Programming in C.Create a program which turns your Arduino into a .pdf
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Programming in C. Create a program which turns your Arduino into a light based electronic instrument. The program should play music based on the amount of light hitting the optical sensor. There should be a way to capture particularly pleasing tones and play those tones back in the order they are captured. The program must utilize the following : • An array to hold the stored tones • A function : void read_buttons( int *sw1, int *sw2, int *sw3, int *sw4) to read and store the state of the four buttons on the board • A function playback( notes[] ) which plays back the notes stored • A function clear_playlist( *notes) which clears the stored tones • A function tone_value() which generates a tone based on the current state of the optical sensor • The possible tones should span the range of human hearing Solution #include #include using namespace std; // Class Declaration class prime { //Member Varibale Declaration int a,k,i; public: prime(int x) { a=x; } // Object Creation For Class void calculate() { k=1; { for(i=2;i<=a/2;i++) if(a%i==0) { k=0; break; } else { k=1; } } } void show() { if(k==1) cout<<\"\ \"<>a; // Object Creation For Class prime obj(a); // Call Member Functions obj.calculate(); obj.show(); getch(); return 0; }.
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![Programming in C.
Create a program which turns your Arduino into a light based electronic instrument. The
program should play music based on the amount of light hitting the optical sensor. There should
be a way to capture particularly pleasing tones and play those tones back in the order they are
captured.
The program must utilize the following :
• An array to hold the stored tones
• A function : void read_buttons( int *sw1, int *sw2, int *sw3, int *sw4) to read and store the
state of the four buttons on the board
• A function playback( notes[] ) which plays back the notes stored
• A function clear_playlist( *notes) which clears the stored tones
• A function tone_value() which generates a tone based on the current state of the optical sensor
• The possible tones should span the range of human hearing
Solution
#include
#include
using namespace std;
// Class Declaration
class prime
{
//Member Varibale Declaration
int a,k,i;
public:
prime(int x)
{
a=x;
}
// Object Creation For Class
void calculate()
{
k=1;
{
for(i=2;i<=a/2;i++)](https://image.slidesharecdn.com/programminginc-230703023747-309e7aed/85/Programming-in-C-Create-a-program-which-turns-your-Arduino-into-a-pdf-1-320.jpg)
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Voice Detection and Reverse Playback
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1.playing audio in javaJava sound API(package javax.sound) support.pdf
1.playing audio in java
Java sound API(package javax.sound) supports two types of audios:
- sampled audio
- musical instrument digital interface(MIDI)
sampled audio:
In the sampled audio ,the supported file formats are: AIFC,AIFF,WAVE,SND,AU and doesn\'t
support the audio format MP3.
Provide two ways to play the audio: using clip and using source data line
using clip : (javax.sound.sampled.clip) used to play a short sound file.
In this method the whole audio clip is loaded into the memoryto have control over audio clip
before playing it.
steps for playing the audio file:
1. create an audioInputStream for a given sound file.
2. acquire audio format and create DataLine.Info Object
3.Obtain the clip
4.open the AudioInputStream ,start playing
5.close the resource acquired
using source data line :(javax.sound.sampled.SourceDataLine),used to play the long sound line.
these type of sounds cant be preloaded into the memory so, the data is read into the buffer in the
form of bytes repeatedly.
steps for playing the audio file:
1. open the sorce data file similarly by creating,acquiring and obtaining as in clip.
2. open and start the sound file
3. repeatedly read a chunk of bytes from the AudioInputStream and send it to the
SourceDataLine\'s buffer untill reaching the end f the file
4.close the resource acquired.
Musical Instrument Digital Interface(MIDI): music is synthesized from special nodes and effects.
steps for playing the audio:
1. allocate a sequence piped from a MIDI file
2. allocate a sequencer to play a MIDI sequence
3. set the current sequence for the sequencer to play
4. open the sequencer to load the sequence.
5. set the loop count by using SetLoopCount() and start playing the music by using start()
6. stop the play using stop().
2. creating a timer:
the Timer is provided in the java.util package.
In which we create an instance for thread like
Thread thread= new Thread();
then using this instance thread we use the sleep() available in the timer class as follows:
thread.sleep();
here the arguments int the sleep() is nothing but the time in milli seconds for example:
thread.sleep(2000) will sleep the process execution or triggering for 20 seconds.
BLanks:
1.
actionPerformed() in the Listener interface
2.
3.
close()
4.
5.
scope
Solution
1.playing audio in java
Java sound API(package javax.sound) supports two types of audios:
- sampled audio
- musical instrument digital interface(MIDI)
sampled audio:
In the sampled audio ,the supported file formats are: AIFC,AIFF,WAVE,SND,AU and doesn\'t
support the audio format MP3.
Provide two ways to play the audio: using clip and using source data line
using clip : (javax.sound.sampled.clip) used to play a short sound file.
In this method the whole audio clip is loaded into the memoryto have control over audio clip
before playing it.
steps for playing the audio file:
1. create an audioInputStream for a given sound file.
2. acquire audio format and create DataLine.Info Object
3.Obtain the clip
4.open the A.
Deep Learning with Audio Signals: Prepare, Process, Design, Expect
Is deep learning Alchemy? No! But it heavily relies on tips and tricks, a set of common wisdom that probably works for similar problems. In this talk, I’ll introduce what the audio/music research societies have discovered while playing with deep learning when it comes to audio classification and regression -- how to prepare the audio data and preprocess them, how to design the networks (or choose which one to steal from), and what we can expect as a result.
Recommended
Core audio
iOS Core Audio Introduction
Stephen Cussen's presentation for the Cocoa Conspiracy team at Ideas and Coffee at the South West Cyber Port
Voice Detection and Reverse Playback
This project detects a voice signal from a microphone, then plays it back in the reverse direction using DSP Starter Kit (DSK). This was done at IIT Patna.
