TLC can be used to help determine the number of components in a mixt.pdf
•
0 likes•4 views
TLC can be used to help determine the number of components in a mixture, the identity of compounds, and the purity of a compound. By observing the appearance of a product or the disappearance of a reactant, it can also be used to monitor the progress of a reaction. The sample is applied to the layer of adsorbent, near one edge, as a small spot of a solution. After the solvent has evaporated, the adsorbent-coated sheet is propped more or less vertically in a closed container, with the edge to which the spot was applied down. The spot on the thin layer plate must be positioned above the level of the solvent in the container .If it is below the level of the solvent, the spot will be washed off the plate into the developing solvent. The solvent, which is in the bottom of the container, creeps up the layer of adsorbent, passes over the spot, and, as it continues up, effects a separation of the materials in the spot (\"develops\" the chromatogram). When the solvent front has nearly reached nearly the top of the adsorbent, the thin layer plate is removed from the container. Solution TLC can be used to help determine the number of components in a mixture, the identity of compounds, and the purity of a compound. By observing the appearance of a product or the disappearance of a reactant, it can also be used to monitor the progress of a reaction. The sample is applied to the layer of adsorbent, near one edge, as a small spot of a solution. After the solvent has evaporated, the adsorbent-coated sheet is propped more or less vertically in a closed container, with the edge to which the spot was applied down. The spot on the thin layer plate must be positioned above the level of the solvent in the container .If it is below the level of the solvent, the spot will be washed off the plate into the developing solvent. The solvent, which is in the bottom of the container, creeps up the layer of adsorbent, passes over the spot, and, as it continues up, effects a separation of the materials in the spot (\"develops\" the chromatogram). When the solvent front has nearly reached nearly the top of the adsorbent, the thin layer plate is removed from the container..
Report
Share
Report
Share
Download to read offline
Recommended
TLC is a simple, quick, and inexpensive procedure.pdf
TLC is a simple, quick, and inexpensive procedure that gives the chemist a quick
answer as to how many components are in a mixture. TLC is also used to support the identity of
a compound in a mixture when the Rf of a compound is compared with the Rf of a known
compound (preferably both run on the same TLC plate). A TLC plate is a sheet of glass, metal,
or plastic which is coated with a thin layer of a solid adsorbent (usually silica or alumina). A
small amount of the mixture to be analyzed is spotted near the bottom of this plate. The TLC
plate is then placed in a shallow pool of a solvent in a developing chamber so that only the very
bottom of the plate is in the liquid. This liquid, or the eluent, is the mobile phase, and it slowly
rises up the TLC plate by capillary action. As the solvent moves past the spot that was applied,
an equilibrium is established for each component of the mixture between the molecules of that
component which are adsorbed on the solid and the molecules which are in solution. In principle,
the components will differ in solubility and in the strength of their adsorption to the adsorbent
and some components will be carried farther up the plate than others. When the solvent has
reached the top of the plate, the plate is removed from the developing chamber, dried, and the
separated components of the mixture are visualized. If the compounds are colored, visualization
is straightforward. Usually the compounds are not colored, so a UV lamp is used to visualize the
plates. (The plate itself contains a fluorescent dye which glows everywhere except where an
organic compound is on the plate.)
Solution
TLC is a simple, quick, and inexpensive procedure that gives the chemist a quick
answer as to how many components are in a mixture. TLC is also used to support the identity of
a compound in a mixture when the Rf of a compound is compared with the Rf of a known
compound (preferably both run on the same TLC plate). A TLC plate is a sheet of glass, metal,
or plastic which is coated with a thin layer of a solid adsorbent (usually silica or alumina). A
small amount of the mixture to be analyzed is spotted near the bottom of this plate. The TLC
plate is then placed in a shallow pool of a solvent in a developing chamber so that only the very
bottom of the plate is in the liquid. This liquid, or the eluent, is the mobile phase, and it slowly
rises up the TLC plate by capillary action. As the solvent moves past the spot that was applied,
an equilibrium is established for each component of the mixture between the molecules of that
component which are adsorbed on the solid and the molecules which are in solution. In principle,
the components will differ in solubility and in the strength of their adsorption to the adsorbent
and some components will be carried farther up the plate than others. When the solvent has
reached the top of the plate, the plate is removed from the developing chamber, dried, and the
separated components of the mixture.
last updated Friday, August 14, 2009 Introductio.pdf
last updated Friday, August 14, 2009 Introduction Thin-layer chromatography
(TLC) is a very commonly used technique in synthetic chemistry for identifying compounds,
determining their purity and following the progress of a reaction. It also permits the optimization
of the solvent system for a given separation problem. In comparison with column
chromatography, it only requires small quantities of the compound (~ng) and is much faster as
well. Stationary Phase As stationary phase, a special finely ground matrix (silica gel, alumina,
or similar material) is coated on a glass plate, a metal or a plastic film as a thin layer (~0.25 mm).
In addition a binder like gypsum is mixed into the stationary phase to make it stick better to the
slide. In many cases, a fluorescent powder is mixed into the stationary phase to simplify the
visualization later on (e.g. bright green when you expose it to 254 nm UV light). Preparing the
Plate Do not touch the TLC plate on the side with the white surface. In order to obtain an
imaginary start line, make two notches on each side of the TLC plate. You can also draw a thin
line with pencil. Do not use pen. Why? The start line should be 0.5-1 cm from the bottom of the
plate. Capillary spotters Place a melting point capillary and in the dark blue part of the
Bunsen burner flame. Hold it there until it softens and starts to sag. Quickly remove the capillary
from the flame and pull on both ends to about 2-3 times its original length. If you pull the
capillary inside the flame, you will have a \"piece of art\", but not a good spotter. Allow the
capillary to cool down, and then break it in the middle. Make sure that you break off the closed
end on one of them. Do not use gloves when you pull capillaries. You will have much better
control without them! Watch movie how to pull capillaries here here Spotting the plate The
thin end of the spotter is placed in the dilute solution; the solution will rise up in the capillary
(capillary forces). Touch the plate briefly at the start line. Allow the solvent to evaporate and
spot at the same place again. This way you will get a concentrated and small spot. Try to avoid
spotting too much material, because this will deteriorate the quality of the separation
considerably (‘tailing’). The spots should be far enough away from the edges and from each
other as well. If possible, you should spot the compound or mixture together with the starting
materials and possible intermediates on the plate. They will serve as internal reference since
every TLC plate is slightly different. Developing a Plate A TLC plate can be developed in a
beaker or closed jar (see picture below). Place a small amount of solvent (= mobile phase) in the
container. The solvent level has to be below the starting line of the TLC, otherwise the spots will
dissolve away. The lower edge of the plate is then dipped in a solvent. The solvent (eluent)
travels up the matrix by capillarity, moving the components of the samples at v.
