Abstract
3rd Modification In
The Moon Orbital Motion Equation
The Old Forms
θ1 (Per Solar Day) = θ0 (of Previous Day) + 0.98562 degrees
θ1 (Per Solar Day) = θ0 (of Previous Day) + 1.5 degrees
θ1 (Per Solar Day) = θ0 (of Previous Day) + 1.6 degrees
The 3rd Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees
(The Equation uses 1.7 degrees to minimize the error as possible)
The Equation Concept
- The needs to decrease its real displacement, to be able to move through more near orbits around Earth than apogee orbit (r=0.406 mkm).
- To do that, the moon uses Pythagoras triangle, creating an angle between its motion direction and its orbit horizontal level, which cause the real displacement through the orbit (L =88000 Cos θ) less than the moon displacement (88000 km).
- In paper appendix the Equation concept is discussed with some details.
- This paper tests the new modification by 2 tests, (1st test for June 2020) and (2nd test for October 2020).
Paper conclusion
- The equation is correct and trustee, and should be considered a useful tool in the moon orbital motion study and analysis.
Gerges Francis Tawdrous +201022532292
The Moon Motion Basic Equation (VI) (Test No.5) Gerges francis
Abstract
The Equation Fifth Test
We test the Equation
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
The Equation Concept
- The Equation Concept Is Discussed In The First Paper Of This Series (References)
- This Paper Provides The 5th Test For The Equation
- The Test Uses The Moon Distance Data During The Period (From 6th June 2020 To 30th June 2020)
- This test is different from the previous tests because we'll test the moon 2 motions, The ascending and descending together (Test For 25 Sequenced Days)
- The 5th Test Results Will Be Discussed And Analyzed
Gerges Francis Tawdrous +201022532292
The Moon Motion Basic Equation (III) (Test No.2) Gerges francis
The Equation Second Test
We test the Equation
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
The Equation Concept
- The Equation Concept Is Discussed In The First Paper Of This Series (References)
- This Paper Provides The 2nd Test For The Equation
- The Test Uses The Moon Distance Real Data During 15 Days (From 14th January 2020 To 30th January 2020)
- The 2nd Test Results Will Be Discussed And Analyzed
Gerges Francis Tawdrous +201022532292
The Moon Motion Basic Equation (IV) (Test No.3) Gerges francis
Abstract
The Equation Third Test
We test the Equation
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
The Equation Concept
- The Equation Concept Is Discussed In The First Paper Of This Series (References)
- This Paper Provides The 3rd Test For The Equation
- The Test Uses The Moon Distance Data During 15 Days (From 11th February 2020 To 26th February 2020)
- The 3rd Test Results Will Be Discussed And Analyzed
Gerges Francis Tawdrous +201022532292
The Moon Motion Basic Equation (II) (Test)Gerges francis
I have discovered The Earth Moon Basic Equation
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
The Equation Concept
- The Equation Concept is explained in (Part one) of this series
- This paper will test the equation using the real values of the moon Perigee and apogee radiuses during the year 2020 (from January to October)
- The Test Results Will Be Discussed After The Test
Gerges Francis Tawdrous +201022532292
(Preprint No. 3) (Planet 8 Days Cycle)
Abstract
Paper hypothesis
The Planets Motions depend On 2 Basic Cycles which are:
(A Cycle Of 8 Days) and (A Cycle of 6 days)
The hypothesis explanation
- The paper hypothesis tells, the solar planet motion can't be considered as an independent motion, because the planets move together based on one general system. This system uses (8 days Cycle) of some planets and (6 days Cycle) of other planets to create a general unified motion.
- Based on that the solar planets motions should be considered as (A Train Carriages Motion). The Planets move together one unified motion in which the planets motions data be complementary with each other
- That proves the claim, the solar group is created based on one geometrical design and that necessitates the planets data to be complementary with one another. by that the solar group should be considered as one machine of Gears and each planet is a gear in it.
- The (8 days) and (6 days) cycles should be used as a proof for this fact.
Paper contents
- The paper explains and discusses the 2 basic Cycles.
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
The Moon Geometry
The Moon Data Analysis shows the following:
1- Earth-Moon is an unique planet in the solar group and not similar to any other moon in the group.
2- The Solar Planets are connected together geometrically
i.e.
3- The solar planets are created to be complementary to each other, all of them together consist one geometrical structure (as a triangle, square, or pyramid….)
That means
a. There was an original energy before any matter existence. And from this energy the planet matter is created (based on E=mc2) and the planet orbital distance is created (I suppose the space = Energy). This same energy also causes the planet motion as part of the general geometrical structure.
b. Each solar planet is a part of this same geometrical structure and has a specific job in it (that means no part is absent..! means the original energy created all required planets to form the required geometrical structure)
c. Each Planet Data is created to be suitable for the planet job in the general geometrical structure..
Paper question
How Does The Gravity work?
The Question Explanation
- The motion at distance is one basic question still needs a sufficient answer.
- The mass gravity concept gives us no geometrical mechanism or any explanation concerns the gravity works mechanism, so we don't know if the gravity needs time or works immediately, or if the gravity causes the space to be formed in some geometrical form to perform the gravity effect.
- We have only the word (gravity) which means, some mass will cause another mass to be moving at distance but no details how this motion is done …
- Venus and Saturn motions data gives some reference that these 2 planets motions depend on one another.
- How Venus and Saturn motions can be performed depending on each other? Whatsoever the answer is, it means, (some effect at distance) is found between these 2 planets.
- Can this effect be a reason for the motion at distance which we search for?
The paper analyzes the 2 planets motions data to see if such effect can be found between the 2 planets and How this effect can be transported from one planet to another?
Gerges Francis Tawdrous +201022532292
Paper Question
- Mercury Day Period =2 Mercury Orbital period = 3 Mercury Rotation period
- Why?
The Question Explanation
- Frequently we have asked this question, it's noticeable and promised data, which may hides behind the solar system creation and motion secrets
- Now, the answer be available, let's summarize it in following:
- The solar system motion depends on a cycle of (8 days) of some planets
- Also
Paper Objective
- The paper discusses the cycles (8 and 6 days) origin and effect
Gerges Francis Tawdrous +201022532292
The Moon Motion Basic Equation (VI) (Test No.5) Gerges francis
Abstract
The Equation Fifth Test
We test the Equation
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
The Equation Concept
- The Equation Concept Is Discussed In The First Paper Of This Series (References)
- This Paper Provides The 5th Test For The Equation
- The Test Uses The Moon Distance Data During The Period (From 6th June 2020 To 30th June 2020)
- This test is different from the previous tests because we'll test the moon 2 motions, The ascending and descending together (Test For 25 Sequenced Days)
- The 5th Test Results Will Be Discussed And Analyzed
Gerges Francis Tawdrous +201022532292
The Moon Motion Basic Equation (III) (Test No.2) Gerges francis
The Equation Second Test
We test the Equation
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
The Equation Concept
- The Equation Concept Is Discussed In The First Paper Of This Series (References)
- This Paper Provides The 2nd Test For The Equation
- The Test Uses The Moon Distance Real Data During 15 Days (From 14th January 2020 To 30th January 2020)
- The 2nd Test Results Will Be Discussed And Analyzed
Gerges Francis Tawdrous +201022532292
The Moon Motion Basic Equation (IV) (Test No.3) Gerges francis
Abstract
The Equation Third Test
We test the Equation
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
The Equation Concept
- The Equation Concept Is Discussed In The First Paper Of This Series (References)
- This Paper Provides The 3rd Test For The Equation
- The Test Uses The Moon Distance Data During 15 Days (From 11th February 2020 To 26th February 2020)
- The 3rd Test Results Will Be Discussed And Analyzed
Gerges Francis Tawdrous +201022532292
The Moon Motion Basic Equation (II) (Test)Gerges francis
I have discovered The Earth Moon Basic Equation
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
The Equation Concept
- The Equation Concept is explained in (Part one) of this series
- This paper will test the equation using the real values of the moon Perigee and apogee radiuses during the year 2020 (from January to October)
- The Test Results Will Be Discussed After The Test
Gerges Francis Tawdrous +201022532292
(Preprint No. 3) (Planet 8 Days Cycle)
Abstract
Paper hypothesis
The Planets Motions depend On 2 Basic Cycles which are:
(A Cycle Of 8 Days) and (A Cycle of 6 days)
The hypothesis explanation
- The paper hypothesis tells, the solar planet motion can't be considered as an independent motion, because the planets move together based on one general system. This system uses (8 days Cycle) of some planets and (6 days Cycle) of other planets to create a general unified motion.
- Based on that the solar planets motions should be considered as (A Train Carriages Motion). The Planets move together one unified motion in which the planets motions data be complementary with each other
- That proves the claim, the solar group is created based on one geometrical design and that necessitates the planets data to be complementary with one another. by that the solar group should be considered as one machine of Gears and each planet is a gear in it.
- The (8 days) and (6 days) cycles should be used as a proof for this fact.
Paper contents
- The paper explains and discusses the 2 basic Cycles.
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
The Moon Geometry
The Moon Data Analysis shows the following:
1- Earth-Moon is an unique planet in the solar group and not similar to any other moon in the group.
2- The Solar Planets are connected together geometrically
i.e.
3- The solar planets are created to be complementary to each other, all of them together consist one geometrical structure (as a triangle, square, or pyramid….)
That means
a. There was an original energy before any matter existence. And from this energy the planet matter is created (based on E=mc2) and the planet orbital distance is created (I suppose the space = Energy). This same energy also causes the planet motion as part of the general geometrical structure.
b. Each solar planet is a part of this same geometrical structure and has a specific job in it (that means no part is absent..! means the original energy created all required planets to form the required geometrical structure)
c. Each Planet Data is created to be suitable for the planet job in the general geometrical structure..
Paper question
How Does The Gravity work?
The Question Explanation
- The motion at distance is one basic question still needs a sufficient answer.
- The mass gravity concept gives us no geometrical mechanism or any explanation concerns the gravity works mechanism, so we don't know if the gravity needs time or works immediately, or if the gravity causes the space to be formed in some geometrical form to perform the gravity effect.
- We have only the word (gravity) which means, some mass will cause another mass to be moving at distance but no details how this motion is done …
- Venus and Saturn motions data gives some reference that these 2 planets motions depend on one another.
- How Venus and Saturn motions can be performed depending on each other? Whatsoever the answer is, it means, (some effect at distance) is found between these 2 planets.
- Can this effect be a reason for the motion at distance which we search for?
The paper analyzes the 2 planets motions data to see if such effect can be found between the 2 planets and How this effect can be transported from one planet to another?
Gerges Francis Tawdrous +201022532292
Paper Question
- Mercury Day Period =2 Mercury Orbital period = 3 Mercury Rotation period
- Why?
The Question Explanation
- Frequently we have asked this question, it's noticeable and promised data, which may hides behind the solar system creation and motion secrets
- Now, the answer be available, let's summarize it in following:
- The solar system motion depends on a cycle of (8 days) of some planets
- Also
Paper Objective
- The paper discusses the cycles (8 and 6 days) origin and effect
Gerges Francis Tawdrous +201022532292
The Solar group is one machine each planet should be considered as a gear in this same machine
The Planet matter and orbital distance are created together from the same energy, so both of them are players in the solar group geometrical structure and motions
i.e.
The Matter is Energy (E=mc2)
The Distance is Energy (Hypothesis)
The Solar group is created from one energy.
This same energy created the planets matters and their orbital distances to guarantee the solar group general harmony.
This paper provides the proves for this claim
Why Saturn Orbital Distance = Saturn Uranus Distance?Gerges francis
Why Saturn Orbital Distance = Saturn Uranus Distance?
Best regards
When I have discovered that..
Saturn Orbital Distance = Saturn Uranus Distance
I have asked Why? But the usual answer was ……
It's Pure coincidence….!
Later I have discovered more equalities….As the following:
1. Saturn Orbital Distance = Mars Orbital Circumference = Pluto Eccentricity distance = Saturn Uranus Distance = 1433.5 million km
2. Mercury Saturn Distance = Neptune Pluto Distance = 1375 million km
3. Saturn Pluto Distance = Mercury Neptune Distance = 4436.5 million km
Then I have asked again… why These Distances Are Equal? Is there a geometrical reason behind?…but the usual answer always be …. " Pure Coincidences"
The question wasn't so simple and the answer was mentioned…. I ask clearly… are the solar planets members in the same body? or parts in the same building?- shortly are the solar group as the human hand and the fingers are similar to the planets? means the planets are created and moving depending on each other because all of them consist one machine –one body –one building – one geometrical structure – means the planets aren't separated from each other– but connected with each other.
(that means the space between the planets is a method to connect each planet with others and not to separate each planet from the others)…. This is my question aim!
And the current theory understood that clearly…
And told also a clear answer … that
Any solar planet is separated from the others - each planet is found and move independently..
So the two visions are clear before our eyes ……And the fighting is clear also….
The Solar Group Classical Vision: tells us that… the planet is created independently and move by gravity with the sun without effect of the other solar planets….
My Suggested Vision Is:
The Solar Group is one body – one machine – one building – one geometrical structure – No Planet can be found or move independently from the other planets …. Even the sun herself can't be found without the solar planets… we deal here with one machine – one geometrical structure- so if this geometrical structure has many elements we should be wise enough to see that these elements are members in the same geometrical structure and this structure is found by the cooperation and integration of his members…..
We should fight to prove that we are correct and the current theory is mistaken… Please read the argument…
Paper hypothesis:
Planet day period is defined depends on other planets motions
Paper objective:
The paper tries to prove this fact
Paper contents
1- Planet Velocity And Diameter Relationship
2- Planet Day Period Definition
Gerges Francis Tawdrous +201022532292
The moon indeed moves by gravity (iii) (explanation)Gerges francis
Paper hypotheses
- Light Motion For 1 Second causes Planet Motion For 1 Solar Day (my research 5th hypothesis)
- Planet Matter is created as a result of Planet motion
- Solar system matters are created by planet motion for 2 Solar Days
- Saturn orbital distance is the required distance to be passed by the solar system unified motion during 1 solar day ("The Train Motion Concept")
- Uranus orbital distance is the required distance to be passed by the solar system unified motion during 2 Solar Days
- That explains the theoretical reason behind Uranus and Saturn strong relationship
Mars Immigration Theory (Part II) (Questions and Answers) Gerges francis
Abstract
We discuss here many questions concerning "Mars Immigration Theory"
Let's write the questions in the following order:
(Question No. 1)
How To Prove That Mars Original Orbital Distance Was 84 Mkm And Mars Had Immigrated To Its New Orbital Distance Point 227.9 Mkm
(Question No. 2)
If Mars Diameter Is Changed Through The History, How Can To Prove That?
(Question No. 3)
Why Mars had immigrated from its original point (84 mkm)? And Why specifically to the point 227.9 mkm? Why not to 200 mkm or 250 mkm?
Please Note
Mars Immigration Theory Is Supported By The Giant –Impact Hypothesis
Where This Hypothesis provides Many Geological Proves For Mars Immigration
And
Mars Immigration Theory solves many important questions to improve the Giant-Impact Hypothesis…
Gerges Francis Tawdrous +201022532292
The Moon Creation Effect On The Solar System Geometry Gerges francis
-Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter diameter
-But, The Earth moon circumference =10921 km
-We are astonished, and asked, how a planet circumference can be used as a period of time? But the answer was "It's Just Pure Coincidence Of Numbers!"
- There's no doubt that this answer is mistaken
- Even if, we provide more examples – as this one –
- Uranus (6.8 km/s) moves during 7510 seconds a distance = 51118 km = Uranus Diameter!
- But, Pluto circumference =7510 km
Gerges Francis Tawdrous +201022532292
Abstract
Paper hypothesis
- Venus motion connects Mercury & Earth Motions
- Venus motion causes to create the rate of time (1 hour is equivalent to 24 hours)
- Venus rotation period is the main platform to use the rate of time (1 hour is equivalent to 24 hours).
- Venus uses (1 h) of (Mercury Motion) to be equivalent to (24 h) of Earth motion
- Venus motion shows one clear example of (the motion transportation) among the solar planets. (For Venus motion the transportation is done between Mercury and Earth motions)
- The solar group is A Great Clock (= a machine of gears) and the motion is transported among the planets as among gears.
The hypothesis Explanation
Paper objective:
- The paper analyzes Venus rotation period role in the rate of time creation.
Gerges Francis Tawdrous +201022532292
The Moon Creation Effect On The Solar System Geometry (III)Gerges francis
The Moon Creation Effect On The Solar System Geometry (III)
Abstract
- What relationship is found between Jupiter and the Moon Motions?
- The data shows some very deep relationship but no physical reason we can find behind this relationship – let's provide some data as examples
o Jupiter (13.1 km/s) moves during 10921 seconds a distance =142984 km = Jupiter Diameter
o Where the Earth moon Circumference =10921 km
o 4900 mkm (orbital Jupiter Circumference) = 10921 km x 449197 km (Jupiter Circumference).
Gerges Francis Tawdrous +201022532292
Paper hypothesis:
-Jupiter Cycle of 8 of Jupiter days (=79.2 hours), this Cycle effects on Uranus Orbital Period (30589 solar days)
The hypothesis Explanation:
-Jupiter cycle of 8 days proves that, Uranus orbital period (30589 solar days) can be used as (30589 seconds)!
-That tells us, different rates of time are found in the solar system, and tells also that, several interactions are found between the planets motions which we can't discovered because these interactions are done on different rates of time
-Shortly … Because
-Light motion features are found in the planets motions, Classical Mechanics Science can't help us to discover all interactions found between planets motions, Instead we have to use Relativistic Motions Science to discover these interactions.
Paper Objective:
-The paper discusses the interaction between Jupiter and Uranus Motions which is seen in the dependency of Uranus Orbital Period & Jupiter 8 Days Cycle.
Gerges Francis Tawdrous +201022532292
Abstract
- The solar group is a clock..
- The paper tries to develop our understanding for the solar system motion…
- The classical description which tells - The solar planets are rigid bodies separated from each other in their creation and motion, revolving around the sun by the masses gravity forces – this description fails frequently to explain Planets Motions Data …
- The paper vision tells – The solar planets are one trajectory of energy, or one thread (or one light beam) and each planet is a knot on this thread or a point on this trajectory of energy –
- The solar group – based on the new vision – is one geometrical building and each planet is a part of this same building – and Because of that – Each plant data must be complementary to other planets data –
- (A Complementary Data) is similar to an electron and a positron are produced by the double production experiment – where each particle charge is defined based on the other particle (because of charge reservation law) – similar to that – each planet creation and motion data must be complementary to the other planets to support the general motions harmony –
- That makes the solar group as a machine of gears, and because of the data dependency on one another, that refers to (A Motion Transportation) is found among the planets.
Gerges Francis Tawdrous +201022532292
Paper question
Why Pluto Day Period = 153.3 hours?
The question explanation
- Pluto day period =153.3 hours
- Where the outer planets days periods are (9.9 h, 10.7 h, 17.2 h and 16.1 h).
- That shows Pluto day period = 3 folds their total together!
- Why Pluto has this long day period and how it's defined?
- Also
- Pluto (9.7 km/s) moves during its day period (153.3 h) a distance =2593836 km = Earth motion distance during the solar day 2574720 km (error 1%)
- The Earth moon displacements total during 29.53 days = 2598693 km = Pluto motion distance during its day period 2593836 km (Zero Error)
- Can these distances equality be a reason behind Pluto day definition? Where
- (Pluto day period / Earth day period) = (Earth velocity/ Pluto velocity)
- Can this data be created based on a geometrical rules, depending on each other?
- Pluto motion distance during a solar day/ the Earth moon displacement daily) = (the Earth moon day period/ Pluto day period).
Mr. Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description (Revised) Gerges francis
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
Gerges Francis Tawdrous +201022532292
Abstract
Paper question
- Can The Motion Be Transported From A Solar Planet To Another?