1.playing audio in javaJava sound API(package javax.sound) support.pdf
1.playing audio in java
Java sound API(package javax.sound) supports two types of audios:
- sampled audio
- musical instrument digital interface(MIDI)
sampled audio:
In the sampled audio ,the supported file formats are: AIFC,AIFF,WAVE,SND,AU and doesn\'t
support the audio format MP3.
Provide two ways to play the audio: using clip and using source data line
using clip : (javax.sound.sampled.clip) used to play a short sound file.
In this method the whole audio clip is loaded into the memoryto have control over audio clip
before playing it.
steps for playing the audio file:
1. create an audioInputStream for a given sound file.
2. acquire audio format and create DataLine.Info Object
3.Obtain the clip
4.open the AudioInputStream ,start playing
5.close the resource acquired
using source data line :(javax.sound.sampled.SourceDataLine),used to play the long sound line.
these type of sounds cant be preloaded into the memory so, the data is read into the buffer in the
form of bytes repeatedly.
steps for playing the audio file:
1. open the sorce data file similarly by creating,acquiring and obtaining as in clip.
2. open and start the sound file
3. repeatedly read a chunk of bytes from the AudioInputStream and send it to the
SourceDataLine\'s buffer untill reaching the end f the file
4.close the resource acquired.
Musical Instrument Digital Interface(MIDI): music is synthesized from special nodes and effects.
steps for playing the audio:
1. allocate a sequence piped from a MIDI file
2. allocate a sequencer to play a MIDI sequence
3. set the current sequence for the sequencer to play
4. open the sequencer to load the sequence.
5. set the loop count by using SetLoopCount() and start playing the music by using start()
6. stop the play using stop().
2. creating a timer:
the Timer is provided in the java.util package.
In which we create an instance for thread like
Thread thread= new Thread();
then using this instance thread we use the sleep() available in the timer class as follows:
thread.sleep();
here the arguments int the sleep() is nothing but the time in milli seconds for example:
thread.sleep(2000) will sleep the process execution or triggering for 20 seconds.
BLanks:
1.
actionPerformed() in the Listener interface
2.
3.
close()
4.
5.
scope
Solution
1.playing audio in java
Java sound API(package javax.sound) supports two types of audios:
- sampled audio
- musical instrument digital interface(MIDI)
sampled audio:
In the sampled audio ,the supported file formats are: AIFC,AIFF,WAVE,SND,AU and doesn\'t
support the audio format MP3.
Provide two ways to play the audio: using clip and using source data line
using clip : (javax.sound.sampled.clip) used to play a short sound file.
In this method the whole audio clip is loaded into the memoryto have control over audio clip
before playing it.
steps for playing the audio file:
1. create an audioInputStream for a given sound file.
2. acquire audio format and create DataLine.Info Object
3.Obtain the clip
4.open the A.
Deep Learning with Audio Signals: Prepare, Process, Design, Expect
Is deep learning Alchemy? No! But it heavily relies on tips and tricks, a set of common wisdom that probably works for similar problems. In this talk, I’ll introduce what the audio/music research societies have discovered while playing with deep learning when it comes to audio classification and regression -- how to prepare the audio data and preprocess them, how to design the networks (or choose which one to steal from), and what we can expect as a result.
Modern Improvisation World
I'm going to use both my laptop, iPad and Android mobile phone to create music improvisation cooperation. While each device takes in different role, the main common development depends on Processing open source library for visual sketching and audio filtering production. Features of each devices are described as follow:
- Desktop focus on rhythm and take use of mouse dragging and keyboard. User interface will be friendly and indicates the rhythm or key pressedvia animation feedback.
- iPad (or iPhone)will focus more on graphics due to high performance of browser with Javascript support. Touch events are main part of iPad and audio filtering will be involved to enhance audio effect.
- Android mobile phone is going to have an instruction activity with Material Design card view with some open source projects involved. Action bar will have the main entrance of performance which takes use of accelerometer and touch event to have both audio and graphic interaction.
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Different types of Bits, bytes, and representation of information
1. Digital representation means that everything is represented by numbers only
The usual sequence something (sound, pictures, text, instructions, etc) are converted into
Numbers by some mechanism
2. The numbers can be stored, retrieved, processed, transmitted, The numbers might be
reconstituted into a version of the original.
3.And for (sound, pictures, other real-world values) Make accurate measurements and convert
them to numeric values need to measure intensity/loudness often enough and accurately
enough that we can reconstruct it well enough
higher frequency = higher pitch
human ear can hear ~ 20 Hz to 20 KHz
by taking samples at twice the highest frequency is good enough (Nyquist)
4. CD audio usually uses: 44,100 samples / second and accuracy of 1 in 65,536 (= 2^16) distinct
levels
two samples at each time for stereo data rate is 44,100 x 2 x 16 bits/sample= 1,411,200 bits/sec =
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5.MP3 audio compresses by clever encoding and removal of sounds that won\'t really be heard
data rate is ~ 1 MB/minute
6.A computer’s assembly language corresponds directly to its instruction set; there is one
assembly language mnemonic for each machine instruction. Unless you program in assembly
language, you will have very little visibility of the machine instruction set.
7. differences in instruction sets explain why some programs run on some machines but not
others. Unless two computers share the same instruction set, they will not be able to execute the
same set of machine instructions.
most programming is done in higher-level languages, rather than assembly language. When you
program in a higher-level language, you write statements in the syntax of your programming
language (e.g., Java, C, Python), and the language processor translates your code into the correct
set of machine instructions to execute your intent. If you want to run the same program on a
different computer with a different instruction set, you can often simply supply your code to the
appropriate language processor on the new computer.
General Execution Sequence:
a. Address of the instruction is sent to memory with a READ control signal
b. Instruction is fetched into control unit
c. Decode the instruction
d. Address 1 sent to memory with READ signal
e. Data fetched from memory location 1 into the data path
f. Address 2 sent to memory with READ signal
g. Data fetched from memory location 2 into the data path
h. ADD operation is sent to ALU in data path
i. Address 0 sent to memory with WRITE signal
j. Result sent from data path to memory and written to location 0.
