Mechanical Properties of Dental MaterialsHemavathi N
Mechanical properties are defined by the laws of mechanics i.e. the physical science dealing with forces that act on bodies and the resultant motion, deformation, or stresses that those bodies experiences.
Mechanical properties are usually expressed in units of stress and/or strain.
Mechanical Properties of Dental MaterialsHemavathi N
Mechanical properties are defined by the laws of mechanics i.e. the physical science dealing with forces that act on bodies and the resultant motion, deformation, or stresses that those bodies experiences.
Mechanical properties are usually expressed in units of stress and/or strain.
Strength of Materials Lecture - 2
Elastic stress and strain of materials (stress-strain diagram)
Mehran University of Engineering and Technology.
Department of Mechanical Engineering.
Student information management system project report ii.pdfKamal Acharya
Our project explains about the student management. This project mainly explains the various actions related to student details. This project shows some ease in adding, editing and deleting the student details. It also provides a less time consuming process for viewing, adding, editing and deleting the marks of the students.
Strength of Materials Lecture - 2
Elastic stress and strain of materials (stress-strain diagram)
Mehran University of Engineering and Technology.
Department of Mechanical Engineering.
Student information management system project report ii.pdfKamal Acharya
Our project explains about the student management. This project mainly explains the various actions related to student details. This project shows some ease in adding, editing and deleting the student details. It also provides a less time consuming process for viewing, adding, editing and deleting the marks of the students.
HEAP SORT ILLUSTRATED WITH HEAPIFY, BUILD HEAP FOR DYNAMIC ARRAYS.
Heap sort is a comparison-based sorting technique based on Binary Heap data structure. It is similar to the selection sort where we first find the minimum element and place the minimum element at the beginning. Repeat the same process for the remaining elements.
Industrial Training at Shahjalal Fertilizer Company Limited (SFCL)MdTanvirMahtab2
This presentation is about the working procedure of Shahjalal Fertilizer Company Limited (SFCL). A Govt. owned Company of Bangladesh Chemical Industries Corporation under Ministry of Industries.
Immunizing Image Classifiers Against Localized Adversary Attacksgerogepatton
This paper addresses the vulnerability of deep learning models, particularly convolutional neural networks
(CNN)s, to adversarial attacks and presents a proactive training technique designed to counter them. We
introduce a novel volumization algorithm, which transforms 2D images into 3D volumetric representations.
When combined with 3D convolution and deep curriculum learning optimization (CLO), itsignificantly improves
the immunity of models against localized universal attacks by up to 40%. We evaluate our proposed approach
using contemporary CNN architectures and the modified Canadian Institute for Advanced Research (CIFAR-10
and CIFAR-100) and ImageNet Large Scale Visual Recognition Challenge (ILSVRC12) datasets, showcasing
accuracy improvements over previous techniques. The results indicate that the combination of the volumetric
input and curriculum learning holds significant promise for mitigating adversarial attacks without necessitating
adversary training.
Using recycled concrete aggregates (RCA) for pavements is crucial to achieving sustainability. Implementing RCA for new pavement can minimize carbon footprint, conserve natural resources, reduce harmful emissions, and lower life cycle costs. Compared to natural aggregate (NA), RCA pavement has fewer comprehensive studies and sustainability assessments.
NUMERICAL SIMULATIONS OF HEAT AND MASS TRANSFER IN CONDENSING HEAT EXCHANGERS...ssuser7dcef0
Power plants release a large amount of water vapor into the
atmosphere through the stack. The flue gas can be a potential
source for obtaining much needed cooling water for a power
plant. If a power plant could recover and reuse a portion of this
moisture, it could reduce its total cooling water intake
requirement. One of the most practical way to recover water
from flue gas is to use a condensing heat exchanger. The power
plant could also recover latent heat due to condensation as well
as sensible heat due to lowering the flue gas exit temperature.
Additionally, harmful acids released from the stack can be
reduced in a condensing heat exchanger by acid condensation. reduced in a condensing heat exchanger by acid condensation.
