The correct matches are as discussed below(a) A (Glycoprotiens ar.pdf
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The correct matches are as discussed below: (a) A (Glycoprotiens are complex proteins found on the outer layer of the plasma membrane and form the structural component of surface receptors) (b) A (The outer surface proteins such as glycoproteins can be easily separated from the plasma membrane by mild treatments of salts) (c) C (The proteins/biomolecules localized on the inner side of plasma membrane are tightly bound to it and thus require harsh chemical treatments are required for their separation) (d) D (A transmembrane protein which spans the whole width of the plasma membrane is actively involved in transport of ions and materials across it) (e) B (A ganglioside is a complex biomolecular lipid found on the periphery of the cell whose branches are embedded in the membrane itself) (f) D, E (Both, the transmembrane protein and the phospholipid of plasma membrane show flip- flop action for transport of materials across it. This is owing to the dynamic physical state of the plasma membrane) Solution The correct matches are as discussed below: (a) A (Glycoprotiens are complex proteins found on the outer layer of the plasma membrane and form the structural component of surface receptors) (b) A (The outer surface proteins such as glycoproteins can be easily separated from the plasma membrane by mild treatments of salts) (c) C (The proteins/biomolecules localized on the inner side of plasma membrane are tightly bound to it and thus require harsh chemical treatments are required for their separation) (d) D (A transmembrane protein which spans the whole width of the plasma membrane is actively involved in transport of ions and materials across it) (e) B (A ganglioside is a complex biomolecular lipid found on the periphery of the cell whose branches are embedded in the membrane itself) (f) D, E (Both, the transmembrane protein and the phospholipid of plasma membrane show flip- flop action for transport of materials across it. This is owing to the dynamic physical state of the plasma membrane).
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BSC1005 Biology General Chapter 6 1 Chapter 6 Cel.docx
BSC1005 Biology General
Chapter 6
1
Chapter 6: Cell Energy, Transport and Enzymes
1) Many of the enzymes that control a deep-sea firefly squid's ability to produce light energy from chemical energy are located
A) in membranes.
B) in the nucleus.
C) within chloroplasts.
D) outside of cells.
E) within mitochondria.
2) The fluid mosaic model describes the plasma membrane as consisting of
A) a phospholipid bilayer with embedded carbohydrates.
B) two layers of phospholipids with protein sandwiched between them.
C) a protein bilayer with embedded phospholipids.
D) carbohydrates, proteins, and phospholipids that can drift in the membrane.
E) individual proteins and phospholipids that can drift in a phospholipid bilayer.
3) Membrane phospholipids
A) have hydrophobic heads that face the center of the membrane and are shielded from water.
B) have hydrophilic tails that face outward and are exposed to water.
C) often have "kinks" in their tails caused by the presence of a double bond between carbons.
D) remain fluid because they are tightly packed against one another.
E) form impermeable layers for cells.
4) The cholesterol associated with animal cell membranes
A) is attached to membrane proteins and extends into the watery environment surrounding the cell.
B) helps to stabilize the cell membrane at body temperature.
C) makes the cell membrane fluid at room temperature.
D) is an abnormality resulting from a diet high in cholesterol.
E) helps solidify the membranes when the room temperature is below freezing.
5) A major function of glycoproteins and glycolipids in the cell membrane is to
A) glue cells together to form tissues.
B) allow the cells of an embryo to sort themselves into tissues and organs.
C) attach the cell membrane to the cytoskeleton.
D) help the cell resist swelling.
E) help the cell retain its shape.
6) When physicians perform an organ transplant, they choose a donor whose tissues match those of the recipient as closely as
possible. Which of the following cell components are being matched?
A) plasma membrane phospholipids
B) plasma membrane proteins
C) cell-surface carbohydrates
D) plasma membrane cholesterols
E) cytoskeletal elements
7) Most of the functions of a cell membrane are performed by
A) glycolipids.
B) proteins.
C) phospholipids.
D) cholesterol.
E) nucleotides.
BSC1005 Biology General
Chapter 6
2
9) Relaying a message from a membrane receptor to a molecule that performs a specific function within a cell is called
A) signal transduction.
B) inhibition.
C) competition.
D) self-recognition.
E) selective permeability.
10) Plasma membranes are selectively permeable. This means that
A) anything can pass into or out of a cell as long as the membrane is intact and the cell is healthy.
B) the plasma membrane allows some substances to enter or leave a cell more easily than others.
C) glucose cannot ...
Structure and function of plasma membrane 2
The presentation consists of 72 slides,describes following heads
DEFINITION : STRUCTURE OF PLASMA MEMBRANE
COMPONENTS OF PLASMA MEMBRANE ( (BIOCHEMICAL PROPERTIES)
LIPID BILAYER
PROTEINS
CARBOHYDRATES
CHOLESTEROL
MODELS EXPLAINING STRUCTURE OF BIO MEMBRANE
FLUID MOSAIC MODEL
MOBILITY OF MEMBRANE
GLYCOCALYX : GLYCOPROTEINS AND GLYCOLIPIDS
TRANSPORT OF IONS AND MOLECULES ACROSS PLASMA MEMBRANE
FUNCTIONS OF PLASMA MEMBRANE
DIVERSITY OF CELL MEMBRANES
SITE OF ATPASE ION CARRIER CHANNELS AND PUMPS-RECEPTORS
1 An important aspect of transport by facilitated transport.pdf
1. An important aspect of transport by facilitated transporters and pumps is a. their rigidity b. their
alpha-helices c. these proteins have beta-pleated sheets d. these proteins can move in and out of
the membrane e. these proteins undergo conformational changes In the species Ferroplasma
acidophilum, which is a kind of Archaea that lives in very acidic environments, the plasma
membrane is primarily made up of a monolayer of molecules that look like this:. Use this
information for the following two questions. 2. Given the picture, how is molecular makeup of the F
. acidophilum membrane lipid similar to membrane lipids of animals? a. they both have long,
branched carbon chains ether-bonded to glycerol b. they both have cholesterol-modified lipids c.
they both have a glycerol backbone with a phospho-head group and two carbon chain covalently
attached d. individual phospholipid molecules from both have a hydrophobic region and two
hydrophilic regions e. all of the above 3. Given the picture, if you were studying F. acidophilum,
which of the following statements would you predict NOT to hold true: a. the general structure of
an intergral membrane protein in this organism are similiar to those in animals (ie, there must be a
hydrophilic region, hydrophobic alpha-helix, and another hydrophilic region) b. the modifications of
the membrane lipids compared to animal likely makes this membrane more resistant to harsh
environments (ie, acidic, hot) c. integral membrane proteins could diffuse laterally in this
organism's membane d. freeze-fracture EM studies of these cells could be used to reveal two
surfaces, one with pits and one with domes, representing embedded membrane proteins e.
peripheral membrane proteins could be associated with this kind of membrane.
Plasma membrane By KK Sahu Sir
Introduction
Definition
Chemical composition
Molecular Structure of PM
Bilayel Model
Garter and Grendel s Model
Overton e Model
Fluid Mosaic Model
. Membrane Protein
Transmembrane Protein
Exterinsic Protein
non cytosolic Protein
6. Protein complex in pm.( cell coat)
7. Function of PM
8. Referance
Recommended
BSC1005 Biology General Chapter 6 1 Chapter 6 Cel.docx
BSC1005 Biology General
Chapter 6
1
Chapter 6: Cell Energy, Transport and Enzymes
1) Many of the enzymes that control a deep-sea firefly squid's ability to produce light energy from chemical energy are located
A) in membranes.
B) in the nucleus.
C) within chloroplasts.
D) outside of cells.
E) within mitochondria.
2) The fluid mosaic model describes the plasma membrane as consisting of
A) a phospholipid bilayer with embedded carbohydrates.