Thin Layer Chromatography and HighPerformance Thin Layer chromatography
It helps for the pharmacy and Ayurveda stydents
THIN LAYER CHROMATOGRAPHY (1).pptx
Thin Layer Chromatography is a technique used to isolate non-volatile mixtures. The experiment is conducted on a sheet of aluminium foil, plastic, or glass which is coated with a thin layer of adsorbent material. The material usually used is aluminium oxide, cellulose, or silica gel.
Recommended
TLC is a simple, quick, and inexpensive procedure.pdf
TLC is a simple, quick, and inexpensive procedure that gives the chemist a quick
answer as to how many components are in a mixture. TLC is also used to support the identity of
a compound in a mixture when the Rf of a compound is compared with the Rf of a known
compound (preferably both run on the same TLC plate). A TLC plate is a sheet of glass, metal,
or plastic which is coated with a thin layer of a solid adsorbent (usually silica or alumina). A
small amount of the mixture to be analyzed is spotted near the bottom of this plate. The TLC
plate is then placed in a shallow pool of a solvent in a developing chamber so that only the very
bottom of the plate is in the liquid. This liquid, or the eluent, is the mobile phase, and it slowly
rises up the TLC plate by capillary action. As the solvent moves past the spot that was applied,
an equilibrium is established for each component of the mixture between the molecules of that
component which are adsorbed on the solid and the molecules which are in solution. In principle,
the components will differ in solubility and in the strength of their adsorption to the adsorbent
and some components will be carried farther up the plate than others. When the solvent has
reached the top of the plate, the plate is removed from the developing chamber, dried, and the
separated components of the mixture are visualized. If the compounds are colored, visualization
is straightforward. Usually the compounds are not colored, so a UV lamp is used to visualize the
plates. (The plate itself contains a fluorescent dye which glows everywhere except where an
organic compound is on the plate.)
Solution
TLC is a simple, quick, and inexpensive procedure that gives the chemist a quick
answer as to how many components are in a mixture. TLC is also used to support the identity of
a compound in a mixture when the Rf of a compound is compared with the Rf of a known
compound (preferably both run on the same TLC plate). A TLC plate is a sheet of glass, metal,
or plastic which is coated with a thin layer of a solid adsorbent (usually silica or alumina). A
small amount of the mixture to be analyzed is spotted near the bottom of this plate. The TLC
plate is then placed in a shallow pool of a solvent in a developing chamber so that only the very
bottom of the plate is in the liquid. This liquid, or the eluent, is the mobile phase, and it slowly
rises up the TLC plate by capillary action. As the solvent moves past the spot that was applied,
an equilibrium is established for each component of the mixture between the molecules of that
component which are adsorbed on the solid and the molecules which are in solution. In principle,
the components will differ in solubility and in the strength of their adsorption to the adsorbent
and some components will be carried farther up the plate than others. When the solvent has
reached the top of the plate, the plate is removed from the developing chamber, dried, and the
separated components of the mixture.
last updated Friday, August 14, 2009 Introductio.pdf
last updated Friday, August 14, 2009 Introduction Thin-layer chromatography
(TLC) is a very commonly used technique in synthetic chemistry for identifying compounds,
determining their purity and following the progress of a reaction. It also permits the optimization
of the solvent system for a given separation problem. In comparison with column
chromatography, it only requires small quantities of the compound (~ng) and is much faster as
well. Stationary Phase As stationary phase, a special finely ground matrix (silica gel, alumina,
or similar material) is coated on a glass plate, a metal or a plastic film as a thin layer (~0.25 mm).
In addition a binder like gypsum is mixed into the stationary phase to make it stick better to the
slide. In many cases, a fluorescent powder is mixed into the stationary phase to simplify the
visualization later on (e.g. bright green when you expose it to 254 nm UV light). Preparing the
Plate Do not touch the TLC plate on the side with the white surface. In order to obtain an
imaginary start line, make two notches on each side of the TLC plate. You can also draw a thin
line with pencil. Do not use pen. Why? The start line should be 0.5-1 cm from the bottom of the
plate. Capillary spotters Place a melting point capillary and in the dark blue part of the
Bunsen burner flame. Hold it there until it softens and starts to sag. Quickly remove the capillary
from the flame and pull on both ends to about 2-3 times its original length. If you pull the
capillary inside the flame, you will have a \"piece of art\", but not a good spotter. Allow the
capillary to cool down, and then break it in the middle. Make sure that you break off the closed
end on one of them. Do not use gloves when you pull capillaries. You will have much better
control without them! Watch movie how to pull capillaries here here Spotting the plate The
thin end of the spotter is placed in the dilute solution; the solution will rise up in the capillary
(capillary forces). Touch the plate briefly at the start line. Allow the solvent to evaporate and
spot at the same place again. This way you will get a concentrated and small spot. Try to avoid
spotting too much material, because this will deteriorate the quality of the separation
considerably (‘tailing’). The spots should be far enough away from the edges and from each
other as well. If possible, you should spot the compound or mixture together with the starting
materials and possible intermediates on the plate. They will serve as internal reference since
every TLC plate is slightly different. Developing a Plate A TLC plate can be developed in a
beaker or closed jar (see picture below). Place a small amount of solvent (= mobile phase) in the
container. The solvent level has to be below the starting line of the TLC, otherwise the spots will
dissolve away. The lower edge of the plate is then dipped in a solvent. The solvent (eluent)
travels up the matrix by capillarity, moving the components of the samples at v.
Thin Layer Chromatography and HighPerformance Thin Layer chromatography
It helps for the pharmacy and Ayurveda stydents
THIN LAYER CHROMATOGRAPHY (1).pptx
Thin Layer Chromatography is a technique used to isolate non-volatile mixtures. The experiment is conducted on a sheet of aluminium foil, plastic, or glass which is coated with a thin layer of adsorbent material. The material usually used is aluminium oxide, cellulose, or silica gel.
Thin layer chromatography faculty of pharmacy zagazig university
this power point was mede by Dena ezzat , a pharmacist student in third year . this persentation in phytochemistry subject.
