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Calcula las razones trigonométricas seno, coseno y tangente de los ángulos agudos (A y B) del triángulo rectángulo que aparecen abajo.
Donde el valor de a o el
lado del ángulo que falta la
medida se obtiene por
medio del teorema de
Pitágoras.
h= 𝟒. 𝟓𝒄𝒎
a= 2.06 cm
b=4 cm
𝒉𝟐
= 𝒂𝟐
+ 𝒃𝟐
𝒉𝟐
− 𝒃𝟐
= 𝒂𝟐
𝒂𝟐
= 𝒉𝟐
− 𝒃𝟐
𝒂𝟐
= (𝟒. 𝟓𝒄𝒎)𝟐
−(𝟒𝒄𝒎)𝟐
𝒂𝟐
= 𝟐𝟎. 𝟐𝟓𝒄𝒎𝟐
− 𝟏𝟔𝒄𝒎𝟐
𝒂𝟐
= 𝟒. 𝟐𝟓𝒄𝒎𝟐
𝒂𝟐
= 𝟒. 𝟐𝟓𝒄𝒎
𝒂 = 𝟒. 𝟐𝟓𝒄𝒎 = 𝒄𝒎
𝒂 =2.06m
1
2
.
ℎ = 4.5𝑐𝑚
𝑐𝑜 = 2.06 𝑐𝑚
𝑐𝑎 = 4𝑐𝑚
𝑠𝑒𝑛𝑜 =
𝑐𝑜
ℎ
𝐶𝑜𝑠𝑒𝑛𝑜 =
𝑐𝑎
ℎ
𝑡𝑎𝑛𝑔𝑒𝑛𝑡𝑒 =
𝑐𝑜
𝑐𝑎
se cancela seno a la menos 1 por seno y así mismo con arco
coseno y seno, igualmente para tangente y arco tangente.
𝑠𝑒𝑛𝑜−1
𝑠𝑒𝑛𝑜 𝐴 = 𝑠𝑒𝑛𝑜−1
(
2.06𝑐𝑚
4.5𝑐𝑚
)
𝐴 = 𝑠𝑒𝑛𝑜−1
2.06𝑐𝑚
4.5𝑐𝑚
𝑨 = 𝟐𝟕. 𝟐𝟒°
𝐶𝑜𝑠−1
𝐶𝑜𝑠 𝐴 = 𝐶𝑜𝑠−1
4𝑐𝑚
4.5𝑐𝑚
𝐴 = 𝐶𝑜𝑠−1
4𝐶𝑀
4.5𝐶𝑀
𝑨 = 𝟐𝟕. 𝟐𝟒°
𝑡𝑎𝑛𝑔−1
𝑡𝑎𝑛𝑔 𝐴 = 𝑡𝑎𝑛𝑔−1
2.06𝑐𝑚
4𝑐𝑚
𝐴 = 𝑡𝑎𝑛𝑔−1
2.06𝑐𝑚
4𝑐𝑚
𝑨 = 𝟐𝟕. 𝟐𝟒°
h= 𝟒. 𝟓𝒄𝒎
a= 2.06 cm
b=4 cm
Una vez encontrado el valor del los tres lados
de los triángulos rectángulos para el Angulo
𝜶 𝒚 𝜷 se procede a buscar el seno coseno
tangente.
En primer lugar se empezara con el Angulo A
y posteriormente 𝑩.
ℎ = 4.5 𝑐𝑚
𝑐𝑜 = 4𝑐𝑚
𝑐𝑎 = 2.06 𝑐𝑚
𝑠𝑒𝑛𝑜 =
𝑐𝑜
ℎ
𝐶𝑜𝑠𝑒𝑛𝑜 =
𝑐𝑎
ℎ
𝑡𝑎𝑛𝑔𝑒𝑛𝑡𝑒 =
𝑐𝑜
𝑐𝑎
𝑠𝑒𝑛𝑜 𝐵 =
𝑐𝑜
ℎ
𝑠𝑒𝑛𝑜−1
𝑠𝑒𝑛𝑜 𝐵 = 𝑠𝑒𝑛𝑜−1
4𝑐𝑚
4.5𝑐𝑚
𝐵 = 𝑠𝑒𝑛𝑜−1
4𝑐𝑚
4.5𝑐𝑚
𝑩 = 𝟔𝟐. 𝟕𝟑°
𝐶𝑜𝑠−1
𝐶𝑜𝑠 𝐵 = 𝐶𝑜𝑠−1
2.06𝑐𝑚
4.5𝑐𝑚
𝐵 = 𝐶𝑜𝑠−1
2.06𝑐𝑚
4.5𝑐𝑚
𝑩 = 𝟔𝟐, 𝟕𝟑°
𝑡𝑎𝑛𝑔−1
𝑡𝑎𝑛𝑔 𝐵 = 𝑡𝑎𝑛𝑔−1
4𝑐𝑚
2,06𝑐𝑚
𝐵 = 𝑡𝑎𝑛𝑔−1
4𝑐𝑚
2,06𝑐𝑚
𝑩 = 𝟔𝟐. 𝟕𝟑°
1
2
h= 𝟒. 𝟓𝒄𝒎
a= 2.06 cm
b=4 cm
ℎ = 4.5 𝑐𝑚
𝑐𝑜 = 4𝑐𝑚
𝑐𝑎 = 2.06 𝑐𝑚
Una vez encontrado el Angulo A se
realiza la parte b donde encuentra el
valor del Angulo B.para realizar y
obtener el resultado de seno, coseno y
tangente para ello se debe tener
encuentra los valores de la
hipotenusa, cateto opuesto y cateto
adyacente
¡GRACIAS POR SU ATENCIÓN!

