The AREA OF THE TRIANGLE
Mrs.Neveen kamel
Prepared by
Area of the triangle
Width
Length Base
Height
A =L x W=……Cm² A =½ A
A =½ x L x W
A =½ x B x H
B = 2 cm. H = 3 cm. A = ?3 cm²
B = 4 cm. H = 6 cm. A =12 cm²
B = 0.2 cm. H = 0.4 cm. A = 0.04 cm²
?
?
A
½ B H
B= 2A ÷ H H= 2A ÷ B
A = ½ x B x H
2A= B x H
Calculate the area of ABC in each of following :
B
A
C
A
B C
A
B DC3.6cm.
3.6cm.
12cm.
4cm.
3cm.
8cm.
A = ½ x B x H
= ½ x 3 x 4
= 6 cm².
A = ½ x B x H
= ½ x 12 x 8
= 48 cm².
A = ½ x B x H
= ½ x 3.6 x 3.6
= 6.48 cm².
If the area of a triangle is 12 cm².find :
[a] Its height , if its corresponding
base length is 6 cm.
H= 2A ÷ B
= 2 x 12 ÷ 6
= 4 cm².
[b] Its base length , if its
corresponding height length is 8 cm.
H = 2A ÷ B
= 2 x 12 ÷ 8
= 3 cm².
Calculate the area of the following figure :
D
A
C
3cm.
5 cm.
4cm.
B
E
A = ½ x 5 x 4
= 20 cm².
A = 3 x 5
= 15 cm².
A = A +A
=15+20
=35 cm².
In the following figure find the area of the
shaded part :
A
C
D B
E
10 cm.
6cm.
A1 = ½ x 10 x 6
=
A2 = ½ x 10 x 3
=
?
?
30 cm².
15cm².
A = A1-A2
= 30-15
=15 cm².

Area of triangle copy

  • 1.
    The AREA OFTHE TRIANGLE Mrs.Neveen kamel Prepared by
  • 2.
    Area of thetriangle Width Length Base Height A =L x W=……Cm² A =½ A A =½ x L x W A =½ x B x H
  • 3.
    B = 2cm. H = 3 cm. A = ?3 cm² B = 4 cm. H = 6 cm. A =12 cm² B = 0.2 cm. H = 0.4 cm. A = 0.04 cm² ? ?
  • 4.
    A ½ B H B=2A ÷ H H= 2A ÷ B A = ½ x B x H 2A= B x H
  • 5.
    Calculate the areaof ABC in each of following : B A C A B C A B DC3.6cm. 3.6cm. 12cm. 4cm. 3cm. 8cm. A = ½ x B x H = ½ x 3 x 4 = 6 cm². A = ½ x B x H = ½ x 12 x 8 = 48 cm². A = ½ x B x H = ½ x 3.6 x 3.6 = 6.48 cm².
  • 6.
    If the areaof a triangle is 12 cm².find : [a] Its height , if its corresponding base length is 6 cm. H= 2A ÷ B = 2 x 12 ÷ 6 = 4 cm². [b] Its base length , if its corresponding height length is 8 cm. H = 2A ÷ B = 2 x 12 ÷ 8 = 3 cm².
  • 7.
    Calculate the areaof the following figure : D A C 3cm. 5 cm. 4cm. B E A = ½ x 5 x 4 = 20 cm². A = 3 x 5 = 15 cm². A = A +A =15+20 =35 cm².
  • 8.
    In the followingfigure find the area of the shaded part : A C D B E 10 cm. 6cm. A1 = ½ x 10 x 6 = A2 = ½ x 10 x 3 = ? ? 30 cm². 15cm². A = A1-A2 = 30-15 =15 cm².