Thin Layer Chromatography
introduction, history, principle, experimental techniques, evaluation on chromatogram, adv. & dis-adv., common problems, comparision, applications and analysis of drugs through TLC(2000-2017)
Thin-Layer-Chromatography-of-inkdyes.pdf
Chemistry paractical
Titration of a paper
Paper chromatography
Uses of a chemistry
Uses of a computer
Chromatography
brief view of chromatography and its types
types of chromatography based on its classification
procedure used in it and types of resins used
Paper Chromatography.pptx
Chromatography, Chromatographic terms
Stationary Phase : Liquid, deposited in network of cellulose fibers.
-Mobile Phase : Liquid, solvent(single or mixture)
Filter Paper
Solvent System
Spraying reagentsSpraying reagents
DnaAORC This protein is responsible for initiation of DNA replicat.pdf
DnaA/ORC: This protein is responsible for initiation of DNA replication. When DNA replication
is temperature sensitive, it affects the function of Dna A/ ORC. It cannot bind to the N-terminus
and thus DNA replication is immediately stopped. So with the increase in temperature, there is
quick stop of the DNA replication.
SSB/RPA: This is the protein complex which acts on the single stranded DNA complex. In the
presences on non-permissible temperatures, this protein complex will quick stop the process of
DNA replication. Thus replication fork is not formed since it requires presence of one of the
proteins from the complex. It can be said that since the process is of so high order, quick stop
mutation takes please due to non- permissible temperature.
DnaB/Mcm: this protein complex is responsible for separating the DNA strand. With the
increase in temperature, the protein cannot separate the DNA strands. Thus DNA replication
stops immediately. Thus it is a quick stop type mutanation.
DNA ligase: there 3 major functions of DNA ligase 1) It seals the repairs in the DNA 2) Joins
the recombinant fragment and 3) it joins Okazaki fragment. When there is temperature sensitive
mutants, DNA ligase will follow the process of slow stop mutants. It is because DNA replication
has taken place only sealing part is left. So DNA replication will be completed but Okazaki
fragments will not be joined.
Solution
DnaA/ORC: This protein is responsible for initiation of DNA replication. When DNA replication
is temperature sensitive, it affects the function of Dna A/ ORC. It cannot bind to the N-terminus
and thus DNA replication is immediately stopped. So with the increase in temperature, there is
quick stop of the DNA replication.
SSB/RPA: This is the protein complex which acts on the single stranded DNA complex. In the
presences on non-permissible temperatures, this protein complex will quick stop the process of
DNA replication. Thus replication fork is not formed since it requires presence of one of the
proteins from the complex. It can be said that since the process is of so high order, quick stop
mutation takes please due to non- permissible temperature.
DnaB/Mcm: this protein complex is responsible for separating the DNA strand. With the
increase in temperature, the protein cannot separate the DNA strands. Thus DNA replication
stops immediately. Thus it is a quick stop type mutanation.
DNA ligase: there 3 major functions of DNA ligase 1) It seals the repairs in the DNA 2) Joins
the recombinant fragment and 3) it joins Okazaki fragment. When there is temperature sensitive
mutants, DNA ligase will follow the process of slow stop mutants. It is because DNA replication
has taken place only sealing part is left. So DNA replication will be completed but Okazaki
fragments will not be joined..
Answer(19)Mary’s parents are normal, therefore her brother must.pdf
Answer:
(19)
Mary’s parents are normal, therefore her brother must have got the disease allele from his mother
who is a carrier of the disease.
Parents
XY (Mary’s father) x XhX (Mary’s mother)
XhY (Mary’s brother)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
(a) Therefore Mary has 50% chance or ½ chance of being a carrier
(b) (c) and (d)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
Among mary’s sons, one will be a carrier and another will be hemophiliac
Among mary’s daughters, one will be a carrier and another will be normal
(e) the carrier daughter can transmit the disease to her son’s
Solution
Answer:
(19)
Mary’s parents are normal, therefore her brother must have got the disease allele from his mother
who is a carrier of the disease.
Parents
XY (Mary’s father) x XhX (Mary’s mother)
XhY (Mary’s brother)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
(a) Therefore Mary has 50% chance or ½ chance of being a carrier
(b) (c) and (d)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
Among mary’s sons, one will be a carrier and another will be hemophiliac
Among mary’s daughters, one will be a carrier and another will be normal
(e) the carrier daughter can transmit the disease to her son’s.
More Related Content
Similar to TLC can be used to help determine the number of components in a mixt.pdf
Thin layer chromatography faculty of pharmacy zagazig university
this power point was mede by Dena ezzat , a pharmacist student in third year . this persentation in phytochemistry subject.
Thin Layer Chromatography
introduction, history, principle, experimental techniques, evaluation on chromatogram, adv. & dis-adv., common problems, comparision, applications and analysis of drugs through TLC(2000-2017)
Thin-Layer-Chromatography-of-inkdyes.pdf
Chemistry paractical
Titration of a paper
Paper chromatography
Uses of a chemistry
Uses of a computer
Chromatography
brief view of chromatography and its types
types of chromatography based on its classification
procedure used in it and types of resins used
Paper Chromatography.pptx
Chromatography, Chromatographic terms
Stationary Phase : Liquid, deposited in network of cellulose fibers.
-Mobile Phase : Liquid, solvent(single or mixture)
Filter Paper
Solvent System
Spraying reagentsSpraying reagents
Similar to TLC can be used to help determine the number of components in a mixt.pdf (20)
column chromatography details about column preparation
column chromatography details about column preparation
Thin layer chromatography faculty of pharmacy zagazig university
Thin layer chromatography faculty of pharmacy zagazig university
More from aquacosmossystems
DnaAORC This protein is responsible for initiation of DNA replicat.pdf
DnaA/ORC: This protein is responsible for initiation of DNA replication. When DNA replication
is temperature sensitive, it affects the function of Dna A/ ORC. It cannot bind to the N-terminus
and thus DNA replication is immediately stopped. So with the increase in temperature, there is
quick stop of the DNA replication.
SSB/RPA: This is the protein complex which acts on the single stranded DNA complex. In the
presences on non-permissible temperatures, this protein complex will quick stop the process of
DNA replication. Thus replication fork is not formed since it requires presence of one of the
proteins from the complex. It can be said that since the process is of so high order, quick stop
mutation takes please due to non- permissible temperature.
