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Lecture note on
Advances in Advanced Animal Nutrition
By
Yisehak Kechero (PhD, Associate professor)
1
Nutrition:
• Process by which living organism receives
nutrients and uses them to promote it’s vital
activities
– Animals use nutrients to enable them to:
• maintain . grow
• reproduce . lay eggs
• lactate . produce wool
• work
Chapter 1
Terminologies
2
Terminologies
Nutrient: Nutrients are chemical substances in food
that body cells use for body function (growth,
maintenance, and repair)
Diet: Selection of food which is normally eaten by
animal or population
Food: Substance when eaten , digested, absorbed
provide at least one nutrient
Balanced diet : Diet that provide adequate amount
of all nutrients
3
Terminologies
Malnutrition: Caused by incorrect amount of
nutrient intake
Nutritional status:
Health status that produced by balanced between
requirements and intake
Dietitian/nutritionist: Persons who applies
science of nutrition to animal in health and
disease
4
Terminologies
Metabolism :
process by which living systems acquire and use free
energy to carry out vital processes
Anabolism (biosynthesis ):
Complex molecules are synthesized from simpler ones
Catabolism(degradation): Complex molecules are broken
to simpler ones
Digestion: Breakdown of feed nutrients into suitable form
for absorption
Absorption: Transfer of digested nutrients from GIT into
circulating blood or lymph systems
5
Role of Metabolism in Nutrition
Definition: the sum of all biochemical changes that take
place in a living organism.
Group these reactions into two types:
anabolic catabolic
Reactions: require energy release energy
Produce: more complex more simple compounds
compounds
Modus
Operandi: Occurs in small steps, each of which is controlled
by specific enzymes.
6
Chapter 2
FEED ANALYSIS SYSTEMS
• Feed analysis systems
– Proximate analysis system (Weende system)
• Developed in 1864 at Weende Experiment Station
in Germany
– the analysis of feed into its basic components
• Dry matter or water, crude protein, crude fiber,
ether extract, ash, nitrogen free extract (NFE)
– Detergent analysis system (Van Soest
system)
• Developed in 1964 at USDA Beltsville Research
Center 7
PROXIMATE ANALYSIS COMPONENTS
• Dry matter
• Ash (total ash or crude ash)
• Crude protein (CP)
• Ether extract (crude fat)
• Crude fiber (CF)
• Nitrogen-free extract (NFE)
8
• Dry matter (DM)
– Partial DM, Lab. DM, Actual/ total DM
– DM is weight of a feed remaining after a feed is dried in
a 100oC oven for 24 hours/105°C 16 hr etc
• DM,% = wt after drying/wt before drying  100%
• % moisture = 100 – DM,%
Reagents: none
Avg. 2 grams used
– Problems with method
• Errors from losses of volatile components
– Particularly a problem with fermented feeds
– Can be avoided by freeze drying
• Drying at > 100oC destroys sample for further
analysis
– Can be avoided by freeze drying or drying at 50-
65oC for 72-48 hours in preparation for analysis
AOAC 9
Dry matter
• Percent DM = (W3-W1)100/W2-W1)
• Where,
– W1= weight of empty container,
– W2= weight of empty container plus sample
– W3 = weight of container and sample after drying
• Varies with types of feeds (ex green feeds, dry
feeds, milk, silage, hay )
• Equipment: paper bag, forced air drying oven,
analytical balance,Desiccator
• Qulity control, Constant weight, duplicate 10
• Ash ( Crude ash)
– Material remaining after oxidation of a sample
at 600oC for 2 hours in a muffle furnace
• % Ash = wt after ashing/sample wt x 100%
• % Organic matter = 100 - % ash
– Equipment: Incineration dish, Analytical
balance, Muffle furnace, Desiccator
– % Ash = (W3- W2) x 100/ (W2-W1)
– Problems
• No indication of amounts of individual minerals
• Some minerals (Sulfur, Selenium, Zinc, Iodine are
lost)
– Significance
• May indicate soil contamination or adulteration of
feedstuff or diet. 11
• Crude protein (CP)
– % Crude protein = %N x 6.25
– %N determination
• Kjeldahl N
Sample→Boil in conc. H2SO4→(NH4)2SO4→Add conc. NaOH, → Titrate
catalyst distill NH3, and trap NH4 borate
in boric acid
• blue colour....pink colour
Factor of 6.25 assumes that most proteins contain 16% N
CP,% = measured mg N/100 mg sample x 100 mg protein/16 mg N
= measured mg N/100 mg/sample x 6.25
Coversion Factors:
 6.25 for all forages, compounded feeds and mixed feeds
 5.7 for cereal grains
 6.38 for milk
12
Crude protein
• % N = (Vs-Vb) x M(HCl) x 1 x 14.007/ (Wx
10)
– Vs= ml Hcl needed to titrate the sample
– Vb = ml Hcl needed for the blank test
– M (HCl) = molarity of HCl
– 1= the acid factor
– 14.007= molecular weight of N,
– 10 = conversion from mg/g to % (1.4007 to
14.007), and weight of the sample (g)
Quality control: control standard should be used, duplicate
analysis,use blank 13
• Problems with crude protein procedure
– Sources of N
• True protein
– Chains of amino acids bound by peptide linkages
– Can meet the protein requirements of either nonruminant or
ruminant animals
• Nonprotein nitrogen
– Forms
» Free amino acids
» Nucleic acids
» Ammonia
» Urea
– Can meet the protein requirements of ruminant animals
» Urea and biuret commonly added to ruminant diets
– Can not meet the protein requirements of nonruminant animals
– Says nothing about the amino acid composition of the
feed source
• Commonly assume that the concentration of individual amino
acids is constant within the protein a given feedstuff
• Can analyze for individual amino acids
14
– Crude protein says nothing about the digestibility of a
protein
• Varies with feedstuff
% Crude protein % Protein Digestibility
Soybean meal 45 90
Feather meal 80 75
• Varies with heat damage
– When overheated, protein will bind to the cell wall carbohydrates
particularly across lysine
– Causes
» Molding of forages
» Over-heating during processing
» Over-drying of grains or soybeans
– Referred to as the Maillard or Browning Reaction
– Results
% Crude protein % Protein Digestibility
Well-preserved alfalfa hay 18 90
Heat-damaged alfalfa hay 18 60 15
Crude Protein
Non-protein
nitrogen
True protein
(60 to 80%)
Essential amino acids
Arginine (Arg)
Histidine (His)
Isoleucine (Ile)
Leucine (Leu)
Lysine (Lys)
Methionine (Met)
Phenylalanine (Phe)
Threonine (Thr)
Tryptophan (Trp)
Valine (Val)
Non-essential
amino acids
Alanine (Ala)
Asparagine (Asn)
Aspartic acid (Asp)
Cysteine (Cys)
Glutamic acid (Glu)
Glutamine (Gln)
Glycine (Gly)
Proline (Pro)
Serine (Ser)
Tyrosine (Tyr)
Amides
Amines
Amino acids
Peptides
Nucleic acids
Nitrates
Ammonia
Urea
Lignified
nitrogen
16
• Ether extract (EE)
– Also called crude fat
– Material removed by refluxing ether through a feed
sample for 4 hours
% Ether extract = (Sample wt-residue after ether
extract)/Sample wt x 100%
– Theoretically represents fat content of the feedstuff
• A high ether extract content should indicate a high
energy concentration
– Problem with procedure
• Ether extract consists of:
–True lipids
»Fats and oils
–Non-nutritional ether soluble components
»Fat-soluble vitamins
»Chlorophyll
»Pigments
»Volatile oils
»Waxes 17
Crude fiber (CF)
– Procedure
Sample→Extract with dilute H2SO4 →Residue→Burn at 600oC→Ash
followed by dilute NaOH
% CF = (Residue wt-Ash wt)/sample wt x 100%
– Theoretically represents
• the structural carbohydrates (Cellulose and lignin)
– Limited digestibility in ruminants
– Poor digestibility in nonruminants
• Lignin
– Indigestible by ruminants and nonruminants
– Problems with procedure
• Poor recovery of components
% recovered
– Cellulose 90
– Hemicellulose 50-60
– Lignin 13-70 18
• Nitrogen-free extract (NFE)
– No actual analysis
– Calculation by difference
• %NFE = %DM – (%ash+%CP+%EE+%CF)
– Theoretically represents:
• Starch
• Sugars
– Problems:
• Contains all of the errors from other analyses
– Largest error is unrecovered lignin will be placed in NFE
19
DETERGENT ANALYSIS SYSTEM
20
• Neutral detergent fiber (NDF)
– Consists of hemicellulose, cellulose, lignin, cell wall
bound protein and insoluble ash
– Significe:
• Highly related to feed intake
• DMI, % BW = 120/% NDF
• Acid detergent fiber (ADF)
– Consists of cellulose, lignin, poorly digested protein,
and insoluble ash
– Significance:
• Highly related to digestibility and energy concentration
• DDM% = 88.9 – (.779 x %ADF)
• NEl, Mcal/lb (for legumes) = 1.011 – (0.0113 x %ADF)
– Combination of DDM (determined from ADF) and DMI
(determined from NDF) is used to determine Relative
Feed Value (RFV)
• RFV=DDM x DMI / 1.29
• Used for hay marketing
21
– Nitrogen bound to acid detergent fiber is a measure of
heat-damaged protein
• Called ADIN or ADF-CP
– Procedure
Sample→Extract with AD→ADF→Analyze N by
Kjeldahl procedure
ADF-CP, % of total CP= %ADFN x 6.25/%CP x 100%
– Relationship to protein digestibility (called adjusted CP)
• If ADF-CP, % of total CP <14, ADIN is considered digestible
– Adjusted CP = CP
• If ADF-CP, % of total CP is >14 and <20
– Adjusted CP = ((100 – (ADF-CP, % of CP – 7))/100) x CP
• If ADF-CP, % of total CP is > 20
– Adjusted CP = CP – ADF-CP, % of CP
22
• N bound to NDF and ADF used to determine
rumen degradable, rumen undegradable, and
indigestible fractions
Rumen degradable protein = Total CP – (NDFCP, % of CP xTotal CP)
Rumen undegradable protein = (NDFCP, % of CP xTotal CP) –
(ADFCP, % of CP xTotal CP)
Indigestible protein = (ADFCP, % of CP xTotal CP)
23
OTHER ANALYTICAL PROCEDURES
• Near infrared reflectance spectroscopy (NIRS)
– Determines the concentrations of protein, amino acids,
lipids, and carbohydrates based on absorption of near
infrared light
– Advantages
• Rapid
• Used by most commercial labs
– Limitations
• Requires calibration
• Inability to measure heterogeneous molecules like lignin
• Inability to measure minerals
24
• Atomic absorption spectroscopy
– Used for mineral analysis
– Procedure
• Sample ashed and extracted into a solvent
• Dissolved sample sucked into a flame with a light at a
specific wavelength going through it
• Absorption of light directly proportional to absorption of light
– Limitation
• Expense
• High performance liquid chromatography
– Used of amino acids, lipids and vitamins
– Procedure
• Sample dissolved in organic solvent injected into column
• Column differentially separates components
• Detector measures components as they through the column
– Limitation
• Expense
25
26
Chemical Evaluation
3/Van Soest Fiber Analysis --
replaces the Weende System of
crude fiber analysis with neutral
and acid detergent fiber (NDF
and ADF)
 more accurate
 more precisely identify the
fiber components
Van Soest Fiber
Air-dry Feed Sample
Boil with neutral
detergent, pH = 7
Neutral Detergent Fiber
cellulose, hemicellulose,
and lignin
Neutral Detergent Solubles
cell contents and pectin
Boil in acid
detergent, pH = 0
Acid Detergent Fiber
cellulose and lignin
Acid Detergent Solubles
hemicellulose
Lignin
Rinse in 72% sulfuric acid
Cellulose
(dissolved) 27
Chapter 3
Classification of feeds
28
Roughages
• Contains more than 18% crude fiber when
that are dry
Hulls Straw
Silage
Roughage
Hay
Legume/non-
legume forages
Pasture
29
Legume Roughages
• Can take nitrogen from the air
• Able to due so because they have nodules on
their roots that contain bacteria
• These bacteria fix the nitrogen from the air in soil
and make it available for the plant to use
– Do so by combining the free nitrogen with other
elements to form nitrogen compounds
• All the clovers, alfalfa, soybeans, peas and
beans etc
• Usually higher in protein than nonlegume
roughages
30
Nonlegume Roughages
• Cannot use nitrogen from the air
• Lower in protein
• Many common livestock feeds are
nonlegume
31
Concentrates
• Contains less than 18% crude fiber when
dry
• Two classes
– Protein supplements
– Energy feeds
32
Protein Supplements
• 20% or more CP protein
• Divided into 2 groups based on their
source
33
Protein Supplements
• Animal proteins
– Come from animals or
animal by-products
– Common: meat and
bone meal, fish meal,
dried milk (whole &
skimmed), blood meal,
feather meal
– Most contain more than
47% crude protein
– More balanced essential
amino acids
– Variable quality
compared to origin
proteins
• Plant Proteins
– Come from plants
– Common: soybean oil
meal, cottonseed meal,
linseed oil meal, peanut oil
meal, corn gluten feed,
brewers dried grains,
distillers dried grains
– Most contain less than
47% crude protein
– Soybean oil meal is used
most
• Can supply necessary
amino acids for swine
and poultry 34
Commercial Protein
Supplements
• Made by commercial feed
companies
• Mixes of animal and plant
protein feeds
• Usually made for 1 class
of animal
• Often mix of minerals,
vitamins, antibiotics
• Feed tag needs to be
read and feeding
directions followed
35
Energy Feeds
• Feeds with less than 20% crude protein
• Most grains
– Oats, corn, sorghum, barley, rye, wheat,
ground ear corn, wheat bran, wheat
middling's, dried citrus pulp, dried beet pulp,
dried whey
– Corn is the most widely used
– Followed by sorghum grain, oats, barley
36
Chapter 4
Nutrients
6 major classes
1. Water
2. carbohydrates -
3. lipids -
4. proteins
5. vitamins
6. minerals
Energy
37
Figure 5–1: The essential nutrients.
38
Water (H2O)
• Overlook when formulating rations—assumed animals
have access to good quality water
– EXTREMELY IMPORTANT
• Cheapest & most abundant nutrient
• May lose 100% of body fat, 50% of body protein and live
• Lose 10% of body water, dehydration occurs and may
result in death (species dependent)
• 65-85% of body weight at birth
• 45-60% of body weight at maturity
• Many tissues contain 70-90% water
39
Functions of Water
1. Transport of nutrients and excretions
2. Chemical reactions and solvent
properties
3. Body temperature regulation
4. Aids in cell shape maintenance
5. Lubricates and cushions joints and
organs
40
Sources of Water
1. Drinking water
2. Water in feed
3. Metabolic water
41
Sources of Water
1. Drinking
– Pigs = 1.5-3 gal/hd/day
– Sheep = 1-3 gal/hd/day
– Cattle = 10-14 gal/hd/day
– Horses = 10-14 gal/hd/day
– Poultry = 2 parts water:1 part feed
42
Sources of Water
2. Water contained in feeds
• Highly variable in feedstuffs
• Grains = 9-30% water
• Forages
– Hay <5%
– Silage 65-75%
– Lush young grass >90%
43
Calculating Water Content of
Feedstuffs
• 100 kgs of silage (65% moisture) contains
how much actual feed?
• 100 kgs * .65 = 65 kgs of water
• 100 kgs – 65 kgs = 35 kgs of feed
44
Sources of Water
3. Metabolic Water
- Results from the oxidation of organic
nutrients in the tissues
- 1 g of carbohydrates = 0.6 g of water
- 1 g of protein = 0.4 g of water
- 1 g of fat = 1 g of water
- May account for 5-10% of total water
intake
45
Sources of Water Loss
• Urine
• Feces
• Lungs
• Skin
• Milk
46
Factors Affecting Water Intake
• Temperature & humidity
• Dietary factors
–High moisture feeds reduce drinking
–Fiber, DM intake, salt, and protein
increase drinking
• Lactating vs dry
• Water quality
47
Water Absorption
• Readily absorbed
– Monogastrics/Ruminants: Jejunum, Ileum,
Cecum, Large Intestine
– Ruminants: Rumen and Omasum
48
CARBOHYDRATES (CHO)
49
Carbohydrates (CHO)
• Primary component found in livestock feeds
– 70% of DM of forages
– 80% of DM of grains
• Serve as source of energy or bulk (fiber) in the
diet
– Not ESSENTIAL/Technical nutrients
• Synthesized by animals
50
Types of CHO
• Monosaccharides: 1 sugar molecule
– Glucose
• Primary sugar body uses for fuel, plants are rich in
glucose
– Fructose
• Found in honey (75%), fruits, and cane sugar
• Sweetest sugar, molasses
– Galactose
• Found many plants tissues
• Present in low concentrations in animal feedstuffs
51
Monosaccharide (Glucose)
Formula: C6H12O6
52
53
Galactose, sometimes abbreviated Gal, is a monosaccharide sugar that is less
sweet than glucose. It is a C-4 epimer of glucose. Galactan is a polymer of the
sugar galactose found in hemicellulose
Types of CHO
• Disaccharides: 2 sugar molecules linked by a
glycosidic bond
– a sugar consisting of two linked monosaccharide units
• Forexample
– Lactose (galactose + glucose),… lactase
• Milk sugar
– Sucrose (fructose + glucose),… sucrase
• Table sugar
– Maltose,…Maltase
• also known as maltobiose or malt sugar, is a disaccharide formed
from two units of glucose joined with an α(1→4) bond, formed
from a condensation reaction
54
Disaccharide (Sucrose)
55
Disaccharides:
(+)-maltose “malt sugar”
two glucose units (alpha)
(+)-cellobiose
two glucose units (beta)
Cellobiose, a reducing sugar, consists of two β-glucose
molecules linked by a β(1→4) bond. It can be
hydrolyzed to glucose enzymatically or with acid
56
C12H22O11
(+)-maltose
O
H
H
HO
H
H
OH
H
OH
OH
O
H
HO
H
HO
H
OH
H
H
OH
O
two glucose units
alpha C-1 to C-4
reducing sugar
O
H
HO
H
HO
H
H
OH
H
OH
O
H
O
H
HO
H
H
OH
H
OH
OH
(+)-cellobiose
two glucose units
beta C-1 to C-4
reducing sugar
57
O
H
HO
H
HO
H
OH
H
H
OH
glucose alpha C-1
to beta C1 fructose
O
HO
H
H
HO
H
H
OH
H
OH
O
H
O
H
HO
H
H
OH
H
OH
OH galactose beta C-1
to C-4 glucose
reducing sugar
(+)-lactose
O
O
CH
2
OH
CH2OH
H
H
OH
HO
H
(+)-sucrose
acetal
non-reducing
58
Types of CHO
• Oligosaccharides: group of CHO
consisting of 2-10 sugar groups
• Present in feed ingredients
– Fructooligosaccharides (Inulin): present in
many feedstuffs in variable amounts
– Galactooligosaccharides: present in
soybeans and many feedstuffs
59
Types of CHO
• Oligosaccharides
– Not hydrolytically digested or digested by the action of
mammalian or livestock enzymes
– Fermented by beneficial bacteria present in GIT
– “Functional Feed Ingredient”: foodstuffs which, apart from
their normal nutritional value, are said to help promote or
sustain healthiness
• PREBIOTIC
– non-digestible food ingredients that stimulate the growth
and/or activity of bacteria in the digestive system in ways
claimed to be beneficial to health in simple stomach animals
– a dietary supplement in the form of nondigestible
carbohydrate that favors the growth of desirable microflora in
the large bowel
60
Probiotic
• substance containing beneficial
microorganisms: a substance containing
live microorganisms that claims to be
beneficial to humans and animals, e.g. by
restoring the balance of microflora in the
digestive tract
61
Soybean Oligosaccharides
62
Fructooligosaccharides (Inulin)
63
Types of CHO
• Polysaccharides: many sugar
molecules(>10) linked by a glycosidic bond
– Starch: a natural substance composed of
chains of glucose units, made by plants and
providing a major energy source for animals.
