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The Regular Polygon
Collegeof EngineeringandComputerStudies,
St. Michael’s College
Iligan City
Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City
Regular Polygon
Regular polygons are
polygons with all sides
equal and all included
angles equal. Meaning,
regular polygons are
both equilateral and
equiangular.
Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City
Properties of Regular Polygon
1. The center of the circumscribing circle,
the center of inscribed circle, and the
center of polygon itself are coincidence.
2. All sides of regular polygon are equal in
length; it is denoted by x in the figure.
3. All included angles are equal; it is
denoted by β.
4. All external angles α, are equal.
5. Central angles of each segment are
equal; it is denoted by θ.
Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City
Properties of Regular Polygon (cont’n.)
6. The apothem is the radius of the inscribed circle,
r.
7. The number of sides is equal to the number of
vertices, both are denoted by n.
8. Diagonals that pass through the center has
length equal to the diameter of the
circumscribing circle.
9. The triangular segment with area denoted as
A1 is an isosceles triangle. The length of the two
equal sides of this triangle is the radius of the
circumscribing circle and the altitude of this
triangle is the radius of the inscribed circle.
Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City
Formulas of Regular Polygon
Area of one segment, A1
𝐴1 =
1
2
𝑥𝑟; 𝐴1 =
1
2
𝑅2 sin 𝜃
Total Area, A
𝐴 = 𝑛𝐴1
Perimeter, P
𝑃 = 𝑛𝑥
Central Angle, 𝜽
𝜃 =
360°
𝑛
Exterior angle, 𝜶
𝛼 = 𝜃
Interior angle, 𝜷
𝛽 = 180° − 𝛼
𝛽 = 180°
𝑛 − 2
𝑛
Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City
Problems 1:
Find the area of the regular pentagon as shown in
the figure.
Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City
Problems 2:
Three squares are drawn so that
each will contain a side of regular
hexagon as shown in the given
figure. If the hexagon has a
perimeter of 60 in., compute the
area of the region common to the
three squares. The required area
is the shaded region in the figure.
Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City
Solution:
Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City
Solution (cont’n.):

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Regular polygon

  • 1. The Regular Polygon Collegeof EngineeringandComputerStudies, St. Michael’s College Iligan City
  • 2. Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City Regular Polygon Regular polygons are polygons with all sides equal and all included angles equal. Meaning, regular polygons are both equilateral and equiangular.
  • 3. Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City Properties of Regular Polygon 1. The center of the circumscribing circle, the center of inscribed circle, and the center of polygon itself are coincidence. 2. All sides of regular polygon are equal in length; it is denoted by x in the figure. 3. All included angles are equal; it is denoted by β. 4. All external angles α, are equal. 5. Central angles of each segment are equal; it is denoted by θ.
  • 4. Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City Properties of Regular Polygon (cont’n.) 6. The apothem is the radius of the inscribed circle, r. 7. The number of sides is equal to the number of vertices, both are denoted by n. 8. Diagonals that pass through the center has length equal to the diameter of the circumscribing circle. 9. The triangular segment with area denoted as A1 is an isosceles triangle. The length of the two equal sides of this triangle is the radius of the circumscribing circle and the altitude of this triangle is the radius of the inscribed circle.
  • 5. Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City Formulas of Regular Polygon Area of one segment, A1 𝐴1 = 1 2 𝑥𝑟; 𝐴1 = 1 2 𝑅2 sin 𝜃 Total Area, A 𝐴 = 𝑛𝐴1 Perimeter, P 𝑃 = 𝑛𝑥 Central Angle, 𝜽 𝜃 = 360° 𝑛 Exterior angle, 𝜶 𝛼 = 𝜃 Interior angle, 𝜷 𝛽 = 180° − 𝛼 𝛽 = 180° 𝑛 − 2 𝑛
  • 6. Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City Problems 1: Find the area of the regular pentagon as shown in the figure.
  • 7. Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City Problems 2: Three squares are drawn so that each will contain a side of regular hexagon as shown in the given figure. If the hexagon has a perimeter of 60 in., compute the area of the region common to the three squares. The required area is the shaded region in the figure.
  • 8. Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City Solution:
  • 9. Collegeof EngineeringandComputerStudies, St. Michael’s College, Iligan City Solution (cont’n.):