DnaB/Mcm: this protein complex is responsible for separating the DNA strand. With the
increase in temperature, the protein cannot separate the DNA strands. Thus DNA replication
stops immediately. Thus it is a quick stop type mutanation.
DNA ligase: there 3 major functions of DNA ligase 1) It seals the repairs in the DNA 2) Joins
the recombinant fragment and 3) it joins Okazaki fragment. When there is temperature sensitive
mutants, DNA ligase will follow the process of slow stop mutants. It is because DNA replication
has taken place only sealing part is left. So DNA replication will be completed but Okazaki
fragments will not be joined.
Solution
DnaA/ORC: This protein is responsible for initiation of DNA replication. When DNA replication
is temperature sensitive, it affects the function of Dna A/ ORC. It cannot bind to the N-terminus
and thus DNA replication is immediately stopped. So with the increase in temperature, there is
quick stop of the DNA replication.
SSB/RPA: This is the protein complex which acts on the single stranded DNA complex. In the
presences on non-permissible temperatures, this protein complex will quick stop the process of
DNA replication. Thus replication fork is not formed since it requires presence of one of the
proteins from the complex. It can be said that since the process is of so high order, quick stop
mutation takes please due to non- permissible temperature.
DnaB/Mcm: this protein complex is responsible for separating the DNA strand. With the
increase in temperature, the protein cannot separate the DNA strands. Thus DNA replication
stops immediately. Thus it is a quick stop type mutanation.
DNA ligase: there 3 major functions of DNA ligase 1) It seals the repairs in the DNA 2) Joins
the recombinant fragment and 3) it joins Okazaki fragment. When there is temperature sensitive
mutants, DNA ligase will follow the process of slow stop mutants. It is because DNA replication
has taken place only sealing part is left. So DNA replication will be completed but Okazaki
fragments will not be joined..
Answer(19)Mary’s parents are normal, therefore her brother must.pdf
Answer:
(19)
Mary’s parents are normal, therefore her brother must have got the disease allele from his mother
who is a carrier of the disease.
Parents
XY (Mary’s father) x XhX (Mary’s mother)
XhY (Mary’s brother)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
(a) Therefore Mary has 50% chance or ½ chance of being a carrier
(b) (c) and (d)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
Among mary’s sons, one will be a carrier and another will be hemophiliac
Among mary’s daughters, one will be a carrier and another will be normal
(e) the carrier daughter can transmit the disease to her son’s
Solution
Answer:
(19)
Mary’s parents are normal, therefore her brother must have got the disease allele from his mother
who is a carrier of the disease.
Parents
XY (Mary’s father) x XhX (Mary’s mother)
XhY (Mary’s brother)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
(a) Therefore Mary has 50% chance or ½ chance of being a carrier
(b) (c) and (d)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
Among mary’s sons, one will be a carrier and another will be hemophiliac
Among mary’s daughters, one will be a carrier and another will be normal
(e) the carrier daughter can transmit the disease to her son’s.
Answer Q1. Red mangroove is the last mangroove to colonise on the.pdf
Answer :
Q1. Red mangroove is the last mangroove to colonise on the shore line
Q2. The melon of Dolphins are used for the focusing of sound pulses.
Q4. Coral reef accounts for the largest pecentage of the oceans primary
Solution
Answer :
Q1. Red mangroove is the last mangroove to colonise on the shore line
Q2. The melon of Dolphins are used for the focusing of sound pulses.
Q4. Coral reef accounts for the largest pecentage of the oceans primary.
An Arrhenius acid produces H+ ions insolutionA Bronsted-Lowry acid.pdf
An Arrhenius acid produces H+ ions insolution
A Bronsted-Lowry acid is a protoon donor.
A Lewis base is an eelectron pair donor.
Water could behave as an Arrhenius acid, Bronsted-Lowryacid, and a Lewis base.
Water acting as an arrhenius acid: Water acts as asArrhenius acid as it is capable of producing
protons insolution.
H2O (l) H+ (aq) + OH-(aq)
Water acting as a Bronsted-Lowry acid: Water acts as aBronsted-Lowry acid as it can donate H+
to a base.
H2O (l) + NH3 (aq) NH4+ (aq) + OH- (aq)
Water acting as a Lewis base: Water acts as a Lewis baseas it can donate the lone pair of
electrons present on the Oxygenatom.
Al+3 (aq) + H2O (l) Al(H2O)6+3 (aq)
Solution
An Arrhenius acid produces H+ ions insolution
A Bronsted-Lowry acid is a protoon donor.
A Lewis base is an eelectron pair donor.
Water could behave as an Arrhenius acid, Bronsted-Lowryacid, and a Lewis base.
Water acting as an arrhenius acid: Water acts as asArrhenius acid as it is capable of producing
protons insolution.
H2O (l) H+ (aq) + OH-(aq)
Water acting as a Bronsted-Lowry acid: Water acts as aBronsted-Lowry acid as it can donate H+
to a base.
H2O (l) + NH3 (aq) NH4+ (aq) + OH- (aq)
Water acting as a Lewis base: Water acts as a Lewis baseas it can donate the lone pair of
electrons present on the Oxygenatom.
Al+3 (aq) + H2O (l) Al(H2O)6+3 (aq).
Ans. One of the main disadvantage is chromatic aberrasion. A more li.pdf
Ans. One of the main disadvantage is chromatic aberrasion. A more likely cost of trichromacy
arises when an image is sampled by receptors with differing spectral sensivities because it is not
possible to separate luminanance information.
Solution
Ans. One of the main disadvantage is chromatic aberrasion. A more likely cost of trichromacy
arises when an image is sampled by receptors with differing spectral sensivities because it is not
possible to separate luminanance information..
A coordination problem occurs in situations where there is no Nash E.pdf
A coordination problem occurs in situations where there is no Nash Equilibrium or there is more
than one Nash Equilibrium. it also occure when there is a unique but undireable Nash
Equilibrium.
Option (B), Option (D) and option (E) is correct answer.
Solution
A coordination problem occurs in situations where there is no Nash Equilibrium or there is more
than one Nash Equilibrium. it also occure when there is a unique but undireable Nash
Equilibrium.
Option (B), Option (D) and option (E) is correct answer..
1. When an integrated F plasmid leaves the chromosome it may take so.pdf
1. When an integrated F plasmid leaves the chromosome it may take some chromosomal genes
from one side of the integration site and it results in F\' cells. Integration of F plasmid into the
host chromosome results in Hfr (High frequency of recombination) cells
2. Genetic transfer in Archaea is by means of horizontal gene transfer where genes can be
transfered from one to other similar to bacteria conjugation or transduction.
