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ST THOMAS TRAINING COLLEGE, MUKKOLAKKAL 
SELF DESIGNED INNOVATIVE LESSON 
1 
Prepared by 
NISHA .B 
Reg. No. 13386004 
MATHEMATHICS
SELF DESIGNED INNOVATIVE LESSON 
Name of the teacher: NISHA .B standard: VIII 
Name of the school : ST. MARY’S H.S.S PATTOM Division : S 
Subject : MATHEMATICS Strength: 50 
Unit : Ratio and Proportion Date : 23/7/2014 
Subunit : Problems on Ratio Duration: 45 minutes 
CURRICULAR STATEMENT 
To workout problems on Ratios. 
CONTENT ANALYSIS 
TERMS: Ratio, Fractional forms, Triangle, Three measures. 
FACTS: . A method to compare two quantities of the same kind with same unit in termed as ratio. 
. Ratios can be written in terms of the smallest possible numbers after removing any common 
2 
factors. 
CONCEPT: Concept of the relation between two numbers and related problems 
PROCESS: Process of teaching and learning the relation of parts. 
PROCESS SKILLS: Observing, Inferring, Classifying, and Calculating.
LEARNING OUTCOMES 
3 
The pupil: 
I. remembers above facts, concept etc. related to the problems on Ratio. 
II. develops understanding above facts, concept etc. related to the problems on Ratios. 
III. applies above facts concepts etc. in new and relevant situations. 
IV. discriminates the above facts, concept etc related to the problems on Ratio. 
V. detects the above facts, concept etc related to the problems on Ratios. 
VI. designs new idea related to calculating the problems on Ratios. 
VII. develops skill related to solving the problems on Ratio. 
VIII. creates interest in solving the different types of problems on Ratios. 
PRE REQUISITES: Identification of the problems, calculating the Problems. 
LEARNING AIDS: Ordinary classroom equipments, Charts. 
LEARNING STRATEGIES: Group discussion , Group activity method. 
INTERACTION PROCEDURE PUPIL’S RESPONSES 
Introduction 
Teacher: How many sides are there in a triangle? 
Teacher draws a triangle, then teacher asks the students 
can you find the ratio of each sides of the 
triangle? 
A triangle has 3 sides .
INTERACTION PROCEDURE 
6 c m 5cm 
4 
8 cm 
Teacher: today we are going to find the ratios of three 
measures. 
Teacher shows a chart with magic circle in which 3 
Different Colors of beads were pasted. 
Then teacher gives the ratios of each color. Colors are 
Yellow, black and green. 
chart 
PUPIL’S RESPONSES 
No responses. 
Students keenly 
observe
INTERACTION PROCEDURE 
The ratio of black, Yellow and Green beads are in 
5 
3:2:1.The total no. of beads is 30. 
Teacher asks the students , can you find the no. of each 
color of beads without counting 
First, we find the sum of ratio. 
What is the sum of ratio? 
Then what is fraction of black beads? 
Yellow beads = 
Green beads = 
There for , no. of black beads =30*3/6 = 15 
No. of yellow beads = 
No. of green beads = 
Then teacher calls a student for counting the 
no. of beads in the circle. 
Teacher: The above answers and counted beads are in 
same number. Then teacher shows another chart and 
then asks the students to find the ratio of the beads. 
PUPIL’S RESPONSES 
No response 
6 
3/6 
2/6 
1/6 
30*2/6= 10 
30*1/6 = 5 
Students actively 
Participate
INTERACTION PROCEDURE 
The chart in which a beautiful circle with different 
6 
colour of beads. 
CHART 
THREE MEASURES 
Then teacher gives the no. of green beads is 20. 
No. of blue beads is 10.No. of black beads is 15. 
Then teacher asks the students to find the ratio of black, 
green and blue beads. Teacher can you find the total no. of beads 
in this circle? 
PUPIL’S RESPONSES 
Students 
observe the 
chart 
Yes it has 45 beads.
7 
What the fraction of green beads = 
Fraction of black beads = 
Fraction of the blue beads = 
So the number of beads is 45. 
The ratio of black, green and blue = 
ACTIVITY 1 
Teacher gives question of introductory part. 
6cm 5cm 
8cm 
What is the ratio of the sides of the triangle? 
ACTIVITY 2 
3.5cm 2.5cm 
4cm 
Find the ratio the sides of the triangle? 
20/45 
15/45 
10/45 
10:20:15 
Fractional forms 
are 
6/19,5/19,8/19 
Ratio = 6:5:8 
Fractional forms are 
3.5/10 = 35/10 = 7/20 
25/100=1/4 = 5/20 
4/10 = 8/20 
Ratio = 7:5:8
INTERACTION PROCEDURE 
8 
ACTIVITY 3 
Give a circle with 3 colors of dotes. Find the no. of different colors. 
The ratio of the red violet and Yellow dotes is 3:2:4. 
CLASS ASSIGNMENT 
Ali put up 40,000 rupees Jose 20,000 rupees and John 
50,000 rupees. To start an agency .What is the ratio of their investment? 
PUPIL’S RESPONSES 
Ratio of the dotes 
= 3:2:4 
Sum of ratio =9 
No. of red dotes 
= 4/9*27 
=12 
No. of violet dotes 
= 2/9*27 
=6 
No. of yellow dotes 
= 3/9*27 
=9
9 
INTERACTION PROCEDURE 
FOLLOW UP ACTIVITY 
HOME ASSIGNMENT 
In a contest, the first gets 1000 rupees as prize, 
the second gets 600 rupees and third 400 rupees . 
