Two formulas can determine the number of subnets and hosts per subnet: the number of subnets equals 2s, and the number of hosts per subnet equals 2h - 2. These formulas calculate the values based on the number of binary bits used. A custom subnet mask can divide a single network into multiple subnets, with each range having a set number of usable addresses. ANDing the IP address with the custom subnet mask shows which subnet range it belongs to.
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Industrigolv av betong – Svenska Betongföreningens betongrapport nr 13. Presenterat av Johan Silfwerbrand, CBI Betonginstitutet, på Programråd Västs golvseminarium den 11 september i Göteborg.
Lab 18 Answer TemplateProblem 1:
IP address: 192.168.10.0 /27 (given)
a. Subnet Mask: 255.255.255.224
b. Bits Borrowed: 3
c. Number of subnets: 8
d. Magic number: 32
e. Number of valid hosts per subnet: 30
f. (Sub) network address of subnet 0: 192.168.10.0
g. First usable host address in subnet 0: 192.168.10.1
h. Last usable host address in subnet 0: 192.168.10.30
i. Broadcast address in subnet 0: 192.168.10.31
j. (Sub) Network address in subnet 3: 192.168.10.64
k. Last usable host address in subnet 4: 192.168.10.158
Subnet
Subnet address
1st Host address
Last Host address
Broadcast
0
192.168.10.0
192.168.10.1
192.168.10.30
192.168.10.31
1
192.168.10.32
192.168.10.33
192.168.10.62
192.168.10.63
2
192.168.10.64
192.168.10.65
192.168.10.94
192.168.10.95
3
192.168.10.96
192.168.10.97
192.168.10.126
192.168.10.127
4
192.168.10.128
192.168.10.129
192.168.10.158
192.168.10.159
5
192.168.10.160
192.168.10.161
192.168.10.190
192.168.10.191
6
192.168.10.192
192.168.10.193
192.168.10.222
192.168.10.223
7
192.168.10.224
192.168.10.225
192.168.10.254
192.168.10.255Problem 2:
IP address: 192.168.10.0 / 26 (given)
a. Subnet Mask: 255.255.255.192
b. Bits Borrowed:
c. Number of subnets: _4
d. Magic number:
e. Number of valid hosts per subnet: 62
f. (Sub) network address of subnet 0: 192.168.10.0
g. First usable host address in subnet 0: 192.168.10.1
h. Last usable host address in subnet 0: 192.168.10.62
i. Broadcast address in subnet 0: 192.168.10.63
j. (Sub) Network address in subnet 1: 192.168.10.64
k. Last usable host address in subnet 2: 192.168.10.190
Subnet
Subnet address
1st Host address
Last Host address
Broadcast
0
192.168.10.0
192.168.10.1
192.168.10.14
192.168.10.15
1
192.168.10.16
192.168.10.17
192.168.10.30
192.168.10.31
2
192.168.10.32
192.168.10.33
192.168.10.46
192.168.10.47
3
192.168.10.48
192.168.10.49
192.168.10.62
192.168.10.63
Etc.
Problem 3:
IP address: 192.168.10.0 (given)
Subnet Mask: 255.255.255.240
a. Slash prefix: _________________________________________
b. Bits Borrowed: _________________________________________
c. Number of possible subnets: _________________________________________
d. Magic number: _________________________________________
e. Number of usable hosts per subnet: _________________________________________
f. (Sub) network address of subnet 0: _________________________________________
g. First usable host address in subnet 0: _________________________________________
h. Last usable host address in subnet 0: _________________________________________
i. Broadcast address in subnet 0: _________________________________________
j. (Sub) Network address in subnet 1: _________________________________________
k. Last usable host address in subnet 2: _________________________________________
Subnet
Subnet address
1st Host address
Last Host address
Broadcast
0
1
2
3
Etc.
Problem 4:
IP address: 192.168.10.0 (given)
Minimum number of subnets needed: 31
a. Slash prefix: _ ...