3. Methanogenesis is the formation of methane by the methanogens. Methanogenesis actually
complete the decomposition process. The semi-final products of decomposition like carbon
dioxide, small organics and hydrogen are completely removed. If methanogenesis does not
happen, it leads to accumulation of carbon in anaerobic envrionment. Methanogens belong to
group archaea.
4. To resist high temperatures in the environment, bacteria convert all its unsaturated fatty acids
in the membrane to saturated fatty acids. It prevents the denaturation of enzymes and proteins in
the cell.
5. Methanogenesis takes place in Anaerobic condition because oxygen inhibits the growth of
methanogens.
Solution
1. When an integrated F plasmid leaves the chromosome it may take some chromosomal genes
from one side of the integration site and it results in F\' cells. Integration of F plasmid into the
host chromosome results in Hfr (High frequency of recombination) cells
2. Genetic transfer in Archaea is by means of horizontal gene transfer where genes can be
transfered from one to other similar to bacteria conjugation or transduction.
3. Methanogenesis is the formation of methane by the methanogens. Methanogenesis actually
complete the decomposition process. The semi-final products of decomposition like carbon
dioxide, small organics and hydrogen are completely removed. If methanogenesis does not
happen, it leads to accumulation of carbon in anaerobic envrionment. Methanogens belong to
group archaea.
4. To resist high temperatures in the environment, bacteria convert all its unsaturated fatty acids
in the membrane to saturated fatty acids. It prevents the denaturation of enzymes and proteins in
the cell.
5. Methanogenesis takes place in Anaerobic condition because oxygen inhibits the growth of
methanogens..
1. A DNA molecule contains two strands of poly deoxyribonucleotide s.pdf
1. A DNA molecule contains two strands of poly deoxyribonucleotide strands twisted together to
form a double helix. The two strands are antiparallel, i.e., one strand runs in the 5’ to 3’ direction
while the other in 3’ to 5’ direction. The sugar-phosphate backbone is found on the exterior of
this helix and the bases are branching towards the center.
RNA, in the majority cases, consists of one strand (polymer of ribonucleotides) of nucleic acids
linked together by 3\',5\'-phosphodiester bonds.
2. The mRNA molecules which are transcribed from genes of the total genome and have the base
sequence complementary to DNA, carry DNA,s genetic information\'s for the assembly of amino
acids into the polypeptide chains, to the cytoplasmic sites of protein synthesis, the ribosomes. to
which they become associated to participate in codon-anticodon interaction with tRNA, are
called informational or messenger RNAs (mRNA) .
Solution
1. A DNA molecule contains two strands of poly deoxyribonucleotide strands twisted together to
form a double helix. The two strands are antiparallel, i.e., one strand runs in the 5’ to 3’ direction
while the other in 3’ to 5’ direction. The sugar-phosphate backbone is found on the exterior of
this helix and the bases are branching towards the center.
RNA, in the majority cases, consists of one strand (polymer of ribonucleotides) of nucleic acids
linked together by 3\',5\'-phosphodiester bonds.
2. The mRNA molecules which are transcribed from genes of the total genome and have the base
sequence complementary to DNA, carry DNA,s genetic information\'s for the assembly of amino
acids into the polypeptide chains, to the cytoplasmic sites of protein synthesis, the ribosomes. to
which they become associated to participate in codon-anticodon interaction with tRNA, are
called informational or messenger RNAs (mRNA) ..
Ethyl 4-aminobenzoate is a basic organic compound. In basic and neut.pdf
Ethyl 4-aminobenzoate is a basic organic compound. In basic and neutral solutions, it will be
insoluble in water. However, in acidic solutions, the amino group will be protonated, formed a
charged salt species. As with normal salts, this is water-soluble. So; 1.0 M HCl: soluble 1.0 M
NaOH and Water: insoluble.
Solution
Ethyl 4-aminobenzoate is a basic organic compound. In basic and neutral solutions, it will be
insoluble in water. However, in acidic solutions, the amino group will be protonated, formed a
charged salt species. As with normal salts, this is water-soluble. So; 1.0 M HCl: soluble 1.0 M
NaOH and Water: insoluble..
draw a sphere and use raytracing on the sphere in OpenGL glut. .pdf
/* draw a sphere and use raytracing on the sphere in OpenGL glut. */
#include
#include
#include
#include
#include
#define screen_width 750
#define screen_height 750
#define true 1
#define false 0
#define perpendicular 0
int gridXsize = 20;
int gridZsize = 20;
float plane[] = {0.0, 1.0, 0.0, -50.0,};
float sphere[] = {250.0, 270.0, -100.0, 100.0};
float eye[] = {0.0, 400.0, 550.0};
float light[] = {250.0, 550.0, -200.0};
float dot(float *u, float *v)
{
return u[0]*v[0] + u[1]*v[1] + u[2]*v[2];
}
void norm(float *u)
{
float norm = sqrt(abs(dot(u,u)));
for (int i =0; i <3; i++)
{
u[i] = u[i]/norm;
}
}
float plane_intersect(float *u, float *pO)
{
float normt[3] = {plane[0], plane[1], plane[2]};
float s;
if (dot(u,normt) == 0)
{
s = -10;
}
else
{
s = (plane[3]-(dot(pO,normt)))/(dot(u,normt));
}
return s;
}
float sphere_intersect(float *u, float *pO)
{
float deltaP[3] = {sphere[0]-pO[0],sphere[1]-pO[1],sphere[2]-pO[2]};
float deltLen = sqrt(abs(dot(deltaP,deltaP)));
float t=0;
float answer;
float det;
if ((det =(abs(dot(u,deltaP)*dot(u,deltaP))- (deltLen*deltLen)+sphere[3]*sphere[3])) < 0)
{
answer = -10;
}
else
{
t =-1*dot(u,deltaP)- sqrt(det) ;
if (t>0)
{
answer = t;
}
else
{