The Question Explanation
- The planets use (8 days and 6 days) cycles and these cycles refers to a form of the transportation of motion among the solar planets
- The motion transportation is done based on different rates of time found among the planets
- Based on that
- 1 hour of Mercury motion be equivalent to 24 hours of Uranus motion
- And because
- (Venus velocity / Mercury velocity) = 0.738
- 1 hour of Venus motion be equivalent to 17.7 hours of Uranus motion
- This claim should be the paper hypothesis, where the paper tries to prove this fact
- By proving the different rates of time (specifically 1 hour of Venus Motion = 17.7 hours of Uranus Motion), that gives a reference of mutual effect of planets motion on one another which gives support for the motion transposition claim.
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description (2nd Revised) Gerges francis
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
Gerges Francis Tawdrous +201022532292
Is There A Geometrical Shape For The SpaceGerges francis
Is There A Geometrical Shape For The Space?
Yes …
How to prove?
Let's see the moon orbit data in following:
1- Earth moon distance at perigee radius = the outer planets diameters total (1%)
2- Earth moon distance at apogee radius = the solar planets diameters total
3- The moon orbital distance between Perigee and apogee = Earth Circumference = the inner planets diameters total
4- Earth moon distance at total solar eclipse radius = Saturn Circumference
How to explain this data? Can we imagine that Saturn is created after the Earth Moon creation and Saturn used the moon Data
Imagine you have an area and you used partitions to create rooms and offices in this area – now – imagine that – these partitions are so transparent and can't be seen by any person – how to know if the partitions are found or not?
They prevent you to pass– when we don't see the partition it forces us to stop – the moon has to stop at defined points in its motion – the moon can't move beyond neither perigee nor apogee, where both points are defined by other calculations NOT related to the moon motion – even if we don't know yet by what geometrical mechanism the planets diameters total can restrict the moon motion! but because the same points are defined by other calculations that tell us – the restriction points were made by The Space Division and not by the moon motion – that's what I try to prove in this paper – and if I prove that the space is divided, that will prove my claim – "There's A Geometrical Shape For The Space"
Paper Contents
2- The Earth Moon Orbit Analysis
3- Jupiter Effect of the Earth Moon Creation and Motion
4- Mars Migration Theory Revision (The Earth Moon Creation)
Gerges Francis Tawdrous +201022532292
Is Saturn The Last Planet Created In The Solar System? Gerges francis
Paper Question
Is Saturn The Last Planet Created In The Solar System?
I claim that – Saturn is the last planet created in the solar system
This claim I provide depend on Saturn data
Because
Saturn Data Is An Old Data
i.e. Saturn Data is found before Saturn Creation
For example
Saturn orbital distance = Mars Orbital Circumference =1433.5 mkm
That tells us may Saturn orbital distance be created depending on Mars orbital circumference or Vice versa – so one planet must be before the other
Also
Saturn Circumference = Earth Moon Distance At The Total Solar Eclipse
Or
Saturn diameter =Venus Circumference x π
The data tells that Saturn is created after Mars, Venus and Earth Moon Creation – this conclusion we can reach based on the suggested Vision – let's remember it:
The solar system is not separated planets from each other – on the contrary – the solar system is one geometrical building and each planet is a part of this same building – because of that the solar system planets data is created depending on each other – based on that the space doesn’t separate the planets but connects them together – where the matter and space (planet matter and distance) is used as geometrical players in this same geometrical building
Shortly
If the planets data is created depending on each other and Saturn data is found as other planets data that may support the claim that "Saturn is created as the last planet in the solar system"
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description (Revised) (2)Gerges francis
Abstract
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
- The moon using of Pythagoras triangle technique causes the moon orbit to be created in a triangle form, which we analyze in this paper
Gerges Francis Tawdrous +201022532292
Paper Question
- There's a rate of time which is (1 hour of a planet motion is equivalent to 24 hours of another planet motion)? Why is this rate required for the solar system geometry?
The Question Explanation
- Pluto motion on one side in proportionality with the 3 inner planets motions total (Mercury + Venus + Earth) on the other side –causes to create this rate of time (1 hour is equivalent to 24 hours)
- Why is this rate required?
- Because this rate of time is necessary for Saturn motion –shortly – Saturn motion depends on this rate of time
Gerges Francis Tawdrous +201022532292
The moon orbital motion geometry (revised) (2)Gerges francis
The Moon Orbital Motion Geometry (Revised) (2)
Abstract
Paper hypotheses
Hypothesis no. 1
Pluto motion effects on the moon orbital motion and causes to create the moon orbital inclination (5.1 degrees)
As a result of this effect the moon orbital circumference at apogee orbit be shorter than the moon displacements total during 29.53 days with 1%
Hypothesis no. 2
Pluto and Uranus Axial Tilts Interaction causes the moon orbit regression (19 degrees per year) and also causes Venus Axial Tilt Regression.
Paper Conclusions
(1st)
Earth Cycle 1461 days is created as a result of the moon orbit regression
(2nd)
Uranus Motion effect on the moon orbital motion and causes to create Metonic Cycle.
(3rd)
A 2nd force effect on the moon orbital motion.
Paper Question
How can the far planets effect on the moon orbital motion spite of the huge distance?
Gerges Francis Tawdrous +201022532292
Abstract
Why Jupiter diameter =142984 km?
We have asked this question before … so why we need a new paper concerning this same question?!
I would write some theory in consistency with the physics book, But I can't!
While the big bang theory tells that the solar planets are created based random actions and events, I provide data proving that, no planet data can be created by any random process, on the contrary, planet data is created depending on each other and complementary to one another.
While the solar system current description tells that, each planet is a separated planet found independent from the other planets data. I provide crucial proves that the solar system is one building and each planet is a part of this same building, and each planet data is created based on the other planets data – as in any creature body its leg data should be proportional to its hand data
While the current theory tells that, the sun is a star produces the sun rays based on nuclear interactions, I prove that, the sun is a mirror and the sun rays energy is produced by planets motion energies total. where Earth motion concentrates the planets motions energies total and produce the rays which is reflected to us as the sun rays…
While the current theory tells that, the matter data is created independently from any factors, I prove that, the matter dimensions are created in proportionality with space dimensions, both are created by light motion.
While the current theory tells us that, Jupiter is a common planet similar to many others, I prove that, Jupiter energy is the origin by which the solar planets are created
While the physics book tells that, the sun is created independently from the planets data, I prove that, The Sun Is Created Depending On Jupiter And Earth Specifically…
The question is, from where I brought these strange ideas?! From the planets data… i.e. I brought these ideas from the Truth.
Gerges Francis Tawdrous +201022532292
A Modification In
The Moon Orbital Motion Equation
The Old Form
θ1 (Per Solar Day) = θ0 (of Previous Day) + 0.98562 degrees
The Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.5 degrees
- The Equation uses 1.5 degrees in place of the angle (0.98562 degrees) because the moon axial tilt declines on the Earth Ecliptic line with 1.5 degrees.
- This paper tests the new modification on the equation accuracy
- The modified equation defines the moon position with an accuracy =96.12 %
(where the error is (3.88 %))
The Equation Concept
- The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement (L) through its orbit can be less than (88000 km) where (L =88000 Cos (θ))
- The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- The angle (θ) defines the moon real displacement and its distance to perigee radius (r=0.363 mkm).
- For that reason the equation depends on the angle (θ).
Gerges Francis Tawdrous +201022532292
The moon motion basic equation (modified) (revised)Gerges francis
The Moon Motion Basic Equation (modified) (Revised)
Abstract
A Modification In
The Moon Orbital Motion Equation
The Old Form
θ1 (Per Solar Day) = θ0 (of Previous Day) + 0.98562 degrees
The Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.6 degrees
- The Equation uses 1.5 degrees in place of the angle (0.98562 degrees) because the moon axial tilt (6.7 degrees) declines on the Earth Ecliptic line with 1.6 degrees.
- This paper tests the new modification on the equation accuracy
- The modified equation defines the moon position with an accuracy =96.12 %
(where the error is (3.88 %))
The Equation Concept
- The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement (L) through its orbit can be less than (88000 km) where (L =88000 Cos (θ))
- The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- The angle (θ) defines the moon real displacement and its distance to perigee radius (r=0.363 mkm).
- For that reason the equation depends on the angle (θ).
Gerges Francis Tawdrous +201022532292
The Solar group is one machine each planet should be considered as a gear in this same machine
The Planet matter and orbital distance are created together from the same energy, so both of them are players in the solar group geometrical structure and motions
i.e.
The Matter is Energy (E=mc2)
The Distance is Energy (Hypothesis)
The Solar group is created from one energy.
This same energy created the planets matters and their orbital distances to guarantee the solar group general harmony.
This paper provides the proves for this claim
Why Saturn Orbital Distance = Saturn Uranus Distance?Gerges francis
Why Saturn Orbital Distance = Saturn Uranus Distance?
Best regards
When I have discovered that..
Saturn Orbital Distance = Saturn Uranus Distance
I have asked Why? But the usual answer was ……
It's Pure coincidence….!
Later I have discovered more equalities….As the following:
1. Saturn Orbital Distance = Mars Orbital Circumference = Pluto Eccentricity distance = Saturn Uranus Distance = 1433.5 million km
2. Mercury Saturn Distance = Neptune Pluto Distance = 1375 million km
3. Saturn Pluto Distance = Mercury Neptune Distance = 4436.5 million km
Then I have asked again… why These Distances Are Equal? Is there a geometrical reason behind?…but the usual answer always be …. " Pure Coincidences"
The question wasn't so simple and the answer was mentioned…. I ask clearly… are the solar planets members in the same body? or parts in the same building?- shortly are the solar group as the human hand and the fingers are similar to the planets? means the planets are created and moving depending on each other because all of them consist one machine –one body –one building – one geometrical structure – means the planets aren't separated from each other– but connected with each other.
(that means the space between the planets is a method to connect each planet with others and not to separate each planet from the others)…. This is my question aim!
And the current theory understood that clearly…
And told also a clear answer … that
Any solar planet is separated from the others - each planet is found and move independently..
So the two visions are clear before our eyes ……And the fighting is clear also….
The Solar Group Classical Vision: tells us that… the planet is created independently and move by gravity with the sun without effect of the other solar planets….
My Suggested Vision Is:
The Solar Group is one body – one machine – one building – one geometrical structure – No Planet can be found or move independently from the other planets …. Even the sun herself can't be found without the solar planets… we deal here with one machine – one geometrical structure- so if this geometrical structure has many elements we should be wise enough to see that these elements are members in the same geometrical structure and this structure is found by the cooperation and integration of his members…..
We should fight to prove that we are correct and the current theory is mistaken… Please read the argument…
Paper hypothesis:
Planet day period is defined depends on other planets motions
Paper objective:
The paper tries to prove this fact
Paper contents
1- Planet Velocity And Diameter Relationship
2- Planet Day Period Definition
Gerges Francis Tawdrous +201022532292
The moon indeed moves by gravity (iii) (explanation)Gerges francis
Paper hypotheses
- Light Motion For 1 Second causes Planet Motion For 1 Solar Day (my research 5th hypothesis)
- Planet Matter is created as a result of Planet motion
- Solar system matters are created by planet motion for 2 Solar Days
- Saturn orbital distance is the required distance to be passed by the solar system unified motion during 1 solar day ("The Train Motion Concept")
- Uranus orbital distance is the required distance to be passed by the solar system unified motion during 2 Solar Days
- That explains the theoretical reason behind Uranus and Saturn strong relationship
Mars Immigration Theory (Part II) (Questions and Answers) Gerges francis
Abstract
We discuss here many questions concerning "Mars Immigration Theory"
Let's write the questions in the following order:
(Question No. 1)
How To Prove That Mars Original Orbital Distance Was 84 Mkm And Mars Had Immigrated To Its New Orbital Distance Point 227.9 Mkm
(Question No. 2)
If Mars Diameter Is Changed Through The History, How Can To Prove That?
(Question No. 3)
Why Mars had immigrated from its original point (84 mkm)? And Why specifically to the point 227.9 mkm? Why not to 200 mkm or 250 mkm?
Please Note
Mars Immigration Theory Is Supported By The Giant –Impact Hypothesis
Where This Hypothesis provides Many Geological Proves For Mars Immigration
And
Mars Immigration Theory solves many important questions to improve the Giant-Impact Hypothesis…
Gerges Francis Tawdrous +201022532292
The Moon Creation Effect On The Solar System Geometry Gerges francis
-Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter diameter
-But, The Earth moon circumference =10921 km
-We are astonished, and asked, how a planet circumference can be used as a period of time? But the answer was "It's Just Pure Coincidence Of Numbers!"
- There's no doubt that this answer is mistaken
- Even if, we provide more examples – as this one –
- Uranus (6.8 km/s) moves during 7510 seconds a distance = 51118 km = Uranus Diameter!
- But, Pluto circumference =7510 km
Gerges Francis Tawdrous +201022532292
Abstract
Paper hypothesis
- Venus motion connects Mercury & Earth Motions
- Venus motion causes to create the rate of time (1 hour is equivalent to 24 hours)
- Venus rotation period is the main platform to use the rate of time (1 hour is equivalent to 24 hours).
- Venus uses (1 h) of (Mercury Motion) to be equivalent to (24 h) of Earth motion
- Venus motion shows one clear example of (the motion transportation) among the solar planets. (For Venus motion the transportation is done between Mercury and Earth motions)
- The solar group is A Great Clock (= a machine of gears) and the motion is transported among the planets as among gears.
The hypothesis Explanation
Paper objective:
- The paper analyzes Venus rotation period role in the rate of time creation.
Gerges Francis Tawdrous +201022532292
The Moon Creation Effect On The Solar System Geometry (III)Gerges francis
The Moon Creation Effect On The Solar System Geometry (III)
Abstract
- What relationship is found between Jupiter and the Moon Motions?
- The data shows some very deep relationship but no physical reason we can find behind this relationship – let's provide some data as examples
o Jupiter (13.1 km/s) moves during 10921 seconds a distance =142984 km = Jupiter Diameter
o Where the Earth moon Circumference =10921 km
o 4900 mkm (orbital Jupiter Circumference) = 10921 km x 449197 km (Jupiter Circumference).
Gerges Francis Tawdrous +201022532292
Paper hypothesis:
-Jupiter Cycle of 8 of Jupiter days (=79.2 hours), this Cycle effects on Uranus Orbital Period (30589 solar days)
The hypothesis Explanation:
-Jupiter cycle of 8 days proves that, Uranus orbital period (30589 solar days) can be used as (30589 seconds)!
-That tells us, different rates of time are found in the solar system, and tells also that, several interactions are found between the planets motions which we can't discovered because these interactions are done on different rates of time
-Shortly … Because
-Light motion features are found in the planets motions, Classical Mechanics Science can't help us to discover all interactions found between planets motions, Instead we have to use Relativistic Motions Science to discover these interactions.
Paper Objective:
-The paper discusses the interaction between Jupiter and Uranus Motions which is seen in the dependency of Uranus Orbital Period & Jupiter 8 Days Cycle.
Gerges Francis Tawdrous +201022532292
Abstract
- The solar group is a clock..
- The paper tries to develop our understanding for the solar system motion…
- The classical description which tells - The solar planets are rigid bodies separated from each other in their creation and motion, revolving around the sun by the masses gravity forces – this description fails frequently to explain Planets Motions Data …
- The paper vision tells – The solar planets are one trajectory of energy, or one thread (or one light beam) and each planet is a knot on this thread or a point on this trajectory of energy –
- The solar group – based on the new vision – is one geometrical building and each planet is a part of this same building – and Because of that – Each plant data must be complementary to other planets data –
- (A Complementary Data) is similar to an electron and a positron are produced by the double production experiment – where each particle charge is defined based on the other particle (because of charge reservation law) – similar to that – each planet creation and motion data must be complementary to the other planets to support the general motions harmony –
- That makes the solar group as a machine of gears, and because of the data dependency on one another, that refers to (A Motion Transportation) is found among the planets.
Gerges Francis Tawdrous +201022532292
Paper question
Why Pluto Day Period = 153.3 hours?
The question explanation
- Pluto day period =153.3 hours
- Where the outer planets days periods are (9.9 h, 10.7 h, 17.2 h and 16.1 h).
- That shows Pluto day period = 3 folds their total together!
- Why Pluto has this long day period and how it's defined?
- Also
- Pluto (9.7 km/s) moves during its day period (153.3 h) a distance =2593836 km = Earth motion distance during the solar day 2574720 km (error 1%)
- The Earth moon displacements total during 29.53 days = 2598693 km = Pluto motion distance during its day period 2593836 km (Zero Error)
- Can these distances equality be a reason behind Pluto day definition? Where
- (Pluto day period / Earth day period) = (Earth velocity/ Pluto velocity)
- Can this data be created based on a geometrical rules, depending on each other?
- Pluto motion distance during a solar day/ the Earth moon displacement daily) = (the Earth moon day period/ Pluto day period).
Mr. Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description (Revised) Gerges francis
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
Gerges Francis Tawdrous +201022532292
Abstract
Paper question
- Can The Motion Be Transported From A Solar Planet To Another?
The Question Explanation
- The planets use (8 days and 6 days) cycles and these cycles refers to a form of the transportation of motion among the solar planets
- The motion transportation is done based on different rates of time found among the planets
- Based on that
- 1 hour of Mercury motion be equivalent to 24 hours of Uranus motion
- And because
- (Venus velocity / Mercury velocity) = 0.738
- 1 hour of Venus motion be equivalent to 17.7 hours of Uranus motion
- This claim should be the paper hypothesis, where the paper tries to prove this fact
- By proving the different rates of time (specifically 1 hour of Venus Motion = 17.7 hours of Uranus Motion), that gives a reference of mutual effect of planets motion on one another which gives support for the motion transposition claim.
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description (2nd Revised) Gerges francis
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
Gerges Francis Tawdrous +201022532292
Is There A Geometrical Shape For The SpaceGerges francis
Is There A Geometrical Shape For The Space?
Yes …
How to prove?
Let's see the moon orbit data in following:
1- Earth moon distance at perigee radius = the outer planets diameters total (1%)
2- Earth moon distance at apogee radius = the solar planets diameters total
3- The moon orbital distance between Perigee and apogee = Earth Circumference = the inner planets diameters total
4- Earth moon distance at total solar eclipse radius = Saturn Circumference
How to explain this data? Can we imagine that Saturn is created after the Earth Moon creation and Saturn used the moon Data
Imagine you have an area and you used partitions to create rooms and offices in this area – now – imagine that – these partitions are so transparent and can't be seen by any person – how to know if the partitions are found or not?
They prevent you to pass– when we don't see the partition it forces us to stop – the moon has to stop at defined points in its motion – the moon can't move beyond neither perigee nor apogee, where both points are defined by other calculations NOT related to the moon motion – even if we don't know yet by what geometrical mechanism the planets diameters total can restrict the moon motion! but because the same points are defined by other calculations that tell us – the restriction points were made by The Space Division and not by the moon motion – that's what I try to prove in this paper – and if I prove that the space is divided, that will prove my claim – "There's A Geometrical Shape For The Space"
Paper Contents
2- The Earth Moon Orbit Analysis
3- Jupiter Effect of the Earth Moon Creation and Motion
4- Mars Migration Theory Revision (The Earth Moon Creation)
Gerges Francis Tawdrous +201022532292
Is Saturn The Last Planet Created In The Solar System? Gerges francis
Paper Question
Is Saturn The Last Planet Created In The Solar System?