Types of instructions sets are :
MOV
ADD
SUB
MUL
DIV
IMUL
DEC
AND
INC
OR
XOR
NOR
NOT
OUT
IN
JMP
CALL
Solution
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1. Digital representation means that everything is represented by numbers only
The usual sequence something (sound, pictures, text, instructions, etc) are conver.
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Slides from PyCon 2013 tutorial reformatted for self-study. Code at https://github.com/mchua/pycon-sigproc, original description follows: Why do pianos sound different from guitars? How can we visualize how deafness affects a child's speech? These are signal processing questions, traditionally tackled only by upper-level engineering students with MATLAB and differential equations; we're going to do it with algebra and basic Python skills. Based on a signal processing class for audiology graduate students, taught by a deaf musician.
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Computer Programming and MCUs:
- Assembly Language
- STM32CubeIDE
- STM32F3DISCOVERY Board MCU
Objectives:
1. Create a function that can chase an LED around the LED circle. This means that only one LED
should be on, and the currently on LED will move either clockwise, or anti-clockwise around the
circle of LEDs. Provide a value to the function in R1 which selects whether the LED goes
clockwise or anti-clockwise. Provide a value to the function in R2 which selects how many LEDs
should be on at the same time (1 LED chasing, 2 LEDs chasing, etc).
2. Make a map between an ASCII character and a pattern of LEDs being on/off. Demonstrate this
with a function that uses an ASCII value stored in R1 to turn the LEDs on/off to show the pattern.
3. Use the discovery board user input button to step through the characters in an ASCII string and
show the LED patterns one at a time.
General Assumptions/hints:
- User Button located in GPIO port A (base address: 0x48000000)
- LEDs located in GPIO port E (base address: 0x48001000)
- LED circle located in GPIO port E, bits 8-15
- Use STM32F3-Reference-Manual-Large.pdf for register addresses/offsets
Basic steps:
1. Enable the clock for each I/O port we want to use
2. Setup GPIO Registers (Button = input, LEDs = output)
3. Read from input or write from output
STM32F3DISCOVERY Board MCU:
STM32CubeIDE:
P. Project Explorer x Thern arn no projects in ynur workspaca. To add a project: Create a mew
Makefile project in a directory centaining revisting cade Create a new C or Ct+ prodect Crate a
Naw STM37 prolact Craata a Naw StM37 Proinct fram an Fristing Create a project... timpert
projects... D itams selected.
Paper on Modeling and Subtractive synthesis of virtual violin
Abstract :
Although solutions to the challenge of binaural artificial recreation of audio specializations exist in the Computer Music domain, a review of the area suggests that a comprehensive, generic, accurate and efficient tool set is required; hence this paper/thesis will deal with automated sound creation using sound synthesis. The entire setup was implemented using Csound. Csound implements many synthesis techniques unavailable through other means, such as user-controlled physical modeling.
I need help writing the methods for the song and playList class in J.pdf
I need help writing the methods for the song and playList class in Java. I already have the
interface and the getters and setter. Can someone help with the methods?
Song Class
public class Song
private String artist // the artist performing the song
private String title // the title of the song
private int minutes // number of min in length
private int seconds // number of seconds of length of the song (always less than 60)
// Add Getters / Setters for all fields
// Three constructors (remember to initialize ALL fields in each of the constructors - regardless
of the number of parameters!)
public Song(String artist, String title)
public Song(String artist, String title, int minutes, int seconds)
public Song(Song s)
public boolean equals(Object o) // a song is equal if all four fields are equal
public String toString() { // Use this code for toString EXACTLY
return \"{Song: title = \" + title + \" artist = \" + artist + \"}\";
}
public void play() { // Use this code for play EXACTLY
System.out.printf(\"Playing Song: artist = %-20s title = %s\ \", artist, title);
}
Make the Song class implement the interface Comparable, and make the ordering criteria as
follows: Songs will be ordered by artist in ascending order. If the artists are the same, then by
title in ascending order. If both artist and title are the same, then any order is acceptable.
Don’t forget to include any methods needed to implement the Playable interface.
PlayList Class
public class PlayList
Methods that modify the list should return a boolean return true if they successfully change the
list, otherwise they return false. Note that a PlayList can contain other PlayLists!
Methods that return a Playable element return null if they fail to find the song in question.
private String name // contains the name of the playlist
private ArrayList playableList // ArrayList of Playable elements that make up the play list
// Add Getters / Setters for name and songList
// Add a toString() method that returns the name of the playlist followed by its contents (by
calling toString() on each item it contains). You should only have one name/title per line
// Two constructors (remember to initialize ALL fields in each of the constructors - regardless of
the number of parameters!)
public PlayList() // empty play list named \"Untitled\"
public PlayList(String newName) // empty play list
public boolean loadSongs(String fileName) // loads songs from file, more on this below
public boolean clear() // removes all playable elements in the play list
public boolean addSong(Song s) // adds Song s to the end of the play list
public Playable removePlayable(int index) // removes Playable element at index from the list and
returns it
public Playable removePlayable(Playable p) // removes every occurrence of Playable p from the
list and returns p
public Playable getPlayable(int index) // returns the Playable element at the appropriate index
public boolean addPlayList(PlayList pl) //adds the PlayList that is being pa.
How do autopolyploidy and allopolyploidy differ Only autopolyploidy.pdf
How do autopolyploidy and allopolyploidy differ? Only autopolyploidy involves an increase in
chromosome sets. The chromosomes of an autopolyploid individual come from the same
species, while an allopolyploid has sets of chromosomes from different species. Autopolyploidy
is a mechanism of speciation in plants, while allopolyploid is a mechanism of speciation animals.
Autopolyploidy is sympatric, while allopolyploidy is allopatric.
