Write a program in Java that reads a set of doubles from a file, sto.pdf
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![Write a program in Java that reads a set of doubles from a file, stores them in an array or
ArrayList, and then prints them back out to the console (using System.out.println statements) in
REVERSE order.
For example, if the input file input.txt file contains
27.3
45.6
98.3
10.1
The console output will display
10.1
98.3
45.6
27.3
Solution
ReadAndDisplayReverse.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class ReadAndDisplayReverse {
public static void main(String[] args) throws FileNotFoundException {
File inputFile = new File("D:input.txt");
if(inputFile.exists()){
Scanner scan = new Scanner(inputFile);
ArrayList list = new ArrayList();
while(scan.hasNextDouble()){
list.add(scan.nextDouble());
}
System.out.println("The numbers in reverse order: ");
for(int i=list.size()-1; i>=0; i--){
System.out.println(list.get(i));](https://image.slidesharecdn.com/writeaprograminjavathatreadsasetofdoublesfromafilesto-230702074713-4f94239e/85/Write-a-program-in-Java-that-reads-a-set-of-doubles-from-a-file-sto-pdf-1-320.jpg)
Recommended
Change the code in Writer.java only to get it working. Must contain .pdf
Change the code in Writer.java only to get it working. Must contain methods: logReverse() ,
logMax(), logDuplicates(),
This lab is going to focus on File Output, which you will find is somewhat similar to console
output.
FileMain.java
import java.io.IOException;
import java.util.ArrayList;
import java.util.Scanner;
public class FileMain {
public static void main(String[] args) throws IOException{
Scanner scnr = new Scanner(System.in);
System.out.print("Please enter the name of the file you would like to read: ");
String fileName = scnr.next();
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents(fileName);
System.out.println("Please enter a name for your new file: ");
String newFileName = scnr.next();
Writer fileOut = new Writer(newFileName);
fileOut.logReverse(fileContents);
fileOut.logMax(fileContents);
fileOut.logDuplicates(fileContents);
fileOut.closeWriter();
scnr.close();
}
}
Filetester.java
import java.io.IOException;
import java.util.ArrayList;
public class FileTester {
public static boolean testLogReverse(ArrayList contents) throws IOException {
Writer writer = new Writer("logReverseTest.txt");
writer.logReverse(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Reversed file contents: ");
expected.add("58");
expected.add("12");
expected.add("19");
expected.add("42");
expected.add("12");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logReverseTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogMax(ArrayList contents) throws IOException {
Writer writer = new Writer("logMaxTest.txt");
writer.logMax(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("The largest number in the file is: 58");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logMaxTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogDuplicates(ArrayList contents) throws IOException {
Writer writer = new Writer("logDuplicatesTest.txt");
writer.logDuplicates(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Duplicates found: true");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logDuplicatesTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static void main(String[] args) throws IOException {
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents("nums.txt");
System.out.println("logReverse test passed? " + testLogReverse(fileContents));
System.out.println("logMax test passed? " + testLogMax(fileContents));
System.out.println("logDuplicates test passed? " + testLogDuplicates(fileContents));
}
}
Reader.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Sca.
Write a program in java that asks a user for a file name and prints .pdf
Write a program in java that asks a user for a file name and prints the number of characters,
words (separated by whitespace), and lines in that file. Then, it replaces each line of the file with
its reverse. For example, if the file contains the following lines (Test1.txt):
This is a test
Hi there
Output on the console:
Number of characters: 22
Number of words: 6
Number of lines: 2
Data written to the file (Test1.txt):
tset a si sihT
ereth iH
Solution
ReadFileCount.java
import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintStream;
import java.util.Scanner;
public class ReadFileCount {
public static void main(String[] args) throws FileNotFoundException {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter file name: \");
String fileName = scan.next();
StringBuffer finalsb = new StringBuffer();
File file = new File(fileName);
if(file.exists()){
int numberOfLines = 0;
int numberOfCharacters = 0;
int numberOfWords = 0;
Scanner scan1 = new Scanner(file);;
while(scan1.hasNextLine()){
StringBuffer sb = new StringBuffer();
String s = scan1.nextLine();
sb.append(s);
numberOfLines++;
numberOfCharacters = numberOfCharacters + s.length();
String words[] = s.split(\" \");
numberOfWords = numberOfWords + words.length;
finalsb.append(sb.reverse());
finalsb.append(\"\ \");
}
System.out.println(\"Number of characters: \"+numberOfCharacters);
System.out.println(\"Number of words: \"+numberOfWords);
System.out.println(\"Number of lines : \"+numberOfLines);
PrintStream ps =new PrintStream(file);
ps.print(finalsb.toString());
ps.flush();
ps.close();
System.out.println(\"Data written to the file \"+fileName);
}
else{
System.out.println(\"File does not exist\");
}
}
}
Output:
Enter file name:
D:\\\\Test1.txt
Number of characters: 0
Number of words: 0
Number of lines : 0
Data written to the file D:\\\\Test1.txt
Test1.txt
tset a si sihT
ereht iH.
Please I am trying to get this code to output in -txt file- I need you.pdf
Please I am trying to get this code to output in .txt file:
I need your help:
import java.io.File; // Import the File class
import java.io.FileNotFoundException; // Import this class to handle errors
// Import the Scanner class to read text files
import java.util.*;
import java.io.*;
public class KMeans {
List<double []> clusterCentroids;
Map<Integer,List<Double>> dataMatrix;
List<double[]> data;
Integer numClusters;
public void writeFile(List<Double> value, File filename) {
try {
FileWriter myWriter = new FileWriter(filename);
myWriter.write(value.toString());
myWriter.close();
System.out.println("Successfully wrote to the file.");
} catch (IOException e) {
System.out.println("An error occurred.");
e.printStackTrace();
}
}
public KMeans() {
data = new ArrayList<double []>();
dataMatrix = new LinkedHashMap<>();
}
void readData(String filePath, int n, List<Double> c) {
numClusters = n;
try {
BufferedReader br = new BufferedReader(new FileReader(new File(filePath)));
String line;
int i = 0;
while((line = br.readLine()) != null) {
String [] elem = line.split("\\s+");
int j = 0;
for(String d : elem) {
if(isCentroid(j, c)) {
this.clusterCentroids.get(i)[j] = ((Double.valueOf(d)));
}
//data.get(i)[j] = ((Double.valueOf(d)));
System.out.println(data.get(j)[i]);
}
System.out.println();
i++;
}
br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
private boolean isCentroid(int j, List<Double> c) {
for(int i = 0; i < c.size(); i++) {
if(j == c.get(i)) {
return true;
}
}
return false;
}
public static void main(String [] args) {
Scanner sc = new Scanner(System.in);
List<Double> centroids = new ArrayList<>();
String filePath = ("C:\\Users\\mamdo\\eclipse-
workspace\\K_project\\src\\synthetic_control_data.txt");
int n = 6;
for(int i=0;i<n;i++) {
Random r = new Random();
centroids.add((double)r.nextInt(600)+1);
}
System.out.println("Initial Clusters Centroids : " + centroids);
KMeans km = new KMeans();
//km.readData(filePath,n,centroids);
//km.calc();
}
}
.
Use arrays to store data for analysis. Use functions to perform the .pdf
Use arrays to store data for analysis. Use functions to perform the analysis described below. All
output is to be written to an output file.
Solution
import java.util.Scanner;
import java.util.ArrayList;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.util.ArrayList;
public class DNA{
private String dna;
public DNA(){
}
public void read_store(String filename){
/*try {
Scanner in;
//in = new Scanner(new FileReader(filename));
dna = in.next();
}catch(IOException e){
System.out.println(\"file not there \" + e);
return;
}*/
}
public char compliment_base(char c){
if(c == \'A\') return \'T\';
if(c == \'T\') return \'A\';
if(c == \'G\') return \'C\';
if(c == \'C\') return \'G\';
return \' \';
}
public void DrawDNA(String seq){
System.out.println(\"---+-----+------+------+------\");
for (char c : seq.toCharArray() ) {
System.out.print(c + \" \");
}
System.out.println(\"DNA Sequence \");
System.out.println(\"................................\");
for (char c : seq.toCharArray() ) {
System.out.print(compliment_base(c) + \" \");
}
System.out.println(\" Complement \");
System.out.println(\"---+-----+------+------+------\");
System.out.println(\"\");
}
public void Prefix(int n, String base){
String output = base.substring(0,n);
DrawDNA(output);
}
public static void main(String[] args) {
DNA d = new DNA();
d.DrawDNA(\"ATGC\");
d.Prefix(4,\"ACGTTGCA\");
}
}
---+-----+------+------+------
A T G C DNA Sequence
................................
T A C G Complement
---+-----+------+------+------
---+-----+------+------+------
A C G T DNA Sequence
................................
T G C A Complement
---+-----+------+------+------.
Recommended
Change the code in Writer.java only to get it working. Must contain .pdf
Change the code in Writer.java only to get it working. Must contain methods: logReverse() ,
logMax(), logDuplicates(),
This lab is going to focus on File Output, which you will find is somewhat similar to console
output.
FileMain.java
import java.io.IOException;
import java.util.ArrayList;
import java.util.Scanner;
public class FileMain {
public static void main(String[] args) throws IOException{
Scanner scnr = new Scanner(System.in);
System.out.print("Please enter the name of the file you would like to read: ");
String fileName = scnr.next();
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents(fileName);
System.out.println("Please enter a name for your new file: ");
String newFileName = scnr.next();
Writer fileOut = new Writer(newFileName);
fileOut.logReverse(fileContents);
fileOut.logMax(fileContents);
fileOut.logDuplicates(fileContents);
fileOut.closeWriter();
scnr.close();
}
}
Filetester.java
import java.io.IOException;
import java.util.ArrayList;
public class FileTester {
public static boolean testLogReverse(ArrayList contents) throws IOException {
Writer writer = new Writer("logReverseTest.txt");
writer.logReverse(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Reversed file contents: ");
expected.add("58");
expected.add("12");
expected.add("19");
expected.add("42");
expected.add("12");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logReverseTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogMax(ArrayList contents) throws IOException {
Writer writer = new Writer("logMaxTest.txt");
writer.logMax(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("The largest number in the file is: 58");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logMaxTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogDuplicates(ArrayList contents) throws IOException {
Writer writer = new Writer("logDuplicatesTest.txt");
writer.logDuplicates(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Duplicates found: true");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logDuplicatesTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static void main(String[] args) throws IOException {
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents("nums.txt");
System.out.println("logReverse test passed? " + testLogReverse(fileContents));
System.out.println("logMax test passed? " + testLogMax(fileContents));
System.out.println("logDuplicates test passed? " + testLogDuplicates(fileContents));
}
}
Reader.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Sca.
Write a program in java that asks a user for a file name and prints .pdf
Write a program in java that asks a user for a file name and prints the number of characters,
words (separated by whitespace), and lines in that file. Then, it replaces each line of the file with
its reverse. For example, if the file contains the following lines (Test1.txt):
This is a test
Hi there
Output on the console:
Number of characters: 22
Number of words: 6
Number of lines: 2
Data written to the file (Test1.txt):
tset a si sihT
ereth iH
Solution
ReadFileCount.java
import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintStream;
import java.util.Scanner;
public class ReadFileCount {
public static void main(String[] args) throws FileNotFoundException {
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter file name: \");
String fileName = scan.next();
StringBuffer finalsb = new StringBuffer();
File file = new File(fileName);
if(file.exists()){
int numberOfLines = 0;
int numberOfCharacters = 0;
int numberOfWords = 0;
Scanner scan1 = new Scanner(file);;
while(scan1.hasNextLine()){
StringBuffer sb = new StringBuffer();
String s = scan1.nextLine();
sb.append(s);
numberOfLines++;
numberOfCharacters = numberOfCharacters + s.length();
String words[] = s.split(\" \");
numberOfWords = numberOfWords + words.length;
finalsb.append(sb.reverse());
finalsb.append(\"\ \");
}
System.out.println(\"Number of characters: \"+numberOfCharacters);
System.out.println(\"Number of words: \"+numberOfWords);
System.out.println(\"Number of lines : \"+numberOfLines);
PrintStream ps =new PrintStream(file);
ps.print(finalsb.toString());
ps.flush();
ps.close();
System.out.println(\"Data written to the file \"+fileName);
}
else{
System.out.println(\"File does not exist\");
}
}
}
Output:
Enter file name:
D:\\\\Test1.txt
Number of characters: 0
Number of words: 0
Number of lines : 0
Data written to the file D:\\\\Test1.txt
Test1.txt
tset a si sihT
ereht iH.
