The document discusses the concept of normal force and how the weight of an object on an inclined plane can be resolved into components that are perpendicular and parallel to the surface. It gives an example of an object weighing 520 N that is placed on a 30 degree inclined plane, and calculates that the force perpendicular to the surface (normal force) is 450 N.

1. Force
Normal

4. Weight

5. Weight

6. Normal
Weight

7. Normal
Weight

8. N
W

9. inclined plane

10. W

11. x
y

12. W’s
component
into surface
W

13. W’s
component
into surface
W

14. Wy
W

15. N
Wy
W

16. N
Wy
W

17. N
Wy
W

19. N
Wy
W

20. N
Wy
W

21. 30°

22. N
Wy
30°
W

23. N
Wy
30°
W
Wy = W • cos 30°

24. N
Wy
30°
W = 520 N
Wy = W • cos 30°

25. N
Wy
30°
W = 520 N
Wy = 520 N • cos 30°

26. N
Wy
30°
W = 520 N
Wy = 520 N • cos 30°
= 450 N into the slope

27. N
450 N
30°
W = 520 N

28. 450 N
450 N
30°
W = 520 N