• Formula: (C6H10O5)n
– Cellulose: The main constituent of the cell walls
of plants and algae. most abundant CHO in
nature
– Hemicellulose: One of the principle 64
Polysaccharides
n
65
Polysaccharides
starch
cellulose
Starch 20% amylose (water soluble)
80% amylopectin (water insoluble)
amylose + H2O  (+)-maltose
(+)-maltose + H2O  (+)-glucose
starch is a poly glucose (alpha-glucoside to C-4)
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
66
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
CH2
O
Amylopectin + H2O  (+)-maltose
(+)-maltose + H2O  (+)-glucose
Also a polyglucose, but branched every 20-25 units:
67
Cellulose is a polyglucose with a beta-linkage:
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
O
68
Cellular respiration begins with glycolysis
69
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
ATP
H H
H
H
HO
1
H
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
Glucose 6-phosphate
O
OH
OH
OH
OH2C
P
ATP
H
HO
H
H
H
H
H
H
H
HO
1
2
H
H
Phosphofructokinase
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
Glucose 6-phosphate
O
OH
OH
OH
CH2OH
Fructose 6-phosphate
O
OH
H
OH2C 6
5
4 3
2
1
ADP
P
OH2C
P
ATP
ATP
OH
H
HO
H
H
H
H
H H
H
H
HO
H
HO
1
2
3
H
H
Phosphofructokinase
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
Glucose 6-phosphate
O
OH
OH
OH
CH2OH
Fructose 6-phosphate
O
OH
H
OH2C 6
5
4 3
2
1
CH2O
Fructose 1, 6-bisphosphate
O
OH
H
OH2C
ADP
P
P
P
OH2C
P
ATP
ATP
OH
H
HO
H
H
H
H
H
H
H
H
H
H
HO
HO
H
HO
OH
1
2
3
4
H
H
Phosphofructokinase
Dihydroxyacetone
phosphate
CH2OH
CH2O
C O
Glyceraldehyde
3-phosphate
HCOH
CH2O
O
H
C
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
Glucose 6-phosphate
O
OH
OH
OH
CH2OH
Fructose 6-phosphate
O
OH
H
OH2C 6
5
4 3
2
1
CH2O
Fructose 1, 6-bisphosphate
O
OH
H
OH2C
ADP
P
P
P
P
P
OH2C
P
ATP
ATP
OH
H
HO
H
H
H
H
H
H
H
H
H
H
HO
HO
H
HO
OH
1
2
3
4
5
H
H
+ 2H+
NADH
HCOH
C
CH2O
O
O 1, 3-Bisphosphoglyceric acid
(2 molecules)
2
P
P
Phosphofructokinase
Dihydroxyacetone
phosphate
CH2OH
CH2O
C O
Glyceraldehyde
3-phosphate
HCOH
CH2O
O
H
C
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
Glucose 6-phosphate
O
OH
OH
OH
CH2OH
Fructose 6-phosphate
O
OH
H
OH2C 6
5
4 3
2
1
CH2O
Fructose 1, 6-bisphosphate
O
OH
H
OH2C
ADP
P
P
P
P
P
OH2C
P
ATP
ATP
OH
H
HO
H
H
H
H
H
H
H
H
H
H
HO
HO
H
HO
OH
1
2
3
4
5
6
H
H
2 NAD+ + 2 P
+ 2H+
NADH
HCOH
C
CH2O
O
COOH
O
2
2 ADP
HCOH
CH2O
1, 3-Bisphosphoglyceric acid
(2 molecules)
2
3-Phosphoglyceric acid
(2 molecules)
P
P
P
Phosphofructokinase
Dihydroxyacetone
phosphate
CH2OH
CH2O
C O
Glyceraldehyde
3-phosphate
HCOH
CH2O
O
H
C
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
Glucose 6-phosphate
O
OH
OH
OH
CH2OH
Fructose 6-phosphate
O
OH
H
OH2C 6
5
4 3
2
1
CH2O
Fructose 1, 6-bisphosphate
O
OH
H
OH2C
ADP
P
P
P
P
P
OH2C
P
ATP
ATP
ATP
OH
H
HO
H
H
H
H
H
H
H
H
H
H
HO
HO
H
HO
OH
1
2
3
4
5
6
7
H
H
2 NAD+ + 2 P
+ 2H+
NADH
HCOH
C
CH2O
O
COOH
O
2
2 ADP
HCOH
CH2O
1, 3-Bisphosphoglyceric acid
(2 molecules)
2
3-Phosphoglyceric acid
(2 molecules)
COOH
CH2OH
HCO 2-Phosphoglyceric acid
(2 molecules)
P
P
P
P
Phosphofructokinase
Dihydroxyacetone
phosphate
CH2OH
CH2O
C O
Glyceraldehyde
3-phosphate
HCOH
CH2O
O
H
C
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
Glucose 6-phosphate
O
OH
OH
OH
CH2OH
Fructose 6-phosphate
O
OH
H
OH2C 6
5
4 3
2
1
CH2O
Fructose 1, 6-bisphosphate
O
OH
H
OH2C
ADP
P
P
P
P
P
OH2C
P
ATP
ATP
ATP
OH
H
HO
H
H
H
H
H
H
H
H
H
H
HO
HO
H
HO
OH
1
2
3
4
5
6
7
8
H
H
2 NAD+ + 2 P
+ 2H+
NADH
HCOH
C
CH2O
O
COOH
O
2
2 ADP
HCOH
CH2O
1, 3-Bisphosphoglyceric acid
(2 molecules)
2
3-Phosphoglyceric acid
(2 molecules)
COOH
CH2OH
HCO 2-Phosphoglyceric acid
(2 molecules)
COOH
CH2
C O Phosphoenolpyruvic acid
(2 molecules)
P
P
P
P
P
Phosphofructokinase
Dihydroxyacetone
phosphate
CH2OH
CH2O
C O
Glyceraldehyde
3-phosphate
HCOH
CH2O
O
H
C
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
Glucose 6-phosphate
O
OH
OH
OH
CH2OH
Fructose 6-phosphate
O
OH
H
OH2C 6
5
4 3
2
1
CH2O
Fructose 1, 6-bisphosphate
O
OH
H
OH2C
ADP
P
P
P
P
P
OH2C
P
ATP
ATP
ATP
OH
H
HO
H
H
H
H
H
H
H
H
H
H
HO
HO
H
HO
OH
1
2
3
4
5
6
7
8
9
H
H
2 NAD+ + 2 P
+ 2H+
NADH
2 NAD+ + 2
HCOH
C
CH2O
O
COOH
O
2
2 ADP
P
HCOH
CH2O
1, 3-Bisphosphoglyceric acid
(2 molecules)
2
3-Phosphoglyceric acid
(2 molecules)
COOH
CH2OH
HCO 2-Phosphoglyceric acid
(2 molecules)
Pyruvic acid
(2 molecules)
COOH
CH2
2
2 ADP
C O Phosphoenolpyruvic acid
(2 molecules)
COOH
CH3
C O
P
P
P
P
P
Phosphofructokinase
Dihydroxyacetone
phosphate
CH2OH
CH2O
C O
Glyceraldehyde
3-phosphate
HCOH
CH2O
O
H
C
ADP
O
Glucose (1 molecule)
CH2OH
OH
OH
OH
4 1
3 2
5
6
Glucose 6-phosphate
O
OH
OH
OH
CH2OH
Fructose 6-phosphate
O
OH
H
OH2C 6
5
4 3
2
1
CH2O
Fructose 1, 6-bisphosphate
O
OH
H
OH2C
ADP
P
P
P
P
P
OH2C
P
ATP
ATP
ATP
ATP
OH
H
HO
H
H
H
H
H
H
H
H
H
H
HO
HO
H
HO
OH
1
2
3
4
5
6
7
8
9
10
H
H
70
Function of CHO
• Source of energy
• Source of heat
• Building block for other nutrients
71
Sources of CHO
• Cereal Grains
– Most feedstuffs of plant origin are high in
CHO content
72
CHO Digestion
• Dietary CHO must be converted to be absorbed
– Simple sugars (monosaccharides)
• How?
– Action of amylase enzyme
• Salivary amylase (swine, poultry)
• Intestinal amylase
– Action of other disaccharidases
• Produced by mucosal lining of duodenum
73
CHO Digestion
• Mammals do not produce enzymes
necessary to digest oligosaccharides and
celluloses (fibrous feedstuffs)
– Digestion occurs as result of bacterial
fermentation
• Where?
– Rumen
– Large Intestine (caecum and colon)
74
CHO Digestion
• Fermentation yields:
– CO2
– H2O
– CH4
– Heat (heat increment)
– Volatile Fatty Acids (VFA) or also referred
to as Short Chain Fatty Acids (SCFA)
• 2 to 6 carbons
75
VFA Production
• Serve as 70 - 80% of energy
requirement in ruminants
– VFA’s produced in rumen
• Serve as ~16% of Maintenance energy
requirement in swine
– VFA’s produced in large intestine
They are:
1. Acetate/acetic acid (2 carbons)
2. Propionate/propionic acid (3 carbons)
3. Butyrate/butyric acid (4 carbons) 76
VFAs
• Acetate
–  with higher roughage levels
– Produced by cellulolytic & hemicellulolytic
bacteria
C
H
H
H
C
OH
O
77
VFAs
• Propionate
–  with higher concentrate levels
–  Feed efficiency
– Ionophores increase propionate
production
C
H
H
H
C
O
C
H
H
OH
78
VFAs
• Butyrate
– Energy source for rumen wall growth
• Papillae growth
– Energy source for colonic cell growth
• monogastrics
C
H
H
H
C
O
C
H
H
C
H
H OH
79
VFAs
• Lactate (not volatile)
– Anaerobic conditions
–  rumen and blood pH
– Inhibits most microbial growth
– Acidosis situation
80
CHO Absorption
• Once simple sugars are formed, they are
absorbed rapidly by small intestine
• Then monosaccharides diffuse into the
portal vein which transports them to sites
of metabolism
81
VFA Absorption
• Absorbed through the rumen wall or large
intestine mucosa
• Provide energy source to the animal
82
Absorption of VFA
70% of VFA absorbed from rumen-reticulum
60 to 70% of remainder absorbed from omasum
Papillae are important – provide surface area
Absorption from rumen is by passive diffusion
Concentration in portal vein less than rumen
VFA concentrations
Rumen 50 - 150 mM
Portal blood 1 - 2 mM
Peripheral blood 0.5 - 1 mM
Absorption increases at lower pH
H+ + Ac- HAc
Undissociated acids diffuse more readily
At pH 5.7 to 6.7 both forms are present, however most is dissociated
At higher pH, 1 equiv of HCO3 enters the rumen with absorption of
2 equiv of VFA
83
VFA Absorption
Absorption of Ac-
Ac- Ac- Portal
HAc blood
H+ Metabolism
HCO3
-
H2O H2CO3
+
CO2 CO2 Carbonic
Metabolism anhydrase
HAc HAc
Rumen
84
VFA Absorption
Rate of absorption:
Butyrate > Propionate > Acetate
Absorption greater with increasing concentrations
of acids in the rumen
Absorption increases at lower rumen pH
Absorption greater in grain fed animals
Faster fermentation – More VFA produced
Lower pH
Growth of papillae
85
Metabolism of VFA by GIT
Half or more of butyrate converted to
- hydroxybutyric acid in rumen epithelium.
5% of propionate converted to lactic acid by
rumen epithelium.
Some acetate is used as energy by tissues of gut.
VFA and metabolites carried by portal vein to liver.
86
Tissue Metabolism
VFA
VFA GIT tissues Liver
Body tissues
Use of VFA
Energy
Carbon for synthesis
Long-chain fatty acids
Glucose
Amino acids
Other
87
Utilization of Acetate in Metabolism
1. Acetate (As energy) Energy
Acetate Acetyl CoA Krebs cycle 2 CO2
2 carbons (10 ATP/mole)
2. Acetate (Carbon for synthesis of fatty acids – in adipose)
Acetate Acetyl CoA Fatty acids Lipids
H
+NADPH NADP
+
Glycerol
Pentose PO4 CO2
shunt Glucose
88
Utilization of Butryate in Metabolism
Butyrate (As energy)
Butyrate Butyrl CoA B-hydroxybutyrate Acetyl CoA
Krebs
cycle 2 CO2
Energy
(27 ATP/mole)
Some butyrate also used as a primer for short-chain fatty acids
89
Utilization of Propionate in Metabolism
Propionate
Propionate Propionyl CoA Methylmalonyl CoA
CO2 Succinyl CoA
Vit B12
Glucose Krebs
cycle 2 CO2
Energy
(18 ATP/mole)
90
Utilization of VFA in Metabolism
Summary
Acetate
Energy
Carbon source for fatty acids
Adipose
Mammary gland
Not used for net synthesis of glucose
Propionate
Energy
Precursor of glucose
Butyrate
Energy
Carbon source for fatty acids - mammary
91
Effect of VFA on Endocrine System
Propionate
Increases blood glucose
Stimulates release of insulin
Butryate
Not used for synthesis of glucose
Stimulates release of insulin
Stimulates release of glucagon
Increases blood glucose
Acetate
Not used for synthesis of glucose
Does not stimulate release of insulin
Glucose
Stimulates release of insulin
92
Energetic Efficiency of VFA in
Metabolism
ATP/mole Energy in ATP % Heat of
(kcal/mole) combustion
Acetate 10 76.0 36.3
Propionate 18 136.8 37.2
Butyrate 27 205.2 39.1
Glucose 38 288.8 42.9
93
Energetic Efficiency of VFA
Fermentation and Metabolism
Cellulose
10 Glucose VFA ATP
(6730 kcal) (5240 kcal (1946 kcal)
60A 28.9%
Starch 30P
10B
Absorbed as glucose ATP
(6730 kcal) (2888 kcal)
42.9%
94
Lower Energy Value of
Roughage Compared with concentrate
- Less digested
- Lignin limits digestibility of digestible fiber
- Greater energy lost from fermentation
CO2, N2O,CH4, Heat
- Increased rumination
Rumen contractions
Chewing
-More bulk in digestive tract
-Lower passage rate
95
Requirements for Glucose
Ruminants
1. Nervous system
Energy and source of carbon
2. Fat synthesis
NADPH
Glycerol
3.Pregnancy
Fetal energy requirement
4. Lactation
Milk sugar - lactose
96
Sources of Glucose Carbon
Ruminants
Ruminants dependent on gluconeogenesis (glucose
synthesis) for major portion of glucose
Sources of glucose in metabolism
1. Propionate
2. Amino acids
3. Lactic acid
4. Glycerol
5. Carbohydrate digestion in intestine
Absorption of glucose from intestine
97
Glucose Synthesis
Acetate Amino acids
Ketone Acetyl CoA
Bodies
Fatty
Butyrate acids
Citrate
Glycerol
Acetyl CoA
Lactate CO2 2 CO2
Pyruvate Oxaloacetate
PEP
Glucose Succinate
Proteins Amino acids
Propionate
98
Consequences of Inadequate Glucose in
Metabolism
1. Low blood glucose
2. High blood ketones
3. High blood concentrations of long-chain fatty acids
(NEFA)
Metabolic disorders
• Causes fatty liver
• ketosis in lactating cows and
• pregnancy toxemia in pregnant ewes
99
Pregnancy Toxemia
Pregnant Ewes
• During the last month of pregnancy
• Ewes with multiple faetuses
• Inadequate nutrition of ewe
• High demands for glucose by faetuses
• Low blood glucose and insulin
• Mobilization of body fat
• Increase in nonesterified fatty acids (NEFA) in blood
• Increased ketone production by liver
100
Fatty Acid Metabolism
Relation to Glucose
Diet fat Adipose Diet CHOH
CO2 Acetate
Malonyl CoA
LCFA NEFA Acetate
CO2
Glycerol LCFA acyl CoA
2 CO2
Triglycerides
Carnitine
FA acyl carnitine
Malonyl CoA
inhibits CO2 (Mitochondria)
Ketones
101
Low Blood Glucose and Insulin
• Increased release of nonesterified fatty acids
from adipose.
• Less synthesis of fatty acids
Reduced malonyl CoA
• Reduced sensitivity of carnitine palmitoyl-
transferase-1 to malonyl CoA
Increased transfer of fatty acids into
mitochondria for oxidation
• Increased ketone production
102
Fatty Acid Oxidation
FA acyl CoA
Acetyl CoA
CO2
Acetoacetyl CoA
Acetoacetate
(Mitochondria)
3-OH butyrate
FA acyl carnitine
Carnitine
CoA
103
Low Milk Fat
Cows fed high concentrate diets:
Reduced milk fat percentage
Early theory
Low rumen pH
Shift from acetate to propionate production
Increased blood insulin
Decrease in blood growth hormone
More recent theory
Increased production of trans fatty acids in
the rumen
Trans fatty acids reduce milk fat synthesis
104
Long-Chain Fatty Acid Synthesis
Ruminants
Synthesis is primarily in adipose or mammary gland
– Limited synthesis in the liver
Ruminants conserve glucose supply
– Glucose not extensively used for long chain
fatty acid synthesis
Most of carbon is supplied by acetate
Some butyrate used in mammary gland
Glucose metabolism supplies some of NADPH
needed for fatty acid synthesis 105
Long-Chain Fatty Acid Synthesis
Lactic acid, Propionate, Amino acids
GlucoseRuminants
limit use of glucose
Acetyl-CoA carboxylase
Acetyl CoA Fatty acids Triglycerides
NADPH NADP
Acetate Glycerol-3-P
Glu-6-P dehydrogenase Gly-3-P dehydrogenase
Glucose
106
Long-Chain Fatty Acid Synthesis
Glucose
NADPH NADP
Pyruvate Malate Fatty acids
Malate dehydrogenase NADP
Pyruvate Oxaloacetate
NADPH
Acetyl CoA Acetyl CoA
Oxaloacetate Citrate lyase
Citrate Citrate Acetate
Mitocondria Cytosol
107
Long-Chain Fatty Acid Synthesis
Citrate Citrate
Isocitrate
NADP Isocitrate
NADPH dehydrogenase
a-Ketoglutarate
Mitochondria Cytosol
Supplies about half of NADPH for fatty acid synthesis
108
Long-Chain Fatty Acid Synthesis
Butyrate
• Can be used in mammary gland as primer for
synthesis of fatty acids
• Shorter chain acids
Methylmalonyl (propionate)
• Is used as primer for synthesis of fatty acids
in sheep fed high-concentrate diets
• Branched-chain acids
109
LIPIDS
What are lipids?
110
Lipids
Lipids (fats & oils)
 Most livestock feeds contain 1-5% fat or oil
• Insoluble in water but soluble in organic solvents
• Dense energy source:
– 1 g fat = 9.45 kcal GE
– 1 g protein = 3.5 kcal GE
– 1 g CHO = 4.2 kcal GE
• Thus, fat produces 2.25 times the energy than CHO
111
Lipids
1. Triglyceride: primary storage form of lipids
2. Saturated fatty acids: contain no double
bonds
3. Unsaturated fatty acids: contain 1 or more
double bonds
112
Lipids
113
Lipids
• Fats = solid at room temp = animal origin
– saturated
• Oils = liquid at room temp = plant origin +
fish
– unsaturated
114
Functions of Lipids
• Dietary energy supply
• Source of insulation & protection
• Source of essential fatty acids (EFA)
• Carrier for fat soluble vitamins
115
Lipids
• Essential fatty acids (EFA): Those fatty acids that an
animal requires, but which it cannot be synthesized in
adequate amounts to meet the animal’s need
– Linoleic C18:2
– Linolenic C18:3
– Arachidonic C20:4
116
Oleic Acid (OA): C18:1, n-9 or -9
Good source: Olive oil, Peanut oil, Soy oil
Linoleic Acid (LA): C18:2, n-6 or -6.
Essential Fatty Acid
Alpha Linolenic Acid (ALA): C18:3, n-3 or -3.
