What is heartwood What is sapwood What is the most abundant tissu.pdf
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What is heartwood? What is sapwood? What is the most abundant tissue in the three-year-old stem? What are three contrasting differences in structure between the sunflower stem and the TNia stem? What are two techniques that can be used to determine the age of a woody twig? Solution 1. Heart wood is the dead and inner wood tissue produced by cork cambium. It is dark in colr and is distinguished from sap wood by its color and texture. Sapwood is the outermost living wood tissue. It is also produced by cambium but is composed of different types of cells. It is lightin color. It is involved conduction of water and minerals from roots to all parts of tree. 2. In a three year old stem, the secondary xylem and phloem are bundant than primary xylem and phloem. These vascular tissues conspicuously appear as annual rings by which the age of the tree is known. 3. 4. The age of a woody twig can be determined by counting the number of groups of bud scale scars on it and he the number of terminal bud scale scars present.SunflowerTiliaAnnualperennialherb exhibits no secondary growthtree exhibits secondary growthVascular bundles form a ring. Xylem lies inside the vascular bundles. Phloem lies outside and phloem fibers are tough. The center of stem is filled with ground tissue known as pithOne year old stem exhibits no secondary growth and contains a layer of xylem and two later meristems called vascular and cork cambium. During second year growth 2 rings of xylem is observed. During third year secondary xylem is obseved and secondary phloem towards inside to xylem..
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This presentation is about wood structure
Here you will be able to learn about wood and its necessary details. You will get information about the anatomy of wood and details about soft and hard wood.
Wood anatomy
introduction
ontogeny of secondary vascular tissues
growth rings
heart wood
types of heart wood
sap wood
wood parenchyma
secondarygrowthindicotstem-220125143633.pdf
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Recommended
This presentation is about wood structure
Here you will be able to learn about wood and its necessary details. You will get information about the anatomy of wood and details about soft and hard wood.
Wood anatomy
introduction
ontogeny of secondary vascular tissues
growth rings
heart wood
types of heart wood
sap wood
wood parenchyma
secondarygrowthindicotstem-220125143633.pdf
fhjkdcbvsdjbvsdjbvmsdnbkldfbnjkgfcbvmxd bvmnmbdjhfehsnkhasferhgjfjfdjbvdmc vnascv md vfm vd vsdnngvsdkvsdjknsdm,bnd vd, vndf,nsdnv,kdn,nvdfmbfg b.,vnsdklsdvndfk.nbtfbhdvdfdfbdfh
Gymnosperms.pptx
Gymnosperms definition
Morphological characters of Gymnosperms
Anatomy of Gymnosperms
Cycas
General character of cycas
Sexual reproduction in cycas
Asexual reproduction in cycas
Economical importance of cycas
Pinus
Characters of pinus
Sexual reproduction in pinus
Asexual reproduction in pinus
Importance of pinus
Roots anatomy
Stem anatomy
Xylem
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Lab 5- Stems 1- Examine the woody dicot twig provided- Note at the tip.pdf
Lab 5: Stems 1. Examine the woody dicot twig provided. Note at the tip of the twig the terminal
bud protected by bud scales. 2. Locate a node (leaf attachment region of stem), and examine the
leaf scar(s) present. 3. How many bundle scars are present in each leaf scar? 2 (Bundle scars
usually appear as tiny bumps where strands of xylem and phloem broke when the leaf fell from
the stem; if necessary, use your dissecting microscope to locate them.] 4. Groups of small,
narrow scars (bud scale scars) often extend around the twig: these are created when the terminal
bud scales of a previous terminal bud fall off. Are any such groups of scars present? If so, how
old is your twig? Explain 5. Leaves are usually attached to the stem at an angle. The region
immediately above the leaf base and the stem is called an axil. Are the axillary buds (there is
normally one axillary bud in each axil) similar to the terminal buds? If not, how do they differ?
