transcription
modulation.
In CHIP DNA methylation stauninig of CHIP done by various stains. Stained CHIP show
intensities of methylated and unmethylated bead types. Data analysis gives florescence intensity
ratio between methylated and unmethylated group.
Value of ratio is 0, 1, 0.5 represents non methylation, total methylation and one copy methylated
other not respectively.
DNA methylation measure by following other method also
Bisulfite treatment
Whole genomic DNA amplification
Hybridization and single base extension
In Gene expression two following procees take important part:-
TRANSCRIPTION:- DNA to RNA by RNA polymerase which use DNA as template and
produce RNA.
TRANSLATION:- RNA to Protein translation (tRNA charged with amino acid enter in ribosome
with correct mRNA triplet , ribisome then add aminoacid.
In cancer, gene promoter contain CpG island with numerous CpG sites. When CpG
sitesethylated gene become silence.
Thanks...
You get a call from a customer who reinstalled Windows on his comput.pdf
You get a call from a customer who reinstalled Windows on his computer after a crash.
Fortunately, he had recently backed up all this data to an external USB drive and was able to
restore everything on his NTFS-formatted file system. However, he had a number of encrypted
files that he had backed up along with the rest of his data that he can no longer access. What
happened?
A. NTFS-encrypted files cannot be backed up, and when the computer crashed, those files were
lost forever. When the customer tried to restore these files, only corrupted versions were
restored.
B. NTFS-encrypted files are not restored with the original encryption key used before the backup
process and thus become inaccessible.
C. When the customer reinstalled Windows, even though he used his old username, the computer
assigned him a completely different security identifier (SID). The restored NTFS-encrypted files
are looking for his original SID.
D. When the customer reinstalled Windows, he didn’t use his original username. The restored
NTFS-encrypted files are looking for the original username.
Solution
C. NTFS encryption used the customer’s SID to associate with the encrypted file. Now that the
customer reinstalled Windows, a completely new SID was assigned to the customer. Without the
original SID, he can’t access the encrypted files. A third-party decryption application may help
him access his encrypted data..
You are running the Windows installation setup for Windows 7 on a co.pdf
You are running the Windows installation setup for Windows 7 on a computer. When the
Windows Setup screen appears, what do you notice?
A. The Setup screen has been drastically redesigned from Windows Vista.
B. The Setup screen is almost exactly the same as Windows Vista.
C. The Setup screen hasn’t changed since Windows XP.
D. Unlike Windows Vista, the Setup screen immediately launches into the GUI.
Solution
B. The Windows 7 Setup screen is virtually the same as the screen in Windows Vista, both
beginning in a black character-mode screen and then launching the GUI..
Write a program to decipher messages encoded using a prefix code, gi.pdf
Write a program to decipher messages encoded using a prefix code, given the encoding tree.
Such codes are widely used in applications that compress data, including JPEG for images, MP3
for music, and DivX for video. using Huffman Trees (Prefix Binary Trees) c++
Solution
#include #include #include #include // for CHAR_BIT #include #include const int
UniqueSymbols = 1 << CHAR_BIT; const char* SampleString = \"this is an example for
huffman encoding\"; typedef std::vector HuffCode; typedef std::map HuffCodeMap; class
INode { public: const int f; virtual ~INode() {} protected: INode(int f) : f(f) {} };
class InternalNode : public INode { public: INode *const left; INode *const right;
InternalNode(INode* c0, INode* c1) : INode(c0->f + c1->f), left(c0), right(c1) {}
~InternalNode() { delete left; delete right; } }; class LeafNode :
public INode { public: const char c; LeafNode(int f, char c) : INode(f), c(c) {} };
struct NodeCmp { bool operator()(const INode* lhs, const INode* rhs) const { return lhs->f
> rhs->f; } }; INode* BuildTree(const int (&frequencies)[UniqueSymbols]) {
std::priority_queue, NodeCmp> trees; for (int i = 0; i < UniqueSymbols; ++i) {
if(frequencies[i] != 0) trees.push(new LeafNode(frequencies[i], (char)i)); }
while (trees.size() > 1) { INode* childR = trees.top(); trees.pop();
INode* childL = trees.top(); trees.pop(); INode* parent = new
InternalNode(childR, childL); trees.push(parent); } return trees.top(); } void
GenerateCodes(const INode* node, const HuffCode& prefix, HuffCodeMap& outCodes) {
if (const LeafNode* lf = dynamic_cast(node)) { outCodes[lf->c] = prefix; }
else if (const InternalNode* in = dynamic_cast(node)) { HuffCode leftPrefix =
prefix; leftPrefix.push_back(false); GenerateCodes(in->left, leftPrefix,
outCodes); HuffCode rightPrefix = prefix; rightPrefix.push_back(true);
GenerateCodes(in->right, rightPrefix, outCodes); } } int main() { // Build
frequency table int frequencies[UniqueSymbols] = {0}; const char* ptr =
SampleString; while (*ptr != \'\\0\') ++frequencies[*ptr++]; INode* root =
BuildTree(frequencies); HuffCodeMap codes; GenerateCodes(root, HuffCode(),
codes); delete root; for (HuffCodeMap::const_iterator it = codes.begin(); it !=
codes.end(); ++it) { std::cout << it->first << \" \"; std::copy(it-
>second.begin(), it->second.end(), std::ostream_iterator(std::cout)); std::cout
<< std::endl; } return 0; }.
