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International Journal of Mathematics and Statistics Invention (IJMSI)
E-ISSN: 2321 – 4767 P-ISSN: 2321 - 4759
www.ijmsi.org Volume 4 Issue 6 || August. 2016 || PP-35-38
www.ijmsi.org 35 | Page
The Fourth Largest Estrada Indices for Trees
Bingjun Li
Department of Mathematics, Hunan Institute of Humanities, Science and Technology
Loudi, Hunan, P.R. China, 417000.
ABSTRACT
Let G be a simple graph with n vertices, and λ1, · · · , λn be the eigenvalues of its adjacent
matrix. The Estrada index of G is a graph invariant, defined as EE = i
e
n
i

1
 ,, is proposed as a
measure of branching in alkanes. In this paper, we obtain two candidates which have the fourth
largest EE among trees with n vertices.
Keywords: Estrada index; trees; extremal graph
I. Introduction
Throughout the paper, G is a simple graph with vertex set V = {v1; ...; vn} and the edge set E. Let
A(G) be the adjacent matrix of G, which is a symmetric (0; 1) matrix. The spectrum of G is the
eigenvalues of its adjacency matrix, which are denoted by λ1, · · · , λn . For basic properties of
graph eigenvalues, the readers are referred to [1]. A graph-spectrum-based invariant, put forward
by Estrada [2], is defined as
EE = EE(G) = i
e
n
i

1
 .
EE is usually referred as the Estrada index. The Esteada index has been successfully related to
chemical properties of organic molecules, especially proteins[2-3]. Estrada and
Rodriguez-Velazquez[4-5] showed that EE provides a measure of the centrality of complex
(communication, social, metabolic, etc.) networks. It was also proposed as a measure of
molecular branching[6]. Within groups of isomers, EE was found to increase with the increasing
extent of branching of carbon-atom skeleton. In addition, EE characterizes the structure of
alkanes via electronic partition function. Therefore it is natural to investigate the relations
between the Estrada index and the graph-theoretic properties of G. Let d(u) denote the degree of
vertex u. A vertex of degree 1 is called a pendant vertex or a leaf. A connected graph without
any cycle is a tree. The path Pn is a tree of order n with exactly two pendant vertices. The star of
order n, denoted by Sn is a tree with n − 1 pendant vertices. Let d(u) denote the degree of vertex
u. A vertex of degree 1 is called a pendant vertex. A connected graph without any cycle is a tree.
The path Pn is a tree of order n with exactly two pendant vertices. The star of order n, denoted
by Sn, is a tree with n − 1 pendant vertices. The double star of order n, denoted by S(p, q), is a
tree with n − 2 pendant vertices. p, q are the degrees of vertices whose degrees are bigger than 1
in S(p, q) The ∆−starlike T (n1, ..., n∆) is a tree composed of the root v, and the paths P1, P2, ...,
P∆ of length n1, n2, ..., n∆ attached at v. The number of vertices of a tree T (n1, ..., n∆) equals n =
n1 + n2 + ... + n∆.
A walk in a graph G is a finite non-null sequence w = v0e1v1e2v2…vk−1ekvk, whose terms are
alternately vertices and edges, such that, for every 1 ≤ i ≤ k, the ends of ei are vi−1 and vi. We say
that w is a walk from v0 to vk, or a (v0, vk)− walk. The vertices v0 and vk are called the initial and
The fourth largest Estrada indices for trees
www.ijmsi.org 36 | Page
final vertices of w, respectively, and v1, ..., vk−1 its internal vertices. The integer k is the length of
w. The walk is closed if v0 = vk.
In a simple graph, a walk v1e1v2e2v3…vk−1ek−1vk is determined by the sequence v1v2...vk−1vk
of its vertices, hence a walk in a simple graph can be simply specified by its vertex sequence.
For any vertex u in G, we denote by Sk(G, u) the set of walks in G with length k starting
from u, and by Mk(G, u) the number of walks in G with length k starting from u. Therefore, the
set of all closed walks of length k in G, denoted by Sk(G), equals to Uv∈G Sk(G, v), and Mk(G)
=  Gv k
vGM ),( Error! Reference source not found.. The diameter of G, denoted by
Diam(G) is the length of the longest path in G. Since every tree is a bipartite graph, there is no
any self-returning walk with odd length in a tree.