B) two layers of phospholipids with protein sandwiched between them.
C) a protein bilayer with embedded phospholipids.
D) carbohydrates, proteins, and phospholipids that can drift in the membrane.
E) individual proteins and phospholipids that can drift in a phospholipid bilayer.
3) Membrane phospholipids
A) have hydrophobic heads that face the center of the membrane and are shielded from water.
B) have hydrophilic tails that face outward and are exposed to water.
C) often have "kinks" in their tails caused by the presence of a double bond between carbons.
D) remain fluid because they are tightly packed against one another.
E) form impermeable layers for cells.
4) The cholesterol associated with animal cell membranes
A) is attached to membrane proteins and extends into the watery environment surrounding the cell.
B) helps to stabilize the cell membrane at body temperature.
C) makes the cell membrane fluid at room temperature.
D) is an abnormality resulting from a diet high in cholesterol.
E) helps solidify the membranes when the room temperature is below freezing.
5) A major function of glycoproteins and glycolipids in the cell membrane is to
A) glue cells together to form tissues.
B) allow the cells of an embryo to sort themselves into tissues and organs.
C) attach the cell membrane to the cytoskeleton.
D) help the cell resist swelling.
E) help the cell retain its shape.
6) When physicians perform an organ transplant, they choose a donor whose tissues match those of the recipient as closely as
possible. Which of the following cell components are being matched?
A) plasma membrane phospholipids
B) plasma membrane proteins
C) cell-surface carbohydrates
D) plasma membrane cholesterols
E) cytoskeletal elements
7) Most of the functions of a cell membrane are performed by
A) glycolipids.
B) proteins.
C) phospholipids.
D) cholesterol.
E) nucleotides.
BSC1005 Biology General
Chapter 6
2
9) Relaying a message from a membrane receptor to a molecule that performs a specific function within a cell is called
A) signal transduction.
B) inhibition.
C) competition.
D) self-recognition.
E) selective permeability.
10) Plasma membranes are selectively permeable. This means that
A) anything can pass into or out of a cell as long as the membrane is intact and the cell is healthy.
B) the plasma membrane allows some substances to enter or leave a cell more easily than others.
C) glucose cannot ...
Structure and function of plasma membrane 2
The presentation consists of 72 slides,describes following heads
DEFINITION : STRUCTURE OF PLASMA MEMBRANE
COMPONENTS OF PLASMA MEMBRANE ( (BIOCHEMICAL PROPERTIES)
LIPID BILAYER
PROTEINS
CARBOHYDRATES
CHOLESTEROL
MODELS EXPLAINING STRUCTURE OF BIO MEMBRANE
FLUID MOSAIC MODEL
MOBILITY OF MEMBRANE
GLYCOCALYX : GLYCOPROTEINS AND GLYCOLIPIDS
TRANSPORT OF IONS AND MOLECULES ACROSS PLASMA MEMBRANE
FUNCTIONS OF PLASMA MEMBRANE
DIVERSITY OF CELL MEMBRANES
SITE OF ATPASE ION CARRIER CHANNELS AND PUMPS-RECEPTORS
1 An important aspect of transport by facilitated transport.pdf
1. An important aspect of transport by facilitated transporters and pumps is a. their rigidity b. their
alpha-helices c. these proteins have beta-pleated sheets d. these proteins can move in and out of
the membrane e. these proteins undergo conformational changes In the species Ferroplasma
acidophilum, which is a kind of Archaea that lives in very acidic environments, the plasma
membrane is primarily made up of a monolayer of molecules that look like this:. Use this
information for the following two questions. 2. Given the picture, how is molecular makeup of the F
. acidophilum membrane lipid similar to membrane lipids of animals? a. they both have long,
branched carbon chains ether-bonded to glycerol b. they both have cholesterol-modified lipids c.
they both have a glycerol backbone with a phospho-head group and two carbon chain covalently
attached d. individual phospholipid molecules from both have a hydrophobic region and two
hydrophilic regions e. all of the above 3. Given the picture, if you were studying F. acidophilum,
which of the following statements would you predict NOT to hold true: a. the general structure of
an intergral membrane protein in this organism are similiar to those in animals (ie, there must be a
hydrophilic region, hydrophobic alpha-helix, and another hydrophilic region) b. the modifications of
the membrane lipids compared to animal likely makes this membrane more resistant to harsh
environments (ie, acidic, hot) c. integral membrane proteins could diffuse laterally in this
organism's membane d. freeze-fracture EM studies of these cells could be used to reveal two
surfaces, one with pits and one with domes, representing embedded membrane proteins e.
peripheral membrane proteins could be associated with this kind of membrane.
Plasma membrane By KK Sahu Sir
Introduction
Definition
Chemical composition
Molecular Structure of PM
Bilayel Model
Garter and Grendel s Model
Overton e Model
Fluid Mosaic Model
. Membrane Protein
Transmembrane Protein
Exterinsic Protein
non cytosolic Protein
6. Protein complex in pm.( cell coat)
7. Function of PM
8. Referance
Lehninger principles of biochemistry 7th edition nelson test bank
Lehninger principles of biochemistry 7th edition nelson test bank
2) In order to act as a barrier against unregulated exchange between t.docx
2) In order to act as a barrier against unregulated exchange between the interior of the cell and the immediate external environment of that cell, the cell membrane has evolved with the following properties: Answer a) a lipid bi-layer is arranged so that it has a hydrophilic exterior and a hydrophobic interior that limits the passage of polar molecules but not lipids. b) a lipid bi-layer is arranged so that it has a hydrophobic exterior and a hydrophilic interior that limits the passage of polar molecules but not lipids. c) a lipid bi-layer is hydrophobic and is covered in hydrophilic proteins which limit the passage of polar molecules but not lipids. d) a lipid bi-layer is completely impermeable except in the regions where protein channels exist. 3) Passive diffusion follows the laws of thermodynamics. It occurs because Answer a) the movement of molecules down its electrical gradient will decrease entropy. b) molecules will naturally move up their concentration gradients as described by th thermodynamic law of entropy. c) molecules move with their electro-chemical gradients toward greater entropy. d) molecules move with their electro-chemical gradients toward reduced entropy. NAME 4) While the laws of physics govern passive diffusion, there are still obstacles that restrict the passive movement of molecules. Which of the following restricts passive diffusion? a) particle concentration, particle size and particle location. b) particle charge, particle size and particle location. c) particle size, particle concentration and particle gradient. d) particle size, particle concentration and particle charge. 5) Facilitated diffusion can Answet a) increase the rate at which particles accumulate with in a cell until the particle concentration is at equilibrium between the inside and outside of the cell. b) increase the rate at which particles accumulate with in a cell until the particle concentration is increased within the cell. c) requires an energy source to allow entry of particles into the cell. d) requires a lipid based intermediate to act as the carrier. 6) Active transport Answer. a) requires that a concentration gradient must be formed because it is using energy derived from the cleavage of ATP. b) can produce a concentration gradient but only if there is co-transported molecule. c) requires a concentration gradient and the cleavage of ATP to reverse the process. d) can create a concentration gradient with the cleavage of ATP.
.
UEC Senior 1 Biology 独中高一生物 2.2.1.1 fluid mosaic model
Malaysia Chinese Independent School Senior 1 Biology (English)
TEST BANK FOR PATHOPHYSIOLOGY 9TH EDITION by MCCANCE 2023.pdf
A Test bank is a ready-made electronic Q&A testing resource that is tailored to the contents of an individual textbook. Feedback is often provided on answers given by students, containing page references to the book.
Membrane Proteins & its types
Integral & Peripheral membrane proteins
Helical membrane proteins could be single pass /multi pass
porins which are beta sheets ion channels.
Which of the following is true about the nucleolusA)found in prok.pdf
Which of the following is true about the nucleolus?
A)found in prokaryotic cells in place of a true nucleus B)contains membran attached ribosomes
C)assembles ribosomal subunits D)all are true E)none are true
If the nucleolus was removed, this would deplete the RNA in the nucleus.
A)True B)Fals (Since most of the RNA in the nucleus is messenger RNA)
If the nucleolus was removed synthesis of new ribosomes would not occur.
A)True B)False (all the ribosomes a cell uses in its lifetime are present in the cytoplasm when
the cell first forms)
Which of the following is true about nuclear membran permeability?
A)hydrophilic(aqueous) channels are larger than those of the plasma membrane B)large proteins
can pass in and out of the nucleus in fully folded form in an aqueous solution(passage does not
require hydrophobic leaders and membrane attachment) C)movement of large molecule through
pores require assistance of transporter proteins D)the outer layer of the nuclear membrane is
continuous with the endoplasmic reticulum, therefore large molecules produced in the nucleus
can directly enter the ER lumen without needing to be transported through a membrane. E) all
are true F)none are true
Enzymes used for DNA replication are made on ribosomes located outside the nucleus.
A)True B)Flase
Solution
Answer :
Question number 1: The correct among all the statement is C (assembles ribosomal subunits)
Explanation : Nucleolus is the darkly stained, circular suborganelle which lacks any limiting
membrane and is formed during the interphase. it is site where ribosomes are manufactured..
Biological membranes, transport & Related questions
Biological membranes, transport & Related questions
test bank Lehninger Principles of Biochemistry, 8e David Nelson, Michael Cox ...
test bank for students
1. Translation program#includestdio.h#includeconio.h#incl.pdf
1. Translation program:
#include
#include
#include
#include
#include
int x1,y1,x2,y2,x3,y3,mx,my;
void draw();
void tri();
void main()
{
int gd=DETECT,gm;
int c;
initgraph(&gd,&gm,\"d:\\\\tc\\\\bgi \");
printf(\"Enter the 1st point for the triangle:\");
scanf(\"%d%d\",&x1,&y1);
printf(\"Enter the 2nd point for the triangle:\");
scanf(\"%d%d\",&x2,&y2);
printf(\"Enter the 3rd point for the triangle:\");
scanf(\"%d%d\",&x3,&y3);
cleardevice();
draw();
getch();
tri();
getch();
}
void draw()
{
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
}
void tri()
{
int x,y,a1,a2,a3,b1,b2,b3;
printf(\"Enter the Transaction coordinates\");
scanf(\"%d%d\",&x,&y);
cleardevice();
a1=x1+x;
b1=y1+y;
a2=x2+x;
b2=y2+y;
a3=x3+x;
b3=y3+y;
line(a1,b1,a2,b2);
line(a2,b2,a3,b3);
line(a3,b3,a1,b1);
}
getch();
closegraph();
2.
//rotation
#include
#include
#include
#include
#include
#include
float x1,y1,x2,y2,x,y,x3,y3,x4,y4,a;
int ch;
int main(void)
{
int gdriver = DETECT, gmode, errorcode;
clrscr();
initgraph(&gdriver, &gmode, \"c:\\\\tc\\\\bgi\");
cout<<\"enter coordinates of line1:\ \";
cin>>x1>>y1>>x2>>y2;
cout<<\"enter coordinates for relative line:\ \";
cin>>x3>>y3;
cout<<\"enter the angle of rotation:\ \";cin>>a;
cleardevice();
line(x1,y1,x2,y2);
moveto(x2,y2);
lineto(x3,y3);
moveto(x3,y3);
lineto(x1,y1);
a=a*(3.14/180);
x1=(x1*cos(a))-(y1*sin(a));
y1=(x1*sin(a))+(y1*cos(a));
x2=(x2*cos(a))-(y2*sin(a));
y2=(x2*sin(a))+(y2*cos(a));
x3=(x3*cos(a))-(y3*sin(a));
y3=(x3*sin(a))+(y3*cos(a));
cout<<\"now hit a key to see rotation:\";
getch();
moveto(x1,y1);
lineto(x2,y2);
moveto(x2,y2);
lineto(x3,y3);
moveto(x3,y3);
lineto(x1,y1);
getch();
closegraph();
}
3. Reflection
#include
#include
#include
#include
void main()
{
int gd=DETECT,gm;
int x1,y1,x2,y2,x3,y3;
char a;
clrscr();
initgraph(&gd,&gm,\"\");
printf(\"\ enter the coordinates of triangle\");
sacnf(\"%d%d%d%d%d%d\",&x1,&y1,&x2,&y2,&x3,&y3);
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
line(320,0,320,430);
line(0,240,640,240);
printf(\"\ enter the axis of reflection\");
scanf(\"%d\",&a);
if(a=\'x\'||a=\'X\')
{
x1=x1;
x2=x2;
x3=x3;
y1=y1+240;
y2=y2+240;
y3=y3+240;
}
else
if(a=\'y\'||a=\'Y\')
{
y1=y1;
y2=y2;
y3=y3;
x1+=320;
x2+=320;
x3+=320;
}
printf(\"\ triangle after reflection\");
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
getch();
closegraph();
}
Solution
1. Translation program:
#include
#include
#include
#include
#include
int x1,y1,x2,y2,x3,y3,mx,my;
void draw();
void tri();
void main()
{
int gd=DETECT,gm;
int c;
initgraph(&gd,&gm,\"d:\\\\tc\\\\bgi \");
printf(\"Enter the 1st point for the triangle:\");
scanf(\"%d%d\",&x1,&y1);
printf(\"Enter the 2nd point for the triangle:\");
scanf(\"%d%d\",&x2,&y2);
printf(\"Enter the 3rd point for the triangle:\");
scanf(\"%d%d\",&x3,&y3);
cleardevice();
draw();
getch();
tri();
getch();
}
void draw()
{
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
}
void tri()
{
int x,y,a1,a2,a3,b1,b2,b3;
printf(\"Enter the Transaction coordinates\.
1A. The acronym DBLC is used to name the Database Life Cycle.The DBL.pdf
1A. The acronym DBLC is used to name the Database Life Cycle.The DBLC traces the history
of the databse system from its starting point to its obsolescence.The DBLC is composed of six
phases:initial study,design,inplementation and loading,testing and evaluation,operation and
maintenence and evolution.
2A.Centralized conceptual database design consists of typical simple databases and conducted by
single person or small team.
Decentralized conceptual database design consists of large number of entities and complex
relations and spread across multiple sites and developed by multiple teams.
Aggregation process requires designer to create single model in which various aggregation
problems must be addressed like synonyms and homonyms,entity and subtypes.
3A.The minimal data rule specifies that all the data defined in the data model are actually
required to fit to present and expected tuture data requirements.
4A.Top-down design by identifying the differnet entity types and definition to each entity
attributes. in other words top down design starts by defining the required data sets and defines
the data elements for each of those data sets.
Bottom up design first defiines the required attributes and theb groups the attributes to form
entities.
Refer the below diagram for third answer
Solution
1A. The acronym DBLC is used to name the Database Life Cycle.The DBLC traces the history
of the databse system from its starting point to its obsolescence.The DBLC is composed of six
phases:initial study,design,inplementation and loading,testing and evaluation,operation and
maintenence and evolution.
2A.Centralized conceptual database design consists of typical simple databases and conducted by
single person or small team.
Decentralized conceptual database design consists of large number of entities and complex
relations and spread across multiple sites and developed by multiple teams.
Aggregation process requires designer to create single model in which various aggregation
problems must be addressed like synonyms and homonyms,entity and subtypes.
3A.The minimal data rule specifies that all the data defined in the data model are actually
required to fit to present and expected tuture data requirements.
4A.Top-down design by identifying the differnet entity types and definition to each entity
attributes. in other words top down design starts by defining the required data sets and defines
the data elements for each of those data sets.
