y^(iv)-4y=0taking 4y to RHS we gety^(iv) = 4yy^(iii) = integra.pdf

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y^(iv)-4y=0 taking 4y to RHS we get y^(iv) = 4y y^(iii) = integral of(4y) =4 y^(ii) = integral of(4) = 0+ A note:The integral of a constant C with respect to y is Cy+ A y^(i) = integral of(A) = 0 +A y =(intgral of A) =0+A So the general solution is y= A(constant). Solution y^(iv)-4y=0 taking 4y to RHS we get y^(iv) = 4y y^(iii) = integral of(4y) =4 y^(ii) = integral of(4) = 0+ A note:The integral of a constant C with respect to y is Cy+ A y^(i) = integral of(A) = 0 +A y =(intgral of A) =0+A So the general solution is y= A(constant)..

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They trade away higher fecundity for future reproduction. Being iteroparous, they can produce Offsprings throughout life, but they produce single Offsprings trading away their fecundity so that they can reproduce throughout. Solution They trade away higher fecundity for future reproduction. Being iteroparous, they can produce Offsprings throughout life, but they produce single Offsprings trading away their fecundity so that they can reproduce throughout..

They trade away higher fecundity for future reproduction.Being ite.pdf

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The statements that are consistent with facts known about membrane are 1. Some transport processes use the energy of a second transport process to move species across membranes. 2. Active transport always employs ATP hydrolysis to provide the energy for the transporter. Solution The statements that are consistent with facts known about membrane are 1. Some transport processes use the energy of a second transport process to move species across membranes. 2. Active transport always employs ATP hydrolysis to provide the energy for the transporter..

The statements that are consistent with facts known about membrane a.pdf

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The implementation algorithm whose amortized complexity is O (1) to implement queue using two stacks is given as follows: Algorithm for Enqueue: Enqueue(element): //Push the element in the stack 1. S1.push(element) Algorithm for Dequeue: Dequeue(): //Check the condition that stack 2 is empty or not. //If it is empty then execute do part otherwise go //to the else part. if S2.isEmpty() then //Execute the while loop till the //size of stack 1 is greater than 1. while S1.size() > 1 do //Pop the element from stack 1 and // store it in the variable element. element = S1.pop() //And push the popped element // of stack 1 to the stack 2. S2.push(element) //Pop the element form stack 1 and //store it in the variable element. element = S1.pop() //Return the element. return element //The else part. else //Pop the element form stack 2 and //store it in the variable element. element = S2.pop() //Return the element. return element Where, S1 and S2 represent stack 1 and stack 2 respectively. Explanation: 1 + 1 + 1 + … + n Thus, for the dequeue operation the amortized complexity is O (1). Solution The implementation algorithm whose amortized complexity is O (1) to implement queue using two stacks is given as follows: Algorithm for Enqueue: Enqueue(element): //Push the element in the stack 1. S1.push(element) Algorithm for Dequeue: Dequeue(): //Check the condition that stack 2 is empty or not. //If it is empty then execute do part otherwise go //to the else part. if S2.isEmpty() then //Execute the while loop till the //size of stack 1 is greater than 1. while S1.size() > 1 do //Pop the element from stack 1 and // store it in the variable element. element = S1.pop() //And push the popped element // of stack 1 to the stack 2. S2.push(element) //Pop the element form stack 1 and //store it in the variable element. element = S1.pop() //Return the element. return element //The else part. else //Pop the element form stack 2 and //store it in the variable element. element = S2.pop() //Return the element. return element Where, S1 and S2 represent stack 1 and stack 2 respectively. Explanation: 1 + 1 + 1 + … + n Thus, for the dequeue operation the amortized complexity is O (1)..

