The solar group is a clock (iii)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
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Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Solar Group is A Clock (III)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –16th
April 2021
1- Abstract
Paper hypothesis
- Venus motion connects Mercury & Earth Motions
- Venus motion causes to create the rate of time (1 hour is equivalent to 24 hours)
- Venus rotation period is the main platform to use the rate of time (1 hour is
equivalent to 24 hours).
- Venus uses (1 h) of (Mercury Motion) to be equivalent to (24 h) of Earth motion
- Venus motion shows one clear example of (the motion transportation) among the
solar planets. (For Venus motion the transportation is done between Mercury and
Earth motions)
- The solar group is A Great Clock (= a machine of gears) and the motion is
transported among the planets as among gears.
The hypothesis Explanation
- The solar system motion main concept is that (equal distances are used for
different rates of time). That means, by equality of distances, Planets different
motions can create different rates of time
- The solar system is one building (one machine) and each planet is a part in this
same building connected to it by geometrical Mechanisms.
Paper objective:
- The paper analyzes Venus rotation period role in the rate of time creation.

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2- Venus Rotation Period Analysis
2-1 Preface
2-2 Venus Motion Effect
2-3 The Rate Of Time Creation Process
2-1 Preface
- Let's summarize the whole idea in following
o Venus motion uses the distances values as periods of time –
o Venus motion uses 1 million km to be equivalent to 1 solar day (24 hours)
(in more accurate value =23.9 hours = Earth Rotation Period)
o And
o Venus motion uses 1 million km to be equivalent to 1 hour of Mercury
Motion
o By that
o Venus motion is ( The Gear) on which Mercury motion is transported to
Earth motion –
o Based on this description we have 3 Gears move in one unified motion –
and these 3 gears (Mercury – Venus – Earth) move together in harmony
motion – in which – 1 hour of Mercury motion be equivalent to (23.9 hours
or 24 hours) of Earth motion
o Venus works as the middle Gear between the 2 motions on which this
motion is transported.
Notice
- What does mean " the motion transportation" among planets?
- This expression will be explained through the discussion – where it's a new
expression to describe the solar planets motions – and we should define it as clear
as possible through the discussion.

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2-2 Venus Motion Effect
I - Data
(1)
2.574 mkm x 243 Solar days = 625.6 mkm (Earth Jupiter Distance)
And
3.02 mkm x 243 Solar days = 735 mkm
(2)
47.4 km/s x 243 hours = 41.4 mkm (Earth Venus Distance)
And
2 x 24.1 km/s x 243 hours = 42.16 mkm
(3)
4.095 mkm x 58.66 solar days = 240 mkm
And
And
But
366.7 = 116.75 solar days x π
(4)
243 solar days = 27.3 solar days x 8.9
(5)
(47.4/4.7) x 24 hours = 242 hours

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II – Discussion
Equation No. (1)
2.574 mkm x 243 Solar days = 625.6 mkm (Earth Jupiter Distance)
And
3.02 mkm x 243 Solar days = 735 mkm
Where
- 2.574 mkm = Earth motion distance during a solar day
- 243 days = Venus Rotation Period
- 3.024 mkm = Venus motion distance during a solar day
- Equation no. (1) tells, Earth moves during 243 solar days a distance = Earth Jupiter
distance (629 mkm) (error 0.5%)
- These are 3 known values, Earth velocity per a solar day, uses a defined period
(Venus rotation period 243 d) to pass a defined distance (Earth Jupiter distance)
- That tells, the motion is designed and mentioned geometrically – and that means-
Earth considers Venus rotation period through its motion - this meaning supports
the new description that the solar system is one geometrical building (as machine
of gears) and each planet is a part of this building (or a gear in this machine). This
is an important meaning because the classical description considers the planets as
separated rigid bodies independent in their motions from each other – and here we
have Earth motion uses Venus rotation period – the data gives more wide vision
because the period (243 days) passes on Venus while Venus does its rotation
period – but what about of the Earth (the most neighbor planet), does Earth know
that Venus rotates its rotation period in 243 days? The Earth knows that and uses
this same period for Earth motion – on the other side Venus uses 365.25 days for
Venus motion – the interaction is done normally and be seen in both planets
motions data

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- Venus during 243 solar days does its rotation period and pass a distance =735
mkm
- The most near distance is 720.7 mkm = Mercury Jupiter Distance but the error is
around 2%, which creates a difficulty to accept this distance as our mentioned
distance (735 mkm)
- But
- Uranus (6.8 km/s) moves during 30589 hours a distance = 742 mkm (this distance
has an error 1% b with our distance 735 mkm )
- Where 30589 solar days = Uranus Orbital Period
- That means, Uranus uses its orbital period (30589 days) in hours units to pass the
distance 742 mkm
- The motion velocity is Venus (known velocity) and the period is Venus rotation
period (known period) but the distance is 742 mkm which is a new distance for us
- Why an interaction be found between Venus and Uranus motions?
- Let's leave this question to be answered in the next point
- The previous equation discussion tells us that, Earth and Venus use the period 243
as 243 solar days (Venus Rotation period 5832.5 hours =243 days)
- In this paper we discuss a rate of time in which (1 hour is equivalent to 24 hours)
and here in this equation we use the value as 243 solar days (used in days units),
- In Mercury motion this period should be used as 243 hours
- And by that
- 1 hour of Mercury motion will be equivalent to 24hours of Earth motion, IF
There's a relationship between Mercury and Earth motions
- Let's discuss the next equation

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Equation No. (2)
47.4 km/s x 243 hours = 41.4 mkm (Earth Venus Distance)
And
2 x 24.1 km/s x 243 hours = 42.16 mkm
Where
- 47.4 km/s = Mercury velocity
- 24.1 km/s = Mars velocity
- Equation no. (2) tells that, Mercury moves during 243 hours a distance = Venus
Earth Distance
- And
- Mars velocity = 0.5 Mercury Velocity (Approximately), So
- Mars needs a double value of the same period to pass the distance (error 1.8%)
- Equation no. (2) provides a proof for the claim, Mercury (at least) moves a
distance during 243 hours and this distance connects between Earth and Venus
- Can this data provide a clear meaning? What's the relationship between this
distance 41.4 mkm (Venus Earth Distance) and the distance Earth passes 629 mkm
(Earth Jupiter Distance)? How to create a connection between this data?!
- This connection is discussed in point no. 3 (The Motion Transportation)
- Now let's take a look on the equation no. 3