answer = -10;
}
}
return answer;
}
void find_reflect(float *u, float s, float *pO)
{
float n[3] = {pO[0]+s *u[0]-sphere[0],pO[1]+s *u[1]-sphere[1],pO[2]+s *u[2]- sphere[2]};
float l[3] = {s *u[0],s *u[1],s *u[2]};
u[0] =(2*dot(l,n)*n[0])-l[0];
u[1] = (2*dot(l,n)*n[1])-l[1];
u[2] = (2*dot(l,n)*n[2])-l[2];
}
float find_shade(float *u,float s, float *pO)
{
float answer;
float lightVec[3] = {light[0]-(pO[0]+s *u[0]), light[1]-(pO[1]+s *u[1]), light[2]-(pO[2]+s
*u[2])};
float n[3] = {pO[0]+s *u[0]-sphere[0],pO[1]+s *u[1]-sphere[1],pO[2]+s *u[2]-sphere[2]};
answer = -1*dot(lightVec,n)/(sqrt(abs(dot(lightVec,lightVec)))*sqrt(abs(dot(n,n))));
return answer;
}
void init()
{
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
gluOrtho2D(0,screen_width,0,screen_height);
}
void display()
{
glClear(GL_COLOR_BUFFER_BIT| GL_DEPTH_BUFFER_BIT);
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
for (int i=0; i < screen_width; i++)
{
for (int j=0; j < screen_height; j++)
{
float ray[3] = {1*(eye[0]-i),-1*(eye[1]-j),1*eye[2]};
float point[3] = {i,j,0};
norm(ray);
int plotted = false;
while (!plotted)
{
float s_plane = plane_intersect(ray, point);
float s_sphere = sphere_intersect(ray, point);
if (s_plane <= 0 && s_sphere <=0)
{
glColor3f(0,0,0);
glBegin(GL_POINTS);
glVertex3f(i,j,0);
glEnd();
plotted = true;
}
else if (s_sphere >= 0 && (s_plane <=0 || s_sphere <= s_plane))
{
find_reflect(ray, s_sphere, point);
}
else if (s_plane >=0 && (s_sphere <=0 ||s_plane <= s_sphere))
{
float shade = find_shade(ray, s_plane, point);
float xx = s_plane*ray[0] + eye[0];
float z = s_plane*ray[2] + eye[2];
if (abs((int)xx/gridXsize)%2 == abs((int)z/gridZsize)%2)
{
glColor3f(shade,0,0);
}
else
{
glColor3f(shade,shade,shade);
}
glBegin(GL_POINTS);
glVertex3f(i,j,0);
glEnd();
plotted = true;
}
}
}
}
glFlush();
}
int main(.
SnO2 (ore) is initially washed and dressed. then .pdf
SnO2 (ore) is initially washed and dressed. then it is treated with red hot
coke/coall(acts as reducing agent) SnO2(s) + C(s)---------> Sn(molten) +CO(g) thus obtained
molten Sn is cooled to Pure solid form
Solution
SnO2 (ore) is initially washed and dressed. then it is treated with red hot
coke/coall(acts as reducing agent) SnO2(s) + C(s)---------> Sn(molten) +CO(g) thus obtained
molten Sn is cooled to Pure solid form.
d) Valine Note its side chain doesnt contain a.pdf
d) Valine Note: its side chain doesn\'t contain acidic H such as those in NH or
COOH group. Thus, pH value doesn\'t affect the charge since no protonation or deprotonation
happens.
Solution
d) Valine Note: its side chain doesn\'t contain acidic H such as those in NH or
COOH group. Thus, pH value doesn\'t affect the charge since no protonation or deprotonation
happens..
Amphiprotic. The preferred term is amphoteric. A .pdf
Amphiprotic. The preferred term is amphoteric. A compound that is amphoteric can
behave as either an acid or a base. These are most commonly explained when using the
Bronsted-Lowry theory of acids and bases. Sorry. NONE of these are amphoteric (or
amphiprotic). In order to behave as a Bronsted-Lowry acid it must donate a proton. That
narrows it down to HCl and HSO4-. In order to behave as a base it must accept a proton. A, D
and E can all accept protons. HCl is a strong acid and dissociates to form H+ and Cl-. There is
no tendency to gain a proton. HSO4- is a weak acid and can donate a proton, but it won\'t accept
a proton to make H2SO4 because H2SO4 is a strong acid and completely dissociates. Even if
one of the choices had been HSO3- we would still have a problem. It would be tempting to say
that HSO3- could gain a proton to make the weak acid H2SO3. The problem is that H2SO3 does
not exist in aqueous solution. It is a fictitious acid, much like H2CO3 which also cannot exist in
aqueous solution. The bottom line is that NONE of these are amphoteric. ========= Follow
up ========== See! HPV got suckered. Sorry, you can\'t possibly form H2SO4 and OH-.
H2SO4 is a strong acid and completely dissociates to form H+ and HSO4-. The H+ will combine
with OH- to make water, and you\'re right back where you started. No. HSO4- is NOT
amphoteric in aqueous solution. ======= More follow up ========== \"Would it matter
about the physical state?\" No. For the substance to gain a proton, it will be in aqueous solution.
As soon as HCl interacts with water it will dissociate to form H+ and Cl-.
=============================== You may see that HSO4- is listed as an amphoteric
substance, but only because whoever wrote that didn\'t think it through.
Solution
Amphiprotic. The preferred term is amphoteric. A compound that is amphoteric can
behave as either an acid or a base. These are most commonly explained when using the
Bronsted-Lowry theory of acids and bases. Sorry. NONE of these are amphoteric (or
amphiprotic). In order to behave as a Bronsted-Lowry acid it must donate a proton. That
narrows it down to HCl and HSO4-. In order to behave as a base it must accept a proton. A, D
and E can all accept protons. HCl is a strong acid and dissociates to form H+ and Cl-. There is
no tendency to gain a proton. HSO4- is a weak acid and can donate a proton, but it won\'t accept
a proton to make H2SO4 because H2SO4 is a strong acid and completely dissociates. Even if
one of the choices had been HSO3- we would still have a problem. It would be tempting to say
that HSO3- could gain a proton to make the weak acid H2SO3. The problem is that H2SO3 does
not exist in aqueous solution. It is a fictitious acid, much like H2CO3 which also cannot exist in
aqueous solution. The bottom line is that NONE of these are amphoteric. ========= Follow
up ========== See! HPV got suckered. Sorry, you can\'t possibly form H2SO4 and OH-.