Please I am trying to get this code to output in -txt file- I need you.pdf
Please I am trying to get this code to output in .txt file:
I need your help:
import java.io.File; // Import the File class
import java.io.FileNotFoundException; // Import this class to handle errors
// Import the Scanner class to read text files
import java.util.*;
import java.io.*;
public class KMeans {
List<double []> clusterCentroids;
Map<Integer,List<Double>> dataMatrix;
List<double[]> data;
Integer numClusters;
public void writeFile(List<Double> value, File filename) {
try {
FileWriter myWriter = new FileWriter(filename);
myWriter.write(value.toString());
myWriter.close();
System.out.println("Successfully wrote to the file.");
} catch (IOException e) {
System.out.println("An error occurred.");
e.printStackTrace();
}
}
public KMeans() {
data = new ArrayList<double []>();
dataMatrix = new LinkedHashMap<>();
}
void readData(String filePath, int n, List<Double> c) {
numClusters = n;
try {
BufferedReader br = new BufferedReader(new FileReader(new File(filePath)));
String line;
int i = 0;
while((line = br.readLine()) != null) {
String [] elem = line.split("\\s+");
int j = 0;
for(String d : elem) {
if(isCentroid(j, c)) {
this.clusterCentroids.get(i)[j] = ((Double.valueOf(d)));
}
//data.get(i)[j] = ((Double.valueOf(d)));
System.out.println(data.get(j)[i]);
}
System.out.println();
i++;
}
br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
private boolean isCentroid(int j, List<Double> c) {
for(int i = 0; i < c.size(); i++) {
if(j == c.get(i)) {
return true;
}
}
return false;
}
public static void main(String [] args) {
Scanner sc = new Scanner(System.in);
List<Double> centroids = new ArrayList<>();
String filePath = ("C:\\Users\\mamdo\\eclipse-
workspace\\K_project\\src\\synthetic_control_data.txt");
int n = 6;
for(int i=0;i<n;i++) {
Random r = new Random();
centroids.add((double)r.nextInt(600)+1);
}
System.out.println("Initial Clusters Centroids : " + centroids);
KMeans km = new KMeans();
//km.readData(filePath,n,centroids);
//km.calc();
}
}
.
Use arrays to store data for analysis. Use functions to perform the .pdf
Use arrays to store data for analysis. Use functions to perform the analysis described below. All
output is to be written to an output file.
Solution
import java.util.Scanner;
import java.util.ArrayList;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.util.ArrayList;
public class DNA{
private String dna;
public DNA(){
}
public void read_store(String filename){
/*try {
Scanner in;
//in = new Scanner(new FileReader(filename));
dna = in.next();
}catch(IOException e){
System.out.println(\"file not there \" + e);
return;
}*/
}
public char compliment_base(char c){
if(c == \'A\') return \'T\';
if(c == \'T\') return \'A\';
if(c == \'G\') return \'C\';
if(c == \'C\') return \'G\';
return \' \';
}
public void DrawDNA(String seq){
System.out.println(\"---+-----+------+------+------\");
for (char c : seq.toCharArray() ) {
System.out.print(c + \" \");
}
System.out.println(\"DNA Sequence \");
System.out.println(\"................................\");
for (char c : seq.toCharArray() ) {
System.out.print(compliment_base(c) + \" \");
}
System.out.println(\" Complement \");
System.out.println(\"---+-----+------+------+------\");
System.out.println(\"\");
}
public void Prefix(int n, String base){
String output = base.substring(0,n);
DrawDNA(output);
}
public static void main(String[] args) {
DNA d = new DNA();
d.DrawDNA(\"ATGC\");
d.Prefix(4,\"ACGTTGCA\");
}
}
---+-----+------+------+------
A T G C DNA Sequence
................................
T A C G Complement
---+-----+------+------+------
---+-----+------+------+------
A C G T DNA Sequence
................................
T G C A Complement
---+-----+------+------+------.
import java.io.BufferedReader;import java.io.File;import java.io.pdf
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class FileEdit {
public static List lines = new ArrayList();
public static void main(String[] args) throws IOException
{
Scanner s = new Scanner(System.in);
System.out.print("EDIT: ");
String fileName = s.nextLine();
BufferedReader br = new BufferedReader(new FileReader(new File(fileName)));
String str="";
int count=0;
while((str=br.readLine())!=null)
{
lines.add(count, str);
System.out.println((++count) + "> "+ str);
}
String text="";
String command = "";
System.out.print((++count)+"> ");
command=s.nextLine();
String commandArr[];
int flag;
while(!command.equals("E"))
{
flag=0;
commandArr = command.split("\\s");
if(commandArr[0].equals("I")) //Insertion
{
while(true)
{
if(commandArr.length==1&&flag!=2)
{
System.out.print((count)+"> ");
text = s.nextLine();
insertLine(text,count-1);
}
else if(commandArr.length==2&&flag!=2)
{
System.out.print((commandArr[1])+"> ");
count=Integer.parseInt(commandArr[1]);
text = s.nextLine();
insertLine(text,Integer.parseInt(commandArr[1])-1);
}
else
insertLine(text,count-1);
System.out.print((++count)+"> ");
command=s.nextLine();
commandArr = command.split("\\s");
if(commandArr[0].equals("I")||commandArr[0].equals("L")||commandArr[0].equals("D")||comm
andArr[0].equals("E"))
{
flag=1;
break;
}
else
{
flag=2;
text=command;
}
}
}
else if(commandArr[0].equals("L")) //Listing
{
printList();
}
else if(commandArr[0].equals("D")) //Deletion
{
if(commandArr.length==1)
{
deleteLine(count-1,count-1);
}
else if(commandArr.length==2)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[1])-1);
}
else if(commandArr.length==3)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[2])-1);
}
count=lines.size();
}
if(flag!=1)
{
System.out.print((count++)+"> ");
command = s.nextLine();
}
}
}
public static void insertLine(String text,int count)
{
if (count >= lines.size()) {
for(int i = lines.size(); i <= count; i++) {
lines.add(null);
}
}
lines.set(count,text);
}
public static void deleteLine(int start,int end)
{
for(int i=start;i<=end;i++)
lines.remove(i);
}
public static void printList()
{
for(int i=0;i "+lines.get(i));
}
}
Here is my output:
EDIT: textin.txt
1> The First Line
1>
2> And another line
3> I 3
3> The second line
4> One more line
5> L
1> null
2> null
3> The second line
4> One more line
5> D 2
3> L
1> null
2> The second line
3> One more line
4> E
How can I keep it from printing "null" after ">" and it just be blank. I need the output to look like
this:
1> The first line
2>
3> And another line
4> I 3
3> The second line
4> One more line
5> L
1> The first line
2>
3> The second line
4> One more line
5> And another line
5> D 2
4> L
1> The first line
2> The second line
3> One more line
4> And another line
5> E.
Write a program that will count the number of characters- words- and l.docx
Write a program that will count the number of characters, words, and lines in a file. Words are separated by whitespace characters. The file name should be passed as a command-line argument, as shown;
c:\\exercise>java Exercise12_13 Loan.java
File Loan.java has
1919 characters
210 words
71 lines
c:\\exercise>
Solution
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
import java.util.StringTokenizer;
public class ass1
{
public static void main(String[] args) throws FileNotFoundException
{
//Â Â Scanner console = new Scanner(System.in);
System.out.println(args[0]);
//System.out.println(args[1]);
//System.out.println(args[2]);
String inputFile=args[0];
File file = new File(inputFile);
Scanner in = new Scanner(file);
int words = 0;
int lines = 0;
int chars = 0;
while(in.hasNextLine()) {
lines++;
String line = in.nextLine();
chars += line.length();
words += new StringTokenizer(line, \" \").countTokens();
}
System.out.println(\"characters are \"+chars);
System.out.println(\"words are \"+words);
System.out.println(\"lines are \"+lines);
}
}
.
Here is my code for a linefile editor import java.io.BufferedRea.pdf
Here is my code for a line/file editor:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class FileEdit {
public static List lines = new ArrayList();
public static void main(String[] args) throws IOException
{
Scanner s = new Scanner(System.in);
System.out.print("EDIT: ");
String fileName = s.nextLine();
BufferedReader br = new BufferedReader(new FileReader(new File(fileName)));
String str="";
int count=0;
while((str=br.readLine())!=null)
{
lines.add(count, str);
System.out.println((++count) + "> "+ str);
}
String text="";
String command = "";
System.out.print((++count)+"> ");
command=s.nextLine();
String commandArr[];
int flag;
while(!command.equals("E"))
{
flag=0;
commandArr = command.split("\\s");
if(commandArr[0].equals("I")) //Insertion
{
while(true)
{
if(commandArr.length==1&&flag!=2)
{
System.out.print((count)+"> ");
text = s.nextLine();
insertLine(text,count-1);
}
else if(commandArr.length==2&&flag!=2)
{
System.out.print((commandArr[1])+"> ");
count=Integer.parseInt(commandArr[1]);
text = s.nextLine();
insertLine(text,Integer.parseInt(commandArr[1])-1);
}
else
insertLine(text,count-1);
System.out.print((++count)+"> ");
command=s.nextLine();
commandArr = command.split("\\s");
if(commandArr[0].equals("I")||commandArr[0].equals("L")||commandArr[0].equals("D")||comm
andArr[0].equals("E"))
{
flag=1;
break;
}
else
{
flag=2;
text=command;
}
}
}
else if(commandArr[0].equals("L")) //Listing
{
printList();
}
else if(commandArr[0].equals("D")) //Deletion
{
if(commandArr.length==1)
{
deleteLine(count-1,count-1);
}
else if(commandArr.length==2)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[1])-1);
}
else if(commandArr.length==3)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[2])-1);
}
count=lines.size();
}
if(flag!=1)
{
System.out.print((count++)+"> ");
command = s.nextLine();
}
}
}
public static void insertLine(String text,int count)
{
if (count >= lines.size()) {
for(int i = lines.size(); i <= count; i++) {
lines.add(null);
}
}
lines.set(count,text);
}
public static void deleteLine(int start,int end)
{
for(int i=start;i<=end;i++)
lines.remove(i);
}
public static void printList()
{
for(int i=0;i "+lines.get(i));
}
}
Here is my output:
EDIT: textin.txt
1> The First Line
1>
2> And another line
3> I 3
3> The second line
4> One more line
5> L
1> null
2> null
3> The second line
4> One more line
5> D 2
3> L
1> null
2> The second line
3> One more line
4> E
How can I keep it from printing "null" after ">" and it just be blank. I need the output to look like
this:
1> The first line
2>
3> And another line
4> I 3
3> The second line
4> One more line
5> L
1> The first line
2>
3> The second line
4> One more line
5> And another line
5> D 2
4> L
1> The first line
2> The second line
3> One more line
4> And another line
5> E.
Create a text file named lnfo.txt. Enter the following informatio.pdf
Create a text file named \"lnfo.txt\". Enter the following information using Linked List (any
method). Name rightarrow String Address rightarrow String Phone rightarrow String There
should be continues loop which will ask the above information and write down in the TEXT File.
When user inputs Exit in Name Field then program should be ended.
Solution
package sample;
import java.io.*;
public class ReadWrite {
public static void main(String[] args) {
BufferedReader reader = null;
try {
reader = new BufferedReader(new InputStreamReader(System.in));
File file = new File(\"C:\\\\Temp\\\\Info.txt\");
// creates the file
file.createNewFile();
// creates a FileWriter Object
FileWriter writer = new FileWriter(file);
while (true) {
System.out.print(\"Enter Name : \");
String name = reader.readLine();
if (\"Exit\".equals(name)) {
System.out.println(\"Exit!\");
writer.flush();
writer.close();
System.exit(0);
}
System.out.print(\"Enter Address : \");
String address = reader.readLine();
System.out.print(\"Enter Phone : \");
String phone = reader.readLine();
// Writes the content to the file
writer.write(\"\ \ -----------\");
writer.write(\"\ Name : \"+name);
writer.write(\"\ Address : \"+address);
writer.write(\"\ Phone : \"+phone);
writer.write(\"\ -----------\");
System.out.println(\"Added Below Record Successfully \");
System.out.println(\"-----------\ \");
System.out.println(\"Name : \"+name);
System.out.println(\"Address : \"+address);
System.out.println(\"Phone : \"+phone);
System.out.println(\"-----------\ \");
}
} catch (IOException ex) {
ex.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
}
}
package sample;
import java.io.*;
public class ReadWrite {
public static void main(String[] args) {
BufferedReader reader = null;
try {
reader = new BufferedReader(new InputStreamReader(System.in));
File file = new File(\"C:\\\\Temp\\\\Info.txt\");
// creates the file
file.createNewFile();
// creates a FileWriter Object
FileWriter writer = new FileWriter(file);
while (true) {
System.out.print(\"Enter Name : \");
String name = reader.readLine();
if (\"Exit\".equals(name)) {
System.out.println(\"Exit!\");
writer.flush();
writer.close();
System.exit(0);
}
System.out.print(\"Enter Address : \");
String address = reader.readLine();
System.out.print(\"Enter Phone : \");
String phone = reader.readLine();
// Writes the content to the file
writer.write(\"\ \ -----------\");
writer.write(\"\ Name : \"+name);
writer.write(\"\ Address : \"+address);
writer.write(\"\ Phone : \"+phone);
writer.write(\"\ -----------\");
System.out.println(\"Added Below Record Successfully \");
System.out.println(\"-----------\ \");
System.out.println(\"Name : \"+name);
System.out.println(\"Address : \"+address);
System.out.println(\"Phone : \"+phone);
System.out.println(\"-----------\ \");
}
} catch (IOException ex) {
ex.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOExcept.