For the path Pn = v1v2...vn and the star Sn with center v1, and any integer k ≥ 0, we have
Mk(Pn, vi) = Mk(Pn, vn−i+1) and Mk(Sn, vj ) = Mk(Sn, vt) for all 1 ≤ i ≤ n and 2 ≤ j, t ≤ n by
symmetry.
Some mathematical properties of the Estrada index were established. One of most
important properties is the following:
EE=∑k≥0(Mk (G))/k!
Mk(G) is called the k-th spectral moment of the graph G. Mk(G) is equal to the number of closed
walks of length k in G. Thus, if for two graphs G1 and G2, we have Mk(G1) ≥ Mk(G2) for all k
≥0, then EE(G1)≥EE(G2). Moreover, if there is at least one positive integer t such that
Mt(G1) > Mt(G2), then EE(G1) > EE(G2). The question of finding the lower and upper bounds for
EE and the corresponding extremal graphs attracted the attention of many researchers.G, J. A. de
la Penna, I. Gutman and J. Rada [9] established lower and upper bounds for EE in terms of the
number of vertices and number of edges and some inequalities between EE and the energy of G.
Deng showed that among n-vertex trees, Pn has the minimum and Sn the maximum Estrada
index, and among connected graphs of order n, the path Pn has the minimum Estrada index.
Among these, Ilic and Stevanovic[10] obtained the unique tree with minimum Estrada index
among the set of trees with given maximum degree, and determines the tree with second minima
EE. Zhang et al. [11] determined the unique tree with maximum Estrada index among the set of
trees with given matching number. Zhang et al.[11] determined the unique tree with maximum
Estrada index among the set of trees with given matching number. In [12], Li proved that,
among trees with n vertices, S(2; n − 2) and S(3; n − 3) have the second and the third largest EE,
respectively. In this paper, we obtain two candidates which have the fourth largest EE among
trees with n vertices.
II. Main results
First of all, we list and prove some lemmas, which will be used later.
Lemma 2.1[12]
Let G = S(p, q) be a double star with centers w, v and leaves ui, i = 1, 2, ..., p+
q-2, and assume that d(w) = p and d(v) = q. Then Mk(G, v) > Mk(G, ui) and Mk(G, w) >Mk(G, ui)
for all i = 1, 2, ..., p + q−2. If p ≤ q, then Mk(G, w) ≤ Mk(G, v) for every k ≥ 1, and Mk(G, w) <
Mk(G, v) for at least one integer k0 if p < q.
Lemma 2.2[10]
Let Pn = v1v2...vn. For every k ≥ 0, the following hold: Mk(Pn, v1) ≤Mk(Pn, v2)
≤ ... ≤ Mk(Pn, vError! Reference source not found.n/2) with strict inequality for sufficiently large k.
Lemma 2.3[12]
Let v be a pendant vertex of a simple graph G, and v1 is the only vertex
connecting v. We have an injection ηk from Sk(G, v) to Sk(G, v1) for every k ≥ 1, and ηk0 is not
surjective for at least one integer k0 if v1 is an internal vertex. Therefore, Mk(G, v) ≤ Mk(G, v1) for
every k ≥ 1, and Mk0 (G, v) < Mk0 (G, v1) for at least one integer k0.
Lemma 2.4[12]
Let u1, u2 be two non-isolated vertices of a simple graph H , u be a non-isolated
vertices of a simple graph G. If H1 and H2 are the graphs obtained from H by identifying u1 and
u2 to u, respectively, depicted in Figure 1. If Mk(H, u1) ≤ Mk(H, u2) for all integer k ≥ 0, and
Mk0 (H, u1) < Mk0 (H, u2) for at least one integer k0, then Mt(H1) ≤ Mt(H2) for all integer t ≥ 0,and
Mt0 (H1) < Mt0 (H2) for at least one integer t0.
The fourth largest Estrada indices for trees
www.ijmsi.org 37 | Page
For n = 5, we only have three trees: S5, P5, P5,3. Therefore, we only need consider n > 5 in
the
following.
Lemma 2.5 If G has the fourth largest Estrada index among trees with n vertices, then
Diam(G)<5.