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Equation No. (3)
4.095 mkm (Mercury velocity per solar day) x 58.66 solar days = 240 mkm
And
2.082 mkm (Mars velocity per solar day) x 116.75 solar days = 243 mkm
And
3.024 mkm (Venus velocity per solar day)x 365.25 solar days = 1106 mkm
But
366.7 = 116.75 solar days x π
- Mercury moves during its rotation period (58.66 days) a distance = 240 mkm
- Mars moves during Venus day period (116.75 days) a distance = 243mkm
- Venus sees 240 mkm (error 1%) and 243 mkm as 243 solar days
- This data shows that Mercury and Mars use the same behavior with Venus
- They also understand Venus language - because
- Venus moves during (365.25 days) a distance =1106 mkm = 2π x175.9 mkm
Where 175.94 solar days = Mercury Day Period
- The period 365.25 days depends on Venus day period where (366.7 = 116.75 x π)
but 366.7 Earth rotation periods = 365.25 solar days
- This equation no. (3) should be discussed as deep as possible later –
- I provide it here to show that, Mercury and Mars use the same behavior with
Venus and specially with Venus Rotation Period (243 days) and this same
behavior is found based on a general interaction found between the three planets
motions.
- So the simple equation by which Mars moves a distance =243 mkm during 116.75
days, is just a cover hidden under it a river of interactions found between the 2
planets – it's 2 members of one body are interacted together to produce one task
does by the 2 members – and this simple equation – is a reference only about the
great machine under cover…

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Equation No. (4)
243 solar days = 27.3 solar days x 8.9
Where
- 243 days = Venus rotation period
- 27.3 days = The Moon Orbital Period
- What's 8.9?
- 89 solar days = 2136 hours
- 2136 mkm = π x 680 mkm (Venus Orbital Circumference)
- The equation uses 1 mkm to be = 1 hour ( in the value 2136 mkm)
- But
- 243 and 27.3 both values are used in solar days
- That means
- The equation uses a different rate of time – where 1 hour be equivalent 24 hours
Equation No. (5)
(47.4/4.7) x 24 hours = 242 hours
Where
- 47.4 km/s = Mercury Velocity
- 4.7 km/s = Pluto velocity
- The input value is 24 hours but the output is 242 hours, if this value aim to the
value 243 solar days (Venus rotation period), so this equation shows the rate of
time mechanism – where the equation output 242 hours (or 243 hours) which will
be used as 243 solar days (Venus Rotation Period) . and the machine uses the rate
(47.4/4.7)
- What can this rate do?
- It's the rate between Mercury velocity (the greatest velocity) and Pluto velocity
(the smallest velocity) and that means,. The whole machine is used in this process,
the machine uses its motion to perform this task.

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2-3 The Rate Of Time Creation Process
I- Data
Equation No. (3) (continued)
And
And
But 366.7 = 116.75 solar days x π
II- Discussion
- The rate of time is
- (1 hour of Mercury Motion is Equivalent to 24 hours of Earth motion)
- We use the equation no.(3) to discuss it as possible and show this rate of time
o Mercury moves during its rotation period 58.66 days distance =240 mkm
o But
o Mercury rotation period = 1407.6 hours = 58.66 solar days
o 2 Mercury rotation periods = 2 x 1407.6 h = 2815.2 hours
o If 1 mkm = 1 hour
o 2815.2 hours will be = 2815.2 mkm = Mercury Uranus Distance
o The input is
o 2815.2 mkm which is used as 2815.2 hours by Mercury motion
o The output is
o 2 x 243 mkm where each 1 mkm be equivalent to 1solar day (24 hours)
o The input is Mercury Uranus Distance 2815 mkm
o The output must be Earth Uranus Distance 2722 mkm
o Where 2722 mkm = 243 mkm x 2 x 5.6 degrees
o The input is 2 Mercury rotation period (2 x 1407.6 h) and the output is 2
Venus rotation period (2 x 243 solar days)
o 5.6 deg = 0.5 deg + 5.1 deg (= the moon orbital inclination measured above
the moon diameter)
o The rate of time is created with (the moon orbital inclination creation)

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(1st
Point)
Why Uranus Distance is used by the rate (1 mkm = 1 hour)
17687 mkm = 24 x 735 mkm
17687 mkm = 2π x 2815 mkm (Mercury Uranus Distance)
- Where
- 735 mkm = Venus Motion distance during 243 solar days
- The previous data tells that, each 1 mkm of Venus motion is equivalent to 24 mkm
of the distance (17687 mkm) where this distance is the circumference of Mercury
Uranus Distance
- Simply it tells, Venus uses the rate (1: 24) and this rate is created by Mercury
Uranus Motions interaction
- For that reason the distance (742 mkm) which is passed by Uranus during the
period 30589 hours be equivalent to Venus motion distance during 243 days (1%)
- But
- What's the relationship between Venus & Uranus motion data? Why does Uranus
motion consider Venus motion?
o 30589 days = 5.1 x 6000 days
o Venus diameter =12104 km if each 1 km = 1 days so it = 12104 days
o Between (6000 and 6052 the error 1%)
Shortly
o The interaction between Venus and Uranus Motions aim to create the moon
orbital inclination -
o And in this creation the rate of time (1 hour is equivalent to 1 solar day) is
created as a side product for the moon orbital inclination creation process.
o Notice 12104 km = 243 km x 49.8
o Why this is important? Because 49.8 x 2 = 99.6
o 101.8 I different from 99.6 with error (2%) and the rate 101.8 = (Pluto
orbital distance/ Mercury orbital distance)