The implementation algorithm whose amortized complexity is O (1) to .pdf

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The correct matches are as discussed below: (a) A (Glycoprotiens are complex proteins found on the outer layer of the plasma membrane and form the structural component of surface receptors) (b) A (The outer surface proteins such as glycoproteins can be easily separated from the plasma membrane by mild treatments of salts) (c) C (The proteins/biomolecules localized on the inner side of plasma membrane are tightly bound to it and thus require harsh chemical treatments are required for their separation) (d) D (A transmembrane protein which spans the whole width of the plasma membrane is actively involved in transport of ions and materials across it) (e) B (A ganglioside is a complex biomolecular lipid found on the periphery of the cell whose branches are embedded in the membrane itself) (f) D, E (Both, the transmembrane protein and the phospholipid of plasma membrane show flip- flop action for transport of materials across it. This is owing to the dynamic physical state of the plasma membrane) Solution The correct matches are as discussed below: (a) A (Glycoprotiens are complex proteins found on the outer layer of the plasma membrane and form the structural component of surface receptors) (b) A (The outer surface proteins such as glycoproteins can be easily separated from the plasma membrane by mild treatments of salts) (c) C (The proteins/biomolecules localized on the inner side of plasma membrane are tightly bound to it and thus require harsh chemical treatments are required for their separation) (d) D (A transmembrane protein which spans the whole width of the plasma membrane is actively involved in transport of ions and materials across it) (e) B (A ganglioside is a complex biomolecular lipid found on the periphery of the cell whose branches are embedded in the membrane itself) (f) D, E (Both, the transmembrane protein and the phospholipid of plasma membrane show flip- flop action for transport of materials across it. This is owing to the dynamic physical state of the plasma membrane).

The correct matches are as discussed below(a) A (Glycoprotiens ar.pdf

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Step1 Moles of He = 50/4.0026 Step2 Moles of Xe = 50/131.29 Step3 Find total moles Step4 Partial pressure of He=[ Moles of He/Total moles] x750 torr Step5 Partial pressure of Xe = 750 - partial pressure of He Solution Step1 Moles of He = 50/4.0026 Step2 Moles of Xe = 50/131.29 Step3 Find total moles Step4 Partial pressure of He=[ Moles of He/Total moles] x750 torr Step5 Partial pressure of Xe = 750 - partial pressure of He.

Step1 Moles of He = 504.0026Step2 Moles of Xe = 50131.29Step3 .pdf

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SKIN :SENSORY ORGAN The human skin is the external covering of the body. In people, it is the biggest organ of the integumentary framework. The skin has up to seven layers of ectodermal tissue and watches the hidden muscles, bones, tendons and inside organs. Human skin is like that of most different warm blooded creatures. Despite the fact that about all human skin is secured with hair follicles, it can seem bald. There are two general sorts of skin, bristly and glabrous skin. The descriptive word cutaneous truly signifies \"of the skin\" . Since it interfaces with the earth, skin assumes an essential insusceptibility part in securing the body against pathogens[3] and over the top water loss. Its different capacities are protection, temperature direction, sensation, blend of vitamin D, and the insurance of vitamin B folates. Extremely harmed skin will attempt to recuperate by framing scar tissue. This is frequently stained and depigmented. In people, skin pigmentation shifts among populaces, and skin sort can go from dry to slick. Such skin assortment gives a rich and various living space for microorganisms that number around 1000 species from 19 phyla, exhibit on the human skin Skin has mesodermal cells, pigmentation, for example, melanin gave by melanocytes, which ingest a portion of the possibly risky bright radiation (UV) in daylight. It additionally contains DNA repair compounds that switch UV harm, with the end goal that individuals without the qualities for these chemicals endure high rates of skin malignancy. One shape prevalently delivered by UV light, threatening melanoma, is especially intrusive, making it spread rapidly, and can frequently be dangerous. Human skin pigmentation shifts among populaces in a striking way. This has prompted to the order of people(s) on the premise of skin color. The skin is the biggest organ in the human body. For the normal grown-up human, the skin has a surface zone of between 1.5-2.0 square meters (16.1-21.5 sq ft.). The thickness of the skin shifts significantly over all parts of the body, and amongst men and ladies and the youthful and the old. A case is the skin on the lower arm which is all things considered 1.3 mm in the male and 1.26 mm in the female. The normal square inch (6.5 cm²) of skin holds 650 sweat organs, 20 veins, 60,000 melanocytes, and more than 1,000 nerve endings. The normal human skin cell is around 30 micrometers in distance across, yet there are variations. A skin cell more often than not extends from 25-40 micrometers (squared), contingent upon an assortment of variables. Skin is made out of three essential layers: the epidermis, the dermis and the hypodermis .Epidermis, \"epi\" originating from the Greek signifying \"over\" or \"upon\", is the peripheral layer of the skin. It shapes the waterproof, defensive wrap over the body\'s surface which likewise serves as a hindrance to disease and is comprised of stratified squamous epithelium with a hidden basal lamina. The epiderm.

