اا

1. ‫اﻟﺸﻌﺒﻴﺔ‬ ‫اﻃﻴﺔ‬‫ﺮ‬‫اﻟﺪﻳﻤﻘ‬ ‫ﻳﺔ‬‫ﺮ‬‫اﺋ‬‫ﺰ‬‫اﻟﺠ‬ ‫ﻳﺔ‬‫ر‬‫اﻟﺠﻤﻬﻮ‬
‫ﻣﺴﺘﻐﺎﻧﻢ‬ ‫ﻟﻮﻻﻳﺔ‬ ‫ﺑﻴﺔ‬‫ﺮ‬‫اﻟﺘ‬ ‫ﻳﺔ‬‫ﺮ‬‫ﻣﺪﻳ‬
‫ﻋﺸﻌﺎﺷﺔ‬ ‫ﺛﺎﻧﻮﻳﺔ‬
)
‫اﻟﻘﺎدر‬ ‫ﻋﺒﺪ‬ ‫ﻳﻒ‬‫ﺮ‬‫ﺷ‬ ‫ﲪﺪي‬
(
‫اﻷول‬ ‫اﻟﻔﺼﻞ‬ ‫اﻣﺘﺤﺎن‬
‫اﺳﻴﺔ‬‫ر‬‫اﻟﺪ‬ ‫اﻟﺴﻨﺔ‬
:
2016
/
2017
‫اﻟﺸﻌﺒﺔ‬
:
‫ﻳﺎﺿﻴﺎت‬‫ر‬
‫اﻟﻤﺴﺘﻮى‬
:
‫اﻟﺜﺎﻟﺜﺔ‬ ‫اﻟﺴﻨﺔ‬
‫ﻣﺎدة‬ ‫ﻓﻲ‬ ‫اﺧﺘﺒﺎر‬
:
‫ﻳﺎﺋﻴﺔ‬‫ﺰ‬‫اﻟﻔﻴ‬ ‫اﻟﻌﻠﻮم‬
‫اﻟﻤﺪة‬
:
03
‫ﺳﺎﻋﺎت‬
‫أﺳﻮد‬ ‫أو‬ ‫أزرق‬ ‫ﺑﻘﻠﻢ‬ ‫إﺟﺎﺑﺘﻪ‬ ‫ﻳﺮ‬‫ﺮ‬‫ﺗﺤ‬ ، ‫اﻟﺘﻠﻤﻴﺬ‬ ‫ﻋﻠﻰ‬ : ‫ﻣﻼﺣﻈﺔ‬
‫اﻷول‬ ‫اﻟﺗﻣرﯾن‬
:
)
,0
5
0
‫ﻧﻘطﺔ‬
(
‫اﻟﻧظﯾر‬ ‫ﯾﻌﺗﺑر‬
‫ﺑﯾن‬ ‫ﻣن‬ ‫ﻟﻠﺗﻛﻧﺳﯾوم‬
‫اﻟﻣﺷﻌﺔ‬ ‫اﻷﻧوﯾﺔ‬
ّ‫ﺑ‬‫اﻟط‬ ‫اﻟﻣﺟﺎل‬ ‫ﻓﻲ‬ ‫اﻟﻣﺳﺗﻌﻣﻠﺔ‬
‫ﺧطورﺗﮫ‬ ‫وﻗﻠﺔ‬ ، ‫اﻟﻘﺻﯾرة‬ ‫ﺣﯾﺎﺗﮫ‬ ‫ﻟﻣدة‬ ‫اﻋﺗﺑﺎرا‬ ‫ﻲ‬
‫اﻷطﺑﺎء‬ ‫إﺷﺎرة‬ ‫رھن‬ ‫وﺿﻌﮫ‬ ‫وﺳﮭوﻟﺔ‬ ‫اﻟﻣﻧﺧﻔﺿﺔ‬ ‫وﺗﻛﻠﻔﺗﮫ‬ ‫اﻹﺷﻌﺎﻋﯾﺔ‬
.
1
(
‫ﯾﻌﺗﺑر‬
‫و‬
‫ﻟﻠﺗﻛﻧﯾﺳﯾوم‬ ‫ﻧظﯾران‬
.
1
-
1
(
‫و‬ ‫اﻟﻣﺷﻌﺔ‬ ‫اﻟﻧواة‬ ‫ف‬ّ‫ﻋر‬
‫اﻟﻧظﯾر‬ ‫ﻧواة‬ ‫ﺗرﻛﯾب‬ ‫اﻋط‬
.
1
-
2
(
‫اﺳﺗﻘرارا‬ ‫اﻷﻛﺛر‬ ‫اﻟﻧواة‬ ‫اﻟﺗﻌﻠﯾل‬ ‫ﻣﻊ‬ ‫ّد‬‫د‬‫ﺣ‬
.
1
-
3
(
‫اﻟﺗﻛﻧﺳﯾوم‬ ‫ﯾﻧﺗﺞ‬
‫اﻟﻣوﻟﯾﺑدان‬ ‫ﻧواة‬ ‫ﺗﻔﻛك‬ ‫ﻋن‬
( è )
.
‫أ‬
-
‫اﻟﺗﻛﻧﺗﯾوم‬ ‫ﻹﻧﺗﺎج‬ ‫اﻟﻧووي‬ ‫اﻟﺗﻔﺎﻋل‬ ‫ﻣﻌﺎدﻟﺔ‬ ‫أﻛﺗب‬
‫اﻟﻣوﻟﯾﺑدان‬ ‫ﻣن‬ ‫اﻧطﻼﻗﺎ‬
.
‫؟‬ ‫اﻟﺣﺎﺻل‬ ‫اﻟﺗﻔﻛك‬ ‫ﻧﻣط‬ ‫ﻣﺎھو‬
‫ب‬
-
‫اﻟﻣﺗﺣررة‬ ‫اﻟطﺎﻗﺔ‬ ‫أﺣﺳب‬ ‫اﻟﺣﺎدث‬ ‫اﻟﻧووي‬ ‫اﻟﺗﺣول‬ ‫ﯾواﻓق‬ ‫ﻟﻠطﺎﻗﺔ‬ ‫ﻣﺧططﺎ‬ ‫أﻧﺟز‬
ℓ
‫ذﻟك‬ ‫ﺧﻼل‬
.
2
(
‫اﻟﺗﻛﻧﺳﯾوم‬ ‫ﯾﺳﺗﻌﻣل‬
‫ﺑﺟرﻋﺔ‬ ‫اﻹﻧﺳﺎن‬ ‫ﺟﺳم‬ ‫ﺣﻘن‬ ‫ﯾﺗم‬ ‫ﺣﯾث‬ ، ‫ﺗﺷﺧﯾﺻﮭﺎ‬ ‫ﻗﺻد‬ ‫اﻹﻧﺳﺎن‬ ‫ﻟﻌظﺎم‬ ‫اﻹﺷﻌﺎﻋﻲ‬ ‫ﺑﺎﻟﻧﺷﺎط‬ ‫اﻟﺗﺻوﯾر‬ ‫ﻓﻲ‬
‫اﻟﻣﺷﻊ‬ ‫اﻟﺗﻛﻧﯾﺗﯾوم‬ ‫ﻋﻠﻰ‬ ‫ﺗﺣﺗوي‬
‫اﻟﻣﻔﺣوﺻﺔ‬ ‫ﻟﻠﻌظﺎم‬ ‫ﺻورة‬ ‫ﻋﻠﻰ‬ ‫ﻟﻠﺣﺻول‬ ‫زﻣﻧﯾﺔ‬ ‫ﻣدة‬ ‫ﺑﻌد‬ ‫ُﺳﺗﻛﺷف‬‫ﯾ‬ ‫واﻟذي‬
.
‫ﻓﻲ‬ ‫ﻧﻌطﻲ‬
‫اﻟﺷﻛل‬
-
1
-
‫اﻷ‬ ‫ﻋدد‬ ‫ﺑدﻻﻟﺔ‬ ‫اﻹﺷﻌﺎﻋﻲ‬ ‫اﻟﻧﺷﺎط‬ ‫ﻟﺗﻐﯾرات‬ ‫اﻟﺑﯾﺎﻧﻲ‬ ‫اﻟﻣﻧﺣﻧﻰ‬
‫اﻟﻣﺗﻔﻛﻛﺔ‬ ‫ﻧوﯾﺔ‬
= ( )
.
2
-
1
(
‫أ‬
-
‫اﻹﺷﻌﺎﻋﻲ‬ ‫اﻟﻧﺷﺎط‬ ‫ﺛﺎﺑت‬ ‫ﻗﯾﻣﺔ‬ ‫أوﺟد‬ ‫اﻟﻣﺑﯾن‬ ‫اﻟﺑﯾﺎﻧﻲ‬ ‫اﻟﻣﻧﺣﻧﻰ‬ ‫ﻋﻠﻰ‬ ‫ﺑﺎﻻﻋﺗﻣﺎد‬