Lab 18 Answer TemplateProblem 1:
IP address: 192.168.10.0 /27 (given)
a. Subnet Mask: 255.255.255.224
b. Bits Borrowed: 3
c. Number of subnets: 8
d. Magic number: 32
e. Number of valid hosts per subnet: 30
f. (Sub) network address of subnet 0: 192.168.10.0
g. First usable host address in subnet 0: 192.168.10.1
h. Last usable host address in subnet 0: 192.168.10.30
i. Broadcast address in subnet 0: 192.168.10.31
j. (Sub) Network address in subnet 3: 192.168.10.64
k. Last usable host address in subnet 4: 192.168.10.158
Subnet
Subnet address
1st Host address
Last Host address
Broadcast
0
192.168.10.0
192.168.10.1
192.168.10.30
192.168.10.31
1
192.168.10.32
192.168.10.33
192.168.10.62
192.168.10.63
2
192.168.10.64
192.168.10.65
192.168.10.94
192.168.10.95
3
192.168.10.96
192.168.10.97
192.168.10.126
192.168.10.127
4
192.168.10.128
192.168.10.129
192.168.10.158
192.168.10.159
5
192.168.10.160
192.168.10.161
192.168.10.190
192.168.10.191
6
192.168.10.192
192.168.10.193
192.168.10.222
192.168.10.223
7
192.168.10.224
192.168.10.225
192.168.10.254
192.168.10.255Problem 2:
IP address: 192.168.10.0 / 26 (given)
a. Subnet Mask: 255.255.255.192
b. Bits Borrowed:
c. Number of subnets: _4
d. Magic number:
e. Number of valid hosts per subnet: 62
f. (Sub) network address of subnet 0: 192.168.10.0
g. First usable host address in subnet 0: 192.168.10.1
h. Last usable host address in subnet 0: 192.168.10.62
i. Broadcast address in subnet 0: 192.168.10.63
j. (Sub) Network address in subnet 1: 192.168.10.64
k. Last usable host address in subnet 2: 192.168.10.190
Subnet
Subnet address
1st Host address
Last Host address
Broadcast
0
192.168.10.0
192.168.10.1
192.168.10.14
192.168.10.15
1
192.168.10.16
192.168.10.17
192.168.10.30
192.168.10.31
2
192.168.10.32
192.168.10.33
192.168.10.46
192.168.10.47
3
192.168.10.48
192.168.10.49
192.168.10.62
192.168.10.63
Etc.
Problem 3:
IP address: 192.168.10.0 (given)
Subnet Mask: 255.255.255.240
a. Slash prefix: _________________________________________
b. Bits Borrowed: _________________________________________
c. Number of possible subnets: _________________________________________
d. Magic number: _________________________________________
e. Number of usable hosts per subnet: _________________________________________
f. (Sub) network address of subnet 0: _________________________________________
g. First usable host address in subnet 0: _________________________________________
h. Last usable host address in subnet 0: _________________________________________
i. Broadcast address in subnet 0: _________________________________________
j. (Sub) Network address in subnet 1: _________________________________________
k. Last usable host address in subnet 2: _________________________________________
Subnet
Subnet address
1st Host address
Last Host address
Broadcast
0
1
2
3
Etc.
Problem 4:
IP address: 192.168.10.0 (given)
Minimum number of subnets needed: 31
a. Slash prefix: _ ...
This study guide is intended to provide those pursuing the CCNA certification with a framework of what concepts need to be studied. This is not a comprehensive document containing all the secrets of the CCNP nor is it a “braindump” of questions and answers.
I sincerely hope that this document provides some assistance and clarity in your studies.
The Department of Labor National Information, Security, and Geospatial Technology Consortium (NISGTC) Trade Adjustment Assistance Community College Career and Training (TAACCCT) Grant provides RVC with the funds to expand and improve core curriculum as well as prepare students for employment in high-wage, high-skill occupations.