I claim that – Saturn is the last planet created in the solar system
This claim I provide depend on Saturn data
Because
Saturn Data Is An Old Data
i.e. Saturn Data is found before Saturn Creation
For example
Saturn orbital distance = Mars Orbital Circumference =1433.5 mkm
That tells us may Saturn orbital distance be created depending on Mars orbital circumference or Vice versa – so one planet must be before the other
Also
Saturn Circumference = Earth Moon Distance At The Total Solar Eclipse
Or
Saturn diameter =Venus Circumference x π
The data tells that Saturn is created after Mars, Venus and Earth Moon Creation – this conclusion we can reach based on the suggested Vision – let's remember it:
The solar system is not separated planets from each other – on the contrary – the solar system is one geometrical building and each planet is a part of this same building – because of that the solar system planets data is created depending on each other – based on that the space doesn’t separate the planets but connects them together – where the matter and space (planet matter and distance) is used as geometrical players in this same geometrical building
Shortly
If the planets data is created depending on each other and Saturn data is found as other planets data that may support the claim that "Saturn is created as the last planet in the solar system"
Gerges Francis Tawdrous +201022532292
The Moon Orbital Motion Description (Revised) (2)Gerges francis
Abstract
Paper hypothesis No. (1)
There's 2nd force effects on The Earth Moon Orbital Motion
Paper hypothesis No. (2)
Uranus Motion effects on the Earth moon orbital motion and creates Metonic Cycle
Paper Argument
- The moon displacement daily = 88000 km
- During 29.5 days (The Moon Day Period), the total displacements will =2.59 mkm this distance should be = the moon orbital circumference, and this distance = the moon orbital circumference at apogee orbit radius (r=0.406 mkm) (Error 1%)
- That means, if the moon uses this displacement (88000 km) as a real displacement through its orbit, the moon would revolve around Earth only through its apogee orbit (r=0.406 mkm), and be always on the most far point from Earth and can't revolve around Earth through any near orbits.
- To solve this dilemma, the moon uses Pythagoras triangle technique
- By this technique, the moon creates an angle (θ) between its displacement (88000 km) and its orbit horizontal level, So, the real displacement be (L =88000 cos(θ)) by this displacement (L) the moon passes through its orbit although the moon actual displacement = 88000 km daily.
- By Pythagoras technique using the moon can revolve around Earth through more near orbits as perigee orbit (r=0.363 mkm)
- The moon using of Pythagoras triangle technique causes the moon orbit to be created in a triangle form, which we analyze in this paper
Gerges Francis Tawdrous +201022532292
Paper Question
- There's a rate of time which is (1 hour of a planet motion is equivalent to 24 hours of another planet motion)? Why is this rate required for the solar system geometry?
The Question Explanation
- Pluto motion on one side in proportionality with the 3 inner planets motions total (Mercury + Venus + Earth) on the other side –causes to create this rate of time (1 hour is equivalent to 24 hours)
- Why is this rate required?
- Because this rate of time is necessary for Saturn motion –shortly – Saturn motion depends on this rate of time
Gerges Francis Tawdrous +201022532292
The moon orbital motion geometry (revised) (2)Gerges francis
The Moon Orbital Motion Geometry (Revised) (2)
Abstract
Paper hypotheses
Hypothesis no. 1
Pluto motion effects on the moon orbital motion and causes to create the moon orbital inclination (5.1 degrees)
As a result of this effect the moon orbital circumference at apogee orbit be shorter than the moon displacements total during 29.53 days with 1%
Hypothesis no. 2
Pluto and Uranus Axial Tilts Interaction causes the moon orbit regression (19 degrees per year) and also causes Venus Axial Tilt Regression.
Paper Conclusions
(1st)
Earth Cycle 1461 days is created as a result of the moon orbit regression
(2nd)
Uranus Motion effect on the moon orbital motion and causes to create Metonic Cycle.
(3rd)
A 2nd force effect on the moon orbital motion.
Paper Question
How can the far planets effect on the moon orbital motion spite of the huge distance?
Gerges Francis Tawdrous +201022532292
Abstract
Why Jupiter diameter =142984 km?
We have asked this question before … so why we need a new paper concerning this same question?!
I would write some theory in consistency with the physics book, But I can't!
While the big bang theory tells that the solar planets are created based random actions and events, I provide data proving that, no planet data can be created by any random process, on the contrary, planet data is created depending on each other and complementary to one another.
While the solar system current description tells that, each planet is a separated planet found independent from the other planets data. I provide crucial proves that the solar system is one building and each planet is a part of this same building, and each planet data is created based on the other planets data – as in any creature body its leg data should be proportional to its hand data
While the current theory tells that, the sun is a star produces the sun rays based on nuclear interactions, I prove that, the sun is a mirror and the sun rays energy is produced by planets motion energies total. where Earth motion concentrates the planets motions energies total and produce the rays which is reflected to us as the sun rays…
While the current theory tells that, the matter data is created independently from any factors, I prove that, the matter dimensions are created in proportionality with space dimensions, both are created by light motion.
While the current theory tells us that, Jupiter is a common planet similar to many others, I prove that, Jupiter energy is the origin by which the solar planets are created
While the physics book tells that, the sun is created independently from the planets data, I prove that, The Sun Is Created Depending On Jupiter And Earth Specifically…
The question is, from where I brought these strange ideas?! From the planets data… i.e. I brought these ideas from the Truth.
Gerges Francis Tawdrous +201022532292
A Modification In
The Moon Orbital Motion Equation
The Old Form
θ1 (Per Solar Day) = θ0 (of Previous Day) + 0.98562 degrees
The Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.5 degrees
- The Equation uses 1.5 degrees in place of the angle (0.98562 degrees) because the moon axial tilt declines on the Earth Ecliptic line with 1.5 degrees.
- This paper tests the new modification on the equation accuracy
- The modified equation defines the moon position with an accuracy =96.12 %
(where the error is (3.88 %))
The Equation Concept
- The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement (L) through its orbit can be less than (88000 km) where (L =88000 Cos (θ))
- The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- The angle (θ) defines the moon real displacement and its distance to perigee radius (r=0.363 mkm).
- For that reason the equation depends on the angle (θ).
Gerges Francis Tawdrous +201022532292
The moon motion basic equation (modified) (revised)Gerges francis
The Moon Motion Basic Equation (modified) (Revised)
Abstract
A Modification In
The Moon Orbital Motion Equation
The Old Form
θ1 (Per Solar Day) = θ0 (of Previous Day) + 0.98562 degrees
The Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.6 degrees
- The Equation uses 1.5 degrees in place of the angle (0.98562 degrees) because the moon axial tilt (6.7 degrees) declines on the Earth Ecliptic line with 1.6 degrees.
- This paper tests the new modification on the equation accuracy
- The modified equation defines the moon position with an accuracy =96.12 %
(where the error is (3.88 %))
The Equation Concept
- The moon uses Pythagoras triangle to do the following job. While the moon moves a daily displacement =88000 km, The moon real displacement (L) through its orbit can be less than (88000 km) where (L =88000 Cos (θ))
- The moon needs to decrease its daily displacement (88000 km) through its orbit to enable the moon to revolve around Earth in more near orbits to Earth
- The angle (θ) defines the moon real displacement and its distance to perigee radius (r=0.363 mkm).
- For that reason the equation depends on the angle (θ).
Gerges Francis Tawdrous +201022532292
The moon uses pythagoras triangle technique in its orbital motion (part no.3)Gerges francis
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Part No. 3)
Abstract
Paper Argument:
- There are 3 new discovered tools can be used in the moon orbital motion study and analysis, where these 3 tools can help to figure the moon motion trajectory and define the moon position in its orbit, these 3 tools are
1. The concept (the moon uses Pythagoras triangle in its orbital motion)
2. The equation which can define the moon position in its orbit, where this equation depends on the previous concept.
3. The Moon Orbital Triangle which is created as a result of the moon using of Pythagoras triangle technique as one of the moon motion techniques
Paper objective:
- The paper summarizes the advantages of these 3 tools and how they can help to define the moon position in its orbit as near s possible.
- Also
- The paper provides the basic difficulties to figure the moon motion trajectory and the solutions which are provided by the 3 new discovered tools.
Gerges Francis Tawdrous +201022532292
The moon uses pythagoras triangle technique in its orbital motion (part no.3)...Gerges francis
The Moon Uses Pythagoras Triangle Technique In Its Orbital Motion (Part No.3) (Revised)
Abstract
Paper Argument:
- There are 3 new discovered tools can be used in the moon orbital motion study and analysis, where these 3 tools can help to figure the moon motion trajectory and define the moon position in its orbit, these 3 tools are
1. The concept (the moon uses Pythagoras triangle in its orbital motion)
2. The equation (theta= theta + 1.7 degrees) which can define the moon position in its orbit, where this equation depends on the previous concept.
3. The Moon Orbital Triangle which is created as a result of the moon using of Pythagoras triangle technique as one of the moon motion techniques
Paper objective:
- The paper summarizes the advantages of these 3 tools and how they can help to define the moon position in its orbit as near s possible.
- Also
- The paper provides the basic difficulties to figure the moon motion trajectory and the solutions which are provided by the 3 new discovered tools.
Gerges Francis Tawdrous +201022532292
Paper Question
- Imagine there's another rate of time (1 hour is equivalent to 1 solar day)
- How does the solar system use this rate of time in its motion?
The Question Answer Summary
- The solar system depends on the distance to use this rate of time – So- the solar system geometry creates different rates between the distance and time period
- For example
- Some planet motion uses 1 million km for 1 hour
- And another planet motion uses 1 million km for 1 solar day
- By the motion transportation between the planets these 2 different rates of time relative to the equal distances create a configuration for the general harmony.
- And based on that these 2 rates of time be parts of the general motions harmony and be parts in one machine.
- The paper provides detailed examples to explain how this system can work
Paper objective
- The paper discusses the mechanism by which the different rates of time works
Gerges Francis Tawdrous +201022532292
The Moon Orbital Apogee Radius Analysis.pdfGerges francis
The Moon Orbital Apogee Radius Analysis
Abstract
Paper hypothesis no. (1)
- The Solar System Be Created Based On One Geometrical Design
Paper hypothesis no. (2)
- The Solar Planets And Their Distances Be Created Out Of One Light Beam
- This Light Beam Travels With A Velocity 1.16 Million Km Per Second
Paper hypothesis no. (3)
- The moon Metonic Cycle be created by an effect of Uranus motion on the moon motion which necessitates to decrease the moon orbital apogee radius from 413600 km to 406000 km.
Paper hypotheses Explanation
- The paper provides a new vision tells that (The Solar System Be Built Based On One Geometrical Design)
- The design can be in any form as a cube or triangle ……etc
- Means,
- The solar planets and their distances integrate their motions into one design.
- Let's ask
- What does prove this vision? (question no. 1)
- What's the result of this design? (question no. 2)
- How this one design be created? (question no. 3)
- (1st Question)
- The solar system one design be proved by my 3 equations which are
- (1st Equation)
- d2= 4d0 (d- d0) where (d =planet orbital distance) and (d0 = previous planet orb. dis.)
- this equation uses the planets order because each planet orbital distance depends directly on its previous neighbor
- The equation tells, the distance from the sun to Pluto be distributed geometrically in order regardless the planets data – neither their masses nor their diameters –
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
Paper objective
- The paper will test the moon motion basic equation during (17 days), day after day to see if the Equation can predict the moon distance to Earth accurately
The Moon Motion Basic Equation
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
Where
- The angle (θ) is the smallest one in Pythagoras triangle.
- The 0.985 degrees (360 degrees/ 365.25days)
- Let's remember this equation basic concept in following:
- The moon motion distance daily = 88000km, but the moon doesn't use this distance totally as a daily displacement, instead the moon uses Pythagoras triangle to define its real displacement. Based on that the moon uses its daily distance (88000km) as the right triangle hypotenuse and the real distance (L) will be a triangle other dimension (L = 88000 km Cos θ) where , the angle (θ) is the smallest angle in right triangle angles
- Based on that, the moon real displacement is changing with the angle (θ). But
- The greatest available displacement for the moon through the perigee orbit is 77200 km, because during 29.53 days this displacement (77200 x 29.5= 2.27mkm) an this is the perigee orbital circumference, i.e. No Greater Displacement is available through perigee orbit – so any greater displacement necessitates the moon to move higher than Perigee Radius (0r=0.363 mkm) to find more wide orbit to perform any greater displacement than 77200 km.
Gerges Francis Tawdrous +201022532292
Paper question
How Does The Gravity work?
The Question Explanation
- The motion at distance is one basic question still needs a sufficient answer.
- The mass gravity concept gives us no geometrical mechanism or any explanation concerns the gravity works mechanism, so we don't know if the gravity needs time or works immediately, or if the gravity causes the space to be formed in some geometrical form to perform the gravity effect.
- We have only the word (gravity) which means, some mass will cause another mass to be moving at distance but no details how this motion is done …
- Venus and Saturn motions data gives some reference that these 2 planets motions depend on one another.
- How Venus and Saturn motions can be performed depending on each other? Whatsoever the answer is, it means, (some effect at distance) is found between these 2 planets.
- Can this effect be a reason for the motion at distance which we search for?
The paper analyzes the 2 planets motions data to see if such effect can be found between the 2 planets and How this effect can be transported from one planet to another?
Gerges Francis Tawdrous +201022532292
Abstract
Paper hypothesis
- 1 hour of Venus Motion = 24 hours of Uranus Motion
The hypothesis explanation
- Because the solar group is a great clock, its basic task is to uses a motion of 1 second (a light beam motion) to produce a motion of 1 solar day ( a planet motion)
- Because of that, the rate of time 1 hour is equivalent to 24 hours is used
- I claim, 1 hour of Venus motion is equivalent to 24 hours of Uranus motion
- This rate of time is produced by geometrical mechanism and interaction between the planets motions – for that – the light beam velocity isn't used to produce this rate directly by Lorentz Transformations
- This data is so important because it tells there's another method by which a different rate of time can be created – we discuss this method in this paper and tries to see how this different rate of time is produced by a motion transportation among the planets as among the gears
- The paper uses Venus rotation period as a platform for its discussion to explain ho this rate of time be created
- This rate of time (1 hour is equivalent to 24 hours) is a part of the great rate of time (1 second is equivalent to 1 solar day) – we discuss in this paper the rate (1 hour is equivalent to 24 hours).
Gerges Francis Tawdrous +201022532292
The Solar Group is A Clock (VII)
Abstract
Paper Question
- Can The 1 second period of time be different from a planet to another?
The question discussion
- Someone told that, the second period is a human made unit!, It's not true,
- Earth day period (24 hours) – Earth rotation period (23.9 hours) = 0.1 hour
- This fact forces us to divide the solar day into 24 hours and the 1 hour into 60 minutes – easily by using the same rate we define the second period. That means, the time units are defined based on planets motions and cycles
- The direct question is, why we suppose (Earth second period of time) = (Mercury Second period of time)? On what base this hypothesis is suggested?
- The idea is that, because the time unit is defined depends on planet motion features, and these features are changed from one planet to another, that causes the time unit (period) to be different from one planet to another…
Gerges Francis Tawdrous +201022532292
Precession Cycle Effect
Earth orbital distance =149.6 mkm – the light (0.3mkm/sec) needs around 500 seconds to pass this distance… Why?
Paper Hypotheses
Because
(1) Solar Group is one Trajectory of Energy – through which the Energy transports from point to another
(2) Pluto sends The Energy To Earth
(3) Pluto motion depends on a period =500 seconds – using by light beam with velocity =1.16 mkm/sec
(4) Earth motion depends on a period =500 seconds – using by light beam with velocity =0.3 mkm/sec
(5) The period 500 seconds is sent with Pluto energy to Earth
(6) The sending energy causes Pluto and Earth data harmony
The paper tries to prove these facts
Paper question
Why does Saturn move during its day period (10.7 h) a distance = (373644 km) = 98.67% of Saturn Circumference (378675 km)?
The Question Explanation
- Better we need to ask (Why should Saturn move in its day period a distance = its circumference?), what geometrical effect can be produced by that?
- If a planet moves during its day period a distance = its Circumference, that creates a proportionality between this planet circumference, its orbital circumference, its day period and its orbital period, showing this planet motion data is defined based on each other.
- So, if a planet moves during its day period a distance = its circumference, that may create one question controls these 4 planet motion data.
- Saturn gives us this chance, but not accurately, because Saturn moves during its day period a distance = 98.67% of its Circumference (there's a difference between the 2 distances =1.33%)
- Where the difference is so small, the same result can be produced but with some complexities.
- The paper analyzes Saturn motion data to see if such equation can be defined and what difficulties are still found in its way.
Gerges Francis Tawdrous +201022532292
The Moon Orbit Analysis
Earth Moon motion has specific 4 points which are:
1. Perigee Point (R1) : Radius 363000 km from Earth (the nearest point)
2. Total Solar Eclipse (R2) : Radius 377000 km from Earth
3. Average Moon Orbit (R3) : Radius 384000 km (registered)
4. Apogee Point (R4) : Radius 406000 km from Earth (the most far point)
These 4 points are defined by 4 geometrical rules which are:
- (1st Rule) Pythagoras rule : R2n + (86000km)2= R2n+1
(why 86000 km? we'll discuss that in this paper)
- (2nd Rule) Moon Orbital Circumference at Rn= (1/Rn+1)
- (3rd Rule) (Moon Orbital Circumference at Rn+1/ Moon Orbital Circumference at Rn) =1.0725
- (4th Rule) The Rate 365.25
This paper tries to prove this fact, and discusses more deep question… why the moon orbital different radiuses are defined by these 4 geometrical rules?
Uranus Orbital Period Analysis (II) (Revised)Gerges francis
Paper hypothesis
- (1 hour = 1 day) this rate of time is produced by Uranus Motion Effect.
The hypothesis explanation
- The total velocities of (Mercury 47.4 + Venus 35 + Earth 29.8) = 112.2 km/s
- Pluto velocity =4.7 km /s
- means, the distance passed by the 3 planets velocities total in 1 second = the distance passed by Pluto motion during 24 seconds…
- Uranus uses this rate to create 2 gears of motions, the first gear consisted of the 3 planets velocities total and the second gear is Pluto velocity, to create a different rate of time
- By this geometrical mechanism, 1 hour should be = 24 hours
- But
- The real machine works by a little modifications,
- The machine input is 5040 hours but its output is 5040 Earth rotation periods (23.9 hours) –
- Means, this machine need one more modification to reach to the final rate (1 hour is equivalent to 24 hours = 1 solar day)
Paper objective
- The paper discusses the geometrical mechanism by which this process is done.
Gerges Francis Tawdrous +201022532292
The Sun Is A Phenomenon
Abstract
Paper hypothesis
The solar planets velocities total be equivalent to light velocity 300000 km/s
The hypothesis explanation
- The Sun Is A Phenomenon Created By The Planets Motions –
- Means-
- The Sun Rays Energy Source Isn't Any Nuclear Interaction Found Inside The Sun – But – The Sun Rays Energy Be Found By The Planets Motions Energies Total
- Shortly
- The Planets Velocities Total Be Used As One Motion Velocity – And This Motion Uses A Rate Of Time To Reach To Light Velocity.
- Let's explain that in details in following…
- (1)
- We need to suppose that (One Hour Of Mercury Motion =24 Hours Of Any Planet Motion) and
- (One Hour Of Mercury Motion = 24 Solar Days Of Saturn Motion)
- These rates of time be proved in the discussion clearly –
- (2)
- The 9 planets velocities total be =176 km/sec – this value be seen in Mercury Data as (176 solar days = Mercury Day Period)
- We conclude that, Mercury controls this velocities total 176 km/s
- And
- After The Earth Moon Creation, the moon velocity 29.8 km/sec be added to the 9 planets velocities total (176 +29.8 =205.8 km/s)
- The total 205.8 km/s be seen in the moon motion data as (205.8 x π =655.7) (error 1.4%) where (655.7 hours = the moon rotation period)
- That tells the velocities total be seen also in the moon rotation period (a cycle period as Mercury)
- But
- Why for Mercury used (DAYS) but for the moon used (HOURS)??
- Because
- (One Hour Of Mercury Motion = 24 Hours Of The Moon Motion)
- (3)
- The total (205.8 km/s) can create the velocity 300000 km/s only if the rate of time (1=1461) be created – let's see the light velocity creation -
- 300000 km = 205.8s x 9.7 km/s x 24 x 2π
- Let's explain how the light velocity (300000 km/s) be created.
- The planets velocities total (205.8km/s) moves for 1second and passes 205.8 km, this distance be sent from the moon to Saturn in a period form (205.8 seconds)
- But (one hour of any planet motion = 24 hours of Saturn motion) for that reason the period (205.8 s of the moon motion) be equal = (205.8 s x 24) of Saturn motion.