Condensation of vapors in flue gas is a complicated
phenomenon since heat and mass transfer of water vapor and
various acids simultaneously occur in the presence of noncondensable
gases such as nitrogen and oxygen. Design of a
condenser depends on the knowledge and understanding of the
heat and mass transfer processes. A computer program for
numerical simulations of water (H2O) and sulfuric acid (H2SO4)
condensation in a flue gas condensing heat exchanger was
developed using MATLAB. Governing equations based on
mass and energy balances for the system were derived to
predict variables such as flue gas exit temperature, cooling
water outlet temperature, mole fraction and condensation rates
of water and sulfuric acid vapors. The equations were solved
using an iterative solution technique with calculations of heat
and mass transfer coefficients and physical properties.
6th International Conference on Machine Learning & Applications (CMLA 2024)ClaraZara1
6th International Conference on Machine Learning & Applications (CMLA 2024) will provide an excellent international forum for sharing knowledge and results in theory, methodology and applications of on Machine Learning & Applications.
We have compiled the most important slides from each speaker's presentation. This year’s compilation, available for free, captures the key insights and contributions shared during the DfMAy 2024 conference.
6. • For the simplest case of normal stress analysis, consider a rod
with uniform crosssectional area subjected to axial loading.
• If we pull on the rod in its longitudinal direction, it will experience
tension and the length of the rod will increase .
• The internal stress in the rod is exposed if we make an imaginary
cut through the rod at a section. At any chosen cross section, a
continuously distributed force is found acting over the entire area
of the section.
• The intensity of this force is called the stress. If the stress acts in a
direction perpendicular to the cross section, it is called a normal
stress. The normal stress, commonly denoted as is defined as the
force applied on a given area (A),
8. • A normal stress can be tensile (as in the case
of pulling along the rod) or compressive (as in
the case of pushing along the rod). The
polarity of normal stress can also be
determined by isolating an infinitesimally
small volume inside the bar. If the volume is
pulled in one particular axis, the stress is
tensile; if the volume is pushed, the stress is
compressive
9. • The unit elongation of the rod represents the
strain. In this case, it is called normal strain
since the direction of the strain is
perpendicular to the cross section of the
beam. Suppose the steel bar has an original
length denoted Under a given normal stress
the rod is extended to a length of L. The
resultant strain in the bar is defined as
10.
11. • In reality, the applied longitudinal stress
along the x-axis not only produces a
longitudinal elongation in the direction of the
stress, but a reduction of cross-sectional area
as well
12.
13. • The relative dimensional change in the y and
z directions can be expressed as and This
general material characteristic is captured by
a term called the Poisson’s ratio, which is
defined as the ratio between transverse and
longitudinal elongations:
14.
15. • Stress and strain are closely related. Under
small deformation, the stress and the strain
terms are proportional to each other
according to the Hooke’s law, i.e.,
16. • The proportion constant, E, is called the
modulus of elasticity
17. • The modulus of elasticity, often called the
Young’s modulus, is an intrinsic property of a
material. It is a constant for a given material,
irrespective of the shape and dimensions of the
mechanical element. Atoms are held together
with atomic forces. If one imagines inter-atomic
force acting as springs to provide restoring force
when atoms are pulled apart or pushed
together, the modulus of elasticity is the
measure of the stiffness of the inter-atomic
spring near the equilibrium point
18. • Shear stresses can be developed under
different force loading conditions. One of the
simplest ways to generate a pure shear
loading is with a pair of forces acting on
opposite faces of a cube. In this case, the
magnitude of the shear stress is defined as
19.
20. • The unit of is Shear stress has no tendency to
elongate or shorten the element in the x, y,
and z directions. Instead, the shear stresses
produce a change in the shape of the element.
21.
22. • The shear stress is unit less; in fact, it
represents the angular displacement
expressed in the unit of radians. The shear
stress and strain are also related to each
other by a proportional constant, called the
shear modulus of elasticity, G. The expression
of G is simply the ratio of and r
23.