Write a java program that allows the user to input the name of a fil.docx
Write a java program that allows the user to input the name of a fil
Write a java program that allows the user to input the name of a file.docx
Write a java program that allows the user to input the name of a file that contains positive integers (one integer per line) The number of integers in the file The program should find all odd and even numbers and write the odd numbers to a file \"odd.txt\" and write the even numbers to another file \"even.txt\"
Solution
package expertques;
import java.io.File;
import java.io.PrintWriter;
import java.util.Scanner;
public class evenoddwithfile {
public static void main(String[] args) throws Exception {
File in;//file input
File even = new File(\"f://even.txt\");//creates file even
File odd = new File(\"f://odd.txt\");//creates file odd
Scanner s = new Scanner(System.in);//reads input from console or user
System.out.println(\"Enter the file name with path: \");
in = new File(s.nextLine());
System.out.println(\"Enter the number of integers n the file: \");
int n = s.nextInt();
if (in.exists()) {//checks if input file exist or not
Scanner ins = new Scanner(in);//reads input file
PrintWriter pe = new PrintWriter(even);//write to even file
PrintWriter po = new PrintWriter(odd);//writes to odd file
for (int i = 0; i < n; i++) {//loop till the numbers exists
int x = ins.nextInt();//reads from input file
if (x % 2 == 0) {//checks for even or odd
pe.println(x);//if even writes in even file
} else {
po.println(x);//if odd writes in odd file
}
}
pe.close();//closes even file very important else nothing will be written in the file
po.close();//closes odd file very important else nothing will be written in the file
System.out.println(\"File successfully written with odds and evens\");
} else {
System.out.println(\"Error file not found at specified path\");//if file not exist
}
}
}
output
run:
Enter the file name with path:
f://integers.txt
Enter the number of integers n the file:
8
File successfully written with odds and evens
BUILD SUCCESSFUL (total time: 6 seconds)
.
Write a Java program that opens the file, reads all the Grade from t.pdf
Write a Java program that opens the file, reads all the Grade from the file, and using a method
calculates and displays the following A) Displays the grades with their letter values (80 - B) B)
the sum of the Grades in the file C) the average of the Grades in the file
Solution
GradeRead.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class GradeRead {
public static void main(String[] args) throws FileNotFoundException {
Scanner scan1 = new Scanner(System.in);
System.out.print(\"Enter the file name: \");
String fileName = scan1.next();
File file = new File(fileName);
if(file.exists()){
Scanner scan = new Scanner(file);
calculateGradeDetail(scan);
}
else{
System.out.println(\"Input does not exist\");
}
}
public static void calculateGradeDetail(Scanner scan){
int sum = 0;
int count = 0;
char gradeLetter = \'\\0\';
while(scan.hasNextInt()){
count++;
int n = scan.nextInt();
sum = sum + n;
if(n >=90 && n<=100){
gradeLetter = \'A\';
}
else if(n >=80 && n<90){
gradeLetter = \'B\';
}
else if(n >=70 && n<80){
gradeLetter = \'C\';
}
else if(n >=60 && n<=70){
gradeLetter = \'D\';
}
else {
gradeLetter = \'E\';
}
System.out.println(\"Grade: \"+gradeLetter+\" - \"+n);
}
System.out.println(\"The sum of the Grades in the file: \"+sum);
double average = sum/(double)count;
System.out.println(\"the average of the Grades in the file: \"+average);
System.out.println();
}
}
Output:
Enter the file name: D:\\\\grade.txt
Grade: D - 60
Grade: C - 70
Grade: B - 80
Grade: A - 90
Grade: A - 100
Grade: E - 40
Grade: E - 50
Grade: D - 60
The sum of the Grades in the file: 550
the average of the Grades in the file: 68.75
Grade.txt
60
70
80
90
100
40
50
60.
Please help me with a UML class diagram for the following code im.pdf
Please help me with a UML class diagram for the following code:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class FileEdit {
public static List lines = new ArrayList();
public static void main(String[] args) throws IOException
{
Scanner s = new Scanner(System.in);
System.out.print("EDIT: ");
String fileName = s.nextLine();
BufferedReader br = new BufferedReader(new FileReader(new File(fileName)));
String str="";
int count=0;
while((str=br.readLine())!=null)
{
lines.add(count, str);
System.out.println((++count) + "> "+ str);
}
String text="";
String command = "";
System.out.print((++count)+"> ");
command=s.nextLine();
String commandArr[];
int flag;
while(!command.equals("E"))
{
flag=0;
commandArr = command.split("\\s");
if(commandArr[0].equals("I")) //Insertion
{
while(true)
{
if(commandArr.length==1&&flag!=2)
{
System.out.print((count)+"> ");
text = s.nextLine();
insertLine(text,count-1);
}
else if(commandArr.length==2&&flag!=2)
{
System.out.print((commandArr[1])+"> ");
count=Integer.parseInt(commandArr[1]);
text = s.nextLine();
insertLine(text,Integer.parseInt(commandArr[1])-1);
}
else
insertLine(text,count-1);
System.out.print((++count)+"> ");
command=s.nextLine();
commandArr = command.split("\\s");
if(commandArr[0].equals("I")||commandArr[0].equals("L")||commandArr[0].equals("D")||comm
andArr[0].equals("E"))
{
flag=1;
break;
}
else
{
flag=2;
text=command;
}
}
}
else if(commandArr[0].equals("L")) //Listing
{
printList();
}
else if(commandArr[0].equals("D")) //Deletion
{
if(commandArr.length==1)
{
deleteLine(count-1,count-1);
}
else if(commandArr.length==2)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[1])-1);
}
else if(commandArr.length==3)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[2])-1);
}
count=lines.size();
}
if(flag!=1)
{
System.out.print((count++)+"> ");
command = s.nextLine();
}
}
}
public static void insertLine(String text,int count)
{
if (count >= lines.size()) {
for(int i = lines.size(); i <= count; i++) {
lines.add(null);
}
}
lines.set(count,text);
}
public static void deleteLine(int start,int end)
{
for(int i=start;i<=end;i++)
lines.remove(i);
}
public static void printList()
{
for(int i=0;i "+lines.get(i));
}
}.
import java.io.BufferedReader;import java.io.BufferedWriter;.docx
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.StringTokenizer;
/**
* Read a .dat file and reverse it.
* CPS 350
*/
public class Reverse {
public static void main(String[]args) {
if (args.length != 3) {
System.err.println(" Incorrect number of arguments");
System.err.println(" Usage: ");
System.err.
println("\tjava Reverse <stack type> <input file> <output file>");
System.exit(1);
}
boolean useList = true;
if (args[0].compareTo("list")==0)
useList = true;
else if (args[0].compareTo("array")==0)
useList = false;
else {
System.err.println("\tSaw "+args[0]+" instead of list or array as first argument");
System.exit(1);
}
try {
//
// Set up the input file to read, and the output file to write to
//
BufferedReader fileIn =
new BufferedReader(new FileReader(args[1]));
PrintWriter fileOut =
new PrintWriter(new
BufferedWriter(new FileWriter(args[2])));
//
// Read the first line of the .dat file to get sample rate.
// We want to store the sample rate value in a variable,
// but we can ignore the "; Sample Rate" part of the line.
// Step through the first line one token (word) at a time
// using the StringTokenizer. The fourth token is the one
// we want (the sample rate).
//
StringTokenizer str;
String oneLine;
int sampleRate;
String strJunk;
oneLine = fileIn.readLine();
str = new StringTokenizer(oneLine);
strJunk = str.nextToken(); // Read in semicolon
strJunk = str.nextToken(); // Read in "Sample"
strJunk = str.nextToken(); // Read in "Rate"
// Read in sample rate
sampleRate = Integer.parseInt(str.nextToken());
//
// Read in the remainder of the file on line at a time.
// The values in the first column are thrown away.
// Place values from the second column on the stack.
// Stop reading if we reach the end of the file.
//
DStack s;
if (useList)
s = new ListStack();
else
s = new ArrayStack();
String timestep;
double data;
int count = 0;
while ((oneLine = fileIn.readLine()) != null) {
if (oneLine.charAt(0) == ';') {
continue;
}
str = new StringTokenizer(oneLine);
// Read in time step value from first col.
Complete the following Java code such that it opens a file named Fruit.docx
Complete the following Java code such that it opens a file named FruitList.txt, reads the first line from the file, and then prints the first line on console screen. Your Java code should handle possible exception(s). Assume that the file contains the name of a fruit in each line. You don\'t need to provide comments.
// complete import statement(s) here
public class FileRead
{
public static void main(String[] args)
{
// complete the code here
}
}
Solution
import java.io.File;
import java.util.Scanner;
/**
* @author
*
*/
public class FileRead {
/**
* @param args
*/
public static void main(String[] args) {
// complete the code here
Scanner scanner = null;
try {
File file = new File(\"FruitList.txt\");
scanner = new Scanner(file);
// checks the file contains data
if (scanner.hasNext()) {
// prints first line
System.out.println(scanner.nextLine());
}
} catch (Exception e) {
// TODO: handle exception
}
}
}
FruitList.txt
Apple
Orange
Papaya
Banana
Jack Fruit
Watermelon
KIWI
Grapes
Mango
Pineapple
OUTPUT:
Apple
.
In java , I want you to implement a Data Structure known as a Doubly.pdf
In java , I want you to implement a Data Structure known as a Doubly-Ended-Queue. it is a
“fair” data structure in that it implements a FIFO (First In First Out ) behavior. As such, it is
often used to implement various wait lists in computer systems. For example, jobs waiting to use
the CPU, jobs waiting for a printer, jobs waiting to be placed into RAM for execution. In short,
whenever we want a fair strategy for waiting we use queues.
A DEQUE (Doubly-ended-queue) is a related data structure. Although similar to a Queue, it
differs in that it allows for insertions AND deletions from either end of the list (both the front
and the rear).
Your implementation MUST use a doubly-linked-list implementation. You may not use a static
array implementation.
Thus, a Deque is a List but it is one which only concerns itself with the first and last positions for
any insertion or deletion. The 6 operations supported are :
public void insertFront( int item ) - insert the given item (as a node) into the first position of the
Deque.
public void insertRear( int item ) - insert the given item (as a node) into the last position of the
Deque.
public int deleteFront( ) - delete and return the element stored in the first node of the Deque.
public int deletRear( ) – delete and return the element stored in the last node of the Deque.
public boolean isempty( ) - returns true if the Deque is currently empty or false if it is not.
public void printDeque( ) - print the integers from the list, one per line, from the first element
through to the last in order.
Classes
Your program must implement the following 3 classes. public class dequeDriver
This class will contain your program’s main method. It will need to declare a deque object and
process input as indicated below.
Your program should prompt the user for the path of an input file. It should open the file for
input and process it line by line. Each line of the input file will have one of the following forms.
PR
IF
IR
DF
DR
The meanings of each input is as follows:
PR - print the current contents of the deque from front to rear using the printDeque( ) method of
the deque object.
IF - insert the given int value into the front of the deque.
IR - insert the given int value into the rear of the deque.
DF - delete the front value from the deque.
DR – delete the rear element of the deque.
Below is an example input file that your program should be able to process.
PR
IF 4
IF 5
IF 6
IR 7
PR
DR
PR
DF
PR
The output for the input file shown above is :
EMPTY DEQUE
----- Front -----
6
5
4
7
----- Rear -----
----- Front -----
6
5
4
----- Rear -----
----- Front -----
5
4
----- Rear -----
public class dequeNode
This class will implement the linked nodes that will be used to implement the deque itself.
It should have the following protected data members.
protected dequeNode next; // next pointer to next node
protected dequeNode prev; // previous pointer to previous node
protected int val; // the integer value stored within the dequeNod.
I can not get my code to comply it gets mad that I have run declare mo.docx
I can not get my code to comply it gets mad that I have run declare more than once. Please help me figure out how to get this to work
package projectOne;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
import java.util.*;
import java.io.*;
public class Main
{ public static void main(String[] pArgs){
Main mainObject = new Main();
mainObject.run();
} private void run() {
public FileReader readFile() throws FileNotFoundException {
FileReader file = new FileReader(\"p01-in.txt\");
return file;
}
public ArrayList<Integer> getData(FileReader file) throws FileNotFoundException {
Scanner data_read = new Scanner(new BufferedReader(file));
ArrayList<Integer> data = new ArrayList<Integer>();
while (data_read.hasNext()) {
int item = data_read.nextInt();
data.add(item);
}
return data;
}
public ArrayList<Integer> calcRuns(ArrayList<Integer> data) {
ArrayList<Integer> runs = new ArrayList<Integer>();
Iterator<Integer> i_data = data.iterator();
int run = 0;
int temp = i_data.next();
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp < t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
i_data = data.iterator();
temp = i_data.next();
run = 0;
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp > t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
return runs;
}
public void writeOutput(ArrayList<Integer> runs) throws IOException {
PrintWriter out = new PrintWriter(new File(\"p01-runs.txt\"));
ArrayList<Integer> run_count = new ArrayList<Integer>();
int i = 0;
int r_count = Collections.frequency(run_count, i);
while (i < 100) {
run_count.add(r_count);
i++;
r_count = Collections.frequency(runs, i);
}
Iterator<Integer> i_runs = run_count.iterator();
i = 0;
while (i_runs.hasNext()) {
int run = i_runs.next();
String line = \"run_\" + i + \" ,\" + run;
i++;
out.println(line);
}
}
public void run() throws Exception {
FileReader fin = this.readFile();
ArrayList<Integer> data = this.getData(fin);
ArrayList<Integer> runs = this.calcRuns(data);
this.writeOutput(runs);
}
}
Solution
In your program you have to change the syntax errors at method declaration.so your not getting output.