- The rate (2π) be found by the geometrical design
- The data tells, each second Saturn moves, passes a distance =9.7 km but the solar system passes a distance =300000 km
- If the solar system moves (one motion) and uses (one velocity) for this distance (300000 km) for each second - The Solar System Velocity Should Be Equivalent To Light Velocity (300000 km/s) – means – The Planets Velocities Total Should Be Equivalent To Light Velocity (300000 km/s) (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Sun Is a Phenomenon, Created By The Planets Motions Energies (revised).pdfGerges francis
Paper hypothesis
The solar planets distribution between the sun and Pluto depends on one design – this design uses the distance 90000 million km as a distance unit.
The hypothesis explanation
The hypothesis tells – the planets distribution uses one design and this one design gives a chance for the planets to make their distances total equal 90000 million km for a unit period of time – there's a necessity to use this distance we explain here.
The data shows 2 facts
(1st Fact) One Map (One Design) Controls The Planets Distribution Between The Sun And Pluto –
(2nd Fact) This One Design Uses The Distance 90000 Million Km As A Unit
Paper first question
Why does the solar system design use the distance 90000 million km as a unit?
Let's answer in following…
If (c =300000 km/sec = light velocity) how can we measure the value (c2)?
Let's suppose we use the value (c2) for one second – how can we measure it?
In this case the value (c2) will be = 90000 million km
Now
The hypothesis tells, the planets motions aim to pass this distance (90000 million km) and to use this distance based on A Motion For A Period Of Time = One Second
(We Discover In The Paper Discussion How This Motion Can Be Created)
As a result –
The distance 90000 million km will be a equivalent to the value (c2)
And
The value (c2) is the source of energy from which the sun rays be created.
Based on that
The Sun Rays Be Created By The Planets Motions Energies Total
Means,
The Sun Is Not Doing Nuclear Fusion - Instead – the planets motions energies total be accumulated and be used as energy source to produce the sun rays- then the sun disc and body be created from the sun rays energy.
And
Because the planets motions aim to create the sun rays they aim to pass the required distance 90000 million km and the solar system design causes this distance to be used by a motion depends on one second
Paper second question
Can Light Beam Be Produced By Matters Relative Motion?
The planets motions distances total per solar day (=17.75 million km)
(This distance contains the Earth moon velocity which is equal Earth velocity)
During 1461 days the planets motions distances total be =25920 million km
Light (300000 km/s) travels in one day (86400 s) a distance =25920 million km
But the Earth Cycle is (365 +365+365+366 =1461 days)
The idea tells us – if 1461 seconds of the Earth motion = 1 second of the sun motion – the velocities difference between the 2 motions will be= Light Velocity (300000km/s)
The paper discusses how that can be possible- but – here – we discuss the conceptual question- can light beam be created by matters relative motion?
The planets data tells about a new method which is (Motions Use Different Rate Of Time) (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Paper question
Can Saturn Motion effect on Venus Motion?
The Question Explanation
- The gravitation equation gives no hope for a significant effect from Saturn motion on Venus motion because of the great distance between the 2 planets
- But
- The 2 planets data shows that the 2 planets motions must be effective on one another. The data gives no room for doubt concerning this significant effect.
- The dilemma arises 2 basic arguments…
- The first argument tells that, Saturn motion effects on Venus motion, and that necessitates to search behind the data to find the method by which Saturn motion can effect on Venus motion where this method should be considered as another method of planet motion effect on another planet motion in addition to the gravitation equation.
- The second argument tells, (The Motion Be Transported Among The Planets). This argument is so significant because it gives us a solution to answer (how the motion at distance be done?) – and this argument may help to find a definition for the space.
Gerges Francis Tawdrous +201022532292
- The moon orbital triangle is created to explain that, many data in the moon orbit is created based on Pythagoras rule
- This paper provide the moon orbital triangle to be analyzed geometrically as deep as possible
Paper Claim
- The moon motion depends on Pythagoras triangle, and because of that the moon orbital triangle analysis can solve many basic questions in the moon motion
- The moon orbital triangle proves that, there's another force effect on the moon motion, this force is seen in (Point A) in the moon orbital triangle.
Paper question
- Why the moon orbital triangle is a significant triangle?
- Because the moon uses Pythagoras triangle to define its motion points, why? because the moon daily displacement isn't used as a real displacement through the moon orbit – instead – the moon uses part of this displacement to be the real displacement suitably to the orbit radius – that's why the moon orbital triangle is a cornerstone in the moon motion definition –
Gerges Francis Tawdrous +201022532292
(Preprint No. 4) (There's A light Beam Velocity = 1.16 mkm per second)Gerges francis
Abstract
Paper hypothesis
There's a light beam its velocity =1.16 million km per second.
The hypothesis explanation
- The Solar Planets Data Analysis proves that a light beam with velocity 1.16 mkm/sec must be found in the universe.
- Shortly, the solar planets data is created depends on a light beam its velocity 1.16 mkm/sec. And if this light beam isn't found the solar planets data can't be created.
Paper objective
- The paper provides and discuss the planets data which proves the hypothesis.
Mr. Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Abstract
Paper Question
How to form the required hypothesis?
The Question Explanation
- The data analysis method 1st step is (The Directed Data Definition)
- The data analysis method 2nd step is (The hypothesis formation)
- The hypothesis is the task without which the data can't create any meaning.
- The hypothesis basically tries to answer (How the directed data is created?)
- Sometimes the data be so difficult to enable any hypothesis to be formed but the hypothesis is a basic step can't be canceled, in this case such data can not be used.
Gerges Francis Tawdrous +201022532292
Similar to The moon motion basic equation (modified) (part ii) (20)
2012 Phenomenon Has Told Facts Because (The Sun Is A Phenomenon).pdfGerges francis
Best greetings –
2012 Phenomenon has told Facts Because (The Sun Is A Phenomenon)
Abstract
Paper hypothesis
The sun is a phenomenon created by the planets motions – means - the sun is not doing nuclear fusion to create its rays but the sun rays be created by Planets Motions Energies total- As a result – the sun is created after all planets creation and motion which disproves Newton theory of the sun gravity where no planet moves by the sun gravity –
The hypothesis explanation
The sun creation as a phenomenon depends on the planets motions energies shows a great gab between the solar system motion description and the real facts of this motion –for that reason – I provide 2 more points to confirm this gab existence while the 2 points be less strange in meaning can prove clearly this gab is found deeply in the description– not only for the sun rays source of energy but also for the basic ideas of the solar system motion.
(Point No. I)
The Mass Gravity Force Can't Cause The Solar System Motion
The planet moves by the force which caused its creation otherwise this planet will be broken by its motion because 2 forces affect on it- Newton Is Wrong In Logic – But –
I wish to move beyond this point –because – I refuse generally the mass gravity force using as a reason for the solar system motion – the idea is wrong in concept –
Basically because
The mass gravity force is so limited force in range and can't provide the solar system motion features – we need one more powerful and intelligent force – the eclipse phenomenon may help this explanation –the force which created the planets diameters in proportionality with specific distances – and the sun diameter be used also in this process- the force considers each planet motion and velocity – thinking about the whole process to produce the total solar eclipse by many players their creation data be created for this purpose.
Usually the total solar eclipse be considered as pure coincidence result and the beauty of geometry be removed- the paper analyzes the eclipse geometrical data to show a small part of the beauty –
Can the mass gravity poor concept do that? the description Newton told can explain how the matter be created? or how is planet data created? why is the moon diameter =3475 km? because if it be 5000 km the whole geometry will be changed….
The moon creation can help to see another part of this force beauty – the moon be created by planets collision but the moon diameter be created based one exact equations – means- the force works geometrically even through the collisions
In fact
This idea also shows the gab between the solar system facts and the current theory because – while – the current description supposes the planets data be created by random process, initial conditions and unknown historical factors that fact is that the planets data be created based on exact equations
Gerges Francis Tawdrous +201022532292
Peoples' Friendship university of Russia – Moscow (2010-2013)
The Sun Rays Production Theory
Abstract
Paper hypothesis
The Sun Rays Energy Source Is The Planets Motions Energy – means- The Sun Is Not doing nuclear fusion to create its rays – instead – the planets motions energies total be used to create the sun rays.
The hypothesis explanation
I- The Sun Rays Creation Depend On The Relative Motion Concept
This point provides the method by which the sun rays be created – the rays creation depend on the relative motion – that means- we need to find 2 motions in the solar system move relative one another and the different velocity between the 2 motions be = Light Velocity = 300000 km/sec
Regardless – this is possible or not – our job be defined clearly –
We need 2 motions move relative one another and the different velocity between these 2 motions be = Light Velocity = 300000 km/sec
II- Can We Attribute Mechanical Features For The Space?
Here we try to produce the 2 relative motions –
(Let's suppose the sun isn't found but the planets still revolve around its space point)
We have to attribute mechanical features for the space – let's do that in following
We suppose the space be similar to a sea water and the planet be similar to a stick moves perpendicularly through the sea water – this is similar to – a spoon turns water in a vessel - the spoon motion through the water causes a wave in the water –
The theory supposes the planet motion causes a wave in the space –
let's use this hypothesis in our analysis…
Mercury revolves around the sun (point) with velocity 47.4 km/sec – how to see that in our description?
Mercury (a stick moves through water perpendicularly) revolves around the sun point and causes to create a wave by its motion – Mercury velocity is 47.4 km/sec and that causes the wave velocity to be (47.4 km/sec)
And -
Venus (a stick moves through water perpendicularly) revolves around the sun point and causes to create a wave by its motion – Venus velocity (35 km/s) – by that the wave velocity be (47.4 km/sec +35 km/sec = 82.4 km/sec)
And – The Earth moon (a stick moves through water perpendicularly) revolves around the sun point and causes to create a wave by its motion –the moon velocity (29.8 km/s) – by that the wave velocity be (47.4 km/sec +35 km/sec +29.8 = 112.2 km/sec) (continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Paper hypothesis
The Sun Is Not Doing Nuclear Fusion
Saturn motion causes to produce the sun rays
means, Saturn moves by light velocity relative to the sun point –
The hypothesis Proof
The paper hypothesis tells Saturn motion causes to produce the sun rays
Let's prove that in following
(1)
The Planets Motions Use Different Rates Of Time Where
One hour of Mercury motion be = 24 hours of any planet motion (except Saturn)
One hour of Any Planet motion be = 24 hours of Saturn
These rates of time be proved in the paper discussion.
(2)
Saturn moves a distance =90000 million km in a period = 107470 days
The period 107470 days (of Saturn) = 576 x 186.6 days (Of Mercury)
Means this period (107470 days) be seen on Mercury as (186.6 days)
(3)
The 9 planets velocities total be =176 km/sec –
This total be created relative to the point of space on which the sun will be created –
Means
We suppose the sun isn't found and the planets still revolve around the point of space on which the sun will be created-
Mercury (47.4 km/s) revolves around this point of space and creates a different in velocity with it = (47.4km/s)
Venus (35 km/s) revolves around this point and creates a different in velocity = 47.4km/s + 35km/s =82.4 km/s
The 9 planets velocities total 176 km/s causes to create a different velocity =176 km/s with this point of space
Now
The rate of time be created based on the rate of velocities –means
1day of this point of Space be =176 days of Mercury
(Mercury controls this velocities total 176 km/s)
But
107470 days (of Saturn) be =186.6 days (of Mercury) = 1.0725 days of the point of space
We know the rate (1.0725) effect on the solar system – for example – this rate effect on 40% of all distances and 60% 0f all planets axial tilts and effect on many other data-
By this rate (1.0725) the period (1.0725 days) will be = one day
Means
107470 days (of Saturn) be =186.6 days (of Mercury) = one day of the point of space
But
The solar system creation theory tells– the planets matters and their distances be created from one energy and this energy be provided by one light beam and the planets move with this light beam based on the rate of time (One Second of Light motion be = One Solar day of Planet Motion)
This must be the same rate be used with the space because the matter and space be created together.
As a result
107470 days (of Saturn) be =186.6 days (of Mercury) = one day of the point of space =one second of light motion
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Paper hypothesis
(1)
The Sun Rays Be Produced By Planets Velocities Total - The Sun Is Not Doing Nuclear Fusion
Light (300000 km/sec) travels in one solar day a distance = the solar planets motions distances total in 1461 solar days–
The solar planets velocities total uses this rate of time (1=1461) and produces light velocity (300000 km/sec) from the planets velocities total
(2)
If the solar planets motions can't produce light velocity the solar system would be destroyed.
Paper conclusion
Because the sun rays energy be provided by the planets motions energies total and the planets move in cycles – that necessitates – the sun creation and death depend on a cycle –means- after this sun be dead another sun will be created because the sun is a phenomenon created based on a cycle (as the eclipse)
The hypothesis explanation
(1)
The Planets Matters And Their Distances Be Created Out Of One Energy -
This idea can be acceptable simply by the physics book because it's known that the matter and space be created of energies – here – I add one idea only tells that-from the same one energy the planets matters and their distances be created –
The matter and space have different forms spite they be created from the same energy because the creation rules be different for them- as the oil and coal - they be created from the same source but the creation rules be different and the forms be different as a result
The idea causes basic change in the solar system motion description–because –instead of the separated planets as separated points – we deal with one energy which causes to create a continuum of data – by that –the data can be transported among the planets (in fact it does).
The idea doesn't create any new thing– but – it discovers the unjustifiable description for the planets motions – where it be believed that the planets are separated from one another as islands in a sea and no connection can be available – this description is mistaken in concept because the matter is created of energy and the space is created of energy and it's illogical to prevent the contact between them -here – the transportation of data among the planets should be a proved fact depend on the planets motions.
Shortly
The continuum of data of the solar system is a logical fact should be proved, and the separated points description should be considered unjustifiable vision.
A Conclusion
From one energy the planets matters and their distances be created
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
National Bank Of Egypt Practice The Fraud (2020-2022).pdfGerges francis
Please help (1-9-2022)
National Bank Of Egypt Practice The Fraud (2020-2022)
National bank of Egypt practice Fraud and Breach of Trust
Because
It refused the judgment issued by The French ministry of Justice and denies the money by judged and disregarded the Foreign Court Judgment.
Sent to the honorable united Nations Secretary – General
António Guterres
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Passport No./ A11263731 ID. No./27410090102716
best Greetings
The Sun Creation Process
Abstract
Paper hypothesis
From One Light Beam Energy The Solar System Be Created
And
This Light Beam travels with 1.16 million km per second
The hypothesis explanation..
- (1)
- The solar system be created out of one light beam energy –
- The solar planets matters and their distances be created of one energy and this one energy be provided by one light beam and this light beam travels with velocity 1160000 km/s –
- Shortly
- The physics book accepts that (matter and space be created of energies)
- The hypothesis adds one idea only tells
- (from the same one energy the solar planets matters and their distances be created) this is the hypothesis main idea –
- Matter and Space creation be done from the same stuff (energy) but by using different geometrical rules –the idea is similar to the creation of the oil and coal both be created from the same source but they have 2 different forms because the creation process depend on 2 different geometrical rules.
- The matter and space creation process can be summarized by the following data
- (light 1.16 million/s = matter + space + light 300000 km/s)
- The data tells the input energy be a light beam its velocity 1160000 km/s, from this energy the matter and space be created and the light known velocity 300000 km/s be created as a side product from the process.
- Briefly
- If we find Matters in the universe – we can't find the light velocity 1160000 km/s because its energy be consumed in the matter and space creation process and produced the known light beam velocity 300000 km/s as a side product.
- Based on this vision
- The matter be a geometrical point found on a trajectory of energy or (on a light beam) – by that – the matter moves by light motion –
- Imagine a rock in a tube form be found in some sea water and the water passes through this rock tube and pushes the rock itself to move with the water-
- That answers the question (how does planet move?) no sun gravity be used here – instead – the planet moves by light motion from its energy the planet be created.
- Here we disprove Newton theory of the sun gravity – because
- By one force the planet be created and moving otherwise this planet will be broken by effect of 2 forces on it – here – the force caused the planet creation is the light beam energy and the force causes the planet motion is this same light beam motion- that explains the safe planet motion.
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
Paper hypothesis
Venus motion effect on the moon motion and causes the moon orbital period to be = the moon rotation period =27.3 days
The hypothesis explanation..
- The hypothesis explanation can be summarized in 3 questions:
- (1) Can Planet Data Depend On Exaction Equations?
- (2) By What Equation Planet Diameter Can Be Defined?
- (3) How Can Planet Diameter Equation Change The Solar System Vision?
- Let's try to answer these questions in following…
(1st Question)
Can Planet Data Depend On Exaction Equations?
- (1)
- Planet Data Be Created Based On Exact Equations –
- As a plane or rocket manufacture – the manufacturer needs exact equations to define this plane length, width, weight and all specifications, otherwise this plane can't fly safely.
- The moving planet under the physical laws has to define its diameter, mass, orbital distance, period, inclination, rotation period, axial tilt …and all data based on Exact Equations otherwise this planet can't move safely.
- I have discovered 5 equations can conclude Planets Data theoretically without observation which prove this fact decisively.
- Then we have to ask (How Planet Data Be Created In Order?)
- (2)
- Planet orbital distance be defined before this planet creation - because – the planets motions leave an empty place for the new planet – by that- each planet orbital distance be defined by the other planets orbital distances and motions trajectories.
- My first equation proves this fact – because – it proves each planet orbital distance depends on its neighbor planet orbital distance –
- d2=4d0 (d-d0) where d= planet orbital distance and d0= its neighbor orbital distance
- Example (Venus orbital distance)2= 4 (Mercury orbital distance) x50.3 million km (Venus orbital distance=108.2 million km Mercury orbital distance =57.9 million km)
- This equation be tested and discussed in this paper – but its concept is a clear one – it tells the planets leave an empty space for the new planet – for that reason each planet orbital distance depends on its neighbor planet orbital distance.
- Logically the new planet can't disturb the current planets positions or motions trajectories – by that –the orbital distance be defined by the neighbors positions –
- (3)
- The new planet has to revolve around the sun based on its orbital distance which be defined obligatorily where no data of this planet be taken into consideration in its orbital distance definition –neither mass nor diameter – instead – the distance be defined based on the neighbor distance.
- But
- Planet diameter should be a function in its orbital distance – otherwise – this planet will be broken through its motion –
- The function between planet diameter and its orbital distance is the necessary requirement to cause the planet safe motion
Gerges Francis Tawdrous +201022532292
Vodafone-Egypt Practices a fraud and breach of trust during 2013-2022.pdfGerges francis
Vodafone –Egypt practices a fraud and breach of trust during (2013-2022)
Vodafone –Egypt practices a fraud and breach of trust during (2013-2022)
2013-2022: Egypt authority prevented any job from me and prevented me to travel abroad- They Torture My Mother By Electric Shock And Try To Kill Her By Insulin Injection- they threaten our lives –Please Help
2010-2013: I have studied in Faculty of physics & Math– Physics Department – Peoples Friendship University of Russia – Moscow – Russian Federation.
2013-2022 (Details) - Because I couldn't return to Moscow - I have performed an interesting research in astrophysics- many international physicists interested for it – while Egypt authority realized my research importance they:
(I) torture my mother by electric shocks to force me stop publishing my papers
(II) They practice hacking on my accounts & Telephone Calls (+201022532292).
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Petition (with signature) (Egypt Persecution Against The Coptic).pdfGerges francis
Please help
Egypt Authority Persecutes The Coptic -Please Help
EGYPT AUTHORITY TRIES TO KILL MY MOTHER – PLEASE HELP
(Also they force my family to send me to the madhouse)
Because
Egypt Authority tries to STEAL my astrophysics research results, I worked in it since 2013 till now –Egypt authority torture us to steal my research – they hanged many of my accounts and even prevent me to write my research papers by using torture.