B. Herbaceous Dicot Stems 1. How does the armingement of the primary xylem and primary
phloem in the young alfalfa stem differ from their arrangement in the buttercup (Ranunculus)
root you examined in the previous lab? *You may need to look at the cross. section of the
buttercup root again. 2. Use the space below to draw a cross section of a dicot root and an
herbaceous dicot stem. 3. With the aid of a sharp razor blade, cut paper-thin cross sections of a
coleus stem. Mount in a drop of phloroglucinol (or water) on a slide and add a coverslip.
Examine with lowest power of your microscope. What similarities between this and aifalfa stems
can you detect? Internal Structure of a Woody Stem 1. Examined a prepared slide of a woody
stem (Tilia xs). 2. Note that the phloem in the Tilia stem is quite complex compared to an
herbaceous dicot stem, and that there are several additional tissues. Focus on the outermost part
of the Tilia stem first. Note that by the time the stem is.
Gymnospermic wood
IT CONSISTS A BRIEF INTRODUCTION TO GYMNOSPERMS. ANATOMY OF GYMNOSPERMIC WOOD IS DISCUSSED BRIEFLY.
Wood Grain Overview.pdf
Who ever thought there would be some much to write about with regards to wood grain
Vegetative characters of equisetum
Equisetum popularly known a the ‘horse-tail’ or ‘scouring rush’.
It is now represented by nearly 30 species which are seen world wide except in Australia and New Zealand.
Some species prefer damp and shady places while others grow in marshes, ponds or stream banks
Some are found in xerophytic habitats
If you were given an unknown plant and asked to determine whether .pdf
If you were given an unknown plant and asked to determine whether it is a conifer or a cycad,
what would you look for if given only wood? Only leaves?
If you were given an unknown plant and asked to determine whether it is a conifer or a cycad,
what would you look for if given only wood? Only leaves?
Solution
CONIFERS IDENTIFICATION
STEM (OR) WOOD
Stems raise the photosynthetic leaves into the light and provide a channel for nutrients between
the leaves and the roots. Most of the diameter of mature conifer stems consists of secondary
xylem (wood) produced by the vascular cambium, a permanent cylinder of dividing cells that lies
just inside the bark. Because the growth of most conifers is cyclic, the wood generally consists of
distinct growth rings, which are delimited by the juxtaposition of small dark cells from the end of
a growing season with larger, lighter cells that mark resumption of growth. In temperate conifers,
the rings correspond to annual growth flushes, since no wood is formed during winter dormancy.
Tropical species may lack this correspondence unless their habitat has strong seasonal variation
in rainfall. Otherwise, they may have more than one growth ring in a year, each accompanying a
new flush of leaves and branches.
The wood of conifers is generally more uniform and simpler in structure than that of flowering
plants. One type of cell, the tracheid, serves both to transport water and to support the trunk so
that conifers lack the more textured wood associated with the mixture of vessel elements and
fibres in hardwoods. The wood may have longitudinal resin canals lined with living cells, but
most of its living cells are found in the rays that extend horizontally from the centre of the stem
to the vascular cambium. The pits, the tiny thinnings that connect adjacent wood cells, are quite
varied among conifer families and genera and are one of the chief features used to identify
conifer woods.The bark that clothes the trunks may be thin, smooth, and flaky, peeling annually
to reveal fresh bright colours, as in the lacebark pine (Pinus bungeana) of China and the tecate
cypress (Cupressus guadalupensis) of southern California and Baja California, or it may
accumulate in broad, colourful plates, as in the ponderosa pine (Pinus ponderosa) of western
North America, or as thick, fireproof, fibrous ridges on the giant sequoias (Sequoiadendron
giganteum). The practiced eye can distinguish different species of co-occurring conifers by their
bark alone.Some conifers have transient special determinate twigs called short shoots that carry
most of the photosynthetic leaves. In the bald cypress (Taxodium) and dawn redwood
(Metasequoia), the short shoots look like double-sided combs and are shed each fall, to be
followed by new ones in the same spots on the branches when growth resumes the following
spring. The short shoots of pine (Pinus), with their fascicles of two to five (rarely one or eight)
needles, are retained for up to 20 years but .