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Let me take this questions and provide you a short journey through existing deployment models and use cases for AI software. On practical examples, we discuss what cloud/on-premise strategy we may need for applying it to our own infrastructure to get it to work from an enterprise perspective. I want to give an overview about infrastructure requirements and technologies, what could be beneficial or limiting your AI use cases in an enterprise environment. An interactive Demo will give you some insides, what approaches I got already working for real.
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The IoT and OT threat landscape report has been prepared by the Threat Research Team at Sectrio using data from Sectrio, cyber threat intelligence farming facilities spread across over 85 cities around the world. In addition, Sectrio also runs AI-based advanced threat and payload engagement facilities that serve as sinks to attract and engage sophisticated threat actors, and newer malware including new variants and latent threats that are at an earlier stage of development.
The latest edition of the OT/ICS and IoT security Threat Landscape Report 2024 also covers:
State of global ICS asset and network exposure
Sectoral targets and attacks as well as the cost of ransom
Global APT activity, AI usage, actor and tactic profiles, and implications
Rise in volumes of AI-powered cyberattacks
Major cyber events in 2024
Malware and malicious payload trends
Cyberattack types and targets
Vulnerability exploit attempts on CVEs
Attacks on counties – USA
Expansion of bot farms – how, where, and why
In-depth analysis of the cyber threat landscape across North America, South America, Europe, APAC, and the Middle East
Why are attacks on smart factories rising?
Cyber risk predictions
Axis of attacks – Europe
Systemic attacks in the Middle East
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https://sectrio.com/resources/ot-threat-landscape-reports/sectrio-releases-ot-ics-and-iot-security-threat-landscape-report-2024/
LF Energy Webinar: Electrical Grid Modelling and Simulation Through PowSyBl -...DanBrown980551
Do you want to learn how to model and simulate an electrical network from scratch in under an hour?
Then welcome to this PowSyBl workshop, hosted by Rte, the French Transmission System Operator (TSO)!
During the webinar, you will discover the PowSyBl ecosystem as well as handle and study an electrical network through an interactive Python notebook.
PowSyBl is an open source project hosted by LF Energy, which offers a comprehensive set of features for electrical grid modelling and simulation. Among other advanced features, PowSyBl provides:
- A fully editable and extendable library for grid component modelling;
- Visualization tools to display your network;
- Grid simulation tools, such as power flows, security analyses (with or without remedial actions) and sensitivity analyses;
The framework is mostly written in Java, with a Python binding so that Python developers can access PowSyBl functionalities as well.
What you will learn during the webinar:
- For beginners: discover PowSyBl's functionalities through a quick general presentation and the notebook, without needing any expert coding skills;
- For advanced developers: master the skills to efficiently apply PowSyBl functionalities to your real-world scenarios.
JMeter webinar - integration with InfluxDB and GrafanaRTTS
Watch this recorded webinar about real-time monitoring of application performance. See how to integrate Apache JMeter, the open-source leader in performance testing, with InfluxDB, the open-source time-series database, and Grafana, the open-source analytics and visualization application.
In this webinar, we will review the benefits of leveraging InfluxDB and Grafana when executing load tests and demonstrate how these tools are used to visualize performance metrics.
Length: 30 minutes
Session Overview
-------------------------------------------
During this webinar, we will cover the following topics while demonstrating the integrations of JMeter, InfluxDB and Grafana:
- What out-of-the-box solutions are available for real-time monitoring JMeter tests?
- What are the benefits of integrating InfluxDB and Grafana into the load testing stack?
- Which features are provided by Grafana?
- Demonstration of InfluxDB and Grafana using a practice web application
To view the webinar recording, go to:
https://www.rttsweb.com/jmeter-integration-webinar
Let's dive deeper into the world of ODC! Ricardo Alves (OutSystems) will join us to tell all about the new Data Fabric. After that, Sezen de Bruijn (OutSystems) will get into the details on how to best design a sturdy architecture within ODC.
