tested on EclipseRainfall.javaimpo.pdf
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//tested on Eclipse /*************Rainfall.java*************/ import java.text.DecimalFormat; import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class RainFall { /*Data member variable*/ private double monthlyRainFall; private double monthsRainFall[]=new double[12]; private int month=0; private double maxRain=0.0; private int maxrainMonth; private double minRain=0.0; private int minRainMonth; /*creating map for storing month*/ Map monthMap=new HashMap(); Scanner input=new Scanner(System.in); /*Initializing map with value while default constructor*/ public RainFall(){ monthMap.put(0, \"January\"); monthMap.put(1, \"February\"); monthMap.put(2, \"March\"); monthMap.put(3, \"April\"); monthMap.put(4, \"May\"); monthMap.put(5, \"June\"); monthMap.put(6, \"July\"); monthMap.put(7, \"August\"); monthMap.put(8, \"September\"); monthMap.put(9, \"October\"); monthMap.put(10, \"November\"); monthMap.put(11, \"December\"); } /*Getting monthlyRainFall*/ public double getMonthlyRainFall() { return monthlyRainFall; } /*Setting monthly rainfall If it is negative then it loops until positive */ public void setMonthlyRainFall(double monthlyRainFall) { while(monthlyRainFall<0){ System.out.println(\"Please Enter positive value of monthly rainfall\"); monthlyRainFall=input.nextDouble(); } monthsRainFall[month++]=monthlyRainFall; } /*Getting average month rain fall*/ public void averageMonthlyRainFall(){ double totalRainFall=0; /*first calculate totalRain fall after that divide it total month*/ for(int i=0;imonthsRainFall[i]){ minRain=monthsRainFall[i]; minRainMonth=i; } } System.out.println(\"Min Rain Month Fall: \"+monthMap.get(minRainMonth)); } /*Main method start*/ public static void main(String[] args) { Scanner sc=new Scanner(System.in); /*Creating instance of rainFall class*/ RainFall rainFall=new RainFall(); /*getting rainfall for each month from user*/ for(int i=0;i<12;i++){ System.out.println(\"Please Enter rainFall for \"+(i+1)+\" Month\"); rainFall.setMonthlyRainFall(sc.nextDouble()); } /*Average Monthly rainfall*/ rainFall.averageMonthlyRainFall(); /*Total Rain Fall in a year*/ rainFall.totalRainFall(); /*Max rainFall Month*/ rainFall.maxRainFallMonth(); /*Minimum rainFall Month*/ rainFall.minRainFallMonth(); sc.close(); } } /***************output************/ Please Enter rainFall for 1 Month 121 Please Enter rainFall for 2 Month 134 Please Enter rainFall for 3 Month 54 Please Enter rainFall for 4 Month 167 Please Enter rainFall for 5 Month 256 Please Enter rainFall for 6 Month 456 Please Enter rainFall for 7 Month 78 Please Enter rainFall for 8 Month 290 Please Enter rainFall for 9 Month 176 Please Enter rainFall for 10 Month 263 Please Enter rainFall for 11 Month 100 Please Enter rainFall for 12 Month 189 Average Monthly Rain Fall: 190.33 Total Rain Fall for the year: 2284 Max Rain Month Fall: June Min Rain Month Fall: March Thanks a lot. If you have any doubt. Please let me know Solution //tested on Eclipse /********.
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![//tested on Eclipse
/*************Rainfall.java*************/
import java.text.DecimalFormat;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class RainFall {
/*Data member variable*/
private double monthlyRainFall;
private double monthsRainFall[]=new double[12];
private int month=0;
private double maxRain=0.0;
private int maxrainMonth;
private double minRain=0.0;
private int minRainMonth;
/*creating map for storing month*/
Map monthMap=new HashMap();
Scanner input=new Scanner(System.in);
/*Initializing map with value while default constructor*/
public RainFall(){
monthMap.put(0, "January");
monthMap.put(1, "February");
monthMap.put(2, "March");
monthMap.put(3, "April");
monthMap.put(4, "May");
monthMap.put(5, "June");
monthMap.put(6, "July");
monthMap.put(7, "August");
monthMap.put(8, "September");
monthMap.put(9, "October");
monthMap.put(10, "November");
monthMap.put(11, "December");
}
/*Getting monthlyRainFall*/
public double getMonthlyRainFall() {](https://image.slidesharecdn.com/testedoneclipserainfall-230630171703-90546d89/85/tested-on-EclipseRainfall-javaimpo-pdf-1-320.jpg)
![return monthlyRainFall;
}
/*Setting monthly rainfall If it is negative then it loops until positive */
public void setMonthlyRainFall(double monthlyRainFall) {
while(monthlyRainFall<0){
System.out.println("Please Enter positive value of monthly rainfall");
monthlyRainFall=input.nextDouble();
}
monthsRainFall[month++]=monthlyRainFall;
}
/*Getting average month rain fall*/
public void averageMonthlyRainFall(){
double totalRainFall=0;
/*first calculate totalRain fall after that divide it total month*/
for(int i=0;imonthsRainFall[i]){
minRain=monthsRainFall[i];
minRainMonth=i;
}
}
System.out.println("Min Rain Month Fall: "+monthMap.get(minRainMonth));
}
/*Main method start*/
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
/*Creating instance of rainFall class*/
RainFall rainFall=new RainFall();
/*getting rainfall for each month from user*/
for(int i=0;i<12;i++){
System.out.println("Please Enter rainFall for "+(i+1)+" Month");
rainFall.setMonthlyRainFall(sc.nextDouble());
}
/*Average Monthly rainfall*/
rainFall.averageMonthlyRainFall();
/*Total Rain Fall in a year*/
rainFall.totalRainFall();](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
tested on eclipseRainFall.javai.pdf
//tested on eclipse
/******************RainFall.java***********/
import java.text.DecimalFormat;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class RainFall {
/*Data member variable*/
private double monthlyRainFall;
private double monthsRainFall[]=new double[12];
private int month=0;
private double maxRain=0.0;
private int maxrainMonth;
private double minRain=0.0;
private int minRainMonth;
/*creating map for storing month*/
Map monthMap=new HashMap();
Scanner input=new Scanner(System.in);
/*Initializing map with value while default constructor*/
public RainFall(){
monthMap.put(0, \"January\");
monthMap.put(1, \"February\");
monthMap.put(2, \"March\");
monthMap.put(3, \"April\");
monthMap.put(4, \"May\");
monthMap.put(5, \"June\");
monthMap.put(6, \"July\");
monthMap.put(7, \"August\");
monthMap.put(8, \"September\");
monthMap.put(9, \"October\");
monthMap.put(10, \"November\");
monthMap.put(11, \"December\");
}
public double getMonthlyRainFall() {
return monthlyRainFall;
}
/*Setting monthly rainfall If it is negative then it loops until positive */
public void setMonthlyRainFall(double monthlyRainFall) {
while(monthlyRainFall<0){
System.out.println(\"Please Enter positive value of monthly rainfall\");
monthlyRainFall=input.nextDouble();
}
monthsRainFall[month++]=monthlyRainFall;
}
/*Getting average month rain fall*/
public void averageMonthlyRainFall(){
double totalRainFall=0;
for(int i=0;imonthsRainFall[i]){
minRain=monthsRainFall[i];
minRainMonth=i;
}
}
System.out.println(\"Min Rain Month Fall: \"+monthMap.get(minRainMonth));
}
/*Main method start*/
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
/*Creating instance of rainFall class*/
RainFall rainFall=new RainFall();
/*getting rainfall for each month from user*/
for(int i=0;i<12;i++){
System.out.println(\"Please Enter rainFall for \"+(i+1)+\" Month\");
rainFall.setMonthlyRainFall(sc.nextDouble());
}
/*Average Monthly rainfall*/
rainFall.averageMonthlyRainFall();
/*Total Rain Fall in a year*/
rainFall.totalRainFall();
/*Max rainFall Month*/
rainFall.maxRainFallMonth();
/*Minimum rainFall Month*/
rainFall.minRainFallMonth();
sc.close();
}
}
/***********output**********/
Please Enter rainFall for 1 Month
121
Please Enter rainFall for 2 Month
134
Please Enter rainFall for 3 Month
156
Please Enter rainFall for 4 Month
178
Please Enter rainFall for 5 Month
234
Please Enter rainFall for 6 Month
245
Please Enter rainFall for 7 Month
56
Please Enter rainFall for 8 Month
456
Please Enter rainFall for 9 Month
765
Please Enter rainFall for 10 Month
122
Please Enter rainFall for 11 Month
179
Please Enter rainFall for 12 Month
110
Average Monthly Rain Fall: 229.67
Total Rain Fall for the year: 2756
Max Rain Month Fall: September
Min Rain Month Fall: July
Thanks a lot. If you have any doubt please let me know
Solution
//tested on eclipse
/******************RainFall.java***********/
import java.text.DecimalFormat;
import java.util.HashMap;
i.
import java.util.Scanner; import java.text.; public class Ave.pdf
import java.util.Scanner;
import java.text.*;
public class AverageRainfall {
public static void main(String[] args) {
int years; // Variable to hold the amount of years
final int MONTHS = 12; // Constant to hold the amount of months in a year
int totalMonths = 0; // Months accumulator variable
double monthlyRain; // Holds the amount of rain in inches for each month
double totalRainfall = 0; // Holds the total rainfall
NumberFormat df = DecimalFormat.getInstance(); // Decimal formating
df.setMaximumFractionDigits(2);
// Create Scanner object
Scanner input = new Scanner(System.in);
// Prompt user for the number of years
System.out.println(\"Enter the number of years: \");
years = input.nextInt();
System.out.println(\"Enter the rainfall amount for each month \");
// Construct for-loop for each year
for(int i=0; i < years; i++){
for(int j=1; j
Solution
import java.util.Scanner;
import java.text.*;
public class AverageRainfall {
public static void main(String[] args) {
int years; // Variable to hold the amount of years
final int MONTHS = 12; // Constant to hold the amount of months in a year
int totalMonths = 0; // Months accumulator variable
double monthlyRain; // Holds the amount of rain in inches for each month
double totalRainfall = 0; // Holds the total rainfall
NumberFormat df = DecimalFormat.getInstance(); // Decimal formating
df.setMaximumFractionDigits(2);
// Create Scanner object
Scanner input = new Scanner(System.in);
// Prompt user for the number of years
System.out.println(\"Enter the number of years: \");
years = input.nextInt();
System.out.println(\"Enter the rainfall amount for each month \");
// Construct for-loop for each year
for(int i=0; i < years; i++){
for(int j=1; j.
Don't Make Android Bad... Again
In 2008 Android app code had a lot of boilerplate, and was very error prone.
More code.. more bugs!
Now it doesn't have to be... but that is an option that each developer needs to take!
Hi Please find my code####### RainFall.java ###################.pdf
Hi Please find my code:
####### RainFall.java ###################
public class RainFall {
private double[] monthlyRainFallArr;
public RainFall(double[] rainFallArr) {
monthlyRainFallArr = new double[12]; // creating an array to store monthly rainfall
for(int i=0; i<12; i++)
monthlyRainFallArr[i] = rainFallArr[i];
}
public double getTotalRainFallForYear(){
double total = 0;
for(int i=0; i<12; i++)
total += monthlyRainFallArr[i];
return total;
}
// function to get average monthly rail fall
public double getAverageMonthlyRainFall(){
double totalYear = getTotalRainFallForYear();
return totalYear/12;
}
// function to get month number with least rail fall
public int getMonthWithLeastRainFall(){
int min_index = 0;
for(int i=1; i<12; i++){
if(monthlyRainFallArr[i] < monthlyRainFallArr[min_index]){
min_index = i;
}
}
return (min_index+1);
}
// function to get month number with most rail fall
public int getMonthWithMostRainFall(){
int max_index = 0;
for(int i=1; i<12; i++){
if(monthlyRainFallArr[i] > monthlyRainFallArr[max_index]){
max_index = i;
}
}
return (max_index+1);
}
}
############## RainFallTest.java ##################
import java.util.Scanner;
public class RainFallTest {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
double rainFallArr[] = new double[12];
System.out.println(\"Enter rain fall data for 12 month: \");
for(int i=0; i<12; i++){
System.out.print(\"Rail Fall data for \"+(i+1)+\" month: \");
rainFallArr[i] = sc.nextDouble();
}
RainFall rainfall = new RainFall(rainFallArr);
System.out.println(\"Total rain fall for year: \"+rainfall.getTotalRainFallForYear());
System.out.println(\"Average monthly rain fall: \"+rainfall.getAverageMonthlyRainFall());
System.out.println(\"Month Number with least rainfall:
\"+rainfall.getMonthWithLeastRainFall());
System.out.println(\"Month Number with most rainfall:
\"+rainfall.getMonthWithMostRainFall());
}
}
/*
Sample Output:
Enter rain fall data for 12 month:
Rail Fall data for 1 month: 45.43
Rail Fall data for 2 month: 48.76
Rail Fall data for 3 month: 46.56
Rail Fall data for 4 month: 47.23
Rail Fall data for 5 month: 44.32
Rail Fall data for 6 month: 43.23
Rail Fall data for 7 month: 58.76
Rail Fall data for 8 month: 55.65
Rail Fall data for 9 month: 50.76
Rail Fall data for 10 month: 49.12
Rail Fall data for 11 month: 37.45
Rail Fall data for 12 month: 38.00
Total rain fall for year: 565.27
Average monthly rain fall: 47.10583333333333
Month Number with least rainfall: 11
Month Number with most rainfall: 7
*/
Solution
Hi Please find my code:
####### RainFall.java ###################
public class RainFall {
private double[] monthlyRainFallArr;
public RainFall(double[] rainFallArr) {
monthlyRainFallArr = new double[12]; // creating an array to store monthly rainfall
for(int i=0; i<12; i++)
monthlyRainFallArr[i] = rainFallArr[i];
}
public double getTotalRainFallForYear(){
double total = 0;
for(int i=0; i<12; i++)
total += monthlyRainFallArr[i];
return total;
}
// function .