Essential Fatty Acid
117
Eicosapentaenoic Acid (EPA): C20:5, n-3 or -3. Essential Fatty Acid. Good
source: Fish oil
Docosahexaenoic Acid (DHA): C22:6, n-3 or -3. Essential
Fatty Acid. Good Source: Fish oil
Arachidonic Acid (AA): C20:4, n-6 or -6. Good source:
Liver, Beef. 118
EFA
• Physiological needs:
– Cell membrane structure
– Synthesis of prostaglandins which
control blood pressure and smooth
muscle contractions
• Deficiency:
– Scaly, flaky skin (Poor feather growth)
– Poor growth
119
Plasma Membrane
120
Sources of Lipids (EFA)
• Most feeds contain low levels
– > 10%
• Unprocessed oil seeds (soybean, cottonseed,
sunflower seed) contain up to 20% fat
• Forages and Fodders are not good sources
• Traditionally, if additional fat is needed it is added
to the diet
– Animal fats
– Vegetable oils
121
Lipid Digestion
• Occurs in the small intestine (duodenum)
• Bile produced by liver emulsifies fat
• Pancreatic lipase (enzyme) breaks apart
fat for absorption
• Monoglycerides (MG)—absorbed into SI
mucosal cells
• Free Fatty Acids (FFA)—absorbed into SI
mucosal cells or enter blood circulation
directly 122
Lipid Absorption
• Very efficient
– Absorption rates range from 70-96%
• Generally, oils (unsaturated fats) are
absorbed more completely than fats
(saturated fats)
123
Ketosis
• Disorder of metabolism
– Insufficient energy intake in high producing
animals (e.g. Dairy cattle in early lactation and
sheep in late pregnancy)
– Results in catabolism (breakdown) of body
energy (fat) reserves
124
Ketosis
• 2 C fragments (ketones) of fat catabolism
(breakdown) build up
• Toxic levels cause
– Body weight loss
– Abortion
– Poor milk production
125
Ideal = no limitation to burn fat in the CAC
126
Worse = deviate fat to ketone synthesis
- low energetic
efficiency/hypoglacemia
- “drunk cow” 127
Worst = fatty liver disease
128
AMINO ACIDS GLUCOSE TRIGLYCERIDES
(in chylomicrons)
Blood
GLUCOSE
GASTROINTESTINAL
TRACT
+ H2O +
CO2
MOST TISSUES
Oxidation
ATP
1
AMINO ACIDS GLUCOSE TRIGLYCERIDES
(in chylomicrons)
Blood
GLUCOSE
GASTROINTESTINAL
TRACT
HEPATOCYTES IN LIVER
+ H2O +
CO2
MOST TISSUES
Oxidation
ATP
Fatty acids
Triglycerides
Glyceraldehyde
3-phosphate Glycogen
Glucose
+ H2O +
CO2 ATP
1
2
AMINO ACIDS GLUCOSE TRIGLYCERIDES
(in chylomicrons)
Blood
GLUCOSE
GASTROINTESTINAL
TRACT
HEPATOCYTES IN LIVER
+ H2O +
CO2
MOST TISSUES
Oxidation
ATP
Triglycerides
ADIPOSE TISSUE
VLDLs
Triglycerides
Fatty acids
Triglycerides
Glyceraldehyde
3-phosphate Glycogen
Glucose
+ H2O +
CO2 ATP
1
2
3
AMINO ACIDS GLUCOSE TRIGLYCERIDES
(in chylomicrons)
Blood
GLUCOSE
GASTROINTESTINAL
TRACT
GLUCOSE
HEPATOCYTES IN LIVER
SKELETAL
MUSCLE
Storage
+ H2O +
CO2
MOST TISSUES
Oxidation
ATP
Triglycerides
ADIPOSE TISSUE
VLDLs
Fatty
acids
Triglycerides
Glyceraldehyde
3-phosphate
Glucose
Fatty acids
Triglycerides
Glyceraldehyde
3-phosphate Glycogen
Glucose
Glycogen
Glycogen
+ H2O +
CO2 ATP
1
2
3
4
4
AMINO ACIDS GLUCOSE TRIGLYCERIDES
(in chylomicrons)
Blood
GLUCOSE
GASTROINTESTINAL
TRACT
GLUCOSE
HEPATOCYTES IN LIVER
SKELETAL
MUSCLE
Storage
+ H2O +
CO2
MOST TISSUES
Oxidation
ATP
Triglycerides
ADIPOSE TISSUE
VLDLs
Triglycerides
Fatty
acids
Triglycerides
Glyceraldehyde
3-phosphate
Glucose
Fatty acids
Triglycerides
Glyceraldehyde
3-phosphate Glycogen
Glucose
Glycogen
Glycogen
+ H2O +
CO2 ATP
1
2
3
4 5
4
AMINO ACIDS GLUCOSE TRIGLYCERIDES
(in chylomicrons)
Blood
GLUCOSE
GASTROINTESTINAL
TRACT
GLUCOSE
HEPATOCYTES IN LIVER
SKELETAL
MUSCLE
Storage
+ H2O +
CO2
MOST TISSUES
Oxidation
ATP
Triglycerides
ADIPOSE TISSUE
VLDLs
Triglycerides
Fatty
acids
Triglycerides
Glyceraldehyde
3-phosphate
Glucose
Keto acids
Fatty acids
Triglycerides
Glyceraldehyde
3-phosphate Glycogen
Glucose
Glycogen
Glycogen
+ H2O +
CO2 ATP
1
2
3
4 5
6
4
AMINO ACIDS GLUCOSE TRIGLYCERIDES
(in chylomicrons)
Blood
GLUCOSE
GASTROINTESTINAL
TRACT
GLUCOSE
HEPATOCYTES IN LIVER
SKELETAL
MUSCLE
Storage
+ H2O +
CO2
MOST TISSUES
Oxidation
ATP
Triglycerides
ADIPOSE TISSUE
VLDLs
Triglycerides
Fatty
acids
Triglycerides
Glyceraldehyde
3-phosphate
Glucose
Keto acids
Fatty acids
Proteins
Triglycerides
Glyceraldehyde
3-phosphate Glycogen
Glucose
Glycogen
Glycogen
+ H2O +
CO2 ATP
1
2
3
4 5
6
7
4
AMINO ACIDS GLUCOSE TRIGLYCERIDES
(in chylomicrons)
Blood
GLUCOSE
GASTROINTESTINAL
TRACT
GLUCOSE
HEPATOCYTES IN LIVER
SKELETAL
MUSCLE
Storage
+ H2O +
CO2
MOST TISSUES
Oxidation
ATP
Triglycerides
ADIPOSE TISSUE
VLDLs
Triglycerides
Fatty
acids
Triglycerides
Glyceraldehyde
3-phosphate
Glucose
Keto acids
Fatty acids
Proteins
Triglycerides
Glyceraldehyde
3-phosphate Glycogen
Glucose
Glycogen
Glycogen
Proteins
Proteins
+ H2O +
CO2 ATP
1
2
3
4 5
6
7
8
4
129
1
Liver glycogen
Glucose
LIVER
Blood
HEART
ADIPOSE TISSUE
SKELETAL MUSCLE TISSUE
OTHER TISSUES
1
Liver glycogen
Glucose
LIVER
Glycerol
Blood
HEART
Fatty acids
Glycerol
Triglycerides
ADIPOSE TISSUE
SKELETAL MUSCLE TISSUE
OTHER TISSUES
2
Fatty acids
1
Liver glycogen
Glucose
LIVER
Lactic acid
Glycerol
Blood
HEART
Fatty acids
Glycerol
Triglycerides
ADIPOSE TISSUE
SKELETAL MUSCLE TISSUE
OTHER TISSUES
3
2
Fatty acids
1
Liver glycogen
Keto acids
Glucose
Amino acids
LIVER
Lactic acid
Glycerol
Blood
HEART
Muscle proteins
Fatty acids
Glycerol
Triglycerides
ADIPOSE TISSUE
Fasting or
starvation
SKELETAL MUSCLE TISSUE
OTHER TISSUES
Proteins
Amino acids
Amino acids
4
4
3
4
2
Fatty acids
1
Liver glycogen
Keto acids
Glucose
Amino acids
LIVER
Lactic acid
Glycerol
Blood
HEART
Fatty acids
Muscle proteins
Fatty acids
Glycerol
Triglycerides
ADIPOSE TISSUE
Fasting or
starvation
SKELETAL MUSCLE TISSUE
OTHER TISSUES
Fatty acids
Proteins
Amino acids
Amino acids
Fatty acids
ATP
ATP
ATP
4
5
5
4
3
5
4
2
Fatty acids
1
Liver glycogen
Keto acids
Glucose
Amino acids
LIVER
Lactic acid
Glycerol
Blood
HEART
Fatty acids
Muscle proteins
Fatty acids
Glycerol
Triglycerides
ADIPOSE TISSUE
Fasting or
starvation
SKELETAL MUSCLE TISSUE
OTHER TISSUES
Fatty acids
Proteins
Amino acids
Amino acids
Fatty acids
Lactic acid
ATP
ATP
ATP
ATP
4
5
5
6
4
3
5
4
2
Fatty acids
1
Liver glycogen
Keto acids
Glucose
Amino acids
LIVER
Lactic acid
Glycerol
Blood
HEART
Fatty acids
Muscle proteins
Fatty acids
Glycerol
Triglycerides
ADIPOSE TISSUE
Fasting or
starvation
SKELETAL MUSCLE TISSUE
OTHER TISSUES
Fatty acids
Proteins
Amino acids
Amino acids
Fatty acids
Lactic acid
ATP
ATP
ATP
ATP
ATP
4
5
5
6
7
4
3
5
4
2
Fatty acids
1
Liver glycogen
Keto acids
Glucose
Amino acids
LIVER
Fatty acids
Lactic acid
Ketone bodies
Glycerol
Blood
NERVOUS
TISSUE Ketone
bodies
Glucose
Starvation
HEART
Fatty acids
Muscle proteins
Fatty acids
Glycerol
Triglycerides
ADIPOSE TISSUE
Fasting or
starvation
SKELETAL MUSCLE TISSUE
Ketone bodies
OTHER TISSUES
Fatty acids
Proteins
Amino acids
Amino acids
Fatty acids
Ketone bodies
Lactic acid
ATP
ATP
ATP
ATP
ATP
ATP
ATP
ATP
ATP ATP
4
5
8
5
6
8
8
7
4
3
5
4
2
8
1
Liver glycogen
Keto acids
Glucose
Amino acids
LIVER
Fatty acids
Lactic acid
Ketone bodies
Glycerol
Blood
NERVOUS
TISSUE Ketone
bodies
Glucose
Starvation
HEART
Fatty acids
Muscle proteins
Fatty acids
Glycerol
Triglycerides
ADIPOSE TISSUE
Fasting or
starvation
SKELETAL MUSCLE TISSUE
Ketone bodies
OTHER TISSUES
Fatty acids
Proteins
Amino acids
Glucose
6-phosphate
Pyruvic acid
Lactic
acid
Muscle glycogen
(aerobic) (anaerobic)
Amino acids
Fatty acids
Ketone bodies
Lactic acid
ATP
O2
ATP
ATP
ATP
ATP
ATP
ATP
ATP
ATP
ATP
ATP ATP
+ O2
–
4
5
8
5
6
8
8
7
4
3
9
5
4
2
8
130
PROTEINS
What are proteins
131
Proteins
• Principal constituent of organs and soft
tissues
• Highest concentration of any nutrient,
except water, in the body of all living
organisms and animals
• Required for life
132
Nutrients
Function of Proteins
• supply amino acids for body proteins
- muscle; bone; connective tissue; hormones;
enzymes; antibodies; milk components; cell repair
133
Proteins
• DEFINITION: Proteins are long chains of
amino acids (AA)
– Formed by peptide linkages
• Amino group + carbon skeleton
134
Proteins
Amino Acid (AA) Protein (2 AA joined by peptide
bond between  carboxyl
and  amino group
135
Proteins
• Dietary requirements highest in young,
growing animals and declines at maturity
• Large molecules that vary greatly in size,
shape, and function
– MW = 5000 to millions
136
Categories of Protein
1. Essential Amino Acids (EAA):
– required in the diet
– cannot be synthesized at a rate sufficient to
meet the nutritional requirements
137
Essential AA
• PVT TIM HALL (KNOW!)
• Phenylalanine
• Valine
• Threonine
• Tryptophan
• Isoleucine
• Methionine
• Histidine
• Arginine
• Lysine
• Leucine
138
Categories of Protein
2. Nonessential AA
– animal can produce enough to meet it’s
requirements
3. Semi-essential AA
– Animal can not always produce enough to
meet its requirements
139
Functions of Protein
• Basic structural units of animal body
– Collagen, blood, elastin
• Body metabolism
– Enzymes, hormones, immune system,
hereditary transmission
• Production
– Meat, milk, egg, skin/hair
140
Protein Deficiency
• Reduced growth & feed efficiency
• Infertility
• Reduced birth weights
• Reduced production,and reproduction
141
Sources of Protein
• Most common feedstuffs contain some
protein (the quality is another issue)
– Animal origin diets are the richest sources
– Plant origin diets are also good sources of
proteins
• KEY: to combine feedstuffs into the diet
so that AA requirements are met
– e.g. Using a corn-soybean meal diet for pigs
142
Protein Digestion
• Proteins must be broken down into AA for
absorption in the GIT
– Exception! Early in life (> 48 h after birth)
proteins from milk (immunoglobulins) can be
absorbed intact across the intestinal
epithelium
143
Protein Digestion/Absorption
in Monogastrics
144
Monogastric Protein Digestion
• Stomach: HCl unfolds (denatures) proteins
and activates pepsinogen secreted by
stomach to pepsin
– Pepsin begins protein digestion to peptides
(short-chain proteins)
• Small intestine: enzymes (trypsin) break
peptides into AA
145
Monogastric Protein
Absorption
• AA are absorbed in anterior part of the
small intestine
– Jejunum and ileum
• AA are absorbed and transported to tissue
via blood
146
Protein Digestion and
Absorption in Ruminants
147
Ruminant Protein Digestion
• In rumen, microbes break down protein to
peptides and AA and then degraded
further to ammonia, VFAs, and carbon
dioxide
• Ammonia and/or NPN (urea) + CHO
source form microbial proteins
148
Ruminant Protein Absorption
• Protein can be absorbed through rumen
wall as ammonia
• Microbial proteins pass to the lower
intestine where they are converted to AA
and absorbed
149
RUMEN
BLOOD STREAM
URINE
SALIVA
ABOMASUM &
SMALL INT.
LIVER TISSUES
FECES
N metabolism in ruminants
FEED
protein
NPN
protein
protein
feed
protein
NPN
microbial protein
peptides
amino acids
NH3 NH3
NH3
urea
urea urea
protein
amino acids
amino acids
endogen.
nitrogen
metabolic
fecal
protein
150
Fates of Absorbed AA
1. Tissue protein synthesis
2. Synthesis of enzymes, hormones & other
metabolites
3. Use for energy (inefficient energy source)
151
Various points at which amino acids enter the
Krebs cycle for oxidation
152
MINERALS
What are minerals?
153
Minerals
• Inorganic components of the diet
– inorganic elements (contain no carbon), component left
after ashing
• Can not be synthesized or decomposed by
chemical reactions
• Total mineral content is called “ash”
• Makes up 3-5% of the body weight
154
1ppm =
1/1000000
So one
parts-per
million is
equal to
0.0001
percent:
1ppm =
1/1000000
155
Categories of Minerals
• Macro Minerals: Minerals normally present at
greater levels in animal body or needed in large
amounts in the diet (found in concentrations >
100 ppm)
– Calcium (Ca)
– Phosphorus (P)
– Sodium (Na)
– Chloride (Cl)
– Magnesium (Mg)
– Potassium (K)
– Sulfur (S)
+ C O N
156
Categories of Minerals
• Micro (Trace) Minerals: Minerals normally present at low
levels in animal body or needed in small amounts in the
diet (found in concentrations < 100 ppm)
– Cobalt (Co)
– Copper (Cu)
– Fluoride (Fl)
– Iodine (I)
– Iron (Fe)
– Manganese (Mn)
– Molybdenum (Mo)
– Selenium (Se)
– Zinc (Zn)
157
General Mineral Functions
• Skeletal formation and maintenance (Ca, P, Mg,
Cu, Mn)
• Protein synthesis (P, S, Zn)
• Oxygen transport (Fe, Cu)
• Fluid balance—osmotic pressure (Na, Cl, K)
• Acid-base balance regulation (Na, Cl, K)
• Activators or components of enzyme systems
(Ca, P, K, Mg, Fe, Cu, Mn, Zn)
• Mineral-Vitamin relationships (Ca, P, Co, Se)
158
Macro Mineral Deficiencies
• Ca and P
– Inadequate bone mineralization
• Rickets (young)
• Osteomalacia (adult)
– Phytate P—bound and unavailable to nonruminants
• Mg
– Grass tetany-convulsions, coma, death
• Likely in grazing, lactating females in early spring
or fall
• Mg is there in the plant, just in bound form due to
lack of sunlight
159
Macro Mineral Deficiencies
• Fe
– Anemia (insufficient haemoglobin)
– Young pigs (rapid growth, low stores, low Fe
in milk)
160
Trace Mineral Deficiencies
• Mn
– Poor growth
– Poultry—Perosis—deformed and enlarged
hock joints
• I
– Goiter—swollen thyroid
161
Trace Mineral Deficiencies
• Cu
– Fading hair coat color (depigmentation)
– Low Cu utilization may result when excess Mo or Zn
• Zn
– Parakeratosis (dermatitis-thickening of skin)
– Poor hair or feather development
– Exacerbated by high Ca
162
Trace Mineral Deficiencies
• Se
– White muscle disease-nutritional muscular
dystrophy
• Muscle appears white due to Ca-P deposits
– Due to low concentration of Se in soil
163
Mineral Toxicities
• Usually not a problem
• NaCl can be for swine and poultry
– Levels above 8%--causes nervous disorders
• Cu a big problem for sheep and young animals
– Mineral mixes for other species/age groups used
• Se has a small margin between requirement (0.3
ppm) & toxicity (8 ppm)
– Plants grown in regions of high soil Se
164
Sources of Minerals
• Forages usually considered good sources
of minerals
– Largely dependant on soil conditions
• Grains are fair source of P, but low in
other minerals
• Mineral premixes
• Mineral blocks
165
Mineral Absorption
• Minerals are converted to their ionic form
and absorbed in the small intestine
166
Mineral Functions
• Part of some amino acids & vitamins
• metabolic reactions
• enzyme function
• body structure
• transport oxygen
Deficiency examples
White muscle
=selenium
Grass Tetany
=magnesium
Rickets
=calcium
White hair on black cattle
=copper
Anemia
=iron
Retained Placenta
=selenium and Vitamin E
167
Vitamins
• What are vitamins?
• What are their roles in animal production?