Solution
Answer:
b). The chromosomes of an autopolyploid individual come from the same species, while an
allopolyploid has sets of chromsomes from different species
Autopolyploidy arises from fusion of gametes of the same species (cell division errors, etc.). In
this process, polyploid individuals develop as a result of cell division errors that double the DNA
content of gametes in individuals from the same species or a self-fertilizing individual. When
these double-dose gametes fuse, the result is an organism with double the chromosome number
of its parent species.
Allopolyploidy occurs when the gametes from two species fuse to form a polyploid generation
and hybrid offspring..
More Related Content
Similar to Programming in C.Create a program which turns your Arduino into a .pdf
Modern Improvisation World
I'm going to use both my laptop, iPad and Android mobile phone to create music improvisation cooperation. While each device takes in different role, the main common development depends on Processing open source library for visual sketching and audio filtering production. Features of each devices are described as follow:
- Desktop focus on rhythm and take use of mouse dragging and keyboard. User interface will be friendly and indicates the rhythm or key pressedvia animation feedback.
- iPad (or iPhone)will focus more on graphics due to high performance of browser with Javascript support. Touch events are main part of iPad and audio filtering will be involved to enhance audio effect.
- Android mobile phone is going to have an instruction activity with Material Design card view with some open source projects involved. Action bar will have the main entrance of performance which takes use of accelerometer and touch event to have both audio and graphic interaction.
Different types of Bits, bytes, and representation of information1.pdf
Different types of Bits, bytes, and representation of information
1. Digital representation means that everything is represented by numbers only
The usual sequence something (sound, pictures, text, instructions, etc) are converted into
Numbers by some mechanism
2. The numbers can be stored, retrieved, processed, transmitted, The numbers might be
reconstituted into a version of the original.
3.And for (sound, pictures, other real-world values) Make accurate measurements and convert
them to numeric values need to measure intensity/loudness often enough and accurately
enough that we can reconstruct it well enough
higher frequency = higher pitch
human ear can hear ~ 20 Hz to 20 KHz
by taking samples at twice the highest frequency is good enough (Nyquist)
4. CD audio usually uses: 44,100 samples / second and accuracy of 1 in 65,536 (= 2^16) distinct
levels
two samples at each time for stereo data rate is 44,100 x 2 x 16 bits/sample= 1,411,200 bits/sec =
176,400 bytes/sec ~ 10.6 MB/minute
5.MP3 audio compresses by clever encoding and removal of sounds that won\'t really be heard
data rate is ~ 1 MB/minute
6.A computer’s assembly language corresponds directly to its instruction set; there is one
assembly language mnemonic for each machine instruction. Unless you program in assembly
language, you will have very little visibility of the machine instruction set.
7. differences in instruction sets explain why some programs run on some machines but not
others. Unless two computers share the same instruction set, they will not be able to execute the
same set of machine instructions.
most programming is done in higher-level languages, rather than assembly language. When you
program in a higher-level language, you write statements in the syntax of your programming
language (e.g., Java, C, Python), and the language processor translates your code into the correct
set of machine instructions to execute your intent. If you want to run the same program on a
different computer with a different instruction set, you can often simply supply your code to the
appropriate language processor on the new computer.
General Execution Sequence:
a. Address of the instruction is sent to memory with a READ control signal
b. Instruction is fetched into control unit
c. Decode the instruction
d. Address 1 sent to memory with READ signal
e. Data fetched from memory location 1 into the data path
f. Address 2 sent to memory with READ signal
g. Data fetched from memory location 2 into the data path
h. ADD operation is sent to ALU in data path
i. Address 0 sent to memory with WRITE signal
j. Result sent from data path to memory and written to location 0.
Types of instructions sets are :
MOV
ADD
SUB
MUL
DIV
IMUL
DEC
AND
INC
OR
XOR
NOR
NOT
OUT
IN
JMP
CALL
Solution
Different types of Bits, bytes, and representation of information
1. Digital representation means that everything is represented by numbers only
The usual sequence something (sound, pictures, text, instructions, etc) are conver.
Digital signal processing through speech, hearing, and Python
Slides from PyCon 2013 tutorial reformatted for self-study. Code at https://github.com/mchua/pycon-sigproc, original description follows: Why do pianos sound different from guitars? How can we visualize how deafness affects a child's speech? These are signal processing questions, traditionally tackled only by upper-level engineering students with MATLAB and differential equations; we're going to do it with algebra and basic Python skills. Based on a signal processing class for audiology graduate students, taught by a deaf musician.
Computer Programming and MCUs Assembly Language STM32Cu.pdf
Computer Programming and MCUs:
- Assembly Language
- STM32CubeIDE
- STM32F3DISCOVERY Board MCU
Objectives:
1. Create a function that can chase an LED around the LED circle. This means that only one LED
should be on, and the currently on LED will move either clockwise, or anti-clockwise around the
circle of LEDs. Provide a value to the function in R1 which selects whether the LED goes
clockwise or anti-clockwise. Provide a value to the function in R2 which selects how many LEDs
should be on at the same time (1 LED chasing, 2 LEDs chasing, etc).
2. Make a map between an ASCII character and a pattern of LEDs being on/off. Demonstrate this
with a function that uses an ASCII value stored in R1 to turn the LEDs on/off to show the pattern.
3. Use the discovery board user input button to step through the characters in an ASCII string and
show the LED patterns one at a time.
General Assumptions/hints:
- User Button located in GPIO port A (base address: 0x48000000)
- LEDs located in GPIO port E (base address: 0x48001000)
- LED circle located in GPIO port E, bits 8-15
- Use STM32F3-Reference-Manual-Large.pdf for register addresses/offsets
Basic steps:
1. Enable the clock for each I/O port we want to use
2. Setup GPIO Registers (Button = input, LEDs = output)
3. Read from input or write from output
STM32F3DISCOVERY Board MCU:
STM32CubeIDE:
P. Project Explorer x Thern arn no projects in ynur workspaca. To add a project: Create a mew
Makefile project in a directory centaining revisting cade Create a new C or Ct+ prodect Crate a
Naw STM37 prolact Craata a Naw StM37 Proinct fram an Fristing Create a project... timpert
projects... D itams selected.