H2SO4 is a strong acid and completely dissociates to form H+ a.
at equivalence point, Moles OH- added = moles H+.pdf
at equivalence point, Moles OH- added = moles H+ Molarity NaOH x vol. OH- x
1 OH- per NaOH = moles OH- = moles H+ = Molarity H2SO4 x vol H2SO4 x 2 H+ per
H2SO4 More generally, M1V1E1 = M2V2E2, where E is the equivalence factor, number of H+
per formula unit for acids and number of OH- per unit for bases
Solution
at equivalence point, Moles OH- added = moles H+ Molarity NaOH x vol. OH- x
1 OH- per NaOH = moles OH- = moles H+ = Molarity H2SO4 x vol H2SO4 x 2 H+ per
H2SO4 More generally, M1V1E1 = M2V2E2, where E is the equivalence factor, number of H+
per formula unit for acids and number of OH- per unit for bases.
We Know that Water is a Polar component as .pdf
We Know that: Water is a Polar component as the property ofthe solubility Like
dissolves Like methyl tertiary butyl etherwhich is polar compound is relatively more soluble
inwater when compared to other components in gasoline.
Solution
We Know that: Water is a Polar component as the property ofthe solubility Like
dissolves Like methyl tertiary butyl etherwhich is polar compound is relatively more soluble
inwater when compared to other components in gasoline..
molar mass of C2H5OH = 46.1 gmole moles of C2H5O.pdf
molar mass of C2H5OH = 46.1 g/mole moles of C2H5OH = mass / molar mass =
47.0 / 46.1 = 1.02 mole 1 moles of C2H5OH contains 6.02 x 1023 C2H5OH molecules, thus,
number of C2H5OH molecules = 1.02 x 6.02 x 1023 = 6.14 x 1023 C2H5OH molecules
Solution
molar mass of C2H5OH = 46.1 g/mole moles of C2H5OH = mass / molar mass =
47.0 / 46.1 = 1.02 mole 1 moles of C2H5OH contains 6.02 x 1023 C2H5OH molecules, thus,
number of C2H5OH molecules = 1.02 x 6.02 x 1023 = 6.14 x 1023 C2H5OH molecules.
What property of PN code makes them suitable for use in spread spect.pdf
What property of PN code makes them suitable for use in spread spectrum communication?
Solution
Pseudo random noise is used in some electronic musical instruments, either by itself or as an
input to subtractive synthesis, and in many white noise machines.
In spread-spectrum systems, the receiver correlates a locally generated signal with the received
signal. Such spread-spectrum systems require a set of one or more \"codes\" or \"sequences\"
such that
Like random noise, the local sequence has a very low correlation with any other sequence in the
set, or with the same sequence at a significantly different time offset, or with narrow band
interference, or with thermal noise.
Unlike random noise, it must be easy to generate exactly the same sequence at both the
transmitter and the receiver, so the receiver\'s locally generated sequence has a very high
correlation with the transmitted sequence.
In a direct-sequence spread spectrum system, each bit in the pseudorandom binary sequence is
known as a chip and the inverse of its period as chip rate; comparebit rate and symbol rate.
In a frequency-hopping spread spectrum sequence, each value in the pseudo random sequence is
known as a channel number and the inverse of its period as thehop rate. FCC Part 15 mandates at
least 50 different channels and at least a 2.5 Hz hop rate for narrow band frequency-hopping
systems.
GPS satellites broadcast data at a rate of 50 data bits per second – each satellite modulates its
data with one PN bit stream at 1.023 million chips per second and the same data with another PN
bit stream at 10.23 million chips per second. GPS receivers correlate the received PN bit stream
with a local reference to measure distance. GPS is a receive-only system that uses relative timing
measurements from several satellites (and the known positions of the satellites) to determine
receiver position.
Other range-finding applications involve two-way transmissions. A local station generates a
pseudo random bit sequence and transmits it to the remote location (using any modulation
technique). Some object at the remote location echoes this PN signal back to the location station
– either passively, as in some kinds of radar and sonar systems, or using an active transponder at
the remote location, as in the Apollo Unified S-band system.[4] By correlating a (delayed version
of) the transmitted signal with the received signal, a precise round trip time to the remote
location can be determined and thus the distance..
There may have some variables affect the model. So the error term wi.pdf
There may have some variables affect the model. So the error term will reflect a systematic
pattern. Or it is not a correct functional form. So there is a bias.
I would suggest that it can be remedial by using data transformation.
Solution
There may have some variables affect the model. So the error term will reflect a systematic
pattern. Or it is not a correct functional form. So there is a bias.
I would suggest that it can be remedial by using data transformation..
There are four major functional characteristics of skeletal muscle..pdf
There are four major functional characteristics of skeletal muscle.
(i) Contractility- for muscle movement
(ii) Excitability- response to chemical and/or electrical signals.
(iii) Extensibility- the ability to stretch to the normal resting length after contracting
(iv) Elasticity - the ability to return to the original resting length after a muscle has been
stretched.
Solution
There are four major functional characteristics of skeletal muscle.
(i) Contractility- for muscle movement
(ii) Excitability- response to chemical and/or electrical signals.
(iii) Extensibility- the ability to stretch to the normal resting length after contracting
(iv) Elasticity - the ability to return to the original resting length after a muscle has been
stretched..
The distinction is important due to the following reasons.The data.pdf
The distinction is important due to the following reasons.
The data and information are exchangable.
The data is real.
Data may be quantitative or qualitative
Information is a activity data.
To become a data as information ,we need to deposit the data into statements or condition.
Data is uncooked upto the time it is arranged.
Data may be a charecter,text,word,number....etc
i.e joe,smith,84084........
Data comes from the latin word \"datum\".
Data and information are involved binding with each other.
Data is incoherent with out information it means that it is irelevant.
The no of callers for a website by country is example of data.
With the help of formulas we can convert a data into information which can be understood by
humans.
Data can be described in terms of information .
\" DIKW pyramid helps to know the relation ship between data and information\".
Solution
The distinction is important due to the following reasons.
The data and information are exchangable.
The data is real.
Data may be quantitative or qualitative
Information is a activity data.
To become a data as information ,we need to deposit the data into statements or condition.
Data is uncooked upto the time it is arranged.
Data may be a charecter,text,word,number....etc
i.e joe,smith,84084........
Data comes from the latin word \"datum\".
Data and information are involved binding with each other.
Data is incoherent with out information it means that it is irelevant.
The no of callers for a website by country is example of data.
With the help of formulas we can convert a data into information which can be understood by
humans.
Data can be described in terms of information .
\" DIKW pyramid helps to know the relation ship between data and information\"..