168
small amounts for specific body
functions
a. 2 classifications
1. water soluble – C & B-
complex (see Fig 5-1)
– microbes synthesize in
ruminants & horses
2. fat soluble – A, D, E, K
– A & E required in
diets of all animals
– D – produced by
effects of sun on skin
– K – synthesis by
rumen/cecum
microbes
169
Types of Vitamins
• Fat-soluble vitamins
– Vit A (carotene): vision
– Vit D: Ca, P absorption
– Vit E (tocopherol): antioxidant
– Vit K (menadione): blood clotting
• Short shelf life (3-4 months)
• Need lipids for absorption
• Destroyed by heat, minerals
170
Types of Vitamins
• Water-soluble vitamins
– Thiamine
– Riboflavin
– Niacin
– Pyridoxine
– Pantothenic acid
– Biotin
– Choline
– Folic acid
– Vitamin B12
– Vitamin C
B Complex Vitamins
171
Vitamin Functions
• Reproduction
• Fetal Development
• Colostrum Production
• Milk production
• Wool
• Egg
• Racing
172
Vitamin Deficiencies
• Vitamin A
– Xerophtalmia: night blindness
– Poor growth, reproductive failure
• Vitamin D
– Rickets
– Osteomalacia
• Vitamin K
– Poor blood clotting/hemorrhaging
173
Vitamin Deficiencies
• Vitamin C
– Scurvy: slow wound healing, spongy gums,
swollen joints, anemia
• B Complex Vitamins
– Reduced growth/poor appetite
– Dermatitis
– Muscular incoordination
174
Most likely deficient…
• In practical situations:
– Ruminants: A, E, D (limited circumstances)
– Swine: riboflavin, niacin, pantothenic acid,
choline, B12, A, D, and sometimes E
– Poultry: All vitamins except Vitamin C, inositol
175
Vitamin Toxicity
• Unlikely ($)
• Generally nontoxic
– Exceptions:
• A, D, Niacin, Pyridoxine, Choline
176
Sources of Vitamins
• A: green, leafy forages, corn, fish oil
• D: fish oils, sun-cured hay
• E: seed germ oils, green forage or hay
• K: green forage, fish meal, synthetic menadione
177
Sources of Vitamins
• B Vitamins: green forages usually
– Niacin: present in grains, but unavailable to
nonruminants
• B12: protein feeds of animal origin, fermentation
products
• C: citrus fruits, green, leafy forages, well-cured
hay
178
Sources of Vitamins
• Most nonruminants rations contain a
vitamin premix
– Consume basically no forages and B vitamins
are poorly available from cereal grains
179
Vitamin Absorption
• Most vitamins are absorbed in the upper
portion of the small intestine
• Water soluble vitamins are rapidly
absorbed
• Fat soluble vitamin absorption relies on fat
absorption mechanisms
180
Vitamins
• Organic substances required by the animal in
very small amounts
• Necessary for metabolic activity but not part of
body structure
• Content varies greatly in the feed
• Requirements depend on species
– Monogastrics = a lot b/c cannot synthesize
– Ruminants = few vitamins due to microbial synthesis
181
Chapter 5
Formulation of Feeds
182
Formulation of Feeds
 Feed formulation: the preparation of
nutritionally-complete diets for feeding animals
 Least-cost feed formulation:
 a feed formula that is both nutritionally-complete and,
 with a minimum ingredient cost
 Now-a-days is developed and completed
through the use of computers using linear-
programming software
 Manual feed formulations (pearson square,
algebiric, trial error)
-Nutrient composition (proximate + detergent fiber)
basic for formulation of feeds 183
Least-cost Formulation
• Least-cost feed formulations require that the
following information be provided:
 cost of feed ingredients
 nutrient content of feed ingredients
 nutrient requirement of the animal
 availability of the nutrient to the animal
 minimum-maximum restrictions on levels
184
Least-cost Formulations
 Costs of feed ingredients and nutrient content are fairly
available for most commercial feedstuffs
 costs can be evaluated on a daily basis
 nutrient requirements are fairly well known
 the most critical piece of information regards
digestibility/availability of nutrients within the feed
ingredient
 various indices: digestible energy (DE), metabolisable
energy (ME), apparent protein digestibility (APD), etc.
 these can be set in formula with restrictions
 Expressing the Nutrient & Energy Content (DM/as-
is-bases)
185
Expressing the Nutrient & Energy Content
A) Dry matter (DM) basis - The amount contained in only the
DM portion of the feed ingredient/diet, i.e., without water.
[Because feeds contain varying amounts of DM, perhaps,
simpler and more accurate if both the composition and
nutrient requirements are expressed on a DM basis!?]
B) As-fed basis - The amount contained in the feed
ingredient/diet as it would be fed to the animal; including
water.
C) Air-dry basis:
1) Usually, assumed to be approximately 90% DM.
2) Most feeds will equilibrate to about 90% DM after a
prolonged, aerobic storage.
3) Air-dry and as-fed basis may be the same for many
common feeds. 186
Expressing the Nutrient & Energy Content
1)Percent dry matter?
 Determined by drying a sample to remove all
the moisture, and the weight of the remaining
is expressed as a percent of the original
weight.
Example - "1.0 g of maize grain is dried and
0.90 g of maize grain remained after drying,"
then:
0.9/1.0*100=90% DM
187
2/As-Fed Basis Converted to DM
Basis
a) Can be converted by:
188
Nutrient % on as-fed basis = Nutrient % on DM
basis
% DM in the feed expressed as
decimal fraction
% Nutrient (as-fed basis) = % Nutrient (DM basis)
% Feed DM 100% DM
OR
As-Fed Basis Converted to DM Basis
• Example - "Alfalfa silage analyzed to contain
7% CP on an as-fed basis and contained 40%
DM. What would be the CP content on DM
basis?"
• (0.07 ÷ 0.40)*100 = 17.5% CP on DM basis, or
189
7 = X = 17.5% CP on DM basis
40 100
3/DM Basis Converted to As-Fed
Basis
Can be converted by:
A) Nutrient % on DM basis x % DM in the
feed expressed as decimal fraction =
Nutrient % on as-fed basis
OR
190
% Nutrient (as-fed
basis)
= % Nutrient (DM
basis)
% Feed DM 100% DM
3/DM Basis Converted to As-Fed
Basis
• Example? - "Alfalfa silage analyzed contain
10% crude fiber (CF) on a DM basis. If the
linseed meal contains 91% DM, what would be
the % CF expressed on an as-fed basis?“
– 10.0 x 0.91 = 9.1, thus 9.1% on as-fed basis, or
191
x 10 = 9.1% Crude fiber on as-fed
basis
91 100
4/DM/as-fed basis Converted to
Air-Dry Basis
A) DM basis to air-dry basis (90% DM):
 Nutrient % on DM basis x 0.90 = Nutrient
% on air-dry basis
B) As-fed basis to air-dry basis (90% DM):
= (90/ % Feed DM)x Nutrient % on as-fed
basis = Nutrient % on air-dry basis
192
5/Amount in DM and as-fed?
A) Amount in DM = Amount in as-fed  DM
content (decimal)
B) Amount in DM = X (amount in as-fed) 
DM content (decimal)
Amount in as-fed?
X = Amount in DM/ DM content (Decimal)
193
6/ Rule of thumb for conversions
A. When converting from "as-fed to DM?"
• 1) The nutrient content will increase.
• 2)The weight will decrease
B. When converting from "DM to as-fed?"
• 1) The nutrient content will decrease.
• 2) The weight will increase.
194
Balancing rations-using the
Pearson Square
• EXAMPLE
• 1,000 kg of feed is needed to feed a 50-kg
growing calves. A feeding standards table
shows that a 14% crude protein ration is
needed. Maize and Soybean oil meal
(SBOM) are selected as feeds. A feed
composition table shows that maize has
8.9% and SBOM has 45.8% CP on DM
basis. How much maize and soybean oil
meal need to be mixed together for 1,000 kg
of feed? 195
STEP 1
• Draw a square with lines connecting the
opposite corners.
• Write the percent of crude protein (14) in the
center of the square.
14
196
STEP 2
• Write the feeds to be used and their crude
protein percents at the left hand corners of
the square.
14
Maize 8.9
Soybean oil meal 45.8
197
STEP 3
• Subtract the smaller number from the larger,
along the diagonal lines. Write the
differences at the opposite end of the
diagonals.
14
Corn 8.9
Soybean
oil meal 45.8
31.8= 45.8-14
5.1 =14-8.9
198
STEP 3
• The difference between the percent protein in
the soybean oil meal and the percent protein in
the ration are the parts of maize needed.
• The difference between the percent protein in
the maize and the percent protein in the ration
are the parts of soybean oil meal needed.
• The sum of the numbers on the right equals the
difference in the numbers on the left. This fact
is used as a check to see if the square is set up
correctly.
199
STEP 3
14
Maize 8.9
Soybean
oil meal 45.8
31.8
5.1
36.9 36.9
Parts maize
Parts SBOM
200
STEP 4
• Divide the parts of each feed by the total
parts to find the percent of each feed in
the ration
–Maize 31.8/36.9 x100 = 86.2%
–Soybean oil meal =5.1/36.9x100=13.8%
201
STEP 5
• It is known that 1,000 kg of the mixture is
needed. To find the kg of each feed in the
mix, the percent of each feed is multiplied by
the total kilograms of the mix
– Maize 1,000 x 0.862= 862 kg
– SBOM 1,000 x 0.138= 138 kg
*Numbers have been rounded to full pounds.
202
STEP 6
• Check the mix to ensure that the protein need
is met. Multiply the pounds of the feed in the
it’s precent protein .
– Maize 862 kg  0.089= 77 kg of maize protein
– SBOM 138kg  0.458= 63 kg of SBOM protein
• Add the kgs of protein together
– 77kg + 63kg = 140kg
• Divide by the total weight of the mix
– 140kg/1,000kg x 100= 14%
• The mix is balanced for crude protein content!
203
Using Algebraic Equation to
Balance Ration
• May be used instead of Pearson Square
• Basic equations are
 X= kilograms of grain needed
 Y= kilograms of supplement
• Equation #1
 X+Y= total kilogram of mix needed
• Equation # 2
 (% Nutrient in grain)  (X) + (% Nutrient in
supplement)  (Y) = kilograms of nutrient desired
204
EXAMPLE
• Same example as the 1st Pearson Square
Example
• Mix of 1,000 kg is to be balanced for protein
using two feeds.
• Place the desired values in equation 2
– REMEMBER TO EXPRESS % AS DECIMALS
• 0.089X+0.458Y=140
– 140 is found by multiplying the quantity of feed
(1,000 kg) by the percent (14) [or the amount] of
nutrient desired: 1,000 x 0.14
205
EXAMPLE cont…
• Either X or Y must be canceled by the
multiplication of equation 1 by the
percentage of nutrients for either X or Y, and
the resulting equation 3 is subtracted from
equation 2.
• This example uses the percentage crude
protein for maize (0.089), giving equation 3
0.089X+0.089Y = 89 (89 is found by multiplying
0.089  1,000 kg)
206
EXAMPLE cont…
 SUBTRACT equation 3 from equation 2
 0.089X + 0.458Y =140
-0.089X - 0.089Y = -89
0+ 0.369Y= 51
Y= 138 kilograms soybean meal
 X may then be found by substituting the value of Y in
equation or 2 and solving
 X+138 = 1,000
 X=1,000-138
 X= 862 kg of maize
OR , you can use equation 2:
 (0.089X + 0.458 (138) =140
207
Algebraic Equations
• Get the same result as Pearson square
• May be used to balance rations using 3 or
more feeds
• Same initial step must be taken as when
using the Pearson Square—group similar
feeds into two groups and determine the
proportions of each to be used in each
group
– After this is done the same procedure as above
is followed. 208
Algebraic diet formulation (equation with one unknown, X)
(A)
Example - "Formulate a 12% CP diet using corn (8.8% CP) and
a protein supplement (35% CP), with 3% rye (11.9% CP) and
7.5% milo (11.0% CP)."
2) Known quantities?
 3% rye + 7.5% milo = 10.5%, thus the remaining 89.5% to
be balanced!
3) Procedure & check? Algebraic equation with one un known, X:
 If % supplement = X
 % corn = 89.5 - X
 0.119 (3) + 0.11 (7.5) + 0.088 (89.5 - X) + 0.35X = 0.12 (100)
 From left, lb CP from rye, lb CP from milo, lb CP from corn, lb
CP from supplement, and lb CP in 100 lb of diet.
209
Algebraic diet formulation (equation
with one unknown, X), Contin….
• 0.357 + 0.825 + 7.876 - 0.088X + 0.35X = 12
0.35X - 0.088X = 12 - 7.876 - 0.825 -0.357
0.262X = 2.942
X = 11.229 [lb supplement]
89.5 - X = 78.271 [lb corn]
• Check?
• 0.119 (3) + 0.11 (7.5) + 0.088 (78.271) + 0.35 (11.229) = ?
• 0.357 + 0.825 + 6.888 + 3.930 = 12
210
B. Algebraic diet formulation (using
equations with two unknowns, X & Y)
 The same example - "Formulate a 12% CP diet using
corn (8.8% CP) and a protein supplement (35% CP), with
3% rye (11.9% CP) and 7.5% milo (11.0% CP).”
 Known quantities & fixed amount of CP?
 a) 3% Rye + 7.5% milo = 10.5%, thus remaining 89.5%
to be balanced.
 b) 0.119 (3) + 0.11 (7.5)
= 0.357 + 0.825 = 1.182, or 1.182 lb of CP per 100 lb
of diet (or 1.182%) is fixed.
 Thus, the remaining protein (10.818 lb/100 lb feed)
must be balanced with corn and supplement., 1.182+
10.818=12
3) Procedure & check? - See below 211
Algebraic equation with two unknowns, X & Y:
• X = lb corn in the diet
• Y = lb supplement in the diet
• Equation 1: X + Y = 89.5 lb diet
• Equation 2: 0.088X + 0.35Y = 10.818 lb CP
• Equation 3: -0.088X + -0.088Y = -7.876 (=0.08889.5)
0 + 0.262Y = 2.942
Y= 11.229 (lb supplement)
X = 89.5 - 11.229 = 78.271 (lb corn)
• Check?
• 0.119 (3) + 0.11 (7.5) + 0.088 (78.271) + 0.35 (11.229) = ?
• 0.357 + 0.825 + 6.888 + 3.930 = 12
212
C. Pearson square
1) The same example - "Formulate a 12% CP diet using corn
(8.8% CP) and a protein supplement (35% CP), with 3% rye
(11.9% CP) and 7.5% milo (11.0% CP)."
2) Known quantities & fixed amount of CP?
a) 3% Rye + 7.5% milo = 10.5%, thus remaining 89.5% to be
balanced.
b) 0.119 (3) + 0.11 (7.5) = 0.357 + 0.825 = 1.182, or 1.182 lb of
CP per 100 lb of diet (or 1.182%) is fixed.
 Thus, the remaining protein (10.818 lb/100 lb of feed or
10.818%) must be balanced with corn and supplement.
c) Need to determine the % CP necessary in corn supplement
combination to provide 10.818 lb/100 lb of feed . . .
10.818/89.5 x 100 = 12.087%.
3) Procedure & check? - See below
213
Pearson square
• Subtract the smaller number from the larger,
along the diagonal lines. Write the differences
at the opposite end of the diagonals.
12.08%
Corn 8.8
Supplement 35 %
22.913 parts corn
3.287 parts supplement
26.2 total parts
214
Pearson square
• 22.913 parts corn/26.2 total parts100 =87.454% corn
• 3.287 parts supplement/26.2 total parts100 = 12.546%
supplement
– 89.5 x 87.454% = 78.271 lb corn
– 89.5 x 12.546% = 11.229 lb supplement
• Check?
– 3.00 lb rye  11.9% CP = 0.357 lb CP
– 7.50 lb milo  11.0% CP = 0.825 lb CP
– 78.271 lb corn  8.8% CP = 6.888 lb CP
– 11.229 lb supplement  35.0% CP = 3.930 lb CP
– 100.00 lb diet 12.000 lb CP
215
Formulate a supplement (500 kg) to be fed with
1,500 kg of maize of complete diet."
%CP, % Ca, , % P,
Maize 8.8 0.03 0.27
SBOM 50.9 0.26 0.62
Dical - 23.35 18.21
Lime - 35.8 -
Use SBOM, Dical, Lime, salt, Vit premix, TM premix and maize as a carrier, and
Pigs need 14% CP, 0.5% Ca, 0.4% P, 0.5% salt, 0.1% TM (trace mineral) premix &
1.0% Vit premix. 216
Determine the "specifications" for the supplement
a) Complete diet is:
– 1500/2000100 = 75% maize
– 500/2000100 = 25% supplement
b) % CP in supplement:
– 0.088 (0.75) + X(25) = 0.14
0.066 + 0.25X = 0.14
0. 25X = 0.074
X = 0.296
[Thus, 0.296 x 100 = 29.6% (% CP in
supplement)]
217
c) % Ca in supplement:
0.0003 (0.75) + X (0. 25) = 0.005
0.000225 + 0.25X = 0.005
0.25X = 0.4775
X = 0.0191
[Thus, 0.0191 x 100 = 1.91% (% Ca in supplement)]
d/ % P in supplement:
0.0027 (0.75) + X (0.25) = 0.004
0.2025 + 25X = 0.004
0.25X = 0.001975
X = 0.0079
[Thus, 0.0079 X100 = 0.79% (% P in supplement)]
218
e) % salt in supplement:
0 (0.75) + X (0.25) = 0.005
X = 0.02
[Thus, 0.02 x 100 = 2% (% salt in supplement)]
f) % TM in supplement:
0 (0.75) + X (0.25) = 0.001
X = 0.004
[Thus, 0.004 x 100 = 0.4% (% TM premix in
supplement)]
219
Supplement specification, %
CP 29.6
Ca 1.9
P 0.8
Salt 2.0
TM premix 0.4
Vit premix 4
Ration formulation, Example 4
• In this example, a ration will be balanced using corn,
wheat hay, and cotton seed meal (feed values are listed
as: maize, 88% DM, 88.9% TDN, 9.8% CP, 0.03% Ca,
0.31% P; wheat hay: 84% DM, 53% TDN, 9.1% CP,
0.16% Ca, 0.24% P; cottonseed meal: 92% DM, 75%
TDN, 46.1% CP, 0.20% Ca, 1.16%P) for a 350-kg heifer
calf with a desired gain of 2.5 lb/day. Her daily
requirements are (heifer: weight 700, DMI (lb/d, 16.4),
ADG (lb/d, 2.5), TDN, lb/day (12.6 lb), CP, lb/day (1.68),
Ca, lb/day (28), P, lb/day (16):
– 16.4 lb daily dry matter intake
– 76.8% TDN (12.6 lb TDN ÷ 16.4 lb dry matter intake)
– 10.2% CP (1.68 lb CP ÷ 16.4 lb dry matter intake)
220
To balance this ration:
1) Balance for TDN
1.Draw a square and write 76.8 (the desired TDN
concentration) in the middle of the square (fig. 4)
2.At the upper left corner of the square, write “wheat
hay = 53%”.
3.At the lower left corner, write “corn = 88.9%”. These
numbers represent the TDN percentage in each
feedstuff.
 Note: The nutrient requirement in the middle of the
square must be between the nutrient concentrations
of the two ingredients. 221
Balance for TDN
4/ Subtract diagonally across the square, converting
negative answers to positive, and write the numbers on
the right side of the square (top value = 11.2, bottom
value = 23.8%)
5/ Sum the numbers on the right side of the square (11.2 +
23.8 = 35%). These numbers indicate that a ration of
11.2 parts wheat hay and 23.8 parts corn (a total of 35
parts) will result in a ration with 76.8 percent TDN.
6/ Divide the wheat hay and corn “parts” by 35 to get the
percentages of wheat hay (11.2 ÷ 35 = 32%) and corn
(23.8 ÷ 35 = 68%). 222
Balancing for TDN using the Pearson Square method
Balacing:
76.8%
Wheat hay 53%
Whole corn 88.9 %
11.2 ÷ 35 = 0.32 (32%
23.8 ÷ 35 = 0.68 (68%)
35 total parts 100%
223
2. Determine if crude protein is adequate
a) Multiply the percent of each feedstuff in the mix by its
crude protein content. Wheat hay is 32 percent of the mix
and contains 9.1 percent crude protein. Corn is 68 percent
of the mix and contains 9.8 percent crude protein.
Therefore, the crude protein concentration in the mix is:
– Wheat hay: 0.32 × 9.1 = 2.91%
– Corn: 0.68 × 9.8 = 6.66%
– 2.91 + 6.66 = 9.57%,  crude protein is not adequate
(is < 10.2%)
224
b) The crude protein content of the diet needs to be
increased by adding a protein supplement (cotton seed
meal for this example).
• Another Pearson Square will be used to determine the
correct amount of cotton seed meal.
225
3. Determine amount of protein supplement needed
a. Draw a square and write 10.2 (the desired CP
concentration) in the middle of the square.
226
wheat hay: corn mix 9.57
%
Cotton seed meal
46.1%
35.9 ÷ 36.53 = .983
(98.3%)
0.63 ÷ 36.53 = 0.017
(1.7%)
10.2%
• b. At the upper left corner of the square, write
“wheat hay:corn mix = 9.57”. At the lower left
corner, write “cottonseed meal = 46.1”.
• These numbers represent the CP percentage
in each feedstuff.
• Note: The nutrient requirement in the middle
of the square must be between the nutrient
concentrations of the two ingredients.
227
• c. Subtract diagonally across the square,
converting negative answers to positive,
and write the numbers on the right side of
the square (top value = 35.9, bottom value
= 0.63).
228
d). Sum the numbers on the right side of the
square (35.9 + 0.63 = 36.53). These numbers
indicate that a ration of 35.9 parts wheat hay:
corn mix and 0.63 parts cottonseed meal (a
total of 36.53 parts) will result in a ration with
10.2 percent CP.
e). Divide the wheat hay: corn mix and
cottonseed meal “parts” by 36.53 to get the
percentages of wheat hay: corn mix (35.9 ÷
36.53 = 98.3%) and cottonseed meal (0.63 ÷
36.53 = 1.7%).
229
4. Determine the pounds of dry matter that each feedstuff
contributes to the total, and convert from dry matter to as-fed
basis.