Paper on Modeling and Subtractive synthesis of virtual violin
Abstract :
Although solutions to the challenge of binaural artificial recreation of audio specializations exist in the Computer Music domain, a review of the area suggests that a comprehensive, generic, accurate and efficient tool set is required; hence this paper/thesis will deal with automated sound creation using sound synthesis. The entire setup was implemented using Csound. Csound implements many synthesis techniques unavailable through other means, such as user-controlled physical modeling.
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I need help writing the methods for the song and playList class in J.pdf
I need help writing the methods for the song and playList class in Java. I already have the
interface and the getters and setter. Can someone help with the methods?
Song Class
public class Song
private String artist // the artist performing the song
private String title // the title of the song
private int minutes // number of min in length
private int seconds // number of seconds of length of the song (always less than 60)
// Add Getters / Setters for all fields
// Three constructors (remember to initialize ALL fields in each of the constructors - regardless
of the number of parameters!)
public Song(String artist, String title)
public Song(String artist, String title, int minutes, int seconds)
public Song(Song s)
public boolean equals(Object o) // a song is equal if all four fields are equal
public String toString() { // Use this code for toString EXACTLY
return \"{Song: title = \" + title + \" artist = \" + artist + \"}\";
}
public void play() { // Use this code for play EXACTLY
System.out.printf(\"Playing Song: artist = %-20s title = %s\ \", artist, title);
}
Make the Song class implement the interface Comparable, and make the ordering criteria as
follows: Songs will be ordered by artist in ascending order. If the artists are the same, then by
title in ascending order. If both artist and title are the same, then any order is acceptable.
Don’t forget to include any methods needed to implement the Playable interface.
PlayList Class
public class PlayList
Methods that modify the list should return a boolean return true if they successfully change the
list, otherwise they return false. Note that a PlayList can contain other PlayLists!
Methods that return a Playable element return null if they fail to find the song in question.
private String name // contains the name of the playlist
private ArrayList playableList // ArrayList of Playable elements that make up the play list
// Add Getters / Setters for name and songList
// Add a toString() method that returns the name of the playlist followed by its contents (by
calling toString() on each item it contains). You should only have one name/title per line
// Two constructors (remember to initialize ALL fields in each of the constructors - regardless of
the number of parameters!)
public PlayList() // empty play list named \"Untitled\"
public PlayList(String newName) // empty play list
public boolean loadSongs(String fileName) // loads songs from file, more on this below
public boolean clear() // removes all playable elements in the play list
public boolean addSong(Song s) // adds Song s to the end of the play list
public Playable removePlayable(int index) // removes Playable element at index from the list and
returns it
public Playable removePlayable(Playable p) // removes every occurrence of Playable p from the
list and returns p
public Playable getPlayable(int index) // returns the Playable element at the appropriate index
public boolean addPlayList(PlayList pl) //adds the PlayList that is being pa.
How do autopolyploidy and allopolyploidy differ Only autopolyploidy.pdf
How do autopolyploidy and allopolyploidy differ? Only autopolyploidy involves an increase in
chromosome sets. The chromosomes of an autopolyploid individual come from the same
species, while an allopolyploid has sets of chromosomes from different species. Autopolyploidy
is a mechanism of speciation in plants, while allopolyploid is a mechanism of speciation animals.
Autopolyploidy is sympatric, while allopolyploidy is allopatric.
Solution
Answer:
b). The chromosomes of an autopolyploid individual come from the same species, while an
allopolyploid has sets of chromsomes from different species
Autopolyploidy arises from fusion of gametes of the same species (cell division errors, etc.). In
this process, polyploid individuals develop as a result of cell division errors that double the DNA
content of gametes in individuals from the same species or a self-fertilizing individual. When
these double-dose gametes fuse, the result is an organism with double the chromosome number
of its parent species.
Allopolyploidy occurs when the gametes from two species fuse to form a polyploid generation
and hybrid offspring..
How do you find the order of growth for the following recurrenceT.pdf
How do you find the order of growth for the following recurrence?
T(n) = 9T(n/3) + n2
Solution
The Master Theorem applies to recurrences of the following form:
T (n) = aT (n/b) + f (n)
where a 1 and b > 1 are constants and f (n) is an asymptotically positive function.
There are 3 cases:
Case First:-- f(n) is O(nlogba ). Since the leaves grow faster than f, all work is done at the
leaves, so T(n) is (nlogb a).
Case Second:-- f(n) is (nlogba). The leaves grow at same rate as f, so the same order of work is
done at every level of tree. Therfore tree has O(log n) levels times the work done on one level,
yielding T(n) is (nlogb a log n).
Case Third:-- f(n) is (nlogba + ). Here f grows faster than the number of leaves, which means that
asymptotically the total amount of work is dominated by the work done at the root node. For the
upper bound, we also need an extra smoothness condition on f in this case i.e af(n/b) cf(n) for
some constant c < 1 and large n. In this case T(n) is (f(n)).
Therefore, using Master Method on your above Question
a=9, b=3, =log39 = 2, f(n) = n2, so Case 2, i.e. T(n) = (nlogn) = (n2logn)..
Explain SEAD, SAR and SPAAR routing protocols in more details.So.pdf
Explain SEAD, SAR and SPAAR routing protocols in more details.