(They try to burn my laptop- which is my only source for all my research materials)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Passport No./ A11263731 ID. No./27410090102716
Address /11 Mohamed Rageb st- Madenet El Saada – EL Materiya District – Cairo – Egypt
Planet Diameter Be A Function In Its Rotation PeriodGerges francis
Abstract
Paper hypothesis
- Planet Diameter Be Created As A Function In Its Rotation Period
The hypothesis Explanation
- (1)
- Planet Data Be Created Based On Exact Equations –
- As a plane manufacture – the maker needs exact equations to define this plane length, width, weight …etc otherwise this plane can't fly safely.
- The moving planet under the physical laws has to define its data based on exact equations otherwise this planet can't move safely.
- I have discovered 5 equations can conclude Planets Data theoretically prove this fact decisively.
- (2)
- Planet orbital distance be defined before this planet creation - because – the planets motions leave an empty place for the new planet – by that- each planet orbital distance be defined by the other planets orbital distances and motions trajectories.
- My first equation proves each planet orbital distance depends on its previous neighbor planet orbital distance –
- d2 = 4d0 (d-d0) where d= planet orbital distance and d0= its neighbor orb. distance
- We test and discuss this equation in the current paper–
- As a result –
- The planet found itself in an obligatory position be defined by other planets data and the planet data itself has no role in its orbital distance definition.
- (3)
- Planet motion can be a dangerous one if this planet diameter isn't in harmony with its orbital distance – means- the wrong diameter can cause the planet to be broken (The mass can decrease planet velocity – but the wrong diameter can break it) – for that reason – the planet has to create its diameter as a function in its orbital distance to move safely.
- But
- If the function has only 2 variables (planet diameter and its orbital distance), If this planet changes its orbital distance for any reason its diameter will be broken as a result –
- The designer had to create the function between planet diameter and its orbital distance as indirect function contains many other variables and by that if the planet changes its orbital distance the other variables will be changed but the diameter will be saved.
- As a result
- Planet diameter be created as a function in its rotation period and the rotation period be a function in its velocity and the velocity be a function in its orbital distance – by that – the function between planet diameter and its orbital distance be created but contains also other variables to protect the diameter.
- My fourth equation proves this fact let's see it
- (4)
- Planet Diameter Definition Equation (My Fourth Equation)
- (v1/v2) = (s/r) =I
- v = Planet Velocity
- r= Planet Diameter
- s= Planet Rotation Periods Number In Its Orbital Period
- I= Planet Orbital Inclination (a rate to inclination unit)
- v2, s, r and I be belonged to one planet and v1 be belonged to another planet
- we test, discuss and analyze this equation in this current paper.
Gerges Francis Tawdrous +201022532292
-Physics and Mathematics Faculty - Peoples' Friendship university of Russia –
Gerges Francis Tawdrous (Curriculum Vitae).pdfGerges francis
Gerges Francis Tawdrous (Curriculum Vitae)
My Research Argument
(Why Should We Refuse Newton Theory Of The Sun Gravity?)
1-Planet Data Be Created Based On Exact Equations
Planet diameter, mass, orbital distance, period, inclination, rotation period and axial tilt – All planet data be created based on exact equations and geometrical rules - No single data be created based on random process, initial condition nor unknown historical factors.
As in a plane or a rocket manufacture, the maker needs exact equations to define this plane length, width, weight and all its specifications and dimensions –
If this plane data be created by inaccurate dimensions, this plane can't fly
Similar to that
Planet moves through the space under physical laws and if its data be not created based on exact equations this planet will be broken through its motion – because – the safe motion necessitates a full harmony between planet data one another and with the physical laws controls the motions through space
In this investigation we try to define how Planet creates its data – or in more accurate words – By What Order Planet Data Be Created? what data be created at first and what be later? – by that – we can discover the harmony original point.
I have discovered 5 equations by which we can conclude planet data theoretically without observation that proves the idea decisively
2- Planet Orbital Distance Be Defined Before Its Creation
This simple fact be proved by 2 basic proves – "First Proof" The Logical Analysis
The current planets positions define the new planet position
The balancing effect of the planets motions forces the new planet to take the left place for it – because the planets revolve around the sun in their trajectories of motions – for that – the new planet has to find a place far from these trajectories.
Imagine you are in some crowded bus – the people pushed you to the last place in this bus because it's the only free place there – you came later and this is the only available place for you – by that – you are forced to accept this place
Planet orbital distance be defined before the planet creation – the logic proves this fact clearly
"Second Proof"
My First Equation tells (d2 = 4d0 (d-d0))
d = Planet Orbital Distance and d0 = its neighbor planet orbital distance
My equation tells– Planet Orbital Distance Depends On Its Neighbor Distance
It's a simple and a trustee equation – let's use Venus as example
(108.2 million km)2 = 4 (57.9 million km) (50.3 million km)
where
108.2 million km = Venus orbital distance and
57.9 million km = Mercury orbital distance and (50.3 = 108.2 -57.9)
(There are 3 exceptions – Earth depends on Mercury – Mars depends on Venus and Pluto depends on Uranus –
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Planet Motion Logic Disproves Newton Theory Of The Sun Gravity.pdfGerges francis
Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
Abstract
Paper Argument
- Planet Motion Logic Disproves Newton Theory Of The Sun Gravity
- (1)
- By one force planet be created and moving – means - the force which created the Planet– it causes its motion – as a result
- (No Planet Moves By The Sun Gravity) because (The Sun Had Created No Planet)
- One more force caused the planets creation and their motions
- For that reason
- Planet creation and motion data be in harmony one another –
- For example (Mercury creation and motion data be in harmony one another) and Mercury moves safely and isn't broken
- But -we don't have 9 forces in the solar system – One force for each planet – instead – We have one force only caused All Planets Creation And Motion
- Now- let's ask
- How Can One Force Create 9 Planets And Causes Their Motions?
- This force needs to use One Geometrical Design to do this job – as 9 gears be moving by one motor we need a machine to do this job
- Based on this analysis – No planet moves by the sun gravity – Newton is wrong
- (2)
- The gravitation equation is wrong because no planet orbital distance be defined based on it- and that explains the contradiction between the planets masses order and their orbital distances
- This fact is a powerful against Newton – but the logic still more power
- Because
- The planet orbital distance be defined before this planet creation – because – the distance be defined by other planets distances – means - the new planet orbital distance be defined based on the balancing of the current planets motions trajectories and by that the new planet will find itself in a position defined obligatory by other planets –
- This fact be proved also by my first equation which proves that each planet orbital distance depends on its neighbor planet orbital distance (Not On Its Mass)
- My First Equation tells (d2 = 4d0 (d-d0))
- d = Planet Orbital Distance and d0 = its neighbor planet orbital distance
- (My 5 Equations Be Tested And Discussed In The Paper)
- I want to say
- The principle idea is wrong because the distance be defined obligatory by other planets motions trajectories and planet mass can do nothing to change it
- (3)
- The logic still moves against Newton because
- The planet is found itself in an obligatory position and has to revolve around the sun from this position – now what about this planet diameter – because
- If the planet diameter isn't in harmony with its orbital distance this planet will be broken – here – Newton idea is wrong completely because he looked at the mass but planet mass can decrease its velocity where the wrong diameter can cause the planet to be broken – by that – the planet has to create a function between its orbital distance and its diameter to move safely otherwise it will be broken – the point is Newton defined the mass as the basic player! (continued)
Gerges Francis Tawdrous +201022532292
Physics Department
,Why Does Planet Orbit Define Its Velocity, (Kepler Law Analysis).pdfGerges francis
Why Does Planet Orbit Define Its Velocity? (Kepler Law Analysis)
Abstract
Paper question
Kepler stated (Planet Orbit Defines Its Velocity) - Why?
What would happen if (Planet Orbit Doesn't Define Its Velocity)?
The answer of this question be summarized in 5 points which are:
(1)
Planet Data Be Created Based On Exact Equations
(2)
Planet Diameter Should Be An Indirect Function In Its Orbital Distance
(3)
Planet Mass Effects On Its Diameter Definition Equation
(4)
The Necessity Of The Function Between Planet Orbit And Its Velocity
(5)
The Refutation Of Newton Theory Of The Sun Gravity And The Big Bang Theory.
Let's consider each point in some details in following
(Point No. 1)
Planet Data Be Created Based On Exact Equations
- Planet data (Planet diameter, mass, orbital distance, period, inclination, velocity, rotation period and axial tilt), this data be created based on exact equations and no single data be created by random process, initial condition nor unknown historical factors.
- As in a plane or rocket manufacture, the maker needs exact equations to define this plane length, width, weight….etc – all data and specifications be defined based on exact equations – similar to that Planet data be created based on exact equations.
- If planet data doesn't depend on exact equations, this planet can't move because the planet is moving through its trajectory and if this motion suffer from no harmony with All planet data – this planet will be broken through its motion – because it moves against its internal structure – we will discuss this idea deeply later.
(continued)
The Solar Eclipse (Questions And Answers).pdfGerges francis
The Solar Eclipse (Questions And Answers)
Abstract
Paper objective
The paper answers the following questions
1. Can each planet orbital distance depend on its neighbor planet orbital distance? In this case how the distance between the sun and Pluto be created? (Can One Map Be Drawn For All Planets Orbital Distances?)
2. Is There a necessity to create a proportionality between planet diameter and orbital distance?
3. Can Planet rotation period be defined based on its velocity?
4. Correct The wrong sentence (Planet Diameter Should Be A Direct Function In Its Orbital Distance And By That This Planet Will Not Be Broken Through Its Motion?)
5. Why Does Venus Have The Longest Rotation Period In The Solar System?
6. Can Planet orbital Distance be Defined before this planet creation? where planet orbital distance be defined based on its neighbor orbital distance?
7. Why Doesn't The Planet Break After Its Creation?
8. Planet data be (Mass – Diameter- Orbital Distance- Period –Inclination….etc) what data be created at first and what be created later?
9. Explain The Relationship Between Planet Diameter And Orbital Distance?
10. Why does the moon orbital period = the moon rotation period (No For Tidal Locking – this idea is wrong)?
11. Can The Planets Velocities Total Be Defined At First And Each Planet Velocity Be A Function In This Total?
12- Can Solar System Depend On One Geometrical Design?
13- Why Does The Moon Orbital Apogee Radius = 406000 km?
14- Can Mars Orbital Distance Be Changed From 84 million km to 228 million km?
15- Did Newton realize The Solar system Motion Logic?
16- How Be The Sun Disc Created?
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
The Solar Eclipse Phenomenon Analysis (Revised).pdfGerges francis
The Solar Eclipse Phenomenon Analysis (Revised)
Abstract
Paper Argument
The planets motions can be explained only based on the concept (One Geometrical Design Be found Behind the Solar System)
The Argument explanation
The solar planets are created complementary one another and their motions be integrated into one unified motion – by that- the planets be similar to members of one creature - Their creation data depends on one design and their motions be integrated together into one unified motion (as a machine of gears – many gears motions but the machine produces One Unified Motion)
Because of that
Any planet motion can be explained only through the concept (One Geometrical Design Be found Behind the Solar System), because based on this one design the planets be created and by this one design the planets motions be integrated and produced one unified motion.
Paper objective
- We have proved the one geometrical design before
- In this current paper we examine the one geometrical design details – by that the paper provides rich points of discussion because we discuss the geometrical details of this one design and their effects on the planets creation and motion data.
- The paper discussions points be summarized in following:
- (1)
- The paper proves the one design uses one map for the distance - means
- The solar system design uses the distance from the sun to Pluto as one piece of distance be distributed based on one map –
- (2)
- The paper proves the solar system design uses one more map for the velocities. by that, the design considers the planets motions be integrated into one unified motion as a machine of gears and this (unified velocity) be distributed for the planets velocities based on one more map.
- (3)
- The paper answers the question (why does the design use 2 different maps?) and explains the massive importance for this using
- The paper analyzes also my fourth equation to prove that – planet diameter be created as a function in its rotation period and the rotation period be created a function in its velocity and the velocity be a function in its orbital distance.
- (4)
- The paper disproves the tidal locking claim as a reason for the moon cycles periods equality – the idea is wrong – where – the moon orbital period = the moon rotation period because of the solar system one design effect on the moon motion.
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
The Dancing Planets
Abstract
Paper hypothesis
From One Energy The Solar Planets Matters And Their Distances Be Created
The hypothesis explanation
- (1)
- Newton Theory of the sun gravity is wrong in its logic because by one force the planet should be created and moving –otherwise this planet will be broken -means- The force which created the planet it causes its motion – by that no planet moves by the sun gravity
- (2)
- The Big Bang Theory Is Wrong Because – It Supposed – The First Energy Was In A Chaos Form Resulting From The First Explosion – in Fact – The First Energy (Of The Solar System) was in A Geometrical Design Form.
- (3)
- The physics book accepts (Matter and Space be Created Of Energies) – The paper hypothesis adds one idea tells (From One Energy They Were Created) – means - The planets matters and their distances be created from The Same One Energy
- Let's see the paper basic ideas in following
- (A)
- Planet Data Be Created Based On Exact Equations- As any plane or rocket creation – the maker needs exact equations to define this plane length, width and All Other Specifications-
- Similar to that,
- Planet mass, diameter, orbital distance, period, velocity, inclination, rotation period and axial tilt – all data be created based on exact equations and no data be created by any random process, initial conditions or historical unknown factors.
- By that, the planets data can be concluded by mathematical calculations only
- My 5 equations prove this fact (The 5 equations be tested in point no. 3)
- (B)
- The Planet data Exact equations depend on One Geometrical Design –means-
- Because the solar system creation and motion depends on One Geometrical Design, the planets data be created based on exact equations
- The One Geometrical Design is the basic argument of the paper –
- It's similar to the electron and positron be created from Gamma ray (The double production experiment), The 2 particles charges total be (Zero) because gamma ray charge is (Zero)
- By that, one law controls the 2 particles motions – and similar to that – one law or One Geometrical Design controls the solar planets creations and motions
- Also, from Planet motion analysis- we can reach to this same conclusion
- We accept that, one force only be used for planet creation and motion, and the force which created the planet causes its motion –otherwise this planet will be broken because 2 forces effect on it- but
- We don't have 9 forces create the 9 solar planets and cause their motions – instead- we have only one force causes all planets creation and motion –
- This one force can do this job only by using One Geometrical Design -
(continued)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Planet Diameter Definition Equation
Abstract
Planet Diameter Definition Equation (My Fourth Equation)
(v1/v2) = (s/r) = I
v = Planet Velocity
r= Planet Diameter
s= Planet Rotation Periods Number In Its Orbital Period
I= Planet Orbital Inclination
v2, s, r and I be belonged to one planet and v1 be belonged to another planet
The Equation Role
- The equation proves that, Planet diameter be created based on geometrical rule and as a function in this planet motion data –
- That tells, the motion was found and defined before this planet creation and for that the planet diameter be created depending on this planet motion data
The Equation Significance
- The Equation proves the argument
- By One Force The Solar Planets Be Created And Moving
- The sun didn't cause any planet creation, So (No planet moves by the sun gravity)
- By One Force and From One Energy All Planets Matters And Their Distances Be Created And This Energy Causes The Planets Motions.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
Geometry Of Light Motion
Abstract
Paper hypothesis
- The planets matters and their distances be created from The Same One Energy.
- This one energy is provided by one light beam
- This light beam travels with a velocity =1.16 million km per second
Paper objective
- The paper is consisted of 2 parts
- Part no. (I) provides My Research Presentation Summary
- Part no. (II) discusses The Geometry Of Light Motion
- Let's refer to them in following..
Part No. (I) Research Presentation Summary
My research presentation is consisted of 6 points which are
(1)
Planet Orbital Distance Equation (My 1st Equation)
(2)
The Refutation Of Newton Theory Of The Sun Gravity
(No Planet moves by The Sun Gravity)
(3)
The Research Method explanation And Using to prove 2 basic new discoveries which are:
(Mars Migration Theory) and
(The moon using of an angle θ between its motion direction and its orbit level)
(4)
The Research hypothesis (The planets matters and their distances be created from One Energy)
That's why (The Solar System Be Created Based On One Geometrical Design)
Means (One Geometrical Design was found before the solar system creation)
That refutes (The Big Bang Theory)
(5)
The One Energy Is Provided By One Light Beam
(6)
The light beam travels with a velocity 1.16 million km per second.
That refutes (The hypothesis of the Special Theory of Relativity)
Part No. (II) Geometry Of Light Motion
What's the direct question behind this paper?
The matter and space are created from one light beam – means – the matter and space are forms of light forms –
Now, if this is a fact,
Why do we need to fight so hard to prove this very simple and clear fact?
Because
The light uses unknown geometrical rules –
By that this paper should be similar to a book of Geometry – because – it shows types of geometrical rules are unknown for us and not found in our Geometry books
It's a direct answer but not clear
Why don't we know these rules? Why can't we catch them in lab experiments? If so many unknown geometrical rules of light motion are found, and we couldn't catch them during the empirical physics history why can we do that now? Can any one stole at end the Geometry book from the heaven library?!
I have brought with me the planets data and later I have discovered that all unknown geometrical rules be hidden in them.
Shortly
The light creates the matter and space by using unknown geometrical rules – and – we can discover these geometrical rules by using planets data analysis – means – we can know these geometrical rules only if we can read correctly the planets data – for example – if we can answer the question (why the moon diameter =3475 km?) that will help us to discover the rules based on which the moon diameter be created.
So I will present my research summary then we should discuss these unknown geometrical rules.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
A Research Presentation Summary
Abstract
My research presentation is consisted of 6 points which are
(1)
Planet Orbital Distance Equation (My 1st Equation)
(2)
The Refutation Of Newton Theory Of The Sun Gravity (No Planet moves by the sun gravity)
(3)
The Research Method explanation and using to prove (Mars Migration Theory) and (The moon using of an angle θ between its motion direction and its orbit level)
(4)
The Research hypothesis (The planets matters and their distances be created from One Energy)
That's why (The Solar System Be Created Based On One Geometrical Design)
Means (One Geometrical Design was found before the solar system creation)
That refutes (The Big Bang Theory)
(5)
The One Energy Is Provided By One Light Beam
(6)
The light beam travels with a velocity 1.16 million km per second.
That refutes (The hypothesis of the Special Theory of Relativity)
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
Planet Data Analysis As Astrophysics Scientific Method.pdfGerges francis
Planet Data Analysis As Astrophysics Scientific Method
Abstract
Paper Discovery
- Planet Data Analysis should be considered the astrophysics research basic method.
- The paper proves that – We have to use planets data analysis to discover how the solar system be created and moving – the method provides safe approaches to conclude the facts and protects from the imaginary ideas –
- On the other side –
- Planets data analysis method proves – The big bang theory is wrong and Newton theory of the sun gravity is wrong – (also the method proves one light beam its velocity 1.16 million km per second be found) –
- The method opens a new page in the physics book because it provides a new source of knowledge to discover how the solar system be created and moving.
- The paper provides a new concept tells
(Planet Data Be Created Based On Geometrical Rules And Exact Equations)
And (One Law Controls All Planets Data)
- Based on this new concept – Planet Data Analysis can show The Geometrical Rules based on which this planet be created and moving.
- The paper explains and proves the idea shortly.
Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Peoples' Friendship university of Russia – Moscow (2010-2013)
ORCID https://orcid.org/0000-0002-1041-7147
Tumblr https://www.tumblr.com/blog/itsgerges
Livejournal https://gerges2022.livejournal.com/profile
Seminar of U.V. Spectroscopy by SAMIR PANDASAMIR PANDA
Spectroscopy is a branch of science dealing the study of interaction of electromagnetic radiation with matter.
Ultraviolet-visible spectroscopy refers to absorption spectroscopy or reflect spectroscopy in the UV-VIS spectral region.
Ultraviolet-visible spectroscopy is an analytical method that can measure the amount of light received by the analyte.
Observation of Io’s Resurfacing via Plume Deposition Using Ground-based Adapt...Sérgio Sacani
Since volcanic activity was first discovered on Io from Voyager images in 1979, changes
on Io’s surface have been monitored from both spacecraft and ground-based telescopes.