Bottom up design first defiines the required attributes and theb groups the attributes to form
entities.
Refer the below diagram for third answer.
More Related Content
Similar to The correct matches are as discussed below(a) A (Glycoprotiens ar.pdf
Lehninger principles of biochemistry 7th edition nelson test bank
Lehninger principles of biochemistry 7th edition nelson test bank
2) In order to act as a barrier against unregulated exchange between t.docx
2) In order to act as a barrier against unregulated exchange between the interior of the cell and the immediate external environment of that cell, the cell membrane has evolved with the following properties: Answer a) a lipid bi-layer is arranged so that it has a hydrophilic exterior and a hydrophobic interior that limits the passage of polar molecules but not lipids. b) a lipid bi-layer is arranged so that it has a hydrophobic exterior and a hydrophilic interior that limits the passage of polar molecules but not lipids. c) a lipid bi-layer is hydrophobic and is covered in hydrophilic proteins which limit the passage of polar molecules but not lipids. d) a lipid bi-layer is completely impermeable except in the regions where protein channels exist. 3) Passive diffusion follows the laws of thermodynamics. It occurs because Answer a) the movement of molecules down its electrical gradient will decrease entropy. b) molecules will naturally move up their concentration gradients as described by th thermodynamic law of entropy. c) molecules move with their electro-chemical gradients toward greater entropy. d) molecules move with their electro-chemical gradients toward reduced entropy. NAME 4) While the laws of physics govern passive diffusion, there are still obstacles that restrict the passive movement of molecules. Which of the following restricts passive diffusion? a) particle concentration, particle size and particle location. b) particle charge, particle size and particle location. c) particle size, particle concentration and particle gradient. d) particle size, particle concentration and particle charge. 5) Facilitated diffusion can Answet a) increase the rate at which particles accumulate with in a cell until the particle concentration is at equilibrium between the inside and outside of the cell. b) increase the rate at which particles accumulate with in a cell until the particle concentration is increased within the cell. c) requires an energy source to allow entry of particles into the cell. d) requires a lipid based intermediate to act as the carrier. 6) Active transport Answer. a) requires that a concentration gradient must be formed because it is using energy derived from the cleavage of ATP. b) can produce a concentration gradient but only if there is co-transported molecule. c) requires a concentration gradient and the cleavage of ATP to reverse the process. d) can create a concentration gradient with the cleavage of ATP.
.
UEC Senior 1 Biology 独中高一生物 2.2.1.1 fluid mosaic model
Malaysia Chinese Independent School Senior 1 Biology (English)
TEST BANK FOR PATHOPHYSIOLOGY 9TH EDITION by MCCANCE 2023.pdf
A Test bank is a ready-made electronic Q&A testing resource that is tailored to the contents of an individual textbook. Feedback is often provided on answers given by students, containing page references to the book.
Membrane Proteins & its types
Integral & Peripheral membrane proteins
Helical membrane proteins could be single pass /multi pass
porins which are beta sheets ion channels.
Which of the following is true about the nucleolusA)found in prok.pdf
Which of the following is true about the nucleolus?
A)found in prokaryotic cells in place of a true nucleus B)contains membran attached ribosomes
C)assembles ribosomal subunits D)all are true E)none are true
If the nucleolus was removed, this would deplete the RNA in the nucleus.
A)True B)Fals (Since most of the RNA in the nucleus is messenger RNA)
If the nucleolus was removed synthesis of new ribosomes would not occur.
A)True B)False (all the ribosomes a cell uses in its lifetime are present in the cytoplasm when
the cell first forms)
Which of the following is true about nuclear membran permeability?
A)hydrophilic(aqueous) channels are larger than those of the plasma membrane B)large proteins
can pass in and out of the nucleus in fully folded form in an aqueous solution(passage does not
require hydrophobic leaders and membrane attachment) C)movement of large molecule through
pores require assistance of transporter proteins D)the outer layer of the nuclear membrane is
continuous with the endoplasmic reticulum, therefore large molecules produced in the nucleus
can directly enter the ER lumen without needing to be transported through a membrane. E) all
are true F)none are true
Enzymes used for DNA replication are made on ribosomes located outside the nucleus.
A)True B)Flase
Solution
Answer :
Question number 1: The correct among all the statement is C (assembles ribosomal subunits)
Explanation : Nucleolus is the darkly stained, circular suborganelle which lacks any limiting
membrane and is formed during the interphase. it is site where ribosomes are manufactured..
Biological membranes, transport & Related questions
Biological membranes, transport & Related questions
test bank Lehninger Principles of Biochemistry, 8e David Nelson, Michael Cox ...
test bank for students
Similar to The correct matches are as discussed below(a) A (Glycoprotiens ar.pdf (20)
Lehninger principles of biochemistry 7th edition nelson test bank
Lehninger principles of biochemistry 7th edition nelson test bank
2) In order to act as a barrier against unregulated exchange between t.docx
2) In order to act as a barrier against unregulated exchange between t.docx
UEC Senior 1 Biology 独中高一生物 2.2.1.1 fluid mosaic model
UEC Senior 1 Biology 独中高一生物 2.2.1.1 fluid mosaic model
multiple choice exam in both Biology and Chemistry
multiple choice exam in both Biology and Chemistry
TEST BANK FOR PATHOPHYSIOLOGY 9TH EDITION by MCCANCE 2023.pdf
TEST BANK FOR PATHOPHYSIOLOGY 9TH EDITION by MCCANCE 2023.pdf
Which of the following is true about the nucleolusA)found in prok.pdf
Which of the following is true about the nucleolusA)found in prok.pdf
Biological membranes, transport & Related questions
Biological membranes, transport & Related questions
test bank Lehninger Principles of Biochemistry, 8e David Nelson, Michael Cox ...
test bank Lehninger Principles of Biochemistry, 8e David Nelson, Michael Cox ...
More from sutharbharat59
1. Translation program#includestdio.h#includeconio.h#incl.pdf
1. Translation program:
#include
#include
#include
#include
#include
int x1,y1,x2,y2,x3,y3,mx,my;
void draw();
void tri();
void main()
{
int gd=DETECT,gm;
int c;
initgraph(&gd,&gm,\"d:\\\\tc\\\\bgi \");
printf(\"Enter the 1st point for the triangle:\");
scanf(\"%d%d\",&x1,&y1);
printf(\"Enter the 2nd point for the triangle:\");
scanf(\"%d%d\",&x2,&y2);
printf(\"Enter the 3rd point for the triangle:\");
scanf(\"%d%d\",&x3,&y3);
cleardevice();
draw();
getch();
tri();
getch();
}
void draw()
{
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
}
void tri()
{
int x,y,a1,a2,a3,b1,b2,b3;
printf(\"Enter the Transaction coordinates\");
scanf(\"%d%d\",&x,&y);
cleardevice();
a1=x1+x;
b1=y1+y;
a2=x2+x;
b2=y2+y;
a3=x3+x;
b3=y3+y;
line(a1,b1,a2,b2);
line(a2,b2,a3,b3);
line(a3,b3,a1,b1);
}
getch();
closegraph();
2.