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Notice
- The planets motions interaction is so complex, I apologize if the discussion can't
show its depth – let's add one feature in following:
- Uranus (6.8 km/s) moves during its day period (17.2 h) a distance = 412056 km
- Venus (35 km/s) moves during 12104 seconds = 423640 km
- Pluto (4.7 km/s) moves during 90560 seconds = 425632 km
- Where
- 12104 km = Venus diameter
- 90560 days = Pluto Orbital Period
- This data we discussed in (the 6 days cycle)
o The data aims to show that Venus diameter is used as a period of time for
Venus motion by the motion geometrical design – that means- the motion is
mentioned and designed
o The value 12101 km is used simply as 12104 seconds - Also
o During12104 days Venus moves a distance= 2 Uranus orbital circumference
o The planet diameter is used as a period of time for this same planet motion
o As we have discussed in Saturn diameter – where Saturn day period 10.7
hours = 38520 seconds where Saturn diameter 120536 km = 38520 km x π
o Based on that the planet diameter (or circumference) is another form of its
day period or its orbital period – all of them are periods of time found in
different forms
o Also
o Venus diameter 12104 km which is used as 12104 seconds behaves similar
to any planet day period and by that – where Uranus uses its day period
(17.2 h) in the cycle of (6 days cycle), Venus uses its diameter in the same
cycle by using (6 x 12104 seconds) – (the paper discuss also 8 days cycles)

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(2nd
Point)
Why does Mercury Rotation period depend on Mercury Uranus Distance?
- (30589 hours /1407.6 hours) = 21.8
- Where
- 30589 days = Uranus orbital Period
- 1407.6 hours = Mercury rotation period
- 21.8 = Jupiter Mass / Uranus Mass
- The equation uses the value 30589 days as 30589 hours where
- Uranus moves during 30589 hours a distance =742 mkm (1% difference with
Venus motion distance during 243 solar days)
o Why does Mercury rotation period depend on Mercury Uranus Distance?
o Because
o The rate of Mass between Jupiter and Uranus shows the force effect on the
inner planets, where this rate is used frequently in the inner planets motions
data
o That means, Mercury motion is effected by the masses rate of (Jupiter and
Uranus) means mercury motion is effected by Uranus motion and because of
that Uranus orbital period is rated to Mercury rotation period with 21.8
The next question is
- Why the distance 742 mkm is used?
- It's difficult interaction because (30589 seconds x 2 +742 seconds = 17.2 hours),
and that means, Uranus Day period (17.2 hours) is created based on (Uranus
orbital period 30589 but unused in seconds units), in this interaction the value 742s
is distinguish and need more analysis to know what interaction is done with Venus
to define Uranus day period based on this interaction.

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(3rd
Point)
What's the relationship between Mercury and Uranus?
30589 days = (88 days x 346.6 days) + 88 days (Mercury orbital period)
- Where
- 30589 days = Uranus orbital Period
- 346.6 Days = The Nodal Year
- Uranus (6.8km/s) moves during 51118 seconds a distance = 347602 km
- If 1000 km = 1 Solar Day
- 347602 km = 347.6 Solar Days
- 30589 days Uranus orbital Period = 347.6 x 88 solar days (Mercury orbital period)
- Also,
- 2550973 km (the moon apogee orbital circumference) = 21.8 x 116750 km
- If 1000 km = 1 Solar Day
- 116750 km = 116.75 Solar Days = Venus Day Period

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3 – The Motion Transportation
3-1 The 8 Days Cycle
3-3 The Cycles Motions Interaction
Preface
(I)
- Jupiter (13.1 km/s) moves during its day period (9.9 h) a distance = 466884 km
- The distance 466884 km = 449197 km (Jupiter circumference) +17686 km
- The 17686 km during 8 days be 141492 km (Jupiter Diameter) (error 1%)
- That means
- During 8 Jupiter Days (8 x 9.9 = 79.2 h), Jupiter moves a distance = 3735072 km =
8 Jupiter Circumferences + 1 Jupiter Diameter
- Because the additional distance = 1 Jupiter Diameter, we conclude that, it must be
a cycle of Jupiter motion and this additional distance (Jupiter diameter) is a
reference for this cycle
(II)
- The distance passed by Jupiter during (8 Jupiter days) = the distance passed by
Saturn during (10 of Saturn days)
- Let's test that
- Saturn (9.7 km/s) moves during 10 days (10.7 hours) a distance = 3736440 km
- Where 3736440 km = Jupiter motion distance during (8 days)
- That tells
- Jupiter has a cycle of (8 Jupiter days) and
- This distance is transported (if really) to Saturn during (10 Saturn days)
- Based on that, we concluded a rule, a planet motion be transported to the next
plant based on the rate 80% - if true – Uranus motion should be 80% of Saturn
motion, can that be real? NO

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- The next planet is (Neptune)
- Based on that equal distances be
o Passed by Jupiter during (8 Jupiter Days) =
o Passed by Saturn during (10 Saturn Days) =
o Passed by Neptune during (12 Neptune Days)
- In Real Data be
- Jupiter (13.1 km/) during 8 days (79.2 h) moves a distance = 3735072 km
- Saturn (9.7 km/) during 10 days (107 h) moves a distance = 3736440 km
- Neptune (5.4 km/) during 12 days (193.2 h) moves a distance = 3755808 km
- The distances are equal and the errors are less 1%
(III)
A Question
Why doesn't Uranus follow this same rule?
- Uranus (6.8 km/s) moves during (153.3 hours) a distance = 3752784 km
- Uranus uses (153.3 h = Pluto Day period) to pass an equal distance
- Why?? for 2 reasons
(1st
Reason)
- To create a cycle, because
- Uranus motion distance during (153.3 h) – Jupiter motion distance during (79.2 h)
= 3752784 km – 3735072 km = 17712 km
- During 8 days this distance 17712 km will be 141696 km = Jupiter diameter (1%)
- Means, Uranus moves during 8 Pluto days a distance = Jupiter motion distance
during 64 Jupiter days + 1 Jupiter diameter (error 1%)
- In calculations
- Uranus (6.8 km/s) during (8 x153.3 h) moves = 30022272 km
- Jupiter (13.1 km/s) during (64 x 9.9 h) moves = 29880576 km
- Error less 1% (the real difference = 141696 km = Jupiter diameter)
- That means