The java program TwelveDays that prompts user to enter l.pdf
/**
* The java program TwelveDays that prompts user to enter
* last day number then prints the verse of christmas song
* to console.
* */
//TwelveDays.java
import java.util.Scanner;
public class TwelveDays
{
public static void main(String[] args)
{
final int MAX = 12;
int lastDay = 0; //last day for the song, user will update
//create a scanner class object
Scanner scanner = new Scanner(System.in);
//Get the last day and use input validation
do
{
//prompt for lastDay value
System.out.println(\"Enter last day number [1-12]\");
lastDay=Integer.parseInt(scanner.nextLine());
}while(lastDay<1 || lastDay>12);
//set lastDay to day
int day = lastDay;
System.out.print(\"On the \");
//first switch case
switch(day)
{
case 1:
System.out.print(\"first \");
break;
case 2:
System.out.print(\"second\");
break;
case 3:
System.out.print(\"third\");
break;
case 4:
System.out.print(\"fourth\");
break;
case 5:
System.out.print(\"fifth\");
break;
case 6:
System.out.print(\"sixth\");
break;
case 7:
System.out.print(\"seventh\");
break;
case 8:
System.out.print(\"eighth\");
break;
case 9:
System.out.print(\"ninth\");
break;
case 10:
System.out.print(\"tenth\");
break;
case 11:
System.out.print(\"eleventh\");
break;
case 12:
System.out.print(\"twelfth\");
break;
}
System.out.println(\" day of Christmas, my true love sent to me:\");
//second switch case to select gift of day
switch(day)
{
case 12:
System.out.println(\"Twelve Drummers Drumming\");
case 11:
System.out.println(\"Eleven Pipers Piping\");
case 10:
System.out.println(\"Ten Lords a Leaping\");
case 9:
System.out.println(\"Nine Ladies Dancing\");
case 8:
System.out.println(\"Eight Maids a Milking\");
case 7:
System.out.println(\"Seven Swans a Swimming\");
case 6:
System.out.println(\"Six Geese a Laying\");
case 5:
System.out.println(\"Five Golden Rings\");
case 4:
System.out.println(\"Four Calling Birds\");
case 3:
System.out.println(\"Three French Hens\");
case 2:
System.out.print(\"Two Turtle Doves\");
case 1:
if(day>1){
System.out.println(\",and \");
}
System.out.println(\"A Partridge in a Pear Tree.\");
break;
}
}
}//end of the class
------------------------------------------------------------------------------------------------------
Sample output:
Enter last day number [1-12]
12
On the twelfth day of Christmas, my true love sent to me:
Twelve Drummers Drumming
Eleven Pipers Piping
Ten Lords a Leaping
Nine Ladies Dancing
Eight Maids a Milking
Seven Swans a Swimming
Six Geese a Laying
Five Golden Rings
Four Calling Birds
Three French Hens
Two Turtle Doves,and
A Partridge in a Pear Tree.
sample run2\"
Enter last day number [1-12]
11
On the eleventh day of Christmas, my true love sent to me:
Eleven Pipers Piping
Ten Lords a Leaping
Nine Ladies Dancing
Eight Maids a Milking
Seven Swans a Swimming
Six Geese a Laying
Five Golden Rings
Four Calling Birds
Three French Hens
Two Turtle Doves,and
A Partridge in a Pear Tree.
Solution
/**
* The java program TwelveDays that prompts user to enter
* last day number then.
PLEASE complete in java codes A program that pops open an .pdf
PLEASE complete in java codes
A program that pops open an interactive map.
*/
public class App extends PApplet {
/****************************************************************/
/* BEGIN - DON'T MODIFY THIS CODE */
/****************************************************************/
UnfoldingMap map; // will be a reference to the actual map
String mapTitle; // will hold the title of the map
final float SCALE_FACTOR = 0.0002f; // a factor used to scale pedestrian counts to calculate a
reasonable radius for a bubble marker on the map
final int DEFAULT_ZOOM_LEVEL = 11;
final Location DEFAULT_LOCATION = new Location(40.7286683f, -73.997895f); // a hard-coded
NYC location to start with
String[][] data; // will hold data extracted from the CSV data file
/****************************************************************/
/* END - DON'T MODIFY THIS CODE */
/****************************************************************/
/**
* This method is automatically called every time the user presses a key while viewing the map.
* The `key` variable (type char) is automatically is assigned the value of the key that was pressed.
* Complete the functions called from here, such that:
* - when the user presses the `1` key, the code calls the showMay2021MorningCounts method to
show the morning counts in May 2021, with blue bubble markers on the map.
* - when the user presses the `2` key, the code calls the showMay2021EveningCounts method to
show the evening counts in May 2021, with blue bubble markers on the map.
* - when the user presses the `3` key, the code calls the
showMay2021EveningMorningCountsDifferencemethod to show the difference between the
evening and morning counts in May 2021. If the evening count is greater, the marker should be a
green bubble, otherwise, the marker should be a red bubble.
* - when the user presses the `4` key, the code calls the showMay2021VersusMay2019Counts
method to show the difference between the average of the evening and morning counts in May
2021 and the average of the evening and morning counts in May 2019. If the counts for 2021 are
greater, the marker should be a green bubble, otherwise, the marker should be a red bubble.
* - when the user presses the `5` key, the code calls the customVisualization1 method to show
data of your choosing, visualized with marker types of your choosing.
* - when the user presses the `6` key, the code calls the customVisualization2 method to show
data of your choosing, visualized with marker types of your choosing.
*/
public void keyPressed() {
// System.out.println("Key pressed: " + key);
// complete this method
}
/**
* Adds markers to the map for the morning pedestrian counts in May 2021.
* These counts are in the second-to-last field in the CSV data file. So we look at the second-to-last
array element in our data array for these values.
*
* @param data A two-dimensional String array, containing the data returned by the
getDataFromLines method.
*/
public void showMay2021MorningCounts(String[][.
Write a program that uses nested loops to collect data and calculate .docx
Write a program that uses nested loops to collect data and calculate
Modern Android app library stack
The world of open source libraries and tools is vast for Android developers. Writing apps using solely Android SDK is impractical. Libraries can help you in many ways. They can speed up your development, save you creating boilerplate code and dealing with platform fragmentation, simplify your code and make it more readable and maintainable. In the talk I’m showing how several truly useful libraries can help a developer.
Presented at MobCon Europe 2017.
Recommended
tested on eclipseRainFall.javai.pdf
//tested on eclipse
/******************RainFall.java***********/
import java.text.DecimalFormat;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class RainFall {
/*Data member variable*/
private double monthlyRainFall;
private double monthsRainFall[]=new double[12];
private int month=0;
private double maxRain=0.0;
private int maxrainMonth;
private double minRain=0.0;
private int minRainMonth;
/*creating map for storing month*/
Map monthMap=new HashMap();
Scanner input=new Scanner(System.in);
/*Initializing map with value while default constructor*/
public RainFall(){
monthMap.put(0, \"January\");
monthMap.put(1, \"February\");
monthMap.put(2, \"March\");
monthMap.put(3, \"April\");
monthMap.put(4, \"May\");
monthMap.put(5, \"June\");
monthMap.put(6, \"July\");
monthMap.put(7, \"August\");
monthMap.put(8, \"September\");
monthMap.put(9, \"October\");
monthMap.put(10, \"November\");
monthMap.put(11, \"December\");
}
public double getMonthlyRainFall() {
return monthlyRainFall;
}
/*Setting monthly rainfall If it is negative then it loops until positive */
public void setMonthlyRainFall(double monthlyRainFall) {
while(monthlyRainFall<0){
System.out.println(\"Please Enter positive value of monthly rainfall\");
monthlyRainFall=input.nextDouble();
}
monthsRainFall[month++]=monthlyRainFall;
}
/*Getting average month rain fall*/
public void averageMonthlyRainFall(){
double totalRainFall=0;
for(int i=0;imonthsRainFall[i]){
minRain=monthsRainFall[i];
minRainMonth=i;
}
}
System.out.println(\"Min Rain Month Fall: \"+monthMap.get(minRainMonth));
}
/*Main method start*/
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
/*Creating instance of rainFall class*/
RainFall rainFall=new RainFall();
/*getting rainfall for each month from user*/
for(int i=0;i<12;i++){
System.out.println(\"Please Enter rainFall for \"+(i+1)+\" Month\");
rainFall.setMonthlyRainFall(sc.nextDouble());
}
/*Average Monthly rainfall*/
rainFall.averageMonthlyRainFall();
/*Total Rain Fall in a year*/
rainFall.totalRainFall();
/*Max rainFall Month*/
rainFall.maxRainFallMonth();
/*Minimum rainFall Month*/
rainFall.minRainFallMonth();
sc.close();
}
}
/***********output**********/
Please Enter rainFall for 1 Month
121
Please Enter rainFall for 2 Month
134
Please Enter rainFall for 3 Month
156
Please Enter rainFall for 4 Month
178
Please Enter rainFall for 5 Month
234
Please Enter rainFall for 6 Month
245
Please Enter rainFall for 7 Month
56
Please Enter rainFall for 8 Month
456
Please Enter rainFall for 9 Month
765
Please Enter rainFall for 10 Month
122
Please Enter rainFall for 11 Month
179
Please Enter rainFall for 12 Month
110
Average Monthly Rain Fall: 229.67
Total Rain Fall for the year: 2756
Max Rain Month Fall: September
Min Rain Month Fall: July
Thanks a lot. If you have any doubt please let me know
Solution
//tested on eclipse
/******************RainFall.java***********/
import java.text.DecimalFormat;
import java.util.HashMap;
i.
import java.util.Scanner; import java.text.; public class Ave.pdf
import java.util.Scanner;
import java.text.*;
public class AverageRainfall {
public static void main(String[] args) {
int years; // Variable to hold the amount of years
final int MONTHS = 12; // Constant to hold the amount of months in a year
int totalMonths = 0; // Months accumulator variable
double monthlyRain; // Holds the amount of rain in inches for each month
double totalRainfall = 0; // Holds the total rainfall
NumberFormat df = DecimalFormat.getInstance(); // Decimal formating
df.setMaximumFractionDigits(2);
// Create Scanner object
Scanner input = new Scanner(System.in);
// Prompt user for the number of years
System.out.println(\"Enter the number of years: \");
years = input.nextInt();
System.out.println(\"Enter the rainfall amount for each month \");
// Construct for-loop for each year
for(int i=0; i < years; i++){
for(int j=1; j
Solution
import java.util.Scanner;
import java.text.*;
public class AverageRainfall {
public static void main(String[] args) {
int years; // Variable to hold the amount of years
final int MONTHS = 12; // Constant to hold the amount of months in a year
int totalMonths = 0; // Months accumulator variable
double monthlyRain; // Holds the amount of rain in inches for each month
double totalRainfall = 0; // Holds the total rainfall
NumberFormat df = DecimalFormat.getInstance(); // Decimal formating
df.setMaximumFractionDigits(2);
// Create Scanner object
Scanner input = new Scanner(System.in);
// Prompt user for the number of years
System.out.println(\"Enter the number of years: \");
years = input.nextInt();
System.out.println(\"Enter the rainfall amount for each month \");
// Construct for-loop for each year
for(int i=0; i < years; i++){
for(int j=1; j.
Don't Make Android Bad... Again
In 2008 Android app code had a lot of boilerplate, and was very error prone.
More code.. more bugs!
Now it doesn't have to be... but that is an option that each developer needs to take!