Lross section or s yr- od stemSecondary xylem Found as wide- continu.pdf
Lross section or s yr. od stem Secondary xylem Found as wide, continuous rings around the pith.
Vascular cambium Vascular cambium is located on the outer edge of the xylem and produce
secondary xylem and phloem tissues. The vascular cambium underlies the phloem tissues.
Annual rings Also known as growth rings. The cambium layer in woody plants of temperate
biomes have seasonal dormancy. Growth is most active in spring and tapers in summer, ceasing
in fall. Spring wood typically has larger vessels that are more porous. Summer wood is
comprised of denser, smaller cells. The first cells of the next season's spring wood are produced
next to the smallest summer wood cells of the previous year. Annual growth rings are "caused"
by the alternating pattern of spring and summer wood. Phloem The phloem underlies the bark
and appears as wedge-shaped areas. Cork Cork forms beneath the epidermis and is formed by the
cork cambium. Once cork is present, the epidermis splits and falls off. Cortex The cortex is
located beneath the cork and outside the phloem..
Taxus
Taxus baccata commonly known as ‘Yew’, is an evergreen tree attaining a height of 9-20 metres with a massive trunk. Taxus is usually dioecious, but occasionally monoecious trees are also reported.
The reproductive structures become prominent on the plant in February-March. The male and female plants do not show any distinction in their vegetative organization. The differentiation between them can be made only when the plants are in the flowering or fruiting stage. Vegetative reproduction in Taxus is not known.
Describe 3 functions of the cellular membrane and how are these func.pdf
Describe 3 functions of the cellular membrane and how are these functions accomplished by the
chemical make up of the membrane.
Solution
The main functions of the cell membrane are:to maintain the physical integrity of the cell,that is
to mechanically enclose the contents of the cell,also to control the movement of particles e.g.
ions or molecules,into and out of the cell.It also isolates the cytoplasm from the external
environment.
The hydrophilic head and hydrophobic tails of the phospholipid molecules that form the
phospholipid bilayer of the cell membrane forming its physical/mechanical structure.The ion
channels responsible for the selective permeability of the cell membrane.Membrane pumps that
enable active transport of specific molecules across the cell membrane.Carrier proteins and
receptor proteins that transport specific substance across the cell membrane and receive
(chemical) signals from outside the cell that tell the cell to take a specific
action,respectively.Cholesterol molecules and carbohydrate chains that support the structure of
the membrane and its attachment to other tissues,respectively.Surface protein markers that
identify the cell.Membrane proteins acts as a recptor to combine with specific substance such as
hormones while some form narrow passage ways or channels through which various molecules
and ions can cross the cell membrane.Enzymatic proteins carry out metabolic reactions..
Discuss the three main types of intellectual capitalSolutionth.pdf
Discuss the three main types of intellectual capital
Solution
the main types of intellectual capitals are: Copy rights, patents, trade marks and trade secrets.
copy rights: gives the right to the inventor or author or a book or artistick work to his invention.
book publishing and movie distribution comes under this example.
patents: gives the inventor to sell the right to use his invention for commercial and for that he
will charge something from the user. the user will get licence to use it and will be benefited.
manufacturing of McDonald and Dominos pizzas comes under this action.
trademark: is facilitate the seller or producer to differentitate his prodcut from his competitors
product and will be benefited. is like giving licence to sell the products in a region for a
particular period. the producer will allows the seller to sell the product and will get some benefit..