‫ﻟﻠﺗﻛﻧﯾﺳﯾوم‬
.
‫ب‬
-
‫ھﻲ‬ ‫ﻟﮫ‬ ‫اﻟﻌﻣر‬ ‫ﻧﺻف‬ ‫زﻣن‬ ‫ﻗﯾﻣﺔ‬ ّ‫أن‬ ‫ﻣن‬ ‫ﺗﺣﻘق‬
:
½ =
.
‫ﻋﻧد‬ ‫اﻹﺷﻌﺎﻋﻲ‬ ‫ﻧﺷﺎطﮭﺎ‬ ‫ﺑﺣﻘﻧﺔ‬ ‫إﻧﺳﺎن‬ ‫ﺟﺳم‬ ‫ﺣﻘن‬ ‫ﺗم‬
= 0
‫ھو‬
‫ﻟﺣظﺔ‬ ‫ﻋﻧد‬ ‫اﻟﻣﻔﺣوﺻﺔ‬ ‫ﻟﻠﻌظﺎم‬ ‫ﺻورة‬ ‫أﺧذ‬ ‫ﻟﯾﺗم‬
‫ﺗﺻﺑﺢ‬ ‫ﺣﯾث‬
‫ﻋﻧدھﺎ‬ ‫اﻹﺷﻌﺎﻋﻲ‬ ‫اﻟﻧﺷﺎط‬ ‫ﻗﯾﻣﺔ‬
t
‫ھو‬
60%
‫ﻗﯾﻣﺔ‬ ‫ﻣن‬
.
2
-
2
(
‫ﻗﯾﻣﺔ‬ ‫ﺣدد‬
‫اﻟﻠﺣظﺔ‬ ‫ﻋﻧد‬ ‫ﺑﮭﺎ‬ ‫اﻟﺟﺳم‬ ‫ﺣﻘن‬ ‫ﺗم‬ ‫اﻟﺗﻲ‬ ‫اﻟﻣﺷﻌﺔ‬ ‫اﻷﻧوﯾﺔ‬ ‫ﻋدد‬
= 0
.
2
-
3
-
(
‫ﺑﺎﻟﺳﺎﻋﺔ‬ ‫ﺣدد‬
)
ℎ
(
‫ﻗﯾﻣﺔ‬
.
‫اﻟﻣﻌطﯾﺎت‬
:
1 = 931,5 .
،
= 1,0073
= 0,00055
،
= 1,0087
‫اﻟﺼﻔﺤﺔ‬
1
/
4
‫اﻟﻧواة‬
( )
( )
( )
ℓ( )
ℓ =
852,10
ℓ =
852,53
ℓ =
836,28