.
Write a java program that compute the frequency of each word in the fi.docx
Write a java program that compute the frequency of each word in the file
Task: Implementing Word Counter Problem description: Given a text file, you need to compute the frequency of each word in the file. WordFrequency word: String count: int +WordFrequency(String) +getWord): String +getCount): int +incCount): void TestClass +static main(String[): void / /implements ArrayList of // WordFrequency The WordFrequency class stores the frequency (count) of each word.
Solution
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
class FileIO {
public static void main (String[] args) throws IOException {
readTextFileInBinaryMode (\"T.txt\");
}
public static void readTextFileInBinaryMode (String fileName) {
FileReader fileReader = null;
LinkedHashMap <String, Integer> wordcount =
new LinkedHashMap <String, Integer> ();
try {
File file = new File (fileName);
fileReader = new FileReader (file);
int ch = -1;
boolean prevCharIsNotSpace = true;
StringBuilder strBuild = new StringBuilder ();
while ((ch = fileReader.read ()) != -1) {
if (ch == 32) {
if (prevCharIsNotSpace) {
Integer freq = wordcount.get (strBuild.toString ());
wordcount.put (strBuild.toString (), (freq == null ? : freq + 1));
}
prevCharIsNotSpace = false;
continue;
}
if (prevCharIsNotSpace == false)
strBuild = new StringBuilder ();
strBuild.append ((char) ch);
prevCharIsNotSpace = true;
}
}
catch (Exception e) {
System.out.println(\"Exception occurs\"+e.getException());
}
//sorting
List <Map.Entry <String, Integer>> list =
new ArrayList <Map.Entry <String, Integer>> ();
for (Map.Entry <String, Integer> entry : wordcount.entrySet ()) {
System.out.println (entry.getKey () + \" \" + entry.getValue ());
list.add (entry);
}
Collections.sort (list, new MapComprator ());
for (Map.Entry <String, Integer> entry : list) {
System.out.println (entry.getKey () + \" \" + entry.getValue ());
}
}
}
class MapComprator implements Comparator <Map.Entry <String, Integer>> {
public int compare (Entry <String, Integer> o1, Entry <String, Integer> o2) {
return (o2.getValue ().compareTo (o1.getValue ()));
}
}
.
JAVAWrite a program that takes a command-line argument representin.pdf
JAVA
Write a program that takes a command-line argument representing a text file name. The program
should read the given text file and print two lists, each in ascending order. One list should be the
words that exist only once in the text file. The other list should be the words that appear more
than once. Ignore the case of the words when determining whether a word has appeared more
than once. Your program may ignore punctuation.
Solution
//CountOccurrenceOfWords.java
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.Map;
import java.util.Set;
import java.util.TreeMap;
import java.util.ArrayList;
import java.util.*;
public class CountOccurrenceOfWords
{
public static void main(String[] file) throws FileNotFoundException, IOException
{
if (file.length == 0)
{
System.out.println(\"Usage: java CountOccurrenceOfWords targetfile\");
System.exit(0);
}
BufferedReader br = null;
br = new BufferedReader(new FileReader(file[0]));
String text = null;
TreeMap treemap = new TreeMap();
try
{
while ((text = br.readLine()) != null)
{
String[] line = text.split(\"[ \ \\t\ .,;:!?(){}]\");
for (int count = 0; count < line.length; count++)
{
String key = line[count].toLowerCase();
if (key.length() > 0)
{
if (treemap.get(key) == null)
{
treemap.put(key, 1);
}
else
{
int value = treemap.get(key).intValue();
value++;
treemap.put(key, value);
}
}
}
}
Set> entrySet = treemap.entrySet();
// create an empty array list with an initial capacity
ArrayList list1 = new ArrayList(100);
ArrayList list2 = new ArrayList(100);
for (Map.Entry entry : entrySet)
{
if(entry.getValue() == 1 ) list1.add(entry.getKey());
else list2.add(entry.getKey());
}
System.out.print(\"Words that appear \" + \"one \"+ \"time are: \");
for (String word : list1)
{
System.out.print(word + \", \");
}
System.out.println(\"\ \");
System.out.print(\"Words that appear more than one time are: \");
for (String word : list2)
{
System.out.print(word + \", \");
}
System.out.println(\"\ \");
}
catch (IOException error)
{
System.out.println(\"Invalid File\");
}
finally
{
br.close();
}
}
}
/*
words.txt
Sophie Sally and Jack were dachshunds
Dachshunds are the best dogs and all dogs
are better than cats
output:
Words that appear one time are: all, best, better, cats, jack, sally, sophie, than, the, were,
Words that appear more than one time are: and, are, dachshunds, dogs,
*/.
Compare and contrast the advantages and disadvantages of arrays and .pdf
Compare and contrast the advantages and disadvantages of arrays and linked lists. Give an
example problem that is best accomplished by an array. Give an example problem that is best
accomplished with an array.
access directly with array while linked list take some time to access data. However, list can insert
easily the value into middle of list while array needs to increase the capacity and copy behind
part and fore part and input. Array\'s size is fixed while linked list has flexible size.
Stack or queue is well match with linked list because if push and pop from the end point of data
structure.
array is good with when program needs random access.
Solution
Ex: 1,2,3,4,5 to be stored in array
a[0]=1, a[1]=2 etc..
in LL we have to create space for 1 and store the address next to it as null. next when we want to
insert 2 we have to create address for 2 and store that address in pointer of 1. and so on==> 1->2-
>3->4->5.
Initiallly array size is to be definrd, but ll size can grown dynamicallyArrayLinked
ListCollections of elements with same data typeOrdered collection of data conecting by
linksArray elements are stored continuosly in memorystored in the space available and are
linkedcan have random acessbut here it will be sequential accesstakes more time for insertion
and deletion because we are storing continuosly in the memoryit takes more time here as the
value of the link needs to changed onlyIt is static memory allocation as we have to decide
beforeDynamic we have to create space for each value storedCan be 1D 2D and 3DSingular,
Doubly, circularelement is independent because we do not have connection with previous
memory locationaddress of the element is stored in the link partneed extra space for pointerneed
extra space for pointer.
Answer and describe the following five plants habit, habitat, life .pdf
Answer and describe the following five plants: habit, habitat, life span, throns, spines or prickles,
infloresences, leaves (complexity, attachment to stem, arrangement, blade shape, margin, apex,
base, venation and trichomes). Other interesting facts.
1. Isomeris arboea (Bladderpod) - Drought tolerant plant
2. Sinningia macrostachya
3. Ceropegia dichotoma
4. Lilium longiflorum
5. Peperomia verticiliata
Solution
I. Isomeris arboea
Also known as Bladderpod, Burrofat and California cleome.This plant is a fast-growing
evergreen dicot shrub from the family Capparaceae. It is a dense shrub with profuse branching
and small hairs/trichomes. It normally grows in well-draining rocky areas with good exposure to
sunlight. It is found in Southern Sierra Nevada Foothills, Tehachapi Mountain area, San Joaquin
Valley,Central Coast, South Coast, Channel Islands, Deserts, and Baja,CA
Habitat - Coastal bluffs, hills, desert washes, flats below 3,900\'
Height by Width: 3-4\' H x 4\' W
Stems - profusely branched; glabrate or puberulent (bark corky, twigs smooth)
inflorescence: The plant produces abundant inflorescences at the ends of the stem branches, each
a cluster of bright yellow flowers. Each flower has usually four petals and six whiskery
protruding stamens with curling tips holding the anthers. The fruit is an inflated capsule about 4
centimeters long and usually oval in shape. It is smooth and green when new, aging to light
brown. Fruits when dry, resemble a paper lantern that rattles (the seeds inside the dried fruit
rattle around). The flowers are dense terminal racemes. The calyx is four-cleft and the sepals are
fused in the basal half. It has four petals ½” long, 6 yellow stamens that are long and a pistil with
a short style. Sepals persistent, connate ca. 1/2 of length, green, lanceolate, 4–7 × 2.2–4 mm,
margins entire, glabrous; petals yellow, ovate-elliptic, 8–14 × 4.2–5 mm, (apex acute); stamens
yellow, 15–25 mm; anthers 2–2.5 mm; gynophore (reflexed), 10–20 mm in fruit; ovary 3–6 mm
(often aborting in bud); style 0.9–1.2 mm. Capsules (tardily dehiscent), usually inflated ,(valves
sometimes 3), 20–30 × 6–12 mm, smooth. Seeds 5–25, dark brown, obovoid, 6–7 × 5–6 mm,
smooth.
Leaves: Its leaves are made up of three equal leaflike leaflets, each a long, pointed oval 1-4 cm
long. The leaves are alternate, entire, petiolate and trifoliate with leaflets that are oblong-elliptic
with small pointed tips. petiole 1–3 cm; leaflets 3, blade oblong-elliptic, 1.5–4.5 × 0.4–1.3 cm,
margins serrate, apex acuminate to obtuse, surfaces glaucous. Racemes 1–3 cm (6–40 cm in
fruit); bracts unifoliate, obovate to spatulate, 2–15 mm. Pedicels 7–15 mm (thickened in fruit).
extra information:
II. Sinningia macrostachya
Family: Gesneriaceae
Popular names – leather leaf, Gloxinia
Sinningia macrostachya has a perennial stem base, very stiff leaves, and numerous small orange
flowers. Its fleshy stems are joined to the woody trunk. Each year, the woody part of the stems
exten.
More Related Content
Similar to Write a program in Java that reads a set of doubles from a file, sto.pdf
import java.io.BufferedReader;import java.io.File;import java.io.pdf
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class FileEdit {
public static List lines = new ArrayList();
public static void main(String[] args) throws IOException
{
Scanner s = new Scanner(System.in);
System.out.print("EDIT: ");
String fileName = s.nextLine();
BufferedReader br = new BufferedReader(new FileReader(new File(fileName)));
String str="";
int count=0;
while((str=br.readLine())!=null)
{
lines.add(count, str);
System.out.println((++count) + "> "+ str);
}
String text="";
String command = "";
System.out.print((++count)+"> ");
command=s.nextLine();
String commandArr[];
int flag;
while(!command.equals("E"))
{
flag=0;
commandArr = command.split("\\s");
if(commandArr[0].equals("I")) //Insertion
{
while(true)
{
if(commandArr.length==1&&flag!=2)
{
System.out.print((count)+"> ");
text = s.nextLine();
insertLine(text,count-1);
}
else if(commandArr.length==2&&flag!=2)
{
System.out.print((commandArr[1])+"> ");
count=Integer.parseInt(commandArr[1]);
text = s.nextLine();
insertLine(text,Integer.parseInt(commandArr[1])-1);
}
else
insertLine(text,count-1);
System.out.print((++count)+"> ");
command=s.nextLine();
commandArr = command.split("\\s");
if(commandArr[0].equals("I")||commandArr[0].equals("L")||commandArr[0].equals("D")||comm
andArr[0].equals("E"))
{
flag=1;
break;
}
else
{
flag=2;
text=command;
}
}
}
else if(commandArr[0].equals("L")) //Listing
{
printList();
}
else if(commandArr[0].equals("D")) //Deletion
{
if(commandArr.length==1)
{
deleteLine(count-1,count-1);
}
else if(commandArr.length==2)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[1])-1);
}
else if(commandArr.length==3)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[2])-1);
}
count=lines.size();
}
if(flag!=1)
{
System.out.print((count++)+"> ");
command = s.nextLine();
}
}
}
public static void insertLine(String text,int count)
{
if (count >= lines.size()) {
for(int i = lines.size(); i <= count; i++) {
lines.add(null);
}
}
lines.set(count,text);
}
public static void deleteLine(int start,int end)
{
for(int i=start;i<=end;i++)
lines.remove(i);
}
public static void printList()
{
for(int i=0;i "+lines.get(i));
}
}
Here is my output:
EDIT: textin.txt
1> The First Line
1>
2> And another line
3> I 3
3> The second line
4> One more line
5> L
1> null
2> null
3> The second line
4> One more line
5> D 2
3> L
1> null
2> The second line
3> One more line
4> E
How can I keep it from printing "null" after ">" and it just be blank. I need the output to look like
this:
1> The first line
2>
3> And another line
4> I 3
3> The second line
4> One more line
5> L
1> The first line
2>
3> The second line
4> One more line
5> And another line
5> D 2
4> L
1> The first line
2> The second line
3> One more line
4> And another line
5> E.