More Related Content
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Gymnosperms.pptx
Gymnosperms definition
Morphological characters of Gymnosperms
Anatomy of Gymnosperms
Cycas
General character of cycas
Sexual reproduction in cycas
Asexual reproduction in cycas
Economical importance of cycas
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Asexual reproduction in pinus
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Lab 5- Stems 1- Examine the woody dicot twig provided- Note at the tip.pdf
Lab 5: Stems 1. Examine the woody dicot twig provided. Note at the tip of the twig the terminal
bud protected by bud scales. 2. Locate a node (leaf attachment region of stem), and examine the
leaf scar(s) present. 3. How many bundle scars are present in each leaf scar? 2 (Bundle scars
usually appear as tiny bumps where strands of xylem and phloem broke when the leaf fell from
the stem; if necessary, use your dissecting microscope to locate them.] 4. Groups of small,
narrow scars (bud scale scars) often extend around the twig: these are created when the terminal
bud scales of a previous terminal bud fall off. Are any such groups of scars present? If so, how
old is your twig? Explain 5. Leaves are usually attached to the stem at an angle. The region
immediately above the leaf base and the stem is called an axil. Are the axillary buds (there is
normally one axillary bud in each axil) similar to the terminal buds? If not, how do they differ?
B. Herbaceous Dicot Stems 1. How does the armingement of the primary xylem and primary
phloem in the young alfalfa stem differ from their arrangement in the buttercup (Ranunculus)
root you examined in the previous lab? *You may need to look at the cross. section of the
buttercup root again. 2. Use the space below to draw a cross section of a dicot root and an
herbaceous dicot stem. 3. With the aid of a sharp razor blade, cut paper-thin cross sections of a
coleus stem. Mount in a drop of phloroglucinol (or water) on a slide and add a coverslip.
Examine with lowest power of your microscope. What similarities between this and aifalfa stems
can you detect? Internal Structure of a Woody Stem 1. Examined a prepared slide of a woody
stem (Tilia xs). 2. Note that the phloem in the Tilia stem is quite complex compared to an
herbaceous dicot stem, and that there are several additional tissues. Focus on the outermost part
of the Tilia stem first. Note that by the time the stem is.
Gymnospermic wood
IT CONSISTS A BRIEF INTRODUCTION TO GYMNOSPERMS. ANATOMY OF GYMNOSPERMIC WOOD IS DISCUSSED BRIEFLY.
Wood Grain Overview.pdf
Who ever thought there would be some much to write about with regards to wood grain
Vegetative characters of equisetum
Equisetum popularly known a the ‘horse-tail’ or ‘scouring rush’.
It is now represented by nearly 30 species which are seen world wide except in Australia and New Zealand.
Some species prefer damp and shady places while others grow in marshes, ponds or stream banks
Some are found in xerophytic habitats
If you were given an unknown plant and asked to determine whether .pdf
If you were given an unknown plant and asked to determine whether it is a conifer or a cycad,
what would you look for if given only wood? Only leaves?
If you were given an unknown plant and asked to determine whether it is a conifer or a cycad,
what would you look for if given only wood? Only leaves?
Solution
CONIFERS IDENTIFICATION
STEM (OR) WOOD
Stems raise the photosynthetic leaves into the light and provide a channel for nutrients between
the leaves and the roots. Most of the diameter of mature conifer stems consists of secondary
xylem (wood) produced by the vascular cambium, a permanent cylinder of dividing cells that lies
just inside the bark. Because the growth of most conifers is cyclic, the wood generally consists of
distinct growth rings, which are delimited by the juxtaposition of small dark cells from the end of
a growing season with larger, lighter cells that mark resumption of growth. In temperate conifers,
the rings correspond to annual growth flushes, since no wood is formed during winter dormancy.
Tropical species may lack this correspondence unless their habitat has strong seasonal variation
in rainfall. Otherwise, they may have more than one growth ring in a year, each accompanying a
new flush of leaves and branches.