Proof Let G be a tree with fourth maximal Estrada index. On the contrary, we assume that
Diam(T ) ≥ 5. Let T = v1v2...vk be the longest path in G, and let vk+1, ..., vd−2 are neighbours of v2
besides v1 and v3, where d is the degree of v2. By cutting v1v2, vk+1v2, ..., vd−2v2 and adding new
edges v1v3, vk+1v3, ..., vd−2v3, we get a new tree G1 of order n. G1 ≠ Sn because Diam(G1) ≥ 4.
On the other hand, we can obtain G and G1 by identifying the center u of Gd−1 to v2 and v3
of G − {v1, vk, ..., vd−2}, respectively. By lemma 2.2, Mk(G2, v2) ≤ Mk(G2, v3) for every k ≥ 1.
Therefore, Mk(G) ≤ Mk(G1) for all integer k ≥ 0, and Mk0 (G) < Mk0 (G1) for at least one integer
k0 by lemma 2.4. Thus EE(G) < EE(G2) by equation (2). We get a tree G1 with bigger EE than G,
a contradiction. Hence Diam(G) ≤ 4..
Proposition 2.1[12]
Among trees with k ≥ 6 vertices, the double star S(3, n − 3) has the third
largest Estrada index.
Theorem 2.1 If n = 6, 3-starlike tree T (2, 2, 1) has the fourth largest Estrada index; If n = 7, 4-
starlike tree T (2, 2, 1, 1) has the fourth largest Estrada index. For n ≥ 8, S(4, n − 4) or n
-3−starlike tree T (2, 2, 1, 1, ..., 1) has the fourth largest Estrada index.
Proof For n = 6, If we only have two double star trees S(2, 4) and S(3, 3). By Lemma 2.5, if G
has the fourth largest Estrada index, then Diam(G) = 4. We just need to add a pendent edge at
one of internal vertex of the path P4. By lemma 2.2 and lemma 2.4, EE(T (2, 2, 1)) > EE(T (3, 1,
1)). So, T (2, 2, 1) has the fourth largest Estrada index.
For n = 7, we only have two double star trees: S(2, 5) and S(3, 4). By Lemma 2.5, if G has
the fourth largest Estrada index, then Diam(G) = 4. We just need to add a pendent path of length
2 at v3 of the path P4 = v1v2v3v4v5 or add two pendent edges at two of internal vertex of the path
P4. If v3v6v7 is a pendant path attached at v3, we can cut the edge v6v7 and add a new edge v7v3 to
form a new tree with bigger Estrada index by Lemma 2.2 and lemma 2.4. So, T (3, 3, 3) is not
the tree with fourth largest Estrada index. In the same way, we can show that T (2, 2, 1, 1) has
the fourth largest Estrada index.
For n ≥ 8, let P = v1v2v3v4v5 be the longest path in T . If v2 or v4 has a pendent path of length
longer than 1, we can choose another path with length bigger than 5, a contradiction. In the
same way, we can prove that all pendent path at v3 have the length shorter than 2. If v3v6v7 is a
pendant path attached at v3, we can cut the edge v6v7 and add a new edge v7v3 to form a new tree
with bigger Estrada index by Lemma 2.1 and lemma 2.2. So, all pendant paths at v3, v4 and v5
are of length 1.
If d(v2) > 2 and d(v4) > 2, we cut v4w1, ..., v4wt and add new edges v3w1, ..., v3wt to form a
new tree T1 . Obviously, T1 ≠S(3, n − 3). By lemma 2.1 and lemma 2.2, EE(T1) > EE(T ), a
contradiction.
Without loss of generality, we assume that d(v4) = 4. We will compare the Estrada index of
the following three kinds of trees T2, T3 = T (2, 2, 1, ..., 1), T4 = T (3, 1, 1, ..., 1), as shown in
Figure 2.
The fourth largest Estrada indices for trees
www.ijmsi.org 38 | Page
We can obtain T2 from T5 by adding some new edges w1v3, ..., wtv3. Also We can obtain T3 from
T5 by adding some new edges w1v3, ..., wtv3. By lemma 3.2, Sk(P5, v3) ≥ Sk(P5, v2) for all k and
Sk0 (P5, v3) > Sk0 (P5, v2) for at least one integer k0. Then Sk(T5, v3) ≥ Sk(T5, v2) by lemma 3.1.
Therefore, EE(T3) > EE(T2).