With the biological species concept, the process of speciation is fre.pdf
With the biological species concept, the process of speciation is frequently defined as the
evolution of between populations. reproductive isolation genetic drift gene flow reproductive
inclusion geographic separation The phylogenetic species concept looks at __. environmental
adaptations and morphology species response to adverse conditions and genetic data genetic data
and environmental adaptations morphology and environmental adaptations morphology and
genetic data A phylogenetic species comprise __. interbreeding population that are
reproductively isolated individuals that share measurable traits that distinguish them populations
that share a recent evolutionary history individuals that share a recent evolutionary history one
large gene pool subdivided into local populations
Solution
Reproductive isolation
According to biological species concept, species is a group of actually or potentially
interbreeding individuals who are reproductively isolated from other such groups..
Write a class ArrayList that represents an array of integers. Init.pdf
Write a class ArrayList that represents an array of integers. Initially it has a capacity of 1 and is
“empty”.
At any time, it can be partially full, so it keeps track of its current occupied size, as well as its
capacity
(true size).
Write a class ArrayList that represents an array of integers. Initially it has a capacity of 1 and is
“empty”.
At any time, it can be partially full, so it keeps track of its current occupied size, as well as its
capacity
(true size).
However the output for the prime numbers 1 -50 is incorrect. Displaying numbers like 0, 625 for
prime numbers.
This is my code with the main method below
#include
#include
#include
using namespace std;
class ArrayList
{
private:
int *array;
int capacity, asize;
public:
int size();
ArrayList();
int & operator [](unsigned int);
void push_back(int);
void erase(int m);
string toString();
};
// 1.a: Default constructor used to unitialize the array with capacity=1
ArrayList::ArrayList()
{
asize = 0;
capacity = 1;
array = new int[capacity];
}
// This function returns the actual size of array
int ArrayList::size()
{
return asize;
}
// 1.b:The overloaded [] oprtaor return element at ith position in array
int & ArrayList::operator [](unsigned int i)
{
if(i >= asize)
{
cout << \"invalid reference \";
exit(0);
}
return *(array + i);
}
//1.c: This function push m at the end of the array
void ArrayList::push_back(int m)
{
// this condition checks if size is beyond capacity or not. if so double the capacity.
if(asize == capacity)
{
capacity = 2 * capacity;
int *temp = new int[capacity];
for(int i = 0; i < asize; i++)
temp[i] = array[i];
array = new int[capacity];
for(int i = 0; i < asize; i++)
array[i] = temp[i];
}
array[asize] = m;
asize = asize + 1;
}
void ArrayList::erase(int m){
int pos = -1;
for(int i = 0; i < asize; i++){
if(array[i] == m){
pos = i;
break;
}
}
if(pos == -1){
cout << \"Element not present\ \";
}
else{
for(int i = pos; i < asize - 1; i++){
array[i] = array[i + 1];
}
}
asize--;
if(asize == capacity / 2)
{
capacity = capacity / 2;
int *temp = new int[capacity];
for(int i = 0; i < asize; i++)
temp[i] = array[i];
array = new int[capacity];
for(int i = 0; i < asize; i++)
array[i] = temp[i];
}
}
string ArrayList::toString(){
string str = \"[\";
for(int i = 0; i < asize; i++){
ostringstream oss;
oss << array[i];
str += oss.str();
if(i != asize - 1){
str += \", \";
}
}
str += \"]\";
return str;
}
//---------------------------
//You can test above class by using main() below
int main()
{
ArrayList arr; // call ro default constructor
for (int i = 1; i <= 50; i++)
{
arr.push_back(i); // call to push_back()
}
cout << \"Should contain numbers 1..50, is \";
cout << arr.toString();
cout << \"\ \";
return 0;
}
This is my code with the main method below
#include
#include
#include
using namespace std;
class ArrayList
{
private:
int *array;
int capacity, asize;
public:
int size();
ArrayList();
int & operator [](unsigned int);
void push_back(int);
void erase(int m);
string toString();
};
// 1.a:.
what is the relationship between lnx and 1xSolutionThe relat.pdf
what is the relationship between lnx and 1/x?