The wood of conifers is generally more uniform and simpler in structure than that of flowering
plants. One type of cell, the tracheid, serves both to transport water and to support the trunk so
that conifers lack the more textured wood associated with the mixture of vessel elements and
fibres in hardwoods. The wood may have longitudinal resin canals lined with living cells, but
most of its living cells are found in the rays that extend horizontally from the centre of the stem
to the vascular cambium. The pits, the tiny thinnings that connect adjacent wood cells, are quite
varied among conifer families and genera and are one of the chief features used to identify
conifer woods.The bark that clothes the trunks may be thin, smooth, and flaky, peeling annually
to reveal fresh bright colours, as in the lacebark pine (Pinus bungeana) of China and the tecate
cypress (Cupressus guadalupensis) of southern California and Baja California, or it may
accumulate in broad, colourful plates, as in the ponderosa pine (Pinus ponderosa) of western
North America, or as thick, fireproof, fibrous ridges on the giant sequoias (Sequoiadendron
giganteum). The practiced eye can distinguish different species of co-occurring conifers by their
bark alone.Some conifers have transient special determinate twigs called short shoots that carry
most of the photosynthetic leaves. In the bald cypress (Taxodium) and dawn redwood
(Metasequoia), the short shoots look like double-sided combs and are shed each fall, to be
followed by new ones in the same spots on the branches when growth resumes the following
spring. The short shoots of pine (Pinus), with their fascicles of two to five (rarely one or eight)
needles, are retained for up to 20 years but .
Lross section or s yr- od stemSecondary xylem Found as wide- continu.pdf
Lross section or s yr. od stem Secondary xylem Found as wide, continuous rings around the pith.
Vascular cambium Vascular cambium is located on the outer edge of the xylem and produce
secondary xylem and phloem tissues. The vascular cambium underlies the phloem tissues.
Annual rings Also known as growth rings. The cambium layer in woody plants of temperate
biomes have seasonal dormancy. Growth is most active in spring and tapers in summer, ceasing
in fall. Spring wood typically has larger vessels that are more porous. Summer wood is
comprised of denser, smaller cells. The first cells of the next season's spring wood are produced
next to the smallest summer wood cells of the previous year. Annual growth rings are "caused"
by the alternating pattern of spring and summer wood. Phloem The phloem underlies the bark
and appears as wedge-shaped areas. Cork Cork forms beneath the epidermis and is formed by the
cork cambium. Once cork is present, the epidermis splits and falls off. Cortex The cortex is
located beneath the cork and outside the phloem..
Taxus
Taxus baccata commonly known as ‘Yew’, is an evergreen tree attaining a height of 9-20 metres with a massive trunk. Taxus is usually dioecious, but occasionally monoecious trees are also reported.
The reproductive structures become prominent on the plant in February-March. The male and female plants do not show any distinction in their vegetative organization. The differentiation between them can be made only when the plants are in the flowering or fruiting stage. Vegetative reproduction in Taxus is not known.
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Lab 5- Stems 1- Examine the woody dicot twig provided- Note at the tip.pdf
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Solution
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code:
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TRANSLATION:- RNA to Protein translation (tRNA charged with amino acid enter in ribosome
with correct mRNA triplet , ribisome then add aminoacid.
In cancer, gene promoter contain CpG island with numerous CpG sites. When CpG
sitesethylated gene become silence.
Thanks...
You get a call from a customer who reinstalled Windows on his comput.pdf
You get a call from a customer who reinstalled Windows on his computer after a crash.
Fortunately, he had recently backed up all this data to an external USB drive and was able to
restore everything on his NTFS-formatted file system. However, he had a number of encrypted
files that he had backed up along with the rest of his data that he can no longer access. What
happened?
A. NTFS-encrypted files cannot be backed up, and when the computer crashed, those files were
lost forever. When the customer tried to restore these files, only corrupted versions were
restored.
B. NTFS-encrypted files are not restored with the original encryption key used before the backup
process and thus become inaccessible.
C. When the customer reinstalled Windows, even though he used his old username, the computer
assigned him a completely different security identifier (SID). The restored NTFS-encrypted files
are looking for his original SID.
D. When the customer reinstalled Windows, he didn’t use his original username. The restored
NTFS-encrypted files are looking for the original username.
Solution
C. NTFS encryption used the customer’s SID to associate with the encrypted file. Now that the
customer reinstalled Windows, a completely new SID was assigned to the customer. Without the
original SID, he can’t access the encrypted files. A third-party decryption application may help
him access his encrypted data..
You are running the Windows installation setup for Windows 7 on a co.pdf
You are running the Windows installation setup for Windows 7 on a computer. When the
Windows Setup screen appears, what do you notice?