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- Jupiter 8 days cycle which is transported to Saturn as Saturn 10 days cycle and
transported to Neptune as Neptune 12 days cycle is used also by Uranus But
- Uranus creates a greater cycle where
- Uranus (8 Pluto days periods) cycle is used by Jupiter as 64 Jupiter days cycle and
by Saturn as 80 Saturn days cycle and by Neptune as 100 Neptune days cycle
- So, The cycle is transported from one planet to another and this cycle be
configured according to each planet motion – it's one cycle but used by all planets
in different forms according to each planet velocity, day period and other data
- Can that be considered as " A Motion Transportation"?
(2nd
Reason)
- Uranus uses of the period (153.3 hours) cause Pluto day period to be 153.3 hours
- The geometrical mechanism behind this process is discussed in the paper..
Notice
- Saturn (9.7 km/) during 10 days (107 h) moves a distance = 3736440 km
- 10 Saturn Circumferences = 3786750 km
- But
- 3786750 km - 3736440 km = 50310 km (= Uranus Diameter 1.6%)
Notice
- Neptune (5.4 km/) during 12 days (193.2 h) moves a distance = 3755808 km
- 12 Neptune Circumferences x 2 = 3734323.2 km
- 3755808 km -3734323.2 km = 21485 km (Mars Circumference) (0.6%)
Notice
- Uranus (6.8 km/) during 9 Uranus days (17.2h x 9 =154.8 h) a distance =3789504 km
(3789504 km = π x 1206237 km) (where Saturn diameter 120536 km).
- Uranus motion distance during its day period = (2.6 Uranus circumference) (hypo.)
- 3789504 km - (2.6 x9 Uranus Circumferences) 3757851km =31653 =2π x 5040 km

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The Cycle Discussion
I- Data
Group No. (A)
(1)
Jupiter (13.1 km/s) during (64 x 9.9 h) moves a distance = 29880576 km
(2)
Saturn (9.7 km/s) during (80 x 10.7 h) moves a distance = 29891520 km
(3)
Neptune (5.4 km/s) during (100 x 16.1 h) moves a distance = 31298400 km
(4)
Uranus (6.8 km/s) during 8 Pluto days (153.3 x 8) moves a distance= 30022272 km
Group No. (B)
(5)
(6)
Saturn (9.7 km/s) during (640x 10.7 h) moves a distance =239132160 km
(7)
Neptune (5.4 km/s) during (12430 h) moves a distance = 241639200 km
(8)
Uranus (6.8 km/s) during 64 Pluto d. (153.3 x64 h) moves a distance= 240178180 km
(9)
Mercury (47.4 km/s) during (1407.6 h) moves a distance= 240192864 km
(10)
Mars (24.1 km/s) during (2802 h) moves a distance= 243101520 km

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II- Discussion
(1)
(2)
Saturn (9.7 km/s) during (80 x 10.7 h) moves a distance = 29891520 km
(3)
Neptune (5.4 km/s) during (100 x 16.1 h) moves a distance = 31298400 km
(4)
Uranus (6.8 km/s) during 8 Pluto days (153.3 x 8) moves a distance= 30022272 km
Data Analysis
- (4) – (1) = 141696 km = (Jupiter diameter error 1%)
- (4) – (2) = 130752 km
- (3) – (4) = 1276128 km
- (2) – (1) = 10921 km = The Earth Moon Circumference
- Because (4) – (1) ( Uranus Motion distance – Jupiter motion distance) = Jupiter
diameter (error 1%), because of that we have concluded there's a cycle between
Uranus motion (during 8 Pluto days) and Jupiter motion (during Jupiter 64 days)
- The distance 1276128 km = (5.1 mkm/4), because of that, we can create this
difference between Neptune and Uranus motions by using a suitable period
- We know that 5.1 mkm can be = 5.1 degrees = The Moon Orbital Inclination.
- So, let's produce this value as a different between Neptune and Uranus motions
distances in following:

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(1st
Point) (The Moon Orbital Inclination =5.1 degrees)
- Neptune moves during (100 x 4 Neptune days) a distance = 125193600 km
- Uranus moves during (8 x 4 Pluto days) a distance = 120089088 km
- The difference = 5.104512 million km = 5.1 degrees
- Jupiter moves during (64x4 Jupiter days) a distance = 119522304 km
- Saturn moves during (80 x4 Saturn days) a distance = 119566080 km
- The difference = 43776 km = 4 x 10921 km (the moon circumference)
Notice (1)
- Neptune motion 125193600 km – Saturn motion 119566080 km = 5.62752 mkm
- Where 5.6275 mkm = 5.627 degrees
- 5.1 degrees = The Moon Orbital Inclination.
- 0.5 degree = the moon angular diameter
- 5.6 degrees = the moon orbital inclination measured above the moon diameter.
Notice (2)
- Neptune motion needs a period = (4 x 100 Neptune days) = 6440 hours
- Uranus motion is done during (32 Pluto days) = 4905.6 hours
- Jupiter motion is done during (256 Jupiter days) = 2534.4 hours
- Saturn motion is done during (320 Saturn days) = 3424 hours
o 6440 x 0.99 = 6375 hour (but 6375 km = Earth Radius)
o (6440 h /4905.6 h) = 1.3 (but Jupiter orbital inclination =1.3 deg error 1%)
Notice (3)
- Venus (3.024 mkm per solar day) moves during 88 days (Mercury orbital period)
a distance = 266.1 mkm if this value be = 266.1 solar days
- So, 266.1 solar days = 6387 hours
- This value = the period Neptune needs to pass the required distance 125.2 mkm
(error 1%)