2. ‫اﻟﺗﻣرﯾن‬
‫اﻟﺛﺎﻧﻲ‬
:
)
,0
6
0
‫ﻧﻘطﺔ‬
(
‫ﻧﺿﻊ‬
‫ﻛﺄس‬ ‫ﻓﻲ‬
‫ﺣﺟﻣﺎ‬
‫اﻟﺻودﯾوم‬ ‫ﻟﮭﯾدروﻛﺳﯾد‬ ‫ﻣﺎﺋﻲ‬ ‫ﻣﺣﻠول‬ ‫ﻣن‬
)
( ) , ( )
(
‫ﻣﺎدﺗﮫ‬ ‫ﻛﻣﯾﺔ‬
‫اﻟﻣوﻟﻲ‬ ‫وﺗرﻛﯾزه‬
= 10 ℓ.
‫ﻟﺣظﺔ‬ ‫ﻋﻧد‬ ‫إﻟﯾﮫ‬ ‫ﻧﺿﯾف‬ ‫ﺛم‬
= 0
‫اﻟﻣﺎدة‬ ‫ﻛﻣﯾﺔ‬ ‫ﻧﻔس‬ ،
‫ﺗﻔﺎﻋﻠﻲ‬ ‫ﺧﻠﯾط‬ ‫ﻋﻠﻰ‬ ‫ﻟﻧﺣﺻل‬ ‫اﻹﯾﺛﯾل‬ ‫إﯾﺗﺎﻧوات‬ ‫ﻣن‬
‫ﺣﺟﻣﮫ‬ ‫اﻟﻣوﻻت‬ ‫ﻣﺗﺳﺎوي‬
≈ = 10
.
‫ﻧﻧﻣذج‬
‫ﺑﯾن‬ ‫ﯾﺣدث‬ ‫اﻟذي‬ ‫اﻟﻛﯾﻣﯾﺎﺋﻲ‬ ‫اﻟﺗﺣول‬
‫اﻹﯾﺛﯾل‬ ‫إﯾﺗﺎﻧوات‬
‫و‬
‫اﻟﺻودﯾوم‬ ‫ﻟﮭﯾدروﻛﺳﯾد‬
‫اﻟﺗﺎﻟﯾﺔ‬ ‫ﺑﺎﻟﻣﻌﺎدﻟﺔ‬
:
(ℓ) + ( ) −→ ( ) + − ( )
1
-
‫أ‬
-
‫ﻟﻠﺗﻔﺎﻋل‬ ‫اﻷﻋظﻣﻲ‬ ‫اﻟﺗﻘدم‬ ‫واﺳﺗﻧﺗﺞ‬ ‫اﻟﺗﻔﺎﻋل‬ ‫ﻟﺗﻘدم‬ ‫ﺟدوﻻ‬ ‫أﻧﺟز‬
.
‫ب‬
-
‫اﻟﺗﻔ‬ ‫ﻟﻠوﺳط‬ ‫اﻟﻧوﻋﯾﺔ‬ ‫اﻟﻧﺎﻗﻠﯾﺔ‬ ‫ﻋﺑﺎرة‬ ‫أﻛﺗب‬
‫ﺎﻋﻠﻲ‬
:

)
‫ﻋﻧد‬
= 0
(
.

( )
)
‫ﻟﻣﺎ‬
> 0
(
‫ﺑدﻻﻟﺔ‬
،
،
،

‫و‬

.
‫ج‬
-
‫اﻟﺑﯾﺎﻧﻲ‬ ‫اﻟﻣﻧﺣﻧﻰ‬ ‫ﻋﻠﻰ‬ ‫ﺑﺎﻻﻋﺗﻣﺎد‬
= ( )
‫ا‬
‫ﻟﺷﻛل‬
)
2
(
‫ﻋﺑﺎرة‬ ‫أﻛﺗب‬
( )
‫ﺑدﻻﻟﺔ‬
.
‫د‬
-
‫اﻟﺳؤاﻟﯾن‬ ‫ﺑﺈﺟﺎﺑﺔ‬ ‫ﺑﺎﻻﺳﺗﻌﺎﻧﺔ‬
)
‫ب‬
–
‫ج‬
(
‫اﻟﻧﺎﻗﻠﯾﺔ‬ ‫ﺗﻧﺎﻗص‬ ‫ﺳﺑب‬ ‫ّن‬‫ﯾ‬‫ﺑ‬
‫اﻟﺗﻔﺎﻋﻠﻲ‬ ‫اﻟوﺳط‬ ‫ﻓﻲ‬ ‫اﻟﻧوﻋﯾﺔ‬
.
2
-
‫اﻟﻛﯾﻣﺎﺋﻲ‬ ‫اﻟﺗﺣول‬ ‫ﻟﺗطور‬ ‫اﻟزﻣﻧﯾﺔ‬ ‫اﻟﻣﺗﺎﺑﻌﺔ‬
:
‫ﺗطور‬ ‫ﻧﺗﺗﺑﻊ‬
‫اﻟﻧﺎﻗﻠﯾﺔ‬ ‫ﻗﯾﺎس‬ ‫طرﯾق‬ ‫ﻋن‬ ‫اﻟﻛﯾﻣﺎﺋﻲ‬ ‫اﻟﺗﺣول‬
‫ﺑواﺳطﺔ‬ ‫ﻟﻧﺣﺻل‬ ‫اﻟزﻣن‬ ‫ﺧﻼل‬ ‫اﻟﺗﻔﺎﻋﻠﻲ‬ ‫ﻟﻠﻣزﯾﺞ‬ ‫اﻟﻧوﻋﯾﺔ‬
‫اﻟﺑﯾﺎﻧﻲ‬ ‫اﻟﻣﻧﺣﻧﻰ‬ ‫ﻋﻠﻰ‬ ‫ﻣﻌﻠوﻣﺎﺗﯾﺔ‬ ‫ﺑرﻣﺟﯾﺔ‬
= ( )
‫اﻟﺷﻛل‬ ‫ﻓﻲ‬
)
3
(
.
2
-
1
(
‫أﺣﺳب‬
½
‫اﻟﻧوﻋﯾﺔ‬ ‫اﻟﻧﺎﻗﻠﯾﺔ‬
‫اﻟﺗﻔﺎﻋﻠﻲ‬ ‫ﻟﻠﺧﻠﯾط‬
‫ﺛم‬
‫اﻟﺗﻔﺎﻋل‬ ‫ﻧﺻف‬ ‫زﻣن‬ ‫اﺳﺗﻧﺗﺞ‬
½
.
2
-
3
(
‫اﻟﺗﻔﺎﻋل‬ ‫ﺣرﻛﯾﺔ‬
:
‫أ‬
(
‫ﻟﻠﺗﻔﺎﻋل‬ ‫اﻟﺣﺟﻣﯾﺔ‬ ‫اﻟﺳرﻋﺔ‬ ‫ﻋرف‬
‫ﺑدﻻﻟﺔ‬ ‫ﻋﺑﺎرﺗﮭﺎ‬ ‫أوﺟد‬ ‫ﺛم‬
( )
.
‫ب‬
-
‫ﺑﺎﻟوﺣدة‬ ‫ﻟﻠﺗﻔﺎﻋل‬ ‫اﻟﺣﺟﻣﯾﺔ‬ ‫اﻟﺳرﻋﺔ‬ ‫أﺣﺳب‬
)
ℓ . .
(
‫اﻟﻠﺣظﺗﯾن‬ ‫ﻋﻧد‬
) :
= 0
(
‫و‬
)
= 35
(
.
‫ﻟﻠﺗﻔﺎﻋل‬ ‫اﻟﺣﺟﻣﯾﺔ‬ ‫اﻟﺳرﻋﺔ‬ ‫ﺗطور‬ ‫اﺷرح‬
.
‫ﻣﻌطﯾﺎت‬
:
‫اﻟﺷﺎردة‬
( )
( )
( )
‫ﺑـ‬ ‫اﻟﺷﺎردﯾﺔ‬ ‫اﻟﻣوﻟﯾﺔ‬ ‫اﻟﻧوﻋﯾﺔ‬ ‫اﻟﻧﺎﻗﻠﯾﺔ‬
‫ى‬
)
. .
(



‫اﻟﺼﻔﺤﺔ‬
2
/
4

3. ‫اﻟﺗﻣرﯾن‬
‫اﻟﺛﺎﻟث‬
:
)
5
04,
‫ﻧﻘطﺔ‬
(
‫اﻟﻛﮭرﺑﺎﺋﯾﺔ‬ ‫اﻟدارة‬ ‫ﺗﻌﺗﺑر‬
‫اﻟﻛﮭرﺑﺎﺋﯾﺔ‬ ‫اﻷﺟﮭزة‬ ‫ﻣن‬ ‫ﻟﻣﺟﻣوﻋﺔ‬ ‫اﻹﻟﻛﺗروﻧﯾﺔ‬ ‫اﻟﺗراﻛﯾب‬ ‫ﻓﻲ‬ ‫اﻟﻣﺳﺗﻌﻣﻠﺔ‬ ‫اﻟﻛﮭرﺑﺎﺋﯾﺔ‬ ‫اﻟدارات‬ ‫ﺑﯾن‬ ‫ﻣن‬
.
‫ﻓﻲ‬ ‫اﻟﻣﺑﯾن‬ ‫اﻟﺗرﻛﯾب‬ ‫ﯾﺗﻛون‬
‫اﻟﺷﻛل‬
-
4
-
‫ﻣن‬
:
-
‫اﻟﻛﮭرﺑﺎﺋﯾﺔ‬ ‫اﻟﻣﺣرﻛﺔ‬ ‫ﻗوﺗﮫ‬ ‫ﻟﻠﺗوﺗر‬ ‫ﻣﺛﺎﻟﻲ‬ ‫ﻣوﻟد‬
.
-
‫ﺳﻌﺗﺎھﻣﺎ‬ ‫ﻣﻛﺛﻔﺗﯾن‬
‫و‬
= 2
.
-
‫ﻣﻘﺎوﻣﺗﮫ‬ ‫اوﻣﻲ‬ ‫ﻧﺎﻗل‬
= 3 
.
-
‫ﻟﻠﺗﯾﺎر‬ ‫ﻗﺎطﻌﺔ‬
.
‫ﻟﻸزﻣﻧﺔ‬ ‫ﻣﺑدءا‬ ‫ﻧﺧﺗﺎرھﺎ‬ ‫ﻟﺣظﺔ‬ ‫ﻋﻧد‬
)
= 0
(
‫اﻟﻘﺎطﻌﺔ‬ ‫ﻧﻐﻠق‬ ،
.
1
-
‫اﻟﺳﻌﺔ‬ ‫أن‬ ‫ّن‬‫ﯾ‬‫ﺑ‬
Cé
‫ھﻲ‬ ‫اﻟدارة‬ ‫ﻓﻲ‬ ‫اﻟﻣﻛﺎﻓﺋﺔ‬ ‫ﻟﻠﻣﻛﺛﻔﺔ‬
:
1. 2
1+ 2
Cé =
.
2
-
‫أ‬
-
‫اﻟﺗوﺗر‬ ‫ﯾﺣﻘﻘﮭﺎ‬ ‫اﻟﺗﻲ‬ ‫اﻟﺗﻔﺎﺿﻠﯾﺔ‬ ‫اﻟﻣﻌﺎدﻟﺔ‬ ‫أن‬ ‫ّن‬‫ﯾ‬‫ﺑ‬
( )
‫ذ‬ ‫اﻟﻣﻛﺛﻔﺔ‬ ‫طرﻓﻲ‬ ‫ﺑﯾن‬
‫ات‬
‫اﻟﺳﻌﺔ‬
‫ﺗﻛﺗب‬
‫ﺑﺎﻟﺷﻛل‬
:
( )
+
é
2( ) =
2
‫ب‬
-
‫اﻟﻣﻌﺎدﻟﺔ‬ ‫ھذه‬ ‫ﺣل‬ ‫ﯾﻛﺗب‬
‫اﻟﺷﻛل‬ ‫ﻋﻠﻰ‬
:
( ) = (1 − ∝
)
.
-
‫اﻟﺛﺎﺑﺗﯾن‬ ‫ﻣن‬ ‫ﻛل‬ ‫ﻋﺑﺎرة‬ ‫ﺣدد‬
‫و‬
∝
‫ﻟﻠدارة‬ ‫اﻟﻣﻣﯾزة‬ ‫اﻟﻣﻘﺎدﯾر‬ ‫ﺑدﻻﻟﺔ‬
.
‫ج‬
-
‫اﻟﻛﮭرﺑﺎﺋﻲ‬ ‫اﻟﺗﯾﺎر‬ ‫ﺷدة‬ ‫ﻋﺑﺎرة‬ ‫اوﺟد‬
( )
‫اﻟﻣﻛﺛﻔﺔ‬ ‫ﺷﺣﻧﺔ‬ ‫وﻛذا‬
( )
.
3
-
‫ﯾﻣﺛل‬
②
‫و‬
①
‫ﻣﻧﺣﻧﯾﺎ‬
‫اﻟﺷﻛل‬
–
5
-
‫اﻟﻛﮭرﺑﺎﺋﯾﯾن‬ ‫اﻟﺗوﺗرﯾن‬ ‫ﺗطور‬
( )
‫و‬
( )
.
‫أ‬
-
‫اﻟﺗﺑرﯾر‬ ‫ﻣﻊ‬ ‫اﻟﻣﻧﺎﺳب‬ ‫ﻟﻠﺗوﺗر‬ ‫ﺑﯾﺎﻧﻲ‬ ‫ﻣﻧﺣﻧﻰ‬ ‫ﻛل‬ ‫أﻧﺳب‬
.
‫ب‬
-
‫اﻟﺗوﺗر‬ ‫ﻗﯾﻣﺔ‬ ‫ﺣدد‬
‫اﻷﻋظﻣﻲ‬ ‫اﻟﺗﯾﺎر‬ ‫ﺷدة‬ ‫وأﺣﺳب‬
.
‫ج‬
-
‫اﻟزﻣن‬ ‫ﺛﺎﺑت‬ ‫ﻗﯾﻣﺔ‬ ‫ﺑﯾﺎﻧﯾﺎ‬ ‫أوﺟد‬
‫ﺛم‬
‫أن‬ ‫ّن‬‫ﯾ‬‫ﺑ‬
:
= 4
.
4
-
‫اﻟﻣﻛﺎﻓﺋﺔ‬ ‫اﻟﻣﻛﺛﻔﺔ‬ ‫ﻓﻲ‬ ‫اﻟﻣﺧزﻧﺔ‬ ‫ﻟﻠطﺎﻗﺔ‬ ‫اﻷﻋظﻣﯾﺔ‬ ‫اﻟﻘﯾﻣﺔ‬ ‫أﺣﺳب‬
.
‫اﻟراﺑﻊ‬ ‫اﻟﺗﻣرﯾن‬
:
)
5
,
4
0
‫ﻧﻘطﺔ‬
(
‫ﻓﻲ‬ ‫اﻟﻣﺑﯾن‬ ‫اﻟﺗرﻛﯾب‬ ‫ﻧﻧﺟز‬
‫اﻟﺷﻛل‬
-
6
-
‫ﻣن‬ ‫واﻟﻣﻛون‬
:
-
‫اﻟﻛﮭرﺑﺎﺋﯾﺔ‬ ‫اﻟﻣﺣرﻛﺔ‬ ‫ﻗوﺗﮫ‬ ‫ﻟﻠﺗوﺗر‬ ‫ﻣﺛﺎﻟﻲ‬ ‫ﻣوﻟد‬
= 12
-
‫وﺷﯾﻌﺔ‬
‫ﻣﺛﺎﻟﯾﺔ‬
‫ﺗﺣرﯾﺿﮭﺎ‬ ‫ﻣﻌﺎﻣل‬
)
‫ذاﺗﯾﺗﮭﺎ‬
(
.
-
‫اوﻣﯾﯾن‬ ‫ﻧﺎﻗﻠﯾن‬
‫ﻣﻘﺎوﻣﺎﺗﮭﻣﺎ‬
= 40
‫و‬
-
‫اﻟﻛﮭرﺑﺎﺋﻲ‬ ‫ﻟﻠﺗﯾﺎر‬ ‫ﻗﺎطﻌﺔ‬
.
‫اﻟﺼﻔﺤﺔ‬
3
/
4

4. ‫ﻟﻸزﻣﻧﺔ‬ ‫ﻣﺑدءا‬ ‫ﻧﺧﺗﺎرھﺎ‬ ‫ﻟﺣظﺔ‬ ‫ﻋﻧد‬
)
= 0
(
‫اﻟﻘﺎطﻌﺔ‬ ‫ﻧﻐﻠق‬ ،
‫ﺑﺎﻟدارة‬ ‫ﻣوﺻل‬ ‫ﻣﻌﻠوﻣﺎﺗﻲ‬ ‫ﻧظﺎم‬ ‫وﺑواﺳطﺔ‬
)
‫ﯾظﮭر‬ ‫ﻻ‬
‫اﻟدارة‬ ‫ﻓﻲ‬
(
‫اﻟﻣﻧﺣﻧﯾﯾن‬ ‫ﻋﻠﻰ‬ ‫ﻧﺣﺻل‬
( )
‫و‬
( )
‫اﻟﻣدﺧﻠﯾن‬ ‫ﻋﻧد‬ ‫ﻟﻠﺗوﺗرﯾن‬ ‫اﻟﻣﻣﺛﻠﯾن‬
A
‫و‬
B
‫اﻟﺷﻛل‬
-
7
-
.
1
-
‫اﻟﺗوﺗر‬ ‫ﯾﻣﺛل‬ ‫اﻟذي‬ ‫اﻟﻣﻧﺣﻧﻰ‬ ‫ّن‬‫ﯾ‬‫ﻋ‬
( )
‫اﻟﺗوﺗر‬ ‫ﯾﻣﺛل‬ ‫اﻟذي‬ ‫واﻟﻣﻧﺣﻧﻰ‬
( )
.
2
-
‫ﻗﯾﻣﺔ‬ ‫ﺣدد‬
‫اﻟداﺋم‬ ‫اﻟﻧظﺎم‬ ‫ﻓﻲ‬ ‫اﻟﻛﮭرﺑﺎﺋﻲ‬ ‫اﻟﺗﯾﺎر‬ ‫ﺷدة‬ ،
.
3
-
‫اﻟﻣﻘﺎوﻣﺔ‬ ‫ﻗﯾﻣﺔ‬ ‫أن‬ ‫ﻣن‬ ‫ﺗﺣﻘق‬
‫ﻟﻠﻧﺎﻗل‬
‫اﻷوﻣﻲ‬
‫ھﻲ‬
= 8 
.
4
-
‫أﺛﺑت‬ ‫اﻟﺗوﺗرات‬ ‫ﺟﻣﻊ‬ ‫ﻗﺎﻧون‬ ‫ﺑﺎﺳﺗﻌﻣﺎل‬
‫اﻟﺗﻲ‬ ‫اﻟﺗﻔﺎﺿﻠﯾﺔ‬ ‫اﻟﻣﻌﺎدﻟﺔ‬
‫اﻟﻛﮭرﺑﺎﺋﻲ‬ ‫اﻟﺗوﺗر‬ ‫ﯾﺣﻘﻘﮭﺎ‬
( )
.
5
-
‫اﻟﺷﻛل‬ ‫ﻣن‬ ‫ھو‬ ‫اﻟﺗﻔﺎﺿﻠﯾﺔ‬ ‫اﻟﻣﻌﺎدﻟﺔ‬ ‫ﺣل‬ ‫أن‬ ‫ﻋﻠﻣﺎ‬
:
(1 − )
( ) =
.
‫اﻟﺛﺎﺑﺗﯾن‬ ‫ﻋﺑﺎرﺗﻲ‬ ‫أوﺟد‬
‫و‬
‫ﻟﻠدارة‬ ‫اﻟﻣﻣﯾزة‬ ‫اﻟﻣﻘﺎدﯾر‬ ‫ﺑدﻻﻟﺔ‬
.
6
-
‫اﻟزﻣن‬ ‫ﺛﺎﺑت‬ ‫ﻗﯾﻣﺔ‬ ‫ﺣدد‬
‫ﻟﻠدارة‬
.
7
-
‫اﻟﺗﺣرﯾض‬ ‫ﻣﻌﺎﻣل‬ ‫ﻗﯾﻣﺔ‬ ‫اﺳﺗﻧﺗﺞ‬
‫ﻟﻠوﺷﯾﻌﺔ‬
.
8
-
‫اﻟﻠﺣظﺔ‬ ‫ﻋﻧد‬ ‫اﻟوﺷﯾﻌﺔ‬ ‫ﻓﻲ‬ ‫اﻟﻣﺧزﻧﺔ‬ ‫اﻟطﺎﻗﺔ‬ ‫أﺣﺳب‬
=
.
‫اﻟﺼﻔﺤﺔ‬
4
/
4

5. ‫ﻋﺒﺪاﻟﻘﺎدر‬ ‫ﻳﻒ‬‫ﺮ‬‫ﺷ‬ ‫ﺣﻤﺪي‬ ‫ﺛﺎﻧﻮﻳﺔ‬
–
‫ﻋﺸﻌﺎﺷﺔ‬
-
‫ﻟﻤﺎدة‬ ‫اﻷول‬ ‫اﻟﻔﺼﻞ‬ ‫اﻣﺘﺤﺎن‬ ‫ﺗﺼﺤﻴﺢ‬
‫ﻳﺎﺋﻴﺔ‬‫ﺰ‬‫اﻟﻔﻴ‬ ‫اﻟﻌﻠﻮم‬
–
‫اﻟﺜﺎ‬ ‫اﻟﺴﻨﺔ‬
‫ﻟﺜﺔ‬
‫ﺷﻌﺒ‬
‫ﺔ‬
)
‫ﻳﺎﺿﻴﺎت‬‫ر‬
(
‫اﺳﻴﺔ‬‫ر‬‫اﻟﺪ‬ ‫اﻟﺴﻨﺔ‬
:
2016
-
2017
‫د‬
-
‫اﻟﻧﺎﻗﻠﯾﺔ‬ ‫ﺗﻧﺎﻗص‬ ‫ﺳﺑب‬
‫اﻟﺗﻔﺎﻋﻠﻲ‬ ‫اﻟوﺳط‬ ‫ﻓﻲ‬ ‫اﻟﻧوﻋﯾﺔ‬
.
‫اﻟﻌﻼﻗﺗﯾن‬ ‫ﺑﻣطﺎﺑﻘﺔ‬

‫و‬

:
 −  < 0 ⇒  < 
2
-
1
(
‫ﺣﺳ‬
‫ﺎ‬
‫ب‬
½
‫اﺳﺗﻧﺗ‬ ‫ﺛم‬
‫ﺎ‬
‫ج‬
½
.
σ½
= 0,25 − 160 2
⇒ σ½
= 0,17 . −1
= 170 . −1
⟹ ½ = 12
2
-
1
-
‫اﻟﺗﻔﺎﻋل‬ ‫ﺣرﻛﯾﺔ‬
:
‫أ‬
(
‫ﻟﻠﺗﻔﺎﻋل‬ ‫اﻟﺣﺟﻣﯾﺔ‬ ‫اﻟﺳرﻋﺔ‬
‫ﺑدﻻﻟﺔ‬ ‫ﻋﺑﺎرﺗﮭﺎ‬
( )
:
‫واﺣدة‬ ‫ﻓﻲ‬ ‫اﻟزﻣن‬ ‫ﺧﻼل‬ ‫اﻟﺗﻔﺎﻋل‬ ‫ﺗﻘدم‬ ‫ﺗﻐﯾرات‬ ‫ﻣﻘدار‬ ‫ھﻲ‬
‫وﻧﻛﺗب‬ ‫اﻟﺣﺟوم‬
:
=
= −
,
‫ب‬
-
‫ﺣﺳ‬
‫ﺎ‬
‫ب‬
‫ﺑﺎﻟوﺣدة‬
)
ℓ . .
(
‫ﻋﻧد‬
‫اﻟﻠﺣظﺗﯾن‬
) :
= 0
(
‫و‬
)
= 35
. (
= ×
‖ ‖
‖ ‖
(0) = 0,52 ℓ . .
(35min) = 0,083 ℓ . .
‫ﻟﻠﺗﻔﺎﻋل‬ ‫اﻟﺣﺟﻣﯾﺔ‬ ‫اﻟﺳرﻋﺔ‬ ‫ﺗطور‬ ‫ﺷرح‬
.
(0) > (35min)
‫ﺧﻼل‬ ‫اﻟﻣﺗﻔﺎﻋﻼت‬ ‫ﺗراﻛﯾز‬ ‫ﺗﻧﺎﻗص‬ ‫ﺑﺑﺳﺑب‬ ‫ﺗﺗﻧﺎﻗص‬ ‫اﻟﺗﻔﺎﻋل‬ ‫ﺳرﻋﺔ‬
‫اﻟزﻣن‬
.
‫ﻧﺟد‬ ‫ﺑﺎﻟﻣطﺎﺑﻘﺔ‬
:
= . = = 5. 10
Bq
 = − = ×
‖ ‖
‖ ‖
= 3,22. 10
‫ب‬
-
ّ‫أن‬ ‫ﻣن‬ ‫ﺗﺣﻘق‬
½ =
:
½ =
ℓ

= , . ≈
2
-
2
-
‫ﻗﯾﻣﺔ‬
‫اﻟﻠﺣظﺔ‬ ‫ﻋﻧد‬
= 0
:
= . ⇒ = 
= 1,55. 10
2
-
3
-
‫ﺗ‬
‫ﺣد‬
‫ﯾ‬
‫ﺑﺎﻟﺳﺎﻋﺔ‬ ‫د‬
)
ℎ
(
‫ﻗﯾﻣﺔ‬
:
= 0. − ⇒ 0,60 = 
⇒ =

ℓ 0
= 4,4 ℎ
‫اﻟﺛﺎﻧﻲ‬ ‫اﻟﺗﻣرﯾن‬
06
‫ﻧﻘط‬
:
1
-
‫أ‬
-
‫ﻟﻠﺗﻔﺎﻋل‬ ‫اﻷﻋظﻣﻲ‬ ‫اﻟﺗﻘدم‬ ‫واﺳﺗﻧﺗﺞ‬ ‫اﻟﺗﻔﺎﻋل‬ ‫ﻟﺗﻘدم‬ ‫ﺟدوﻻ‬ ‫أﻧﺟز‬
.
‫ﻟﻠﺗﻔﺎﻋل‬ ‫اﻷﻋظﻣﻲ‬ ‫اﻟﺗﻘدم‬
:
− = 0 ⟹ = = = 10 ℓ
‫ب‬
-
‫اﻟﺗﻔﺎﻋﻠﻲ‬ ‫ﻟﻠوﺳط‬ ‫اﻟﻧوﻋﯾﺔ‬ ‫اﻟﻧﺎﻗﻠﯾﺔ‬ ‫ﻋﺑﺎرة‬
:
=  [ ] +  [ ] ⟹ = ( +  )
( ) =  [ ] +  [ ] +  2 3 2( )
−
( ) =  + 
+  = ( +  ) + ( −  )

………………
( ) = + ( −  )
‫ج‬
-
‫ﻋﺑﺎرة‬
( )
‫ﺑدﻻﻟﺔ‬
.
( ) = +
= = 0,25 .
= ×
‖ ‖
‖ ‖
≈ −160 / . ℓ.

…
…………………
⇒ ( ) = 0,25 − 160
(ℓ) + ( ) −→ ( ) + − ( )
‫اﻟﺗﻔﺎﻋل‬ ‫ﻣﻌﺎدﻟﺔ‬
‫ﺑـ‬ ‫اﻟﻣﺎدة‬ ‫ﻛﻣﯾــــــــــﺎت‬
( ℓ)
‫اﻟﺗﻘدم‬
‫اﻟ‬
‫ﺣﺎﻟﺔ‬
0
0
‫إﺑﺗدا‬
−
−
‫اﻧﺗﻘﺎ‬
−
−
‫ﻧﮭﺎ‬
‫اﻷول‬ ‫اﻟﺗﻣرﯾن‬
:
06
‫ﻧﻘطﺔ‬
1
-
1
(
‫اﻟﻧظﯾر‬ ‫ﻧواة‬ ‫ﺗرﻛﯾب‬
:
43 + 56
1
-
2
(
‫اﻟﺗﻌﻠﯾل‬ ‫ﻣﻊ‬ ‫اﺳﺗﻘرارا‬ ‫اﻷﻛﺛر‬ ‫اﻟﻧواة‬
.
ℓ
= 8,621 / é
ℓ
= 8,611 / é
‫اﻟﻧواة‬
‫اﻟﻧواة‬ ‫ﻣن‬ ‫اﺳﺗﻘرارا‬ ‫أﻛﺛر‬
‫ﻷن‬
⇒ ℓ
> ℓ
3
-
‫أ‬
-
‫اﻟﺗﻛﻧﺗﯾوم‬ ‫ﻹﻧﺗﺎج‬ ‫اﻟﻧووي‬ ‫اﻟﺗﻔﺎﻋل‬ ‫ﻣﻌﺎدﻟﺔ‬
.
⟶ +
‫ﺻودي‬ ‫ﻗﺎﻧوﻧﻲ‬ ‫ﺣﺳب‬
99 = 99 +
42 = 43 +
⇒
= 0
= −1
⟹ ⇛
‫اﻟﺗﻔﻛك‬ ‫ﻧﻣط‬
:
)
‫اﻟﻛﺗرون‬
(
⟶ +
‫ب‬
-
‫وﺣﺳ‬ ‫ﻟﻠطﺎﻗﺔ‬ ‫ﻣﺧطط‬
‫ﺎ‬
‫اﻟﻣﺗﺣررة‬ ‫اﻟطﺎﻗﺔ‬ ‫ب‬
ℓ
:
ℓ = − ℓ + + − . − ℓ
ℓ = −[852,10 + (1,0073 + 0,00055 − 1,0087).931,5 − 852,53]
= 737,96
2
-
1
(
‫أ‬
-
‫اﻟﻣﻧﺣﻧﻰ‬ ‫ﻋﻠﻰ‬ ‫ﺑﺎﻻﻋﺗﻣﺎد‬
= ( )
‫إﯾﺟﺎد‬

‫ﻟـ‬
.
‫ﻟدﯾﻧﺎ‬
:
( ) =  ( ) = . − . … … … … . ‫ ﻧظرﯾﺎ‬
( ) = + . … … … … … … … … . . … . ‫ ﺑﯾﺎﻧﯾﺎ‬

6. ⇒ =
− ( )
⇒ =
12 − 10
0,25
= 8 
4
-
‫ﺗﺣﻘﻘﮭﺎ‬ ‫اﻟﺗﻲ‬ ‫اﻟﺗﻔﺎﺿﻠﯾﺔ‬ ‫اﻟﻣﻌﺎدﻟﺔ‬
( )
:
∀ ≥ 0 ∶ ( ) + ( ) + ( ) =
( ) =
( )
=
( )
⇒
( ) =
( )
( ) =
( )
⇒ ( ) +
( )
+
( )
=
⟹
( )
+
( )
( ) =
5
-
‫اﻟﺷﻛل‬ ‫ﻣن‬ ‫ھو‬ ‫اﻟﺗﻔﺎﺿﻠﯾﺔ‬ ‫اﻟﻣﻌﺎدﻟﺔ‬ ‫ﺣل‬
:
.
(1 − )
( ) =
-
‫اﻟﺛﺎﺑﺗﯾن‬ ‫ﻋﺑﺎرﺗﻲ‬ ‫إﯾﺟﺎد‬
:
‫و‬
( )
= A.
A. +
( )
−
( )
=
⇒
( + ) =
=
( ) ⇒
= ( )
=
=
( )
6
-
‫اﻟزﻣن‬ ‫ﺛﺎﺑت‬ ‫ﻗﯾﻣﺔ‬
‫ﻟﻠدارة‬
:
‫اﻟﺑﯾﺎن‬ ‫ﺑﺎﺳﺗﻌﻣﺎل‬
(
‫ﻧﺣﺳب‬
:
( ) = 0,63 (max) = 6,3 ⇒ =
7
-
‫اﻟﺗﺣرﯾض‬ ‫ﻣﻌﺎﻣل‬ ‫ﻗﯾﻣﺔ‬
‫ﻟﻠوﺷﯾﻌﺔ‬
:
=
( )
⇒ = ( + ) ⇒ =
8
-
‫اﻟطﺎ‬ ‫أﺣﺳب‬
‫ﻋﻧد‬ ‫اﻟوﺷﯾﻌﺔ‬ ‫ﻓﻲ‬ ‫اﻟﻣﺧزﻧﺔ‬ ‫ﻗﺔ‬
:
=
( ) = ½ ( ) ⇒ ( )⌋ = = ½ ( )
= = 1,5 ⇒ = 4
⇒ = ,
( )⌋ = , . . ,
⇒ ( )⌋ = ,
3
-
‫أ‬
-
‫اﺳ‬
‫ﻧﺎد‬
‫اﻟﺗﺑرﯾر‬ ‫ﻣﻊ‬ ‫اﻟﻣﻧﺎﺳب‬ ‫ﻟﻠﺗوﺗر‬ ‫ﻣﻧﺣﻧﻰ‬ ‫ﻛل‬
.
(0) = 0
( ) = 0
⇒
(0) =
( ) = 0
‫اﻟﻣﻧﺣﻧﻰ‬

‫ﻟﻠﺗوﺗر‬
( )
2(0) = 0
2( ) = .
‫اﻟﻣﻧﺣﻧﻰ‬

‫ﻟﻠﺗوﺗر‬
( )
‫ب‬
-
‫اﻟﺗوﺗر‬ ‫ﻗﯾﻣﺔ‬
‫اﻷﻋظﻣﻲ‬ ‫اﻟﻛﮭرﺑﺎﺋﻲ‬ ‫اﻟﺗﯾﺎر‬ ‫ﺷدة‬ ‫وﺣﺳﺎب‬
:
= (0)
= =
.
=
⇒
= 12
= 4. 10
‫ج‬
-
‫ﺗ‬
ّ‫ﯾ‬‫ﺑ‬
‫ﺎ‬
‫أن‬ ‫ن‬
:
=
:
‫ﺑﯾﺎﻧﯾﺎ‬ ‫اﻟزﻣن‬ ‫ﺛﺎﺑت‬ ‫ﻧﺣﺳب‬
:
‫اﻟﺑﯾﺎن‬ ‫ﺑﺎﺳﺗﻌﻣﺎل‬

⇒ = 4
( ) = 0,37 = 4,44
= é ⇒ é = ⇒ é =
4
3
+ =
é
⇒ =
é
− = ⇒ C = 4 μ F
4
-
‫ﺣﺳ‬
‫ﺎ‬
‫اﻟﻣﻛﺎﻓﺋﺔ‬ ‫اﻟﻣﻛﺛﻔﺔ‬ ‫ﻓﻲ‬ ‫اﻟﻣﺧزﻧﺔ‬ ‫ﻟﻠطﺎﻗﺔ‬ ‫اﻷﻋظﻣﯾﺔ‬ ‫اﻟﻘﯾﻣﺔ‬ ‫ب‬
:
( ) = ½Cé
2
= ½
. 2
( ) =
3
8
. 144 = 54
‫اﻟﺗﻣرﯾن‬
‫اﻟراﺑﻊ‬
:
)
0
0
.
4
‫ﻧﻘطﺔ‬
(
1
-
‫اﻟﻣﻧﺣﻧﯾﯾن‬ ‫اﺳﻧﺎد‬
:
∀ ≥ 0 ∶
( ) = − ( )
( ) = ( )
(0) = , ( ) = −
(0) = 0) = 0 , ( ) =
‫اﻟﻣﻧﺣﻧﻰ‬ ‫وﻣﻧﮫ‬
( )
‫ﯾواﻓق‬
( )
‫و‬
‫اﻟﻣﻧﺣﻧﻰ‬
( )
‫ﻟـ‬
( )
2
-
‫ﻗﯾﻣﺔ‬
:
( ) =
( ) = 10
⇒ =
( )
= = 0,25
3
-
‫اﻟﻣﻘﺎوﻣﺔ‬ ‫ﻗﯾﻣﺔ‬ ‫أن‬ ‫ﻣن‬ ‫اﻟﺗﺣﻘق‬
‫ھﻲ‬ ‫اﻷوﻣﻲ‬ ‫ﻟﻠﻧﺎﻗل‬
= 
.
‫اﻟﺛﺎﻟث‬ ‫اﻟﺗﻣرﯾن‬
:
)
0
0
.
4
‫ﻧﻘطﺔ‬
(
=?
‫و‬
= 2
.
=? = 3 
1
-
‫ﺗﺑﯾﺎن‬
‫أن‬
:
1. 2
1+ 2
Cé =
.
= =
+ = + =
é
⇒
1
C1
+
1
C2
=
1
é
⇒ Cé = 1. 2
1+ 2
2
-
‫أ‬
-
‫اﻟﺗﻲ‬ ‫اﻟﺗﻔﺎﺿﻠﯾﺔ‬ ‫اﻟﻣﻌﺎدﻟﺔ‬
( )
:
( )
+
é
2( ) =
2
∀ ≥ 0 ∶ ( ) + ( ) + ( ) =
‫اﻟﺗوﺗرات‬ ‫ﺟﻣﻊ‬ ‫ﻗﺎﻧون‬
( ) = = =
( )
( ) =
é
−
⇒
( )
+
é
=

………….
⟹
( )
+
é
( ) =
‫ب‬
-
‫اﻟﺷﻛل‬ ‫ﻋﻠﻰ‬ ‫اﻟﻣﻌﺎدﻟﺔ‬ ‫ھذه‬ ‫ﺣل‬
:
( ) = (1 − ∝
)
.
‫اﻟﺛﺎﺑﺗﯾن‬ ‫ﻣن‬ ‫ﻛل‬ ‫ﻋﺑﺎرة‬
‫و‬
∝
‫ﻟﻠدارة‬ ‫اﻟﻣﻣﯾزة‬ ‫اﻟﻣﻘﺎدﯾر‬ ‫ﺑدﻻﻟﺔ‬
2
= A ∝ −∝
‫ﻓﻲ‬ ‫ﺑﺎﻟﺗﻌوﯾض‬

:
⇒ A ∝ ∝
+
é
−
é
A ∝
=
⇒ A ∝
∝ −
é
=
−
é
∝ −
1
é
= 0
2
−
1
é
⇒
∝=
1
é
=
1
=
. é
2
= . 1
1+ 2
( ) = . (1 − ∝
)
‫ج‬
-
‫اﻟﻛﮭرﺑﺎﺋﻲ‬ ‫اﻟﺗﯾﺎر‬ ‫ﺷدة‬ ‫ﻋﺑﺎرة‬
( )
‫اﻟﻣﻛﺛﻔﺔ‬ ‫ﺷﺣﻧﺔ‬ ‫وﻛذا‬
( )
:
( ) =
( )
=
( )
⇒ ( ) = 2. . 1
1+ 2
.
1
é
−∝
( ) = Cé (1 −
)
⇒ ( ) =
−
= 0
−