Relation between radian and degrees
by
SBR
www.harekrishnahub.com
www.harekrishnahub.com
• Consider a circle with centre O and radius
r units.
• Let PQ be the diameter of the circle.
• Let A and B be any points on the circle,
such that the length of the arc AB is equal
to the radius r of the circle.
• Then the angle ∠𝐴𝑂𝐵 will be equal to 1
radian. (i.e., ∠𝐴𝑂𝐵 = 1 𝑐
)
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We have, length of the semi-circular arc = 𝝅𝒓 and the length of the arc 𝑨𝑩 =
𝒓
∠𝑨𝑶𝑩 = 𝟏 𝒄
and ∠𝑷𝑶𝑸 = 𝟏𝟖𝟎° = 𝒙 𝒄
(say)
We know that in a circle, the arc lengths are proportional to the angles
subtended by them at the centre. Therefore,
𝒂𝒓𝒄 𝑨𝑩
∠𝑨𝑶𝑩
=
𝒂𝒓𝒄 𝑷𝑸
∠𝑷𝑶𝑸
𝒓
𝟏 𝒄 =
𝝅𝒓
𝒙 𝒄
𝒙 𝒄
𝟏 𝒄
=
𝝅𝒓
𝒓
= 𝝅
∴ 𝒙 = 𝝅 𝒄
but 𝒙 = 𝟏𝟖𝟎°
∴ 𝟏𝟖𝟎° = 𝝅 𝒄
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In practise, the subscript for radian is usually omitted.
It is therefore, understood that
∴ 𝝅 𝒄 = 𝟏𝟖𝟎°
𝝅 =
𝟐𝟐
𝟕
= 𝟑. 𝟏𝟒𝟐
∴ 𝟑. 𝟏𝟒𝟐 𝒄 = 𝟏𝟖𝟎°
𝝅 ⟹ 𝟏𝟖𝟎°
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some examples:
Degrees Radians
360 𝟐𝛑
270
𝟑𝛑
𝟐
180 𝛑
90
𝛑
𝟐
60
𝛑
𝟑
45
𝛑
𝟒
30
𝛑
𝟔

Relation between radian and degrees

  • 1.
    Relation between radianand degrees by SBR www.harekrishnahub.com
  • 2.
    www.harekrishnahub.com • Consider acircle with centre O and radius r units. • Let PQ be the diameter of the circle. • Let A and B be any points on the circle, such that the length of the arc AB is equal to the radius r of the circle. • Then the angle ∠𝐴𝑂𝐵 will be equal to 1 radian. (i.e., ∠𝐴𝑂𝐵 = 1 𝑐 )
  • 3.
    www.harekrishnahub.com We have, lengthof the semi-circular arc = 𝝅𝒓 and the length of the arc 𝑨𝑩 = 𝒓 ∠𝑨𝑶𝑩 = 𝟏 𝒄 and ∠𝑷𝑶𝑸 = 𝟏𝟖𝟎° = 𝒙 𝒄 (say) We know that in a circle, the arc lengths are proportional to the angles subtended by them at the centre. Therefore, 𝒂𝒓𝒄 𝑨𝑩 ∠𝑨𝑶𝑩 = 𝒂𝒓𝒄 𝑷𝑸 ∠𝑷𝑶𝑸 𝒓 𝟏 𝒄 = 𝝅𝒓 𝒙 𝒄 𝒙 𝒄 𝟏 𝒄 = 𝝅𝒓 𝒓 = 𝝅 ∴ 𝒙 = 𝝅 𝒄 but 𝒙 = 𝟏𝟖𝟎° ∴ 𝟏𝟖𝟎° = 𝝅 𝒄
  • 4.
    www.harekrishnahub.com In practise, thesubscript for radian is usually omitted. It is therefore, understood that ∴ 𝝅 𝒄 = 𝟏𝟖𝟎° 𝝅 = 𝟐𝟐 𝟕 = 𝟑. 𝟏𝟒𝟐 ∴ 𝟑. 𝟏𝟒𝟐 𝒄 = 𝟏𝟖𝟎° 𝝅 ⟹ 𝟏𝟖𝟎°
  • 5.
    www.harekrishnahub.com some examples: Degrees Radians 360𝟐𝛑 270 𝟑𝛑 𝟐 180 𝛑 90 𝛑 𝟐 60 𝛑 𝟑 45 𝛑 𝟒 30 𝛑 𝟔