By lemma 2.2, EE(T3) > EE(T4) since Mk(P5, v3) ≥ Mk(P5, v2) and Mk1 (P5, v3) ≥ Mk1 (P5,
v2)for at least one integer k1. From above discussion, T3 has the largest Estrada index among
n−vertex trees with length 4. If a graph G has diameter 3, then G is a double star. By lemma 2.1,
EE(S(2, n-2)) > EE(S(3, n − 3)) > EE(S(4, n − 4)) .For n ≥ 8, Trees with fourth largest trees
may be T3 or S(4, n − 4).
Acknowledgement
The project was supported by Hunan Provincial Natural Science Foundation of China(13JJ4103)
and The Education Department of Hunan Province Youth Project(12B067).
References
[1]. D. Cvetkovi, M. Do ob, H. Sachs, Spectra of Graphs-Theory and Application, third ed., Johann Ambrosius
Barth Verlag, Heidelberg, Leipzig, 1995.
[2]. H. Deng, A proof of a conjectures on the Estrada index, Match 62 (2009) 599-606.
[3]. H. Deng, A note on the Estrada index of trees, Match 62 (2009) 607-610.
[4]. J.A. De la Pena, I. Gutman, J. Rada, Estimating the Estrada index, Linear Algebra Appl. 427 (2007) 70-76.
[5]. E. Estrada, Characterization of the folding degree of proteins, Bioinformatics 18 (2002) 697-704.
[6]. E. Estrada, Characterization of the amino acid contribution to the folding degree of proteins, Proteins 54 (2004)
727-737.
[7]. E. Estrada, J. A. Rodriguez-Velazquez, Subgraph centrality in complex networks, Phys. Rev. E 71 (2005)
056103-1C056103-9.
[8]. E. Estrada, J. A. Rodriguez-Velazquez, Spectral measures of bipartivity in complex networks, Phys. Rev. E 72
(2005) 046105-1C046105-6.
[9]. E. Estrada, J. A. Rodriguez-Velazquez, M. Randic, Atomic branching in molecules, Int. J.Quantum Chem. 106
(2006) 823-832.
[10]. A. Ilic, D. Stevanovic, The Estrada index of chemical trees, J. Math. Chem. 47 (2010) 305-14.
[11]. J. Zhang et al., On Estrada index of trees, Linear Algebra and its Applications 434 (2011) 215-223.
[12]. B. Li, The first three largest Estrada index for trees. (to appear)

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The Fourth Largest Estrada Indices for Trees

  • 1. International Journal of Mathematics and Statistics Invention (IJMSI) E-ISSN: 2321 – 4767 P-ISSN: 2321 - 4759 www.ijmsi.org Volume 4 Issue 6 || August. 2016 || PP-35-38 www.ijmsi.org 35 | Page The Fourth Largest Estrada Indices for Trees Bingjun Li Department of Mathematics, Hunan Institute of Humanities, Science and Technology Loudi, Hunan, P.R. China, 417000. ABSTRACT Let G be a simple graph with n vertices, and λ1, · · · , λn be the eigenvalues of its adjacent matrix. The Estrada index of G is a graph invariant, defined as EE = i e n i  1  ,, is proposed as a measure of branching in alkanes. In this paper, we obtain two candidates which have the fourth largest EE among trees with n vertices. Keywords: Estrada index; trees; extremal graph I. Introduction Throughout the paper, G is a simple graph with vertex set V = {v1; ...; vn} and the edge set E. Let A(G) be the adjacent matrix of G, which is a symmetric (0; 1) matrix. The spectrum of G is the eigenvalues of its adjacency matrix, which are denoted by λ1, · · · , λn . For basic properties of graph eigenvalues, the readers are referred to [1]. A graph-spectrum-based invariant, put forward by Estrada [2], is defined as EE = EE(G) = i e n i  1  . EE is usually referred as the Estrada index. The Esteada index has been successfully related to chemical properties of organic molecules, especially proteins[2-3]. Estrada and Rodriguez-Velazquez[4-5] showed that EE provides a measure of the centrality of complex (communication, social, metabolic, etc.) networks. It was also proposed as a measure of molecular branching[6]. Within groups of isomers, EE was found to increase with the increasing extent of branching of carbon-atom skeleton. In addition, EE