A)
Multiply the dry matter intake of the heifer (16.4 lb) by the
percentage of cotton seed meal in the ration (16.4 × 0.017 =
0.28 lb cottonseed meal).
Subtract this amount from total dry matter intake to determine
how much of the dry matter intake remains for the wheat hay
: corn mix (16.4 – 0.28 = 16.12).
Then multiply 16.12 by the relative amounts of wheat hay
and corn obtained from the first Pearson square (32 percent
wheat hay and 68 percent corn).
• Wheat hay: 16.12 × 0.32 = 5.16 lb wheat hay, dry
matter basis 230
b)
• Convert the individual amounts from dry
matter to as-fed basis. This step is required in
order to know how much of each ingredient to
feed to the heifer. The pounds of dry matter of
each feed are divided by the percentage of
dry matter in each feed.
– Cotton seed meal: 0.28 lb ÷ 0.92 = 0.30 lb CSM,
as fed
– Wheat hay: 5.16 ÷ 0.84 = 6.14 lb alfalfa hay, as-
fed
– Corn: 10.96 ÷ 0.88 = 12.45 lb whole corn, as-fed
basis
231
Example 5.Using the Pearson Square to Mix
Two Grains with a Supplement (START)
• Can be used to find out how much of two
grains should be mixed with a supplement
• Proportions of grain must be known first
232
EXAMPLE
• 2,000 pound mix of corn, oats and
soybean oil meal is needed. The mix is to
contain 16% Digestible Protein. A decision
is made to use ¾ corn and ¼ oats in the
mix. Thus, the proportion of corn to oats is
3:1. SBOM has 41.7% CP. How many
pounds of corn, oats and soybean oil meal
are needed?
233
STEP 1
• Need to find the weighted average percent of
protein in the corn and oats first.
• To do this
– Multiply the proportion of corn (3) by the percent
digestible protein in corn (7.1). Do the same for
oats. Then add the two answers together and
divide by the total parts (4). This answer is the
weighted average percentage of digestible protein
in the corn oats mix.
– Take 7.1% TDN for corn, 9.9% TDN for oats
234
STEP 1 cont…
• 3 x 7.1=21.3 (Corn)
• 1 x 9.9= 9.9 (Oats)
31.2
• 31.2/4= 7.8% Digestible Protein in the corn-
oats mix
235
Using the Pearson Square X
• Used in the same method as before to mix two
feeds.
• On a sheet of paper, work out this problem
16
3 parts Corn, 1 part oats 7.8%
Soybean oil meal 41.7%
236

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Nurition in ethiopia1.ppt

  • 1. Lecture note on Advances in Advanced Animal Nutrition By Yisehak Kechero (PhD, Associate professor) 1
  • 2. Nutrition: • Process by which living organism receives nutrients and uses them to promote it’s vital activities – Animals use nutrients to enable them to: • maintain . grow • reproduce . lay eggs • lactate . produce wool • work Chapter 1 Terminologies 2
  • 3. Terminologies Nutrient: Nutrients are chemical substances in food that body cells use for body function (growth, maintenance, and repair) Diet: Selection of food which is normally eaten by animal or population Food: Substance when eaten , digested, absorbed provide at least one nutrient Balanced diet : Diet that provide adequate amount of all nutrients 3
  • 4. Terminologies Malnutrition: Caused by incorrect amount of nutrient intake Nutritional status: Health status that produced by balanced between requirements and intake Dietitian/nutritionist: Persons who applies science of nutrition to animal in health and disease 4
  • 5. Terminologies Metabolism : process by which living systems acquire and use free energy to carry out vital processes Anabolism (biosynthesis ): Complex molecules are synthesized from simpler ones Catabolism(degradation): Complex molecules are broken to simpler ones Digestion: Breakdown of feed nutrients into suitable form for absorption Absorption: Transfer of digested nutrients from GIT into circulating blood or lymph systems 5
  • 6. Role of Metabolism in Nutrition Definition: the sum of all biochemical changes that take place in a living organism. Group these reactions into two types: anabolic catabolic Reactions: require energy release energy Produce: more complex more simple compounds compounds Modus Operandi: Occurs in small steps, each of which is controlled by specific enzymes. 6
  • 7. Chapter 2 FEED ANALYSIS SYSTEMS • Feed analysis systems – Proximate analysis system (Weende system) • Developed in 1864 at Weende Experiment Station in Germany – the analysis of feed into its basic components • Dry matter or water, crude protein, crude fiber, ether extract, ash, nitrogen free extract (NFE) – Detergent analysis system (Van Soest system) • Developed in 1964 at USDA Beltsville Research Center 7
  • 8. PROXIMATE ANALYSIS COMPONENTS • Dry matter • Ash (total ash or crude ash) • Crude protein (CP) • Ether extract (crude fat) • Crude fiber (CF) • Nitrogen-free extract (NFE) 8
  • 9. • Dry matter (DM) – Partial DM, Lab. DM, Actual/ total DM – DM is weight of a feed remaining after a feed is dried in a 100oC oven for 24 hours/105°C 16 hr etc • DM,% = wt after drying/wt before drying  100% • % moisture = 100 – DM,% Reagents: none Avg. 2 grams used – Problems with method • Errors from losses of volatile components – Particularly a problem with fermented feeds – Can be avoided by freeze drying • Drying at > 100oC destroys sample for further analysis – Can be avoided by freeze drying or drying at 50- 65oC for 72-48 hours in preparation for analysis AOAC 9
  • 10. Dry matter • Percent DM = (W3-W1)100/W2-W1) • Where, – W1= weight of empty container, – W2= weight of empty container plus sample – W3 = weight of container and sample after drying • Varies with types of feeds (ex green feeds, dry feeds, milk, silage, hay ) • Equipment: paper bag, forced air drying oven, analytical balance,Desiccator • Qulity control, Constant weight, duplicate 10
  • 11. • Ash ( Crude ash) – Material remaining after oxidation of a sample at 600oC for 2 hours in a muffle furnace • % Ash = wt after ashing/sample wt x 100% • % Organic matter = 100 - % ash – Equipment: Incineration dish, Analytical balance, Muffle furnace, Desiccator – % Ash = (W3- W2) x 100/ (W2-W1) – Problems • No indication of amounts of individual minerals • Some minerals (Sulfur, Selenium, Zinc, Iodine are lost) – Significance • May indicate soil contamination or adulteration of feedstuff or diet. 11
  • 12. • Crude protein (CP) – % Crude protein = %N x 6.25 – %N determination • Kjeldahl N Sample→Boil in conc. H2SO4→(NH4)2SO4→Add conc. NaOH, → Titrate catalyst distill NH3, and trap NH4 borate in boric acid • blue colour....pink colour Factor of 6.25 assumes that most proteins contain 16% N CP,% = measured mg N/100 mg sample x 100 mg protein/16 mg N = measured mg N/100 mg/sample x 6.25 Coversion Factors:  6.25 for all forages, compounded feeds and mixed feeds  5.7 for cereal grains  6.38 for milk 12
  • 13. Crude protein • % N = (Vs-Vb) x M(HCl) x 1 x 14.007/ (Wx 10) – Vs= ml Hcl needed to titrate the sample – Vb = ml Hcl needed for the blank test – M (HCl) = molarity of HCl – 1= the acid factor – 14.007= molecular weight of N, – 10 = conversion from mg/g to % (1.4007 to 14.007), and weight of the sample (g) Quality control: control standard should be used, duplicate analysis,use blank 13
  • 14. • Problems with crude protein procedure – Sources of N • True protein – Chains of amino acids bound by peptide linkages – Can meet the protein requirements of either nonruminant or ruminant animals • Nonprotein nitrogen – Forms » Free amino acids » Nucleic acids » Ammonia » Urea – Can meet the protein requirements of ruminant animals » Urea and biuret commonly added to ruminant diets – Can not meet the protein requirements of nonruminant animals – Says nothing about the amino acid composition of the feed source • Commonly assume that the concentration of individual amino acids is constant within the protein a given feedstuff • Can analyze for individual amino acids 14
  • 15. – Crude protein says nothing about the digestibility of a protein • Varies with feedstuff % Crude protein % Protein Digestibility Soybean meal 45 90 Feather meal 80 75 • Varies with heat damage – When overheated, protein will bind to the cell wall carbohydrates particularly across lysine – Causes » Molding of forages » Over-heating during processing » Over-drying of grains or soybeans – Referred to as the Maillard or Browning Reaction – Results % Crude protein % Protein Digestibility Well-preserved alfalfa hay 18 90 Heat-damaged alfalfa hay 18 60 15
  • 16. Crude Protein Non-protein nitrogen True protein (60 to 80%) Essential amino acids Arginine (Arg) Histidine (His) Isoleucine (Ile) Leucine (Leu) Lysine (Lys) Methionine (Met) Phenylalanine (Phe) Threonine (Thr) Tryptophan (Trp) Valine (Val) Non-essential amino acids Alanine (Ala) Asparagine (Asn) Aspartic acid (Asp) Cysteine (Cys) Glutamic acid (Glu) Glutamine (Gln) Glycine (Gly) Proline (Pro) Serine (Ser) Tyrosine (Tyr) Amides Amines Amino acids Peptides Nucleic acids Nitrates Ammonia Urea Lignified nitrogen 16
  • 17. • Ether extract (EE) – Also called crude fat – Material removed by refluxing ether through a feed sample for 4 hours % Ether extract = (Sample wt-residue after ether extract)/Sample wt x 100% – Theoretically represents fat content of the feedstuff • A high ether extract content should indicate a high energy concentration – Problem with procedure • Ether extract consists of: –True lipids »Fats and oils –Non-nutritional ether soluble components »Fat-soluble vitamins »Chlorophyll »Pigments »Volatile oils »Waxes 17
  • 18. Crude fiber (CF) – Procedure Sample→Extract with dilute H2SO4 →Residue→Burn at 600oC→Ash followed by dilute NaOH % CF = (Residue wt-Ash wt)/sample wt x 100% – Theoretically represents • the structural carbohydrates (Cellulose and lignin) – Limited digestibility in ruminants – Poor digestibility in nonruminants • Lignin – Indigestible by ruminants and nonruminants – Problems with procedure • Poor recovery of components % recovered – Cellulose 90 – Hemicellulose 50-60 – Lignin 13-70 18
  • 19. • Nitrogen-free extract (NFE) – No actual analysis – Calculation by difference • %NFE = %DM – (%ash+%CP+%EE+%CF) – Theoretically represents: • Starch • Sugars – Problems: • Contains all of the errors from other analyses – Largest error is unrecovered lignin will be placed in NFE 19
  • 21. • Neutral detergent fiber (NDF) – Consists of hemicellulose, cellulose, lignin, cell wall bound protein and insoluble ash – Significe: • Highly related to feed intake • DMI, % BW = 120/% NDF • Acid detergent fiber (ADF) – Consists of cellulose, lignin, poorly digested protein, and insoluble ash – Significance: • Highly related to digestibility and energy concentration • DDM% = 88.9 – (.779 x %ADF) • NEl, Mcal/lb (for legumes) = 1.011 – (0.0113 x %ADF) – Combination of DDM (determined from ADF) and DMI (determined from NDF) is used to determine Relative Feed Value (RFV) • RFV=DDM x DMI / 1.29 • Used for hay marketing 21
  • 22. – Nitrogen bound to acid detergent fiber is a measure of heat-damaged protein • Called ADIN or ADF-CP – Procedure Sample→Extract with AD→ADF→Analyze N by Kjeldahl procedure ADF-CP, % of total CP= %ADFN x 6.25/%CP x 100% – Relationship to protein digestibility (called adjusted CP) • If ADF-CP, % of total CP <14, ADIN is considered digestible – Adjusted CP = CP • If ADF-CP, % of total CP is >14 and <20 – Adjusted CP = ((100 – (ADF-CP, % of CP – 7))/100) x CP • If ADF-CP, % of total CP is > 20 – Adjusted CP = CP – ADF-CP, % of CP 22
  • 23. • N bound to NDF and ADF used to determine rumen degradable, rumen undegradable, and indigestible fractions Rumen degradable protein = Total CP – (NDFCP, % of CP xTotal CP) Rumen undegradable protein = (NDFCP, % of CP xTotal CP) – (ADFCP, % of CP xTotal CP) Indigestible protein = (ADFCP, % of CP xTotal CP) 23
  • 24. OTHER ANALYTICAL PROCEDURES • Near infrared reflectance spectroscopy (NIRS) – Determines the concentrations of protein, amino acids, lipids, and carbohydrates based on absorption of near infrared light – Advantages • Rapid • Used by most commercial labs – Limitations • Requires calibration • Inability to measure heterogeneous molecules like lignin • Inability to measure minerals 24
  • 25. • Atomic absorption spectroscopy – Used for mineral analysis – Procedure • Sample ashed and extracted into a solvent • Dissolved sample sucked into a flame with a light at a specific wavelength going through it • Absorption of light directly proportional to absorption of light – Limitation • Expense • High performance liquid chromatography – Used of amino acids, lipids and vitamins – Procedure • Sample dissolved in organic solvent injected into column • Column differentially separates components • Detector measures components as they through the column – Limitation • Expense 25
  • 26. 26
  • 27. Chemical Evaluation 3/Van Soest Fiber Analysis -- replaces the Weende System of crude fiber analysis with neutral and acid detergent fiber (NDF and ADF)  more accurate  more precisely identify the fiber components Van Soest Fiber Air-dry Feed Sample Boil with neutral detergent, pH = 7 Neutral Detergent Fiber cellulose, hemicellulose, and lignin Neutral Detergent Solubles cell contents and pectin Boil in acid detergent, pH = 0 Acid Detergent Fiber cellulose and lignin Acid Detergent Solubles hemicellulose Lignin Rinse in 72% sulfuric acid Cellulose (dissolved) 27
  • 29. Roughages • Contains more than 18% crude fiber when that are dry Hulls Straw Silage Roughage Hay Legume/non- legume forages Pasture 29
  • 30. Legume Roughages • Can take nitrogen from the air • Able to due so because they have nodules on their roots that contain bacteria • These bacteria fix the nitrogen from the air in soil and make it available for the plant to use – Do so by combining the free nitrogen with other elements to form nitrogen compounds • All the clovers, alfalfa, soybeans, peas and beans etc • Usually higher in protein than nonlegume roughages 30
  • 31. Nonlegume Roughages • Cannot use nitrogen from the air • Lower in protein • Many common livestock feeds are nonlegume 31
  • 32. Concentrates • Contains less than 18% crude fiber when dry • Two classes – Protein supplements – Energy feeds 32
  • 33. Protein Supplements • 20% or more CP protein • Divided into 2 groups based on their source 33
  • 34. Protein Supplements • Animal proteins – Come from animals or animal by-products – Common: meat and bone meal, fish meal, dried milk (whole & skimmed), blood meal, feather meal – Most contain more than 47% crude protein – More balanced essential amino acids – Variable quality compared to origin proteins • Plant Proteins – Come from plants – Common: soybean oil meal, cottonseed meal, linseed oil meal, peanut oil meal, corn gluten feed, brewers dried grains, distillers dried grains – Most contain less than 47% crude protein – Soybean oil meal is used most • Can supply necessary amino acids for swine and poultry 34
  • 35. Commercial Protein Supplements • Made by commercial feed companies • Mixes of animal and plant protein feeds • Usually made for 1 class of animal • Often mix of minerals, vitamins, antibiotics • Feed tag needs to be read and feeding directions followed 35
  • 36. Energy Feeds • Feeds with less than 20% crude protein • Most grains – Oats, corn, sorghum, barley, rye, wheat, ground ear corn, wheat bran, wheat middling's, dried citrus pulp, dried beet pulp, dried whey – Corn is the most widely used – Followed by sorghum grain, oats, barley 36
  • 37. Chapter 4 Nutrients 6 major classes 1. Water 2. carbohydrates - 3. lipids - 4. proteins 5. vitamins 6. minerals Energy 37
  • 38. Figure 5–1: The essential nutrients. 38
  • 39. Water (H2O) • Overlook when formulating rations—assumed animals have access to good quality water – EXTREMELY IMPORTANT • Cheapest & most abundant nutrient • May lose 100% of body fat, 50% of body protein and live • Lose 10% of body water, dehydration occurs and may result in death (species dependent) • 65-85% of body weight at birth • 45-60% of body weight at maturity • Many tissues contain 70-90% water 39
  • 40. Functions of Water 1. Transport of nutrients and excretions 2. Chemical reactions and solvent properties 3. Body temperature regulation 4. Aids in cell shape maintenance 5. Lubricates and cushions joints and organs 40
  • 41. Sources of Water 1. Drinking water 2. Water in feed 3. Metabolic water 41
  • 42. Sources of Water 1. Drinking – Pigs = 1.5-3 gal/hd/day – Sheep = 1-3 gal/hd/day – Cattle = 10-14 gal/hd/day – Horses = 10-14 gal/hd/day – Poultry = 2 parts water:1 part feed 42
  • 43. Sources of Water 2. Water contained in feeds • Highly variable in feedstuffs • Grains = 9-30% water • Forages – Hay <5% – Silage 65-75% – Lush young grass >90% 43
  • 44. Calculating Water Content of Feedstuffs • 100 kgs of silage (65% moisture) contains how much actual feed? • 100 kgs * .65 = 65 kgs of water • 100 kgs – 65 kgs = 35 kgs of feed 44
  • 45. Sources of Water 3. Metabolic Water - Results from the oxidation of organic nutrients in the tissues - 1 g of carbohydrates = 0.6 g of water - 1 g of protein = 0.4 g of water - 1 g of fat = 1 g of water - May account for 5-10% of total water intake 45
  • 46. Sources of Water Loss • Urine • Feces • Lungs • Skin • Milk 46
  • 47. Factors Affecting Water Intake • Temperature & humidity • Dietary factors –High moisture feeds reduce drinking –Fiber, DM intake, salt, and protein increase drinking • Lactating vs dry • Water quality 47
  • 48. Water Absorption • Readily absorbed – Monogastrics/Ruminants: Jejunum, Ileum, Cecum, Large Intestine – Ruminants: Rumen and Omasum 48
  • 50. Carbohydrates (CHO) • Primary component found in livestock feeds – 70% of DM of forages – 80% of DM of grains • Serve as source of energy or bulk (fiber) in the diet – Not ESSENTIAL/Technical nutrients • Synthesized by animals 50
  • 51. Types of CHO • Monosaccharides: 1 sugar molecule – Glucose • Primary sugar body uses for fuel, plants are rich in glucose – Fructose • Found in honey (75%), fruits, and cane sugar • Sweetest sugar, molasses – Galactose • Found many plants tissues • Present in low concentrations in animal feedstuffs 51
  • 53. 53 Galactose, sometimes abbreviated Gal, is a monosaccharide sugar that is less sweet than glucose. It is a C-4 epimer of glucose. Galactan is a polymer of the sugar galactose found in hemicellulose