Here, we present the highest spatial resolution images of Io ever obtained from a groundbased telescope. These images, acquired by the SHARK-VIS instrument on the Large
Binocular Telescope, show evidence of a major resurfacing event on Io’s trailing hemisphere. When compared to the most recent spacecraft images, the SHARK-VIS images
show that a plume deposit from a powerful eruption at Pillan Patera has covered part
of the long-lived Pele plume deposit. Although this type of resurfacing event may be common on Io, few have been detected due to the rarity of spacecraft visits and the previously low spatial resolution available from Earth-based telescopes. The SHARK-VIS instrument ushers in a new era of high resolution imaging of Io’s surface using adaptive
optics at visible wavelengths.
(May 29th, 2024) Advancements in Intravital Microscopy- Insights for Preclini...Scintica Instrumentation
Intravital microscopy (IVM) is a powerful tool utilized to study cellular behavior over time and space in vivo. Much of our understanding of cell biology has been accomplished using various in vitro and ex vivo methods; however, these studies do not necessarily reflect the natural dynamics of biological processes. Unlike traditional cell culture or fixed tissue imaging, IVM allows for the ultra-fast high-resolution imaging of cellular processes over time and space and were studied in its natural environment. Real-time visualization of biological processes in the context of an intact organism helps maintain physiological relevance and provide insights into the progression of disease, response to treatments or developmental processes.
In this webinar we give an overview of advanced applications of the IVM system in preclinical research. IVIM technology is a provider of all-in-one intravital microscopy systems and solutions optimized for in vivo imaging of live animal models at sub-micron resolution. The system’s unique features and user-friendly software enables researchers to probe fast dynamic biological processes such as immune cell tracking, cell-cell interaction as well as vascularization and tumor metastasis with exceptional detail. This webinar will also give an overview of IVM being utilized in drug development, offering a view into the intricate interaction between drugs/nanoparticles and tissues in vivo and allows for the evaluation of therapeutic intervention in a variety of tissues and organs. This interdisciplinary collaboration continues to drive the advancements of novel therapeutic strategies.
Multi-source connectivity as the driver of solar wind variability in the heli...Sérgio Sacani
The ambient solar wind that flls the heliosphere originates from multiple
sources in the solar corona and is highly structured. It is often described
as high-speed, relatively homogeneous, plasma streams from coronal
holes and slow-speed, highly variable, streams whose source regions are
under debate. A key goal of ESA/NASA’s Solar Orbiter mission is to identify
solar wind sources and understand what drives the complexity seen in the
heliosphere. By combining magnetic feld modelling and spectroscopic
techniques with high-resolution observations and measurements, we show
that the solar wind variability detected in situ by Solar Orbiter in March
2022 is driven by spatio-temporal changes in the magnetic connectivity to
multiple sources in the solar atmosphere. The magnetic feld footpoints
connected to the spacecraft moved from the boundaries of a coronal hole
to one active region (12961) and then across to another region (12957). This
is refected in the in situ measurements, which show the transition from fast
to highly Alfvénic then to slow solar wind that is disrupted by the arrival of
a coronal mass ejection. Our results describe solar wind variability at 0.5 au
but are applicable to near-Earth observatories.
Richard's aventures in two entangled wonderlandsRichard Gill
Since the loophole-free Bell experiments of 2020 and the Nobel prizes in physics of 2022, critics of Bell's work have retreated to the fortress of super-determinism. Now, super-determinism is a derogatory word - it just means "determinism". Palmer, Hance and Hossenfelder argue that quantum mechanics and determinism are not incompatible, using a sophisticated mathematical construction based on a subtle thinning of allowed states and measurements in quantum mechanics, such that what is left appears to make Bell's argument fail, without altering the empirical predictions of quantum mechanics. I think however that it is a smoke screen, and the slogan "lost in math" comes to my mind. I will discuss some other recent disproofs of Bell's theorem using the language of causality based on causal graphs. Causal thinking is also central to law and justice. I will mention surprising connections to my work on serial killer nurse cases, in particular the Dutch case of Lucia de Berk and the current UK case of Lucy Letby.
This pdf is about the Schizophrenia.
For more details visit on YouTube; @SELF-EXPLANATORY;
https://www.youtube.com/channel/UCAiarMZDNhe1A3Rnpr_WkzA/videos
Thanks...!
Nutraceutical market, scope and growth: Herbal drug technologyLokesh Patil
As consumer awareness of health and wellness rises, the nutraceutical market—which includes goods like functional meals, drinks, and dietary supplements that provide health advantages beyond basic nutrition—is growing significantly. As healthcare expenses rise, the population ages, and people want natural and preventative health solutions more and more, this industry is increasing quickly. Further driving market expansion are product formulation innovations and the use of cutting-edge technology for customized nutrition. With its worldwide reach, the nutraceutical industry is expected to keep growing and provide significant chances for research and investment in a number of categories, including vitamins, minerals, probiotics, and herbal supplements.
The moon motion basic equation (modified) (part ii)
1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Motion Basic Equation (modified) (Part II)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo – Egypt – 17th
December 2020
Abstract
3rd
Modification In
The Moon Orbital Motion Equation
The Old Forms
θ1 (Per Solar Day) = θ0 (of Previous Day) + 0.98562 degrees
θ1 (Per Solar Day) = θ0 (of Previous Day) + 1.5 degrees
θ1 (Per Solar Day) = θ0 (of Previous Day) + 1.6 degrees
The 3rd
Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees
(The Equation uses 1.7 degrees to minimize the error as possible)
The Equation Concept
- The needs to decrease its real displacement, to be able to move through more near
orbits around Earth than apogee orbit (r=0.406 mkm).
- To do that, the moon uses Pythagoras triangle, creating an angle between its
motion direction and its orbit horizontal level, which cause the real displacement
through the orbit (L =88000 Cos θ) less than the moon displacement (88000 km).
- In paper appendix the Equation concept is discussed with some details.
- This paper tests the new modification by 2 tests, (1st
test for June 2020) and (2nd
test for October 2020).
Paper conclusion
- The equation is correct and trustee, and should be considered a useful tool in the
moon orbital motion study and analysis.
2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- The 3rd
Modified Form
The Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees
1st
test (June 2020)
1-1 The Equation Test (6-30 June 2020)
I-Data
Date The Earth Moon Distance
6-6-2020 369418
7-6-2020 373729
8-6-2020 378917
9-6-2020 384534
10-6-2020 390096
11-6-2020 395156
12-6-2020 399345
13-6-2020 402395
14-6-2020 404153
15-6-2020 404574
16-6-2020 403718
17-6-2020 401733
18-6-2020 398840
19-6-2020 395303
20-6-2020 391409
21-6-2020 387432
22-6-2020 383607
23-6-2020 380110
24-6-2020 377044
25-6-2020 374451
26-6-2020 372338
27-6-2020 370703
28-6-2020 369571
29-6-2020 369005
Data Reference is
https://www.timeanddate.com/moon/egypt/cairo?month=1
Note Please
- In the ascending motion from perigee to apogee the angle (1.6 deg) will be minus
- In the descending motion from apogee to perigee the angle (1.6 deg) will be
positive.
3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
II- The Equation Test
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees
1st
The Ascending Motion
(1) 6 –June -2020
Jun 6 369418 km Jun 7 373729km (The Next Day)
On 6/6/2020 the moon Earth distance was 369418 km
So we need to know where the moon will be on the next day (7/6/2020)?
Let's try to do that….
- The radius =369418 km so C (orbital circumference) = 369418 x 2π=2.321 mkm
- The moon moves it during 29.53 days ( L0= 2.321 mkm/29.53) = 78602.1 km
- L0= 78602.1 km but L0 = 88000 km Cos θ0
- θ0= 26.721 degrees
- θ1= θ0- 1.7 = 26.721 – 1.7 = 25.021 degrees
- L1 = 88000 km (Cos 25.021 degrees) = 79741.5 km
- During 29.53 days = L1 x29.53 = 79741.5 km x 29.53 = 2.354 mkm
- 2.354 mkm = 2π x 374772.5 km
- i.e. The moon on next day (7/6/2020) should be on 374772.5 km
The registered value on 7/6/2020 (373729 km)
The difference = 373729 km – 374772.5 km = - 1044 km
4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
(2) 7 –June -2020
Jun 7 373729 km Jun 8 378917km (The Next Day)
On 7/6/2020 the moon Earth distance was 373729 km
So we need to know where the moon will be on the next day (8/6/2020)?
Let's try to do that….
- The radius =373729 km so C (orbital circumference) = 373729 x 2π=2.348 mkm
- The moon moves it during 29.53 days ( L0= 2.348 mkm/29.53) = 79519.4 km
- L0= 79519.4 km but L0 = 88000 km Cos θ0
- θ0= 25.36 degrees
- θ1= θ0- 1.7 = 25.36 – 1.7 = 23.66 degrees
- L1 = 88000 km (Cos 23.66 degrees) = 80603 km
- During 29.53 days = L1 x29.53 = 80603 km x 29.53 = 2.38 mkm
- 2.38 mkm = 2π x 378821.5 km
- i.e. The moon on next day (8/6/2020) should be on 378821.5 km
The registered value on 8/6/2020 (378917 km)
The difference = 378917 km –378821.5 km = 95.5 km
5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
(3) 8 – June -2020
Jun 8 378917 km Jun 9 384534km (The Next Day)
On 8/6/2020 the moon Earth distance was 378917 km
So we need to know where the moon will be on the next day (9/6/2020)?
Let's try to do that….
- The radius =378917 km so C (orbital circumference) = 378917 x 2π=2.3808 mkm
- The moon moves it during 29.53 days ( L0= 2.3808 mkm/29.53) = 80623.3 km
- L0= 80623.3 km but L0 = 88000 km Cos θ0
- θ0= 23.627 degrees
- θ1= θ0- 1.7 = 23. 627 – 1.7 = 21.927 degrees
- L1 = 88000 km (Cos 21.927 degrees) = 81634.1 km
- During 29.53 days = L1 x29.53 =81634.1 km x 29.53 = 2.41 mkm
- 2.41 mkm = 2π x 383667.7 km
- i.e. The moon on next day (9/6/2020) should be on 383667.7 km
The registered value on 9/6/2020 (384534 km)
The difference = 384534 km – 383667.7 km = 867 km
6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
(4) 9 – June -2020
Jun 9 384534 km Jun 10 390096km (The Next Day)
On 9/6/2020 the moon Earth distance was 384534 km
So we need to know where the moon will be on the next day (10/6/2020)?
Let's try to do that….
- The radius =384534 km so C (orbital circumference) = 384534 x 2π=2.416 mkm
- The moon moves it during 29.53 days ( L0= 2.416 mkm/29.53) = 81818.4 km
- L0= 81818.4 km but L0 = 88000 km Cos θ0
- θ0= 21.60 degrees
- θ1= θ0- 1.7 = 21. 60 -1.7 = 19.9 degrees
- L1 = 88000 km (Cos 19.9 degrees) = 82745.35 km
- During 29.53 days = L1 x29.53 = 82745.35 km x 29.53 = 2.443 mkm
- 2.443 mkm = 2π x 388890 km
- i.e. The moon on next day (10/6/2020) should be on 388890 km
The registered value on 10/6/2020 (390096 km)
The difference = 390096 km – 388890 km = 1206 km
7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
(5) 10 – June -2020
Jun 10 390096 km Jun 11 395156km (The Next Day)
On 10/6/2020 the moon Earth distance was 390096 km
So we need to know where the moon will be on the next day (11/6/2020)?
Let's try to do that….
- The radius =390096 km so C (orbital circumference) = 390096 x 2π=2.451 mkm
- The moon moves it during 29.53 days ( L0= 2.451 mkm/29.53) = 83002 km
- L0= 83002 km but L0 = 88000 km Cos θ0
- θ0= 19.4033 degrees
- θ1= θ0- 1.7 = 19.4033 – 1.7 = 17.7033 degrees
- L1 = 88000 km (Cos 17.7033 degrees) = 83832.6 km
- During 29.53 days = L1 x29.53 = 83832.6 km x 29.53 = 2.475 mkm
- 2.475 mkm = 2π x 394000 km
- i.e. The moon on next day (11/6/2020) should be on 394000 km
The registered value on 11/6/2020 (395156 km)
The difference = 395156 km –394000 km = 1156 km
8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
(5) 11 – June -2020
Jun 11 395156 km Jun 12 399345 km (The Next Day)
On 11/6/2020 the moon Earth distance was 395156 km
So we need to know where the moon will be on the next day (12/6/2020)?
Let's try to do that….
- The radius =395156 km so C (orbital circumference) = 395156 x 2π=2.482 mkm
- The moon moves it during 29.53 days ( L0= 2.482 mkm/29.53) = 84078.5 km
- L0= 84078.5 km but L0 = 88000 km Cos θ0
- θ0= 17.169 degrees
- θ1= θ0- 1.7 = 17.169 – 1.7 = 15.469 degrees
- L1 = 88000 km (Cos 15.469 degrees) = 84812.2 km
- During 29.53 days = L1 x29.53 = 84812.2 km x 29.53 = 2.504 mkm
- 2.504 mkm = 2π x 398604.2 km
- i.e. The moon on next day (12/6/2020) should be on 398604.2 km
The registered value on 12/6/2020 (399345 km)
The difference = 399345 km – 398604.2 km = 741 km
9. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
9
(6) 12 – June -2020
Jun 12 399345 km Jun 13 402395 km (The Next Day)
On 12/6/2020 the moon Earth distance was 399345 km
So we need to know where the moon will be on the next day (13/6/2020)?
Let's try to do that….
- The radius =399345 km so C (orbital circumference) = 399345 x 2π=2.509 mkm
- The moon moves it during 29.53 days ( L0= 2.509 mkm/29.53) = 84970 km
- L0= 84970 km but L0 = 88000 km Cos θ0
- θ0= 15.0794 degrees
- θ1= θ0-1.7 = 15.0794 – 1.7 = 13.3794 degrees
- L1 = 88000 km (Cos 13.3794 degrees) = 85611.6 km
- During 29.53 days = L1 x29.53 = 85611.6 km x 29.53 = 2.528 mkm
- 2.528 mkm = 2π x 402361.3 km
- i.e. The moon on next day (13/6/2020) should be on 402361.3 km
The registered value on 13/6/2020 (402395 km)
The difference = 402395 km –402361.3 km = 34 km
10. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
10
(7) 13 – June -2020
Jun 13 402395 km Jun 14 404153 km (The Next Day)
On 13/6/2020 the moon Earth distance was 402395 km
So we need to know where the moon will be on the next day (14/6/2020)?
Let's try to do that….
- The radius =402395 km so C (orbital circumference) = 402395 x 2π=2.528 mkm
- The moon moves it during 29.53 days ( L0= 2.528 mkm/29.53) = 85618.8 km
- L0= 85618.8 km but L0 = 88000 km Cos θ0
- θ0= 13.3592 degrees
- θ1= θ0- 1.7 = 13.3592 – 1.7 = 11.6592 degrees
- L1 = 88000 km (Cos 11.6592 degrees) = 86184.3 km
- During 29.53 days = L1 x29.53 = 86184.3 km x 29.53 = 2.545 mkm
- 2.545 mkm = 2π x 405052.8 km
- i.e. The moon on next day (14/6/2020) should be on 405052.8 km
The registered value on 14/6/2020 (404153 km)
The difference = 404153 km – 405052.8 km = (-) 900 km
Note Please
- This day is the last day in the moon ascending motion from Perigee to apogee, on
the next day the moon will stay on apogee for one more day (404574 km) on (15th
- 6-2020), and then on (16th
-6-2020) will start its descending motion (403718
km). So we will start the descending motion analysis in next page, and because it's
a descending motion we will add the value 0.985 degrees to the angle (θ)
11. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
11
1st
The Descending Motion
(8) 15 – June -2020
Jun 15 404574 km Jun 16 403718 km (The Next Day)
On 15/6/2020 the moon Earth distance was 404574 km
So we need to know where the moon will be on the next day (16/6/2020)?
Let's try to do that….
- The radius =404574 km so C (orbital circumference) = 404574 x 2π=2.542 mkm
- The moon moves it during 29.53 days ( L0= 2.542 mkm/29.53) = 86082.4 km
- L0= 86082.4 km but L0 = 88000 km Cos θ0
- θ0= 11.983 degrees
- θ1= θ0+ 1.7 = 11.983 +1.7 = 13.683 degrees
- L1 = 88000 km (Cos 13.683 degrees) = 85502.5 km
- During 29.53 days = L1 x29.53 =85502.5 km x 29.53 = 2.524 mkm
- 2.524 mkm = 2π x 401848.5 km
- i.e. The moon on next day (16/6/2020) should be on 401848.5 km
The registered value on 16/6/2020 (403718 km)
The difference = 403718 km – 401848.5 km = 1870 km
12. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
12
(9) 16 – June -2020
Jun 16 403718 km Jun 17 401733 km (The Next Day)
On 16/6/2020 the moon Earth distance was 403718 km
So we need to know where the moon will be on the next day (17/6/2020)?
Let's try to do that….
- The radius =403718 km so C (orbital circumference) = 403718 x 2π=2.536 mkm
- The moon moves it during 29.53 days ( L0= 2.536 mkm/29.53) = 85900 km
- L0= 85900 km but L0 = 88000 km Cos θ0
- θ0= 12.5413 degrees
- θ1= θ0+ 1.7 = 12.5413 +1.7 = 14.2413 degrees
- L1 = 88000 km (Cos 14.2413 degrees) = 85295.6 km
- During 29.53 days = L1 x29.53 = 85295.6 km x 29.53 = 2.518 mkm
- 2.518 mkm = 2π x 400876.1 km
- i.e. The moon on next day (17/6/2020) should be on 400876.1 km
The registered value on 17/6/2020 (401733 km)
The difference = 401733 km – 400876.1 km = 857 km
13. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
13
(10) 17 – June -2020
Jun 17 401733 km Jun 18 398840 km (The Next Day)
On 17/6/2020 the moon Earth distance was 401733 km
So we need to know where the moon will be on the next day (18/6/2020)?
Let's try to do that….
- The radius =401733 km so C (orbital circumference) = 401733 x 2π=2.524 mkm
- The moon moves it during 29.53 days ( L0= 2.524 mkm/29.53) = 85478 km
- L0= 85478 km but L0 = 88000 km Cos θ0
- θ0= 13.75 degrees
- θ1= θ0+ 1.7 = 13.75 +1.7 = 15.45 degrees
- L1 = 88000 km (Cos 15.45 degrees) = 84819.9 km
- During 29.53 days = L1 x29.53 = 84819.9 km x 29.53 = 2.504 mkm
- 2.504 mkm = 2π x 398640.7 km
- i.e. The moon on next day (18/6/2020) should be on 398640.7 km
The registered value on 18/6/2020 (398840 km)
The difference = 398840 km –398640.7 km = 200 km
14. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
14
(11) 18 – June -2020
Jun 18 398840 km Jun 19 395303 km (The Next Day)
On 18/6/2020 the moon Earth distance was 398840 km
So we need to know where the moon will be on the next day (19/6/2020)?
Let's try to do that….
- The radius =398840 km so C (orbital circumference) = 398840 x 2π=2.505 mkm
- The moon moves it during 29.53 days ( L0= 2.505 mkm/29.53) = 84862.36 km
- L0= 84862.36 km but L0 = 88000 km Cos θ0
- θ0= 15.346 degrees
- θ1= θ0+ 1.7 = 15.346 +1.7 = 17.046 degrees
- L1 = 88000 km (Cos 17.046 degrees) = 84134.1 km
- During 29.53 days = L1 x29.53 = 84134.1 km x 29.53 = 2.484 mkm
- 2.484 mkm = 2π x 395417.4 km
- i.e. The moon on next day (19/6/2020) should be on 395417.4 km
The registered value on 19/6/2020 (395303 km)
The difference = 395303 km – 395417.4 km = (-) 115 km
15. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
15
(12) 19 – June -2020
Jun 19 395303 km Jun 20 391409 km (The Next Day)
On 19/6/2020 the moon Earth distance was 395303 km
So we need to know where the moon will be on the next day (20/6/2020)?