Hi Please find my code####### RainFall.java ###################.pdf
Hi Please find my code:
####### RainFall.java ###################
public class RainFall {
private double[] monthlyRainFallArr;
public RainFall(double[] rainFallArr) {
monthlyRainFallArr = new double[12]; // creating an array to store monthly rainfall
for(int i=0; i<12; i++)
monthlyRainFallArr[i] = rainFallArr[i];
}
public double getTotalRainFallForYear(){
double total = 0;
for(int i=0; i<12; i++)
total += monthlyRainFallArr[i];
return total;
}
// function to get average monthly rail fall
public double getAverageMonthlyRainFall(){
double totalYear = getTotalRainFallForYear();
return totalYear/12;
}
// function to get month number with least rail fall
public int getMonthWithLeastRainFall(){
int min_index = 0;
for(int i=1; i<12; i++){
if(monthlyRainFallArr[i] < monthlyRainFallArr[min_index]){
min_index = i;
}
}
return (min_index+1);
}
// function to get month number with most rail fall
public int getMonthWithMostRainFall(){
int max_index = 0;
for(int i=1; i<12; i++){
if(monthlyRainFallArr[i] > monthlyRainFallArr[max_index]){
max_index = i;
}
}
return (max_index+1);
}
}
############## RainFallTest.java ##################
import java.util.Scanner;
public class RainFallTest {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
double rainFallArr[] = new double[12];
System.out.println(\"Enter rain fall data for 12 month: \");
for(int i=0; i<12; i++){
System.out.print(\"Rail Fall data for \"+(i+1)+\" month: \");
rainFallArr[i] = sc.nextDouble();
}
RainFall rainfall = new RainFall(rainFallArr);
System.out.println(\"Total rain fall for year: \"+rainfall.getTotalRainFallForYear());
System.out.println(\"Average monthly rain fall: \"+rainfall.getAverageMonthlyRainFall());
System.out.println(\"Month Number with least rainfall:
\"+rainfall.getMonthWithLeastRainFall());
System.out.println(\"Month Number with most rainfall:
\"+rainfall.getMonthWithMostRainFall());
}
}
/*
Sample Output:
Enter rain fall data for 12 month:
Rail Fall data for 1 month: 45.43
Rail Fall data for 2 month: 48.76
Rail Fall data for 3 month: 46.56
Rail Fall data for 4 month: 47.23
Rail Fall data for 5 month: 44.32
Rail Fall data for 6 month: 43.23
Rail Fall data for 7 month: 58.76
Rail Fall data for 8 month: 55.65
Rail Fall data for 9 month: 50.76
Rail Fall data for 10 month: 49.12
Rail Fall data for 11 month: 37.45
Rail Fall data for 12 month: 38.00
Total rain fall for year: 565.27
Average monthly rain fall: 47.10583333333333
Month Number with least rainfall: 11
Month Number with most rainfall: 7
*/
Solution
Hi Please find my code:
####### RainFall.java ###################
public class RainFall {
private double[] monthlyRainFallArr;
public RainFall(double[] rainFallArr) {
monthlyRainFallArr = new double[12]; // creating an array to store monthly rainfall
for(int i=0; i<12; i++)
monthlyRainFallArr[i] = rainFallArr[i];
}
public double getTotalRainFallForYear(){
double total = 0;
for(int i=0; i<12; i++)
total += monthlyRainFallArr[i];
return total;
}
// function .
The java program TwelveDays that prompts user to enter l.pdf
/**
* The java program TwelveDays that prompts user to enter
* last day number then prints the verse of christmas song
* to console.
* */
//TwelveDays.java
import java.util.Scanner;
public class TwelveDays
{
public static void main(String[] args)
{
final int MAX = 12;
int lastDay = 0; //last day for the song, user will update
//create a scanner class object
Scanner scanner = new Scanner(System.in);
//Get the last day and use input validation
do
{
//prompt for lastDay value
System.out.println(\"Enter last day number [1-12]\");
lastDay=Integer.parseInt(scanner.nextLine());
}while(lastDay<1 || lastDay>12);
//set lastDay to day
int day = lastDay;
System.out.print(\"On the \");
//first switch case
switch(day)
{
case 1:
System.out.print(\"first \");
break;
case 2:
System.out.print(\"second\");
break;
case 3:
System.out.print(\"third\");
break;
case 4:
System.out.print(\"fourth\");
break;
case 5:
System.out.print(\"fifth\");
break;
case 6:
System.out.print(\"sixth\");
break;
case 7:
System.out.print(\"seventh\");
break;
case 8:
System.out.print(\"eighth\");
break;
case 9:
System.out.print(\"ninth\");
break;
case 10:
System.out.print(\"tenth\");
break;
case 11:
System.out.print(\"eleventh\");
break;
case 12:
System.out.print(\"twelfth\");
break;
}
System.out.println(\" day of Christmas, my true love sent to me:\");
//second switch case to select gift of day
switch(day)
{
case 12:
System.out.println(\"Twelve Drummers Drumming\");
case 11:
System.out.println(\"Eleven Pipers Piping\");
case 10:
System.out.println(\"Ten Lords a Leaping\");
case 9:
System.out.println(\"Nine Ladies Dancing\");
case 8:
System.out.println(\"Eight Maids a Milking\");
case 7:
System.out.println(\"Seven Swans a Swimming\");
case 6:
System.out.println(\"Six Geese a Laying\");
case 5:
System.out.println(\"Five Golden Rings\");
case 4:
System.out.println(\"Four Calling Birds\");
case 3:
System.out.println(\"Three French Hens\");
case 2:
System.out.print(\"Two Turtle Doves\");
case 1:
if(day>1){
System.out.println(\",and \");
}
System.out.println(\"A Partridge in a Pear Tree.\");
break;
}
}
}//end of the class
------------------------------------------------------------------------------------------------------
Sample output:
Enter last day number [1-12]
12
On the twelfth day of Christmas, my true love sent to me:
Twelve Drummers Drumming
Eleven Pipers Piping
Ten Lords a Leaping
Nine Ladies Dancing
Eight Maids a Milking
Seven Swans a Swimming
Six Geese a Laying
Five Golden Rings
Four Calling Birds
Three French Hens
Two Turtle Doves,and
A Partridge in a Pear Tree.
sample run2\"
Enter last day number [1-12]
11
On the eleventh day of Christmas, my true love sent to me:
Eleven Pipers Piping
Ten Lords a Leaping
Nine Ladies Dancing
Eight Maids a Milking
Seven Swans a Swimming
Six Geese a Laying
Five Golden Rings
Four Calling Birds
Three French Hens
Two Turtle Doves,and
A Partridge in a Pear Tree.
Solution
/**
* The java program TwelveDays that prompts user to enter
* last day number then.
PLEASE complete in java codes A program that pops open an .pdf
PLEASE complete in java codes
A program that pops open an interactive map.
*/
public class App extends PApplet {
/****************************************************************/
/* BEGIN - DON'T MODIFY THIS CODE */
/****************************************************************/
UnfoldingMap map; // will be a reference to the actual map
String mapTitle; // will hold the title of the map
final float SCALE_FACTOR = 0.0002f; // a factor used to scale pedestrian counts to calculate a
reasonable radius for a bubble marker on the map
final int DEFAULT_ZOOM_LEVEL = 11;
final Location DEFAULT_LOCATION = new Location(40.7286683f, -73.997895f); // a hard-coded
NYC location to start with
String[][] data; // will hold data extracted from the CSV data file
/****************************************************************/
/* END - DON'T MODIFY THIS CODE */
/****************************************************************/
/**
* This method is automatically called every time the user presses a key while viewing the map.
* The `key` variable (type char) is automatically is assigned the value of the key that was pressed.
* Complete the functions called from here, such that:
* - when the user presses the `1` key, the code calls the showMay2021MorningCounts method to
show the morning counts in May 2021, with blue bubble markers on the map.
* - when the user presses the `2` key, the code calls the showMay2021EveningCounts method to
show the evening counts in May 2021, with blue bubble markers on the map.
* - when the user presses the `3` key, the code calls the
showMay2021EveningMorningCountsDifferencemethod to show the difference between the
evening and morning counts in May 2021. If the evening count is greater, the marker should be a
green bubble, otherwise, the marker should be a red bubble.
* - when the user presses the `4` key, the code calls the showMay2021VersusMay2019Counts
method to show the difference between the average of the evening and morning counts in May
2021 and the average of the evening and morning counts in May 2019. If the counts for 2021 are
greater, the marker should be a green bubble, otherwise, the marker should be a red bubble.
* - when the user presses the `5` key, the code calls the customVisualization1 method to show
data of your choosing, visualized with marker types of your choosing.
* - when the user presses the `6` key, the code calls the customVisualization2 method to show
data of your choosing, visualized with marker types of your choosing.
*/
public void keyPressed() {
// System.out.println("Key pressed: " + key);
// complete this method
}
/**
* Adds markers to the map for the morning pedestrian counts in May 2021.
* These counts are in the second-to-last field in the CSV data file. So we look at the second-to-last
array element in our data array for these values.
*
* @param data A two-dimensional String array, containing the data returned by the
getDataFromLines method.
*/
public void showMay2021MorningCounts(String[][.
Write a program that uses nested loops to collect data and calculate .docx
Write a program that uses nested loops to collect data and calculate
Modern Android app library stack
The world of open source libraries and tools is vast for Android developers. Writing apps using solely Android SDK is impractical. Libraries can help you in many ways. They can speed up your development, save you creating boilerplate code and dealing with platform fragmentation, simplify your code and make it more readable and maintainable. In the talk I’m showing how several truly useful libraries can help a developer.
Presented at MobCon Europe 2017.
1. Translation program#includestdio.h#includeconio.h#incl.pdf
1. Translation program:
#include
#include
#include
#include
#include
int x1,y1,x2,y2,x3,y3,mx,my;
void draw();
void tri();
void main()
{
int gd=DETECT,gm;
int c;
initgraph(&gd,&gm,\"d:\\\\tc\\\\bgi \");
printf(\"Enter the 1st point for the triangle:\");
scanf(\"%d%d\",&x1,&y1);
printf(\"Enter the 2nd point for the triangle:\");
scanf(\"%d%d\",&x2,&y2);
printf(\"Enter the 3rd point for the triangle:\");
scanf(\"%d%d\",&x3,&y3);
cleardevice();
draw();
getch();
tri();
getch();
}
void draw()
{
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
}
void tri()
{
int x,y,a1,a2,a3,b1,b2,b3;
printf(\"Enter the Transaction coordinates\");
scanf(\"%d%d\",&x,&y);
cleardevice();
a1=x1+x;
b1=y1+y;
a2=x2+x;
b2=y2+y;
a3=x3+x;
b3=y3+y;
line(a1,b1,a2,b2);
line(a2,b2,a3,b3);
line(a3,b3,a1,b1);
}
getch();
closegraph();
2.
//rotation
#include
#include
#include
#include
#include
#include
float x1,y1,x2,y2,x,y,x3,y3,x4,y4,a;
int ch;
int main(void)
{
int gdriver = DETECT, gmode, errorcode;
clrscr();
initgraph(&gdriver, &gmode, \"c:\\\\tc\\\\bgi\");
cout<<\"enter coordinates of line1:\ \";
cin>>x1>>y1>>x2>>y2;
cout<<\"enter coordinates for relative line:\ \";
cin>>x3>>y3;
cout<<\"enter the angle of rotation:\ \";cin>>a;
cleardevice();
line(x1,y1,x2,y2);
moveto(x2,y2);
lineto(x3,y3);
moveto(x3,y3);
lineto(x1,y1);
a=a*(3.14/180);
x1=(x1*cos(a))-(y1*sin(a));
y1=(x1*sin(a))+(y1*cos(a));
x2=(x2*cos(a))-(y2*sin(a));
y2=(x2*sin(a))+(y2*cos(a));
x3=(x3*cos(a))-(y3*sin(a));
y3=(x3*sin(a))+(y3*cos(a));
cout<<\"now hit a key to see rotation:\";
getch();
moveto(x1,y1);
lineto(x2,y2);
moveto(x2,y2);
lineto(x3,y3);
moveto(x3,y3);
lineto(x1,y1);
getch();
closegraph();
}
3. Reflection
#include
#include
#include
#include
void main()
{
int gd=DETECT,gm;
int x1,y1,x2,y2,x3,y3;
char a;
clrscr();
initgraph(&gd,&gm,\"\");
printf(\"\ enter the coordinates of triangle\");
sacnf(\"%d%d%d%d%d%d\",&x1,&y1,&x2,&y2,&x3,&y3);
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
line(320,0,320,430);
line(0,240,640,240);
printf(\"\ enter the axis of reflection\");
scanf(\"%d\",&a);
if(a=\'x\'||a=\'X\')
{
x1=x1;
x2=x2;
x3=x3;
y1=y1+240;
y2=y2+240;
y3=y3+240;
}
else
if(a=\'y\'||a=\'Y\')
{
y1=y1;
y2=y2;
y3=y3;
x1+=320;
x2+=320;
x3+=320;
}
printf(\"\ triangle after reflection\");
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
getch();
closegraph();
}
Solution
1. Translation program:
#include
#include
#include
#include
#include
int x1,y1,x2,y2,x3,y3,mx,my;
void draw();
void tri();
void main()
{
int gd=DETECT,gm;
int c;
initgraph(&gd,&gm,\"d:\\\\tc\\\\bgi \");
printf(\"Enter the 1st point for the triangle:\");
scanf(\"%d%d\",&x1,&y1);
printf(\"Enter the 2nd point for the triangle:\");
scanf(\"%d%d\",&x2,&y2);
printf(\"Enter the 3rd point for the triangle:\");
scanf(\"%d%d\",&x3,&y3);
cleardevice();
draw();
getch();
tri();
getch();
}
void draw()
{
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
}
void tri()
{
int x,y,a1,a2,a3,b1,b2,b3;
printf(\"Enter the Transaction coordinates\.