A. The Setup screen has been drastically redesigned from Windows Vista.
B. The Setup screen is almost exactly the same as Windows Vista.
C. The Setup screen hasn’t changed since Windows XP.
D. Unlike Windows Vista, the Setup screen immediately launches into the GUI.
Solution
B. The Windows 7 Setup screen is virtually the same as the screen in Windows Vista, both
beginning in a black character-mode screen and then launching the GUI..
Write a program to decipher messages encoded using a prefix code, gi.pdf
Write a program to decipher messages encoded using a prefix code, given the encoding tree.
Such codes are widely used in applications that compress data, including JPEG for images, MP3
for music, and DivX for video. using Huffman Trees (Prefix Binary Trees) c++
Solution
#include #include #include #include // for CHAR_BIT #include #include const int
UniqueSymbols = 1 << CHAR_BIT; const char* SampleString = \"this is an example for
huffman encoding\"; typedef std::vector HuffCode; typedef std::map HuffCodeMap; class
INode { public: const int f; virtual ~INode() {} protected: INode(int f) : f(f) {} };
class InternalNode : public INode { public: INode *const left; INode *const right;
InternalNode(INode* c0, INode* c1) : INode(c0->f + c1->f), left(c0), right(c1) {}
~InternalNode() { delete left; delete right; } }; class LeafNode :
public INode { public: const char c; LeafNode(int f, char c) : INode(f), c(c) {} };
struct NodeCmp { bool operator()(const INode* lhs, const INode* rhs) const { return lhs->f
> rhs->f; } }; INode* BuildTree(const int (&frequencies)[UniqueSymbols]) {
std::priority_queue, NodeCmp> trees; for (int i = 0; i < UniqueSymbols; ++i) {
if(frequencies[i] != 0) trees.push(new LeafNode(frequencies[i], (char)i)); }
while (trees.size() > 1) { INode* childR = trees.top(); trees.pop();
INode* childL = trees.top(); trees.pop(); INode* parent = new
InternalNode(childR, childL); trees.push(parent); } return trees.top(); } void
GenerateCodes(const INode* node, const HuffCode& prefix, HuffCodeMap& outCodes) {
if (const LeafNode* lf = dynamic_cast(node)) { outCodes[lf->c] = prefix; }
else if (const InternalNode* in = dynamic_cast(node)) { HuffCode leftPrefix =
prefix; leftPrefix.push_back(false); GenerateCodes(in->left, leftPrefix,
outCodes); HuffCode rightPrefix = prefix; rightPrefix.push_back(true);
GenerateCodes(in->right, rightPrefix, outCodes); } } int main() { // Build
frequency table int frequencies[UniqueSymbols] = {0}; const char* ptr =
SampleString; while (*ptr != \'\\0\') ++frequencies[*ptr++]; INode* root =
BuildTree(frequencies); HuffCodeMap codes; GenerateCodes(root, HuffCode(),
codes); delete root; for (HuffCodeMap::const_iterator it = codes.begin(); it !=
codes.end(); ++it) { std::cout << it->first << \" \"; std::copy(it-
>second.begin(), it->second.end(), std::ostream_iterator(std::cout)); std::cout
<< std::endl; } return 0; }.
With the biological species concept, the process of speciation is fre.pdf
With the biological species concept, the process of speciation is frequently defined as the
evolution of between populations. reproductive isolation genetic drift gene flow reproductive
inclusion geographic separation The phylogenetic species concept looks at __. environmental
adaptations and morphology species response to adverse conditions and genetic data genetic data
and environmental adaptations morphology and environmental adaptations morphology and
genetic data A phylogenetic species comprise __. interbreeding population that are
reproductively isolated individuals that share measurable traits that distinguish them populations
that share a recent evolutionary history individuals that share a recent evolutionary history one
large gene pool subdivided into local populations
Solution
Reproductive isolation
According to biological species concept, species is a group of actually or potentially
interbreeding individuals who are reproductively isolated from other such groups..