  • 54. Types of CHO • Disaccharides: 2 sugar molecules linked by a glycosidic bond – a sugar consisting of two linked monosaccharide units • Forexample – Lactose (galactose + glucose),… lactase • Milk sugar – Sucrose (fructose + glucose),… sucrase • Table sugar – Maltose,…Maltase • also known as maltobiose or malt sugar, is a disaccharide formed from two units of glucose joined with an α(1→4) bond, formed from a condensation reaction 54
  • 56. Disaccharides: (+)-maltose “malt sugar” two glucose units (alpha) (+)-cellobiose two glucose units (beta) Cellobiose, a reducing sugar, consists of two β-glucose molecules linked by a β(1→4) bond. It can be hydrolyzed to glucose enzymatically or with acid 56 C12H22O11
  • 57. (+)-maltose O H H HO H H OH H OH OH O H HO H HO H OH H H OH O two glucose units alpha C-1 to C-4 reducing sugar O H HO H HO H H OH H OH O H O H HO H H OH H OH OH (+)-cellobiose two glucose units beta C-1 to C-4 reducing sugar 57
  • 58. O H HO H HO H OH H H OH glucose alpha C-1 to beta C1 fructose O HO H H HO H H OH H OH O H O H HO H H OH H OH OH galactose beta C-1 to C-4 glucose reducing sugar (+)-lactose O O CH 2 OH CH2OH H H OH HO H (+)-sucrose acetal non-reducing 58
  • 59. Types of CHO • Oligosaccharides: group of CHO consisting of 2-10 sugar groups • Present in feed ingredients – Fructooligosaccharides (Inulin): present in many feedstuffs in variable amounts – Galactooligosaccharides: present in soybeans and many feedstuffs 59
  • 60. Types of CHO • Oligosaccharides – Not hydrolytically digested or digested by the action of mammalian or livestock enzymes – Fermented by beneficial bacteria present in GIT – “Functional Feed Ingredient”: foodstuffs which, apart from their normal nutritional value, are said to help promote or sustain healthiness • PREBIOTIC – non-digestible food ingredients that stimulate the growth and/or activity of bacteria in the digestive system in ways claimed to be beneficial to health in simple stomach animals – a dietary supplement in the form of nondigestible carbohydrate that favors the growth of desirable microflora in the large bowel 60
  • 61. Probiotic • substance containing beneficial microorganisms: a substance containing live microorganisms that claims to be beneficial to humans and animals, e.g. by restoring the balance of microflora in the digestive tract 61
  • 64. Types of CHO • Polysaccharides: many sugar molecules(>10) linked by a glycosidic bond – Starch: a natural substance composed of chains of glucose units, made by plants and providing a major energy source for animals. • Formula: (C6H10O5)n – Cellulose: The main constituent of the cell walls of plants and algae. most abundant CHO in nature – Hemicellulose: One of the principle 64
  • 66. Polysaccharides starch cellulose Starch 20% amylose (water soluble) 80% amylopectin (water insoluble) amylose + H2O  (+)-maltose (+)-maltose + H2O  (+)-glucose starch is a poly glucose (alpha-glucoside to C-4) O O O O O O O O O O O O O O O O 66
  • 67. O O O O O O O O O O O O O O O O O O O O O O O O O O O CH2 O Amylopectin + H2O  (+)-maltose (+)-maltose + H2O  (+)-glucose Also a polyglucose, but branched every 20-25 units: 67
  • 68. Cellulose is a polyglucose with a beta-linkage: O O O O O O O O O O O O O O O O 68
  • 69. Cellular respiration begins with glycolysis 69
  • 70. ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 ATP H H H H HO 1 H ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 Glucose 6-phosphate O OH OH OH OH2C P ATP H HO H H H H H H H HO 1 2 H H Phosphofructokinase ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 Glucose 6-phosphate O OH OH OH CH2OH Fructose 6-phosphate O OH H OH2C 6 5 4 3 2 1 ADP P OH2C P ATP ATP OH H HO H H H H H H H H HO H HO 1 2 3 H H Phosphofructokinase ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 Glucose 6-phosphate O OH OH OH CH2OH Fructose 6-phosphate O OH H OH2C 6 5 4 3 2 1 CH2O Fructose 1, 6-bisphosphate O OH H OH2C ADP P P P OH2C P ATP ATP OH H HO H H H H H H H H H H HO HO H HO OH 1 2 3 4 H H Phosphofructokinase Dihydroxyacetone phosphate CH2OH CH2O C O Glyceraldehyde 3-phosphate HCOH CH2O O H C ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 Glucose 6-phosphate O OH OH OH CH2OH Fructose 6-phosphate O OH H OH2C 6 5 4 3 2 1 CH2O Fructose 1, 6-bisphosphate O OH H OH2C ADP P P P P P OH2C P ATP ATP OH H HO H H H H H H H H H H HO HO H HO OH 1 2 3 4 5 H H + 2H+ NADH HCOH C CH2O O O 1, 3-Bisphosphoglyceric acid (2 molecules) 2 P P Phosphofructokinase Dihydroxyacetone phosphate CH2OH CH2O C O Glyceraldehyde 3-phosphate HCOH CH2O O H C ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 Glucose 6-phosphate O OH OH OH CH2OH Fructose 6-phosphate O OH H OH2C 6 5 4 3 2 1 CH2O Fructose 1, 6-bisphosphate O OH H OH2C ADP P P P P P OH2C P ATP ATP OH H HO H H H H H H H H H H HO HO H HO OH 1 2 3 4 5 6 H H 2 NAD+ + 2 P + 2H+ NADH HCOH C CH2O O COOH O 2 2 ADP HCOH CH2O 1, 3-Bisphosphoglyceric acid (2 molecules) 2 3-Phosphoglyceric acid (2 molecules) P P P Phosphofructokinase Dihydroxyacetone phosphate CH2OH CH2O C O Glyceraldehyde 3-phosphate HCOH CH2O O H C ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 Glucose 6-phosphate O OH OH OH CH2OH Fructose 6-phosphate O OH H OH2C 6 5 4 3 2 1 CH2O Fructose 1, 6-bisphosphate O OH H OH2C ADP P P P P P OH2C P ATP ATP ATP OH H HO H H H H H H H H H H HO HO H HO OH 1 2 3 4 5 6 7 H H 2 NAD+ + 2 P + 2H+ NADH HCOH C CH2O O COOH O 2 2 ADP HCOH CH2O 1, 3-Bisphosphoglyceric acid (2 molecules) 2 3-Phosphoglyceric acid (2 molecules) COOH CH2OH HCO 2-Phosphoglyceric acid (2 molecules) P P P P Phosphofructokinase Dihydroxyacetone phosphate CH2OH CH2O C O Glyceraldehyde 3-phosphate HCOH CH2O O H C ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 Glucose 6-phosphate O OH OH OH CH2OH Fructose 6-phosphate O OH H OH2C 6 5 4 3 2 1 CH2O Fructose 1, 6-bisphosphate O OH H OH2C ADP P P P P P OH2C P ATP ATP ATP OH H HO H H H H H H H H H H HO HO H HO OH 1 2 3 4 5 6 7 8 H H 2 NAD+ + 2 P + 2H+ NADH HCOH C CH2O O COOH O 2 2 ADP HCOH CH2O 1, 3-Bisphosphoglyceric acid (2 molecules) 2 3-Phosphoglyceric acid (2 molecules) COOH CH2OH HCO 2-Phosphoglyceric acid (2 molecules) COOH CH2 C O Phosphoenolpyruvic acid (2 molecules) P P P P P Phosphofructokinase Dihydroxyacetone phosphate CH2OH CH2O C O Glyceraldehyde 3-phosphate HCOH CH2O O H C ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 Glucose 6-phosphate O OH OH OH CH2OH Fructose 6-phosphate O OH H OH2C 6 5 4 3 2 1 CH2O Fructose 1, 6-bisphosphate O OH H OH2C ADP P P P P P OH2C P ATP ATP ATP OH H HO H H H H H H H H H H HO HO H HO OH 1 2 3 4 5 6 7 8 9 H H 2 NAD+ + 2 P + 2H+ NADH 2 NAD+ + 2 HCOH C CH2O O COOH O 2 2 ADP P HCOH CH2O 1, 3-Bisphosphoglyceric acid (2 molecules) 2 3-Phosphoglyceric acid (2 molecules) COOH CH2OH HCO 2-Phosphoglyceric acid (2 molecules) Pyruvic acid (2 molecules) COOH CH2 2 2 ADP C O Phosphoenolpyruvic acid (2 molecules) COOH CH3 C O P P P P P Phosphofructokinase Dihydroxyacetone phosphate CH2OH CH2O C O Glyceraldehyde 3-phosphate HCOH CH2O O H C ADP O Glucose (1 molecule) CH2OH OH OH OH 4 1 3 2 5 6 Glucose 6-phosphate O OH OH OH CH2OH Fructose 6-phosphate O OH H OH2C 6 5 4 3 2 1 CH2O Fructose 1, 6-bisphosphate O OH H OH2C ADP P P P P P OH2C P ATP ATP ATP ATP OH H HO H H H H H H H H H H HO HO H HO OH 1 2 3 4 5 6 7 8 9 10 H H 70
  • 71. Function of CHO • Source of energy • Source of heat • Building block for other nutrients 71
  • 72. Sources of CHO • Cereal Grains – Most feedstuffs of plant origin are high in CHO content 72
  • 73. CHO Digestion • Dietary CHO must be converted to be absorbed – Simple sugars (monosaccharides) • How? – Action of amylase enzyme • Salivary amylase (swine, poultry) • Intestinal amylase – Action of other disaccharidases • Produced by mucosal lining of duodenum 73
  • 74. CHO Digestion • Mammals do not produce enzymes necessary to digest oligosaccharides and celluloses (fibrous feedstuffs) – Digestion occurs as result of bacterial fermentation • Where? – Rumen – Large Intestine (caecum and colon) 74
  • 75. CHO Digestion • Fermentation yields: – CO2 – H2O – CH4 – Heat (heat increment) – Volatile Fatty Acids (VFA) or also referred to as Short Chain Fatty Acids (SCFA) • 2 to 6 carbons 75
  • 76. VFA Production • Serve as 70 - 80% of energy requirement in ruminants – VFA’s produced in rumen • Serve as ~16% of Maintenance energy requirement in swine – VFA’s produced in large intestine They are: 1. Acetate/acetic acid (2 carbons) 2. Propionate/propionic acid (3 carbons) 3. Butyrate/butyric acid (4 carbons) 76
  • 77. VFAs • Acetate –  with higher roughage levels – Produced by cellulolytic & hemicellulolytic bacteria C H H H C OH O 77
  • 78. VFAs • Propionate –  with higher concentrate levels –  Feed efficiency – Ionophores increase propionate production C H H H C O C H H OH 78
  • 79. VFAs • Butyrate – Energy source for rumen wall growth • Papillae growth – Energy source for colonic cell growth • monogastrics C H H H C O C H H C H H OH 79
  • 80. VFAs • Lactate (not volatile) – Anaerobic conditions –  rumen and blood pH – Inhibits most microbial growth – Acidosis situation 80
  • 81. CHO Absorption • Once simple sugars are formed, they are absorbed rapidly by small intestine • Then monosaccharides diffuse into the portal vein which transports them to sites of metabolism 81
  • 82. VFA Absorption • Absorbed through the rumen wall or large intestine mucosa • Provide energy source to the animal 82
  • 83. Absorption of VFA 70% of VFA absorbed from rumen-reticulum 60 to 70% of remainder absorbed from omasum Papillae are important – provide surface area Absorption from rumen is by passive diffusion Concentration in portal vein less than rumen VFA concentrations Rumen 50 - 150 mM Portal blood 1 - 2 mM Peripheral blood 0.5 - 1 mM Absorption increases at lower pH H+ + Ac- HAc Undissociated acids diffuse more readily At pH 5.7 to 6.7 both forms are present, however most is dissociated At higher pH, 1 equiv of HCO3 enters the rumen with absorption of 2 equiv of VFA 83
  • 84. VFA Absorption Absorption of Ac- Ac- Ac- Portal HAc blood H+ Metabolism HCO3 - H2O H2CO3 + CO2 CO2 Carbonic Metabolism anhydrase HAc HAc Rumen 84
  • 85. VFA Absorption Rate of absorption: Butyrate > Propionate > Acetate Absorption greater with increasing concentrations of acids in the rumen Absorption increases at lower rumen pH Absorption greater in grain fed animals Faster fermentation – More VFA produced Lower pH Growth of papillae 85
  • 86. Metabolism of VFA by GIT Half or more of butyrate converted to - hydroxybutyric acid in rumen epithelium. 5% of propionate converted to lactic acid by rumen epithelium. Some acetate is used as energy by tissues of gut. VFA and metabolites carried by portal vein to liver. 86
  • 87. Tissue Metabolism VFA VFA GIT tissues Liver Body tissues Use of VFA Energy Carbon for synthesis Long-chain fatty acids Glucose Amino acids Other 87
  • 88. Utilization of Acetate in Metabolism 1. Acetate (As energy) Energy Acetate Acetyl CoA Krebs cycle 2 CO2 2 carbons (10 ATP/mole) 2. Acetate (Carbon for synthesis of fatty acids – in adipose) Acetate Acetyl CoA Fatty acids Lipids H +NADPH NADP + Glycerol Pentose PO4 CO2 shunt Glucose 88
  • 89. Utilization of Butryate in Metabolism Butyrate (As energy) Butyrate Butyrl CoA B-hydroxybutyrate Acetyl CoA Krebs cycle 2 CO2 Energy (27 ATP/mole) Some butyrate also used as a primer for short-chain fatty acids 89
  • 90. Utilization of Propionate in Metabolism Propionate Propionate Propionyl CoA Methylmalonyl CoA CO2 Succinyl CoA Vit B12 Glucose Krebs cycle 2 CO2 Energy (18 ATP/mole) 90
  • 91. Utilization of VFA in Metabolism Summary Acetate Energy Carbon source for fatty acids Adipose Mammary gland Not used for net synthesis of glucose Propionate Energy Precursor of glucose Butyrate Energy Carbon source for fatty acids - mammary 91
  • 92. Effect of VFA on Endocrine System Propionate Increases blood glucose Stimulates release of insulin Butryate Not used for synthesis of glucose Stimulates release of insulin Stimulates release of glucagon Increases blood glucose Acetate Not used for synthesis of glucose Does not stimulate release of insulin Glucose Stimulates release of insulin 92
  • 93. Energetic Efficiency of VFA in Metabolism ATP/mole Energy in ATP % Heat of (kcal/mole) combustion Acetate 10 76.0 36.3 Propionate 18 136.8 37.2 Butyrate 27 205.2 39.1 Glucose 38 288.8 42.9 93
  • 94. Energetic Efficiency of VFA Fermentation and Metabolism Cellulose 10 Glucose VFA ATP (6730 kcal) (5240 kcal (1946 kcal) 60A 28.9% Starch 30P 10B Absorbed as glucose ATP (6730 kcal) (2888 kcal) 42.9% 94
  • 95. Lower Energy Value of Roughage Compared with concentrate - Less digested - Lignin limits digestibility of digestible fiber - Greater energy lost from fermentation CO2, N2O,CH4, Heat - Increased rumination Rumen contractions Chewing -More bulk in digestive tract -Lower passage rate 95
  • 96. Requirements for Glucose Ruminants 1. Nervous system Energy and source of carbon 2. Fat synthesis NADPH Glycerol 3.Pregnancy Fetal energy requirement 4. Lactation Milk sugar - lactose 96
  • 97. Sources of Glucose Carbon Ruminants Ruminants dependent on gluconeogenesis (glucose synthesis) for major portion of glucose Sources of glucose in metabolism 1. Propionate 2. Amino acids 3. Lactic acid 4. Glycerol 5. Carbohydrate digestion in intestine Absorption of glucose from intestine 97
  • 98. Glucose Synthesis Acetate Amino acids Ketone Acetyl CoA Bodies Fatty Butyrate acids Citrate Glycerol Acetyl CoA Lactate CO2 2 CO2 Pyruvate Oxaloacetate PEP Glucose Succinate Proteins Amino acids Propionate 98
  • 99. Consequences of Inadequate Glucose in Metabolism 1. Low blood glucose 2. High blood ketones 3. High blood concentrations of long-chain fatty acids (NEFA) Metabolic disorders • Causes fatty liver • ketosis in lactating cows and • pregnancy toxemia in pregnant ewes 99
  • 100. Pregnancy Toxemia Pregnant Ewes • During the last month of pregnancy • Ewes with multiple faetuses • Inadequate nutrition of ewe • High demands for glucose by faetuses • Low blood glucose and insulin • Mobilization of body fat • Increase in nonesterified fatty acids (NEFA) in blood • Increased ketone production by liver 100
  • 101. Fatty Acid Metabolism Relation to Glucose Diet fat Adipose Diet CHOH CO2 Acetate Malonyl CoA LCFA NEFA Acetate CO2 Glycerol LCFA acyl CoA 2 CO2 Triglycerides Carnitine FA acyl carnitine Malonyl CoA inhibits CO2 (Mitochondria) Ketones 101
  • 102. Low Blood Glucose and Insulin • Increased release of nonesterified fatty acids from adipose. • Less synthesis of fatty acids Reduced malonyl CoA • Reduced sensitivity of carnitine palmitoyl- transferase-1 to malonyl CoA Increased transfer of fatty acids into mitochondria for oxidation • Increased ketone production 102
  • 103. Fatty Acid Oxidation FA acyl CoA Acetyl CoA CO2 Acetoacetyl CoA Acetoacetate (Mitochondria) 3-OH butyrate FA acyl carnitine Carnitine CoA 103
  • 104. Low Milk Fat Cows fed high concentrate diets: Reduced milk fat percentage Early theory Low rumen pH Shift from acetate to propionate production Increased blood insulin Decrease in blood growth hormone More recent theory Increased production of trans fatty acids in the rumen Trans fatty acids reduce milk fat synthesis 104
  • 105. Long-Chain Fatty Acid Synthesis Ruminants Synthesis is primarily in adipose or mammary gland – Limited synthesis in the liver Ruminants conserve glucose supply – Glucose not extensively used for long chain fatty acid synthesis Most of carbon is supplied by acetate Some butyrate used in mammary gland Glucose metabolism supplies some of NADPH needed for fatty acid synthesis 105
  • 106. Long-Chain Fatty Acid Synthesis Lactic acid, Propionate, Amino acids GlucoseRuminants limit use of glucose Acetyl-CoA carboxylase Acetyl CoA Fatty acids Triglycerides NADPH NADP Acetate Glycerol-3-P Glu-6-P dehydrogenase Gly-3-P dehydrogenase Glucose 106
  • 107. Long-Chain Fatty Acid Synthesis Glucose NADPH NADP Pyruvate Malate Fatty acids Malate dehydrogenase NADP Pyruvate Oxaloacetate NADPH Acetyl CoA Acetyl CoA Oxaloacetate Citrate lyase Citrate Citrate Acetate Mitocondria Cytosol 107
  • 108. Long-Chain Fatty Acid Synthesis Citrate Citrate Isocitrate NADP Isocitrate NADPH dehydrogenase a-Ketoglutarate Mitochondria Cytosol Supplies about half of NADPH for fatty acid synthesis 108
  • 109. Long-Chain Fatty Acid Synthesis Butyrate • Can be used in mammary gland as primer for synthesis of fatty acids • Shorter chain acids Methylmalonyl (propionate) • Is used as primer for synthesis of fatty acids in sheep fed high-concentrate diets • Branched-chain acids 109
  • 111. Lipids Lipids (fats & oils)  Most livestock feeds contain 1-5% fat or oil • Insoluble in water but soluble in organic solvents • Dense energy source: – 1 g fat = 9.45 kcal GE – 1 g protein = 3.5 kcal GE – 1 g CHO = 4.2 kcal GE • Thus, fat produces 2.25 times the energy than CHO 111
  • 112. Lipids 1. Triglyceride: primary storage form of lipids 2. Saturated fatty acids: contain no double bonds 3. Unsaturated fatty acids: contain 1 or more double bonds 112
  • 114. Lipids • Fats = solid at room temp = animal origin – saturated • Oils = liquid at room temp = plant origin + fish – unsaturated 114
  • 115. Functions of Lipids • Dietary energy supply • Source of insulation & protection • Source of essential fatty acids (EFA) • Carrier for fat soluble vitamins 115
  • 116. Lipids • Essential fatty acids (EFA): Those fatty acids that an animal requires, but which it cannot be synthesized in adequate amounts to meet the animal’s need – Linoleic C18:2 – Linolenic C18:3 – Arachidonic C20:4 116
  • 117. Oleic Acid (OA): C18:1, n-9 or -9 Good source: Olive oil, Peanut oil, Soy oil Linoleic Acid (LA): C18:2, n-6 or -6. Essential Fatty Acid Alpha Linolenic Acid (ALA): C18:3, n-3 or -3. Essential Fatty Acid 117
  • 118. Eicosapentaenoic Acid (EPA): C20:5, n-3 or -3. Essential Fatty Acid. Good source: Fish oil Docosahexaenoic Acid (DHA): C22:6, n-3 or -3. Essential Fatty Acid. Good Source: Fish oil Arachidonic Acid (AA): C20:4, n-6 or -6. Good source: Liver, Beef. 118