Write a program that will count the number of characters- words- and l.docx
Write a program that will count the number of characters, words, and lines in a file. Words are separated by whitespace characters. The file name should be passed as a command-line argument, as shown;
c:\\exercise>java Exercise12_13 Loan.java
File Loan.java has
1919 characters
210 words
71 lines
c:\\exercise>
Solution
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
import java.util.StringTokenizer;
public class ass1
{
public static void main(String[] args) throws FileNotFoundException
{
//Â Â Scanner console = new Scanner(System.in);
System.out.println(args[0]);
//System.out.println(args[1]);
//System.out.println(args[2]);
String inputFile=args[0];
File file = new File(inputFile);
Scanner in = new Scanner(file);
int words = 0;
int lines = 0;
int chars = 0;
while(in.hasNextLine()) {
lines++;
String line = in.nextLine();
chars += line.length();
words += new StringTokenizer(line, \" \").countTokens();
}
System.out.println(\"characters are \"+chars);
System.out.println(\"words are \"+words);
System.out.println(\"lines are \"+lines);
}
}
.
Here is my code for a linefile editor import java.io.BufferedRea.pdf
Here is my code for a line/file editor:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class FileEdit {
public static List lines = new ArrayList();
public static void main(String[] args) throws IOException
{
Scanner s = new Scanner(System.in);
System.out.print("EDIT: ");
String fileName = s.nextLine();
BufferedReader br = new BufferedReader(new FileReader(new File(fileName)));
String str="";
int count=0;
while((str=br.readLine())!=null)
{
lines.add(count, str);
System.out.println((++count) + "> "+ str);
}
String text="";
String command = "";
System.out.print((++count)+"> ");
command=s.nextLine();
String commandArr[];
int flag;
while(!command.equals("E"))
{
flag=0;
commandArr = command.split("\\s");
if(commandArr[0].equals("I")) //Insertion
{
while(true)
{
if(commandArr.length==1&&flag!=2)
{
System.out.print((count)+"> ");
text = s.nextLine();
insertLine(text,count-1);
}
else if(commandArr.length==2&&flag!=2)
{
System.out.print((commandArr[1])+"> ");
count=Integer.parseInt(commandArr[1]);
text = s.nextLine();
insertLine(text,Integer.parseInt(commandArr[1])-1);
}
else
insertLine(text,count-1);
System.out.print((++count)+"> ");
command=s.nextLine();
commandArr = command.split("\\s");
if(commandArr[0].equals("I")||commandArr[0].equals("L")||commandArr[0].equals("D")||comm
andArr[0].equals("E"))
{
flag=1;
break;
}
else
{
flag=2;
text=command;
}
}
}
else if(commandArr[0].equals("L")) //Listing
{
printList();
}
else if(commandArr[0].equals("D")) //Deletion
{
if(commandArr.length==1)
{
deleteLine(count-1,count-1);
}
else if(commandArr.length==2)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[1])-1);
}
else if(commandArr.length==3)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[2])-1);
}
count=lines.size();
}
if(flag!=1)
{
System.out.print((count++)+"> ");
command = s.nextLine();
}
}
}
public static void insertLine(String text,int count)
{
if (count >= lines.size()) {
for(int i = lines.size(); i <= count; i++) {
lines.add(null);
}
}
lines.set(count,text);
}
public static void deleteLine(int start,int end)
{
for(int i=start;i<=end;i++)
lines.remove(i);
}
public static void printList()
{
for(int i=0;i "+lines.get(i));
}
}
Here is my output:
EDIT: textin.txt
1> The First Line
1>
2> And another line
3> I 3
3> The second line
4> One more line
5> L
1> null
2> null
3> The second line
4> One more line
5> D 2
3> L
1> null
2> The second line
3> One more line
4> E
How can I keep it from printing "null" after ">" and it just be blank. I need the output to look like
this:
1> The first line
2>
3> And another line
4> I 3
3> The second line
4> One more line
5> L
1> The first line
2>
3> The second line
4> One more line
5> And another line
5> D 2
4> L
1> The first line
2> The second line
3> One more line
4> And another line
5> E.
Create a text file named lnfo.txt. Enter the following informatio.pdf
Create a text file named \"lnfo.txt\". Enter the following information using Linked List (any
method). Name rightarrow String Address rightarrow String Phone rightarrow String There
should be continues loop which will ask the above information and write down in the TEXT File.
When user inputs Exit in Name Field then program should be ended.
Solution
package sample;
import java.io.*;
public class ReadWrite {
public static void main(String[] args) {
BufferedReader reader = null;
try {
reader = new BufferedReader(new InputStreamReader(System.in));
File file = new File(\"C:\\\\Temp\\\\Info.txt\");
// creates the file
file.createNewFile();
// creates a FileWriter Object
FileWriter writer = new FileWriter(file);
while (true) {
System.out.print(\"Enter Name : \");
String name = reader.readLine();
if (\"Exit\".equals(name)) {
System.out.println(\"Exit!\");
writer.flush();
writer.close();
System.exit(0);
}
System.out.print(\"Enter Address : \");
String address = reader.readLine();
System.out.print(\"Enter Phone : \");
String phone = reader.readLine();
// Writes the content to the file
writer.write(\"\ \ -----------\");
writer.write(\"\ Name : \"+name);
writer.write(\"\ Address : \"+address);
writer.write(\"\ Phone : \"+phone);
writer.write(\"\ -----------\");
System.out.println(\"Added Below Record Successfully \");
System.out.println(\"-----------\ \");
System.out.println(\"Name : \"+name);
System.out.println(\"Address : \"+address);
System.out.println(\"Phone : \"+phone);
System.out.println(\"-----------\ \");
}
} catch (IOException ex) {
ex.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
}
}
package sample;
import java.io.*;
public class ReadWrite {
public static void main(String[] args) {
BufferedReader reader = null;
try {
reader = new BufferedReader(new InputStreamReader(System.in));
File file = new File(\"C:\\\\Temp\\\\Info.txt\");
// creates the file
file.createNewFile();
// creates a FileWriter Object
FileWriter writer = new FileWriter(file);
while (true) {
System.out.print(\"Enter Name : \");
String name = reader.readLine();
if (\"Exit\".equals(name)) {
System.out.println(\"Exit!\");
writer.flush();
writer.close();
System.exit(0);
}
System.out.print(\"Enter Address : \");
String address = reader.readLine();
System.out.print(\"Enter Phone : \");
String phone = reader.readLine();
// Writes the content to the file
writer.write(\"\ \ -----------\");
writer.write(\"\ Name : \"+name);
writer.write(\"\ Address : \"+address);
writer.write(\"\ Phone : \"+phone);
writer.write(\"\ -----------\");
System.out.println(\"Added Below Record Successfully \");
System.out.println(\"-----------\ \");
System.out.println(\"Name : \"+name);
System.out.println(\"Address : \"+address);
System.out.println(\"Phone : \"+phone);
System.out.println(\"-----------\ \");
}
} catch (IOException ex) {
ex.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOExcept.
Write a java program that allows the user to input the name of a fil.docx
Write a java program that allows the user to input the name of a fil
Write a java program that allows the user to input the name of a file.docx
Write a java program that allows the user to input the name of a file that contains positive integers (one integer per line) The number of integers in the file The program should find all odd and even numbers and write the odd numbers to a file \"odd.txt\" and write the even numbers to another file \"even.txt\"
Solution
package expertques;
import java.io.File;
import java.io.PrintWriter;
import java.util.Scanner;
public class evenoddwithfile {
public static void main(String[] args) throws Exception {
File in;//file input
File even = new File(\"f://even.txt\");//creates file even
File odd = new File(\"f://odd.txt\");//creates file odd
Scanner s = new Scanner(System.in);//reads input from console or user
System.out.println(\"Enter the file name with path: \");
in = new File(s.nextLine());
System.out.println(\"Enter the number of integers n the file: \");
int n = s.nextInt();
if (in.exists()) {//checks if input file exist or not
Scanner ins = new Scanner(in);//reads input file
PrintWriter pe = new PrintWriter(even);//write to even file
PrintWriter po = new PrintWriter(odd);//writes to odd file
for (int i = 0; i < n; i++) {//loop till the numbers exists
int x = ins.nextInt();//reads from input file
if (x % 2 == 0) {//checks for even or odd
pe.println(x);//if even writes in even file
} else {
po.println(x);//if odd writes in odd file
}
}
pe.close();//closes even file very important else nothing will be written in the file
po.close();//closes odd file very important else nothing will be written in the file
System.out.println(\"File successfully written with odds and evens\");
} else {
System.out.println(\"Error file not found at specified path\");//if file not exist
}
}
}
output
run:
Enter the file name with path:
f://integers.txt
Enter the number of integers n the file:
8
File successfully written with odds and evens
BUILD SUCCESSFUL (total time: 6 seconds)
.
Write a Java program that opens the file, reads all the Grade from t.pdf
Write a Java program that opens the file, reads all the Grade from the file, and using a method
calculates and displays the following A) Displays the grades with their letter values (80 - B) B)
the sum of the Grades in the file C) the average of the Grades in the file
Solution
GradeRead.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class GradeRead {
public static void main(String[] args) throws FileNotFoundException {
Scanner scan1 = new Scanner(System.in);
System.out.print(\"Enter the file name: \");
String fileName = scan1.next();
File file = new File(fileName);
if(file.exists()){
Scanner scan = new Scanner(file);
calculateGradeDetail(scan);
}
else{
System.out.println(\"Input does not exist\");
}
}
public static void calculateGradeDetail(Scanner scan){
int sum = 0;
int count = 0;
char gradeLetter = \'\\0\';
while(scan.hasNextInt()){
count++;
int n = scan.nextInt();
sum = sum + n;
if(n >=90 && n<=100){
gradeLetter = \'A\';
}
else if(n >=80 && n<90){
gradeLetter = \'B\';
}
else if(n >=70 && n<80){
gradeLetter = \'C\';
}
else if(n >=60 && n<=70){
gradeLetter = \'D\';
}
else {
gradeLetter = \'E\';
}
System.out.println(\"Grade: \"+gradeLetter+\" - \"+n);
}
System.out.println(\"The sum of the Grades in the file: \"+sum);
double average = sum/(double)count;
System.out.println(\"the average of the Grades in the file: \"+average);
System.out.println();
}
}
Output:
Enter the file name: D:\\\\grade.txt
Grade: D - 60
Grade: C - 70
Grade: B - 80
Grade: A - 90
Grade: A - 100
Grade: E - 40
Grade: E - 50
Grade: D - 60
The sum of the Grades in the file: 550
the average of the Grades in the file: 68.75
Grade.txt
60
70
80
90
100
40
50
60.
Please help me with a UML class diagram for the following code im.pdf
Please help me with a UML class diagram for the following code:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class FileEdit {
public static List lines = new ArrayList();
public static void main(String[] args) throws IOException
{
Scanner s = new Scanner(System.in);
System.out.print("EDIT: ");
String fileName = s.nextLine();
BufferedReader br = new BufferedReader(new FileReader(new File(fileName)));
String str="";
int count=0;
while((str=br.readLine())!=null)
{
lines.add(count, str);
System.out.println((++count) + "> "+ str);
}
String text="";
String command = "";
System.out.print((++count)+"> ");
command=s.nextLine();
String commandArr[];
int flag;
while(!command.equals("E"))
{
flag=0;
commandArr = command.split("\\s");
if(commandArr[0].equals("I")) //Insertion
{
while(true)
{
if(commandArr.length==1&&flag!=2)
{
System.out.print((count)+"> ");
text = s.nextLine();
insertLine(text,count-1);
}
else if(commandArr.length==2&&flag!=2)
{
System.out.print((commandArr[1])+"> ");
count=Integer.parseInt(commandArr[1]);
text = s.nextLine();
insertLine(text,Integer.parseInt(commandArr[1])-1);
}
else
insertLine(text,count-1);
System.out.print((++count)+"> ");
command=s.nextLine();
commandArr = command.split("\\s");
if(commandArr[0].equals("I")||commandArr[0].equals("L")||commandArr[0].equals("D")||comm
andArr[0].equals("E"))
{
flag=1;
break;
}
else
{
flag=2;
text=command;
}
}
}
else if(commandArr[0].equals("L")) //Listing
{
printList();
}
else if(commandArr[0].equals("D")) //Deletion
{
if(commandArr.length==1)
{
deleteLine(count-1,count-1);
}
else if(commandArr.length==2)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[1])-1);
}
else if(commandArr.length==3)
{
deleteLine(Integer.parseInt(commandArr[1])-1,Integer.parseInt(commandArr[2])-1);
}
count=lines.size();
}
if(flag!=1)
{
System.out.print((count++)+"> ");
command = s.nextLine();
}
}
}
public static void insertLine(String text,int count)
{
if (count >= lines.size()) {
for(int i = lines.size(); i <= count; i++) {
lines.add(null);
}
}
lines.set(count,text);
}
public static void deleteLine(int start,int end)
{
for(int i=start;i<=end;i++)
lines.remove(i);
}
public static void printList()
{
for(int i=0;i "+lines.get(i));
}
}.
import java.io.BufferedReader;import java.io.BufferedWriter;.docx
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.StringTokenizer;
/**
* Read a .dat file and reverse it.