Solution
SEAD Protocols: SEAD is a proactive secure routing protocol based on DSDV-SQ-protocol. It
does not rely on asymmetric encryption primitive but instead it relies on one-way hash chain for
security. The algorithm expects that there is some authenticated and secure way to deliver the
initial key KN. This could be done by key delivery in advance or by using public key encryption
and signatures for key delivery. The basic idea of SEAD is, to authenticate the sequence number
and metric of a routing table update message using hash chains elements. In addition, the
receiver also authenticates the sender ensuring that the routing information originates from the
correct node. The source of each routing update message in SEAD must also be authenticated
since an attacker may be able to create routing loops through the impersonation attack. There are
two different approaches proposed such as broadcast authentication mechanism, TESLA and
Message Authentication Codes
SAR routing protocols: SAR takes an approach to routing that incorporates security level of
nodes into traditional routing metrics. In most protocols the length of the route is the only metric
used. It does not target any protocol, but it rather provides security at a more generalized level of
security. The goal is exposing security to the application and to the routing protocol. SAR uses
AODV or DSR as a base protocol; it embeds the security metric into RREQ packet itself and
changes the forwarding behavior of the protocol. When intermediate nodes receive an RREQ
packet with a particular security metric or trust level, the node can only process the packet or
forward it if it can provide the required security or trust level.
SPAAR routing protocols: The SPAAR protocol was developed with the classical managed-
hostile environment in mind, thus meant to provide a very high level of security, and sometimes
at the cost of performance. Among other things, SPAAR also requires that each device to use a
GPS locator to determine its position, although some leeway is given to nodes using a so-called
“locator-proxy” if absolute security is not required. In SPAAR packets are only accepted
between neighboring nodes one hop away from each other, this is to avoid the “invisible node-
attack”. The basic transmission procedure is quite similar to ARAN, although the group
neighborhood key is used for encryption in order to ensure one-hop communication only. Since
all nodes also have information on their location they only forward RREQs if their position is
closer to the destination position.
Dynamic routing protocols are used toa) establish paths real ti.pdf
Dynamic routing protocols are used to:
a) establish path\'s real time between routers
b) define overhead bits within the packet
c) encapsulate the IP packet into a Layer 2 frame
d) reroute traffic during circuit failures and network congestion
e) a and b
f) a, c, and d
g) all of the above
Solution
a,c,d.
Evaluate expression without a calculator. Write answer in radians..pdf
Evaluate expression without a calculator. Write answer in radians.
Please show step by step so I can check my work. My answer -pi/6
Solution
sin^-1(-1/2) =y
range of sin^-1(x) : -pi/2<=y<=pi/2
So, value of y would be less than pi/2and its is -ve so it should be between -pi/2 and 0
y = sin^-1(-1/2)
siny = -1/2
y = -pi/6 radians.
Epithelial tissues that are only one cell thick are called _____ Epi.pdf
Epithelial tissues that are only one cell thick are called _____ Epithelial tissues that are more
than one cell thick are called _____ Of these two basic types of epithelial tissues, which is most
likely better at transport of substances? What structural aspect of this tissue makes it good at
doing this? What is the major function of the other basic type of epithelial tissue? What
structural aspect of this tissue makes It good at doing this? If the cells in an epithelial tissue are
wider than they are tall, they are called _____ cells. If the cells in an epithelial tissue are taller
than they are wide, they are called _____ cells. If the cells In an epithelial tissue are as wide as
they are tall, they are called _____ cells. Of these three types of cell shapes found In epithelial
tissues, which one is best at allowing for simple diffusion? What structural aspect of this tissue
makes it good at doing this? Of these three types of cell shapes found in epithelial tissues, which
ate best at allowing for active transport processes? What structural aspect of this tissue makes it
good at doing this? What type of cell-surface characteristic helps an epithelial tissue reduce
friction? What type of cell-surface characteristic helps an epithelial tissue in absorption and/or
secretion? What type of cell-surface characteristic helps an epithelial tissue allows it to move
particles across its surface?
Solution
- epithelium cells that are only one cell thick are known as simple epithelial tissues
- epithelium cells that are more than one cell thickness are known as stratified epithelial tissue
- simple epithelial tissue is good at transport of substances
- epithelial tissue consists of basement membrane on which it rests. this membrane acts as a
scaffold. through this membrane ther is nerve supply as this membrane is permeable hence it
allows the transport of substances
-the major function of stratified epithelial tisue is protection of the cells
-epithelial tissues acts as a lining surface to the body organs
-.
Describe in five sentences how the TLR system is used to fight HSV-1 .pdf
Describe in five sentences how the TLR system is used to fight HSV-1 encephalitis.
Solution
Toll like receptors are one type of PRRs, which are associate in the recognition of pathogen,
associated molecular patterns. These receptors are initially identified in Drosophila, they are also
found in macrophages, mast cells, dendritic cells in mammals. Toll-like receptors trigger the
production and release of cytokines and also activate other host defense responses associated
with innate and adaptive immune response. In response to HSV -1 (herpes simplex virus 1), the
TLR-2 releases cytokines that cause severe inflammatory response (innate immune response),
which leads to encephalitis. Antagonism of these receptors is likely to provide protection against
encephalitis caused by HSV-1. The TLR-2 are mainly located on the surface of microglia and
astrocytes..
Daunte is frustrated about managements recent decision to merge hi.pdf
Daunte is frustrated about management\'s recent decision to merge his two teams into one. He
discusses this issue with Claire, a so-worker. Claire responds by saying, \"Its sounds like
management\'s decision really bothers you.\" In the context of listening skills, Clarire\'s
statement best exemplifies a (n) sarcastic tone that blocks responses. (b) active response that
mirrors feelings (c) active response that advises the speaker. (d) blocking response that criticies
the speaker (e) negative response that magnifies the problem.
Solution
(b) active response that mirrors feelings.
Concern over the weather associated with El Nino has increased intere.pdf
Concern over the weather associated with El Nino has increased interest in the possibility that
the climate on earth is getting warmer. The most common theory relates an increase in
atmospheric levels of carbon dioxide (CO_2), a greenhouse gas, to increases in temperature. A
regression analysis of the mean annual CO_2 concentration (in parts per million) in the
atmosphere at the top of Mauna Loa in Hawaii and the mean annual air temperature (in degrees
Celsius) over both land and sea across the globe for 37 years was performed. Assume all
conditions are met for simple linear regression inference. A hypothesis test is to be performed to
determine if CO_2 levels is a significant predictor of air temperature. What is the correct
conclusion based on the results of the hypothesis test? Choose the correct answer below.