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Here is something new! In our next Connector Corner webinar, we will demonstrate how you can use a single workflow to:
Create a campaign using Mailchimp with merge tags/fields
Send an interactive Slack channel message (using buttons)
Have the message received by managers and peers along with a test email for review
But there’s more:
In a second workflow supporting the same use case, you’ll see:
Your campaign sent to target colleagues for approval
If the “Approve” button is clicked, a Jira/Zendesk ticket is created for the marketing design team
But—if the “Reject” button is pushed, colleagues will be alerted via Slack message
Join us to learn more about this new, human-in-the-loop capability, brought to you by Integration Service connectors.
And...
Speakers:
Akshay Agnihotri, Product Manager
Charlie Greenberg, Host
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The publishing industry has been selling digital audiobooks and ebooks for over a decade and has found its groove. What’s changed? What has stayed the same? Where do we go from here? Join a group of leading sales peers from across the industry for a conversation about the lessons learned since the popularization of digital books, best practices, digital book supply chain management, and more.
Link to video recording: https://bnctechforum.ca/sessions/selling-digital-books-in-2024-insights-from-industry-leaders/
Presented by BookNet Canada on May 28, 2024, with support from the Department of Canadian Heritage.
Neuro-symbolic is not enough, we need neuro-*semantic*Frank van Harmelen
Neuro-symbolic (NeSy) AI is on the rise. However, simply machine learning on just any symbolic structure is not sufficient to really harvest the gains of NeSy. These will only be gained when the symbolic structures have an actual semantics. I give an operational definition of semantics as “predictable inference”.
All of this illustrated with link prediction over knowledge graphs, but the argument is general.
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https://arxiv.org/abs/2306.08302
2. Microsoft Research's GraphRAG paper and a review paper on various uses of knowledge graphs:
https://www.microsoft.com/en-us/research/blog/graphrag-unlocking-llm-discovery-on-narrative-private-data/
Unsubscribed: Combat Subscription Fatigue With a Membership Mentality by Head...
Subnetting Principles
1. How to determine the number of subnets and the
number of hosts per subnet
Two formulas can provide this basic information:
Number of subnets = 2 s (Second subnet formula: Number of subnets = 2s - 2)
Number of hosts per subnet = 2 h - 2
Both formulas calculate the number of hosts or subnets based on the number of binary bits
used. For example if you borrow three bits from the host portion of the address use the
number of subnets formula to determine the total number of subnets gained by borrowing the
three bits. This would be 23 or 2 x 2 x 2 = 8 subnets
To determine the number of hosts per subnet you would take the number of binary bits used in
the host portion and apply this to the number of hosts per subnet formula If five bits are in the
host portion of the address this would be 2 5 or 2 x 2 x 2 x 2 x 2 = 32 hosts.
When dealing with the number of hosts per subnet you have to subtract two addresses from
the range. The first address in every range is the subnet number. The last address in every
range is the broadcast address. These two addresses cannot be assigned to any device in
the network which is why you have to subtract two addresses to find the number of usable
addresses in each range.
For example if two bits are borrowed for the network portion of the address you can easily
determine the number of subnets and hosts per subnets using the two formulas.
195. 223 . 50 . 0 0 0 0 0 0 0 0
The number of subnets The number of hosts created by
created by borrowing 2 leaving 6 bits is 26 - 2 or
bits is 2 2 or 2 x 2 = 4 2 x 2 x 2 x 2 x 2 x 2 = 64 - 2 = 62
subnets. usable hosts per subnet.
What about that second subnet formula:
s
Number of subnets = 2 - 2
In some instances the first and last subnet range of addresses are reserved. This is similar to
the first and last host addresses in each range of addreses.
The first range of addresses is the zero subnet. The subnet number for the zero subnet is
also the subnet number for the classful subnet address.
The last range of addresses is the broadcast subnet. The broadcast address for the last
subnet in the broadcast subnet is the same as the classful broadcast address.