* CPS 350
*/
public class Reverse {
public static void main(String[]args) {
if (args.length != 3) {
System.err.println(" Incorrect number of arguments");
System.err.println(" Usage: ");
System.err.
println("\tjava Reverse <stack type> <input file> <output file>");
System.exit(1);
}
boolean useList = true;
if (args[0].compareTo("list")==0)
useList = true;
else if (args[0].compareTo("array")==0)
useList = false;
else {
System.err.println("\tSaw "+args[0]+" instead of list or array as first argument");
System.exit(1);
}
try {
//
// Set up the input file to read, and the output file to write to
//
BufferedReader fileIn =
new BufferedReader(new FileReader(args[1]));
PrintWriter fileOut =
new PrintWriter(new
BufferedWriter(new FileWriter(args[2])));
//
// Read the first line of the .dat file to get sample rate.
// We want to store the sample rate value in a variable,
// but we can ignore the "; Sample Rate" part of the line.
// Step through the first line one token (word) at a time
// using the StringTokenizer. The fourth token is the one
// we want (the sample rate).
//
StringTokenizer str;
String oneLine;
int sampleRate;
String strJunk;
oneLine = fileIn.readLine();
str = new StringTokenizer(oneLine);
strJunk = str.nextToken(); // Read in semicolon
strJunk = str.nextToken(); // Read in "Sample"
strJunk = str.nextToken(); // Read in "Rate"
// Read in sample rate
sampleRate = Integer.parseInt(str.nextToken());
//
// Read in the remainder of the file on line at a time.
// The values in the first column are thrown away.
// Place values from the second column on the stack.
// Stop reading if we reach the end of the file.
//
DStack s;
if (useList)
s = new ListStack();
else
s = new ArrayStack();
String timestep;
double data;
int count = 0;
while ((oneLine = fileIn.readLine()) != null) {
if (oneLine.charAt(0) == ';') {
continue;
}
str = new StringTokenizer(oneLine);
// Read in time step value from first col.
Complete the following Java code such that it opens a file named Fruit.docx
Complete the following Java code such that it opens a file named FruitList.txt, reads the first line from the file, and then prints the first line on console screen. Your Java code should handle possible exception(s). Assume that the file contains the name of a fruit in each line. You don\'t need to provide comments.
// complete import statement(s) here
public class FileRead
{
public static void main(String[] args)
{
// complete the code here
}
}
Solution
import java.io.File;
import java.util.Scanner;
/**
* @author
*
*/
public class FileRead {
/**
* @param args
*/
public static void main(String[] args) {
// complete the code here
Scanner scanner = null;
try {
File file = new File(\"FruitList.txt\");
scanner = new Scanner(file);
// checks the file contains data
if (scanner.hasNext()) {
// prints first line
System.out.println(scanner.nextLine());
}
} catch (Exception e) {
// TODO: handle exception
}
}
}
FruitList.txt
Apple
Orange
Papaya
Banana
Jack Fruit
Watermelon
KIWI
Grapes
Mango
Pineapple
OUTPUT:
Apple
.
In java , I want you to implement a Data Structure known as a Doubly.pdf
In java , I want you to implement a Data Structure known as a Doubly-Ended-Queue. it is a
“fair” data structure in that it implements a FIFO (First In First Out ) behavior. As such, it is
often used to implement various wait lists in computer systems. For example, jobs waiting to use
the CPU, jobs waiting for a printer, jobs waiting to be placed into RAM for execution. In short,
whenever we want a fair strategy for waiting we use queues.
A DEQUE (Doubly-ended-queue) is a related data structure. Although similar to a Queue, it
differs in that it allows for insertions AND deletions from either end of the list (both the front
and the rear).
Your implementation MUST use a doubly-linked-list implementation. You may not use a static
array implementation.
Thus, a Deque is a List but it is one which only concerns itself with the first and last positions for
any insertion or deletion. The 6 operations supported are :
public void insertFront( int item ) - insert the given item (as a node) into the first position of the
Deque.
public void insertRear( int item ) - insert the given item (as a node) into the last position of the
Deque.
public int deleteFront( ) - delete and return the element stored in the first node of the Deque.
public int deletRear( ) – delete and return the element stored in the last node of the Deque.
public boolean isempty( ) - returns true if the Deque is currently empty or false if it is not.
public void printDeque( ) - print the integers from the list, one per line, from the first element
through to the last in order.
Classes
Your program must implement the following 3 classes. public class dequeDriver
This class will contain your program’s main method. It will need to declare a deque object and
process input as indicated below.
Your program should prompt the user for the path of an input file. It should open the file for
input and process it line by line. Each line of the input file will have one of the following forms.
PR
IF
IR
DF
DR
The meanings of each input is as follows:
PR - print the current contents of the deque from front to rear using the printDeque( ) method of
the deque object.
IF - insert the given int value into the front of the deque.
IR - insert the given int value into the rear of the deque.
DF - delete the front value from the deque.
DR – delete the rear element of the deque.
Below is an example input file that your program should be able to process.
PR
IF 4
IF 5
IF 6
IR 7
PR
DR
PR
DF
PR
The output for the input file shown above is :
EMPTY DEQUE
----- Front -----
6
5
4
7
----- Rear -----
----- Front -----
6
5
4
----- Rear -----
----- Front -----
5
4
----- Rear -----
public class dequeNode
This class will implement the linked nodes that will be used to implement the deque itself.
It should have the following protected data members.
protected dequeNode next; // next pointer to next node
protected dequeNode prev; // previous pointer to previous node
protected int val; // the integer value stored within the dequeNod.
I can not get my code to comply it gets mad that I have run declare mo.docx
I can not get my code to comply it gets mad that I have run declare more than once. Please help me figure out how to get this to work
package projectOne;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
import java.util.*;
import java.io.*;
public class Main
{ public static void main(String[] pArgs){
Main mainObject = new Main();
mainObject.run();
} private void run() {
public FileReader readFile() throws FileNotFoundException {
FileReader file = new FileReader(\"p01-in.txt\");
return file;
}
public ArrayList<Integer> getData(FileReader file) throws FileNotFoundException {
Scanner data_read = new Scanner(new BufferedReader(file));
ArrayList<Integer> data = new ArrayList<Integer>();
while (data_read.hasNext()) {
int item = data_read.nextInt();
data.add(item);
}
return data;
}
public ArrayList<Integer> calcRuns(ArrayList<Integer> data) {
ArrayList<Integer> runs = new ArrayList<Integer>();
Iterator<Integer> i_data = data.iterator();
int run = 0;
int temp = i_data.next();
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp < t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
i_data = data.iterator();
temp = i_data.next();
run = 0;
while (i_data.hasNext()) {
int t1 = i_data.next();
if (temp > t1)
run++;
else {
runs.add(run);
run = 0;
}
temp = t1;
}
return runs;
}
public void writeOutput(ArrayList<Integer> runs) throws IOException {
PrintWriter out = new PrintWriter(new File(\"p01-runs.txt\"));
ArrayList<Integer> run_count = new ArrayList<Integer>();
int i = 0;
int r_count = Collections.frequency(run_count, i);
while (i < 100) {
run_count.add(r_count);
i++;
r_count = Collections.frequency(runs, i);
}
Iterator<Integer> i_runs = run_count.iterator();
i = 0;
while (i_runs.hasNext()) {
int run = i_runs.next();
String line = \"run_\" + i + \" ,\" + run;
i++;
out.println(line);
}
}
public void run() throws Exception {
FileReader fin = this.readFile();
ArrayList<Integer> data = this.getData(fin);
ArrayList<Integer> runs = this.calcRuns(data);
this.writeOutput(runs);
}
}
Solution
In your program you have to change the syntax errors at method declaration.so your not getting output.
.
Write a java program that compute the frequency of each word in the fi.docx
Write a java program that compute the frequency of each word in the file
Task: Implementing Word Counter Problem description: Given a text file, you need to compute the frequency of each word in the file. WordFrequency word: String count: int +WordFrequency(String) +getWord): String +getCount): int +incCount): void TestClass +static main(String[): void / /implements ArrayList of // WordFrequency The WordFrequency class stores the frequency (count) of each word.
Solution
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
class FileIO {
public static void main (String[] args) throws IOException {
readTextFileInBinaryMode (\"T.txt\");
}
public static void readTextFileInBinaryMode (String fileName) {
FileReader fileReader = null;
LinkedHashMap <String, Integer> wordcount =
new LinkedHashMap <String, Integer> ();
try {
File file = new File (fileName);
fileReader = new FileReader (file);
int ch = -1;
boolean prevCharIsNotSpace = true;
StringBuilder strBuild = new StringBuilder ();
while ((ch = fileReader.read ()) != -1) {
if (ch == 32) {
if (prevCharIsNotSpace) {
Integer freq = wordcount.get (strBuild.toString ());
wordcount.put (strBuild.toString (), (freq == null ? : freq + 1));
}
prevCharIsNotSpace = false;
continue;
}
if (prevCharIsNotSpace == false)
strBuild = new StringBuilder ();
strBuild.append ((char) ch);
prevCharIsNotSpace = true;
}
}
catch (Exception e) {
System.out.println(\"Exception occurs\"+e.getException());
}
//sorting
List <Map.Entry <String, Integer>> list =
new ArrayList <Map.Entry <String, Integer>> ();
for (Map.Entry <String, Integer> entry : wordcount.entrySet ()) {
System.out.println (entry.getKey () + \" \" + entry.getValue ());
list.add (entry);
}
Collections.sort (list, new MapComprator ());
for (Map.Entry <String, Integer> entry : list) {
System.out.println (entry.getKey () + \" \" + entry.getValue ());
}
}
}
class MapComprator implements Comparator <Map.Entry <String, Integer>> {
public int compare (Entry <String, Integer> o1, Entry <String, Integer> o2) {
return (o2.getValue ().compareTo (o1.getValue ()));
}
}
.
JAVAWrite a program that takes a command-line argument representin.pdf
JAVA
Write a program that takes a command-line argument representing a text file name. The program
should read the given text file and print two lists, each in ascending order. One list should be the
words that exist only once in the text file. The other list should be the words that appear more
than once. Ignore the case of the words when determining whether a word has appeared more
than once. Your program may ignore punctuation.
Solution
//CountOccurrenceOfWords.java
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.Map;
import java.util.Set;
import java.util.TreeMap;
import java.util.ArrayList;
import java.util.*;
public class CountOccurrenceOfWords
{
public static void main(String[] file) throws FileNotFoundException, IOException
{
if (file.length == 0)
{
System.out.println(\"Usage: java CountOccurrenceOfWords targetfile\");
System.exit(0);
}
BufferedReader br = null;
br = new BufferedReader(new FileReader(file[0]));
String text = null;
TreeMap treemap = new TreeMap();
try
{
while ((text = br.readLine()) != null)
{
String[] line = text.split(\"[ \ \\t\ .,;:!?(){}]\");
for (int count = 0; count < line.length; count++)
{
String key = line[count].toLowerCase();
if (key.length() > 0)
{
if (treemap.get(key) == null)
{
treemap.put(key, 1);
}
else
{
int value = treemap.get(key).intValue();
value++;
treemap.put(key, value);
}
}
}
}
Set> entrySet = treemap.entrySet();
// create an empty array list with an initial capacity
ArrayList list1 = new ArrayList(100);
ArrayList list2 = new ArrayList(100);
for (Map.Entry entry : entrySet)
{
if(entry.getValue() == 1 ) list1.add(entry.getKey());
else list2.add(entry.getKey());
}
System.out.print(\"Words that appear \" + \"one \"+ \"time are: \");
for (String word : list1)
{
System.out.print(word + \", \");
}
System.out.println(\"\ \");
System.out.print(\"Words that appear more than one time are: \");
for (String word : list2)
{
System.out.print(word + \", \");
}
System.out.println(\"\ \");
}
catch (IOException error)
{
System.out.println(\"Invalid File\");
}
finally
{
br.close();
}
}
}
/*
words.txt
Sophie Sally and Jack were dachshunds
Dachshunds are the best dogs and all dogs
are better than cats
output:
Words that appear one time are: all, best, better, cats, jack, sally, sophie, than, the, were,
Words that appear more than one time are: and, are, dachshunds, dogs,
*/.