1A. The acronym DBLC is used to name the Database Life Cycle.The DBL.pdf
1A. The acronym DBLC is used to name the Database Life Cycle.The DBLC traces the history
of the databse system from its starting point to its obsolescence.The DBLC is composed of six
phases:initial study,design,inplementation and loading,testing and evaluation,operation and
maintenence and evolution.
2A.Centralized conceptual database design consists of typical simple databases and conducted by
single person or small team.
Decentralized conceptual database design consists of large number of entities and complex
relations and spread across multiple sites and developed by multiple teams.
Aggregation process requires designer to create single model in which various aggregation
problems must be addressed like synonyms and homonyms,entity and subtypes.
3A.The minimal data rule specifies that all the data defined in the data model are actually
required to fit to present and expected tuture data requirements.
4A.Top-down design by identifying the differnet entity types and definition to each entity
attributes. in other words top down design starts by defining the required data sets and defines
the data elements for each of those data sets.
Bottom up design first defiines the required attributes and theb groups the attributes to form
entities.
Refer the below diagram for third answer
Solution
1A. The acronym DBLC is used to name the Database Life Cycle.The DBLC traces the history
of the databse system from its starting point to its obsolescence.The DBLC is composed of six
phases:initial study,design,inplementation and loading,testing and evaluation,operation and
maintenence and evolution.
2A.Centralized conceptual database design consists of typical simple databases and conducted by
single person or small team.
Decentralized conceptual database design consists of large number of entities and complex
relations and spread across multiple sites and developed by multiple teams.
Aggregation process requires designer to create single model in which various aggregation
problems must be addressed like synonyms and homonyms,entity and subtypes.
3A.The minimal data rule specifies that all the data defined in the data model are actually
required to fit to present and expected tuture data requirements.
4A.Top-down design by identifying the differnet entity types and definition to each entity
attributes. in other words top down design starts by defining the required data sets and defines
the data elements for each of those data sets.
Bottom up design first defiines the required attributes and theb groups the attributes to form
entities.
Refer the below diagram for third answer.
In chemistry, hybridisation (or hybridization) is.pdf
In chemistry, hybridisation (or hybridization) is the concept of mixing atomic
orbitals to form new hybrid orbitals suitable for the qualitative description of atomic bonding
properties. Hybridised orbitals are very useful in the explanation of the shape of molecular
orbitals for molecules. It is an integral part of valence bond theory. Although sometimes taught
together with the valence shell electron-pair repulsion (VSEPR) theory, valence bond and
hybridization are in fact not related to the VSEPR model.[1] Contents [hide] 1 Historical
development 2 Types of hybridisation 2.1 sp3 hybrids 2.2 sp2 hybrids 2.3 sp hybrids 3
Hybridisation and molecule shape 3.1 Explanation of the shape of water 3.2 Controversy
regarding d-orbital participation 4 Hybridisation theory vs. MO theory 5 See also 6 External
links 7 References [edit]Historical development Chemist Linus Pauling first developed the
hybridisation theory in order to explain the structure of molecules such as methane (CH4).[2]
This concept was developed for such simple chemical systems, but the approach was later
applied more widely, and today it is considered an effective heuristic for rationalizing the
structures of organic compounds. For quantitative calculations of electronic structure and
molecular properties, hybridisation theory is not as practical as molecular orbital theory.
Problems with hybridisation are especially notable when the d orbitals are involved in bonding,
as in coordination chemistry and organometallic chemistry. Although hybridisation schemes in
transition metal chemistry can be used, they are not generally as accurate. Orbitals are a model
representation of the behaviour of electrons within molecules. In the case of simple
hybridisation, this approximation is based on atomic orbitals, similar to those obtained for the
hydrogen atom, the only atom for which an exact analytic solution to its Schrödinger equation is
known. In heavier atoms, like carbon, nitrogen, and oxygen, the atomic orbitals used are the 2s
and 2p orbitals, similar to excited state orbitals for hydrogen. Hybridised orbitals are assumed to
be mixtures of these atomic orbitals, superimposed on each other in various proportions. The
theory of hybridisation is most applicable under these assumptions. It gives a simple orbital
picture equivalent to Lewis structures. Hybridisation is not required to describe molecules, but
for molecules made up from carbon, nitrogen and oxygen (and to a lesser extent, sulfur and
phosphorus) the hybridisation theory/model makes the description much easier. The
hybridisation theory finds its use mainly in organic chemistry. Its explanation starts with the way
bonding is organized in methane. [edit]Types of hybridisation [edit]sp3 hybrids Hybridisation
describes the bonding atoms from an atom\'s point of view. That is, for a tetrahedrally
coordinated carbon (e.g., methane, CH4), the carbon should have 4 orbitals with the correct
symmetry to bond to the 4 hydrogen atoms. The .
RPS 19 stands for ribosomal protein S19. This proteins is synthesise.pdf
RPS 19 stands for ribosomal protein S19. This proteins is synthesised and located in the cytosol.
It is then transported to the respective destinations. RPS 19 to reach the mitochondria must cross
the 2 mitochondrial membranes the outer and inner membrane.
Solution
RPS 19 stands for ribosomal protein S19. This proteins is synthesised and located in the cytosol.
It is then transported to the respective destinations. RPS 19 to reach the mitochondria must cross
the 2 mitochondrial membranes the outer and inner membrane..
y^(iv)-4y=0taking 4y to RHS we gety^(iv) = 4yy^(iii) = integra.pdf
y^(iv)-4y=0
taking 4y to RHS we get
y^(iv) = 4y
y^(iii) = integral of(4y)
=4
y^(ii) = integral of(4)
= 0+ A note:The integral of a constant C with respect to y is Cy+ A
y^(i) = integral of(A)
= 0 +A
y =(intgral of A)
=0+A
So the general solution is y= A(constant).
Solution
y^(iv)-4y=0
taking 4y to RHS we get
y^(iv) = 4y
y^(iii) = integral of(4y)
=4
y^(ii) = integral of(4)
= 0+ A note:The integral of a constant C with respect to y is Cy+ A
y^(i) = integral of(A)
= 0 +A
y =(intgral of A)
=0+A
So the general solution is y= A(constant)..
Fe(s) + Mn2+(aq) Fe2+(aq) + Mn(s)Yes this reaction is spon.pdf
Fe(s) + Mn2+(aq) Fe2+(aq) + Mn(s)
Yes this reaction is spontaneous in the reverse direction
This is because E of the whole rection will be +ve in the reverse direction
We know that if E of the reaction is +ve, the reaction is Spontaneous
Solution
Fe(s) + Mn2+(aq) Fe2+(aq) + Mn(s)
Yes this reaction is spontaneous in the reverse direction
This is because E of the whole rection will be +ve in the reverse direction
We know that if E of the reaction is +ve, the reaction is Spontaneous.
When Na2SO3 is dissolved in water, Na+ and SO32- ions are formedN.pdf
When Na2SO3 is dissolved in water, Na+ and SO32- ions are formed:
Na2SO3 => 2 Na+ + SO32-
The SO32- ions are weak bases and ionize in water to form HSO3- and OH- ions:
SO32- + H2O <=> HSO3- + OH-
Since OH- ions are formed, the pH will be greater than 7 and the solution is basic.
Solution
When Na2SO3 is dissolved in water, Na+ and SO32- ions are formed:
Na2SO3 => 2 Na+ + SO32-
The SO32- ions are weak bases and ionize in water to form HSO3- and OH- ions:
SO32- + H2O <=> HSO3- + OH-
Since OH- ions are formed, the pH will be greater than 7 and the solution is basic..
To convert html code into Java servlet you have to write all html ta.pdf
To convert html code into Java servlet you have to write all html tag within out.println statement.
Out.println() is used to direct execute/print on browser.
# Program
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Student extends HttpServlet {
@Override
public void doGet(HttpServletRequest request, HttpServletResponse response) throws
IOException, ServletException {
response.setContentType(\"text/html;charset=UTF-8\");
PrintWriter out = response.getWriter();
try {
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"Registration Form\");
out.println(\"Name:\");
out.println(\" \");
out.println(\" Username:\");
out.println(\"\");
out.println(\"Password:\");
out.println(\" \");
out.println(\" Address:\");
out.println(\"\");
out.println(\" Country:\");
out.println(\"\");
out.println(\"please country\");
out.println(\"USA\");
out.println(\"UK\");
out.println(\" \");
out.println(\"ZIP Code:\");
out.println(\"\");
out.println(\" Email:\");
out.println(\" \");
out.println(\" Sex:\");
out.println(\"Male\");
out.println(\" Female\");
out.println(\" Language:\");
out.println(\" English\");
out.println(\" French\");
out.println(\"Germany\");
out.println(\" \");
out.println(\" About: \");
out.println(\" \");
out.println(\" \");
out.println(\" \");
out.println(\"\");
out.println(\" \");
out.println(\" \");
} finally {
out.close();
}
}
}
Solution
To convert html code into Java servlet you have to write all html tag within out.println statement.
Out.println() is used to direct execute/print on browser.
# Program
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Student extends HttpServlet {
@Override
public void doGet(HttpServletRequest request, HttpServletResponse response) throws
IOException, ServletException {
response.setContentType(\"text/html;charset=UTF-8\");
PrintWriter out = response.getWriter();
try {
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"Registration Form\");
out.println(\"Name:\");
out.println(\" \");
out.println(\" Username:\");
out.println(\"\");
out.println(\"Password:\");
out.println(\" \");
out.println(\" Address:\");
out.println(\"\");
out.println(\" Country:\");
out.println(\"\");
out.println(\"please country\");
out.println(\"USA\");
out.println(\"UK\");
out.println(\" \");
out.println(\"ZIP Code:\");
out.println(\"\");
out.println(\" Email:\");
out.println(\" \");
out.println(\" Sex:\");.
Therapsids is a group of synapsidsAdaptation1.Four limbs extent.pdf
Therapsids is a group of synapsids
Adaptation:
1.Four limbs extent vertically in contrast to crawling limbs
2..Feet were more symmetrical
3.Jaws were more complexed and powerful
4.Frontal incisors canines for tearing.
Hadrocodium
They were primitive mammals
1.Advance features
2.Large brain
3.Advance ear
Prosimian
Group of primates,
primitive mammalians characters is bicornuate uterus
Solution
Therapsids is a group of synapsids
Adaptation:
1.Four limbs extent vertically in contrast to crawling limbs
2..Feet were more symmetrical
3.Jaws were more complexed and powerful
4.Frontal incisors canines for tearing.
Hadrocodium
They were primitive mammals
1.Advance features
2.Large brain
3.Advance ear
Prosimian
Group of primates,
primitive mammalians characters is bicornuate uterus.
They trade away higher fecundity for future reproduction.Being ite.pdf
They trade away higher fecundity for future reproduction.
Being iteroparous, they can produce Offsprings throughout life, but they produce single
Offsprings trading away their fecundity so that they can reproduce throughout.
Solution
They trade away higher fecundity for future reproduction.
Being iteroparous, they can produce Offsprings throughout life, but they produce single
Offsprings trading away their fecundity so that they can reproduce throughout..
The statements that are consistent with facts known about membrane a.pdf
The statements that are consistent with facts known about membrane are
1. Some transport processes use the energy of a second transport process to move species across
membranes.
2. Active transport always employs ATP hydrolysis to provide the energy for the transporter.
Solution
The statements that are consistent with facts known about membrane are
1. Some transport processes use the energy of a second transport process to move species across
membranes.
2. Active transport always employs ATP hydrolysis to provide the energy for the transporter..
The implementation algorithm whose amortized complexity is O (1) to .pdf
The implementation algorithm whose amortized complexity is O (1) to implement queue using
two stacks is given as follows:
Algorithm for Enqueue:
Enqueue(element):
//Push the element in the stack 1.
S1.push(element)
Algorithm for Dequeue:
Dequeue():
//Check the condition that stack 2 is empty or not.
//If it is empty then execute do part otherwise go
//to the else part.
if S2.isEmpty() then
//Execute the while loop till the
//size of stack 1 is greater than 1.
while S1.size() > 1 do
//Pop the element from stack 1 and
// store it in the variable element.
element = S1.pop()
//And push the popped element
// of stack 1 to the stack 2.
S2.push(element)
//Pop the element form stack 1 and
//store it in the variable element.
element = S1.pop()
//Return the element.
return element
//The else part.
else
//Pop the element form stack 2 and
//store it in the variable element.
element = S2.pop()
//Return the element.
return element
Where, S1 and S2 represent stack 1 and stack 2 respectively.
Explanation:
1 + 1 + 1 + … + n
Thus, for the dequeue operation the amortized complexity is O (1).
Solution
The implementation algorithm whose amortized complexity is O (1) to implement queue using
two stacks is given as follows:
Algorithm for Enqueue:
Enqueue(element):
//Push the element in the stack 1.
S1.push(element)
Algorithm for Dequeue:
Dequeue():
//Check the condition that stack 2 is empty or not.