  • 119. EFA • Physiological needs: – Cell membrane structure – Synthesis of prostaglandins which control blood pressure and smooth muscle contractions • Deficiency: – Scaly, flaky skin (Poor feather growth) – Poor growth 119
  • 121. Sources of Lipids (EFA) • Most feeds contain low levels – > 10% • Unprocessed oil seeds (soybean, cottonseed, sunflower seed) contain up to 20% fat • Forages and Fodders are not good sources • Traditionally, if additional fat is needed it is added to the diet – Animal fats – Vegetable oils 121
  • 122. Lipid Digestion • Occurs in the small intestine (duodenum) • Bile produced by liver emulsifies fat • Pancreatic lipase (enzyme) breaks apart fat for absorption • Monoglycerides (MG)—absorbed into SI mucosal cells • Free Fatty Acids (FFA)—absorbed into SI mucosal cells or enter blood circulation directly 122
  • 123. Lipid Absorption • Very efficient – Absorption rates range from 70-96% • Generally, oils (unsaturated fats) are absorbed more completely than fats (saturated fats) 123
  • 124. Ketosis • Disorder of metabolism – Insufficient energy intake in high producing animals (e.g. Dairy cattle in early lactation and sheep in late pregnancy) – Results in catabolism (breakdown) of body energy (fat) reserves 124
  • 125. Ketosis • 2 C fragments (ketones) of fat catabolism (breakdown) build up • Toxic levels cause – Body weight loss – Abortion – Poor milk production 125
  • 126. Ideal = no limitation to burn fat in the CAC 126
  • 127. Worse = deviate fat to ketone synthesis - low energetic efficiency/hypoglacemia - “drunk cow” 127
  • 128. Worst = fatty liver disease 128
  • 129. AMINO ACIDS GLUCOSE TRIGLYCERIDES (in chylomicrons) Blood GLUCOSE GASTROINTESTINAL TRACT + H2O + CO2 MOST TISSUES Oxidation ATP 1 AMINO ACIDS GLUCOSE TRIGLYCERIDES (in chylomicrons) Blood GLUCOSE GASTROINTESTINAL TRACT HEPATOCYTES IN LIVER + H2O + CO2 MOST TISSUES Oxidation ATP Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glycogen Glucose + H2O + CO2 ATP 1 2 AMINO ACIDS GLUCOSE TRIGLYCERIDES (in chylomicrons) Blood GLUCOSE GASTROINTESTINAL TRACT HEPATOCYTES IN LIVER + H2O + CO2 MOST TISSUES Oxidation ATP Triglycerides ADIPOSE TISSUE VLDLs Triglycerides Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glycogen Glucose + H2O + CO2 ATP 1 2 3 AMINO ACIDS GLUCOSE TRIGLYCERIDES (in chylomicrons) Blood GLUCOSE GASTROINTESTINAL TRACT GLUCOSE HEPATOCYTES IN LIVER SKELETAL MUSCLE Storage + H2O + CO2 MOST TISSUES Oxidation ATP Triglycerides ADIPOSE TISSUE VLDLs Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glucose Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glycogen Glucose Glycogen Glycogen + H2O + CO2 ATP 1 2 3 4 4 AMINO ACIDS GLUCOSE TRIGLYCERIDES (in chylomicrons) Blood GLUCOSE GASTROINTESTINAL TRACT GLUCOSE HEPATOCYTES IN LIVER SKELETAL MUSCLE Storage + H2O + CO2 MOST TISSUES Oxidation ATP Triglycerides ADIPOSE TISSUE VLDLs Triglycerides Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glucose Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glycogen Glucose Glycogen Glycogen + H2O + CO2 ATP 1 2 3 4 5 4 AMINO ACIDS GLUCOSE TRIGLYCERIDES (in chylomicrons) Blood GLUCOSE GASTROINTESTINAL TRACT GLUCOSE HEPATOCYTES IN LIVER SKELETAL MUSCLE Storage + H2O + CO2 MOST TISSUES Oxidation ATP Triglycerides ADIPOSE TISSUE VLDLs Triglycerides Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glucose Keto acids Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glycogen Glucose Glycogen Glycogen + H2O + CO2 ATP 1 2 3 4 5 6 4 AMINO ACIDS GLUCOSE TRIGLYCERIDES (in chylomicrons) Blood GLUCOSE GASTROINTESTINAL TRACT GLUCOSE HEPATOCYTES IN LIVER SKELETAL MUSCLE Storage + H2O + CO2 MOST TISSUES Oxidation ATP Triglycerides ADIPOSE TISSUE VLDLs Triglycerides Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glucose Keto acids Fatty acids Proteins Triglycerides Glyceraldehyde 3-phosphate Glycogen Glucose Glycogen Glycogen + H2O + CO2 ATP 1 2 3 4 5 6 7 4 AMINO ACIDS GLUCOSE TRIGLYCERIDES (in chylomicrons) Blood GLUCOSE GASTROINTESTINAL TRACT GLUCOSE HEPATOCYTES IN LIVER SKELETAL MUSCLE Storage + H2O + CO2 MOST TISSUES Oxidation ATP Triglycerides ADIPOSE TISSUE VLDLs Triglycerides Fatty acids Triglycerides Glyceraldehyde 3-phosphate Glucose Keto acids Fatty acids Proteins Triglycerides Glyceraldehyde 3-phosphate Glycogen Glucose Glycogen Glycogen Proteins Proteins + H2O + CO2 ATP 1 2 3 4 5 6 7 8 4 129
  • 130. 1 Liver glycogen Glucose LIVER Blood HEART ADIPOSE TISSUE SKELETAL MUSCLE TISSUE OTHER TISSUES 1 Liver glycogen Glucose LIVER Glycerol Blood HEART Fatty acids Glycerol Triglycerides ADIPOSE TISSUE SKELETAL MUSCLE TISSUE OTHER TISSUES 2 Fatty acids 1 Liver glycogen Glucose LIVER Lactic acid Glycerol Blood HEART Fatty acids Glycerol Triglycerides ADIPOSE TISSUE SKELETAL MUSCLE TISSUE OTHER TISSUES 3 2 Fatty acids 1 Liver glycogen Keto acids Glucose Amino acids LIVER Lactic acid Glycerol Blood HEART Muscle proteins Fatty acids Glycerol Triglycerides ADIPOSE TISSUE Fasting or starvation SKELETAL MUSCLE TISSUE OTHER TISSUES Proteins Amino acids Amino acids 4 4 3 4 2 Fatty acids 1 Liver glycogen Keto acids Glucose Amino acids LIVER Lactic acid Glycerol Blood HEART Fatty acids Muscle proteins Fatty acids Glycerol Triglycerides ADIPOSE TISSUE Fasting or starvation SKELETAL MUSCLE TISSUE OTHER TISSUES Fatty acids Proteins Amino acids Amino acids Fatty acids ATP ATP ATP 4 5 5 4 3 5 4 2 Fatty acids 1 Liver glycogen Keto acids Glucose Amino acids LIVER Lactic acid Glycerol Blood HEART Fatty acids Muscle proteins Fatty acids Glycerol Triglycerides ADIPOSE TISSUE Fasting or starvation SKELETAL MUSCLE TISSUE OTHER TISSUES Fatty acids Proteins Amino acids Amino acids Fatty acids Lactic acid ATP ATP ATP ATP 4 5 5 6 4 3 5 4 2 Fatty acids 1 Liver glycogen Keto acids Glucose Amino acids LIVER Lactic acid Glycerol Blood HEART Fatty acids Muscle proteins Fatty acids Glycerol Triglycerides ADIPOSE TISSUE Fasting or starvation SKELETAL MUSCLE TISSUE OTHER TISSUES Fatty acids Proteins Amino acids Amino acids Fatty acids Lactic acid ATP ATP ATP ATP ATP 4 5 5 6 7 4 3 5 4 2 Fatty acids 1 Liver glycogen Keto acids Glucose Amino acids LIVER Fatty acids Lactic acid Ketone bodies Glycerol Blood NERVOUS TISSUE Ketone bodies Glucose Starvation HEART Fatty acids Muscle proteins Fatty acids Glycerol Triglycerides ADIPOSE TISSUE Fasting or starvation SKELETAL MUSCLE TISSUE Ketone bodies OTHER TISSUES Fatty acids Proteins Amino acids Amino acids Fatty acids Ketone bodies Lactic acid ATP ATP ATP ATP ATP ATP ATP ATP ATP ATP 4 5 8 5 6 8 8 7 4 3 5 4 2 8 1 Liver glycogen Keto acids Glucose Amino acids LIVER Fatty acids Lactic acid Ketone bodies Glycerol Blood NERVOUS TISSUE Ketone bodies Glucose Starvation HEART Fatty acids Muscle proteins Fatty acids Glycerol Triglycerides ADIPOSE TISSUE Fasting or starvation SKELETAL MUSCLE TISSUE Ketone bodies OTHER TISSUES Fatty acids Proteins Amino acids Glucose 6-phosphate Pyruvic acid Lactic acid Muscle glycogen (aerobic) (anaerobic) Amino acids Fatty acids Ketone bodies Lactic acid ATP O2 ATP ATP ATP ATP ATP ATP ATP ATP ATP ATP ATP + O2 – 4 5 8 5 6 8 8 7 4 3 9 5 4 2 8 130
  • 132. Proteins • Principal constituent of organs and soft tissues • Highest concentration of any nutrient, except water, in the body of all living organisms and animals • Required for life 132
  • 133. Nutrients Function of Proteins • supply amino acids for body proteins - muscle; bone; connective tissue; hormones; enzymes; antibodies; milk components; cell repair 133
  • 134. Proteins • DEFINITION: Proteins are long chains of amino acids (AA) – Formed by peptide linkages • Amino group + carbon skeleton 134
  • 135. Proteins Amino Acid (AA) Protein (2 AA joined by peptide bond between  carboxyl and  amino group 135
  • 136. Proteins • Dietary requirements highest in young, growing animals and declines at maturity • Large molecules that vary greatly in size, shape, and function – MW = 5000 to millions 136
  • 137. Categories of Protein 1. Essential Amino Acids (EAA): – required in the diet – cannot be synthesized at a rate sufficient to meet the nutritional requirements 137
  • 138. Essential AA • PVT TIM HALL (KNOW!) • Phenylalanine • Valine • Threonine • Tryptophan • Isoleucine • Methionine • Histidine • Arginine • Lysine • Leucine 138
  • 139. Categories of Protein 2. Nonessential AA – animal can produce enough to meet it’s requirements 3. Semi-essential AA – Animal can not always produce enough to meet its requirements 139
  • 140. Functions of Protein • Basic structural units of animal body – Collagen, blood, elastin • Body metabolism – Enzymes, hormones, immune system, hereditary transmission • Production – Meat, milk, egg, skin/hair 140
  • 141. Protein Deficiency • Reduced growth & feed efficiency • Infertility • Reduced birth weights • Reduced production,and reproduction 141
  • 142. Sources of Protein • Most common feedstuffs contain some protein (the quality is another issue) – Animal origin diets are the richest sources – Plant origin diets are also good sources of proteins • KEY: to combine feedstuffs into the diet so that AA requirements are met – e.g. Using a corn-soybean meal diet for pigs 142
  • 143. Protein Digestion • Proteins must be broken down into AA for absorption in the GIT – Exception! Early in life (> 48 h after birth) proteins from milk (immunoglobulins) can be absorbed intact across the intestinal epithelium 143
  • 145. Monogastric Protein Digestion • Stomach: HCl unfolds (denatures) proteins and activates pepsinogen secreted by stomach to pepsin – Pepsin begins protein digestion to peptides (short-chain proteins) • Small intestine: enzymes (trypsin) break peptides into AA 145
  • 146. Monogastric Protein Absorption • AA are absorbed in anterior part of the small intestine – Jejunum and ileum • AA are absorbed and transported to tissue via blood 146
  • 147. Protein Digestion and Absorption in Ruminants 147
  • 148. Ruminant Protein Digestion • In rumen, microbes break down protein to peptides and AA and then degraded further to ammonia, VFAs, and carbon dioxide • Ammonia and/or NPN (urea) + CHO source form microbial proteins 148
  • 149. Ruminant Protein Absorption • Protein can be absorbed through rumen wall as ammonia • Microbial proteins pass to the lower intestine where they are converted to AA and absorbed 149
  • 150. RUMEN BLOOD STREAM URINE SALIVA ABOMASUM & SMALL INT. LIVER TISSUES FECES N metabolism in ruminants FEED protein NPN protein protein feed protein NPN microbial protein peptides amino acids NH3 NH3 NH3 urea urea urea protein amino acids amino acids endogen. nitrogen metabolic fecal protein 150
  • 151. Fates of Absorbed AA 1. Tissue protein synthesis 2. Synthesis of enzymes, hormones & other metabolites 3. Use for energy (inefficient energy source) 151
  • 152. Various points at which amino acids enter the Krebs cycle for oxidation 152
  • 154. Minerals • Inorganic components of the diet – inorganic elements (contain no carbon), component left after ashing • Can not be synthesized or decomposed by chemical reactions • Total mineral content is called “ash” • Makes up 3-5% of the body weight 154
  • 155. 1ppm = 1/1000000 So one parts-per million is equal to 0.0001 percent: 1ppm = 1/1000000 155
  • 156. Categories of Minerals • Macro Minerals: Minerals normally present at greater levels in animal body or needed in large amounts in the diet (found in concentrations > 100 ppm) – Calcium (Ca) – Phosphorus (P) – Sodium (Na) – Chloride (Cl) – Magnesium (Mg) – Potassium (K) – Sulfur (S) + C O N 156
  • 157. Categories of Minerals • Micro (Trace) Minerals: Minerals normally present at low levels in animal body or needed in small amounts in the diet (found in concentrations < 100 ppm) – Cobalt (Co) – Copper (Cu) – Fluoride (Fl) – Iodine (I) – Iron (Fe) – Manganese (Mn) – Molybdenum (Mo) – Selenium (Se) – Zinc (Zn) 157
  • 158. General Mineral Functions • Skeletal formation and maintenance (Ca, P, Mg, Cu, Mn) • Protein synthesis (P, S, Zn) • Oxygen transport (Fe, Cu) • Fluid balance—osmotic pressure (Na, Cl, K) • Acid-base balance regulation (Na, Cl, K) • Activators or components of enzyme systems (Ca, P, K, Mg, Fe, Cu, Mn, Zn) • Mineral-Vitamin relationships (Ca, P, Co, Se) 158
  • 159. Macro Mineral Deficiencies • Ca and P – Inadequate bone mineralization • Rickets (young) • Osteomalacia (adult) – Phytate P—bound and unavailable to nonruminants • Mg – Grass tetany-convulsions, coma, death • Likely in grazing, lactating females in early spring or fall • Mg is there in the plant, just in bound form due to lack of sunlight 159
  • 160. Macro Mineral Deficiencies • Fe – Anemia (insufficient haemoglobin) – Young pigs (rapid growth, low stores, low Fe in milk) 160
  • 161. Trace Mineral Deficiencies • Mn – Poor growth – Poultry—Perosis—deformed and enlarged hock joints • I – Goiter—swollen thyroid 161
  • 162. Trace Mineral Deficiencies • Cu – Fading hair coat color (depigmentation) – Low Cu utilization may result when excess Mo or Zn • Zn – Parakeratosis (dermatitis-thickening of skin) – Poor hair or feather development – Exacerbated by high Ca 162
  • 163. Trace Mineral Deficiencies • Se – White muscle disease-nutritional muscular dystrophy • Muscle appears white due to Ca-P deposits – Due to low concentration of Se in soil 163
  • 164. Mineral Toxicities • Usually not a problem • NaCl can be for swine and poultry – Levels above 8%--causes nervous disorders • Cu a big problem for sheep and young animals – Mineral mixes for other species/age groups used • Se has a small margin between requirement (0.3 ppm) & toxicity (8 ppm) – Plants grown in regions of high soil Se 164
  • 165. Sources of Minerals • Forages usually considered good sources of minerals – Largely dependant on soil conditions • Grains are fair source of P, but low in other minerals • Mineral premixes • Mineral blocks 165
  • 166. Mineral Absorption • Minerals are converted to their ionic form and absorbed in the small intestine 166
  • 167. Mineral Functions • Part of some amino acids & vitamins • metabolic reactions • enzyme function • body structure • transport oxygen Deficiency examples White muscle =selenium Grass Tetany =magnesium Rickets =calcium White hair on black cattle =copper Anemia =iron Retained Placenta =selenium and Vitamin E 167
  • 168. Vitamins • What are vitamins? • What are their roles in animal production? 168
  • 169. small amounts for specific body functions a. 2 classifications 1. water soluble – C & B- complex (see Fig 5-1) – microbes synthesize in ruminants & horses 2. fat soluble – A, D, E, K – A & E required in diets of all animals – D – produced by effects of sun on skin – K – synthesis by rumen/cecum microbes 169
  • 170. Types of Vitamins • Fat-soluble vitamins – Vit A (carotene): vision – Vit D: Ca, P absorption – Vit E (tocopherol): antioxidant – Vit K (menadione): blood clotting • Short shelf life (3-4 months) • Need lipids for absorption • Destroyed by heat, minerals 170
  • 171. Types of Vitamins • Water-soluble vitamins – Thiamine – Riboflavin – Niacin – Pyridoxine – Pantothenic acid – Biotin – Choline – Folic acid – Vitamin B12 – Vitamin C B Complex Vitamins 171
  • 172. Vitamin Functions • Reproduction • Fetal Development • Colostrum Production • Milk production • Wool • Egg • Racing 172
  • 173. Vitamin Deficiencies • Vitamin A – Xerophtalmia: night blindness – Poor growth, reproductive failure • Vitamin D – Rickets – Osteomalacia • Vitamin K – Poor blood clotting/hemorrhaging 173
  • 174. Vitamin Deficiencies • Vitamin C – Scurvy: slow wound healing, spongy gums, swollen joints, anemia • B Complex Vitamins – Reduced growth/poor appetite – Dermatitis – Muscular incoordination 174
  • 175. Most likely deficient… • In practical situations: – Ruminants: A, E, D (limited circumstances) – Swine: riboflavin, niacin, pantothenic acid, choline, B12, A, D, and sometimes E – Poultry: All vitamins except Vitamin C, inositol 175
  • 176. Vitamin Toxicity • Unlikely ($) • Generally nontoxic – Exceptions: • A, D, Niacin, Pyridoxine, Choline 176
  • 177. Sources of Vitamins • A: green, leafy forages, corn, fish oil • D: fish oils, sun-cured hay • E: seed germ oils, green forage or hay • K: green forage, fish meal, synthetic menadione 177
  • 178. Sources of Vitamins • B Vitamins: green forages usually – Niacin: present in grains, but unavailable to nonruminants • B12: protein feeds of animal origin, fermentation products • C: citrus fruits, green, leafy forages, well-cured hay 178
  • 179. Sources of Vitamins • Most nonruminants rations contain a vitamin premix – Consume basically no forages and B vitamins are poorly available from cereal grains 179
  • 180. Vitamin Absorption • Most vitamins are absorbed in the upper portion of the small intestine • Water soluble vitamins are rapidly absorbed • Fat soluble vitamin absorption relies on fat absorption mechanisms 180
  • 181. Vitamins • Organic substances required by the animal in very small amounts • Necessary for metabolic activity but not part of body structure • Content varies greatly in the feed • Requirements depend on species – Monogastrics = a lot b/c cannot synthesize – Ruminants = few vitamins due to microbial synthesis 181
  • 183. Formulation of Feeds  Feed formulation: the preparation of nutritionally-complete diets for feeding animals  Least-cost feed formulation:  a feed formula that is both nutritionally-complete and,  with a minimum ingredient cost  Now-a-days is developed and completed through the use of computers using linear- programming software  Manual feed formulations (pearson square, algebiric, trial error) -Nutrient composition (proximate + detergent fiber) basic for formulation of feeds 183
  • 184. Least-cost Formulation • Least-cost feed formulations require that the following information be provided:  cost of feed ingredients  nutrient content of feed ingredients  nutrient requirement of the animal  availability of the nutrient to the animal  minimum-maximum restrictions on levels 184