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Discussion (continued)
- Why the previous calculations are important? What useful result can be found
behind?
- The Distances Define The Required Periods
o The distance 1276128 km is a difference between Uranus motion during (8
Pluto days) and Saturn motion done during (80 Saturn days)
o We don’t know this distance 1276128 km, By that, these cycles aren't useful
for us, But
o We know the distance 5.1 mkm (where 5.1 mkm = 4 x 1276128 km)
o That means, the cycle which we deal with is a quarter of the complete one
cycle – and based on that – the complete cycle is done by
o Uranus motion during (32 Pluto days)
o And by Saturn motion during (320 Saturn days)
Based on that
o If the complete cycle is found based on these periods we have to modify the
other plants motions accordingly to see what data these planets may tell us
o This method is know, for example
o Earth orbital period = around 365.25 days, we don't know how to account
this (0.25 day), it's some unknown value
o Means, the complete cycle = (3 x 365.25 days = 1461 days)
o Based on this same method, this discussion is done, but we use the distance
o For example
o Earth orbital distance =149.6 mkm, if the cycle causes a difference = 18.7
mkm, so that means, this cycle period is (= 1/8) of the complete cycle –
o That explains why we analyze the produced distances.
- In the next point, we use the distance 130752 km to find the correct cycle of it –
for that we need to use the data group no. (2)

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(2nd
Point) (The Moon Orbital Circumference)
- The distance 130752 km = the difference distance between 2 motions which are
- Uranus motion distance during (8 Pluto days) and
- Saturn motion distance during (8 Saturn days)
- The distance 130752 km is a different between 2 other distances which are:
o 141696 km (= Jupiter diameter error 1%) which is a different distance
between Uranus motion distance during (8 Pluto days) and Jupiter motion
distance during (64 Jupiter days).
o 10921 km (= the moon circumference) which is a different distance between
Saturn motion distance during (80 Saturn days) and Jupiter motion distance
during (64 Jupiter days).
o Why do we need this distance 130752 km?
o Because, 406000 km (the moon apogee radius) = π x 129234 km
o The difference between 130752 km and 129234 km is (1%)
o That means, the moon apogee orbit radius (r =406000 km) is defined
depends on the distance 130752 km
This data is important because
o The Moon Apogee Orbital Circumference 2550973 km (r =406000 km)
o But
o The moon displacements (88000 km) total during 29.53 days = 2598693 km
o The moon orbital circumference must be = 2598693 km = 2π x 413600 km
o Shortly
o The moon apogee radius should be = 413600 km because the moon daily
displacement =88000 km, But the fact is, the apogee radius =406000 km
o Why?
Notice
o 130752 km – 129234 km = 1518 km = (Venus diameter /8)
o So, we need a cycle of 8 times the previous one, let's see it in following..

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Group No. (B)
(5)
(6)
Saturn (9.7 km/s) during (640 x 10.7 h) moves a distance =239132160 km
(7)
Neptune (5.4 km/s) during (12430 h) moves a distance = 241639200 km
(8)
Uranus (6.8 km/s) during 64 Pluto d. (153.3 x64 h) moves a distance= 240178180 km
(9)
Mercury (47.4 km/s) during (1407.6 h) moves a distance= 240192864 km
(10)
Mars (24.1 km/s) during (2802 h) moves a distance= 243101520 km

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II- Discussion (continued)
(2nd
Point) (The Moon Orbital Circumference) (continued)
- (6) – (5) = 87550 km
- (8) – (5) = 1.133566 mkm = 1726 km + 1131840 km (Jupiter day velocity)
- (8) – (6) = 1.046020 mkm
- (10) – (5) = 4.05691 mkm (= Mercury motion distance per a solar day 1%)
- The Value which we deal with is the distance 1.046020 mkm
o ((8 x 406000 km) /π) = 1033870.5 km
o 406000 km = The Moon Apogee Orbital Radius
o 1.046020 mkm - 1033870.5 km = 12104 km (Venus Diameter)
o Because of Venus Diameter we conclude that this cycle is the complete one
and the previous was a part of it – so the compete cycle is in which
Uranus motion is done during 24 Pluto days (9811.2 h)
Jupiter motion is done during 512 Jupiter days (5068.8 h)
Saturn motion is done during 640 Saturn days (6848 h)
Neptune motion is done during (12430 hours)
Notice
- 1.133566 mkm = 4.7 km/s (Pluto velocity) x 2 x 120536 seconds
- Where
- 120536 km = Saturn Diameter
- The data shows that, Saturn diameter is created in double value
Notice
- (8) – (5) = 1.133566 mkm = 1726 km + 1131840 km
- Where
- 1737 km = The moon radius (error 0.6%)
- 1131840 km = Jupiter Motion Distance during a solar day
- This data tells that, one more cycle is found we still don't discover it this cycle will
distinguish between the value 1726 km and 1131840 km

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(3rd
Point) (Venus Rotation Period = 243 Solar Days)
- The previous data aimed to create Venus diameter as a different distance to define
the complete cycle and its periods of time
- The complete cycle distance is 240 mkm (approximately) (99%)
- This distance is passed by Jupiter, Saturn, Uranus and Neptune according to the
discussion but
- 240 mkm is passed by Mercury during its rotation period (58.66 days) (99%)
- Also
- Mars moves during Venus day period a distance = 243 mkm (100%)
- Where
- Venus rotation period =243 mkm
- That makes the planets motions for this distance to be very specific and interesting
motions – and – that tells – the complete cycle aims to pass the distance (243
mkm) which is seen by Venus as (243 solar days = Venus rotation period)
Notice
- We used the number (8) for the cycle because we wanted to create Venus diameter
as a difference between the 2 motions, but by using of the number (8) that made
the distance to be = 240 mkm (or 243 mkm) which is related to Venus rotation
period – that means – we follow Venus in this cycle and motion –
- So we need to put in mind always that, Venus is our goal behind in this motion
investigation.
Data Analysis
(I)
- (9) – (5) = 240.19286 mkm – 239.044610 mkm = 1.148250 mkm
- 1.148250 mkm = π x 365501 km
- (But 366556 km = the outer planets diameters total)
- where (366556 km /365501 km) = (361/360)
- the difference between 366556 km – 365501 = 1055 km
- Earth diameter = 12 x 1063 km (error 0.8%)