Let's try to do that….
- The radius =395303 km so C (orbital circumference) = 395303 x 2π=2.483 mkm
- The moon moves it during 29.53 days ( L0= 2.483 mkm/29.53) = 84109.8 km
- L0= 84109.8 km but L0 = 88000 km Cos θ0
- θ0= 17.1 degrees
- θ1= θ0+ 1.7 = 17.1 +1.7 = 18.8 degrees
- L1 = 88000 km (Cos 18.8 degrees) = 83305.1 km
- During 29.53 days = L1 x29.53 = 83305.1 km x 29.53 = 2.460 mkm
- 2.460 mkm = 2π x 391521.2 km
- i.e. The moon on next day (20/6/2020) should be on 391521.2 km
The registered value on 20/6/2020 (391409 km)
The difference = 391409 km – 391521.2 km = - (113) km
16. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
16
(13) 20 – June -2020
Jun 20 391409 km Jun 21 387432 km (The Next Day)
On 20/6/2020 the moon Earth distance was 391409 km
So we need to know where the moon will be on the next day (21/6/2020)?
Let's try to do that….
- The radius =391409 km so C (orbital circumference) = 391409 x 2π=2.459 mkm
- The moon moves it during 29.53 days ( L0= 2.459 mkm/29.53) = 83281.3 km
- L0= 83281.3 km but L0 = 88000 km Cos θ0
- θ0= 18.848 degrees
- θ1= θ0+ 1.7 = 18.848 +1.7 = 20.548 degrees
- L1 = 88000 km (Cos 20.548 degrees) = 82401.3 km
- During 29.53 days = L1 x29.53 = 82401.3 km x 29.53 = 2.433 mkm
- 2.433 mkm = 2π x 387273.4 km
- i.e. The moon on next day (21/6/2020) should be on 387273.4 km
The registered value on 21/6/2020 (387432 km)
The difference = 387432 km – 387273.4 km = 159 km
17. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
17
(14) 21 – June -2020
Jun 21 387432 km Jun 22 383607 km (The Next Day)
On 21/6/2020 the moon Earth distance was 387432 km
So we need to know where the moon will be on the next day (22/6/2020)?
Let's try to do that….
- The radius =387432 km so C (orbital circumference) = 387432 x 2π=2.434 mkm
- The moon moves it during 29.53 days ( L0= 2.434 mkm/29.53) = 82435 km
- L0= 82435 km but L0 = 88000 km Cos θ0
- θ0= 20.485 degrees
- θ1= θ0+ 1.7 = 20.485 +1.7 = 22.185 degrees
- L1 = 88000 km (Cos 22.185 degrees) = 81485.3 km
- During 29.53 days = L1 x29.53 = 81485.3 km x 29.53 = 2.406 mkm
- 2.406 mkm = 2π x 382968.4 km
- i.e. The moon on next day (22/6/2020) should be on 382968.4 km
The registered value on 22/6/2020 (383607 km)
The difference = 383607 km – 382968.4 km =639 km
18. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
18
(15) 22 – June -2020
Jun 22 383607 km Jun 23 380110 km (The Next Day)
On 22/6/2020 the moon Earth distance was 383607 km
So we need to know where the moon will be on the next day (23/6/2020)?
Let's try to do that….
- The radius =383607 km so C (orbital circumference) = 383607 x 2π=2.41 mkm
- The moon moves it during 29.53 days ( L0= 2.41 mkm/29.53) = 81621.2 km
- L0= 81621.2 km but L0 = 88000 km Cos θ0
- θ0= 21.9495 degrees
- θ1= θ0+ 1.7 = 21.9495 +1.7 =23.6495 degrees
- L1 = 88000 km (Cos 23.6495 degrees) = 80609.5 km
- During 29.53 days = L1 x29.53 = 80609.5 km x 29.53 = 2.380 mkm
- 2.380 mkm = 2π x 378852 km
- i.e. The moon on next day (23/6/2020) should be on 378852 km
The registered value on 23/6/2020 (380110 km)
The difference = 380110 km – 378852 km =1258 km
19. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
19
(16) 23 – June -2020
Jun 23 380110 km Jun 24 377044 km (The Next Day)
On 23/6/2020 the moon Earth distance was 380110 km
So we need to know where the moon will be on the next day (24/6/2020)?
Let's try to do that….
- The radius =380110 km so C (orbital circumference) = 380110 x 2π=2.388 mkm
- The moon moves it during 29.53 days ( L0= 2.388 mkm/29.53) = 80877 km
- L0= 80877 km but L0 = 88000 km Cos θ0
- θ0= 23.2112 degrees
- θ1= θ0+ 1.7 = 23.2112 +1.7 = 24.9112 degrees
- L1 = 88000 km (Cos 24.9112 degrees) = 79812.6 km
- During 29.53 days = L1 x29.53 = 79812.6 km x 29.53 = 2.356 mkm
- 2.356 mkm = 2π x 375107 km
- i.e. The moon on next day (24/6/2020) should be on 375107 km
The registered value on 24/6/2020 (377044 km)
The difference = 377044 km – 375107 km =1937 km
20. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
20
(17) 24 – June -2020
Jun 24 377044 km Jun 25 374451 km (The Next Day)
On 24/6/2020 the moon Earth distance was 377044 km
So we need to know where the moon will be on the next day (25/6/2020)?
Let's try to do that….
- The radius =377044 km so C (orbital circumference) = 377044 x 2π=2.369 mkm
- The moon moves it during 29.53 days ( L0= 2.369 mkm/29.53) = 80224.8 km
- L0= 80224.8 km but L0 = 88000 km Cos θ0
- θ0= 24.266 degrees
- θ1= θ0+ 1.7 = 24.266 +1.7 = 25.966 degrees
- L1 = 88000 km (Cos 25.966 degrees) = 79116.7 km
- During 29.53 days = L1 x29.53 = 79116.7 km x 29.53 = 2.336 mkm
- 2.336 mkm = 2π x 371836.5 km
- i.e. The moon on next day (25/6/2020) should be on 371836.5 km
The registered value on 25/6/2020 (374451 km)
The difference = 374451 km – 371836.5 km =2615 km
21. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
21
(18) 25 – June -2020
Jun 25 374451 km Jun 26 372338 km (The Next Day)
On 25/6/2020 the moon Earth distance was 374451 km
So we need to know where the moon will be on the next day (26/6/2020)?
Let's try to do that….
- The radius =374451 km so C (orbital circumference) = 374451 x 2π=2.352 mkm
- The moon moves it during 29.53 days ( L0= 2.352 mkm/29.53) = 79673 km
- L0= 79673 km but L0 = 88000 km Cos θ0
- θ0= 25.126 degrees
- θ1= θ0+ 1.7 = 25.126 +1.7 = 26.826 degrees
- L1 = 88000 km (Cos 26.826 degrees) = 78529.5 km
- During 29.53 days = L1 x29.53 =78529.5 km x 29.53 = 2.318 mkm
- 2.318 mkm = 2π x 369077 km
- i.e. The moon on next day (26/6/2020) should be on 369077 km
The registered value on 26/6/2020 (372338 km)
The difference = 372338 km – 369077 =3262 km
22. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
22
(19) 26 – June -2020
Jun 26 372338 km Jun 27 370703 km (The Next Day)
On 26/6/2020 the moon Earth distance was 372338 km
So we need to know where the moon will be on the next day (27/6/2020)?
Let's try to do that….
- The radius =372338 km so C (orbital circumference) = 372338 x 2π=2.339 mkm
- The moon moves it during 29.53 days ( L0= 2.339 mkm/29.53) = 79223.4 km
- L0= 79223.4 km but L0 = 88000 km Cos θ0
- θ0= 25.8 degrees
- θ1= θ0+ 1.7 = 25.8 +1.7 = 27.5 degrees
- L1 = 88000 km (Cos 27.5 degrees) = 78057 km
- During 29.53 days = L1 x29.53 = 78057 km x 29.53 = 2.305 mkm
- 2.305 mkm = 2π x 366855.6 km
- i.e. The moon on next day (27/6/2020) should be on 366855.6 km
The registered value on 27/6/2020 (370703 km)
The difference = 370703 km –366855.6 =3847 km
Note Please
- This day is the last day in the moon descending motion, after it the moon stay in
perigee 3 days!! (28-6-2020 369571 km), (29-6-2020 369005 km), (30-6-2020
369106 km) –
- That tells, when the moon changes its motion from ascending to descending and
vice versa, the moon consumes long time in this process which causes great error
for the calculations…
- i.e. there's specific reason at perigee and apogee point causes the moon to stay
longer time there than expected…
- based on that, we have to analyze the equation test results for 20 days only
23. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
23
2-2 The Test Results Discussion And Analysis
Let's take a look on the different distances between the equation results and the
registered data in following
Day Registered Data Results (1.7) Difference
6-6-2020 369418 km
7-6-2020 373729 km 374772.5 - 1044
8-6-2020 378917 km 378821.5 96
9-6-2020 384534 km 383667.7 867
10-6-2020 390096 km 388890 1206
11-6-2020 395156 km 394000 1156
12-6-2020 399345 km 398604.2 741
13-6-2020 402395 km 402361.3 34
14-6-2020 404153 km 405052.8 -900
15-6-2020 404574 km ---- ---
16-6-2020 403718 km 401848.5 1870
17-6-2020 401733 km 400876.1 857
18-6-2020 398840 km 398640.7 200
19-6-2020 395303 km 395417.4 115
20-6-2020 391409 km 391521.2 -113
21-6-2020 387432 km 387273.4 159
22-6-2020 383607 km 382968.4 639
23-6-2020 380110 km 378852 1258
24-6-2020 377044 km 375107 1937
25-6-2020 374451 km 371836.5 2615
26-6-2020 372338 km 369077 3262
27-6-2020 370703 km 366855.6 3847
[
24. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
24
The Test Results Analysis:
- The Total Results Are 20 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 2 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 3 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 20) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
Category of results defines the moon position in error range from (1300
km to 2000 km) = error (4.5%), that means (2 values of 20) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
Category of results defines the moon position in error range from (2000
km to 3500 km) = error (8%), that means (3 values of 20) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily
25. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
25
1-3 The Equation 2nd
Test (1-31 October 2020)
The Modified form
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees
2nd
test (October 2020)
I-Data
Date The Earth Moon Distance
1-10-2020 405,190
2-10-2020 Moon does not pass the meridian on this day.
3-10-2020 406,102
4-10-2020 406,299
5-10-2020 405,690
6-10-2020 404,171
7-10-2020 401,649
8-10-2020 398,073
9-10-2020 393,464
10-10-2020 387,944
11-10-2020 381,763
12-10-2020 375,302
13-10-2020 369,063
14-10-2020 363,617
15-10-2020 359,530
16-10-2020 357,269
17-10-2020 357,105
18-10-2020 359,048
19-10-2020 362,851
20-10-2020 368,058
21-10-2020 374,101
22-10-2020 380,412
23-10-2020 386,497
24-10-2020 391,989
25-10-2020 396,659
26-10-2020 400,395
27-10-2020 403,181
28-10-2020 405,059
29-10-2020 406,104
30-10-2020 406,391
31-10-2020 405,979
Data Reference is https://www.timeanddate.com/moon/egypt/cairo?month=1
Note Please (In the ascending motion from perigee to apogee the angle (1.7 deg) will be minus and
In the descending motion from apogee to perigee the angle (1.7 deg) will be positive.
26. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
26
The Equation Test
θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees
1st
The descending Motion (So +1.7)
(1) 5 –October -2020
October 5 405690 km October 6 404171 km (The Next Day)
On 5/10/2020 the moon Earth distance was 405690km
So we need to know where the moon will be on the next day (6/10/2020)?
Let's try to do that….
- The radius =405690 km so C (orbital circumference) = 405690 x 2π=2.549 mkm
- The moon moves it during 29.53 days ( L0= 2.549mkm/29.53) = 86319.8 km
- L0= 86319.8 km but L0 = 88000 km Cos θ0
- θ0= 11.214 degrees
- θ1= θ0+ 1.7 = 11.214 + 1.7 = 12.914 degrees
- L1 = 88000 km (Cos 12.914 degrees) = 85774.16 km
- During 29.53 days = L1 x29.53 = 85774.16 km x 29.53 = 2.532 mkm
- 2. 532 mkm = 2π x 403125.3 km
- i.e. The moon on next day (6/10/2020) should be on 403125.3 km
The registered value on 7/6/2020 (404171 km)
The difference = 404171 km – 403125.3 km = 1046 km
27. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
27
(2) 6 –October -2020
October 6 404171 km October 7 401649 km (The Next Day)
On 6/10/2020 the moon Earth distance was 404171 km
So we need to know where the moon will be on the next day (7/10/2020)?
Let's try to do that….
- The radius = 404171 km so C (orbital circumference) = 404171 x 2π=2.539 mkm
- The moon moves it during 29.53 days ( L0= 2.539mkm/29.53) = 85996.6 km
- L0= 85996.6 km but L0 = 88000 km Cos θ0
- θ0= 12.249 degrees
- θ1= θ0+ 1.7 = 12.249 + 1.7 = 13.949 degrees
- L1 = 88000 km (Cos 13.949 degrees) = 85404.9 km
- During 29.53 days = L1 x29.53 = 85404.9 km x 29.53 = 2.522 mkm
- 2. 522 mkm = 2π x 401390 km
- i.e. The moon on next day (7/10/2020) should be on 401390 km
The registered value on 7/10/2020 (404171 km)
The difference = 401649 – 401390 km = 259 km
28. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
28
(3) 7 –October -2020
October 7 401649 km October 8 398073 km (The Next Day)
On 7/10/2020 the moon Earth distance was 401649 km
So we need to know where the moon will be on the next day (8/10/2020)?
Let's try to do that….
- The radius = 401649 km so C (orbital circumference) = 401649 x 2π=2.523 mkm
- The moon moves it during 29.53 days ( L0= 2.523mkm/29.53) = 85460 km
- L0= 85460 km but L0 = 88000 km Cos θ0
- θ0= 13.799 degrees
- θ1= θ0+ 1.7 = 13.799 + 1.7 = 15.499 degrees
- L1 = 88000 km (Cos 15.499 degrees) = 84800 km
- During 29.53 days = L1 x29.53 = 84800 km x 29.53 = 2.504 mkm
- 2.504 mkm = 2π x 398545.6 km
- i.e. The moon on next day (8/10/2020) should be on 398545.6 km
The registered value on 8/10/2020 (398073 km)
The difference = 398073 – 398545.6 km = (- 473 km)
29. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
29
(4) 8 –October -2020
October 8 398073 km October 9 393464 km (The Next Day)
On 8/10/2020 the moon Earth distance was 398073 km
So we need to know where the moon will be on the next day (9/10/2020)?
Let's try to do that….
- The radius = 398073 km so C (orbital circumference) = 398073 x 2π=2.50 mkm
- The moon moves it during 29.53 days ( L0= 2.50mkm/29.53) = 84700 km
- L0= 84700 km but L0 = 88000 km Cos θ0
- θ0= 15.742 degrees
- θ1= θ0+ 1.7 = 15.742 + 1.7 = 17.44 degrees
- L1 = 88000 km (Cos 17.44 degrees) = 83953.5 km
- During 29.53 days = L1 x29.53 = 83953.5 km x 29.53 = 2.479 mkm
- 2.479 mkm = 2π x 394568.8 km
- i.e. The moon on next day (9/10/2020) should be on 394568.8 km
The registered value on 9/10/2020 (393464 km)
The difference = 393464 – 394568.8 km = (- 1105 km)
30. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
30
(5) 9 –October -2020
October 9 393464 km October 10 387944 km (The Next Day)
On 9/10/2020 the moon Earth distance was 393464 km
So we need to know where the moon will be on the next day (10/10/2020)?
Let's try to do that….
- The radius = 393464 km so C (orbital circumference) = 393464 x 2π=2.47 mkm
- The moon moves it during 29.53 days ( L0= 2.47mkm/29.53) = 83718.5 km
- L0= 83718.5 km but L0 = 88000 km Cos θ0
- θ0= 17.946 degrees
- θ1= θ0+ 1.7 = 17.946 + 1.7 = 19.646 degrees
- L1 = 88000 km (Cos 19.646 degrees) = 82877.3 km
- During 29.53 days = L1 x29.53 = 82877.3 km x 29.53 = 2.447 mkm
- 2.447 mkm = 2π x 389510 km
- i.e. The moon on next day (10/10/2020) should be on 389510 km
The registered value on 10/10/2020 (387944 km)
The difference = 387944 – 389510 km = (- 1567 km)
31. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
31
(6) 10 –October -2020
October 10 387944 km October 11 381763 km (The Next Day)
On 10/10/2020 the moon Earth distance was 387944 km
So we need to know where the moon will be on the next day (11/10/2020)?
Let's try to do that….
- The radius = 387944 km so C (orbital circumference) = 387944 x 2π=2.43 mkm
- The moon moves it during 29.53 days ( L0= 2.43mkm/29.53) = 82544 km
- L0= 82544 km but L0 = 88000 km Cos θ0
- θ0= 20.28 degrees
- θ1= θ0+ 1.7 = 20.28 + 1.7 = 21.981 degrees
- L1 = 88000 km (Cos 21.981 degrees) = 81602.7 km
- During 29.53 days = L1 x29.53 = 81602.7 km x 29.53 = 2.409 mkm
- 2.409 mkm = 2π x 383520 km
- i.e. The moon on next day (11/10/2020) should be on 383520 km
The registered value on 11/10/2020 (381763 km)
The difference = 381763 – 383520 km = (- 1758 km)
32. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
32
(7) 11 –October -2020
October 11 381763 km October 12 375302 km (The Next Day)
On 11/10/2020 the moon Earth distance was 381763 km
So we need to know where the moon will be on the next day (12/10/2020)?
Let's try to do that….
- The radius = 381763 km so C (orbital circumference) = 381763 x 2π=2.39 mkm
- The moon moves it during 29.53 days ( L0= 2.39mkm/29.53) = 81229 km
- L0= 81229 km but L0 = 88000 km Cos θ0
- θ0= 22.623 degrees
- θ1= θ0+ 1.7 = 22.623 + 1.7 = 24.323 degrees
- L1 = 88000 km (Cos 24.323 degrees) = 80189 km
- During 29.53 days = L1 x29.53 = 80189 km x 29.53 = 2.368 mkm
- 2.368 mkm = 2π x 376875.3 km
- i.e. The moon on next day (12/10/2020) should be on 376875.3 km
The registered value on 12/10/2020 (375302 km)
The difference = 375302 – 376875.3 km = (- 1574 km)
33. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
33
(8) 12 –October -2020
October 12 375302 km October 13 369063 km (The Next Day)
On 12/10/2020 the moon Earth distance was 375302 km
So we need to know where the moon will be on the next day (13/10/2020)?
Let's try to do that….
- The radius = 375302 km so C (orbital circumference) = 375302 x 2π=2.358 mkm
- The moon moves it during 29.53 days ( L0= 2.358 mkm/29.53) = 79854.1 km
- L0= 79854.1 km but L0 = 88000 km Cos θ0
- θ0= 24.847 degrees
- θ1= θ0+ 1.7 = 24.847 + 1.7 = 26.547 degrees
- L1 = 88000 km (Cos 26.547 degrees) = 78722 km
- During 29.53 days = L1 x29.53 = 78722 km x 29.53 = 2.324 mkm
- 2.324 mkm = 2π x 369981.1 km
- i.e. The moon on next day (13/10/2020) should be on 369981.1 km
The registered value on 13/10/2020 (369063 km)
The difference = 369063 – 369981.1 km = (- 919 km)
34. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
34
(9) 13 –October -2020
October 13 369063 km October 14 363617 km (The Next Day)
On 13/10/2020 the moon Earth distance was 369063 km
So we need to know where the moon will be on the next day (14/10/2020)?
Let's try to do that….