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Paso 3 tarea 2 a ejercicio grupal_unidad 2

  • 1. .
  • 2. Calcula las razones trigonométricas seno, coseno y tangente de los ángulos agudos (A y B) del triángulo rectángulo que aparecen abajo. Donde el valor de a o el lado del ángulo que falta la medida se obtiene por medio del teorema de Pitágoras. h= 𝟒. 𝟓𝒄𝒎 a= 2.06 cm b=4 cm 𝒉𝟐 = 𝒂𝟐 + 𝒃𝟐 𝒉𝟐 − 𝒃𝟐 = 𝒂𝟐 𝒂𝟐 = 𝒉𝟐 − 𝒃𝟐 𝒂𝟐 = (𝟒. 𝟓𝒄𝒎)𝟐 −(𝟒𝒄𝒎)𝟐 𝒂𝟐 = 𝟐𝟎. 𝟐𝟓𝒄𝒎𝟐 − 𝟏𝟔𝒄𝒎𝟐 𝒂𝟐 = 𝟒. 𝟐𝟓𝒄𝒎𝟐 𝒂𝟐 = 𝟒. 𝟐𝟓𝒄𝒎 𝒂 = 𝟒. 𝟐𝟓𝒄𝒎 = 𝒄𝒎 𝒂 =2.06m
  • 3. 1 2 . ℎ = 4.5𝑐𝑚 𝑐𝑜 = 2.06 𝑐𝑚 𝑐𝑎 = 4𝑐𝑚 𝑠𝑒𝑛𝑜 = 𝑐𝑜 ℎ 𝐶𝑜𝑠𝑒𝑛𝑜 = 𝑐𝑎 ℎ 𝑡𝑎𝑛𝑔𝑒𝑛𝑡𝑒 = 𝑐𝑜 𝑐𝑎 se cancela seno a la menos 1 por seno y así mismo con arco coseno y seno, igualmente para tangente y arco tangente. 𝑠𝑒𝑛𝑜−1 𝑠𝑒𝑛𝑜 𝐴 = 𝑠𝑒𝑛𝑜−1 ( 2.06𝑐𝑚 4.5𝑐𝑚 ) 𝐴 = 𝑠𝑒𝑛𝑜−1 2.06𝑐𝑚 4.5𝑐𝑚 𝑨 = 𝟐𝟕. 𝟐𝟒° 𝐶𝑜𝑠−1 𝐶𝑜𝑠 𝐴 = 𝐶𝑜𝑠−1 4𝑐𝑚 4.5𝑐𝑚 𝐴 = 𝐶𝑜𝑠−1 4𝐶𝑀 4.5𝐶𝑀 𝑨 = 𝟐𝟕. 𝟐𝟒° 𝑡𝑎𝑛𝑔−1 𝑡𝑎𝑛𝑔 𝐴 = 𝑡𝑎𝑛𝑔−1 2.06𝑐𝑚 4𝑐𝑚 𝐴 = 𝑡𝑎𝑛𝑔−1 2.06𝑐𝑚 4𝑐𝑚 𝑨 = 𝟐𝟕. 𝟐𝟒° h= 𝟒. 𝟓𝒄𝒎 a= 2.06 cm b=4 cm Una vez encontrado el valor del los tres lados de los triángulos rectángulos para el Angulo 𝜶 𝒚 𝜷 se procede a buscar el seno coseno tangente. En primer lugar se empezara con el Angulo A y posteriormente 𝑩.
  • 4. ℎ = 4.5 𝑐𝑚 𝑐𝑜 = 4𝑐𝑚 𝑐𝑎 = 2.06 𝑐𝑚 𝑠𝑒𝑛𝑜 = 𝑐𝑜 ℎ 𝐶𝑜𝑠𝑒𝑛𝑜 = 𝑐𝑎 ℎ 𝑡𝑎𝑛𝑔𝑒𝑛𝑡𝑒 = 𝑐𝑜 𝑐𝑎 𝑠𝑒𝑛𝑜 𝐵 = 𝑐𝑜 ℎ 𝑠𝑒𝑛𝑜−1 𝑠𝑒𝑛𝑜 𝐵 = 𝑠𝑒𝑛𝑜−1 4𝑐𝑚 4.5𝑐𝑚 𝐵 = 𝑠𝑒𝑛𝑜−1 4𝑐𝑚 4.5𝑐𝑚 𝑩 = 𝟔𝟐. 𝟕𝟑° 𝐶𝑜𝑠−1 𝐶𝑜𝑠 𝐵 = 𝐶𝑜𝑠−1 2.06𝑐𝑚 4.5𝑐𝑚 𝐵 = 𝐶𝑜𝑠−1 2.06𝑐𝑚 4.5𝑐𝑚 𝑩 = 𝟔𝟐, 𝟕𝟑° 𝑡𝑎𝑛𝑔−1 𝑡𝑎𝑛𝑔 𝐵 = 𝑡𝑎𝑛𝑔−1 4𝑐𝑚 2,06𝑐𝑚 𝐵 = 𝑡𝑎𝑛𝑔−1 4𝑐𝑚 2,06𝑐𝑚 𝑩 = 𝟔𝟐. 𝟕𝟑° 1 2 h= 𝟒. 𝟓𝒄𝒎 a= 2.06 cm b=4 cm ℎ = 4.5 𝑐𝑚 𝑐𝑜 = 4𝑐𝑚 𝑐𝑎 = 2.06 𝑐𝑚 Una vez encontrado el Angulo A se realiza la parte b donde encuentra el valor del Angulo B.para realizar y obtener el resultado de seno, coseno y tangente para ello se debe tener encuentra los valores de la hipotenusa, cateto opuesto y cateto adyacente
  • 5. ¡GRACIAS POR SU ATENCIÓN!