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Data Analysis
(II)
- (10) – (9) = 2.908660 mkm
- Where
- 2.908660 mkm x 2π = 18.275 mkm
- Venus Motion distance during (6 solar days) = 3.02 mkm x 6 = 18.275 mkm
- We need to complete this discussion after the cycle (6 days) discussion because
Venus (here) connects with the cycle (6 days)
- So this data should be discussed in Point no. (3) of this paper
Notice
- Jupiter needs 5068.6 hours (= 211.2 days) to move the distance 239.03 mkm
- Where
- ((4331 days (Jupiter orbital period) x 2) /211.2 days) =41
- 41 deg = the solar plants orbital inclinations total
- And
- 97.8 deg (Uranus axial tilt) /3.1 deg (Jupiter axial tilt) = 41deg /1.3 deg
- Where
- 1.3 deg = Jupiter orbital inclination.
Notice
- Mercury (47.4 km/s) moves during (366556 seconds) a distance =17.37 mkm
Notice
- Jupiter orbital period 4331 solar days = 4225.4 Mars rotation periods (24.6 h)
- And
- (1409.47 hours/24.6 h) = 180/π
- Where
- 1407.6 hours = Mercury rotation period
- 1409.47 h – 1407.6 h = 6750 seconds (Mars diameter =6792 km) (error 0.6%)
Notice
- 2π (5.1 deg) = 2π (4.4 deg) + 4.4 deg

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- Where
- 4.4 deg = 3.1 deg (Jupiter axial tilt) + 1.3 deg (Jupiter Orbital Inclination)
- 5.1 deg = The moon Orbital Inclination
Notice
- Mars moves during (116.75 days) a distance = 243.1 mkm (data no. 10)
- Mercury moves during (58.66 days) a distance = 240.19 mkm (data no. 9)
o If these motions are done for 2 cycles, means:
o Mars moves during (116.75 days x 2) a distance = 2 x 243.1 = 486.2 mkm
o Mercury moves during (58.66 days x 2) a distance= 2 x240.19=480.38 mkm
o The difference = 486.2 mkm – 480.38 mkm = 5.8 mkm
o If the result is 5.6 mkm
o 5.6 mkm = 5.6 degrees = 5.1 + 0.5
o 5.1 deg = The moon orbital inclination
o 0.5 deg = the moon angular diameter
o 5.6 deg = the moon orbital inclination measured above the moon diameter
o That means
o The distances difference aim to create the moon orbital inclination
o The motions interaction is complex because it needs an effect of Uranus
motion and also we need to correct the number from 5.8 mkm to 5.6 mkm.
Notice
- Venus moves during 88 solar days a distance = 266.1 mkm
- If 1 mkm = 1 day
- So, 266.1 days = 6387 hours
- Neptune needs 6440 mkm to pass 125.2 mkm where this distance causes the
difference 5.1 mkm (where 5.1 mkm define the moon orbital inclination 5.1 deg)
- The data shows 2 rates of time where 1 hour of a planet motion = 24 hours of
another planet motion.

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Preface
- Uranus (6.8 km/s) moves during its day period (17.2 h) a distance = 421056 km
- Venus (35 km/s) moves during 12104 seconds a distance = 423640 km
- Pluto (4.7 km/s) moves during 90560 seconds a distance = 425632 km
- Where
- 12104 km = Venus Diameter
- 90560 days = Pluto orbital Period
- The previous data gives the base on which the (6 time units Cycle) is created – and
based on that, the provided data uses (6 Uranus days 10.3h) and (6 x 12104 s) and
(6 x 90560 s) to pass the mentioned distances and creates the defined differences
- Based on that,
(1)
Venus (35 km/s) moves during 12104 seconds (x 6) a distance = 2541840 km
Uranus moves during 6 Uranus days period (103.2 h) a distance = 2526336 km
2541840 km – 2526336 km = 15504 km (Mercury Circumference error 1%)
(2)
Pluto (4.7 km/s) moves during 90560 s x 6 a distance = 2553792 km
Venus (35 km/s) moves during 12104 seconds (x 6) a distance = 2541840 km
2553792 km – 2541840 km = 11952 km (Venus Diameter 12104 km error 1.2%)
(3)
Pluto (4.7 km/s) moves during 90560 s x 6 a distance = 2553792 km
Uranus moves during 6 Uranus days period (103.2 h) a distance = 2526336 km
And
2553792 km – 2526336 km = 27456 km (= 86400 km /π)
(4)
Jupiter (13.1 km/s) moves during (6) of Jupiter days (59.4 h) a distance = 2.8 mkm =
2π2
x 142984 km (Jupiter Diameter)

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(5)
Neptune (5.4 km/s) moves during (6) of Neptune days (96.6 h) a distance = 1.87 mkm
= Jupiter (13.1 km/s) motion distance during 142984 seconds.
Basic Questions
- The cycle of (6 units) doesn’t depend on planet day period Why?
- Because
o The planet diameter is used as a period of time, and also planet orbital
period is a period of time
o These all data consist together the planet motion required periods of time
but in categories- as we have seen in Saturn analysis – let's remember it
o Saturn day period =10.7 hours but Saturn diameter =120536 km and can be
used as 120536 seconds where 10.7 h x 3600 s x π = 120536 s
o That means, Saturn diameter in fact = Saturn day period but be seen in
another form – Saturn orbital period should be a third form for the same
period of time
o But we have no equation can express these 3 values in each planet..! that's
the difficulty because we don't know the geometrical rule based on which
the planet diameter is created (again we need to ask, how the matter is
created?)
Notice
- Pluto moves during (6 x 90560 s) a distance = 2553792 km
- Pluto moves during its day period (153.3 h) a distance =2593836 km
- The difference = 40080 km = Earth Circumference
- Please remember 40080 km = the 5 inner planets diameters total