//If it is empty then execute do part otherwise go
//to the else part.
if S2.isEmpty() then
//Execute the while loop till the
//size of stack 1 is greater than 1.
while S1.size() > 1 do
//Pop the element from stack 1 and
// store it in the variable element.
element = S1.pop()
//And push the popped element
// of stack 1 to the stack 2.
S2.push(element)
//Pop the element form stack 1 and
//store it in the variable element.
element = S1.pop()
//Return the element.
return element
//The else part.
else
//Pop the element form stack 2 and
//store it in the variable element.
element = S2.pop()
//Return the element.
return element
Where, S1 and S2 represent stack 1 and stack 2 respectively.
Explanation:
1 + 1 + 1 + … + n
Thus, for the dequeue operation the amortized complexity is O (1)..
The correct matches are as discussed below(a) A (Glycoprotiens ar.pdf
The correct matches are as discussed below:
(a) A (Glycoprotiens are complex proteins found on the outer layer of the plasma membrane and
form the structural component of surface receptors)
(b) A (The outer surface proteins such as glycoproteins can be easily separated from the plasma
membrane by mild treatments of salts)
(c) C (The proteins/biomolecules localized on the inner side of plasma membrane are tightly
bound to it and thus require harsh chemical treatments are required for their separation)
(d) D (A transmembrane protein which spans the whole width of the plasma membrane is
actively involved in transport of ions and materials across it)
(e) B (A ganglioside is a complex biomolecular lipid found on the periphery of the cell whose
branches are embedded in the membrane itself)
(f) D, E (Both, the transmembrane protein and the phospholipid of plasma membrane show flip-
flop action for transport of materials across it. This is owing to the dynamic physical state of the
plasma membrane)
Solution
The correct matches are as discussed below:
(a) A (Glycoprotiens are complex proteins found on the outer layer of the plasma membrane and
form the structural component of surface receptors)
(b) A (The outer surface proteins such as glycoproteins can be easily separated from the plasma
membrane by mild treatments of salts)
(c) C (The proteins/biomolecules localized on the inner side of plasma membrane are tightly
bound to it and thus require harsh chemical treatments are required for their separation)
(d) D (A transmembrane protein which spans the whole width of the plasma membrane is
actively involved in transport of ions and materials across it)
(e) B (A ganglioside is a complex biomolecular lipid found on the periphery of the cell whose
branches are embedded in the membrane itself)
(f) D, E (Both, the transmembrane protein and the phospholipid of plasma membrane show flip-
flop action for transport of materials across it. This is owing to the dynamic physical state of the
plasma membrane).
Step1 Moles of He = 504.0026Step2 Moles of Xe = 50131.29Step3 .pdf
Step1 Moles of He = 50/4.0026
Step2 Moles of Xe = 50/131.29
Step3 Find total moles
Step4 Partial pressure of He=[ Moles of He/Total moles] x750 torr
Step5 Partial pressure of Xe = 750 - partial pressure of He
Solution
Step1 Moles of He = 50/4.0026
Step2 Moles of Xe = 50/131.29
Step3 Find total moles
Step4 Partial pressure of He=[ Moles of He/Total moles] x750 torr
Step5 Partial pressure of Xe = 750 - partial pressure of He.
SKIN SENSORY ORGANThe human skin is the external covering of the .pdf
SKIN :SENSORY ORGAN
The human skin is the external covering of the body. In people, it is the biggest organ of the
integumentary framework. The skin has up to seven layers of ectodermal tissue and watches the
hidden muscles, bones, tendons and inside organs. Human skin is like that of most different
warm blooded creatures. Despite the fact that about all human skin is secured with hair follicles,
it can seem bald. There are two general sorts of skin, bristly and glabrous skin. The descriptive
word cutaneous truly signifies \"of the skin\" . Since it interfaces with the earth, skin assumes an
essential insusceptibility part in securing the body against pathogens[3] and over the top water
loss. Its different capacities are protection, temperature direction, sensation, blend of vitamin D,
and the insurance of vitamin B folates. Extremely harmed skin will attempt to recuperate by
framing scar tissue. This is frequently stained and depigmented. In people, skin pigmentation
shifts among populaces, and skin sort can go from dry to slick. Such skin assortment gives a rich
and various living space for microorganisms that number around 1000 species from 19 phyla,
exhibit on the human skin
Skin has mesodermal cells, pigmentation, for example, melanin gave by melanocytes, which
ingest a portion of the possibly risky bright radiation (UV) in daylight. It additionally contains
DNA repair compounds that switch UV harm, with the end goal that individuals without the
qualities for these chemicals endure high rates of skin malignancy. One shape prevalently
delivered by UV light, threatening melanoma, is especially intrusive, making it spread rapidly,
and can frequently be dangerous. Human skin pigmentation shifts among populaces in a striking
way. This has prompted to the order of people(s) on the premise of skin color. The skin is the
biggest organ in the human body. For the normal grown-up human, the skin has a surface zone of
between 1.5-2.0 square meters (16.1-21.5 sq ft.). The thickness of the skin shifts significantly
over all parts of the body, and amongst men and ladies and the youthful and the old. A case is the
skin on the lower arm which is all things considered 1.3 mm in the male and 1.26 mm in the
female. The normal square inch (6.5 cm²) of skin holds 650 sweat organs, 20 veins, 60,000
melanocytes, and more than 1,000 nerve endings. The normal human skin cell is around 30
micrometers in distance across, yet there are variations. A skin cell more often than not extends
from 25-40 micrometers (squared), contingent upon an assortment of variables. Skin is made out
of three essential layers: the epidermis, the dermis and the hypodermis .Epidermis, \"epi\"
originating from the Greek signifying \"over\" or \"upon\", is the peripheral layer of the skin. It
shapes the waterproof, defensive wrap over the body\'s surface which likewise serves as a
hindrance to disease and is comprised of stratified squamous epithelium with a hidden basal
lamina.
The epiderm.
a) FlaseIn terms of trasing volume it is by far the largest market.pdf
a) Flase
In terms of trasing volume it is by far the largest market in the world
b) True
As home currency weakens, one has to pay more units of home currency to buy one unit of
foreign currency, hence making import costlier
Solution
a) Flase
In terms of trasing volume it is by far the largest market in the world
b) True
As home currency weakens, one has to pay more units of home currency to buy one unit of
foreign currency, hence making import costlier.
Ques-1Part-a Mitosis it is a somatic cell division in an organi.pdf
Ques-1:
Part-a: Mitosis: it is a somatic cell division in an organism & this division is useful to maintain
body growth
Part-b: Meiosis: it is the reproductive reduction cell division & it is useful to produce gametes for
fertilization finally to generate a mature embryo
Part-c: cytokinesis: It is defined as the process of division of cytoplasm during cell division
either in mitosis or meiosis & this is useful for carrying cell organelles
Part-d: chromosome: it is the hereditary material that carries genomic information for gene
expression & useful for inheritance of parental traits to offspring
Mitosis ---> somatic cell division & produces two identical daughter cells with equal number of
chromosomes (cytokinesis & karyokinesis).
Meiosis ----> a reduction division occurs in reproductive germ cells in which allosomes
determine sex determination finally generates half of the chromosomes in daughter cells
Part-a: Mitosis: it is a somatic cell division in an organism & this division is useful to maintain
body growth
Part-b: Meiosis: it is the reproductive reduction cell division & it is useful to produce gametes for
fertilization finally to generate a mature embryo
Part-c: cytokinesis: It is defined as the process of division of cytoplasm during cell division
either in mitosis or meiosis & this is useful for carrying cell organelles
Part-d: chromosome: it is the hereditary material that carries genomic information for gene
expression & useful for inheritance of parental traits to offspring
Cell plate is absent during animal cell division instead a complete cleavage of the cells during
division can be observed in animal cells. Cell plate formation during cell division observed only
in plants.
Haploid cells (n) are normally produced by reduction division of meiosis from diploid parent
cells (2n). This type of division occurs in germ cells of male and female species. The
chromosomes of the diploid germ cell undergo reduction in meiosis I and generate half of the
chromosomes when compared to parent diploid cell.
Meiosis division in a reproductive cell often results in four haploid cells with only single set of
chromosomes.
Meiosis-I prophase-I In this process double stranded homologous chromosomes line up each
other, and result in forming a tetrad; this is termed as Synapsis.
Terminal chaismata hold the homologous chromosomes together in metaphase I finally these are
going to align on the metaphase plate. Synapsis allows homologous chromosomes to travel to the
center by forming spindle formation through microtubules attaching to the centromeres finally to
the opposite poles of the cell. Later, crossing over takes place to exchanges paternal and maternal
genes to form tetrad where genetic variation occurs. Crossing over takes place to exchange equal
amounts of DNA generates genetic variability in prophase -I of meiosis.
Crossing over occurs in which lined up chromosomal ends exchange genetic information by
switching their places. Crossing over can un.
Proportional tax is a tax where the rate of tax is fixed. It is a pr.pdf
Proportional tax is a tax where the rate of tax is fixed. It is a predetermined fixed percentage of
one’s income if it is an income tax or it is a fixed percentage of the value of the product if it is a
sales tax. It is also called flat tax. It is regressive in application as all the people pay same
amount. Hence the people earning less pay a higher percentage of their income and the people
paying more pay lesser percentage of their income.
Progressive tax is a tax where the rate of taxation increases with the increase in income or value
of products. Usually this is done by applying brackets to the income or value of products. For
example, people with income from 0 to 20000 fall in one bracket and hence the rate of taxation is
the same for the bracket as a whole let’s say 10%. People with income from 20001 to 40000 fall
in another bracket and they have a different rate of taxation let’s say 12%.Progressive tax works
on the logic of “ability to pay”.
Creating value without producing something new is done by exchanging one good or service
with other. This is done by estimating the exchange value of the goods or services to be
exchanged. The quantified worth of one good or service expressed in terms of the worth of
another is known as the exchange value. In the business of foreign exchange, the value of each
currency is expressed in terms of value of another currency to be exchanged. This creates and
exchange value or exchange rate of one currency to another.
A private currency is a currency issued by private organizations. In many countries it is illegal to
issue private paper currencies. Such a system (of private currencies) will create a protection
against inflation. Once an available instrument or arrangement for investment of present, add-
valuing currency could be created, the public would invest in great numbers, because they would
want to relieve themselves of the fear of devaluing money.
Interest would exist in a pure economy if there is a positive time preference. Time preference is
nothing but, the relative valuation placed on a good at an earlier date compared to its valuation at
a later date. Interest is thus explained as the propensity of individuals to discount the future. A
positive time preference is a necessary and sufficient condition for the existence of Interest in
any economy.
Static view is when resources are allocated efficiently at a point in time. An example of static
efficiency would be whether a firm could produce 2million cars a year more cheaply by using
more labor and less capital. Productive and allocative efficiency are static concepts of efficiency,
they can be used to discuss whether more could be produced now if resources were allocated in a
different way. These concepts can be used for instance, to discuss whether industries dominated
by a monopoly producer might produce at lower cost if competition were introduced in the
industry.
Dynamic view is concerned with how resoures are allocated over a period of tim.
POS system is a networked invironment where a main computer linked t.pdf
POS system is a networked invironment where a main computer linked to multiple checkout
terminals.With a POS system:
The Design considerations of POS system:
Thanks
Solution
POS system is a networked invironment where a main computer linked to multiple checkout
terminals.With a POS system:
The Design considerations of POS system:
Thanks.
Q) The passage of traits from parents of offspring is called A H.pdf
Q) The passage of traits from parents of offspring is called ?
A: Heredity
Q) A breed of chicken shows co-dominance for feather color. One allele codes for black feathers,
another codes for white feathers. The feathers of heterozygous chickens of this breed will be
A: Speckled (Because in co-dominance both alleles are equally dominant and shows up as spots)
Q) Situation in which one allele of gene is not completely dominant over another allele for that
gene are called
A: Incomplete dominance
Q) In rabbits, there are four different versions of the gene for coat color. What pattern of
inheritance is this ?
A: Multiple alleles ( As we call each version of the gene as an allele)
Q) Variation in human skin color is an example of
A: Polygenic traits (there are 3 important genes coding for skin color and we get one of each of
those three genes from each of our parents)
Q) Which of the following assort independently?
A: Chromosomes (During meiosis, the pairs of homologous chromosome are divided in half to
form haploid cells. This assortment of homologous chromosomes is random and hence
independent)
Q) The plants that Gregor Mendel crossed to produce F1 generation made up of the
A: P (Also known as parents used for crossing)
Q) Due to the process of segregation, alleles separate during the production of
A: Gametes (gametes are produced at the end of meiosis and will be haploid in nature)
Q) The scientific study of heredity is called
A: Genetics
Solution
Q) The passage of traits from parents of offspring is called ?
A: Heredity
Q) A breed of chicken shows co-dominance for feather color. One allele codes for black feathers,
another codes for white feathers. The feathers of heterozygous chickens of this breed will be
A: Speckled (Because in co-dominance both alleles are equally dominant and shows up as spots)
Q) Situation in which one allele of gene is not completely dominant over another allele for that
gene are called
A: Incomplete dominance
Q) In rabbits, there are four different versions of the gene for coat color. What pattern of
inheritance is this ?