Write a class ArrayList that represents an array of integers. Init.pdf
Write a class ArrayList that represents an array of integers. Initially it has a capacity of 1 and is
“empty”.
At any time, it can be partially full, so it keeps track of its current occupied size, as well as its
capacity
(true size).
Write a class ArrayList that represents an array of integers. Initially it has a capacity of 1 and is
“empty”.
At any time, it can be partially full, so it keeps track of its current occupied size, as well as its
capacity
(true size).
However the output for the prime numbers 1 -50 is incorrect. Displaying numbers like 0, 625 for
prime numbers.
This is my code with the main method below
#include
#include
#include
using namespace std;
class ArrayList
{
private:
int *array;
int capacity, asize;
public:
int size();
ArrayList();
int & operator [](unsigned int);
void push_back(int);
void erase(int m);
string toString();
};
// 1.a: Default constructor used to unitialize the array with capacity=1
ArrayList::ArrayList()
{
asize = 0;
capacity = 1;
array = new int[capacity];
}
// This function returns the actual size of array
int ArrayList::size()
{
return asize;
}
// 1.b:The overloaded [] oprtaor return element at ith position in array
int & ArrayList::operator [](unsigned int i)
{
if(i >= asize)
{
cout << \"invalid reference \";
exit(0);
}
return *(array + i);
}
//1.c: This function push m at the end of the array
void ArrayList::push_back(int m)
{
// this condition checks if size is beyond capacity or not. if so double the capacity.
if(asize == capacity)
{
capacity = 2 * capacity;
int *temp = new int[capacity];
for(int i = 0; i < asize; i++)
temp[i] = array[i];
array = new int[capacity];
for(int i = 0; i < asize; i++)
array[i] = temp[i];
}
array[asize] = m;
asize = asize + 1;
}
void ArrayList::erase(int m){
int pos = -1;
for(int i = 0; i < asize; i++){
if(array[i] == m){
pos = i;
break;
}
}
if(pos == -1){
cout << \"Element not present\ \";
}
else{
for(int i = pos; i < asize - 1; i++){
array[i] = array[i + 1];
}
}
asize--;
if(asize == capacity / 2)
{
capacity = capacity / 2;
int *temp = new int[capacity];
for(int i = 0; i < asize; i++)
temp[i] = array[i];
array = new int[capacity];
for(int i = 0; i < asize; i++)
array[i] = temp[i];
}
}
string ArrayList::toString(){
string str = \"[\";
for(int i = 0; i < asize; i++){
ostringstream oss;
oss << array[i];
str += oss.str();
if(i != asize - 1){
str += \", \";
}
}
str += \"]\";
return str;
}
//---------------------------
//You can test above class by using main() below
int main()
{
ArrayList arr; // call ro default constructor
for (int i = 1; i <= 50; i++)
{
arr.push_back(i); // call to push_back()
}
cout << \"Should contain numbers 1..50, is \";
cout << arr.toString();
cout << \"\ \";
return 0;
}
This is my code with the main method below
#include
#include
#include
using namespace std;
class ArrayList
{
private:
int *array;
int capacity, asize;
public:
int size();
ArrayList();
int & operator [](unsigned int);
void push_back(int);
void erase(int m);
string toString();
};
// 1.a:.
what is the relationship between lnx and 1xSolutionThe relat.pdf
what is the relationship between lnx and 1/x?
Solution
The relation between ln x and (1/x) is explained in terms of definite and indefinte integrals.
Indefinite integral:
Int (1/x) dx + C = lnx +C.
Definite integral:
{Int (1/t) dt from t = 0 to t = x} = lnx.
Or in other words ln (x) is the area under the curve f(x) = ln(t) between the ordinates t= 0 to t =
x, which could be calculated by evaluation of the definite integral Int (1/t)dt from t = 0 to t =x..
Which of these conclusions is supported by plant phylogenies (evolut.pdf
Which of these conclusions is supported by plant phylogenies (evolutionary trees)?