What is the ratio of prize Money? 
ENRICHMENT ACTIVITY 
The perimeter of a triangle is 60cm and its sides are in the 
ratio 4:5:6. What are length of sides? 
PUPIL’S RESPONSES

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Self designed innovative lesson

  • 1. ST THOMAS TRAINING COLLEGE, MUKKOLAKKAL SELF DESIGNED INNOVATIVE LESSON 1 Prepared by NISHA .B Reg. No. 13386004 MATHEMATHICS
  • 2. SELF DESIGNED INNOVATIVE LESSON Name of the teacher: NISHA .B standard: VIII Name of the school : ST. MARY’S H.S.S PATTOM Division : S Subject : MATHEMATICS Strength: 50 Unit : Ratio and Proportion Date : 23/7/2014 Subunit : Problems on Ratio Duration: 45 minutes CURRICULAR STATEMENT To workout problems on Ratios. CONTENT ANALYSIS TERMS: Ratio, Fractional forms, Triangle, Three measures. FACTS: . A method to compare two quantities of the same kind with same unit in termed as ratio. . Ratios can be written in terms of the smallest possible numbers after removing any common 2 factors. CONCEPT: Concept of the relation between two numbers and related problems PROCESS: Process of teaching and learning the relation of parts. PROCESS SKILLS: Observing, Inferring, Classifying, and Calculating.
  • 3. LEARNING OUTCOMES 3 The pupil: I. remembers above facts, concept etc. related to the problems on Ratio. II. develops understanding above facts, concept etc. related to the problems on Ratios. III. applies above facts concepts etc. in new and relevant situations. IV. discriminates the above facts, concept etc related to the problems on Ratio. V. detects the above facts, concept etc related to the problems on Ratios. VI. designs new idea related to calculating the problems on Ratios. VII. develops skill related to solving the problems on Ratio. VIII. creates interest in solving the different types of problems on Ratios. PRE REQUISITES: Identification of the problems, calculating the Problems. LEARNING AIDS: Ordinary classroom equipments, Charts. LEARNING STRATEGIES: Group discussion , Group activity method. INTERACTION PROCEDURE PUPIL’S RESPONSES Introduction Teacher: How many sides are there in a triangle? Teacher draws a triangle, then teacher asks the students can you find the ratio of each sides of the triangle? A triangle has 3 sides .
  • 4. INTERACTION PROCEDURE 6 c m 5cm 4 8 cm Teacher: today we are going to find the ratios of three measures. Teacher shows a chart with magic circle in which 3 Different Colors of beads were pasted. Then teacher gives the ratios of each color. Colors are Yellow, black and green. chart PUPIL’S RESPONSES No responses. Students keenly observe
  • 5. INTERACTION PROCEDURE The ratio of black, Yellow and Green beads are in 5 3:2:1.The total no. of beads is 30. Teacher asks the students , can you find the no. of each color of beads without counting First, we find the sum of ratio. What is the sum of ratio? Then what is fraction of black beads? Yellow beads = Green beads = There for , no. of black beads =30*3/6 = 15 No. of yellow beads = No. of green beads = Then teacher calls a student for counting the no. of beads in the circle. Teacher: The above answers and counted beads are in same number. Then teacher shows another chart and then asks the students to find the ratio of the beads. PUPIL’S RESPONSES No response 6 3/6 2/6 1/6 30*2/6= 10 30*1/6 = 5 Students actively Participate
  • 6. INTERACTION PROCEDURE The chart in which a beautiful circle with different 6 colour of beads. CHART THREE MEASURES Then teacher gives the no. of green beads is 20. No. of blue beads is 10.No. of black beads is 15. Then teacher asks the students to find the ratio of black, green and blue beads. Teacher can you find the total no. of beads in this circle? PUPIL’S RESPONSES Students observe the chart Yes it has 45 beads.
  • 7. 7 What the fraction of green beads = Fraction of black beads = Fraction of the blue beads = So the number of beads is 45. The ratio of black, green and blue = ACTIVITY 1 Teacher gives question of introductory part. 6cm 5cm 8cm What is the ratio of the sides of the triangle? ACTIVITY 2 3.5cm 2.5cm 4cm Find the ratio the sides of the triangle? 20/45 15/45 10/45 10:20:15 Fractional forms are 6/19,5/19,8/19 Ratio = 6:5:8 Fractional forms are 3.5/10 = 35/10 = 7/20 25/100=1/4 = 5/20 4/10 = 8/20 Ratio = 7:5:8
  • 8. INTERACTION PROCEDURE 8 ACTIVITY 3 Give a circle with 3 colors of dotes. Find the no. of different colors. The ratio of the red violet and Yellow dotes is 3:2:4. CLASS ASSIGNMENT Ali put up 40,000 rupees Jose 20,000 rupees and John 50,000 rupees. To start an agency .What is the ratio of their investment? PUPIL’S RESPONSES Ratio of the dotes = 3:2:4 Sum of ratio =9 No. of red dotes = 4/9*27 =12 No. of violet dotes = 2/9*27 =6 No. of yellow dotes = 3/9*27 =9
  • 9. 9 INTERACTION PROCEDURE FOLLOW UP ACTIVITY HOME ASSIGNMENT In a contest, the first gets 1000 rupees as prize, the second gets 600 rupees and third 400 rupees . What is the ratio of prize Money? ENRICHMENT ACTIVITY The perimeter of a triangle is 60cm and its sides are in the ratio 4:5:6. What are length of sides? PUPIL’S RESPONSES