SKIN SENSORY ORGANThe human skin is the external covering of the .pdf

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a) Flase In terms of trasing volume it is by far the largest market in the world b) True As home currency weakens, one has to pay more units of home currency to buy one unit of foreign currency, hence making import costlier Solution a) Flase In terms of trasing volume it is by far the largest market in the world b) True As home currency weakens, one has to pay more units of home currency to buy one unit of foreign currency, hence making import costlier.

a) FlaseIn terms of trasing volume it is by far the largest market.pdf

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tested on EclipseRainfall.javaimpo.pdf

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Ques-1: Part-a: Mitosis: it is a somatic cell division in an organism & this division is useful to maintain body growth Part-b: Meiosis: it is the reproductive reduction cell division & it is useful to produce gametes for fertilization finally to generate a mature embryo Part-c: cytokinesis: It is defined as the process of division of cytoplasm during cell division either in mitosis or meiosis & this is useful for carrying cell organelles Part-d: chromosome: it is the hereditary material that carries genomic information for gene expression & useful for inheritance of parental traits to offspring Mitosis ---> somatic cell division & produces two identical daughter cells with equal number of chromosomes (cytokinesis & karyokinesis). Meiosis ----> a reduction division occurs in reproductive germ cells in which allosomes determine sex determination finally generates half of the chromosomes in daughter cells Part-a: Mitosis: it is a somatic cell division in an organism & this division is useful to maintain body growth Part-b: Meiosis: it is the reproductive reduction cell division & it is useful to produce gametes for fertilization finally to generate a mature embryo Part-c: cytokinesis: It is defined as the process of division of cytoplasm during cell division either in mitosis or meiosis & this is useful for carrying cell organelles Part-d: chromosome: it is the hereditary material that carries genomic information for gene expression & useful for inheritance of parental traits to offspring Cell plate is absent during animal cell division instead a complete cleavage of the cells during division can be observed in animal cells. Cell plate formation during cell division observed only in plants. Haploid cells (n) are normally produced by reduction division of meiosis from diploid parent cells (2n). This type of division occurs in germ cells of male and female species. The chromosomes of the diploid germ cell undergo reduction in meiosis I and generate half of the chromosomes when compared to parent diploid cell. Meiosis division in a reproductive cell often results in four haploid cells with only single set of chromosomes. Meiosis-I prophase-I In this process double stranded homologous chromosomes line up each other, and result in forming a tetrad; this is termed as Synapsis. Terminal chaismata hold the homologous chromosomes together in metaphase I finally these are going to align on the metaphase plate. Synapsis allows homologous chromosomes to travel to the center by forming spindle formation through microtubules attaching to the centromeres finally to the opposite poles of the cell. Later, crossing over takes place to exchanges paternal and maternal genes to form tetrad where genetic variation occurs. Crossing over takes place to exchange equal amounts of DNA generates genetic variability in prophase -I of meiosis. Crossing over occurs in which lined up chromosomal ends exchange genetic information by switching their places. Crossing over can un.