A: Multiple alleles ( As we call each version of the gene as an allele)
Q) Variation in human skin color is an example of
A: Polygenic traits (there are 3 important genes coding for skin color and we get one of each of
those three genes from each of our parents)
Q) Which of the following assort independently?
A: Chromosomes (During meiosis, the pairs of homologous chromosome are divided in half to
form haploid cells. This assortment of homologous chromosomes is random and hence
independent)
Q) The plants that Gregor Mendel crossed to produce F1 generation made up of the
A: P (Also known as parents used for crossing)
Q) Due to the process of segregation, alleles separate during the production of
A: Gametes (gametes are produced at the end of meiosis and will be haploid in nature)
Q) The scientific study of heredity is called
A: Genetics.
Digital Tools and AI for Teaching Learning and Research
This Presentation in details discusses on Digital Tools and AI for Teaching Learning and Research
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1. Translation program#includestdio.h#includeconio.h#incl.pdf
1. Translation program:
#include
#include
#include
#include
#include
int x1,y1,x2,y2,x3,y3,mx,my;
void draw();
void tri();
void main()
{
int gd=DETECT,gm;
int c;
initgraph(&gd,&gm,\"d:\\\\tc\\\\bgi \");
printf(\"Enter the 1st point for the triangle:\");
scanf(\"%d%d\",&x1,&y1);
printf(\"Enter the 2nd point for the triangle:\");
scanf(\"%d%d\",&x2,&y2);
printf(\"Enter the 3rd point for the triangle:\");
scanf(\"%d%d\",&x3,&y3);
cleardevice();
draw();
getch();
tri();
getch();
}
void draw()
{
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
}
void tri()
{
int x,y,a1,a2,a3,b1,b2,b3;
printf(\"Enter the Transaction coordinates\");
scanf(\"%d%d\",&x,&y);
cleardevice();
a1=x1+x;
b1=y1+y;
a2=x2+x;
b2=y2+y;
a3=x3+x;
b3=y3+y;
line(a1,b1,a2,b2);
line(a2,b2,a3,b3);
line(a3,b3,a1,b1);
}
getch();
closegraph();
2.
//rotation
#include
#include
#include
#include
#include
#include
float x1,y1,x2,y2,x,y,x3,y3,x4,y4,a;
int ch;
int main(void)
{
int gdriver = DETECT, gmode, errorcode;
clrscr();
initgraph(&gdriver, &gmode, \"c:\\\\tc\\\\bgi\");
cout<<\"enter coordinates of line1:\ \";
cin>>x1>>y1>>x2>>y2;
cout<<\"enter coordinates for relative line:\ \";
cin>>x3>>y3;
cout<<\"enter the angle of rotation:\ \";cin>>a;
cleardevice();
line(x1,y1,x2,y2);
moveto(x2,y2);
lineto(x3,y3);
moveto(x3,y3);
lineto(x1,y1);
a=a*(3.14/180);
x1=(x1*cos(a))-(y1*sin(a));
y1=(x1*sin(a))+(y1*cos(a));
x2=(x2*cos(a))-(y2*sin(a));
y2=(x2*sin(a))+(y2*cos(a));
x3=(x3*cos(a))-(y3*sin(a));
y3=(x3*sin(a))+(y3*cos(a));
cout<<\"now hit a key to see rotation:\";
getch();
moveto(x1,y1);
lineto(x2,y2);
moveto(x2,y2);
lineto(x3,y3);
moveto(x3,y3);
lineto(x1,y1);
getch();
closegraph();
}
3. Reflection
#include
#include
#include
#include
void main()
{
int gd=DETECT,gm;
int x1,y1,x2,y2,x3,y3;
char a;
clrscr();
initgraph(&gd,&gm,\"\");
printf(\"\ enter the coordinates of triangle\");
sacnf(\"%d%d%d%d%d%d\",&x1,&y1,&x2,&y2,&x3,&y3);
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
line(320,0,320,430);
line(0,240,640,240);
printf(\"\ enter the axis of reflection\");
scanf(\"%d\",&a);
if(a=\'x\'||a=\'X\')
{
x1=x1;
x2=x2;
x3=x3;
y1=y1+240;
y2=y2+240;
y3=y3+240;
}
else
if(a=\'y\'||a=\'Y\')
{
y1=y1;
y2=y2;
y3=y3;
x1+=320;
x2+=320;
x3+=320;
}
printf(\"\ triangle after reflection\");
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
getch();
closegraph();
}
Solution
1. Translation program:
#include
#include
#include
#include
#include
int x1,y1,x2,y2,x3,y3,mx,my;
void draw();
void tri();
void main()
{
int gd=DETECT,gm;
int c;
initgraph(&gd,&gm,\"d:\\\\tc\\\\bgi \");
printf(\"Enter the 1st point for the triangle:\");
scanf(\"%d%d\",&x1,&y1);
printf(\"Enter the 2nd point for the triangle:\");
scanf(\"%d%d\",&x2,&y2);
printf(\"Enter the 3rd point for the triangle:\");
scanf(\"%d%d\",&x3,&y3);
cleardevice();
draw();
getch();
tri();
getch();
}
void draw()
{
line(x1,y1,x2,y2);
line(x2,y2,x3,y3);
line(x3,y3,x1,y1);
}
void tri()
{
int x,y,a1,a2,a3,b1,b2,b3;
printf(\"Enter the Transaction coordinates\.
1A. The acronym DBLC is used to name the Database Life Cycle.The DBL.pdf
1A. The acronym DBLC is used to name the Database Life Cycle.The DBLC traces the history
of the databse system from its starting point to its obsolescence.The DBLC is composed of six
phases:initial study,design,inplementation and loading,testing and evaluation,operation and
maintenence and evolution.
2A.Centralized conceptual database design consists of typical simple databases and conducted by
single person or small team.
Decentralized conceptual database design consists of large number of entities and complex
relations and spread across multiple sites and developed by multiple teams.
Aggregation process requires designer to create single model in which various aggregation
problems must be addressed like synonyms and homonyms,entity and subtypes.
3A.The minimal data rule specifies that all the data defined in the data model are actually
required to fit to present and expected tuture data requirements.
4A.Top-down design by identifying the differnet entity types and definition to each entity
attributes. in other words top down design starts by defining the required data sets and defines
the data elements for each of those data sets.
Bottom up design first defiines the required attributes and theb groups the attributes to form
entities.
Refer the below diagram for third answer
Solution
1A. The acronym DBLC is used to name the Database Life Cycle.The DBLC traces the history
of the databse system from its starting point to its obsolescence.The DBLC is composed of six
phases:initial study,design,inplementation and loading,testing and evaluation,operation and
maintenence and evolution.
2A.Centralized conceptual database design consists of typical simple databases and conducted by
single person or small team.
Decentralized conceptual database design consists of large number of entities and complex
relations and spread across multiple sites and developed by multiple teams.
Aggregation process requires designer to create single model in which various aggregation
problems must be addressed like synonyms and homonyms,entity and subtypes.
3A.The minimal data rule specifies that all the data defined in the data model are actually
required to fit to present and expected tuture data requirements.
4A.Top-down design by identifying the differnet entity types and definition to each entity
attributes. in other words top down design starts by defining the required data sets and defines
the data elements for each of those data sets.
Bottom up design first defiines the required attributes and theb groups the attributes to form
entities.
Refer the below diagram for third answer.
In chemistry, hybridisation (or hybridization) is.pdf
In chemistry, hybridisation (or hybridization) is the concept of mixing atomic
orbitals to form new hybrid orbitals suitable for the qualitative description of atomic bonding
properties. Hybridised orbitals are very useful in the explanation of the shape of molecular
orbitals for molecules. It is an integral part of valence bond theory. Although sometimes taught
together with the valence shell electron-pair repulsion (VSEPR) theory, valence bond and
hybridization are in fact not related to the VSEPR model.[1] Contents [hide] 1 Historical
development 2 Types of hybridisation 2.1 sp3 hybrids 2.2 sp2 hybrids 2.3 sp hybrids 3
Hybridisation and molecule shape 3.1 Explanation of the shape of water 3.2 Controversy
regarding d-orbital participation 4 Hybridisation theory vs. MO theory 5 See also 6 External
links 7 References [edit]Historical development Chemist Linus Pauling first developed the
hybridisation theory in order to explain the structure of molecules such as methane (CH4).[2]
This concept was developed for such simple chemical systems, but the approach was later
applied more widely, and today it is considered an effective heuristic for rationalizing the
structures of organic compounds. For quantitative calculations of electronic structure and
molecular properties, hybridisation theory is not as practical as molecular orbital theory.
Problems with hybridisation are especially notable when the d orbitals are involved in bonding,
as in coordination chemistry and organometallic chemistry. Although hybridisation schemes in
transition metal chemistry can be used, they are not generally as accurate. Orbitals are a model
representation of the behaviour of electrons within molecules. In the case of simple
hybridisation, this approximation is based on atomic orbitals, similar to those obtained for the
hydrogen atom, the only atom for which an exact analytic solution to its Schrödinger equation is
known. In heavier atoms, like carbon, nitrogen, and oxygen, the atomic orbitals used are the 2s
and 2p orbitals, similar to excited state orbitals for hydrogen. Hybridised orbitals are assumed to
be mixtures of these atomic orbitals, superimposed on each other in various proportions. The
theory of hybridisation is most applicable under these assumptions. It gives a simple orbital
picture equivalent to Lewis structures. Hybridisation is not required to describe molecules, but
for molecules made up from carbon, nitrogen and oxygen (and to a lesser extent, sulfur and
phosphorus) the hybridisation theory/model makes the description much easier. The
hybridisation theory finds its use mainly in organic chemistry. Its explanation starts with the way
bonding is organized in methane. [edit]Types of hybridisation [edit]sp3 hybrids Hybridisation
describes the bonding atoms from an atom\'s point of view. That is, for a tetrahedrally
coordinated carbon (e.g., methane, CH4), the carbon should have 4 orbitals with the correct
symmetry to bond to the 4 hydrogen atoms. The .
RPS 19 stands for ribosomal protein S19. This proteins is synthesise.pdf
RPS 19 stands for ribosomal protein S19. This proteins is synthesised and located in the cytosol.
It is then transported to the respective destinations. RPS 19 to reach the mitochondria must cross
the 2 mitochondrial membranes the outer and inner membrane.
Solution
RPS 19 stands for ribosomal protein S19. This proteins is synthesised and located in the cytosol.
It is then transported to the respective destinations. RPS 19 to reach the mitochondria must cross
the 2 mitochondrial membranes the outer and inner membrane..
y^(iv)-4y=0taking 4y to RHS we gety^(iv) = 4yy^(iii) = integra.pdf
y^(iv)-4y=0
taking 4y to RHS we get
y^(iv) = 4y
y^(iii) = integral of(4y)
=4
y^(ii) = integral of(4)
= 0+ A note:The integral of a constant C with respect to y is Cy+ A
y^(i) = integral of(A)
= 0 +A
y =(intgral of A)
=0+A
So the general solution is y= A(constant).
Solution
y^(iv)-4y=0
taking 4y to RHS we get
y^(iv) = 4y
y^(iii) = integral of(4y)
=4
y^(ii) = integral of(4)
= 0+ A note:The integral of a constant C with respect to y is Cy+ A
y^(i) = integral of(A)
= 0 +A
y =(intgral of A)
=0+A
So the general solution is y= A(constant)..
Fe(s) + Mn2+(aq) Fe2+(aq) + Mn(s)Yes this reaction is spon.pdf
Fe(s) + Mn2+(aq) Fe2+(aq) + Mn(s)
Yes this reaction is spontaneous in the reverse direction
This is because E of the whole rection will be +ve in the reverse direction
We know that if E of the reaction is +ve, the reaction is Spontaneous
Solution
Fe(s) + Mn2+(aq) Fe2+(aq) + Mn(s)
Yes this reaction is spontaneous in the reverse direction
This is because E of the whole rection will be +ve in the reverse direction
We know that if E of the reaction is +ve, the reaction is Spontaneous.
When Na2SO3 is dissolved in water, Na+ and SO32- ions are formedN.pdf
When Na2SO3 is dissolved in water, Na+ and SO32- ions are formed:
Na2SO3 => 2 Na+ + SO32-
The SO32- ions are weak bases and ionize in water to form HSO3- and OH- ions:
SO32- + H2O <=> HSO3- + OH-
Since OH- ions are formed, the pH will be greater than 7 and the solution is basic.
Solution
When Na2SO3 is dissolved in water, Na+ and SO32- ions are formed:
Na2SO3 => 2 Na+ + SO32-
The SO32- ions are weak bases and ionize in water to form HSO3- and OH- ions:
SO32- + H2O <=> HSO3- + OH-
Since OH- ions are formed, the pH will be greater than 7 and the solution is basic..
To convert html code into Java servlet you have to write all html ta.pdf
To convert html code into Java servlet you have to write all html tag within out.println statement.
Out.println() is used to direct execute/print on browser.