//rotation
#include
#include
#include
#include
#include
#include
float x1,y1,x2,y2,x,y,x3,y3,x4,y4,a;
int ch;
int main(void)
{
int gdriver = DETECT, gmode, errorcode;
clrscr();
initgraph(&gdriver, &gmode, \"c:\\\\tc\\\\bgi\");
cout<<\"enter coordinates of line1:\ \";
cin>>x1>>y1>>x2>>y2;
cout<<\"enter coordinates for relative line:\ \";
cin>>x3>>y3;
cout<<\"enter the angle of rotation:\ \";cin>>a;
cleardevice();
line(x1,y1,x2,y2);
moveto(x2,y2);
lineto(x3,y3);
moveto(x3,y3);
lineto(x1,y1);
a=a*(3.14/180);
x1=(x1*cos(a))-(y1*sin(a));
y1=(x1*sin(a))+(y1*cos(a));
x2=(x2*cos(a))-(y2*sin(a));
y2=(x2*sin(a))+(y2*cos(a));
x3=(x3*cos(a))-(y3*sin(a));
y3=(x3*sin(a))+(y3*cos(a));
cout<<\"now hit a key to see rotation:\";
getch();
moveto(x1,y1);
lineto(x2,y2);
moveto(x2,y2);
lineto(x3,y3);
moveto(x3,y3);
lineto(x1,y1);
getch();
closegraph();
}
3. Reflection
#include
#include
#include
#include
void main()
{
int gd=DETECT,gm;
int x1,y1,x2,y2,x3,y3;
char a;
clrscr();
initgraph(&gd,&gm,\"\");
printf(\"\ enter the coordinates of triangle\");
sacnf(\"%d%d%d%d%d%d\",&x1,&y1,&x2,&y2,&x3,&y3);
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
line(320,0,320,430);
line(0,240,640,240);
printf(\"\ enter the axis of reflection\");
scanf(\"%d\",&a);
if(a=\'x\'||a=\'X\')
{
x1=x1;
x2=x2;
x3=x3;
y1=y1+240;
y2=y2+240;
y3=y3+240;
}
else
if(a=\'y\'||a=\'Y\')
{
y1=y1;
y2=y2;
y3=y3;
x1+=320;
x2+=320;
x3+=320;
}
printf(\"\ triangle after reflection\");
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
getch();
closegraph();
}
Solution
1. Translation program:
#include
#include
#include
#include
#include
int x1,y1,x2,y2,x3,y3,mx,my;
void draw();
void tri();
void main()
{
int gd=DETECT,gm;
int c;
initgraph(&gd,&gm,\"d:\\\\tc\\\\bgi \");
printf(\"Enter the 1st point for the triangle:\");
scanf(\"%d%d\",&x1,&y1);
printf(\"Enter the 2nd point for the triangle:\");
scanf(\"%d%d\",&x2,&y2);
printf(\"Enter the 3rd point for the triangle:\");
scanf(\"%d%d\",&x3,&y3);
cleardevice();
draw();
getch();
tri();
getch();
}
void draw()
{
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
}
void tri()
{
int x,y,a1,a2,a3,b1,b2,b3;
printf(\"Enter the Transaction coordinates\.
1A. The acronym DBLC is used to name the Database Life Cycle.The DBL.pdf
1A. The acronym DBLC is used to name the Database Life Cycle.The DBLC traces the history
of the databse system from its starting point to its obsolescence.The DBLC is composed of six
phases:initial study,design,inplementation and loading,testing and evaluation,operation and
maintenence and evolution.
2A.Centralized conceptual database design consists of typical simple databases and conducted by
single person or small team.
Decentralized conceptual database design consists of large number of entities and complex
relations and spread across multiple sites and developed by multiple teams.
Aggregation process requires designer to create single model in which various aggregation
problems must be addressed like synonyms and homonyms,entity and subtypes.
3A.The minimal data rule specifies that all the data defined in the data model are actually
required to fit to present and expected tuture data requirements.
4A.Top-down design by identifying the differnet entity types and definition to each entity
attributes. in other words top down design starts by defining the required data sets and defines
the data elements for each of those data sets.
Bottom up design first defiines the required attributes and theb groups the attributes to form
entities.
Refer the below diagram for third answer
Solution
1A. The acronym DBLC is used to name the Database Life Cycle.The DBLC traces the history
of the databse system from its starting point to its obsolescence.The DBLC is composed of six
phases:initial study,design,inplementation and loading,testing and evaluation,operation and
maintenence and evolution.
2A.Centralized conceptual database design consists of typical simple databases and conducted by
single person or small team.
Decentralized conceptual database design consists of large number of entities and complex
relations and spread across multiple sites and developed by multiple teams.
Aggregation process requires designer to create single model in which various aggregation
problems must be addressed like synonyms and homonyms,entity and subtypes.
3A.The minimal data rule specifies that all the data defined in the data model are actually
required to fit to present and expected tuture data requirements.
4A.Top-down design by identifying the differnet entity types and definition to each entity
attributes. in other words top down design starts by defining the required data sets and defines
the data elements for each of those data sets.
Bottom up design first defiines the required attributes and theb groups the attributes to form
entities.
Refer the below diagram for third answer.
In chemistry, hybridisation (or hybridization) is.pdf
In chemistry, hybridisation (or hybridization) is the concept of mixing atomic
orbitals to form new hybrid orbitals suitable for the qualitative description of atomic bonding
properties. Hybridised orbitals are very useful in the explanation of the shape of molecular
orbitals for molecules. It is an integral part of valence bond theory. Although sometimes taught
together with the valence shell electron-pair repulsion (VSEPR) theory, valence bond and
hybridization are in fact not related to the VSEPR model.[1] Contents [hide] 1 Historical
development 2 Types of hybridisation 2.1 sp3 hybrids 2.2 sp2 hybrids 2.3 sp hybrids 3
Hybridisation and molecule shape 3.1 Explanation of the shape of water 3.2 Controversy
regarding d-orbital participation 4 Hybridisation theory vs. MO theory 5 See also 6 External
links 7 References [edit]Historical development Chemist Linus Pauling first developed the
hybridisation theory in order to explain the structure of molecules such as methane (CH4).[2]
This concept was developed for such simple chemical systems, but the approach was later
applied more widely, and today it is considered an effective heuristic for rationalizing the
structures of organic compounds. For quantitative calculations of electronic structure and
molecular properties, hybridisation theory is not as practical as molecular orbital theory.
Problems with hybridisation are especially notable when the d orbitals are involved in bonding,
as in coordination chemistry and organometallic chemistry. Although hybridisation schemes in
transition metal chemistry can be used, they are not generally as accurate. Orbitals are a model
representation of the behaviour of electrons within molecules. In the case of simple
hybridisation, this approximation is based on atomic orbitals, similar to those obtained for the
hydrogen atom, the only atom for which an exact analytic solution to its Schrödinger equation is
known. In heavier atoms, like carbon, nitrogen, and oxygen, the atomic orbitals used are the 2s
and 2p orbitals, similar to excited state orbitals for hydrogen. Hybridised orbitals are assumed to
be mixtures of these atomic orbitals, superimposed on each other in various proportions. The
theory of hybridisation is most applicable under these assumptions. It gives a simple orbital
picture equivalent to Lewis structures. Hybridisation is not required to describe molecules, but
for molecules made up from carbon, nitrogen and oxygen (and to a lesser extent, sulfur and
phosphorus) the hybridisation theory/model makes the description much easier. The
hybridisation theory finds its use mainly in organic chemistry. Its explanation starts with the way
bonding is organized in methane. [edit]Types of hybridisation [edit]sp3 hybrids Hybridisation
describes the bonding atoms from an atom\'s point of view. That is, for a tetrahedrally
coordinated carbon (e.g., methane, CH4), the carbon should have 4 orbitals with the correct
symmetry to bond to the 4 hydrogen atoms. The .
RPS 19 stands for ribosomal protein S19. This proteins is synthesise.pdf
RPS 19 stands for ribosomal protein S19. This proteins is synthesised and located in the cytosol.
It is then transported to the respective destinations. RPS 19 to reach the mitochondria must cross
the 2 mitochondrial membranes the outer and inner membrane.
Solution
RPS 19 stands for ribosomal protein S19. This proteins is synthesised and located in the cytosol.