Solution
Here, the t statistic is
t = B1 / sB1
here, B1 = 0.004, sB1 = 0.009.
Thus,
t = 4.444444444
For a 0.001 level, the critical t value is, as df = n - 1 = 36,
tcrit= 3.582149701
Thus, as t > 3.5821, then it is OPTION D. [ANSWER].
Clostridium difficile is a bacteria currently making headlines. It h.pdf
Clostridium difficile is a bacteria currently making headlines. It has long been the considered the
most common health-care associated infection, causing death to a large number of patients when
they contract it during hospital stays. The CDC is now reporting an increase in C. difficile cases
even outside of hospitals, which is raising concern. Below is an electron micrograph of C.
difficile. If you were able to do a Gram stain on a sample of the bacteria, you would find that the
cells stain a dark purple.
Given this information, how would you classify C. difficile?
A.
Gram negative, rod shaped
B.
Gram positive, coccus shaped
C.
Gram negative, coccus shaped
D.
Gram positive, rod shaped
Many protists have evolved complex life cycles that include sexual reproduction. This means
that:
A.
haploid cells must undergo meiotic divisions to form gametes.
B.
complex mating behavior likely evolved at the same time as sexual reproduction.
C.
genetic material from two haploid cells is combined at some point in the life cycle.
D.
diploid cells must undergo mitotic cell division in order to reproduce.
Protists:
A.
are all eukaryotes.
B.
are all heterotrophs.
C.
are all photosynthetic.
D.
are all single-celled.
E.
All of the above are correct.
All of the following are examples of the evidence that supports the endosymbiotic theory
EXCEPT:
A.
Mitochondria and chloroplasts have their own genomes.
B.
Mitochondria and chloroplasts divide in a process resembling binary fission.
C.
Mitochondria and chloroplasts are similar in size to bacteria.
D.
Mitochondria and chloroplasts have linear chromosomes.
Solution
Clostridium difficle is a Gram positive, rod shaped bacteria.(option-D) Many protists have
evolved complex sexual reproductive life cycles which includes haploid cells undergo meiotic
division to form gametes. Protists are all eukaryotes, not an animal, plant or fungus. The point
\"mitochondria and chloroplaats have linear chromosomes\" is not an evidence that supports for
endosymbiotic theory..
You cloned an EcoRI digested DNA fragment into a unique EcoRI site o.pdf
You cloned an EcoRI digested DNA fragment into a unique EcoRI site of a vector. You identify
a recombinant vector that you believe has the DNA of interest. To generate a restriction map of
the recombinant plasmid, you take three individual samples of the plasmid and digest them with
EcoRI, HindIII, and with both EcoRI and HindIII. You then run the digested DNA on an
agarose
gel to see the fragments. The gel is then subjected to a Southern hybridization using the EcoRI
insert as a probe. Assume that the insert fragment is smaller than the vector.
15. Which fragment (s) on the gel would hybridize to the probe which represents the inert?
16. Which fragment (s) on the gel would hybridize to a probe representing the 5.3 kb band
observed in the EcoRI lane?
17. Which fragment (s) in the EcoRI lane would hybridize to a probe representing the 4.1 kb
band observed in the HindIII lane?
18. The cloning strategy used being non-directional, the recombinant plasmid may represent one
of two possible orientations of the insert. You perform a hybridization with the 1.5 kb band
observed in the EcoRI lane. Which fragment (s) would not be observed in the opposite
orientation of that represented on the gel?
PLEASE EXPLAIN THOUGHT PROCESS 5.3 4.1 2.7 1.5 EcoRI HindIII EcoRI Hind 3.0 2.3
1.1 0.4
Solution
The band of HINDIII (2.7) and the band of EcoRI+HINDIII (2.3) represent the fragments that
will hybridize to 5.3kb band probe.
The band of EcoRI+HINDIII (3.0) and the band of EcoRI (1.5) represent the fragments that will
hybridize to 4.1kb band probe.
The fragments which will mot be observed in opposite direction are the ones which are dual
enzyme digested. The reason behind this is that when dual enzyme digestion occurs it causes an
incompatible recognition sequence in the opposite direction. Therefore such fragments are found
in the middle of two individual enzyme digestions..
You have constructed a new reporter gene to help you find novel zebr.pdf
You have constructed a new reporter gene to help you find novel zebrafish mutations. The
reporter gene consists of several LEG/TCF binding domains in the enhancer fused to the coding
region for green fluorescent protein (GFP). Wild-type embryos that contain this transgene
normally express it in the brain and eye primordia and have no developmental defects. You then
mutagenize this reporter strain to look for new mutants that affect GFP expression.
Which developmental pathway are these mutants likely to be in and why?
You find a mutant (which you call GLO-1) that ubiquitously expresses your reporter gene
throughout the entire embryo. Which molecule in the above pathway is most likely to be mutated
and why?
Solution
Ans.) Nacre, a zebrafish homolog of MITF is required for pigment cell differentiation. We
isolated a promoter region of shell that contains Tcf/Lef binding sites which will mediate Wnt
responsiveness. This promoter binds to zebrafish Lef1 protein in vitro, and a nacre
communicator construct is powerfully inhibited by dominant-negative Tcf in malignant
melanoma cells. Mutation of Tcf/Lef sites abolishes Lef1 binding and reporter operates in vivo.
Wnt signaling so directly activates shell, which in flip ends up in pigment cell differentiation.
It was determined that the human melanocyte-specific MITF promoter contains many purported
Tcf/Lef binding sites, hallmarks of Wnt/-catenin-mediated transcriptional control. To test the
hypothesis that nacre could be a target of the Wnt/-catenin pathway in zebrafish, a
promoter/enhancer region is isolated for this sequence from a genomic bacteriophage library.