- The radius = 369063 km so C (orbital circumference) = 369063 x 2π=2.318 mkm
- The moon moves it during 29.53 days ( L0= 2.318 mkm/29.53) = 78526.6 km
- L0= 78526.6 km but L0 = 88000 km Cos θ0
- θ0= 26.83 degrees
- θ1= θ0+ 1.7 = 26.83 + 1.7 = 28.53 degrees
- L1 = 88000 km (Cos 28.53 degrees) = 77313.9 km
- During 29.53 days = L1 x29.53 =77313.9 km x 29.53 = 2.283 mkm
- 2.283 mkm = 2π x 363363.4 km
- i.e. The moon on next day (14/10/2020) should be on 363363.4 km
The registered value on 14/10/2020 (363617 km)
The difference = 363617 km – 363363.4 km = 254 km
35. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
35
(10) 14 –October -2020
October 14 363617 km October 15 359530 km (The Next Day)
On 14/10/2020 the moon Earth distance was 363617 km
So we need to know where the moon will be on the next day (14/10/2020)?
Let's try to do that….
- The radius = 363617 km so C (orbital circumference) = 363617 x 2π=2.28 mkm
- The moon moves it during 29.53 days ( L0= 2.28 mkm/29.53) = 77367.8 km
- L0= 77367.8 km but L0 = 88000 km Cos θ0
- θ0= 28.456 degrees
- θ1= θ0+ 1.7 = 28.456 + 1.7 = 30.156 degrees
- L1 = 88000 km (Cos 30.156 degrees) = 76090 km
- During 29.53 days = L1 x29.53 = 76090 km x 29.53 = 2.246 mkm
- 2.246 mkm = 2π x 357612 km
- i.e. The moon on next day (15/10/2020) should be on 357612 km
The registered value on 15/10/2020 (359530 km)
The difference = 359530 km – 357612 km = 1918 km
36. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
36
(11) 15 –October -2020
October 15 359530 km October 16 357269 km (The Next Day)
On 11/10/2020 the moon Earth distance was 359530 km
So we need to know where the moon will be on the next day (16/10/2020)?
Let's try to do that….
- The radius = 359530 km so C (orbital circumference) = 359530 x 2π=2.25 mkm
- The moon moves it during 29.53 days ( L0= 2.25 mkm/29.53) = 76498.3 km
- L0= 76498.3 km but L0 = 88000 km Cos θ0
- θ0= 29.622 degrees
- θ1= θ0+ 1.7 = 29.622 + 1.7 = 31.322 degrees
- L1 = 88000 km (Cos 31.322 degrees) = 75174.2 km
- During 29.53 days = L1 x29.53 =75174.2 km x 29.53 = 2.219 mkm
- 2.219 mkm = 2π x 353307 km
- i.e. The moon on next day (16/10/2020) should be on 353307 km
The registered value on 16/10/2020 (357269 km)
The difference = 357269 km – 353307 km = 3962 km
Note Please
- the moon stays in perigee one more day before to start its ascending motion, so the
day (17-10-2020) (the distance is 357105 km) can't be defined by the equation, so
we will start the ascending motion with the day (18-10-2020)
37. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
37
2nd
The ascending Motion (So -1.7)
(12) 18 –October -2020
October 18 359048 km October 19 362851 km (The Next Day)
On 18/10/2020 the moon Earth distance was 359048 km
So we need to know where the moon will be on the next day (19/10/2020)?
Let's try to do that….
- The radius = 359048 km so C (orbital circumference) = 359048 x 2π=2.255 mkm
- The moon moves it during 29.53 days ( L0= 2.255 mkm/29.53) = 76395.7 km
- L0= 76395.7 km but L0 = 88000 km Cos θ0
- θ0= 29.757 degrees
- θ1= θ0- 1.7 = 29.757 - 1.7 = 28.057 degrees
- L1 = 88000 km (Cos 28.057 degrees) = 77657.8 km
- During 29.53 days = L1 x29.53 =77657.8 km x 29.53 = 2.293 mkm
- 2.293 mkm = 2π x 364979.7 km
- i.e. The moon on next day (19/10/2020) should be on 364979.7 km
The registered value on 19/10/2020 (362851 km)
The difference = 362851 km – 364979.7 km = - (2129 km)
38. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
38
(13) 19 –October -2020
October 19 362851 km October 20 368058 km (The Next Day)
On 19/10/2020 the moon Earth distance was 362851 km
So we need to know where the moon will be on the next day (20/10/2020)?
Let's try to do that….
- The radius = 362851 km so C (orbital circumference) = 362851 x 2π=2.279 mkm
- The moon moves it during 29.53 days ( L0=2.279 mkm/29.53) = 77205 km
- L0= 77205 km but L0 = 88000 km Cos θ0
- θ0= 28.67 degrees
- θ1= θ0- 1.7 = 28.67 - 1.7 = 26.978 degrees
- L1 = 88000 km (Cos 26.978 degrees) = 78423.7 km
- During 29.53 days = L1 x29.53 =78423.7 km x 29.53 = 2.3158 mkm
- 2.3158 mkm = 2π x 368579.3 km
- i.e. The moon on next day (20/10/2020) should be on 368579.3 km
The registered value on 20/10/2020 (368058 km)
The difference = 368058 km – 368579.3 km = - (522 km)
39. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
39
(14) 20 –October -2020
October 20 368058 km October 21 374101 km (The Next Day)
On 20/10/2020 the moon Earth distance was 368058 km
So we need to know where the moon will be on the next day (21/10/2020)?
Let's try to do that….
- The radius = 368058 km so C (orbital circumference) = 368058 x 2π=2.31 mkm
- The moon moves it during 29.53 days ( L0=2.31 mkm/29.53) = 78313 km
- L0= 78313 km but L0 = 88000 km Cos θ0
- θ0= 27.137 degrees
- θ1= θ0- 1.7 =27.137- 1.7 = 25.437 degrees
- L1 = 88000 km (Cos 25.437 degrees) =79470 km
- During 29.53 days = L1 x29.53 =79470 km x 29.53 = 2.346 mkm
- 2.346 mkm = 2π x 373492.4 km
- i.e. The moon on next day (21/10/2020) should be on 373492.4 km
The registered value on 21/10/2020 (374101 km)
The difference = 374101 km – 373492.4 km = 609 km
40. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
40
(15) 21 –October -2020
October 21 374101 km October 22 380412 km (The Next Day)
On 21/10/2020 the moon Earth distance was 374101 km
So we need to know where the moon will be on the next day (22/10/2020)?
Let's try to do that….
- The radius = 374101 km so C (orbital circumference) = 374101 x 2π=2.35 mkm
- The moon moves it during 29.53 days ( L0=2.35 mkm/29.53) = 79598.6 km
- L0= 79598.6 km but L0 = 88000 km Cos θ0
- θ0= 25.24 degrees
- θ1= θ0- 1.7 =25.24- 1.7 = 23.54 degrees
- L1 = 88000 km (Cos 23.54 degrees) =80676.7 km
- During 29.53 days = L1 x29.53 =80676.7 km x 29.53 = 2.382 mkm
- 2.382 mkm = 2π x 379168.3 km
- i.e. The moon on next day (22/10/2020) should be on 379168.3 km
The registered value on 22/10/2020 (380412 km)
The difference = 380412 km – 379168.3 km = 1244 km
41. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
41
(16) 22 –October -2020
October 22 380412 km October 23 386497 km (The Next Day)
On 22/10/2020 the moon Earth distance was 380412 km
So we need to know where the moon will be on the next day (23/10/2020)?
Let's try to do that….
- The radius = 380412 km so C (orbital circumference) = 380412 x 2π=2.39 mkm
- The moon moves it during 29.53 days ( L0=2.39 mkm/29.53) = 80941.4 km
- L0= 80941.4 km but L0 = 88000 km Cos θ0
- θ0= 23.1 degrees
- θ1= θ0- 1.7 = 23.1 - 1.7 = 21.404 degrees
- L1 = 88000 km (Cos 21.404 degrees) =81930 km
- During 29.53 days = L1 x29.53 =81930 km x 29.53 = 2.419 mkm
- 2.419 mkm = 2π x 385059.3 km
- i.e. The moon on next day (23/10/2020) should be on 385059.3 km
The registered value on 23/10/2020 (386497 km)
The difference = 386497 km –385059.3 km = 1438 km
42. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
42
(17) 23 –October -2020
October 23 386497 km October 24 391989 km (The Next Day)
On 23/10/2020 the moon Earth distance was 386497 km
So we need to know where the moon will be on the next day (24/10/2020)?
Let's try to do that….
- The radius = 386497 km so C (orbital circumference) = 386497 x 2π=2.42 mkm
- The moon moves it during 29.53 days ( L0=2.42 mkm/29.53) = 82236.1 km
- L0= 82236.1 km but L0 = 88000 km Cos θ0
- θ0= 20.852 degrees
- θ1= θ0- 1.7 = 20.852 - 1.7 = 19.152 degrees
- L1 = 88000 km (Cos 19.152 degrees) =83129.2 km
- During 29.53 days = L1 x29.53 =83129.2 km x 29.53 = 2.4548 mkm
- 2.4548 mkm = 2π x 390694.3 km
- i.e. The moon on next day (24/10/2020) should be on 390694.3 km
The registered value on 24/10/2020 (391989 km)
The difference = 391989 km –390694.3 km = 1295 km
43. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
43
(18) 24 –October -2020
October 24 391989 km October 25 396659 km (The Next Day)
On 24/10/2020 the moon Earth distance was 391989 km
So we need to know where the moon will be on the next day (25/10/2020)?
Let's try to do that….
- The radius = 391989 km so C (orbital circumference) = 391989 x 2π=2.462 mkm
- The moon moves it during 29.53 days ( L0=2.462 mkm/29.53) = 83404.6 km
- L0= 83404.6 km but L0 = 88000 km Cos θ0
- θ0= 18.597 degrees
- θ1= θ0- 1.7 = 18.597 - 1.7 = 16.897 degrees
- L1 = 88000 km (Cos 16.897 degrees) =84200 km
- During 29.53 days = L1 x29.53 =84200 km x 29.53 = 2.486 mkm
- 2.486 mkm = 2π x 395729.5 km
- i.e. The moon on next day (25/10/2020) should be on 395729.5 km
The registered value on 25/10/2020 (396659 km)
The difference = 396659 km –395729.5 km = 930 km
44. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
44
(19) 25 –October -2020
October 25 396659 km October 26 400395 km (The Next Day)
On 25/10/2020 the moon Earth distance was 396659 km
So we need to know where the moon will be on the next day (26/10/2020)?
Let's try to do that….
- The radius = 391989 km so C (orbital circumference) = 396659 x 2π=2.49 mkm
- The moon moves it during 29.53 days ( L0=2.49 mkm/29.53) = 84398.3 km
- L0= 84398.3 km but L0 = 88000 km Cos θ0
- θ0= 16.449 degrees
- θ1= θ0- 1.7 = 16.449 - 1.7 = 14.749 degrees
- L1 = 88000 km (Cos 14.749 degrees) = 85100.4 km
- During 29.53 days = L1 x29.53 = 85100.4 km x 29.53 = 2.513 mkm
- 2.513 mkm = 2π x 399958.7 km
- i.e. The moon on next day (26/10/2020) should be on 399958.7 km
The registered value on 26/10/2020 (400395 km)
The difference = 400395 km –399958.7 km =437 km
45. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
45
(20) 26 –October -2020
October 26 400395 km October 27 403181 km (The Next Day)
On 26/10/2020 the moon Earth distance was 400395 km
So we need to know where the moon will be on the next day (27/10/2020)?
Let's try to do that….
- The radius = 400395 km so C (orbital circumference) = 400395 x 2π=2.515 mkm
- The moon moves it during 29.53 days ( L0=2.515 mkm/29.53) = 85193.22 km
- L0= 85193.22 km but L0 = 88000 km Cos θ0
- θ0= 14.5 degrees
- θ1= θ0- 1.7 = 14.5 - 1.7 = 12.809 degrees
- L1 = 88000 km (Cos 12.809 degrees) = 85809.8 km
- During 29.53 days = L1 x29.53 = 85809.8 km x 29.53 = 2.533 mkm
- 2.533 mkm = 2π x 403299 km
- i.e. The moon on next day (27/10/2020) should be on 403299 km
The registered value on 27/10/2020 (403181 km)
The difference = 403181 km – 403299 km =112 km
46. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
46
(21) 27 –October -2020
October 27 403181 km October 28 405059 km (The Next Day)
On 27/10/2020 the moon Earth distance was 403181 km
So we need to know where the moon will be on the next day (28/10/2020)?
Let's try to do that….
- The radius = 403181 km so C (orbital circumference) = 403181 x 2π=2.533 mkm
- The moon moves it during 29.53 days ( L0=2.533 mkm/29.53) = 85786 km
- L0= 85786 km but L0 = 88000 km Cos θ0
- θ0= 12.879 degrees
- θ1= θ0- 1.7 = 12.879 - 1.7 = 11.179 degrees
- L1 = 88000 km (Cos 11.179 degrees) = 86330 km
- During 29.53 days = L1 x29.53 = 86330 km x 29.53 = 2.549 mkm
- 2.549 mkm = 2π x 405738.5 km
- i.e. The moon on next day (28/10/2020) should be on 405738.5 km
The registered value on 28/10/2020 (405059 km)
The difference = 405059 km – 405738.5 km = - (680) km
47. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
47
(22) 28 –October -2020
October 28 405059 km October 29 406104 km (The Next Day)
On 28/10/2020 the moon Earth distance was 405059 km
So we need to know where the moon will be on the next day (29/10/2020)?
Let's try to do that….
- The radius = 405059 km so C (orbital circumference) = 405059 x 2π=2.54 mkm
- The moon moves it during 29.53 days ( L0=2.54 mkm/29.53) = 86185.6 km
- L0= 86185.6 km but L0 = 88000 km Cos θ0
- θ0= 11.655 degrees
- θ1= θ0- 1.7 = 11.655 - 1.7 = 9.955 degrees
- L1 = 88000 km (Cos 9.955 degrees) = 86675 km
- During 29.53 days = L1 x29.53 = 86675 km x 29.53 = 2.559 mkm
- 2.559 mkm = 2π x 407359.4 km
- i.e. The moon on next day (29/10/2020) should be on 407359.4 km
The registered value on 29/10/2020 (406104 km)
The difference = 406104 km – 407359.4 km = - (1256) km
48. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
48
2-4 The Test Results Discussion And Analysis
Let's take a look on the different distances between the equation results and the
registered data in following
Day Registered Data Results (1.7) Difference
5-10-2020 405,690 km --- ---
6-10-2020 404,171 km 403125.3 km 1046 km
7-10-2020 401,649 km 401390 km 259 km
8-10-2020 398,073 km 398545.6 Km - 473 km
9-10-2020 393,464 km 394568.8 km -1105 km
10-10-2020 387,944 km 389510 km -1567 km
11-10-2020 381,763 km 383520 km -1758 km
12-10-2020 375,302 km 376875.3km -1574 km
13-10-2020 369,063 km 369981km -919 km
14-10-2020 363,617 km 363363.4km 254 km
15-10-2020 359,530 km 357612 km 1918 km
16-10-2020 357,269 km 353307 km 3962 km
17-10-2020 357,105 km ---- --
18-10-2020 359,048 km --- --
19-10-2020 362,851 km 364979.7 km - 2129 km
20-10-2020 368,058 km 368579.3 km -522 km
21-10-2020 374,101 km 373492.4 km 609 km
22-10-2020 380,412 km 379168.3 Km 1244 Km
23-10-2020 386,497 km 385059.3Km 1438 km
24-10-2020 391,989 km 390694.3 km 1295 km
25-10-2020 396,659 km 395729.5 km 930 km
26-10-2020 400,395 km 399958.7 km 437 km
27-10-2020 403,181 km 403299 km 112 km
28-10-2020 405,059 km 405738.5 km -680 km
29-10-2020 406,104 km 407359.4 km -1256 km
[
49. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
49
The Test Results Analysis:
- The Total Results Are 22 Values
(1st
Category)
o 15 values, defines the moon position in range 1300 km (Error 3%)
(2nd
Category)
o 5 values, defines the moon position in range 1300-2000 km (Error 4.6 %)
(3rd
Category)
o 2 values, defines the moon position in range 2000-3500 km (Error 8 %)
- The Results Explanation
- The distance from perigee to apogee =43000 km…
o 1st
Category of results defines the moon position in error range (1300 km) =
error (3%), that means, (15 values of 22) defines the moon position with
error (3%) only (Small Error Range)
o 2nd
Category of results defines the moon position in error range from (1300
km to 2000 km) = error (4.5%), that means (5 values of 22) defines the
moon position with error (4.5%) (Average Error Range)
o 3rd
Category of results defines the moon position in error range from (2000
km to 3500 km) = error (8%), that means (2 values of 22) defines the moon
position with error (8%) (Great Error Range)
- The Equation Accuracy
o The previous explanation shows that, the equation has a good range of
accuracy and its error is in the acceptable error range
The Conclusion
The Equation Is correct and trustee
And
It's a useful tool to define the moon position daily
50. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
50
Appendix No. 1 (The Moon Orbital Motion Equation Concept)
- The moon moves daily (88000 km) on the right triangle hypotenuse (AC), but the
moon creates an angle (θ) between its motion direction and its orbital horizontal
level, by that the real displacement will be (L= 88000 km cos (θ)) through the
moon orbit, and by that, spite the moon moves 88000 km and the orbital horizontal
distance be less than (88000 km) and this is the objective for which the moon uses
Pythagoras triangle –
- As an example, if (θ) =28.63 degrees So the real displacement (L) = 77237 km, So,
if the moon real displacement daily be equal this value during 29.53 days the moon
will move a distance = 2.28 million km and this will be the moon orbital
circumference, BUT for what radius? 2.28 mkm = 2π x (0.363 mkm)
- The Moon Orbital Perigee Radius =0.363 mkm
- That means, the moon by a real displacement =77237 km can move around Earth
through the perigee orbit (radius =0.363 mkm), this is the useful result the moon
performs by using Pythagoras triangle,
- Now let's suppose the moon doesn't use Pythagoras triangle, what would happen?
- The moon daily displacement = 88000 km, during 29.53 days the moon moves a
distance = 2.598 mkm BUT for what radius? 2.598 mkm = 2π x (0.413 mkm)
- The Moon Orbital Apogee Radius =0.406 mkm
- So the moon will move along month revolving round Earth through its apogee
orbit (or even far from apogee orbit) because the total distance can't be passed
through any more near orbit around Earth…
- The data shows how Pythagoras triangle is so useful for the moon orbital motion.
51. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
51
The Angle θ
- The angle (θ) needs to pay some attention for its specific effect…let's summarize
the idea in following
o The angle (θ) changes the real displacement (L = 88000 cos (θ)), through the
moon orbit..
o We know that, when the real displacement (L) be shorter the moon can
move through near orbits to Earth and that means the moon will be near or
at Perigee radius (0.363 mkm)
o When the real displacement (L) be greater the moon has to move through
orbits far from Earth and by that the moon will be near or at to apogee orbit
o That means, the angle (θ) does change the real displacement (L) and also
change the distance between the moon to perigee or to apogee, shortly, the
angle defines the moon position (as a ship) between 2 river banks….
- Let's analyze the angle (θ) in some deep
o We know that (363000)2
+ (86000)2
= (373000)2
o In Pythagoras triangle with the previous dimensions, what's the angle (θ)
value? (θ) = 13.33 degrees
o Also (396800)2
+ (86000)2
= (406000)2
the angle (θ) = 12.229 degrees
o I have used (363000 km and 406000 km) because they are the perigee and
apogee radiuses between which the moon moves.
o The difference between angles = 1.1 degrees
i.e.,
The angle (1.1 deg.) controls the moon motion from perigee to apogee.
52. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
52
References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
The Moon Motion Basic Equation (III) (Test No.2)
https://www.academia.edu/s/e493aec33a
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-basic-equation-iii-test-no2
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous