Please use c++ and give screen shot of full code There are n boxes of.pdf

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Please use c++ and give screen shot of full code There are n boxes of n different items in a warehouse. Each box has a label that says the name ( mi ), total weight (w_i) in kg and the total value (v_i i) in taka of that item (i). All items are divisible. Suppose, k thieves have come to steal from the warehouse, each with a knapsack of capacity W_i. Given each thief wants to maximize his/her profit. how manv thieves will be needed to embtv the warehouse?.

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Please show your work! Draw an UML class diagram showing the classes.pdf

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Please the following is the currency class of perious one. class Currency { protected: int whole; int fraction; virtual std::string get_name() = 0; public: Currency() { whole = 0; fraction = 0; } Currency(double value) { if (value < 0) throw "Invalid value"; whole = int(value); fraction = std::round(100 * (value - whole)); } Currency(const Currency& curr) { whole = curr.whole; fraction = curr.fraction; } /* This algorithm gets the whole part or fractional part of the currency Pre: whole, fraction - integer numbers Post: Return: whole or fraction */ int get_whole() { return whole; } int get_fraction() { return fraction; } /* This algorithm adds an object to the same currency Pre: object (same currency) Post: Return: */ void set_whole(int w) { if (w >= 0) whole = w; } void set_fraction(int f) { if (f >= 0 && f < 100) fraction = f; } /* This algorithm adds an object to the same currency Pre: object (same currency) Post: Return: */ void add(const Currency* curr) { whole += curr->whole; fraction += curr->fraction; if (fraction > 100) { whole++; fraction %= 100; } } /* This algorithm subtracts an object to the same currency Pre: object (same currency) Post: Return: */ void subtract(const Currency* curr) { if (!isGreater(*curr)) throw "Invalid Subtraction"; whole -= curr->whole; if (fraction < curr->fraction) { fraction = fraction + 100 - curr->fraction; whole--; } else { fraction -= curr->fraction; } } /* This algorithm compares the an object of the same currency for equality or inequality Pre: object (same currency) Post: Return: whole/fraction */ bool isEqual(const Currency& curr) { return curr.whole == whole && curr.fraction == fraction; } /* This algorithm compares the an object of the same currency to determine which is greater or smaller Pre: object (same currency) Post: Return: true/false */ bool isGreater(const Currency& curr) { if (whole < curr.whole) return false; if (whole == curr.whole && fraction < curr.fraction) return false; return true; } /* This algorithm prints the name and value of the currency object Pre: value of whole, fraction, and the name Post: whole, fraction, get_name() Return: */ void print() { std::cout << whole << "." << fraction << " " << get_name() << std::endl; } }; class Krone : public Currency { protected: /* This algorithm gets the name for the Currency. Pre: name - declared as string and initialized as Krone Post: Return: name */ std::string name = "Krone"; std::string get_name() { return name; } public: Krone() : Currency() { } Krone(double value) : Currency(value) { } Krone(Krone& curr) : Currency(curr) { } }; class Soum : public Currency { protected: /* This algorithm gets the name for the Currency. Pre: name - declared as string and initialized as Soum Post: Return: name */ std::string name = "Soum"; std::string get_name() { return name; } public: Soum() : Currency() { } Soum(double value) : Currency(value) { } Soum(Krone& curr) : Currency(curr) { } }; A LinkNode structure or class which will have two attrib.

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Please trace the execution of the following solution to the Dining Philosopher problem. #define N ___ enum status(EATING, HUNGRY, THINKING}; monitor diningPhilosophers { status state[N]; condition self[N]; test(int i) { if((state[(i-1) mod N] != EATING) && (state[i] == HUNGRY) && (state[(i+1) mod N] != EATING)) { state[i] = EATING; self[i].signal(); } }; public: diningPhilosophers() { // Initilization for(int i = 0; i < N; i++) state[i] = THINKING; }; test(int i) { if((state[(i-1) mod N] != EATING) && (state[i] == HUNGRY) && (state[(i+1) mod N] != EATING)) { state[i] = EATING; self[i].signal(); }; }; public: diningPhilosophers() {...}; pickUpForks(int i) { state[i] = HUNGRY; test(i); if(state[i] != EATING) self[i].wait(); }; putDownForks(int i) { state[i] = THINKING; test((i-1) mod N); test((i+1) mod N); }; }.

Please trace the execution of the following solution to the Dining Phi.pdf

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please show elegoo arduino board setup using a passive buzzer. heres the code below: #define F_CPU 16000000 UL // CPU Frequency #include <avr/io.h> #include <util/delay.h> volatile uint8_t notePlaying = 0 ; void setup () { DDRB |= ( 1 << PB6 ) ; // Set PB6 as output TCCR1A = 0 ; // Clear Timer1 registers TCCR1B = 0 ; TIMSK1 = 0 ; OCR1A = 0 ; } void playNote ( uint16_t frequency) { if ( notePlaying ) { TCCR1B = 0 ; // Stop the timer notePlaying = 0 ; } else { // Calculate the prescaler value uint16_t prescaler = 1 ; while (( F_CPU / ( prescaler * frequency * 2 )) > 65535 ) { prescaler <<= 1 ; } // Configure Timer1 TCCR1B = ( 1 << WGM12 ) | ( prescaler & 0x 07 ) ; // Mode 4, prescaler OCR1A = ( F_CPU / ( prescaler * frequency * 2 )) - 1 ; // Output compare value TIMSK1 = ( 1 << OCIE1A ) ; // Enable compare match interrupt notePlaying = 1 ; // Start the timer TCNT1 = 0 ; TCCR1B |= ( 1 << CS10 ) | (( prescaler >> 1 ) & 0x 03 ) ; // Start timer } } ISR ( TIMER1_COMPA_vect ) { PORTB ^= ( 1 << PB6 ) ; // Toggle PB6 state } void loop () { if ( Serial . available () > 0 ) { char key = Serial . read () ; switch ( key ) { case 'A': playNote ( 440 ) ; break ; case 'B': playNote ( 494 ) ; break ; case 'C': playNote ( 523 ) ; break ; case 'D': playNote ( 587 ) ; break ; case 'E': playNote ( 659 ) ; break ; case 'F': playNote ( 698 ) ; break ; case 'G': playNote ( 784 ) ; break ; case 'q': TCCR1B = 0 ; // Stop the timer notePlaying = 0 ; break ; } } } #define F_CPU 16000000 UL // CPU Frequency #include <avr/io.h> #include <util/delay.h> volatile uint8_t notePlaying = 0 ; void setup () { DDRB |= ( 1 << PB6 ) ; // Set PB6 as output TCCR1A = 0 ; // Clear Timer1 registers TCCR1B = 0 ; TIMSK1 = 0 ; OCR1A = 0 ; } void playNote ( uint16_t frequency) { if ( notePlaying ) { TCCR1B = 0 ; // Stop the timer notePlaying = 0 ; } else { // Calculate the prescaler value uint16_t prescaler = 1 ; while (( F_CPU / ( prescaler * frequency * 2 )) > 65535 ) { prescaler <<= 1 ; } // Configure Timer1 TCCR1B = ( 1 << WGM12 ) | ( prescaler & 0x 07 ) ; // Mode 4, prescaler OCR1A = ( F_CPU / ( prescaler * frequency * 2 )) - 1 ; // Output compare value TIMSK1 = ( 1 << OCIE1A ) ; // Enable compare match interrupt notePlaying = 1 ; // Start the timer TCNT1 = 0 ; TCCR1B |= ( 1 << CS10 ) | (( prescaler >> 1 ) & 0x 03 ) ; // Start timer } } ISR ( TIMER1_COMPA_vect ) { PORTB ^= ( 1 << PB6 ) ; // Toggle PB6 state } void loop () { if ( Serial . available () > 0 ) { char key = Serial . read () ; switch ( key ) { case 'A': playNote ( 440 ) ; break ; case 'B': playNote ( 494 ) ; break ; case 'C': playNote ( 523 ) ; break ; case 'D': playNote ( 587 ) ; break ; case 'E': playNote ( 659 ) ; break ; case 'F': playNote ( 698 ) ; break ; case 'G': playNote ( 784 ) ; break ; case 'q': TCCR1B = 0 ; // Stop the timer notePlaying = 0 ; break ; } } } #define F_CPU 16000000 UL // CPU Frequency #include <avr/io.h> #include <util/delay.h> volatile uint8_t notePlaying = 0 ; void setup () { DDRB |= ( 1 << PB6 ) .

please show elegoo arduino board setup using a passive buzzer- heres t.pdf

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Please translate this into MIPS Assembly without using Psuedo-instruct.pdf

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