Ques-1Part-a Mitosis it is a somatic cell division in an organi.pdf

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Proportional tax is a tax where the rate of tax is fixed. It is a predetermined fixed percentage of one’s income if it is an income tax or it is a fixed percentage of the value of the product if it is a sales tax. It is also called flat tax. It is regressive in application as all the people pay same amount. Hence the people earning less pay a higher percentage of their income and the people paying more pay lesser percentage of their income. Progressive tax is a tax where the rate of taxation increases with the increase in income or value of products. Usually this is done by applying brackets to the income or value of products. For example, people with income from 0 to 20000 fall in one bracket and hence the rate of taxation is the same for the bracket as a whole let’s say 10%. People with income from 20001 to 40000 fall in another bracket and they have a different rate of taxation let’s say 12%.Progressive tax works on the logic of “ability to pay”. Creating value without producing something new is done by exchanging one good or service with other. This is done by estimating the exchange value of the goods or services to be exchanged. The quantified worth of one good or service expressed in terms of the worth of another is known as the exchange value. In the business of foreign exchange, the value of each currency is expressed in terms of value of another currency to be exchanged. This creates and exchange value or exchange rate of one currency to another. A private currency is a currency issued by private organizations. In many countries it is illegal to issue private paper currencies. Such a system (of private currencies) will create a protection against inflation. Once an available instrument or arrangement for investment of present, add- valuing currency could be created, the public would invest in great numbers, because they would want to relieve themselves of the fear of devaluing money. Interest would exist in a pure economy if there is a positive time preference. Time preference is nothing but, the relative valuation placed on a good at an earlier date compared to its valuation at a later date. Interest is thus explained as the propensity of individuals to discount the future. A positive time preference is a necessary and sufficient condition for the existence of Interest in any economy. Static view is when resources are allocated efficiently at a point in time. An example of static efficiency would be whether a firm could produce 2million cars a year more cheaply by using more labor and less capital. Productive and allocative efficiency are static concepts of efficiency, they can be used to discuss whether more could be produced now if resources were allocated in a different way. These concepts can be used for instance, to discuss whether industries dominated by a monopoly producer might produce at lower cost if competition were introduced in the industry. Dynamic view is concerned with how resoures are allocated over a period of tim.

Proportional tax is a tax where the rate of tax is fixed. It is a pr.pdf

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POS system is a networked invironment where a main computer linked t.pdf

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Q) The passage of traits from parents of offspring is called ? A: Heredity Q) A breed of chicken shows co-dominance for feather color. One allele codes for black feathers, another codes for white feathers. The feathers of heterozygous chickens of this breed will be A: Speckled (Because in co-dominance both alleles are equally dominant and shows up as spots) Q) Situation in which one allele of gene is not completely dominant over another allele for that gene are called A: Incomplete dominance Q) In rabbits, there are four different versions of the gene for coat color. What pattern of inheritance is this ? A: Multiple alleles ( As we call each version of the gene as an allele) Q) Variation in human skin color is an example of A: Polygenic traits (there are 3 important genes coding for skin color and we get one of each of those three genes from each of our parents) Q) Which of the following assort independently? A: Chromosomes (During meiosis, the pairs of homologous chromosome are divided in half to form haploid cells. This assortment of homologous chromosomes is random and hence independent) Q) The plants that Gregor Mendel crossed to produce F1 generation made up of the A: P (Also known as parents used for crossing) Q) Due to the process of segregation, alleles separate during the production of A: Gametes (gametes are produced at the end of meiosis and will be haploid in nature) Q) The scientific study of heredity is called A: Genetics Solution Q) The passage of traits from parents of offspring is called ? A: Heredity Q) A breed of chicken shows co-dominance for feather color. One allele codes for black feathers, another codes for white feathers. The feathers of heterozygous chickens of this breed will be A: Speckled (Because in co-dominance both alleles are equally dominant and shows up as spots) Q) Situation in which one allele of gene is not completely dominant over another allele for that gene are called A: Incomplete dominance Q) In rabbits, there are four different versions of the gene for coat color. What pattern of inheritance is this ? A: Multiple alleles ( As we call each version of the gene as an allele) Q) Variation in human skin color is an example of A: Polygenic traits (there are 3 important genes coding for skin color and we get one of each of those three genes from each of our parents) Q) Which of the following assort independently? A: Chromosomes (During meiosis, the pairs of homologous chromosome are divided in half to form haploid cells. This assortment of homologous chromosomes is random and hence independent) Q) The plants that Gregor Mendel crossed to produce F1 generation made up of the A: P (Also known as parents used for crossing) Q) Due to the process of segregation, alleles separate during the production of A: Gametes (gametes are produced at the end of meiosis and will be haploid in nature) Q) The scientific study of heredity is called A: Genetics.

