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Answer:
(19)
Mary’s parents are normal, therefore her brother must have got the disease allele from his mother
who is a carrier of the disease.
Parents
XY (Mary’s father) x XhX (Mary’s mother)
XhY (Mary’s brother)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
(a) Therefore Mary has 50% chance or ½ chance of being a carrier
(b) (c) and (d)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
Among mary’s sons, one will be a carrier and another will be hemophiliac
Among mary’s daughters, one will be a carrier and another will be normal
(e) the carrier daughter can transmit the disease to her son’s
Solution
Answer:
(19)
Mary’s parents are normal, therefore her brother must have got the disease allele from his mother
who is a carrier of the disease.
Parents
XY (Mary’s father) x XhX (Mary’s mother)
XhY (Mary’s brother)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
(a) Therefore Mary has 50% chance or ½ chance of being a carrier
(b) (c) and (d)
For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will
inherit the disease allele and a one in two (50%) chance her daughters will be carriers.
Among mary’s sons, one will be a carrier and another will be hemophiliac
Among mary’s daughters, one will be a carrier and another will be normal
(e) the carrier daughter can transmit the disease to her son’s

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Answer(19)Mary’s parents are normal, therefore her brother must.pdf

  • 1. Answer: (19) Mary’s parents are normal, therefore her brother must have got the disease allele from his mother who is a carrier of the disease. Parents XY (Mary’s father) x XhX (Mary’s mother) XhY (Mary’s brother) For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will inherit the disease allele and a one in two (50%) chance her daughters will be carriers. (a) Therefore Mary has 50% chance or ½ chance of being a carrier (b) (c) and (d) For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will inherit the disease allele and a one in two (50%) chance her daughters will be carriers. Among mary’s sons, one will be a carrier and another will be hemophiliac Among mary’s daughters, one will be a carrier and another will be normal (e) the carrier daughter can transmit the disease to her son’s Solution Answer: (19) Mary’s parents are normal, therefore her brother must have got the disease allele from his mother who is a carrier of the disease. Parents XY (Mary’s father) x XhX (Mary’s mother) XhY (Mary’s brother) For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will inherit the disease allele and a one in two (50%) chance her daughters will be carriers. (a) Therefore Mary has 50% chance or ½ chance of being a carrier (b) (c) and (d) For a carrier female, with each pregnancy there is a one in two (50%) chance her sons will inherit the disease allele and a one in two (50%) chance her daughters will be carriers. Among mary’s sons, one will be a carrier and another will be hemophiliac Among mary’s daughters, one will be a carrier and another will be normal (e) the carrier daughter can transmit the disease to her son’s