characterizes the structure of alkanes via electronic partition function. Therefore it is natural to investigate the relations between the Estrada index and the graph-theoretic properties of G. Let d(u) denote the degree of vertex u. A vertex of degree 1 is called a pendant vertex or a leaf. A connected graph without any cycle is a tree. The path Pn is a tree of order n with exactly two pendant vertices. The star of order n, denoted by Sn is a tree with n − 1 pendant vertices. Let d(u) denote the degree of vertex u. A vertex of degree 1 is called a pendant vertex. A connected graph without any cycle is a tree. The path Pn is a tree of order n with exactly two pendant vertices. The star of order n, denoted by Sn, is a tree with n − 1 pendant vertices. The double star of order n, denoted by S(p, q), is a tree with n − 2 pendant vertices. p, q are the degrees of vertices whose degrees are bigger than 1 in S(p, q) The ∆−starlike T (n1, ..., n∆) is a tree composed of the root v, and the paths P1, P2, ..., P∆ of length n1, n2, ..., n∆ attached at v. The number of vertices of a tree T (n1, ..., n∆) equals n = n1 + n2 + ... + n∆. A walk in a graph G is a finite non-null sequence w = v0e1v1e2v2…vk−1ekvk, whose terms are alternately vertices and edges, such that, for every 1 ≤ i ≤ k, the ends of ei are vi−1 and vi. We say that w is a walk from v0 to vk, or a (v0, vk)− walk. The vertices v0 and vk are called the initial and
  • 2. The fourth largest Estrada indices for trees www.ijmsi.org 36 | Page final vertices of w, respectively, and v1, ..., vk−1 its internal vertices. The integer k is the length of w. The walk is closed if v0 = vk. In a simple graph, a walk v1e1v2e2v3…vk−1ek−1vk is determined by the sequence v1v2...vk−1vk of its vertices, hence a walk in a simple graph can be simply specified by its vertex sequence. For any vertex u in G, we denote by Sk(G, u) the set of walks in G with length k starting from u, and by Mk(G, u) the number of walks in G with length k starting from u. Therefore, the set of all closed walks of length k in G, denoted by Sk(G), equals to Uv∈G Sk(G, v), and Mk(G) =  Gv k vGM ),( Error! Reference source not found.. The diameter of G, denoted by Diam(G) is the length of the longest path in G. Since every tree is a bipartite graph, there is no any self-returning walk with odd length in a tree. For the path Pn = v1v2...vn and the star Sn with center v1, and any integer k ≥ 0, we have Mk(Pn, vi) = Mk(Pn, vn−i+1) and Mk(Sn, vj ) = Mk(Sn, vt) for all 1 ≤ i ≤ n and 2 ≤ j, t ≤ n by symmetry. Some mathematical properties of the Estrada index were established. One of most important properties is the following: EE=∑k≥0(Mk (G))/k! Mk(G) is called the k-th spectral moment of the graph G. Mk(G) is equal to the number of closed walks of length k in G. Thus, if for two graphs G1 and G2, we have Mk(G1) ≥ Mk(G2) for all k ≥0, then EE(G1)≥EE(G2). Moreover, if there is at least one positive integer t such that Mt(G1) > Mt(G2), then EE(G1) > EE(G2). The question of finding the lower and upper bounds for EE and the corresponding extremal graphs attracted the attention of many researchers.G, J. A. de la Penna, I. Gutman and J. Rada [9] established lower and upper bounds for EE in terms of the number of vertices and number of edges and some inequalities between EE and the energy of G. Deng showed that among n-vertex trees, Pn has the minimum and Sn the maximum Estrada index, and among connected graphs of order n, the path Pn has the minimum Estrada index. Among these, Ilic and Stevanovic[10] obtained the unique tree with minimum Estrada index among the set of trees with given maximum degree, and determines the tree with second minima EE. Zhang et al. [11] determined the unique tree with maximum Estrada index among the set of trees with given matching number. Zhang et al.