Q) The passage of traits from parents of offspring is called A H.pdf

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Personality Disorders come under the hierarchy of mental disorders alongside Bipolar Disorders or mood disorders, or neurocognitive disorders. This disorder incudes long term thoughts and feelings which result in unhealthy and inconsistent behaviour of a person, also called as maladaptive pattern of behaviour. Personality is defined as a set of thoughts, feelings, personal behaviour and mental traits that distinguish an individual from one another. How people with personality disorders behave? Diagnostic and statistical manual of mental disorders, fifth edition (DSM-5) lists these personality disorders in the same list as other mental disorders. Solution Personality Disorders come under the hierarchy of mental disorders alongside Bipolar Disorders or mood disorders, or neurocognitive disorders. This disorder incudes long term thoughts and feelings which result in unhealthy and inconsistent behaviour of a person, also called as maladaptive pattern of behaviour. Personality is defined as a set of thoughts, feelings, personal behaviour and mental traits that distinguish an individual from one another. How people with personality disorders behave? Diagnostic and statistical manual of mental disorders, fifth edition (DSM-5) lists these personality disorders in the same list as other mental disorders..

Personality Disorders come under the hierarchy of mental disorders a.pdf

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13.D. zygote in animal cells meiosis results in gametes which posses single copy of a chromosome. in fertilization two haploid gametes fuse to produce Zygote. then this zygote undergo several cell division (Mitosis) until it get enough number of cells for differentiation. 14.A.Homologus chromosomes are separated. in meiosis I the chromosome number get reduced. in this stage the first step is formation of synapsis where pairing of two homologous chromosomes occurs, and another major event is crossing over occurs between the homologous chromosomes results in exchange of genetic material. by the end of the meiosis I Homologous chromosomes are separated. 15.A. This statement is true for Mitosis and Meiosis II in the anaphase of the cell cycle both in Mitosis and Meiosis II, the chromatids are separated and migrated to opposite poles.chromatids separation are mediated by Kinetochore micortubules. 16.A.synapsis of chromosome synapsis is the event only observe in the meiosis I, where Pairing of the homologous chromosomes occurs. 17. 18.D.8 unique gametes from AaBbCCDdEE. the formula is 2 number of heterozygotes = there are 3 heterozygotes = 23 =8. so 8 unique gametes are produced form the genotype 19. C.1/2 BbTt × BBtt BBTt Black fur short tail BBtt Black fur long tail BbTt Black fur short tail Bbtt Black fur long tail 20.D.1 short tail - S is dominant over long tail - s heterozygous to tail length - Ss Homozygous short tail mouse - SS SS × Ss SS Short Tail SS Short tail Ss Short tail Ss Short tail 21.D.interphase before both either meiosis or mitosis.BTBtbTbtBt BBTt Black fur short tail BBtt Black fur long tail BbTt Black fur short tail Bbtt Black fur long tail Solution 13.D. zygote in animal cells meiosis results in gametes which posses single copy of a chromosome. in fertilization two haploid gametes fuse to produce Zygote. then this zygote undergo several cell division (Mitosis) until it get enough number of cells for differentiation. 14.A.Homologus chromosomes are separated. in meiosis I the chromosome number get reduced. in this stage the first step is formation of synapsis where pairing of two homologous chromosomes occurs, and another major event is crossing over occurs between the homologous chromosomes results in exchange of genetic material. by the end of the meiosis I Homologous chromosomes are separated. 15.A. This statement is true for Mitosis and Meiosis II in the anaphase of the cell cycle both in Mitosis and Meiosis II, the chromatids are separated and migrated to opposite poles.chromatids separation are mediated by Kinetochore micortubules. 16.A.synapsis of chromosome synapsis is the event only observe in the meiosis I, where Pairing of the homologous chromosomes occurs. 17. 18.D.8 unique gametes from AaBbCCDdEE. the formula is 2 number of heterozygotes = there are 3 heterozygotes = 23 =8. so 8 unique gametes are produced form the genotype 19. C.1/2 BbTt × BBtt BBTt Black fur short tail BBtt Black fur long tail BbTt Black fur short.