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The Cycle Discussion
I-Data
(A)
Venus motion distance during its day period = 352.6 mkm
But
2115 mkm = 6 x 352.6 mkm (2136 mkm =680 mkm x π)
(B)
1458 days = 6 x 243 days (Venus Rotation Period)
(C)
18048 mkm (Uranus orbital Circumference) = 6 x 3030 mkm (error 1%)
(D)
30589 days x 6 = 366556 days
And 742 days x 6 = 4452 days
(E)
175.94 days = 6 x 29.32 days
II-Discussion
- Let's analyze the data as possible in following…
o Pluto motion during (6 x 90560 s) pass a distance = 2553792 km
o Pluto moves during its day period (153.3h) a distance = 2593836 km
o Uranus moves during (153.3 h) a distance = 3752784 km
But
o 2593836 km – 2553792 km = 40044 km (Earth Circumference)
o Venus moves during (6 x 12104 s) a distance = 2541840 km
Where
o 2541840 km – 2553792 = 12104 km (Venus Diameter) (error 1.2%)
o That makes Pluto in specific position, so let's analyze it in following:

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Pluto Positions In 3 Different Cycles
(1st
Cycle)
- Pluto (4.7 km/s) moves during its day period (153.3 h) a distance =2593836 km
(2nd
Cycle)
- Pluto (4.7 km/s) moves during (6 x 90560 seconds) a distance =2553792 km
(3rd
Cycle)
- Uranus (6.8 km/s) moves during (153.3 h) a distance = 3752784 km
- Let's write a word to remember each cycle in following
o (1st
Cycle) Pluto moves the distance 2593836 km which is equal earth
motion distance during its day period = the moon displacements total
during 29.53 days = Uranus motion distance during (378675 seconds)
o (2nd
Cycle) Pluto moves the distance 2553792 km during the cycle of (6
units) in which Uranus, Venus and Pluto moves equal distances, where
Uranus uses (6 of its days) and Venus uses (6 x 12104 seconds) and Pluto
uses (6 x 90560 seconds)
o (3rd
Cycle) Uranus motion during Pluto day period a distance = Jupiter
motion distance during (8 Jupiter days) = Saturn motion distance during (10
Saturn days) = Neptune motion distance during (12 Neptune days) – by this
cycle Uranus causes Pluto day to be =153.3 hours.
- In this analyze we interest for the following
o 2593836 km – 2553792 km = 40080 km = Earth Circumference
o This is very important because the 2 distances are passed by Pluto motion
during 2 different cycles periods – that makes the 2 cycles as 2 walls to
define the distance 40080 km clearly
o Also, The Earth Circumference = Mercury diameter+ Venus diameter +
Earth diameter + the moon diameter + Mars diameter

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A Question
Why does Pluto 2 motion distances difference = Earth Circumference?
- 2593836 km – 2553792 km = 40080 km = Earth Circumference
- In what period of time this difference is found?
- (153.3 hours) – (6 x 90560 seconds) = 8520 seconds
- Pluto (4.7 km/s) moves during 8520 s a distance =40044 km= Earth Circumference
- Is this period 8520 seconds so specific?
Saturn Day Period =10.7 hours
- 10.7 hours x 3600 = 38520 seconds
- That means
- 38520 seconds – 8520 seconds = 30000 seconds ( Zero Error)
- Can we use 10 Saturn days? Yes, Why?
- Because
- Uranus motion distance during (Pluto day period 153.3 h) = Jupiter motion
distance during (8 Jupiter days) = Saturn motion distance during (10 Saturn days)
= Neptune motion distance during (12 Neptune days)
- So during 10 Saturn days
- 10 x (10.7 hours) x 3600 = 10 x (38520 seconds - 8520 seconds) = 300000 s
- Why we need this value 300000 seconds? Because
Mercury Day Period =176 solar days – 5040 seconds
- 5040 minutes x 0.99 = 4990 minutes
- 4990 minutes x 60 s = 299400 seconds (approximately = 300000 seconds)
- Why do we need that?
- Because Mercury Day Period is less than 176 solar days by 5040 seconds because
of Saturn motion. (Specifically, because Saturn motion distance during its day
period less with 5040 km than its Circumference).

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Notice (1)
- Pluto moves during 8520 seconds a distance = Earth Circumference
- But
- Mercury (47.4 km/s) moves during 8520 seconds a distance = 404000 km = Earth
Moon distance at apogee radius (r =406000 km error = 0.5%)
- Please remember that
o The moon displacements total during 29.53 days = 2598693 km
o This distance should be the moon orbital circumference and where
o 2598693 km = 2π x 413600 km
o That means, the moon apogee radius have to be = 413600 km but
o The moon uses Pythagorean rule and by that could decrease this distance
413600 km to be only 406000 km
o The previous data tells us this decreasing is done depends on the period
8520 seconds by Mercury Motion.
But why Mercury motion is used here?
- Because
- Mercury (47.4 km/s) moves during 366556 seconds distance = 17.37 mkm
- And
- (366556 km /Pluto diameter 2390 km) =153.3 (where Pluto Day Period =153.3h)
- (366556 km /The moon diameter 3475 km) =105.5 And (105.5 x 2π =663 km)
- Where the Moon Rotation Period =655.7 hours. (error 1%)
- (366556 km = the outer planets diameters total)
Where
- The moon orbit inclination (5.1 deg) is created depends on (17.2 deg), and as a
result of the moon orbital inclination creation, the moon orbit radius is decreased
from 413600 km to 406000 km – this process is done by Mercury motion during
366556 seconds –
Also 366556 days = 6 x 30589 days (Uranus Orbital Period)

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Notice (2)
- Pluto moves during 8520 seconds a distance = Earth Circumference
- Pluto moves during 8520 Minutes a distance = 2.4 mkm = the moon motion
distance during a solar day
- Pluto moves during 8520 hours a distance =144 mkm = Mars displacement from
its original orbital distance (84 mkm) to its current orbital distance (227.9 mkm)
- Pluto moves during 8520 days a distance =3475 mkm = the moon diameter 3475
km x 1 mkm.
Notice (3)
- Light known velocity (0.3 mkm/s) moves during (2 x 8520 seconds) a distance =
5127 mkm (Jupiter Pluto Distance)
- This data is important because it tells there's some reason to use (2) values of this
value (8520 seconds)
- The value (8520 seconds) is the difference (Pluto day period 153.3 hours) and (a
period = 6 x 90560 seconds where 90560 days Pluto orbital period)
- The data tells there's some reason to use the double value (2 Pluto days – 12 x
90560 seconds), let's see why it should be
o During (2 Pluto days 153.3 h x 2) Pluto moves a distance = 5.187672 mkm
o During (12 x 90560 seconds) Pluto moves a distance =5.107584 mkm
o 2 Pluto days 153.3 h x 2) Pluto moves = 5.187672 mkm
o The difference = 80088 km = 4 Earth Circumferences
o Why the period (2 Pluto days) or (12 x 90560 s) is required?
o Because the moon orbital inclination =5.1 deg =5.1 mkm
o That means
o The moon orbital inclination creation needs double value of the distance by
which the moon orbital circumference is created…
Notice (4)
- 12 x 90560 seconds = 224.7 sec x 4846 = 243 sec x 4472

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Notice (5)
- Venus moves during (12104 s x 12) a distance = 5083680 km
- The difference = 23904 km
- But
- 47720 km = 2 x 23860 km
- (47720 km is the difference between the moon displacement total and the moon
orbital circumference)
- That tells we need a double value?!!
- So
- Venus moves during (12104 s x 24) a distance = 10167360 km
- The difference = 47808 km (equal approximately the distance 47720 km)
Notice (6)
- Uranus moves during its day period a distance =421056 km
- Saturn moves during its day period a distance = 373644 km
- The difference = 47412 km
- That tells
- This value 47720 km is created as a difference between Uranus and Saturn motion
during their days periods – but this is done as a general concept – the direct effect
is done by the difference of motion between Venus and Pluto motions.
- That means, there's one geometrical context by which this process is done…
Notice (7)
- Uranus moves during (24 of its days periods) (= 412.8 h) a distance = 10.105 mkm
- Pluto moves during (24 x 90560 seconds) a distance = 10.215168 mkm
- The difference = 1% (accurately) = (109824 km) = (6.8 x51118)/π (0.7%)

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Let's complete our data discussion in following…
Equation (A)
Venus motion distance during its day period = 352.6 mkm
But 2115 mkm = 6 x 352.6 mkm (2136 mkm =680 mkm x π) (1%)
- 2094 mkm = Jupiter Uranus Distance
- The Equation shows that, the (6) cycles effects on Venus distances
Equation (B)
1458 days = 6 x 243 days (Venus Rotation Period)
- Where
- 1461 days = earth cycle
- There's 3 days different and this value needs more analysis to know why this
difference is found.
Equation (C)
18048 mkm (Uranus orbital Circumference) = 6 x 3030 mkm (error 1%)
- 3030 mkm = Uranus Pluto Distance
- Equation no. (6) tells that Uranus orbital circumference depends on the distance
between Pluto and Uranus based on the Cycle (of 6 units)
Equation (D)
30589 days x 6 = 366556 days And 742 days x 6 = 4452 days
- Where
- 30589 days = Uranus Orbital Period
- 366556 km = the outer planets diameters total
- 742 seconds = (Uranus day period 17.2 h) – (2 x 30589 sec).
- 4495.1 mkm = Neptune Orbital Distance

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Equation (4)
Jupiter (13.1 km/s) moves during (6) of Jupiter days (59.4 h) a distance = 2.8 mkm =
2π2
x 142984 km (Jupiter Diameter)
Equation no (8) shows the cycle (6 units) effect on Jupiter motion
Equation (5)
Neptune (5.4 km/s) moves during (6) of Neptune days (96.6 h) a distance = 1.87 mkm
= Jupiter (13.1 km/s) motion distance during 142984 seconds.
Equation no. (9) shows that, Neptune uses the cycle as (6Neptune days) but the
distance depends on Jupiter and not on Uranus - some interaction must be found
behind this data – and the interaction between Uranus and Jupiter (through Pluto day
period) is very useful to understand this relationship.
Equation (E)
175.94 days = 6 x 29.32 days
- Where
- 175.94 days = Mercury day period
- The moon day period =29.53 days and the value 29.32 days is different by around
0.7%).
- (142984 km Jupiter diameter/4879 km Mercury diameter) = 29.32
Notice
- Jupiter moves during 2 Saturn days a distance = 1 mkm (error 1%)
- The moon moves during 2 Saturn days a distance = Mars motion distance during
Mars day period
- Mercury moves during 2 Saturn days a distance =3.65 mkm

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3-3 The Cycles Motions Interaction
I- Data
Equation No. (1)
2 x 6 x 243 days = ( 2 x 1461 days) – 6 days
Equation No. (2)
2.908660 mkm x 2π = 18.275 mkm = 3.02 mkm x 6
- Where
- 1461 days = Earth Cycle (365 +365 +365 +366 )
- 2.908660 mkm = Mars motion during (116.7 days) – Mercury motion during
(58.66 days)
II- Discussion
- The 2 cycles discussion follow Venus rotation period as a basic value (243 days
which is equivalent to 243 mkm)
- The previous 2 equations show that, Venus connects between the 2 cycles (8 days
cycle) and (6 days cycle)
- This connection is done for Venus rotation period as a targeted value
Equation No. (1)
2 x 6 x 243 days = ( 2 x 1461 days) – 6 days
- Earth Cycle for (8 years = 2 x 1461 days) depends on Venus rotation period (6
values)
- But the difference between both = 6 solar days
- Venus (35 km/s) moves during 6 solar days (6 x 86400 s) a distance = 18.2 mkm
- This value is defined as the difference between 2 motions which are
o Mars motion distance during Venus day period (116.75 days) =243.1 mkm
o And
o Mercury motion distance during its rotation period (58.66 days) =240 mkm
The geometrical mechanism behind still need more analysis – but the data shows that-
the two cycles are connected together through Venus rotation period.

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References
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJhl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

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