10
2. Class C Address unsubnetted:
195. 223 . 50 . 0
195.223.50.0 to 195.223.50.255
Notice that the subnet and
broadcast addresses match.
Class C Address subnetted (2 bits borrowed):
195. 223 . 50 . 0 0 0 0 0 0 0 0
(Invalid range) (0) 195.223.50.0 to 195.223.50.63
(1) 195.223.50.64 to 195.223.50.127
(2) 195.223.50.128 to 195.223.50.191
(Invalid range) (3) 195.223.50.192 to 195.223.50.255
The primary reason the the zero and broadcast subnets were not used had to do pirmarily with
the broadcast addresses. If you send a broadcast to 195.223.255 are you sending it to all 255
addresses in the classful C address or just the 62 usable addresses in the broadcast range?
The CCNA and CCENT certification exams may have questions which will require you to
determine which formula to use, and whehter or not you can use the first and last subnets. Use
the chart below to help decide.
When to use which formula to determine the number of subnets
s s
Use the 2 - 2 formula and don’t use the Use the 2 formula and use the zero and
zero and broadcast ranges if... broadcast ranges if...
Classful routing is used Classless routing or VLSM is used
RIP version 1 is used RIP version 2, EIGRP, or OSPF is used
The no ip subnet zero command is The ip subnet zero command is
configured on your router configured on your router (default setting)
No other clues are given
Bottom line for the CCNA exams; if a question does not give you any clues as to whether or not
to allow these two subnets, assume you can use them.
s
This workbook has you use the number of subnets = 2 formula.
11
3. ANDING With
Custom subnet masks
When you take a single network such as 192.100.10.0 and divide it into five smaller networks
(192.100.10.16, 192.100.10.32, 192.100.10.48, 192.100.10.64, 192.100.10.80) the outside
world still sees the network as 192.100.10.0, but the internal computers and routers see five
smaller subnetworks. Each independent of the other. This can only be accomplished by using
a custom subnet mask. A custom subnet mask borrows bits from the host portion of the
address to create a subnetwork address between the network and host portions of an IP
address. In this example each range has 14 usable addresses in it. The computer must still
AND the IP address against the custom subnet mask to see what the network portion is and
which subnetwork it belongs to.
IP Address: 192 . 100 . 10 . 0
Custom Subnet Mask: 255.255.255.240
Address Ranges: 192.10.10.0 to 192.100.10.15
192.100.10.16 to 192.100.10.31
192.100.10.32 to 192.100.10.47 (Range in the sample below)
192.100.10.48 to 192.100.10.63
192.100.10.64 to 192.100.10.79
192.100.10.80 to 192.100.10.95
192.100.10.96 to 192.100.10.111
192.100.10.112 to 192.100.10.127
192.100.10.128 to 192.100.10.143
192.100.10.144 to 192.100.10.159
192.100.10.160 to 192.100.10.175
192.100.10.176 to 192.100.10.191
192.100.10.192 to 192.100.10.207
192.100.10.208 to 192.100.10.223
192.100.10.224 to 192.100.10.239
192.100.10.240 to 192.100.10.255
Sub
Network Network Host
IP Address: 1 1 0 0 0 0 0 0 . 0 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 1 (192 . 100 . 10 . 33)
Custom Subnet Mask: 1 1 1 1 1 1 1 1 . 0 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 1 1 1 1 0 0 0 0 (255 . 255 . 255 . 240)
AND: 1 1 0 0 0 0 0 0 . 0 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 0 (192 . 100 . 10 . 32)
Four bits borrowed from the host
portion of the address for the
custom subnet mask.
The ANDING process of the four borrowed bits
shows which range of IP addresses this
particular address will fall into.
In the next set of problems you will determine the necessary information to determine the
correct subnet mask for a variety of IP addresses.
9
4. Produced by: Robb Jones
jonesr@careertech.net
Frederick County Career & Technology Center
Cisco Networking Academy
Frederick County Public Schools
Frederick, Maryland, USA