13.D. zygotein animal cells meiosis results in gametes which posse.pdf

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Interfacepackage PJ1; public interface SimpleFractionInterface.pdf

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partial pressure = total pressure * mole fraction since partial pressure are equal then P(He) = P(O2) total pressure * mole fraction(He) =total pressure * mole fraction(O2) So mole fraction(He) =mole fraction(O2) Hence they have equal number of moles Solution partial pressure = total pressure * mole fraction since partial pressure are equal then P(He) = P(O2) total pressure * mole fraction(He) =total pressure * mole fraction(O2) So mole fraction(He) =mole fraction(O2) Hence they have equal number of moles.

$partial pressure = total pressure mole fraction.pdf$ $partial pressure = total pressure mole fraction.pdf$

partial pressure = total pressure mole fraction.pdf

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Delta E is the change in internal energy. If the .pdf

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(A) Oxygen gas is an element. It contains a single element O. Compounds and mixtures contain 2 or more elements. (B) Cellulose is a polysaccharide. Sucrose is a disaccharide. Hexose and Glucose are monosaccharides. Solution (A) Oxygen gas is an element. It contains a single element O. Compounds and mixtures contain 2 or more elements. (B) Cellulose is a polysaccharide. Sucrose is a disaccharide. Hexose and Glucose are monosaccharides..

(A) Oxygen gas is an element. It contains a single element O.Compo.pdf

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ans:the given configuration for above elemntfrom perfiodic table is 55 Cs caesium : [Xe] 6s1 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 6s1 The atom ceasium comes under alkali metals.All of the atoms of alkali metals have one electron in their outmost electron shells, hence their only way for achieving the equivalent of filled outmost electron shells is to give up one electron to an element with high electronegativity, They have the lowest ionization potentials in their periods of the periodic table, because the removal of their single electrons from their outmost electron shells gives them the stable electron configuration of inert gases. Another way of stating this is that caesium has high electropositivity(a measure of an element\'s ability to donate electrons). Electro negativity:Electronegativity, is a chemical property that describes the ability of an atom to attract electrons (or electron density) towards itself. so form this we can bserve that we have Caesium which is alkali metal easily donates electrons so we commonly express it as most electropositive element but not a less electronegative element . we also can express it as least electronegative since it is the opposite of most electropositive .since caesium is the most elctropositve element we usually express in that electropositivity only. Solution ans:the given configuration for above elemntfrom perfiodic table is 55 Cs caesium : [Xe] 6s1 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 6s1 The atom ceasium comes under alkali metals.All of the atoms of alkali metals have one electron in their outmost electron shells, hence their only way for achieving the equivalent of filled outmost electron shells is to give up one electron to an element with high electronegativity, They have the lowest ionization potentials in their periods of the periodic table, because the removal of their single electrons from their outmost electron shells gives them the stable electron configuration of inert gases. Another way of stating this is that caesium has high electropositivity(a measure of an element\'s ability to donate electrons). Electro negativity:Electronegativity, is a chemical property that describes the ability of an atom to attract electrons (or electron density) towards itself. so form this we can bserve that we have Caesium which is alkali metal easily donates electrons so we commonly express it as most electropositive element but not a less electronegative element . we also can express it as least electronegative since it is the opposite of most electropositive .since caesium is the most elctropositve element we usually express in that electropositivity only..

ansthe given configuration for above elemntfrom .pdf

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