More from aquacosmossystems (20)
DnaAORC This protein is responsible for initiation of DNA replicat.pdf
DnaAORC This protein is responsible for initiation of DNA replicat.pdf
Answer(19)Mary’s parents are normal, therefore her brother must.pdf
Answer(19)Mary’s parents are normal, therefore her brother must.pdf
Answer Q1. Red mangroove is the last mangroove to colonise on the.pdf
Answer Q1. Red mangroove is the last mangroove to colonise on the.pdf
An Arrhenius acid produces H+ ions insolutionA Bronsted-Lowry acid.pdf
An Arrhenius acid produces H+ ions insolutionA Bronsted-Lowry acid.pdf
Ans. One of the main disadvantage is chromatic aberrasion. A more li.pdf
Ans. One of the main disadvantage is chromatic aberrasion. A more li.pdf
A coordination problem occurs in situations where there is no Nash E.pdf
A coordination problem occurs in situations where there is no Nash E.pdf
1. When an integrated F plasmid leaves the chromosome it may take so.pdf
1. When an integrated F plasmid leaves the chromosome it may take so.pdf
1. A DNA molecule contains two strands of poly deoxyribonucleotide s.pdf
1. A DNA molecule contains two strands of poly deoxyribonucleotide s.pdf
Ethyl 4-aminobenzoate is a basic organic compound. In basic and neut.pdf
Ethyl 4-aminobenzoate is a basic organic compound. In basic and neut.pdf
draw a sphere and use raytracing on the sphere in OpenGL glut. .pdf
draw a sphere and use raytracing on the sphere in OpenGL glut. .pdf
SnO2 (ore) is initially washed and dressed. then .pdf
SnO2 (ore) is initially washed and dressed. then .pdf
d) Valine Note its side chain doesnt contain a.pdf
d) Valine Note its side chain doesnt contain a.pdf
Amphiprotic. The preferred term is amphoteric. A .pdf
Amphiprotic. The preferred term is amphoteric. A .pdf
at equivalence point, Moles OH- added = moles H+.pdf
at equivalence point, Moles OH- added = moles H+.pdf
molar mass of C2H5OH = 46.1 gmole moles of C2H5O.pdf
molar mass of C2H5OH = 46.1 gmole moles of C2H5O.pdf
What property of PN code makes them suitable for use in spread spect.pdf
What property of PN code makes them suitable for use in spread spect.pdf
There may have some variables affect the model. So the error term wi.pdf
There may have some variables affect the model. So the error term wi.pdf
There are four major functional characteristics of skeletal muscle..pdf
There are four major functional characteristics of skeletal muscle..pdf
The distinction is important due to the following reasons.The data.pdf
The distinction is important due to the following reasons.The data.pdf
Recently uploaded
Best Digital Marketing Institute In NOIDA
Safalta Digital marketing institute in Noida, provide complete applications that encompass a huge range of virtual advertising and marketing additives, which includes search engine optimization, virtual communication advertising, pay-per-click on marketing, content material advertising, internet analytics, and greater. These university courses are designed for students who possess a comprehensive understanding of virtual marketing strategies and attributes.Safalta Digital Marketing Institute in Noida is a first choice for young individuals or students who are looking to start their careers in the field of digital advertising. The institute gives specialized courses designed and certification.
for beginners, providing thorough training in areas such as SEO, digital communication marketing, and PPC training in Noida. After finishing the program, students receive the certifications recognised by top different universitie, setting a strong foundation for a successful career in digital marketing.
1.4 modern child centered education - mahatma gandhi-2.pptx
Child centred education is an educational approach that priorities the interest, needs and abilities of the child in the learning process.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
Unit 8 - Information and Communication Technology (Paper I).pdf
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
Home assignment II on Spectroscopy 2024 Answers.pdf
Answers to Home assignment on UV-Visible spectroscopy: Calculation of wavelength of UV-Visible absorption
CACJapan - GROUP Presentation 1- Wk 4.pdf
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
Chapter -12, Antibiotics (One Page Notes).pdf
This is a notes for the D.Pharm students and related to the antibiotic drugs.
Honest Reviews of Tim Han LMA Course Program.pptx
Personal development courses are widely available today, with each one promising life-changing outcomes. Tim Han’s Life Mastery Achievers (LMA) Course has drawn a lot of interest. In addition to offering my frank assessment of Success Insider’s LMA Course, this piece examines the course’s effects via a variety of Tim Han LMA course reviews and Success Insider comments.
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
Operation Blue Star - Saka Neela Tara
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
The Challenger.pdf DNHS Official Publication
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
Recently uploaded (20)
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
Unit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
Digital Tools and AI for Teaching Learning and Research
Digital Tools and AI for Teaching Learning and Research
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI fund...
Group Presentation 2 Economics.Ariana Buscigliopptx
Group Presentation 2 Economics.Ariana Buscigliopptx
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
TLC can be used to help determine the number of components in a mixt.pdf
- 1. TLC can be used to help determine the number of components in a mixture, the identity of compounds, and the purity of a compound. By observing the appearance of a product or the disappearance of a reactant, it can also be used to monitor the progress of a reaction. The sample is applied to the layer of adsorbent, near one edge, as a small spot of a solution. After the solvent has evaporated, the adsorbent-coated sheet is propped more or less vertically in a closed container, with the edge to which the spot was applied down. The spot on the thin layer plate must be positioned above the level of the solvent in the container .If it is below the level of the solvent, the spot will be washed off the plate into the developing solvent. The solvent, which is in the bottom of the container, creeps up the layer of adsorbent, passes over the spot, and, as it continues up, effects a separation of the materials in the spot ("develops" the chromatogram). When the solvent front has nearly reached nearly the top of the adsorbent, the thin layer plate is removed from the container. Solution TLC can be used to help determine the number of components in a mixture, the identity of compounds, and the purity of a compound. By observing the appearance of a product or the disappearance of a reactant, it can also be used to monitor the progress of a reaction. The sample is applied to the layer of adsorbent, near one edge, as a small spot of a solution. After the solvent has evaporated, the adsorbent-coated sheet is propped more or less vertically in a closed container, with the edge to which the spot was applied down. The spot on the thin layer plate must be positioned above the level of the solvent in the container .If it is below the level of the solvent, the spot will be washed off the plate into the developing solvent. The solvent, which is in the bottom of the container, creeps up the layer of adsorbent, passes over the spot, and, as it continues up, effects a separation of the materials in the spot ("develops" the chromatogram). When the solvent front has nearly reached nearly the top of the adsorbent, the thin layer plate is removed from the container.