# Program
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Student extends HttpServlet {
@Override
public void doGet(HttpServletRequest request, HttpServletResponse response) throws
IOException, ServletException {
response.setContentType(\"text/html;charset=UTF-8\");
PrintWriter out = response.getWriter();
try {
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"Registration Form\");
out.println(\"Name:\");
out.println(\" \");
out.println(\" Username:\");
out.println(\"\");
out.println(\"Password:\");
out.println(\" \");
out.println(\" Address:\");
out.println(\"\");
out.println(\" Country:\");
out.println(\"\");
out.println(\"please country\");
out.println(\"USA\");
out.println(\"UK\");
out.println(\" \");
out.println(\"ZIP Code:\");
out.println(\"\");
out.println(\" Email:\");
out.println(\" \");
out.println(\" Sex:\");
out.println(\"Male\");
out.println(\" Female\");
out.println(\" Language:\");
out.println(\" English\");
out.println(\" French\");
out.println(\"Germany\");
out.println(\" \");
out.println(\" About: \");
out.println(\" \");
out.println(\" \");
out.println(\" \");
out.println(\"\");
out.println(\" \");
out.println(\" \");
} finally {
out.close();
}
}
}
Solution
To convert html code into Java servlet you have to write all html tag within out.println statement.
Out.println() is used to direct execute/print on browser.
# Program
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Student extends HttpServlet {
@Override
public void doGet(HttpServletRequest request, HttpServletResponse response) throws
IOException, ServletException {
response.setContentType(\"text/html;charset=UTF-8\");
PrintWriter out = response.getWriter();
try {
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"\");
out.println(\"Registration Form\");
out.println(\"Name:\");
out.println(\" \");
out.println(\" Username:\");
out.println(\"\");
out.println(\"Password:\");
out.println(\" \");
out.println(\" Address:\");
out.println(\"\");
out.println(\" Country:\");
out.println(\"\");
out.println(\"please country\");
out.println(\"USA\");
out.println(\"UK\");
out.println(\" \");
out.println(\"ZIP Code:\");
out.println(\"\");
out.println(\" Email:\");
out.println(\" \");
out.println(\" Sex:\");.
Therapsids is a group of synapsidsAdaptation1.Four limbs extent.pdf
Therapsids is a group of synapsids
Adaptation:
1.Four limbs extent vertically in contrast to crawling limbs
2..Feet were more symmetrical
3.Jaws were more complexed and powerful
4.Frontal incisors canines for tearing.
Hadrocodium
They were primitive mammals
1.Advance features
2.Large brain
3.Advance ear
Prosimian
Group of primates,
primitive mammalians characters is bicornuate uterus
Solution
Therapsids is a group of synapsids
Adaptation:
1.Four limbs extent vertically in contrast to crawling limbs
2..Feet were more symmetrical
3.Jaws were more complexed and powerful
4.Frontal incisors canines for tearing.
Hadrocodium
They were primitive mammals
1.Advance features
2.Large brain
3.Advance ear
Prosimian
Group of primates,
primitive mammalians characters is bicornuate uterus.
They trade away higher fecundity for future reproduction.Being ite.pdf
They trade away higher fecundity for future reproduction.
Being iteroparous, they can produce Offsprings throughout life, but they produce single
Offsprings trading away their fecundity so that they can reproduce throughout.
Solution
They trade away higher fecundity for future reproduction.
Being iteroparous, they can produce Offsprings throughout life, but they produce single
Offsprings trading away their fecundity so that they can reproduce throughout..
The statements that are consistent with facts known about membrane a.pdf
The statements that are consistent with facts known about membrane are
1. Some transport processes use the energy of a second transport process to move species across
membranes.
2. Active transport always employs ATP hydrolysis to provide the energy for the transporter.
Solution
The statements that are consistent with facts known about membrane are
1. Some transport processes use the energy of a second transport process to move species across
membranes.
2. Active transport always employs ATP hydrolysis to provide the energy for the transporter..
The implementation algorithm whose amortized complexity is O (1) to .pdf
The implementation algorithm whose amortized complexity is O (1) to implement queue using
two stacks is given as follows:
Algorithm for Enqueue:
Enqueue(element):
//Push the element in the stack 1.
S1.push(element)
Algorithm for Dequeue:
Dequeue():
//Check the condition that stack 2 is empty or not.
//If it is empty then execute do part otherwise go
//to the else part.
if S2.isEmpty() then
//Execute the while loop till the
//size of stack 1 is greater than 1.
while S1.size() > 1 do
//Pop the element from stack 1 and
// store it in the variable element.
element = S1.pop()
//And push the popped element
// of stack 1 to the stack 2.
S2.push(element)
//Pop the element form stack 1 and
//store it in the variable element.
element = S1.pop()
//Return the element.
return element
//The else part.
else
//Pop the element form stack 2 and
//store it in the variable element.
element = S2.pop()
//Return the element.
return element
Where, S1 and S2 represent stack 1 and stack 2 respectively.
Explanation:
1 + 1 + 1 + … + n
Thus, for the dequeue operation the amortized complexity is O (1).
Solution
The implementation algorithm whose amortized complexity is O (1) to implement queue using
two stacks is given as follows:
Algorithm for Enqueue:
Enqueue(element):
//Push the element in the stack 1.
S1.push(element)
Algorithm for Dequeue:
Dequeue():
//Check the condition that stack 2 is empty or not.
//If it is empty then execute do part otherwise go
//to the else part.
if S2.isEmpty() then
//Execute the while loop till the
//size of stack 1 is greater than 1.
while S1.size() > 1 do
//Pop the element from stack 1 and
// store it in the variable element.
element = S1.pop()
//And push the popped element
// of stack 1 to the stack 2.
S2.push(element)
//Pop the element form stack 1 and
//store it in the variable element.
element = S1.pop()
//Return the element.
return element
//The else part.
else
//Pop the element form stack 2 and
//store it in the variable element.
element = S2.pop()
//Return the element.
return element
Where, S1 and S2 represent stack 1 and stack 2 respectively.
Explanation:
1 + 1 + 1 + … + n
Thus, for the dequeue operation the amortized complexity is O (1)..
The correct matches are as discussed below(a) A (Glycoprotiens ar.pdf
The correct matches are as discussed below:
(a) A (Glycoprotiens are complex proteins found on the outer layer of the plasma membrane and
form the structural component of surface receptors)
(b) A (The outer surface proteins such as glycoproteins can be easily separated from the plasma
membrane by mild treatments of salts)
(c) C (The proteins/biomolecules localized on the inner side of plasma membrane are tightly
bound to it and thus require harsh chemical treatments are required for their separation)
(d) D (A transmembrane protein which spans the whole width of the plasma membrane is
actively involved in transport of ions and materials across it)
(e) B (A ganglioside is a complex biomolecular lipid found on the periphery of the cell whose
branches are embedded in the membrane itself)
(f) D, E (Both, the transmembrane protein and the phospholipid of plasma membrane show flip-
flop action for transport of materials across it. This is owing to the dynamic physical state of the
plasma membrane)
Solution
The correct matches are as discussed below:
(a) A (Glycoprotiens are complex proteins found on the outer layer of the plasma membrane and
form the structural component of surface receptors)
(b) A (The outer surface proteins such as glycoproteins can be easily separated from the plasma
membrane by mild treatments of salts)
(c) C (The proteins/biomolecules localized on the inner side of plasma membrane are tightly
bound to it and thus require harsh chemical treatments are required for their separation)
(d) D (A transmembrane protein which spans the whole width of the plasma membrane is
actively involved in transport of ions and materials across it)
(e) B (A ganglioside is a complex biomolecular lipid found on the periphery of the cell whose
branches are embedded in the membrane itself)
(f) D, E (Both, the transmembrane protein and the phospholipid of plasma membrane show flip-
flop action for transport of materials across it. This is owing to the dynamic physical state of the
plasma membrane).
Step1 Moles of He = 504.0026Step2 Moles of Xe = 50131.29Step3 .pdf
Step1 Moles of He = 50/4.0026
Step2 Moles of Xe = 50/131.29
Step3 Find total moles
Step4 Partial pressure of He=[ Moles of He/Total moles] x750 torr
Step5 Partial pressure of Xe = 750 - partial pressure of He
Solution
Step1 Moles of He = 50/4.0026
Step2 Moles of Xe = 50/131.29
Step3 Find total moles
Step4 Partial pressure of He=[ Moles of He/Total moles] x750 torr
Step5 Partial pressure of Xe = 750 - partial pressure of He.
SKIN SENSORY ORGANThe human skin is the external covering of the .pdf
SKIN :SENSORY ORGAN
The human skin is the external covering of the body. In people, it is the biggest organ of the
integumentary framework. The skin has up to seven layers of ectodermal tissue and watches the
hidden muscles, bones, tendons and inside organs. Human skin is like that of most different
warm blooded creatures. Despite the fact that about all human skin is secured with hair follicles,
it can seem bald. There are two general sorts of skin, bristly and glabrous skin. The descriptive
word cutaneous truly signifies \"of the skin\" . Since it interfaces with the earth, skin assumes an
essential insusceptibility part in securing the body against pathogens[3] and over the top water
loss. Its different capacities are protection, temperature direction, sensation, blend of vitamin D,
and the insurance of vitamin B folates. Extremely harmed skin will attempt to recuperate by
framing scar tissue. This is frequently stained and depigmented. In people, skin pigmentation
shifts among populaces, and skin sort can go from dry to slick. Such skin assortment gives a rich
and various living space for microorganisms that number around 1000 species from 19 phyla,
exhibit on the human skin
Skin has mesodermal cells, pigmentation, for example, melanin gave by melanocytes, which
ingest a portion of the possibly risky bright radiation (UV) in daylight. It additionally contains
DNA repair compounds that switch UV harm, with the end goal that individuals without the
qualities for these chemicals endure high rates of skin malignancy. One shape prevalently
delivered by UV light, threatening melanoma, is especially intrusive, making it spread rapidly,
and can frequently be dangerous. Human skin pigmentation shifts among populaces in a striking
way. This has prompted to the order of people(s) on the premise of skin color. The skin is the
biggest organ in the human body. For the normal grown-up human, the skin has a surface zone of
between 1.5-2.0 square meters (16.1-21.5 sq ft.). The thickness of the skin shifts significantly
over all parts of the body, and amongst men and ladies and the youthful and the old. A case is the
skin on the lower arm which is all things considered 1.3 mm in the male and 1.26 mm in the
female. The normal square inch (6.5 cm²) of skin holds 650 sweat organs, 20 veins, 60,000
melanocytes, and more than 1,000 nerve endings. The normal human skin cell is around 30
micrometers in distance across, yet there are variations. A skin cell more often than not extends
from 25-40 micrometers (squared), contingent upon an assortment of variables. Skin is made out
of three essential layers: the epidermis, the dermis and the hypodermis .Epidermis, \"epi\"
originating from the Greek signifying \"over\" or \"upon\", is the peripheral layer of the skin. It
shapes the waterproof, defensive wrap over the body\'s surface which likewise serves as a
hindrance to disease and is comprised of stratified squamous epithelium with a hidden basal
lamina.
The epiderm.
a) FlaseIn terms of trasing volume it is by far the largest market.pdf
a) Flase
In terms of trasing volume it is by far the largest market in the world
b) True
As home currency weakens, one has to pay more units of home currency to buy one unit of
foreign currency, hence making import costlier
Solution
a) Flase
In terms of trasing volume it is by far the largest market in the world
b) True
As home currency weakens, one has to pay more units of home currency to buy one unit of
foreign currency, hence making import costlier.
Ques-1Part-a Mitosis it is a somatic cell division in an organi.pdf
Ques-1:
Part-a: Mitosis: it is a somatic cell division in an organism & this division is useful to maintain
body growth
Part-b: Meiosis: it is the reproductive reduction cell division & it is useful to produce gametes for
fertilization finally to generate a mature embryo
Part-c: cytokinesis: It is defined as the process of division of cytoplasm during cell division
either in mitosis or meiosis & this is useful for carrying cell organelles
Part-d: chromosome: it is the hereditary material that carries genomic information for gene
expression & useful for inheritance of parental traits to offspring
Mitosis ---> somatic cell division & produces two identical daughter cells with equal number of
chromosomes (cytokinesis & karyokinesis).
Meiosis ----> a reduction division occurs in reproductive germ cells in which allosomes
determine sex determination finally generates half of the chromosomes in daughter cells
Part-a: Mitosis: it is a somatic cell division in an organism & this division is useful to maintain
body growth
Part-b: Meiosis: it is the reproductive reduction cell division & it is useful to produce gametes for
fertilization finally to generate a mature embryo
Part-c: cytokinesis: It is defined as the process of division of cytoplasm during cell division
either in mitosis or meiosis & this is useful for carrying cell organelles
Part-d: chromosome: it is the hereditary material that carries genomic information for gene
expression & useful for inheritance of parental traits to offspring
Cell plate is absent during animal cell division instead a complete cleavage of the cells during
division can be observed in animal cells. Cell plate formation during cell division observed only
in plants.