Solution
The relation between ln x and (1/x) is explained in terms of definite and indefinte integrals.
Indefinite integral:
Int (1/x) dx + C = lnx +C.
Definite integral:
{Int (1/t) dt from t = 0 to t = x} = lnx.
Or in other words ln (x) is the area under the curve f(x) = ln(t) between the ordinates t= 0 to t =
x, which could be calculated by evaluation of the definite integral Int (1/t)dt from t = 0 to t =x..
Which of these conclusions is supported by plant phylogenies (evolut.pdf
Which of these conclusions is supported by plant phylogenies (evolutionary trees)?
Question 4 options:1)It is likely that the transition to land occurred directly from red algae.2)In
all of the trees generated so far, land plants trace back to more than one ancestral group.3)The
oldest lineages of land plants are descended from some green algae (Charophytes)4)The closest
relative to land plants is fungi
Solution
Answer is option 3) The oldest lineages of land plants are descended from some green algae
(Charophytes)
Land plants evolbed from green algae approximately 510 million years ago. The Charophytes are
still present..
Who are some other individuals who might want to use the informa.pdf
Who are some other individuals who might want to use the information in the financial
statements
Who are some other individuals who might want to use the information in the financial
statements
Who are some other individuals who might want to use the information in the financial
statements
Solution
Some Other Individuals who might use the information in financial statements
1) Suppliers - Suppliers are interested in the information of financial Statements. Suppliers get to
know about solvency and liquidity of company to pay its short term obligations.
2) Employees- Employees use the financial statement information to analyse about the
company\'s ability to pay salary and benefits. Others reasons of using financial statement
information are career development, Financial performance.
3) Customers - Customers use the financial statement information for assessing the company
expansion possibilities, its stability of operations, Its compliances review, for investment
decisions.
Which account below is not a subdivision of owners equityAccumu.pdf
Which account below is not a subdivision of owner\'s equity?
Accumulated Comprehensive Income.
Bond Sinking fund.
Addition Paid-in-Capital.
Retained Earnings.
Accumulated Comprehensive Income.
Bond Sinking fund.
Addition Paid-in-Capital.
Retained Earnings.
Solution
Bonk Sinking Fund not a subdivision of owner\'s equity
Parts of Stockholder Equity are
Capital Stock, Addition Paid-in-Capital, Retained Earnings., Accumulated Comprehensive
Income, Treasury Stock, NONCONTROLLING INTEREST (MINORITY INTEREST).
What is the nucleoid region of a prokaryotic cell a membrane bound .pdf
What is the nucleoid region of a prokaryotic cell? a membrane bound organelle that contains
the DNA a region within the nucleus where parts of ribosomes are made a place within the cell
where DNA is more abundant a place where you\'d expect to find a proton and a neutron
Solution
A place with the cell where DNA is more abundant
The nucleoid refers to an irregularly shaped region within a prokaryotic cell that contains the
genetic material..
What is heartwood What is sapwood What is the most abundant tissu.pdf
What is heartwood? What is sapwood? What is the most abundant tissue in the three-year-old
stem? What are three contrasting differences in structure between the sunflower stem and the
TNia stem? What are two techniques that can be used to determine the age of a woody twig?
Solution
1. Heart wood is the dead and inner wood tissue produced by cork cambium. It is dark in colr
and is distinguished from sap wood by its color and texture.
Sapwood is the outermost living wood tissue. It is also produced by cambium but is composed of
different types of cells. It is lightin color. It is involved conduction of water and minerals from
roots to all parts of tree.
2. In a three year old stem, the secondary xylem and phloem are bundant than primary xylem and
phloem. These vascular tissues conspicuously appear as annual rings by which the age of the tree
is known.
3.
4.
The age of a woody twig can be determined by counting the number of groups of bud scale scars
on it and he the number of terminal bud scale scars present.SunflowerTiliaAnnualperennialherb
exhibits no secondary growthtree exhibits secondary growthVascular bundles form a ring. Xylem
lies inside the vascular bundles. Phloem lies outside and phloem fibers are tough. The center of
stem is filled with ground tissue known as pithOne year old stem exhibits no secondary growth
and contains a layer of xylem and two later meristems called vascular and cork cambium.
During second year growth 2 rings of xylem is observed. During third year secondary xylem is
obseved and secondary phloem towards inside to xylem..
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