24. General Scalar Relation Between
Tensile Stress and Strain
• In order to determine the stress–strain
relation, a tensile test is commonly used. A
rod with precise dimensions, calibrated
crystalline orientation and smooth surface
finish is subjected to a tension force applied in
the longitudinal direction. The amount of
relative displacement and the applied stress
are plotted on a stress-strain curve until the
beam breaks
25. • At low levels of applied stress and strain, the
stress value increases proportionally with
respect to the developed strain, with the
proportional constant being the Young’s
modulus. This segment of the stress-strain
curve is called the elastic deformation regime.
If the stress is removed, the material will
return to its original shape. This force loading
can be repeated for many times.
26. • As the stress exceeds a certain level, the
material enters the plastic deformation regime.
In this regime, the amount of stress and strain
does not follow a linear relationship anymore.
Furthermore, deformation cannot be fully
recovered after the external loading is removed.
Bend a metal paper clip wire slightly, it will
always return to its original shape. If the wire is
bent beyond a certain angle, the clip will never
return to original shapes again. Plastic
deformation is said to have occurred.
27. • The stress-strain curve has two noticeable
points—yield point and fracture point. Before the
yield point is reached, the material remains
elastic. Between the yield point and the fracture
point, the specimen undergoes plastic
deformation. At the fracture point, the specimen
suffers from irreversible failure. The y-coordinate
of the yield point is the yield strength of the
material. The y-coordinate of the fracture point is
designated the ultimate strength (or the fracture
strength) of the material.
28.
29. • However, not all materials exhibit this generic
stress–strain relationship. Some
representative curves for different classes of
materials , including brittle materials (such as
silicon) and soft rubber, both are used
extensively in MEMS.
30.
31. • There are several common qualitative phrases used to
describe materials—strong, ductile, resilient, and
tough. These terms can be explained much more
clearly by relating to the stress strain curves. A material
is strong if it has high yield strength or ultimate
strength. By this account, silicon is even stronger than
stainless steel. Ductility is an important mechanical
property. It is a measure of the degree of plastic
deformation that has been sustained at the point of
fracture. A material that experiences very little or no
plastic deformation upon fracture is termed brittle.
32. • Silicon is a brittle material, which fails in tension with only
little elongation after the proportional limit is exceeded.
Ductility may be expressed quantitatively as either percent
elongation or percent reduction in area. Toughness is a
mechanical measure of the ability of a material to absorb
energy up to fracture. For a static situation, toughness may
be ascertained from the result of the tensile stress-strain
test. It is the area under the stress-strain curve up to the
point of fracture. For a material to be tough, it must display
both strength and ductility. Resilience is the capacity of a
material to absorb energy when it is deformed elastically
and then, upon unloading, to have this energy recovered.
33. General stress strain relations
• To visualize vector components of stress and
strain, let us isolate a unit cube from inside a
material and consider stress components
acting on it. The cube is placed in a
rectangular coordinate system with axes
marked as x, y, and z. For reasons of
convenience that will become apparent later,
the axes and z are also labeled as axes 1, 2,
and 3, respectively
34. • A cube has six faces. Consequently, there are 12 possible
shear force components—two for each face. These are not
all independent. For example, each pair of shear stress
components acting on parallel faces but along the same
axis have equal magnitude and opposite directions for force
balance (Newton’s first law). This reduces the number of
independent shear stress components to six.These six shear
stress components are graphically illustrated in Figure 3.13.
Each component is identified by two subscript letters. The
first letter in the subscript indicates the normal direction of
the facet on which the stress is applied to, while the second
letter indicates the direction of the stress component
35. • Based on torque balance, two shear stress
components acting on two facets but pointing
towards a common edge have the same
magnitude. Specifically, and In other words,
equal shear stresses always exist on mutually
perpendicular planes. The independent
number of shear stress components is
reduced to three
36.
37. • There are six possible normal stress
components—one for each face of a cube.
Under equilibrium conditions, the normal
stress components acting on opposite facets
must have the same magnitude and point to
opposite directions. Therefore, there are three
independent normal stress components .
Normal stress components are labeled with
two subscript letters.
38. • Overall, in a rectangular coordinate system
under motion equilibrium, there are three
independent normal stresses and three shear
ones. It is quite tedious to write down two
subscripts for each component. The notations
of the six independent components can be
further simplified by using the scheme below: