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1
SELF INTRODUCTION
NAME – ARYYAKA SARKAR
TRADE – STRUCTURAL ENGINEERING
STREAM – CIVIL ENGINEERING
POSITION – M.TECH
YEAR – 1st
SEMESTER – 1st
INSTITUTION – NITTTR , KOLKATA
UNIVERSITY – MAKAUT
SESSION – 2023 - 2024
DATE – 29/12/2023
ADVANCED ENGINEERING
MATHEMATICS
SE (CE) 101
NEWTON
RAPHSON
METHOD
4
As we know from school days , and still we have studied
about the solutions of equations like Quadratic equations
, Cubical equations & polynomial equations and having
roots in the form of
π‘₯ =
βˆ’π‘Β± 𝑏2βˆ’4π‘Žπ‘
2π‘Ž
where a, b , c are the coefficient of equation.
But nowadays it is very difficult to remember formulas
for higher degree polynomial equations . Hence to
remove these difficulties there are few numerical
methods, one of the easiest of them is Newton Raphson
Method Which has to be discussed in this power point
presentation.
Newton Raphson method is a numerical technique
which is used to find the roots of Algebraic &
transcendental Equations .
6
Newton Raphson method is a numerical
technique which is used to find the roots of
Algebraic & transcendental Equations .
Algebraic Equations :
An equation of the form of quadratic or
polynomial.
e.g. π‘₯4+π‘₯2+1=0
π‘₯8-1 =0
π‘₯3-2x -5=0
7
Transcendental equation :
An equation which contains some
transcendental functions Such as
exponential or trigonometric functions.
e.g. sin , cos , tan , 𝑒π‘₯ , π‘₯𝑒 , log etc.
3x-cosx-1=0
logx+2x=0
𝑒π‘₯-3x=0
Sinx+10x-7=38
Newton Raphson Method :
Let us consider an equation 𝑓(π‘₯) = 0
having graphical representation as
8
.
β€’ f(x) =0 , is a given equation
β€’ Starting from an initial point π‘₯0
β€’ Determine the slope of f(x) at x=π‘₯0 .Call 𝑓’(π‘₯0).
Slope ;
= tanΡ²
𝑓′(
Hence ;
β€’ Newton Raphson formula
Algorithm for f(x)=0
β€’ Calculate f’(x) symbolically.
Choose an initial guess π‘₯0 as given below let [a,b] be any interval such that 𝑓 π‘Ž < 0 π‘Žπ‘›π‘‘ 𝑓 𝑏 > 0
.
β€’
. Similarly
.
β€’ Then by repetition of this process we can find π‘₯3 ,π‘₯4 , π‘₯5 … …
β€’ At last we reach at a stage where we find π’™π’Š+𝟏 = π’™π’Š.
β€’ Then we will stop.
β€’ Hence π’™π’Š will be the required root of given equation.
NRM by Taylor series :-
if we have given an equation 𝑓(π‘₯) = 0.
π‘₯0 be the approximated root of given equation.
10
β€’ Let (π‘₯0 +h) be the actual root where β€˜h’ is very
small such that f(π‘₯0 + β„Ž)=0
From Taylor series expansion on expanding to
f(π‘₯0 + β„Ž)
f(f’’’(π‘₯0) +…….
Now on neglecting higher powers of h
f(π‘₯0) + hf’(π‘₯0) =0
From above h=
Hence first approximation π‘₯1=(π‘₯0 + β„Ž);
Second approximation ;
On repeating this process
We get
This is the required newton Raphson method.
How to solve an example :
F(x)= π‘₯3- 2x – 5
F’(x) = 3π‘₯2-2
Now checking for initial point ;
F(3) =16
F(2)= -1
F(3) =16
Hence root lies between (2,3)
Initial point
(
From NRM formula
Putting all these above values in this
formula
.
12
𝑛+1 𝑛
π‘₯ = π‘₯ βˆ’
n n
3 x 2
ο€­ 2
ο€­ 2 x ο€­ 5
𝑛+1 𝑛
π‘₯ = π‘₯ βˆ’
n
n n
3 x 2
ο€­ 2
ο€­ 2 x ο€­ 5
x 3
On putting initial value π‘₯0 = 2.5
We get first approximate root;
π‘₯1=2.164179104
Similarly:
π‘₯2=2.097135356
π‘₯3=2.094555232
π‘₯4=2.094551482
π‘₯5=2.094551482
Hence π±πŸ’=π±πŸ“
Hence 2.094551482 is the required root of
given equation
13
β€’ To find the square root of any no.
β€’ To find the inverse
β€’ To find inverse square root.
β€’ Root of any given equation.
Application of NRM :
16
Limitations of NRM:
β€’ F’(x)=0 is real disaster for this
method
β€’ F’’(x)=0 causes the solution to
diverse
β€’ Sometimes get trapped in local
maxima and minima
17
References :
Engineering Mathematics Books
Internet
Classes & Classnotes
Teachers & Friends n.
14
THANK

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Newton Raphson Method in numerical methods of advanced engineering mathematics

  • 1. 1 SELF INTRODUCTION NAME – ARYYAKA SARKAR TRADE – STRUCTURAL ENGINEERING STREAM – CIVIL ENGINEERING POSITION – M.TECH YEAR – 1st SEMESTER – 1st INSTITUTION – NITTTR , KOLKATA UNIVERSITY – MAKAUT SESSION – 2023 - 2024 DATE – 29/12/2023
  • 4. 4 As we know from school days , and still we have studied about the solutions of equations like Quadratic equations , Cubical equations & polynomial equations and having roots in the form of π‘₯ = βˆ’π‘Β± 𝑏2βˆ’4π‘Žπ‘ 2π‘Ž where a, b , c are the coefficient of equation. But nowadays it is very difficult to remember formulas for higher degree polynomial equations . Hence to remove these difficulties there are few numerical methods, one of the easiest of them is Newton Raphson Method Which has to be discussed in this power point presentation. Newton Raphson method is a numerical technique which is used to find the roots of Algebraic & transcendental Equations .
  • 5. 6 Newton Raphson method is a numerical technique which is used to find the roots of Algebraic & transcendental Equations . Algebraic Equations : An equation of the form of quadratic or polynomial. e.g. π‘₯4+π‘₯2+1=0 π‘₯8-1 =0 π‘₯3-2x -5=0
  • 6. 7 Transcendental equation : An equation which contains some transcendental functions Such as exponential or trigonometric functions. e.g. sin , cos , tan , 𝑒π‘₯ , π‘₯𝑒 , log etc. 3x-cosx-1=0 logx+2x=0 𝑒π‘₯-3x=0 Sinx+10x-7=38 Newton Raphson Method : Let us consider an equation 𝑓(π‘₯) = 0 having graphical representation as
  • 7. 8 . β€’ f(x) =0 , is a given equation β€’ Starting from an initial point π‘₯0 β€’ Determine the slope of f(x) at x=π‘₯0 .Call 𝑓’(π‘₯0). Slope ; = tanΡ² 𝑓′( Hence ; β€’ Newton Raphson formula Algorithm for f(x)=0 β€’ Calculate f’(x) symbolically.
  • 8. Choose an initial guess π‘₯0 as given below let [a,b] be any interval such that 𝑓 π‘Ž < 0 π‘Žπ‘›π‘‘ 𝑓 𝑏 > 0 . β€’ . Similarly . β€’ Then by repetition of this process we can find π‘₯3 ,π‘₯4 , π‘₯5 … … β€’ At last we reach at a stage where we find π’™π’Š+𝟏 = π’™π’Š. β€’ Then we will stop. β€’ Hence π’™π’Š will be the required root of given equation. NRM by Taylor series :- if we have given an equation 𝑓(π‘₯) = 0. π‘₯0 be the approximated root of given equation.
  • 9. 10 β€’ Let (π‘₯0 +h) be the actual root where β€˜h’ is very small such that f(π‘₯0 + β„Ž)=0 From Taylor series expansion on expanding to f(π‘₯0 + β„Ž) f(f’’’(π‘₯0) +……. Now on neglecting higher powers of h f(π‘₯0) + hf’(π‘₯0) =0 From above h= Hence first approximation π‘₯1=(π‘₯0 + β„Ž);
  • 10. Second approximation ; On repeating this process We get This is the required newton Raphson method. How to solve an example : F(x)= π‘₯3- 2x – 5 F’(x) = 3π‘₯2-2 Now checking for initial point ; F(3) =16 F(2)= -1 F(3) =16 Hence root lies between (2,3) Initial point ( From NRM formula Putting all these above values in this formula
  • 11. . 12 𝑛+1 𝑛 π‘₯ = π‘₯ βˆ’ n n 3 x 2 ο€­ 2 ο€­ 2 x ο€­ 5 𝑛+1 𝑛 π‘₯ = π‘₯ βˆ’ n n n 3 x 2 ο€­ 2 ο€­ 2 x ο€­ 5 x 3 On putting initial value π‘₯0 = 2.5 We get first approximate root; π‘₯1=2.164179104 Similarly: π‘₯2=2.097135356 π‘₯3=2.094555232 π‘₯4=2.094551482 π‘₯5=2.094551482 Hence π±πŸ’=π±πŸ“ Hence 2.094551482 is the required root of given equation
  • 12. 13 β€’ To find the square root of any no. β€’ To find the inverse β€’ To find inverse square root. β€’ Root of any given equation. Application of NRM :
  • 13. 16 Limitations of NRM: β€’ F’(x)=0 is real disaster for this method β€’ F’’(x)=0 causes the solution to diverse β€’ Sometimes get trapped in local maxima and minima
  • 14. 17 References : Engineering Mathematics Books Internet Classes & Classnotes Teachers & Friends n.