It is then transported to the respective destinations. RPS 19 to reach the mitochondria must cross
the 2 mitochondrial membranes the outer and inner membrane..
y^(iv)-4y=0taking 4y to RHS we gety^(iv) = 4yy^(iii) = integra.pdf
y^(iv)-4y=0
taking 4y to RHS we get
y^(iv) = 4y
y^(iii) = integral of(4y)
=4
y^(ii) = integral of(4)
= 0+ A note:The integral of a constant C with respect to y is Cy+ A
y^(i) = integral of(A)
= 0 +A
y =(intgral of A)
=0+A
So the general solution is y= A(constant).
Solution
y^(iv)-4y=0
taking 4y to RHS we get
y^(iv) = 4y
y^(iii) = integral of(4y)
=4
y^(ii) = integral of(4)
= 0+ A note:The integral of a constant C with respect to y is Cy+ A
y^(i) = integral of(A)
= 0 +A
y =(intgral of A)
=0+A
So the general solution is y= A(constant)..
Fe(s) + Mn2+(aq) Fe2+(aq) + Mn(s)Yes this reaction is spon.pdf
Fe(s) + Mn2+(aq) Fe2+(aq) + Mn(s)
Yes this reaction is spontaneous in the reverse direction
This is because E of the whole rection will be +ve in the reverse direction
We know that if E of the reaction is +ve, the reaction is Spontaneous
Solution
Fe(s) + Mn2+(aq) Fe2+(aq) + Mn(s)
Yes this reaction is spontaneous in the reverse direction
This is because E of the whole rection will be +ve in the reverse direction
We know that if E of the reaction is +ve, the reaction is Spontaneous.
When Na2SO3 is dissolved in water, Na+ and SO32- ions are formedN.pdf
When Na2SO3 is dissolved in water, Na+ and SO32- ions are formed:
Na2SO3 => 2 Na+ + SO32-
The SO32- ions are weak bases and ionize in water to form HSO3- and OH- ions:
SO32- + H2O <=> HSO3- + OH-
Since OH- ions are formed, the pH will be greater than 7 and the solution is basic.
Solution
When Na2SO3 is dissolved in water, Na+ and SO32- ions are formed:
Na2SO3 => 2 Na+ + SO32-
The SO32- ions are weak bases and ionize in water to form HSO3- and OH- ions:
SO32- + H2O <=> HSO3- + OH-
Since OH- ions are formed, the pH will be greater than 7 and the solution is basic..
To convert html code into Java servlet you have to write all html ta.pdf
To convert html code into Java servlet you have to write all html tag within out.println statement.
Out.println() is used to direct execute/print on browser.
# Program
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Student extends HttpServlet {
@Override
public void doGet(HttpServletRequest request, HttpServletResponse response) throws
IOException, ServletException {
response.setContentType(\"text/html;charset=UTF-8\");
PrintWriter out = response.getWriter();
try {
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"Registration Form\");
out.println(\"Name:\");
out.println(\" \");
out.println(\" Username:\");
out.println(\"\");
out.println(\"Password:\");
out.println(\" \");
out.println(\" Address:\");
out.println(\"\");
out.println(\" Country:\");
out.println(\"\");
out.println(\"please country\");
out.println(\"USA\");
out.println(\"UK\");
out.println(\" \");
out.println(\"ZIP Code:\");
out.println(\"\");
out.println(\" Email:\");
out.println(\" \");
out.println(\" Sex:\");
out.println(\"Male\");
out.println(\" Female\");
out.println(\" Language:\");
out.println(\" English\");
out.println(\" French\");
out.println(\"Germany\");
out.println(\" \");
out.println(\" About: \");
out.println(\" \");
out.println(\" \");
out.println(\" \");
out.println(\"\");
out.println(\" \");
out.println(\" \");
} finally {
out.close();
}
}
}
Solution
To convert html code into Java servlet you have to write all html tag within out.println statement.
Out.println() is used to direct execute/print on browser.
# Program
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Student extends HttpServlet {
@Override
public void doGet(HttpServletRequest request, HttpServletResponse response) throws
IOException, ServletException {
response.setContentType(\"text/html;charset=UTF-8\");
PrintWriter out = response.getWriter();
try {
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"Registration Form\");
out.println(\"Name:\");
out.println(\" \");
out.println(\" Username:\");
out.println(\"\");
out.println(\"Password:\");
out.println(\" \");
out.println(\" Address:\");
out.println(\"\");
out.println(\" Country:\");
out.println(\"\");
out.println(\"please country\");
out.println(\"USA\");
out.println(\"UK\");
out.println(\" \");
out.println(\"ZIP Code:\");
out.println(\"\");
out.println(\" Email:\");
out.println(\" \");
out.println(\" Sex:\");.
Therapsids is a group of synapsidsAdaptation1.Four limbs extent.pdf
Therapsids is a group of synapsids
Adaptation:
1.Four limbs extent vertically in contrast to crawling limbs
2..Feet were more symmetrical
3.Jaws were more complexed and powerful
4.Frontal incisors canines for tearing.
Hadrocodium
They were primitive mammals
1.Advance features
2.Large brain
3.Advance ear
Prosimian
Group of primates,
primitive mammalians characters is bicornuate uterus
Solution
Therapsids is a group of synapsids
Adaptation:
1.Four limbs extent vertically in contrast to crawling limbs
2..Feet were more symmetrical
3.Jaws were more complexed and powerful
4.Frontal incisors canines for tearing.
Hadrocodium
They were primitive mammals
1.Advance features
2.Large brain
3.Advance ear
Prosimian
Group of primates,
primitive mammalians characters is bicornuate uterus.
They trade away higher fecundity for future reproduction.Being ite.pdf
They trade away higher fecundity for future reproduction.
Being iteroparous, they can produce Offsprings throughout life, but they produce single
Offsprings trading away their fecundity so that they can reproduce throughout.
Solution
They trade away higher fecundity for future reproduction.
Being iteroparous, they can produce Offsprings throughout life, but they produce single
Offsprings trading away their fecundity so that they can reproduce throughout..
The statements that are consistent with facts known about membrane a.pdf
The statements that are consistent with facts known about membrane are
1. Some transport processes use the energy of a second transport process to move species across
membranes.
2. Active transport always employs ATP hydrolysis to provide the energy for the transporter.
Solution
The statements that are consistent with facts known about membrane are
1. Some transport processes use the energy of a second transport process to move species across
membranes.
2. Active transport always employs ATP hydrolysis to provide the energy for the transporter..
The implementation algorithm whose amortized complexity is O (1) to .pdf
The implementation algorithm whose amortized complexity is O (1) to implement queue using
two stacks is given as follows:
Algorithm for Enqueue:
Enqueue(element):
//Push the element in the stack 1.
S1.push(element)
Algorithm for Dequeue:
Dequeue():
//Check the condition that stack 2 is empty or not.
//If it is empty then execute do part otherwise go
//to the else part.
if S2.isEmpty() then
//Execute the while loop till the
//size of stack 1 is greater than 1.
while S1.size() > 1 do
//Pop the element from stack 1 and
// store it in the variable element.
element = S1.pop()
//And push the popped element
// of stack 1 to the stack 2.
S2.push(element)
//Pop the element form stack 1 and
//store it in the variable element.
element = S1.pop()
//Return the element.
return element
//The else part.
else
//Pop the element form stack 2 and
//store it in the variable element.
element = S2.pop()
//Return the element.
return element
Where, S1 and S2 represent stack 1 and stack 2 respectively.
Explanation:
1 + 1 + 1 + … + n
Thus, for the dequeue operation the amortized complexity is O (1).
Solution
The implementation algorithm whose amortized complexity is O (1) to implement queue using
two stacks is given as follows:
Algorithm for Enqueue:
Enqueue(element):
//Push the element in the stack 1.
S1.push(element)
Algorithm for Dequeue:
Dequeue():
//Check the condition that stack 2 is empty or not.
//If it is empty then execute do part otherwise go
//to the else part.
if S2.isEmpty() then
//Execute the while loop till the
//size of stack 1 is greater than 1.
while S1.size() > 1 do
//Pop the element from stack 1 and
// store it in the variable element.
element = S1.pop()
//And push the popped element
// of stack 1 to the stack 2.
S2.push(element)
//Pop the element form stack 1 and
//store it in the variable element.
element = S1.pop()
//Return the element.
return element
//The else part.
else
//Pop the element form stack 2 and
//store it in the variable element.
element = S2.pop()
//Return the element.
return element
Where, S1 and S2 represent stack 1 and stack 2 respectively.
Explanation:
1 + 1 + 1 + … + n
Thus, for the dequeue operation the amortized complexity is O (1)..
Step1 Moles of He = 504.0026Step2 Moles of Xe = 50131.29Step3 .pdf
Step1 Moles of He = 50/4.0026
Step2 Moles of Xe = 50/131.29
Step3 Find total moles
Step4 Partial pressure of He=[ Moles of He/Total moles] x750 torr
Step5 Partial pressure of Xe = 750 - partial pressure of He
Solution
Step1 Moles of He = 50/4.0026
Step2 Moles of Xe = 50/131.29
Step3 Find total moles
Step4 Partial pressure of He=[ Moles of He/Total moles] x750 torr
Step5 Partial pressure of Xe = 750 - partial pressure of He.
SKIN SENSORY ORGANThe human skin is the external covering of the .pdf
SKIN :SENSORY ORGAN
The human skin is the external covering of the body. In people, it is the biggest organ of the
integumentary framework. The skin has up to seven layers of ectodermal tissue and watches the
hidden muscles, bones, tendons and inside organs. Human skin is like that of most different
warm blooded creatures. Despite the fact that about all human skin is secured with hair follicles,
it can seem bald. There are two general sorts of skin, bristly and glabrous skin. The descriptive
word cutaneous truly signifies \"of the skin\" . Since it interfaces with the earth, skin assumes an
essential insusceptibility part in securing the body against pathogens[3] and over the top water
loss. Its different capacities are protection, temperature direction, sensation, blend of vitamin D,
and the insurance of vitamin B folates. Extremely harmed skin will attempt to recuperate by
framing scar tissue. This is frequently stained and depigmented. In people, skin pigmentation
shifts among populaces, and skin sort can go from dry to slick. Such skin assortment gives a rich
and various living space for microorganisms that number around 1000 species from 19 phyla,
exhibit on the human skin
Skin has mesodermal cells, pigmentation, for example, melanin gave by melanocytes, which
ingest a portion of the possibly risky bright radiation (UV) in daylight. It additionally contains
DNA repair compounds that switch UV harm, with the end goal that individuals without the
qualities for these chemicals endure high rates of skin malignancy. One shape prevalently
delivered by UV light, threatening melanoma, is especially intrusive, making it spread rapidly,
and can frequently be dangerous. Human skin pigmentation shifts among populaces in a striking
way. This has prompted to the order of people(s) on the premise of skin color. The skin is the
biggest organ in the human body. For the normal grown-up human, the skin has a surface zone of
between 1.5-2.0 square meters (16.1-21.5 sq ft.). The thickness of the skin shifts significantly
over all parts of the body, and amongst men and ladies and the youthful and the old. A case is the
skin on the lower arm which is all things considered 1.3 mm in the male and 1.26 mm in the
female. The normal square inch (6.5 cm²) of skin holds 650 sweat organs, 20 veins, 60,000
melanocytes, and more than 1,000 nerve endings. The normal human skin cell is around 30
micrometers in distance across, yet there are variations. A skin cell more often than not extends
from 25-40 micrometers (squared), contingent upon an assortment of variables. Skin is made out
of three essential layers: the epidermis, the dermis and the hypodermis .Epidermis, \"epi\"
originating from the Greek signifying \"over\" or \"upon\", is the peripheral layer of the skin. It
shapes the waterproof, defensive wrap over the body\'s surface which likewise serves as a
hindrance to disease and is comprised of stratified squamous epithelium with a hidden basal
lamina.
The epiderm.
a) FlaseIn terms of trasing volume it is by far the largest market.pdf
a) Flase
In terms of trasing volume it is by far the largest market in the world
b) True
As home currency weakens, one has to pay more units of home currency to buy one unit of
foreign currency, hence making import costlier
Solution
a) Flase
In terms of trasing volume it is by far the largest market in the world
b) True
As home currency weakens, one has to pay more units of home currency to buy one unit of
foreign currency, hence making import costlier.
tested on EclipseRainfall.javaimpo.pdf
//tested on Eclipse
/*************Rainfall.java*************/
import java.text.DecimalFormat;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class RainFall {
/*Data member variable*/
private double monthlyRainFall;
private double monthsRainFall[]=new double[12];
private int month=0;
private double maxRain=0.0;
private int maxrainMonth;
private double minRain=0.0;
private int minRainMonth;
/*creating map for storing month*/
Map monthMap=new HashMap();
Scanner input=new Scanner(System.in);
/*Initializing map with value while default constructor*/
public RainFall(){
monthMap.put(0, \"January\");
monthMap.put(1, \"February\");
monthMap.put(2, \"March\");
monthMap.put(3, \"April\");
monthMap.put(4, \"May\");
monthMap.put(5, \"June\");
monthMap.put(6, \"July\");
monthMap.put(7, \"August\");
monthMap.put(8, \"September\");
monthMap.put(9, \"October\");
monthMap.put(10, \"November\");
monthMap.put(11, \"December\");
}
/*Getting monthlyRainFall*/
public double getMonthlyRainFall() {
return monthlyRainFall;
}
/*Setting monthly rainfall If it is negative then it loops until positive */
public void setMonthlyRainFall(double monthlyRainFall) {
while(monthlyRainFall<0){
System.out.println(\"Please Enter positive value of monthly rainfall\");
monthlyRainFall=input.nextDouble();
}
monthsRainFall[month++]=monthlyRainFall;
}
/*Getting average month rain fall*/
public void averageMonthlyRainFall(){
double totalRainFall=0;
/*first calculate totalRain fall after that divide it total month*/
for(int i=0;imonthsRainFall[i]){
minRain=monthsRainFall[i];
minRainMonth=i;
}
}
System.out.println(\"Min Rain Month Fall: \"+monthMap.get(minRainMonth));
}
/*Main method start*/
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
/*Creating instance of rainFall class*/
RainFall rainFall=new RainFall();
/*getting rainfall for each month from user*/
for(int i=0;i<12;i++){
System.out.println(\"Please Enter rainFall for \"+(i+1)+\" Month\");
rainFall.setMonthlyRainFall(sc.nextDouble());
}
/*Average Monthly rainfall*/
rainFall.averageMonthlyRainFall();
/*Total Rain Fall in a year*/
rainFall.totalRainFall();
/*Max rainFall Month*/
rainFall.maxRainFallMonth();
/*Minimum rainFall Month*/
rainFall.minRainFallMonth();
sc.close();
}
}
/***************output************/
Please Enter rainFall for 1 Month
121
Please Enter rainFall for 2 Month
134
Please Enter rainFall for 3 Month
54
Please Enter rainFall for 4 Month
167
Please Enter rainFall for 5 Month
256
Please Enter rainFall for 6 Month
456
Please Enter rainFall for 7 Month
78
Please Enter rainFall for 8 Month
290
Please Enter rainFall for 9 Month
176
Please Enter rainFall for 10 Month
263
Please Enter rainFall for 11 Month
100
Please Enter rainFall for 12 Month
189
Average Monthly Rain Fall: 190.33
Total Rain Fall for the year: 2284
Max Rain Month Fall: June
Min Rain Month Fall: March
Thanks a lot. If you have any doubt. Please let me know
Solution
//tested on Eclipse
/********.