  • 185. Least-cost Formulations  Costs of feed ingredients and nutrient content are fairly available for most commercial feedstuffs  costs can be evaluated on a daily basis  nutrient requirements are fairly well known  the most critical piece of information regards digestibility/availability of nutrients within the feed ingredient  various indices: digestible energy (DE), metabolisable energy (ME), apparent protein digestibility (APD), etc.  these can be set in formula with restrictions  Expressing the Nutrient & Energy Content (DM/as- is-bases) 185
  • 186. Expressing the Nutrient & Energy Content A) Dry matter (DM) basis - The amount contained in only the DM portion of the feed ingredient/diet, i.e., without water. [Because feeds contain varying amounts of DM, perhaps, simpler and more accurate if both the composition and nutrient requirements are expressed on a DM basis!?] B) As-fed basis - The amount contained in the feed ingredient/diet as it would be fed to the animal; including water. C) Air-dry basis: 1) Usually, assumed to be approximately 90% DM. 2) Most feeds will equilibrate to about 90% DM after a prolonged, aerobic storage. 3) Air-dry and as-fed basis may be the same for many common feeds. 186
  • 187. Expressing the Nutrient & Energy Content 1)Percent dry matter?  Determined by drying a sample to remove all the moisture, and the weight of the remaining is expressed as a percent of the original weight. Example - "1.0 g of maize grain is dried and 0.90 g of maize grain remained after drying," then: 0.9/1.0*100=90% DM 187
  • 188. 2/As-Fed Basis Converted to DM Basis a) Can be converted by: 188 Nutrient % on as-fed basis = Nutrient % on DM basis % DM in the feed expressed as decimal fraction % Nutrient (as-fed basis) = % Nutrient (DM basis) % Feed DM 100% DM OR
  • 189. As-Fed Basis Converted to DM Basis • Example - "Alfalfa silage analyzed to contain 7% CP on an as-fed basis and contained 40% DM. What would be the CP content on DM basis?" • (0.07 ÷ 0.40)*100 = 17.5% CP on DM basis, or 189 7 = X = 17.5% CP on DM basis 40 100
  • 190. 3/DM Basis Converted to As-Fed Basis Can be converted by: A) Nutrient % on DM basis x % DM in the feed expressed as decimal fraction = Nutrient % on as-fed basis OR 190 % Nutrient (as-fed basis) = % Nutrient (DM basis) % Feed DM 100% DM
  • 191. 3/DM Basis Converted to As-Fed Basis • Example? - "Alfalfa silage analyzed contain 10% crude fiber (CF) on a DM basis. If the linseed meal contains 91% DM, what would be the % CF expressed on an as-fed basis?“ – 10.0 x 0.91 = 9.1, thus 9.1% on as-fed basis, or 191 x 10 = 9.1% Crude fiber on as-fed basis 91 100
  • 192. 4/DM/as-fed basis Converted to Air-Dry Basis A) DM basis to air-dry basis (90% DM):  Nutrient % on DM basis x 0.90 = Nutrient % on air-dry basis B) As-fed basis to air-dry basis (90% DM): = (90/ % Feed DM)x Nutrient % on as-fed basis = Nutrient % on air-dry basis 192
  • 193. 5/Amount in DM and as-fed? A) Amount in DM = Amount in as-fed  DM content (decimal) B) Amount in DM = X (amount in as-fed)  DM content (decimal) Amount in as-fed? X = Amount in DM/ DM content (Decimal) 193
  • 194. 6/ Rule of thumb for conversions A. When converting from "as-fed to DM?" • 1) The nutrient content will increase. • 2)The weight will decrease B. When converting from "DM to as-fed?" • 1) The nutrient content will decrease. • 2) The weight will increase. 194
  • 195. Balancing rations-using the Pearson Square • EXAMPLE • 1,000 kg of feed is needed to feed a 50-kg growing calves. A feeding standards table shows that a 14% crude protein ration is needed. Maize and Soybean oil meal (SBOM) are selected as feeds. A feed composition table shows that maize has 8.9% and SBOM has 45.8% CP on DM basis. How much maize and soybean oil meal need to be mixed together for 1,000 kg of feed? 195
  • 196. STEP 1 • Draw a square with lines connecting the opposite corners. • Write the percent of crude protein (14) in the center of the square. 14 196
  • 197. STEP 2 • Write the feeds to be used and their crude protein percents at the left hand corners of the square. 14 Maize 8.9 Soybean oil meal 45.8 197
  • 198. STEP 3 • Subtract the smaller number from the larger, along the diagonal lines. Write the differences at the opposite end of the diagonals. 14 Corn 8.9 Soybean oil meal 45.8 31.8= 45.8-14 5.1 =14-8.9 198
  • 199. STEP 3 • The difference between the percent protein in the soybean oil meal and the percent protein in the ration are the parts of maize needed. • The difference between the percent protein in the maize and the percent protein in the ration are the parts of soybean oil meal needed. • The sum of the numbers on the right equals the difference in the numbers on the left. This fact is used as a check to see if the square is set up correctly. 199
  • 200. STEP 3 14 Maize 8.9 Soybean oil meal 45.8 31.8 5.1 36.9 36.9 Parts maize Parts SBOM 200
  • 201. STEP 4 • Divide the parts of each feed by the total parts to find the percent of each feed in the ration –Maize 31.8/36.9 x100 = 86.2% –Soybean oil meal =5.1/36.9x100=13.8% 201
  • 202. STEP 5 • It is known that 1,000 kg of the mixture is needed. To find the kg of each feed in the mix, the percent of each feed is multiplied by the total kilograms of the mix – Maize 1,000 x 0.862= 862 kg – SBOM 1,000 x 0.138= 138 kg *Numbers have been rounded to full pounds. 202
  • 203. STEP 6 • Check the mix to ensure that the protein need is met. Multiply the pounds of the feed in the it’s precent protein . – Maize 862 kg  0.089= 77 kg of maize protein – SBOM 138kg  0.458= 63 kg of SBOM protein • Add the kgs of protein together – 77kg + 63kg = 140kg • Divide by the total weight of the mix – 140kg/1,000kg x 100= 14% • The mix is balanced for crude protein content! 203
  • 204. Using Algebraic Equation to Balance Ration • May be used instead of Pearson Square • Basic equations are  X= kilograms of grain needed  Y= kilograms of supplement • Equation #1  X+Y= total kilogram of mix needed • Equation # 2  (% Nutrient in grain)  (X) + (% Nutrient in supplement)  (Y) = kilograms of nutrient desired 204
  • 205. EXAMPLE • Same example as the 1st Pearson Square Example • Mix of 1,000 kg is to be balanced for protein using two feeds. • Place the desired values in equation 2 – REMEMBER TO EXPRESS % AS DECIMALS • 0.089X+0.458Y=140 – 140 is found by multiplying the quantity of feed (1,000 kg) by the percent (14) [or the amount] of nutrient desired: 1,000 x 0.14 205
  • 206. EXAMPLE cont… • Either X or Y must be canceled by the multiplication of equation 1 by the percentage of nutrients for either X or Y, and the resulting equation 3 is subtracted from equation 2. • This example uses the percentage crude protein for maize (0.089), giving equation 3 0.089X+0.089Y = 89 (89 is found by multiplying 0.089  1,000 kg) 206
  • 207. EXAMPLE cont…  SUBTRACT equation 3 from equation 2  0.089X + 0.458Y =140 -0.089X - 0.089Y = -89 0+ 0.369Y= 51 Y= 138 kilograms soybean meal  X may then be found by substituting the value of Y in equation or 2 and solving  X+138 = 1,000  X=1,000-138  X= 862 kg of maize OR , you can use equation 2:  (0.089X + 0.458 (138) =140 207
  • 208. Algebraic Equations • Get the same result as Pearson square • May be used to balance rations using 3 or more feeds • Same initial step must be taken as when using the Pearson Square—group similar feeds into two groups and determine the proportions of each to be used in each group – After this is done the same procedure as above is followed. 208
  • 209. Algebraic diet formulation (equation with one unknown, X) (A) Example - "Formulate a 12% CP diet using corn (8.8% CP) and a protein supplement (35% CP), with 3% rye (11.9% CP) and 7.5% milo (11.0% CP)." 2) Known quantities?  3% rye + 7.5% milo = 10.5%, thus the remaining 89.5% to be balanced! 3) Procedure & check? Algebraic equation with one un known, X:  If % supplement = X  % corn = 89.5 - X  0.119 (3) + 0.11 (7.5) + 0.088 (89.5 - X) + 0.35X = 0.12 (100)  From left, lb CP from rye, lb CP from milo, lb CP from corn, lb CP from supplement, and lb CP in 100 lb of diet. 209
  • 210. Algebraic diet formulation (equation with one unknown, X), Contin…. • 0.357 + 0.825 + 7.876 - 0.088X + 0.35X = 12 0.35X - 0.088X = 12 - 7.876 - 0.825 -0.357 0.262X = 2.942 X = 11.229 [lb supplement] 89.5 - X = 78.271 [lb corn] • Check? • 0.119 (3) + 0.11 (7.5) + 0.088 (78.271) + 0.35 (11.229) = ? • 0.357 + 0.825 + 6.888 + 3.930 = 12 210
  • 211. B. Algebraic diet formulation (using equations with two unknowns, X & Y)  The same example - "Formulate a 12% CP diet using corn (8.8% CP) and a protein supplement (35% CP), with 3% rye (11.9% CP) and 7.5% milo (11.0% CP).”  Known quantities & fixed amount of CP?  a) 3% Rye + 7.5% milo = 10.5%, thus remaining 89.5% to be balanced.  b) 0.119 (3) + 0.11 (7.5) = 0.357 + 0.825 = 1.182, or 1.182 lb of CP per 100 lb of diet (or 1.182%) is fixed.  Thus, the remaining protein (10.818 lb/100 lb feed) must be balanced with corn and supplement., 1.182+ 10.818=12 3) Procedure & check? - See below 211
  • 212. Algebraic equation with two unknowns, X & Y: • X = lb corn in the diet • Y = lb supplement in the diet • Equation 1: X + Y = 89.5 lb diet • Equation 2: 0.088X + 0.35Y = 10.818 lb CP • Equation 3: -0.088X + -0.088Y = -7.876 (=0.08889.5) 0 + 0.262Y = 2.942 Y= 11.229 (lb supplement) X = 89.5 - 11.229 = 78.271 (lb corn) • Check? • 0.119 (3) + 0.11 (7.5) + 0.088 (78.271) + 0.35 (11.229) = ? • 0.357 + 0.825 + 6.888 + 3.930 = 12 212
  • 213. C. Pearson square 1) The same example - "Formulate a 12% CP diet using corn (8.8% CP) and a protein supplement (35% CP), with 3% rye (11.9% CP) and 7.5% milo (11.0% CP)." 2) Known quantities & fixed amount of CP? a) 3% Rye + 7.5% milo = 10.5%, thus remaining 89.5% to be balanced. b) 0.119 (3) + 0.11 (7.5) = 0.357 + 0.825 = 1.182, or 1.182 lb of CP per 100 lb of diet (or 1.182%) is fixed.  Thus, the remaining protein (10.818 lb/100 lb of feed or 10.818%) must be balanced with corn and supplement. c) Need to determine the % CP necessary in corn supplement combination to provide 10.818 lb/100 lb of feed . . . 10.818/89.5 x 100 = 12.087%. 3) Procedure & check? - See below 213
  • 214. Pearson square • Subtract the smaller number from the larger, along the diagonal lines. Write the differences at the opposite end of the diagonals. 12.08% Corn 8.8 Supplement 35 % 22.913 parts corn 3.287 parts supplement 26.2 total parts 214
  • 215. Pearson square • 22.913 parts corn/26.2 total parts100 =87.454% corn • 3.287 parts supplement/26.2 total parts100 = 12.546% supplement – 89.5 x 87.454% = 78.271 lb corn – 89.5 x 12.546% = 11.229 lb supplement • Check? – 3.00 lb rye  11.9% CP = 0.357 lb CP – 7.50 lb milo  11.0% CP = 0.825 lb CP – 78.271 lb corn  8.8% CP = 6.888 lb CP – 11.229 lb supplement  35.0% CP = 3.930 lb CP – 100.00 lb diet 12.000 lb CP 215
  • 216. Formulate a supplement (500 kg) to be fed with 1,500 kg of maize of complete diet." %CP, % Ca, , % P, Maize 8.8 0.03 0.27 SBOM 50.9 0.26 0.62 Dical - 23.35 18.21 Lime - 35.8 - Use SBOM, Dical, Lime, salt, Vit premix, TM premix and maize as a carrier, and Pigs need 14% CP, 0.5% Ca, 0.4% P, 0.5% salt, 0.1% TM (trace mineral) premix & 1.0% Vit premix. 216
  • 217. Determine the "specifications" for the supplement a) Complete diet is: – 1500/2000100 = 75% maize – 500/2000100 = 25% supplement b) % CP in supplement: – 0.088 (0.75) + X(25) = 0.14 0.066 + 0.25X = 0.14 0. 25X = 0.074 X = 0.296 [Thus, 0.296 x 100 = 29.6% (% CP in supplement)] 217
  • 218. c) % Ca in supplement: 0.0003 (0.75) + X (0. 25) = 0.005 0.000225 + 0.25X = 0.005 0.25X = 0.4775 X = 0.0191 [Thus, 0.0191 x 100 = 1.91% (% Ca in supplement)] d/ % P in supplement: 0.0027 (0.75) + X (0.25) = 0.004 0.2025 + 25X = 0.004 0.25X = 0.001975 X = 0.0079 [Thus, 0.0079 X100 = 0.79% (% P in supplement)] 218
  • 219. e) % salt in supplement: 0 (0.75) + X (0.25) = 0.005 X = 0.02 [Thus, 0.02 x 100 = 2% (% salt in supplement)] f) % TM in supplement: 0 (0.75) + X (0.25) = 0.001 X = 0.004 [Thus, 0.004 x 100 = 0.4% (% TM premix in supplement)] 219 Supplement specification, % CP 29.6 Ca 1.9 P 0.8 Salt 2.0 TM premix 0.4 Vit premix 4
  • 220. Ration formulation, Example 4 • In this example, a ration will be balanced using corn, wheat hay, and cotton seed meal (feed values are listed as: maize, 88% DM, 88.9% TDN, 9.8% CP, 0.03% Ca, 0.31% P; wheat hay: 84% DM, 53% TDN, 9.1% CP, 0.16% Ca, 0.24% P; cottonseed meal: 92% DM, 75% TDN, 46.1% CP, 0.20% Ca, 1.16%P) for a 350-kg heifer calf with a desired gain of 2.5 lb/day. Her daily requirements are (heifer: weight 700, DMI (lb/d, 16.4), ADG (lb/d, 2.5), TDN, lb/day (12.6 lb), CP, lb/day (1.68), Ca, lb/day (28), P, lb/day (16): – 16.4 lb daily dry matter intake – 76.8% TDN (12.6 lb TDN ÷ 16.4 lb dry matter intake) – 10.2% CP (1.68 lb CP ÷ 16.4 lb dry matter intake) 220
  • 221. To balance this ration: 1) Balance for TDN 1.Draw a square and write 76.8 (the desired TDN concentration) in the middle of the square (fig. 4) 2.At the upper left corner of the square, write “wheat hay = 53%”. 3.At the lower left corner, write “corn = 88.9%”. These numbers represent the TDN percentage in each feedstuff.  Note: The nutrient requirement in the middle of the square must be between the nutrient concentrations of the two ingredients. 221
  • 222. Balance for TDN 4/ Subtract diagonally across the square, converting negative answers to positive, and write the numbers on the right side of the square (top value = 11.2, bottom value = 23.8%) 5/ Sum the numbers on the right side of the square (11.2 + 23.8 = 35%). These numbers indicate that a ration of 11.2 parts wheat hay and 23.8 parts corn (a total of 35 parts) will result in a ration with 76.8 percent TDN. 6/ Divide the wheat hay and corn “parts” by 35 to get the percentages of wheat hay (11.2 ÷ 35 = 32%) and corn (23.8 ÷ 35 = 68%). 222
  • 223. Balancing for TDN using the Pearson Square method Balacing: 76.8% Wheat hay 53% Whole corn 88.9 % 11.2 ÷ 35 = 0.32 (32% 23.8 ÷ 35 = 0.68 (68%) 35 total parts 100% 223
  • 224. 2. Determine if crude protein is adequate a) Multiply the percent of each feedstuff in the mix by its crude protein content. Wheat hay is 32 percent of the mix and contains 9.1 percent crude protein. Corn is 68 percent of the mix and contains 9.8 percent crude protein. Therefore, the crude protein concentration in the mix is: – Wheat hay: 0.32 × 9.1 = 2.91% – Corn: 0.68 × 9.8 = 6.66% – 2.91 + 6.66 = 9.57%,  crude protein is not adequate (is < 10.2%) 224
  • 225. b) The crude protein content of the diet needs to be increased by adding a protein supplement (cotton seed meal for this example). • Another Pearson Square will be used to determine the correct amount of cotton seed meal. 225
  • 226. 3. Determine amount of protein supplement needed a. Draw a square and write 10.2 (the desired CP concentration) in the middle of the square. 226 wheat hay: corn mix 9.57 % Cotton seed meal 46.1% 35.9 ÷ 36.53 = .983 (98.3%) 0.63 ÷ 36.53 = 0.017 (1.7%) 10.2%
  • 227. • b. At the upper left corner of the square, write “wheat hay:corn mix = 9.57”. At the lower left corner, write “cottonseed meal = 46.1”. • These numbers represent the CP percentage in each feedstuff. • Note: The nutrient requirement in the middle of the square must be between the nutrient concentrations of the two ingredients. 227
  • 228. • c. Subtract diagonally across the square, converting negative answers to positive, and write the numbers on the right side of the square (top value = 35.9, bottom value = 0.63). 228
  • 229. d). Sum the numbers on the right side of the square (35.9 + 0.63 = 36.53). These numbers indicate that a ration of 35.9 parts wheat hay: corn mix and 0.63 parts cottonseed meal (a total of 36.53 parts) will result in a ration with 10.2 percent CP. e). Divide the wheat hay: corn mix and cottonseed meal “parts” by 36.53 to get the percentages of wheat hay: corn mix (35.9 ÷ 36.53 = 98.3%) and cottonseed meal (0.63 ÷ 36.53 = 1.7%). 229
  • 230. 4. Determine the pounds of dry matter that each feedstuff contributes to the total, and convert from dry matter to as-fed basis. A) Multiply the dry matter intake of the heifer (16.4 lb) by the percentage of cotton seed meal in the ration (16.4 × 0.017 = 0.28 lb cottonseed meal). Subtract this amount from total dry matter intake to determine how much of the dry matter intake remains for the wheat hay : corn mix (16.4 – 0.28 = 16.12). Then multiply 16.12 by the relative amounts of wheat hay and corn obtained from the first Pearson square (32 percent wheat hay and 68 percent corn). • Wheat hay: 16.12 × 0.32 = 5.16 lb wheat hay, dry matter basis 230
  • 231. b) • Convert the individual amounts from dry matter to as-fed basis. This step is required in order to know how much of each ingredient to feed to the heifer. The pounds of dry matter of each feed are divided by the percentage of dry matter in each feed. – Cotton seed meal: 0.28 lb ÷ 0.92 = 0.30 lb CSM, as fed – Wheat hay: 5.16 ÷ 0.84 = 6.14 lb alfalfa hay, as- fed – Corn: 10.96 ÷ 0.88 = 12.45 lb whole corn, as-fed basis 231
  • 232. Example 5.Using the Pearson Square to Mix Two Grains with a Supplement (START) • Can be used to find out how much of two grains should be mixed with a supplement • Proportions of grain must be known first 232
  • 233. EXAMPLE • 2,000 pound mix of corn, oats and soybean oil meal is needed. The mix is to contain 16% Digestible Protein. A decision is made to use ¾ corn and ¼ oats in the mix. Thus, the proportion of corn to oats is 3:1. SBOM has 41.7% CP. How many pounds of corn, oats and soybean oil meal are needed? 233
  • 234. STEP 1 • Need to find the weighted average percent of protein in the corn and oats first. • To do this – Multiply the proportion of corn (3) by the percent digestible protein in corn (7.1). Do the same for oats. Then add the two answers together and divide by the total parts (4). This answer is the weighted average percentage of digestible protein in the corn oats mix. – Take 7.1% TDN for corn, 9.9% TDN for oats 234
  • 235. STEP 1 cont… • 3 x 7.1=21.3 (Corn) • 1 x 9.9= 9.9 (Oats) 31.2 • 31.2/4= 7.8% Digestible Protein in the corn- oats mix 235
  • 236. Using the Pearson Square X • Used in the same method as before to mix two feeds. • On a sheet of paper, work out this problem 16 3 parts Corn, 1 part oats 7.8% Soybean oil meal 41.7% 236