tugas matematika 1

1. TUGAS MATEMATIKA 1
Disusun Oleh
Nama : Achmad Trybuana Kurniasandy
Kelas : 1 EA
Jurusan : Teknik Elektronika
Semester : 2 ( DUA )
POLITEKNIK MANUFAKTUR NEGERI BANGKA BELITUNG
2014/2015
Kawasan Industri Air Kantung, Sungailiat-Bangka 33211
Telp : 0717-93586, 95252 Faks : 0717-93585
E-mail : polman@polman-babel.ac.id
Website : http://polman-babel.ac.id

2. Carilah nilai turunan dari fungsi berikut ini !
1. 𝒚 = 𝒙 𝟕
+ 𝟔𝒙 𝟓
+ 𝟏𝟐𝒙 𝟑
Jawaban :
𝑦′
= 7𝑥6
+ 30𝑥4
+ 36𝑥2
2. 𝒚 = 𝒙−𝟓
+ 𝟐𝒙−𝟑
+ 𝟑𝒙−𝟕
Jawaban :
𝑦′
= −5𝑥−6
−6𝑥−4
−21𝑥−8
3. 𝒚 = √𝒙 𝟐 + √ 𝒙 𝟕𝟑
Jawaban :
𝑦 = 𝑥
2
2 + 𝑥
7
3 = 𝑥 + 𝑥
7
3
𝑦′
= 1 +
7
3
𝑥
7
3
−
3
3 = 1 +
7
3
𝑥
4
3
𝑦′ = 1 +
7
3
√ 𝑥43
4. 𝒚 =
𝟐
√𝒙
+
𝟔
√ 𝒙 𝟑
Jawaban :
𝑦 =
2
𝑥
1
2
+
6
𝑥
3
2
= 2𝑥−
1
2 + 6𝑥−
3
2
𝑦′
= 2.−
1
2
. 𝑥−
1
2
−
2
2 + 6.−
3
2
. 𝑥−
3
2
−
2
2 = −𝑥−
3
2−9𝑥−
5
2 = −
1
𝑥
3
2
−
9
𝑥
5
2
𝑦′ = −
1
√ 𝑥3
−
9
√ 𝑥5

3. 5. 𝒚 = 𝒙 𝟐
. 𝐬𝐢𝐧 𝟐𝒙
Jawaban :
𝑢 = 𝑥2
→ 𝑢′
= 2𝑥
𝑣 = sin 2𝑥 → 𝑣′
= 2. cos 𝑥
𝑦′
= 𝑢′
. 𝑣 + 𝑢. 𝑣′
= 2𝑥. sin2𝑥 + 𝑥2
. 2.cos 𝑥
𝑦′ = 2𝑥. sin 2𝑥 + 2𝑥2
.cos 𝑥
6. 𝒚 = ( 𝒙 𝟐
+ 𝟏). 𝐜𝐨𝐬 𝟑𝒙
Jawaban :
𝑢 = 𝑥2
+ 1 → 𝑢′
= 2𝑥
𝑣 = cos 3𝑥 → 𝑣′
= −3.sin 3𝑥
𝑦′
= 𝑢′
. 𝑣 + 𝑢. 𝑣′
= 2𝑥. cos 3𝑥 + ( 𝑥2
+ 1).−3. sin3𝑥
𝑦′ = 2𝑥. cos 3𝑥 + (−3𝑥2
− 3).sin 3𝑥
7. 𝒚 = 𝐬𝐢𝐧 𝟓𝒙 . 𝐭𝐚𝐧 𝟐𝒙
Jawaban :
𝑢 = sin 5𝑥 → 𝑢′
= 5.cos 5𝑥
𝑣 = tan 2𝑥 → 𝑣′
= 2. 𝑠𝑒𝑐2
2𝑥
𝑦′
= 𝑢′
. 𝑣 + 𝑢. 𝑣′
= 5.cos 5𝑥 . tan 2𝑥 + sin 5𝑥 . 2. 𝑠𝑒𝑐2
2𝑥
𝑦′
= 5.cos 5𝑥. tan 2𝑥 + 2. sin5𝑥 . 𝑠𝑒𝑐2
2𝑥
8. 𝒚 = 𝐜𝐨𝐬 𝟑𝒙 . 𝐜𝐨𝐭 𝟒𝒙
Jawaban :
𝑢 = cos 3𝑥 → 𝑢′
= −3. sin3𝑥
𝑣 = cot4𝑥 → 𝑣′
= −4. 𝑐𝑠𝑐2
4𝑥
𝑦′
= 𝑢′
. 𝑣 + 𝑢. 𝑣′
= −3.sin 3𝑥 . cot4𝑥 + cos 3𝑥 .−4. 𝑐𝑠𝑐2
4𝑥

4. 𝑦′
= −3.sin 3𝑥 . cot4𝑥 − 4. cos 3𝑥 . 𝑐𝑠𝑐2
4𝑥
9. 𝒚 =
𝐬𝐢𝐧 𝟓𝒙
𝐜𝐨𝐬 𝟕𝒙
Jawaban :
𝑢 = sin 5𝑥 → 𝑢′
= 5.cos 5𝑥
𝑣 = cos 7𝑥 → 𝑣′
= −7.sin 7𝑥
𝑦′
=
𝑢′
. 𝑣 − 𝑢. 𝑣′
𝑣2
=
5.cos 5𝑥 . cos 7𝑥 − sin5𝑥 . −7.sin 7𝑥
(cos 7𝑥)2
𝑦′
=
5.cos 5𝑥. cos 7𝑥 + 7.sin 5𝑥 . sin7𝑥
𝑐𝑜𝑠27𝑥
10. 𝒚 =
𝐜𝐨𝐬 𝟔𝒙
𝐭𝐚𝐧 𝟐𝒙
Jawaban :
𝑢 = cos 6𝑥 → 𝑢′
= −6. sin6𝑥
𝑣 = tan 2𝑥 → 𝑣′
= 2. 𝑠𝑒𝑐2
2𝑥
𝑦′
=
𝑢′
. 𝑣 − 𝑢. 𝑣′
𝑣2
=
−6.sin 6𝑥. tan2𝑥 − cos 6𝑥. 2. 𝑠𝑒𝑐2
2𝑥
(tan 2𝑥)2
𝑦′
=
−6.sin 6𝑥. tan 2𝑥 − 2.cos 6𝑥. 𝑠𝑒𝑐2
2𝑥
𝑡𝑎𝑛22𝑥