Ques-1Part-a Mitosis it is a somatic cell division in an organi.pdf
Ques-1:
Part-a: Mitosis: it is a somatic cell division in an organism & this division is useful to maintain
body growth
Part-b: Meiosis: it is the reproductive reduction cell division & it is useful to produce gametes for
fertilization finally to generate a mature embryo
Part-c: cytokinesis: It is defined as the process of division of cytoplasm during cell division
either in mitosis or meiosis & this is useful for carrying cell organelles
Part-d: chromosome: it is the hereditary material that carries genomic information for gene
expression & useful for inheritance of parental traits to offspring
Mitosis ---> somatic cell division & produces two identical daughter cells with equal number of
chromosomes (cytokinesis & karyokinesis).
Meiosis ----> a reduction division occurs in reproductive germ cells in which allosomes
determine sex determination finally generates half of the chromosomes in daughter cells
Part-a: Mitosis: it is a somatic cell division in an organism & this division is useful to maintain
body growth
Part-b: Meiosis: it is the reproductive reduction cell division & it is useful to produce gametes for
fertilization finally to generate a mature embryo
Part-c: cytokinesis: It is defined as the process of division of cytoplasm during cell division
either in mitosis or meiosis & this is useful for carrying cell organelles
Part-d: chromosome: it is the hereditary material that carries genomic information for gene
expression & useful for inheritance of parental traits to offspring
Cell plate is absent during animal cell division instead a complete cleavage of the cells during
division can be observed in animal cells. Cell plate formation during cell division observed only
in plants.
Haploid cells (n) are normally produced by reduction division of meiosis from diploid parent
cells (2n). This type of division occurs in germ cells of male and female species. The
chromosomes of the diploid germ cell undergo reduction in meiosis I and generate half of the
chromosomes when compared to parent diploid cell.
Meiosis division in a reproductive cell often results in four haploid cells with only single set of
chromosomes.
Meiosis-I prophase-I In this process double stranded homologous chromosomes line up each
other, and result in forming a tetrad; this is termed as Synapsis.
Terminal chaismata hold the homologous chromosomes together in metaphase I finally these are
going to align on the metaphase plate. Synapsis allows homologous chromosomes to travel to the
center by forming spindle formation through microtubules attaching to the centromeres finally to
the opposite poles of the cell. Later, crossing over takes place to exchanges paternal and maternal
genes to form tetrad where genetic variation occurs. Crossing over takes place to exchange equal
amounts of DNA generates genetic variability in prophase -I of meiosis.
Crossing over occurs in which lined up chromosomal ends exchange genetic information by
switching their places. Crossing over can un.
Proportional tax is a tax where the rate of tax is fixed. It is a pr.pdf
Proportional tax is a tax where the rate of tax is fixed. It is a predetermined fixed percentage of
one’s income if it is an income tax or it is a fixed percentage of the value of the product if it is a
sales tax. It is also called flat tax. It is regressive in application as all the people pay same
amount. Hence the people earning less pay a higher percentage of their income and the people
paying more pay lesser percentage of their income.
Progressive tax is a tax where the rate of taxation increases with the increase in income or value
of products. Usually this is done by applying brackets to the income or value of products. For
example, people with income from 0 to 20000 fall in one bracket and hence the rate of taxation is
the same for the bracket as a whole let’s say 10%. People with income from 20001 to 40000 fall
in another bracket and they have a different rate of taxation let’s say 12%.Progressive tax works
on the logic of “ability to pay”.
Creating value without producing something new is done by exchanging one good or service
with other. This is done by estimating the exchange value of the goods or services to be
exchanged. The quantified worth of one good or service expressed in terms of the worth of
another is known as the exchange value. In the business of foreign exchange, the value of each
currency is expressed in terms of value of another currency to be exchanged. This creates and
exchange value or exchange rate of one currency to another.
A private currency is a currency issued by private organizations. In many countries it is illegal to
issue private paper currencies. Such a system (of private currencies) will create a protection
against inflation. Once an available instrument or arrangement for investment of present, add-
valuing currency could be created, the public would invest in great numbers, because they would
want to relieve themselves of the fear of devaluing money.
Interest would exist in a pure economy if there is a positive time preference. Time preference is
nothing but, the relative valuation placed on a good at an earlier date compared to its valuation at
a later date. Interest is thus explained as the propensity of individuals to discount the future. A
positive time preference is a necessary and sufficient condition for the existence of Interest in
any economy.
Static view is when resources are allocated efficiently at a point in time. An example of static
efficiency would be whether a firm could produce 2million cars a year more cheaply by using
more labor and less capital. Productive and allocative efficiency are static concepts of efficiency,
they can be used to discuss whether more could be produced now if resources were allocated in a
different way. These concepts can be used for instance, to discuss whether industries dominated
by a monopoly producer might produce at lower cost if competition were introduced in the
industry.
Dynamic view is concerned with how resoures are allocated over a period of tim.
POS system is a networked invironment where a main computer linked t.pdf
POS system is a networked invironment where a main computer linked to multiple checkout
terminals.With a POS system:
The Design considerations of POS system:
Thanks
Solution
POS system is a networked invironment where a main computer linked to multiple checkout
terminals.With a POS system:
The Design considerations of POS system:
Thanks.
Q) The passage of traits from parents of offspring is called A H.pdf
Q) The passage of traits from parents of offspring is called ?
A: Heredity
Q) A breed of chicken shows co-dominance for feather color. One allele codes for black feathers,
another codes for white feathers. The feathers of heterozygous chickens of this breed will be
A: Speckled (Because in co-dominance both alleles are equally dominant and shows up as spots)
Q) Situation in which one allele of gene is not completely dominant over another allele for that
gene are called
A: Incomplete dominance
Q) In rabbits, there are four different versions of the gene for coat color. What pattern of
inheritance is this ?
A: Multiple alleles ( As we call each version of the gene as an allele)
Q) Variation in human skin color is an example of
A: Polygenic traits (there are 3 important genes coding for skin color and we get one of each of
those three genes from each of our parents)
Q) Which of the following assort independently?
A: Chromosomes (During meiosis, the pairs of homologous chromosome are divided in half to
form haploid cells. This assortment of homologous chromosomes is random and hence
independent)
Q) The plants that Gregor Mendel crossed to produce F1 generation made up of the
A: P (Also known as parents used for crossing)
Q) Due to the process of segregation, alleles separate during the production of
A: Gametes (gametes are produced at the end of meiosis and will be haploid in nature)
Q) The scientific study of heredity is called
A: Genetics
Solution
Q) The passage of traits from parents of offspring is called ?
A: Heredity
Q) A breed of chicken shows co-dominance for feather color. One allele codes for black feathers,
another codes for white feathers. The feathers of heterozygous chickens of this breed will be
A: Speckled (Because in co-dominance both alleles are equally dominant and shows up as spots)
Q) Situation in which one allele of gene is not completely dominant over another allele for that
gene are called
A: Incomplete dominance
Q) In rabbits, there are four different versions of the gene for coat color. What pattern of
inheritance is this ?
A: Multiple alleles ( As we call each version of the gene as an allele)
Q) Variation in human skin color is an example of
A: Polygenic traits (there are 3 important genes coding for skin color and we get one of each of
those three genes from each of our parents)
Q) Which of the following assort independently?
A: Chromosomes (During meiosis, the pairs of homologous chromosome are divided in half to
form haploid cells. This assortment of homologous chromosomes is random and hence
independent)
Q) The plants that Gregor Mendel crossed to produce F1 generation made up of the
A: P (Also known as parents used for crossing)
Q) Due to the process of segregation, alleles separate during the production of
A: Gametes (gametes are produced at the end of meiosis and will be haploid in nature)
Q) The scientific study of heredity is called
A: Genetics.
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