Similar to Write a program in Java that reads a set of doubles from a file, sto.pdf (20)
import java.io.BufferedReader;import java.io.File;import java.io.pdf
import java.io.BufferedReader;import java.io.File;import java.io.pdf
Write a program that will count the number of characters- words- and l.docx
Write a program that will count the number of characters- words- and l.docx
Here is my code for a linefile editor import java.io.BufferedRea.pdf
Here is my code for a linefile editor import java.io.BufferedRea.pdf
Create a text file named lnfo.txt. Enter the following informatio.pdf
Create a text file named lnfo.txt. Enter the following informatio.pdf
Write a java program that allows the user to input the name of a fil.docx
Write a java program that allows the user to input the name of a fil.docx
Write a java program that allows the user to input the name of a file.docx
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Write a Java program that opens the file, reads all the Grade from t.pdf
Write a Java program that opens the file, reads all the Grade from t.pdf
Please help me with a UML class diagram for the following code im.pdf
Please help me with a UML class diagram for the following code im.pdf
import java.io.BufferedReader;import java.io.BufferedWriter;.docx
import java.io.BufferedReader;import java.io.BufferedWriter;.docx
Complete the following Java code such that it opens a file named Fruit.docx
Complete the following Java code such that it opens a file named Fruit.docx
In java , I want you to implement a Data Structure known as a Doubly.pdf
In java , I want you to implement a Data Structure known as a Doubly.pdf
I can not get my code to comply it gets mad that I have run declare mo.docx
I can not get my code to comply it gets mad that I have run declare mo.docx
Write a java program that compute the frequency of each word in the fi.docx
Write a java program that compute the frequency of each word in the fi.docx
JAVAWrite a program that takes a command-line argument representin.pdf
JAVAWrite a program that takes a command-line argument representin.pdf
More from arihantpatna
Compare and contrast the advantages and disadvantages of arrays and .pdf
Compare and contrast the advantages and disadvantages of arrays and linked lists. Give an
example problem that is best accomplished by an array. Give an example problem that is best
accomplished with an array.
access directly with array while linked list take some time to access data. However, list can insert
easily the value into middle of list while array needs to increase the capacity and copy behind
part and fore part and input. Array\'s size is fixed while linked list has flexible size.
Stack or queue is well match with linked list because if push and pop from the end point of data
structure.
array is good with when program needs random access.
Solution
Ex: 1,2,3,4,5 to be stored in array
a[0]=1, a[1]=2 etc..
in LL we have to create space for 1 and store the address next to it as null. next when we want to
insert 2 we have to create address for 2 and store that address in pointer of 1. and so on==> 1->2-
>3->4->5.
Initiallly array size is to be definrd, but ll size can grown dynamicallyArrayLinked
ListCollections of elements with same data typeOrdered collection of data conecting by
linksArray elements are stored continuosly in memorystored in the space available and are
linkedcan have random acessbut here it will be sequential accesstakes more time for insertion
and deletion because we are storing continuosly in the memoryit takes more time here as the
value of the link needs to changed onlyIt is static memory allocation as we have to decide
beforeDynamic we have to create space for each value storedCan be 1D 2D and 3DSingular,
Doubly, circularelement is independent because we do not have connection with previous
memory locationaddress of the element is stored in the link partneed extra space for pointerneed
extra space for pointer.
Answer and describe the following five plants habit, habitat, life .pdf
Answer and describe the following five plants: habit, habitat, life span, throns, spines or prickles,
infloresences, leaves (complexity, attachment to stem, arrangement, blade shape, margin, apex,
base, venation and trichomes). Other interesting facts.
1. Isomeris arboea (Bladderpod) - Drought tolerant plant
2. Sinningia macrostachya
3. Ceropegia dichotoma
4. Lilium longiflorum
5. Peperomia verticiliata
Solution
I. Isomeris arboea
Also known as Bladderpod, Burrofat and California cleome.This plant is a fast-growing
evergreen dicot shrub from the family Capparaceae. It is a dense shrub with profuse branching
and small hairs/trichomes. It normally grows in well-draining rocky areas with good exposure to
sunlight. It is found in Southern Sierra Nevada Foothills, Tehachapi Mountain area, San Joaquin
Valley,Central Coast, South Coast, Channel Islands, Deserts, and Baja,CA
Habitat - Coastal bluffs, hills, desert washes, flats below 3,900\'
Height by Width: 3-4\' H x 4\' W
Stems - profusely branched; glabrate or puberulent (bark corky, twigs smooth)
inflorescence: The plant produces abundant inflorescences at the ends of the stem branches, each
a cluster of bright yellow flowers. Each flower has usually four petals and six whiskery
protruding stamens with curling tips holding the anthers. The fruit is an inflated capsule about 4
centimeters long and usually oval in shape. It is smooth and green when new, aging to light
brown. Fruits when dry, resemble a paper lantern that rattles (the seeds inside the dried fruit
rattle around). The flowers are dense terminal racemes. The calyx is four-cleft and the sepals are
fused in the basal half. It has four petals ½” long, 6 yellow stamens that are long and a pistil with
a short style. Sepals persistent, connate ca. 1/2 of length, green, lanceolate, 4–7 × 2.2–4 mm,
margins entire, glabrous; petals yellow, ovate-elliptic, 8–14 × 4.2–5 mm, (apex acute); stamens
yellow, 15–25 mm; anthers 2–2.5 mm; gynophore (reflexed), 10–20 mm in fruit; ovary 3–6 mm
(often aborting in bud); style 0.9–1.2 mm. Capsules (tardily dehiscent), usually inflated ,(valves
sometimes 3), 20–30 × 6–12 mm, smooth. Seeds 5–25, dark brown, obovoid, 6–7 × 5–6 mm,
smooth.
Leaves: Its leaves are made up of three equal leaflike leaflets, each a long, pointed oval 1-4 cm
long. The leaves are alternate, entire, petiolate and trifoliate with leaflets that are oblong-elliptic
with small pointed tips. petiole 1–3 cm; leaflets 3, blade oblong-elliptic, 1.5–4.5 × 0.4–1.3 cm,
margins serrate, apex acuminate to obtuse, surfaces glaucous. Racemes 1–3 cm (6–40 cm in
fruit); bracts unifoliate, obovate to spatulate, 2–15 mm. Pedicels 7–15 mm (thickened in fruit).
extra information:
II. Sinningia macrostachya
Family: Gesneriaceae
Popular names – leather leaf, Gloxinia
Sinningia macrostachya has a perennial stem base, very stiff leaves, and numerous small orange
flowers. Its fleshy stems are joined to the woody trunk. Each year, the woody part of the stems
exten.
A plant has the genotype (Aa; Bb; Cc). How many different genotype.pdf
A plant has the genotype (A/a; B/b; C/c). How many different genotypes can haploid cells
obtain after meiosis?
Solution
Answer: 8 different types.
Explanation:
Types of different genotype = 2^n,
n is the number of heterozygous alleles
In the given genotype = AaBbCc there 3 heterozygous alleles
Therefore 2^ 3 = 8 different types of gametes.
========.
A) Explain how bilateral symmetry contributed to motion and cephaliz.pdf
A) Explain how bilateral symmetry contributed to motion and cephalization (the evolution of a
head and brain)? B) Explain the common adaptations for reproduction seen in both: organisms
with a parasitic life-style and sessile organisms (those that do not move). C) Explain why those
adaptations are beneficial for each life-style.
Solution
When the animal has right and left sides morror images of each other such a symettry is called
bilateral symmetry.
Bilateral symmetry has contributed to both cephalization and locomotion in animals possessing
them. Animals wuth bilateral symmetry has locomotive organs legs on opposite sides of the body
in symmetrical position. This symmetrical arrangement of locomotive organs enables these
animalsto move thotougjly in steady direction.
Bilateral symmetry resulted in the concentration of brain ,nerves, sense organs ,eyes to the
anterior side of the body forming head..
_______ are any substances that when introduced into the body, stimul.pdf
You have been asked to examine a database to evaluate referential integrity. Which of the
following should you review?
A. Field
B. Aggregation
C. Composite key
D. Foreign key
Solution
D. The foreign key because it refers to an attribute in one table whose value matches the primary
key in another table. Answer A is incorrect because the field refers to the smallest unit of data
within a database. Answer B is incorrect because aggregation refers to the process of combining
several low-sensitivity items, with the result that these items produce a higher-sensitivity data
item. Answer C is incorrect because a composite key is two or more columns that are together
designated as the computer’s primary key..
You decide to spend Break hiking through the Rockies upon arrival, yo.pdf
X=[0:10(a) Create a matrix called test of size 2x2 such that the elements of the matrix test are
test(i, j) = (i^2 - j). Use the command window statements to create this matrix. Use the keyboard
to alter the value of test(1, 2) to -5 and test(2, 2) to 20 What is the value of test(3)? What does
this represent? What is the value of test(5)? Why does this give an error message? Why do test
(2, 2) and test (4) yield the same value? Add a row to test so that the last row of test contains the
entries 2, 9 Create a 1x2 matrix called test 1 whose elements are 12 and 14. Concatenate test 1
with test. Use the cat function to add another column to test. The elements of this new column
are 4, 3, and 7
Solution
(a)
%(a) creating 2 by 2 test matrix
for i=1:2
for j=1:2
test(i,j)=i^2-j;
end
end
test
test(1,2)=-5;
test(2,2)=20;
test
(b)
test(3)=-5 (Since third element matrix is -5 or actual index test(2,1) so 2+1=3, test(3)=-5).
test(5) displays error message because it contains only 4 elements.
test(2,2) and test(4) both are same because index (2,2) means (2+2)=4. so test(2,2)=test(4)
(c)
test(3,1)=2;
test(3,2)=9;
(d)
test1=[12 14];
test=[test; test1].
Which of the following statements is true about cultureA. Culture.pdf
Which is the appropriate test (Z test, single sample, independent samples t or related samples t)
for the following: A researcher is interested in determining whether a new med for appetite
suppression is effective by giving the med to one group that has been matched on weight with
another group that reveives a placebo.
Solution
As the medicine is given to two groups and we want to test whether a new med for appetite
suppression is effective or not. This can be tested only by considering the data of the two
samples and taking their difference.
So, the test has to be a two sample test. So, the possibility of a Z test or a single sample t-test is
nullified. Next, as the two sample data are matched by weight, so the data of the two samples are
no more independent. Hence, the option of independent t-test is also nullified.
So, we are only left with the related sample t-test. And this is also supported by the data. As they
are matched by weight, so they are related to each other. Hence we would go for aa \'related
sample t-test\'..
Which data set has the least sample standard deviation Data set (ii.pdf
What specific mutation is in each of the following proto-oncogenes: A)EGF receptor, B) Ras, C)
Src kinase, would cause them to become oncogenes? Explain.
Solution
A) The most common EGFR mutations are deletion of exon 19 which converts the EGFR proto
oncogene to oncogene that leads to lung cancer. B) Ras proto-oncogene encodes a protein that
receives and transfers signals required for cell division. Mutation at amino acid position 12 or 61
causes formation of oncoprotein that leads to uncontrolled cell division. Thus mutation of amino
acid 12 or 61 converts Ras proto-oncogene to oncogene. C) A truncating mutation of codon 531
of SRC proto-oncogene converts it into oncogene that leads to colorectal cancer.
Whats wrong with this Hardy Weinberg question I thought it was a.pdf
What is the price earnings Ratio for Lowe\'s and Home Depot?
HOME DEPOT Balance Sheet
Consolidated Balance Sheets - USD ($)
$ in Millions
LOWES Balance Sheet
Consolidated Balance Sheets - USD ($)
$ in Millions
Consolidated Balance Sheets - USD ($)
$ in Millions Jan. 29, 2017 Jan. 31, 2016Current Assets:Cash and Cash Equivalents$ 2,538$
2,216Receivables, net2,0291,890Merchandise Inventories12,54911,809Other Current
Assets608569Total Current Assets17,72416,484Property and Equipment, at
cost40,42639,266Less Accumulated Depreciation and Amortization18,51217,075Net Property
and Equipment21,91422,191Goodwill2,0932,102Other Assets1,2351,196Total
Assets42,96641,973Current Liabilities:Short-Term Debt710350Accounts
Payable7,0006,565Accrued Salaries and Related Expenses1,4841,515Sales Taxes
Payable508476Deferred Revenue1,6691,566Income Taxes Payable2534Current Installments of
Long-Term Debt54277Other Accrued Expenses2,1951,941Total Current
Liabilities14,13312,524Long-Term Debt, excluding current installments22,34920,789Other
Long-Term Liabilities1,8551,965Deferred Income Taxes296379Total
Liabilities38,63335,657STOCKHOLDERS\' EQUITYCommon Stock, par value $0.05;
authorized: 10 billion shares; issued: 1.776 billion shares at January 29, 2017 and 1.772 billion
shares at January 31, 2016; outstanding: 1.203 billion shares at January 29, 2017 and 1.252
billion shares at January 31, 20168888Paid-In Capital9,7879,347Retained
Earnings35,51930,973Accumulated Other Comprehensive Loss(867)(898)Treasury Stock, at
cost, 573 million shares at January 29, 2017 and 520 million shares at January 31,
2016(40,194)(33,194)Total Stockholders’ Equity4,3336,316Total Liabilities and Stockholders\'
Equity$ 42,966$ 41,973
Solution
Price at 29 Jan 2017 = 40194 / 573 = $70.15 per share (from Treasury stock data)
Price at 31 Jan 2016 = 33194 / 520 = $63.83 per share
EPS for 2017 = (RE $35519 - RE $30973)m = 4546m / outstanding shares 1776m = $2.56
pershare
Price Earnings ratio for 2017 = Price on 29 Jan 17 / EPS for 2017 = $70.15 / $2.56 = 27.40 times.