This genomic fragment contains the translation initiation site for nacre which is associated with a
836-bp upstream region with a possible transcription begin site, a cAMP response element
(CRE) and several agreement Tcf/Lef binding sites. These CRE and Tcf/Lef locations are not
fully preserved between the human and zebrafish promoters in either their sequences or their
positions from the transcription begin site. To examine whether the purported putative nacre
promoter/enhancer will direct correct abstraction management of organic phenomenon, injected
one -cell zebrafish embryos with the 836-bp deoxyribonucleic acid fragment driving a green
fluorescent macromolecule (GFP) communicator sequence. Mosaic gene expression is typical for
transient transgenics in zebrafish and because the neural crest springs from only a few precursor
cells, reporter potency is minimized. Despite these, it was ready to analyze the fate of the few
reporter-expressing cells in injected animals..
Write a Java program that will incorporate either a sequential searc.pdf
Write a Java program that will incorporate either a sequential search method or a sort method
Solution
class Search
{
public static void main(String args[])
{ int array[],n;
System.out.println(\"Please enter the sixe of array\");
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(\"Please enter\"+ n +\"elements of array\");
for(int i= 0;i.
Answer only with excel instructions.Assume that 96 of ticket hold.pdf
Answer only with excel instructions.
Assume that 96% of ticket holders show up for an airline flight. If a plane seats 200 people, how
many tickets should be sold to make the chance of an overbooked flight (more ticket holders
show up for a flight than there are seats available) is at most 10%.
Solution
Say no. of tickets booked = x
Now only 0.96x will turn up
No. of seats = 200
Now these 0.96x people should get a seat with 90% probability
200 / (0.96x) >=0.9
200/0.864 >= x
x <=231.48
x = 231
Airline will make 231 reservations.
A new species of sea horse has been discovered and is being sequenced.pdf
A new species of sea horse has been discovered and is being sequenced The genome of the new
species is being aligned using the reference sequence from a already-known species of sea horse
Since the two species are evolutionary diverged, there may be some differences between their
sequences Reference sequence: ACCTACATTCACAGAATGAT Fragments a) Align the set
of mini-fragments above. b) How are the sequences of the two sea horse species different? c)
Would this alignment have been easier or more difficult if you didn\'t have any reference
sequence at all (alignment without a reference is called \"de novo\")? Explain d) If there had
been sequencing errors, would this alignment have been easier or more difficult? Explain.
Solution
A) TAGATT TGAATG TCACTGA
B) There is a form of polymorphism occurring in the new sequence of the genes for the new
species of sea horses. There is single nucleotide polymorphism in the new species as C is
replaced by T and A instead of G which may probably occurred due to some sort of mutation
during genetic sequencing.
C) The given alignment would be difficult without reference DNA sequence as reference
sequence gives basic DNA information and a reference database techniques is much easier than
performing a de novo technique though de novo methods are well established using mass spectra
nowadays but still having a reference database helps and gives the better coding information of
protein sequence.
D) if there had been a sequence error there would be difficulty in alignment and in that case we
have to perform de novo sequencing using mass spectra analysis. To know the sequence of the
species and other information regarding the DNA characters..
Which of the following is the mechanism of action for Herceptin Her.pdf
Which of the following is the mechanism of action for Herceptin? Herceptin binds to the HER2
promoter to prevent transcription, thus lowering amounts of receptor. Herceptin binds to
intracellular HER2 proteins to prevent cancer cells from dividing. Herceptin binds to HER3 and
HER4 cell surface receptors to activate the immune system. Herceptin binds to extracellular
domain of HER2 and prevents internalization and subsequent cancer cell division. Herceptin
targets TNF alpha.
Solution
B) herceptin binds to intracellular ER2 proteins to prevent cancer cells from dividing
Trastuzumab (herceptin) activates p27 factor by inhibiting PI3K/Akt, Mirk and hKIS pathways.
HER2 protein can be expressed up to 100 times more in cancer cells. PI3K/Akt, Mirk and hKIS
are intracellular proteins in HER2 pathways are activated which promote cell proliferation.
Signals present in these pathways promote growth of blood vessels in order to supplement for
tumour formation or angiogenesis and therefore resulting in cell proliferation. Thus, when
herceptin inhibits PI3K/Akt, Mirk and hKIS pathways, the cell proliferation is inhibited..
Which of these statements best describes an element An element is c.pdf
Which of these statements best describes an element? An element is composed of three
subatomic particles. An element is formed when two atoms of the same kind are bonded
together. An element is formed when two or more different atoms combine chemically. An
element is composed of identical atoms.
Solution
An element is composed of identical atoms.
Molecules can be made of elements, but elements arent made from molecules. 2 or more atoms
of the same kind make up an element.For example H is hydrogen which is an element formed
from H atoms only whereas H2O is a compount formed from 2 different atoms H and O..
What is the general goal for descriptive statistics How is the goal.pdf
What is the general goal for descriptive statistics? How is the goal served by putting scores in a
frequency distribution? How is the goal served by computing a measure of central tendency?
How is the goal served by computing a measure of variability?
Solution
What is the general goal of descriptive statistics ?
Answer : To simplify , organize, and summarize data so that it is easier for researchers to see
patterns.
How is the goal served by putting scores in a frequency distribution?
A frequncy distribution provides an organized summary of the complete set of scores.
How is the goal served by computing a measure of central tendency?
Summarizes an entires set of scores with a single value that is representative of the whole set.
How is the goal served by computing a measure of variability?
Provides a single number that describes the differences that exist from complete score to another..
What effects are shown on this graph (assume that all effects where.pdf
What effects are shown on this graph? (assume that all effects where the marginal means differ
are significant)
Choose as many as applicable.
A. Main effect of A where scores are higher at A1 than A2
B. Main effect of A where scores are higher at A2 than A1
C, Main effect of B where scores are higher at B1 than B2
D, Main effect of B where scores are higher at B2 than B1
E. Interaction where the effect of A is larger at B1 than B2
F. Interaction where the effect of A is larger at B2 than B1
Solution.
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http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
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