[11] determined the unique tree with maximum Estrada index among the set of trees with given matching number. In [12], Li proved that, among trees with n vertices, S(2; n − 2) and S(3; n − 3) have the second and the third largest EE, respectively. In this paper, we obtain two candidates which have the fourth largest EE among trees with n vertices. II. Main results First of all, we list and prove some lemmas, which will be used later. Lemma 2.1[12] Let G = S(p, q) be a double star with centers w, v and leaves ui, i = 1, 2, ..., p+ q-2, and assume that d(w) = p and d(v) = q. Then Mk(G, v) > Mk(G, ui) and Mk(G, w) >Mk(G, ui) for all i = 1, 2, ..., p + q−2. If p ≤ q, then Mk(G, w) ≤ Mk(G, v) for every k ≥ 1, and Mk(G, w) < Mk(G, v) for at least one integer k0 if p < q. Lemma 2.2[10] Let Pn = v1v2...vn. For every k ≥ 0, the following hold: Mk(Pn, v1) ≤Mk(Pn, v2) ≤ ... ≤ Mk(Pn, vError! Reference source not found.n/2) with strict inequality for sufficiently large k. Lemma 2.3[12] Let v be a pendant vertex of a simple graph G, and v1 is the only vertex connecting v. We have an injection ηk from Sk(G, v) to Sk(G, v1) for every k ≥ 1, and ηk0 is not surjective for at least one integer k0 if v1 is an internal vertex. Therefore, Mk(G, v) ≤ Mk(G, v1) for every k ≥ 1, and Mk0 (G, v) < Mk0 (G, v1) for at least one integer k0. Lemma 2.4[12] Let u1, u2 be two non-isolated vertices of a simple graph H , u be a non-isolated vertices of a simple graph G. If H1 and H2 are the graphs obtained from H by identifying u1 and u2 to u, respectively, depicted in Figure 1. If Mk(H, u1) ≤ Mk(H, u2) for all integer k ≥ 0, and Mk0 (H, u1) < Mk0 (H, u2) for at least one integer k0, then Mt(H1) ≤ Mt(H2) for all integer t ≥ 0,and Mt0 (H1) < Mt0 (H2) for at least one integer t0.
  • 3. The fourth largest Estrada indices for trees www.ijmsi.org 37 | Page For n = 5, we only have three trees: S5, P5, P5,3. Therefore, we only need consider n > 5 in the following. Lemma 2.5 If G has the fourth largest Estrada index among trees with n vertices, then Diam(G)<5. Proof Let G be a tree with fourth maximal Estrada index. On the contrary, we assume that Diam(T ) ≥ 5. Let T = v1v2...vk be the longest path in G, and let vk+1, ..., vd−2 are neighbours of v2 besides v1 and v3, where d is the degree of v2. By cutting v1v2, vk+1v2, ..., vd−2v2 and adding new edges v1v3, vk+1v3, ..., vd−2v3, we get a new tree G1 of order n. G1 ≠ Sn because Diam(G1) ≥ 4. On the other hand, we can obtain G and G1 by identifying the center u of Gd−1 to v2 and v3 of G − {v1, vk, ..., vd−2}, respectively. By lemma 2.2, Mk(G2, v2) ≤ Mk(G2, v3) for every k ≥ 1. Therefore, Mk(G) ≤ Mk(G1) for all integer k ≥ 0, and Mk0 (G) < Mk0 (G1) for at least one integer k0 by lemma 2.4. Thus EE(G) < EE(G2) by equation (2). We get a tree G1 with bigger EE than G, a contradiction. Hence Diam(G) ≤ 4.. Proposition 2.1[12] Among trees with k ≥ 6 vertices, the double star S(3, n − 3) has the third largest Estrada index. Theorem 2.1 If n = 6, 3-starlike tree T (2, 2, 1) has the fourth largest Estrada index; If n = 7, 4- starlike tree T (2, 2, 1, 1) has the fourth largest Estrada index. For n ≥ 8, S(4, n − 4) or n -3−starlike tree T (2, 2, 1, 1, ..., 1) has the fourth largest Estrada index. Proof For n = 6, If we only have two double star trees S(2, 4) and S(3, 3). By Lemma 2.5, if G has the fourth largest Estrada index, then Diam(G) = 4. We just need to add a pendent edge at one of internal vertex of the path P4. By lemma 2.2 and lemma 2.4, EE(T (2, 2, 1)) > EE(T (3, 1, 1)). So, T (2, 2, 1) has the fourth largest Estrada index. For n = 7, we only have two double star trees: S(2, 5) and S(3, 4). By Lemma 2.5, if G has the fourth largest Estrada index, then Diam(G) = 4. We just need to add a pendent path of length 2 at v3 of the path P4 = v1v2v3v4v5 or add two pendent edges at two of internal vertex of the path P4. If v3v6v7 is a pendant path attached at v3, we can cut the edge v6v7 and add a new edge v7v3 to form a new tree with bigger Estrada index by Lemma 2.2 and lemma 2.4. So, T (3, 3, 3) is not the tree with fourth largest Estrada index. In the same way, we can show that T (2, 2, 1, 1) has the fourth largest Estrada index. For n ≥ 8, let P = v1v2v3v4v5 be the longest path in T . If v2 or v4 has a pendent path of length longer than 1, we can choose another path with length bigger than 5, a contradiction. In the same way, we can prove that all pendent path at v3 have the length shorter than 2. If v3v6v7 is a pendant path attached at v3, we can cut the edge v6v7 and add a new edge v7v3 to form a new tree with bigger Estrada index by Lemma 2.1 and lemma 2.2. So, all pendant paths at v3, v4 and v5 are of length 1. If d(v2) > 2 and d(v4) > 2, we cut v4w1, ..., v4wt and add new edges v3w1, ..., v3wt to form a new tree T1 . Obviously, T1 ≠S(3, n − 3). By lemma 2.1 and lemma 2.2, EE(T1) > EE(T ), a contradiction. Without loss of generality, we assume that d(v4) = 4. We will compare the Estrada index of the following three kinds of trees T2, T3 = T (2, 2, 1, ..., 1), T4 = T (3, 1, 1, ..., 1), as shown in Figure 2.
  • 4. The fourth largest Estrada indices for trees www.ijmsi.org 38 | Page We can obtain T2 from T5 by adding some new edges w1v3, ..., wtv3. Also We can obtain T3 from T5 by adding some new edges w1v3, ..., wtv3. By lemma 3.2, Sk(P5, v3) ≥ Sk(P5, v2) for all k and Sk0 (P5, v3) > Sk0 (P5, v2) for at least one integer k0. Then Sk(T5, v3) ≥ Sk(T5, v2) by lemma 3.1. Therefore, EE(T3) > EE(T2). By lemma 2.2, EE(T3) > EE(T4) since Mk(P5, v3) ≥ Mk(P5, v2) and Mk1 (P5, v3) ≥ Mk1 (P5, v2)for at least one integer k1. From above discussion, T3 has the largest Estrada index among n−vertex trees with length 4. If a graph G has diameter 3, then G is a double star. By lemma 2.1, EE(S(2, n-2)) > EE(S(3, n − 3)) > EE(S(4, n − 4)) .For n ≥ 8, Trees with fourth largest trees may be T3 or S(4, n − 4). Acknowledgement The project was supported by Hunan Provincial Natural Science Foundation of China(13JJ4103) and The Education Department of Hunan Province Youth Project(12B067). References [1]. D. Cvetkovi, M. Do ob, H. Sachs, Spectra of Graphs-Theory and Application, third ed., Johann Ambrosius Barth Verlag, Heidelberg, Leipzig, 1995. [2]. H. Deng, A proof of a conjectures on the Estrada index, Match 62 (2009) 599-606. [3]. H. Deng, A note on the Estrada index of trees, Match 62 (2009) 607-610. [4]. J.A. De la Pena, I. Gutman, J. Rada, Estimating the Estrada index, Linear Algebra Appl. 427 (2007) 70-76. [5]. E. Estrada, Characterization of the folding degree of proteins, Bioinformatics 18 (2002) 697-704. [6]. E. Estrada, Characterization of the amino acid contribution to the folding degree of proteins, Proteins 54 (2004) 727-737. [7]. E. Estrada, J. A. Rodriguez-Velazquez, Subgraph centrality in complex networks, Phys. Rev. E 71 (2005) 056103-1C056103-9. [8]. E. Estrada, J. A. Rodriguez-Velazquez, Spectral measures of bipartivity in complex networks, Phys. Rev. E 72 (2005) 046105-1C046105-6. [9]. E. Estrada, J. A. Rodriguez-Velazquez, M. Randic, Atomic branching in molecules, Int. J.Quantum Chem. 106 (2006) 823-832. [10]. A. Ilic, D. Stevanovic, The Estrada index of chemical trees, J. Math. Chem. 47 (2010) 305-14. [11]. J. Zhang et al., On Estrada index of trees, Linear Algebra and its Applications 434 (2011) 215-223. [12]. B. Li, The first three largest Estrada index for trees. (to appear)