Question 4 options:1)It is likely that the transition to land occurred directly from red algae.2)In
all of the trees generated so far, land plants trace back to more than one ancestral group.3)The
oldest lineages of land plants are descended from some green algae (Charophytes)4)The closest
relative to land plants is fungi
Solution
Answer is option 3) The oldest lineages of land plants are descended from some green algae
(Charophytes)
Land plants evolbed from green algae approximately 510 million years ago. The Charophytes are
still present..
Who are some other individuals who might want to use the informa.pdf
Who are some other individuals who might want to use the information in the financial
statements
Who are some other individuals who might want to use the information in the financial
statements
Who are some other individuals who might want to use the information in the financial
statements
Solution
Some Other Individuals who might use the information in financial statements
1) Suppliers - Suppliers are interested in the information of financial Statements. Suppliers get to
know about solvency and liquidity of company to pay its short term obligations.
2) Employees- Employees use the financial statement information to analyse about the
company\'s ability to pay salary and benefits. Others reasons of using financial statement
information are career development, Financial performance.
3) Customers - Customers use the financial statement information for assessing the company
expansion possibilities, its stability of operations, Its compliances review, for investment
decisions.
Which account below is not a subdivision of owners equityAccumu.pdf
Which account below is not a subdivision of owner\'s equity?
Accumulated Comprehensive Income.
Bond Sinking fund.
Addition Paid-in-Capital.
Retained Earnings.
Accumulated Comprehensive Income.
Bond Sinking fund.
Addition Paid-in-Capital.
Retained Earnings.
Solution
Bonk Sinking Fund not a subdivision of owner\'s equity
Parts of Stockholder Equity are
Capital Stock, Addition Paid-in-Capital, Retained Earnings., Accumulated Comprehensive
Income, Treasury Stock, NONCONTROLLING INTEREST (MINORITY INTEREST).
What is the nucleoid region of a prokaryotic cell a membrane bound .pdf
What is the nucleoid region of a prokaryotic cell? a membrane bound organelle that contains
the DNA a region within the nucleus where parts of ribosomes are made a place within the cell
where DNA is more abundant a place where you\'d expect to find a proton and a neutron
Solution
A place with the cell where DNA is more abundant
The nucleoid refers to an irregularly shaped region within a prokaryotic cell that contains the
genetic material..
Use arrays to store data for analysis. Use functions to perform the .pdf
Use arrays to store data for analysis. Use functions to perform the analysis described below. All
output is to be written to an output file.
Solution
import java.util.Scanner;
import java.util.ArrayList;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.util.ArrayList;
public class DNA{
private String dna;
public DNA(){
}
public void read_store(String filename){
/*try {
Scanner in;
//in = new Scanner(new FileReader(filename));
dna = in.next();
}catch(IOException e){
System.out.println(\"file not there \" + e);
return;
}*/
}
public char compliment_base(char c){
if(c == \'A\') return \'T\';
if(c == \'T\') return \'A\';
if(c == \'G\') return \'C\';
if(c == \'C\') return \'G\';
return \' \';
}
public void DrawDNA(String seq){
System.out.println(\"---+-----+------+------+------\");
for (char c : seq.toCharArray() ) {
System.out.print(c + \" \");
}
System.out.println(\"DNA Sequence \");
System.out.println(\"................................\");
for (char c : seq.toCharArray() ) {
System.out.print(compliment_base(c) + \" \");
}
System.out.println(\" Complement \");
System.out.println(\"---+-----+------+------+------\");
System.out.println(\"\");
}
public void Prefix(int n, String base){
String output = base.substring(0,n);
DrawDNA(output);
}
public static void main(String[] args) {
DNA d = new DNA();
d.DrawDNA(\"ATGC\");
d.Prefix(4,\"ACGTTGCA\");
}
}
---+-----+------+------+------
A T G C DNA Sequence
................................
T A C G Complement
---+-----+------+------+------
---+-----+------+------+------
A C G T DNA Sequence
................................
T G C A Complement
---+-----+------+------+------.
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