Haploid cells (n) are normally produced by reduction division of meiosis from diploid parent
cells (2n). This type of division occurs in germ cells of male and female species. The
chromosomes of the diploid germ cell undergo reduction in meiosis I and generate half of the
chromosomes when compared to parent diploid cell.
Meiosis division in a reproductive cell often results in four haploid cells with only single set of
chromosomes.
Meiosis-I prophase-I In this process double stranded homologous chromosomes line up each
other, and result in forming a tetrad; this is termed as Synapsis.
Terminal chaismata hold the homologous chromosomes together in metaphase I finally these are
going to align on the metaphase plate. Synapsis allows homologous chromosomes to travel to the
center by forming spindle formation through microtubules attaching to the centromeres finally to
the opposite poles of the cell. Later, crossing over takes place to exchanges paternal and maternal
genes to form tetrad where genetic variation occurs. Crossing over takes place to exchange equal
amounts of DNA generates genetic variability in prophase -I of meiosis.
Crossing over occurs in which lined up chromosomal ends exchange genetic information by
switching their places. Crossing over can un.
Proportional tax is a tax where the rate of tax is fixed. It is a pr.pdf
Proportional tax is a tax where the rate of tax is fixed. It is a predetermined fixed percentage of
one’s income if it is an income tax or it is a fixed percentage of the value of the product if it is a
sales tax. It is also called flat tax. It is regressive in application as all the people pay same
amount. Hence the people earning less pay a higher percentage of their income and the people
paying more pay lesser percentage of their income.
Progressive tax is a tax where the rate of taxation increases with the increase in income or value
of products. Usually this is done by applying brackets to the income or value of products. For
example, people with income from 0 to 20000 fall in one bracket and hence the rate of taxation is
the same for the bracket as a whole let’s say 10%. People with income from 20001 to 40000 fall
in another bracket and they have a different rate of taxation let’s say 12%.Progressive tax works
on the logic of “ability to pay”.
Creating value without producing something new is done by exchanging one good or service
with other. This is done by estimating the exchange value of the goods or services to be
exchanged. The quantified worth of one good or service expressed in terms of the worth of
another is known as the exchange value. In the business of foreign exchange, the value of each
currency is expressed in terms of value of another currency to be exchanged. This creates and
exchange value or exchange rate of one currency to another.
A private currency is a currency issued by private organizations. In many countries it is illegal to
issue private paper currencies. Such a system (of private currencies) will create a protection
against inflation. Once an available instrument or arrangement for investment of present, add-
valuing currency could be created, the public would invest in great numbers, because they would
want to relieve themselves of the fear of devaluing money.
Interest would exist in a pure economy if there is a positive time preference. Time preference is
nothing but, the relative valuation placed on a good at an earlier date compared to its valuation at
a later date. Interest is thus explained as the propensity of individuals to discount the future. A
positive time preference is a necessary and sufficient condition for the existence of Interest in
any economy.
Static view is when resources are allocated efficiently at a point in time. An example of static
efficiency would be whether a firm could produce 2million cars a year more cheaply by using
more labor and less capital. Productive and allocative efficiency are static concepts of efficiency,
they can be used to discuss whether more could be produced now if resources were allocated in a
different way. These concepts can be used for instance, to discuss whether industries dominated
by a monopoly producer might produce at lower cost if competition were introduced in the
industry.
Dynamic view is concerned with how resoures are allocated over a period of tim.
POS system is a networked invironment where a main computer linked t.pdf
POS system is a networked invironment where a main computer linked to multiple checkout
terminals.With a POS system:
The Design considerations of POS system:
Thanks
Solution
POS system is a networked invironment where a main computer linked to multiple checkout
terminals.With a POS system:
The Design considerations of POS system:
Thanks.
Q) The passage of traits from parents of offspring is called A H.pdf
Q) The passage of traits from parents of offspring is called ?
A: Heredity
Q) A breed of chicken shows co-dominance for feather color. One allele codes for black feathers,
another codes for white feathers. The feathers of heterozygous chickens of this breed will be
A: Speckled (Because in co-dominance both alleles are equally dominant and shows up as spots)
Q) Situation in which one allele of gene is not completely dominant over another allele for that
gene are called
A: Incomplete dominance
Q) In rabbits, there are four different versions of the gene for coat color. What pattern of
inheritance is this ?
A: Multiple alleles ( As we call each version of the gene as an allele)
Q) Variation in human skin color is an example of
A: Polygenic traits (there are 3 important genes coding for skin color and we get one of each of
those three genes from each of our parents)
Q) Which of the following assort independently?
A: Chromosomes (During meiosis, the pairs of homologous chromosome are divided in half to
form haploid cells. This assortment of homologous chromosomes is random and hence
independent)
Q) The plants that Gregor Mendel crossed to produce F1 generation made up of the
A: P (Also known as parents used for crossing)
Q) Due to the process of segregation, alleles separate during the production of
A: Gametes (gametes are produced at the end of meiosis and will be haploid in nature)
Q) The scientific study of heredity is called
A: Genetics
Solution
Q) The passage of traits from parents of offspring is called ?
A: Heredity
Q) A breed of chicken shows co-dominance for feather color. One allele codes for black feathers,
another codes for white feathers. The feathers of heterozygous chickens of this breed will be
A: Speckled (Because in co-dominance both alleles are equally dominant and shows up as spots)
Q) Situation in which one allele of gene is not completely dominant over another allele for that
gene are called
A: Incomplete dominance
Q) In rabbits, there are four different versions of the gene for coat color. What pattern of
inheritance is this ?
A: Multiple alleles ( As we call each version of the gene as an allele)
Q) Variation in human skin color is an example of
A: Polygenic traits (there are 3 important genes coding for skin color and we get one of each of
those three genes from each of our parents)
Q) Which of the following assort independently?
A: Chromosomes (During meiosis, the pairs of homologous chromosome are divided in half to
form haploid cells. This assortment of homologous chromosomes is random and hence
independent)
Q) The plants that Gregor Mendel crossed to produce F1 generation made up of the
A: P (Also known as parents used for crossing)
Q) Due to the process of segregation, alleles separate during the production of
A: Gametes (gametes are produced at the end of meiosis and will be haploid in nature)
Q) The scientific study of heredity is called
A: Genetics.
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● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
Biological Screening of Herbal Drugs in detailed.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
678020731-Sumas-y-Restas-Para-Colorear.pdf
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
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https://app.box.com/s/hqnndn05v4q5a4k4jd597rkdbda0fniiThe French Revolution Class 9 Study Material pdf free download
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
The Challenger.pdf DNHS Official Publication
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is prepared for master's students (MIFB & MIBS) UUM. May it be useful to all.1.4 modern child centered education - mahatma gandhi-2.pptx
Child centred education is an educational approach that priorities the interest, needs and abilities of the child in the learning process.
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
Unit 8 - Information and Communication Technology (Paper I).pdf
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
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Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
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tested on EclipseRainfall.javaimpo.pdf
- 1. //tested on Eclipse /*************Rainfall.java*************/ import java.text.DecimalFormat; import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class RainFall { /*Data member variable*/ private double monthlyRainFall; private double monthsRainFall[]=new double[12]; private int month=0; private double maxRain=0.0; private int maxrainMonth; private double minRain=0.0; private int minRainMonth; /*creating map for storing month*/ Map monthMap=new HashMap(); Scanner input=new Scanner(System.in); /*Initializing map with value while default constructor*/ public RainFall(){ monthMap.put(0, "January"); monthMap.put(1, "February"); monthMap.put(2, "March"); monthMap.put(3, "April"); monthMap.put(4, "May"); monthMap.put(5, "June"); monthMap.put(6, "July"); monthMap.put(7, "August"); monthMap.put(8, "September"); monthMap.put(9, "October"); monthMap.put(10, "November"); monthMap.put(11, "December"); } /*Getting monthlyRainFall*/ public double getMonthlyRainFall() {
- 2. return monthlyRainFall; } /*Setting monthly rainfall If it is negative then it loops until positive */ public void setMonthlyRainFall(double monthlyRainFall) { while(monthlyRainFall<0){ System.out.println("Please Enter positive value of monthly rainfall"); monthlyRainFall=input.nextDouble(); } monthsRainFall[month++]=monthlyRainFall; } /*Getting average month rain fall*/ public void averageMonthlyRainFall(){ double totalRainFall=0; /*first calculate totalRain fall after that divide it total month*/ for(int i=0;imonthsRainFall[i]){ minRain=monthsRainFall[i]; minRainMonth=i; } } System.out.println("Min Rain Month Fall: "+monthMap.get(minRainMonth)); } /*Main method start*/ public static void main(String[] args) { Scanner sc=new Scanner(System.in); /*Creating instance of rainFall class*/ RainFall rainFall=new RainFall(); /*getting rainfall for each month from user*/ for(int i=0;i<12;i++){ System.out.println("Please Enter rainFall for "+(i+1)+" Month"); rainFall.setMonthlyRainFall(sc.nextDouble()); } /*Average Monthly rainfall*/ rainFall.averageMonthlyRainFall(); /*Total Rain Fall in a year*/ rainFall.totalRainFall();
- 3. /*Max rainFall Month*/ rainFall.maxRainFallMonth(); /*Minimum rainFall Month*/ rainFall.minRainFallMonth(); sc.close(); } } /***************output************/ Please Enter rainFall for 1 Month 121 Please Enter rainFall for 2 Month 134 Please Enter rainFall for 3 Month 54 Please Enter rainFall for 4 Month 167 Please Enter rainFall for 5 Month 256 Please Enter rainFall for 6 Month 456 Please Enter rainFall for 7 Month 78 Please Enter rainFall for 8 Month 290 Please Enter rainFall for 9 Month 176 Please Enter rainFall for 10 Month 263 Please Enter rainFall for 11 Month 100 Please Enter rainFall for 12 Month 189 Average Monthly Rain Fall: 190.33 Total Rain Fall for the year: 2284 Max Rain Month Fall: June Min Rain Month Fall: March
- 4. Thanks a lot. If you have any doubt. Please let me know Solution //tested on Eclipse /*************Rainfall.java*************/ import java.text.DecimalFormat; import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class RainFall { /*Data member variable*/ private double monthlyRainFall; private double monthsRainFall[]=new double[12]; private int month=0; private double maxRain=0.0; private int maxrainMonth; private double minRain=0.0; private int minRainMonth; /*creating map for storing month*/ Map monthMap=new HashMap(); Scanner input=new Scanner(System.in); /*Initializing map with value while default constructor*/ public RainFall(){ monthMap.put(0, "January"); monthMap.put(1, "February"); monthMap.put(2, "March"); monthMap.put(3, "April"); monthMap.put(4, "May"); monthMap.put(5, "June"); monthMap.put(6, "July"); monthMap.put(7, "August"); monthMap.put(8, "September"); monthMap.put(9, "October"); monthMap.put(10, "November");
- 5. monthMap.put(11, "December"); } /*Getting monthlyRainFall*/ public double getMonthlyRainFall() { return monthlyRainFall; } /*Setting monthly rainfall If it is negative then it loops until positive */ public void setMonthlyRainFall(double monthlyRainFall) { while(monthlyRainFall<0){ System.out.println("Please Enter positive value of monthly rainfall"); monthlyRainFall=input.nextDouble(); } monthsRainFall[month++]=monthlyRainFall; } /*Getting average month rain fall*/ public void averageMonthlyRainFall(){ double totalRainFall=0; /*first calculate totalRain fall after that divide it total month*/ for(int i=0;imonthsRainFall[i]){ minRain=monthsRainFall[i]; minRainMonth=i; } } System.out.println("Min Rain Month Fall: "+monthMap.get(minRainMonth)); } /*Main method start*/ public static void main(String[] args) { Scanner sc=new Scanner(System.in); /*Creating instance of rainFall class*/ RainFall rainFall=new RainFall(); /*getting rainfall for each month from user*/ for(int i=0;i<12;i++){ System.out.println("Please Enter rainFall for "+(i+1)+" Month"); rainFall.setMonthlyRainFall(sc.nextDouble()); }
- 6. /*Average Monthly rainfall*/ rainFall.averageMonthlyRainFall(); /*Total Rain Fall in a year*/ rainFall.totalRainFall(); /*Max rainFall Month*/ rainFall.maxRainFallMonth(); /*Minimum rainFall Month*/ rainFall.minRainFallMonth(); sc.close(); } } /***************output************/ Please Enter rainFall for 1 Month 121 Please Enter rainFall for 2 Month 134 Please Enter rainFall for 3 Month 54 Please Enter rainFall for 4 Month 167 Please Enter rainFall for 5 Month 256 Please Enter rainFall for 6 Month 456 Please Enter rainFall for 7 Month 78 Please Enter rainFall for 8 Month 290 Please Enter rainFall for 9 Month 176 Please Enter rainFall for 10 Month 263 Please Enter rainFall for 11 Month 100 Please Enter rainFall for 12 Month 189
- 7. Average Monthly Rain Fall: 190.33 Total Rain Fall for the year: 2284 Max Rain Month Fall: June Min Rain Month Fall: March Thanks a lot. If you have any doubt. Please let me know