6. List and define the underlying conditions, or assumptions, which .pdf
6. List and define the underlying conditions, or assumptions, which have had an impact on the
development of GAAP.
Solution
ANSWER:
The underlying conditions/ assumptions, which have had an impact on the development of
GAAP are as follows:
--Business entity: The company for which the financial statements are prepared is distinct and
separate from the owners.
--Going concern or continuity : The assumption is made that the organisation will remain in
business for an indefinite time frame.
--Monetary unit : Accountants requires certain standard of measure to bring financial
transactions together in an appropriate way.
--Realization: Revenue must be recognized when the earning process is virtually complete and
the exchange value need to be objectively determined
--Matching: This concept states to recognize the costs that are related with the recognized
revenue
--Full disclosure: Accounting reports must disclose all facts that may influence the judgment of
an informed reader
--Materiality: The approach involves the relative size and importance of an item to a business.
--Verifiability: The accountant need to adhere as closely as possible to verifiable data.
--Industry practices: Few business use accounting reports that do not conform to the general
theory that underlies accounting
--Transaction approach : The accountant records only events that affect the business financial
position and also can be reasonably determined in monetary terms.
--Accrual basis: Expenses need to recognized when incurred (matching concept), and revenue
are to be recognized when it is realized (realization concept), and
--Consistency: The business must give the similar treatment to comparable transactions from
period to period
--Conservatism : The measurement with the least favorable effect on financial position and net
income in the current period need to be selected.
--Historical cost : Of the numerous values that could be used, the objective and determinable
value should be selected
-- Time period With this assumption, inaccuracies of accounting for entity short of its complete
life span are accepted..
What does the LP tableau below indicate (The xs are decision varia.pdf
Wha is the difference between the large intestine and colon?
Wha is the difference between the large intestine and colon?
Solution
Answer:
The large intestine starts in the pelvis at the right iliac region located immediately under the
waist on the right-hand side. It has 5 parts that are -cecum, appendix, colon, rectum and anus.
Overall function of large intestine is to form feces.
Colon makes up most part of large intestine. It helps in water and salt absorption..
Wha is the difference between the large intestine and colon .pdf
Using the six general trends of the general environment, give a hypothetical example of how
each trend could affect a restaurant business.
Solution
There are six general trends of the general environment--
1) Demographic Segment--It consists of people from different ethnic groups like Indians,
Europeans, Asians etc and its affect on a business. In case of a restaurant business opening of a
Indian restaurant in China will attract lower customers
2)Socio Cultural Segment--It consists of diverse set of people in the workplace who helps in the
company\'s success in the Global Market. E.g. a business employing women, not engaging into
racial discrimination etc. will attract more employees
3)Economic Segment--It depends on the nation\'s economic condition in the World Market. In
case of a restaurant business, an economic slowdown or recession will have a negative impact on
the business.
4)Legal Segment--This segment is dependent on an economy\'s governance laws, policies,
taxation laws and regulations for its employees. In case of restaurant business, a restaurant set up
in a country with heavy taxes and strict regulation, operations can be difficult and prove to be of
losses.
5)Technological Segment--It relates to technological advancements and updation of newer
technology at pace with the competitors. In case of restaurant business, restaurants adopting
newer technologies will be able to produce more and earn more
6)Global Segment--This segment expands the organisation globally so that it can gain a
competitive advantage over its competitors when they have a global presence in the industry. In
case of a restaurant business, going global can prove to be profitable if given chances..
Was airpower decisive in winning World War II Defend your answer..pdf
Using \" for \" loop to calculate compound interest for 20 years. The starting principal is 5000
and the rate is 0.04. Show amount on deposit for each year.
Solution
#include
#include
#include
int main()
{
double principal=5000.0;
double rate=0.04;
int time=20;
double amt=principal;
for(int i=1;i<=20;i++)
{
printf(\"\ Deposit for year %d : %lf\",i,amt);
amt=amt+((amt*rate*1.0)/100);
}
printf(\"compound interest for 20 yrs : %lf\",(amt*pow(1.0+(rate/100),20)));
return 0;
}.
Summarize the workflow of the study of microbial diversity. Draw a d.pdf
Solve the following:
a. How many permutations of all 26 letters of the alphabet are there that contain at least one of
the words: CAR, CART, SCARF, SCARE, SCAR?
b. How many permutations of all 26 letters of the alphabet are there that contain at least one of
the words: MAZE, SWORD, PLANT, CARTS?
Solution
This computer science but:
a) The answer should be Factorial(24) i.e . factorial of 24. It can be solved by formulating a
simple recurrence relation.
b)(26C4+26C5+26C5+26C5)/26!.
It can also be seen as a recurrence relation and solved..
Shifting allocations most often arise as a result of which of the fo.pdf
Salaries of 40 college graduates who took a statistics course in college have a mean, x , of $
68,200. Assuming a standard deviation, , of $18,561, construct a 95% confidence interval for
estimating the population mean .
$___ < < $___
Round to the nearest integer as needed.
Solution
Confidence Interval
CI = x ± Z a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval
Mean(x)=68200
Standard deviation( sd )=18561
Sample Size(n)=40
Confidence Interval = [ 68200 ± Z a/2 ( 18561/ Sqrt ( 40) ) ]
= [ 68200 - 1.96 * (2934.752) , 68200 + 1.96 * (2934.752) ]
= [ 62447.887,73952.113 ]
= [ 62448 ,73953 ].
16.) How would you determine if Cellulous is hydrophobic or hydrophi.pdf
16.) How would you determine if Cellulous is hydrophobic or hydrophilic?
Solution
Hydrophilic substance interact with water and willabsorb it easly . Hydrophobicmeans it seperate
the water . Cellulise is a plymer chain of monosachhride . It is hydrophilic and atrract water
molecules due to its functional group . But it is aplymer chai water does not have ability to
surround compltely each monomerof cellulose fiber .Polymer is less soluble than monomwes
because of entropy . cellulose have hydrogen bond but not as well as water and plymer have low
entropy due to their confuguration and constrained. the attract water on the surface if the
molecules are smaller then water . cellulose is a big polymer so the particals are to large too
dissolved..
Please Explain CompletelyWhat defines the beginning of the hepatic.pdf
Pattern of Stars
Listing 6.4 in the text book demonstrates the use of a nested for loop by printing a pattern of
asterisks (stars), starting from the least number of stars per row (1) to the most number of stars
per row (10). You will modify this program so that it does the following:
Asks the user how many rows of stars they want.
Prints the stars starting with the least stars per row and ending with the most stars per row, but
the stars must be lined up along the right margin instead of the left. (In other words, print a
version of the pattern that has been flipped horizontally i.e. along a vertical axis).
You will need:
An input statement to prompt the user for the number of rows.
An assignment statement to store the number of rows.
A nested for loop as shown in Listing 6.4 (pg 263). You will need to modify the conditions in
some of your for loops to accomplish this task.
This time, you will need two for loops nested within the outermost loop.
The outer loop will control the number of rows, as in the example.
One of the inner loops will control the number of stars per row, again as in the example.
You will need to create another for loop that controls the number of spaces per row, to achieve
the intended pattern. The spaces need to be printed before each row of stars is printed.
Note: The two inner loops do not have to be nested. See the code shell for the intended design.
Sample output:
Enter the number of rows: 8
*
**
***
****
*****
******
*******
********
Code Shell
//*********************************************************
// StarPattern.java
//
// This is a modified version of the Stars.java program
// from Listing 6.4 in the text.
//*********************************************************
//import Scanner class here
public class StarPattern1
{
//------------------------------------------------------
// Prints a triangle shape using asterisk (star)
// characters.
//------------------------------------------------------
public static void main(String[] args)
{
//Create Scanner variable
final int MAX_ROWS = 10; // Replace this constant
// with a variable to store
// the number of rows
//Ask for number of rows
//Store in variable
for (int row = 1; /*adjust condition*/; row++)
{
/*insert a for loop here. This one should
control the number of spaces before each star*/
for (int star = 1; star <= row; star++)
System.out.print(\"*\");
System.out.println();
}
}
}
Solution
//import Scanner class here
import java.util.Scanner;
public class StarPattern1{
public static void main(String[] args)
{
Scanner input = new Scanner( System.in );
//Create Scanner variable
final int MAX_ROWS;
System.out.println(\"Enter the number of rows: \");
MAX_ROWS = input.nextInt();
for (int row = 1; row=row;j--){
System.out.print(\" \"); /*insert a for loop here. This one should
control the number of spaces before each star*/
}
for (int star = 1; star <= row; star++){
System.out.print(\"*\");
}
System.out.println();
}
}
}.
Plant Diversity II – Seed Plants1. Explain how the rise in pro.pdf
ooo T-Mobile LTE 5:40 PM courses.apexlearning.com s of Polynomial Functions Which point
is the best approximation of the relative maximum of the polynomial function graphed below? 30
20 2 10 O A (-2.3, 17.9) O B. (-1.4, 16.9) O c. (-1.1, 14.8) D. (-2.1, 17.2) IL
Solution
in the x axis the value is between -1 and -2 , and the y-axis value is closer to 20 then the answer
is the letter
B = (-1.4, 16.9).
17) Fill out the following table Structure Pili or Fimbriae Flagella.pdf
17) Fill out the following table: Structure Pili or Fimbriae Flagella Capsule PHB inclusion
Sulfur granules Magnetosomes Endo LPS layer Cell wall Function Location
Solution
structure
Function
Location
Pili or fimbrae
Required for bacterial conjugation
On the surface, embedded in cell membrane
Flagella
Bacterial cell motility
On the surface, embedded in cell membrane; numbers vary from 1 to multiple
Capsule
Outside the cell envelope
Protection from antibiotics, mechanical stress and desiccation
PHB inclusion
Present in the bacterial cytoplasm
Acts as storage granules in bacteria
Sulfur granules
Inclusion bodies in cytoplasm
May aid in metabolism- bacteria that use Hydrogen sulfide as electron source for respiration
Magnetosomes
Membranous organelles that are present in magnetotactic bacteria; containing magnetic crystals
Help the bacteria orient in geomagnetic field to search proper environment
Endospores
Generally present in the cytoplasm
Helps the bacterial cells propagate asexually in extreme conditions
LPS layer
Part of cell wall in Gram negative bacterial cells
Protection of the cells, transport of materials and also imparts pathogenicity to the bacterial cells
Cell wall
A part of the cell envelope, surrounding cell membrane
Protection of the cells, transport of materials and maintenance of osmotic pressure.
structure
Function
Location
Pili or fimbrae
Required for bacterial conjugation
On the surface, embedded in cell membrane
Flagella
Bacterial cell motility
On the surface, embedded in cell membrane; numbers vary from 1 to multiple
Capsule
Outside the cell envelope
Protection from antibiotics, mechanical stress and desiccation
PHB inclusion
Present in the bacterial cytoplasm
Acts as storage granules in bacteria
Sulfur granules
Inclusion bodies in cytoplasm
May aid in metabolism- bacteria that use Hydrogen sulfide as electron source for respiration
Magnetosomes
Membranous organelles that are present in magnetotactic bacteria; containing magnetic crystals
Help the bacteria orient in geomagnetic field to search proper environment
Endospores
Generally present in the cytoplasm
Helps the bacterial cells propagate asexually in extreme conditions
LPS layer
Part of cell wall in Gram negative bacterial cells
Protection of the cells, transport of materials and also imparts pathogenicity to the bacterial cells
Cell wall
A part of the cell envelope, surrounding cell membrane
Protection of the cells, transport of materials and maintenance of osmotic pressure..
Mark and I.isa registered for Physics 101 class. Mark attends class 6.pdf
Let’s assume 3M produces “Command Hooks” at a rate of 10,000 units per day. Before
reconfiguring their production process, their flowtime through the process was 100 days. After
reconfiguring, the new flowtime is 35 days. After reconfiguring, how many units of work in
progress inventory are in the process?
< 100,000
Between 100,000 and 300,000
Between 300,000 and 600,000
Between 600,000 and 900,000
>900,000
< 100,000
Between 100,000 and 300,000
Between 300,000 and 600,000
Between 600,000 and 900,000
>900,000
Solution
The number of units in the work in progress inventory would be in the range of 600,000 and
900,000.
As the flowtime has decreased from 100 days to 35 days, thus there would be inventory of 65
days remaining in the process or in other words there would be wor in process remaining for 65
days.
Earlier, when the flowtime was 100 days, then each day production was 10,000, hence inventory
in the system would be for 65 days and related with producing 10,000 units per day, which
would come in the range of 600,000-900,000..
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