The document provides instructions for constructing various angles and triangles using only a compass and straightedge. It includes steps to construct the bisector of an angle, angles of 60°, 30°, 90°, 45° and 120°, equilateral triangles, triangles given base/sides/angles, and triangles given perimeter and two base angles. Diagrams illustrate each construction and explanations are provided for how the methods work.
Basic geometrical constuctions is how to construct angle by using compass and ruler.
this slide can help students or teachers to construct any angles especially for special angles they are 90 degree, 60 degree, 45 degree and 30 degree.
Basic geometrical constuctions is how to construct angle by using compass and ruler.
this slide can help students or teachers to construct any angles especially for special angles they are 90 degree, 60 degree, 45 degree and 30 degree.
Pedagogy of Mathematics (Part II) - Geometry, Geometry, Maths, IX std Maths, Samacheerkalvi maths, II year B.Ed., Pedagogy, Mathematics, circumradius, acute triangle, obtuse triangle, right triangle, incircle of triangle, incentre,
Pedagogy of Mathematics (Part II) - Geometry, Geometry, Maths, IX std Maths, Samacheerkalvi maths, II year B.Ed., Pedagogy, Mathematics, circumradius, acute triangle, obtuse triangle, right triangle, incircle of triangle, incentre,
In some cases it will be watched that numerous checks like waterways, channels, lakes. thick wildernesses, trench, structures, and so on lie on the chain line. These obstructions can be kept away from in tying operation by applying some principal geometric principles.
In this ppt you will find about the Types of obstacles in chain surveying and the solutions to overcome this obstacles.
To see more about chain surveying visit here http://wikienvironment.org/chain-surveying
How to compute area of spherical triangle given the aperture angles subtended...Harish Chandra Rajpoot
The author Mr H.C. Rajpoot has derived the general formula to compute the area of the spherical triangle having each side as a great circle arc on the spherical surface when 1.) aperture angle subtended by each of three sides at the center of sphere are known 2.) arc length of each of three sides is known. These formula are applicable for any spherical triangle to the compute area on the sphere.
Securing your Kubernetes cluster_ a step-by-step guide to success !KatiaHIMEUR1
Today, after several years of existence, an extremely active community and an ultra-dynamic ecosystem, Kubernetes has established itself as the de facto standard in container orchestration. Thanks to a wide range of managed services, it has never been so easy to set up a ready-to-use Kubernetes cluster.
However, this ease of use means that the subject of security in Kubernetes is often left for later, or even neglected. This exposes companies to significant risks.
In this talk, I'll show you step-by-step how to secure your Kubernetes cluster for greater peace of mind and reliability.
Elevating Tactical DDD Patterns Through Object CalisthenicsDorra BARTAGUIZ
After immersing yourself in the blue book and its red counterpart, attending DDD-focused conferences, and applying tactical patterns, you're left with a crucial question: How do I ensure my design is effective? Tactical patterns within Domain-Driven Design (DDD) serve as guiding principles for creating clear and manageable domain models. However, achieving success with these patterns requires additional guidance. Interestingly, we've observed that a set of constraints initially designed for training purposes remarkably aligns with effective pattern implementation, offering a more ‘mechanical’ approach. Let's explore together how Object Calisthenics can elevate the design of your tactical DDD patterns, offering concrete help for those venturing into DDD for the first time!
Software Delivery At the Speed of AI: Inflectra Invests In AI-Powered QualityInflectra
In this insightful webinar, Inflectra explores how artificial intelligence (AI) is transforming software development and testing. Discover how AI-powered tools are revolutionizing every stage of the software development lifecycle (SDLC), from design and prototyping to testing, deployment, and monitoring.
Learn about:
• The Future of Testing: How AI is shifting testing towards verification, analysis, and higher-level skills, while reducing repetitive tasks.
• Test Automation: How AI-powered test case generation, optimization, and self-healing tests are making testing more efficient and effective.
• Visual Testing: Explore the emerging capabilities of AI in visual testing and how it's set to revolutionize UI verification.
• Inflectra's AI Solutions: See demonstrations of Inflectra's cutting-edge AI tools like the ChatGPT plugin and Azure Open AI platform, designed to streamline your testing process.
Whether you're a developer, tester, or QA professional, this webinar will give you valuable insights into how AI is shaping the future of software delivery.
Dev Dives: Train smarter, not harder – active learning and UiPath LLMs for do...UiPathCommunity
💥 Speed, accuracy, and scaling – discover the superpowers of GenAI in action with UiPath Document Understanding and Communications Mining™:
See how to accelerate model training and optimize model performance with active learning
Learn about the latest enhancements to out-of-the-box document processing – with little to no training required
Get an exclusive demo of the new family of UiPath LLMs – GenAI models specialized for processing different types of documents and messages
This is a hands-on session specifically designed for automation developers and AI enthusiasts seeking to enhance their knowledge in leveraging the latest intelligent document processing capabilities offered by UiPath.
Speakers:
👨🏫 Andras Palfi, Senior Product Manager, UiPath
👩🏫 Lenka Dulovicova, Product Program Manager, UiPath
Slack (or Teams) Automation for Bonterra Impact Management (fka Social Soluti...Jeffrey Haguewood
Sidekick Solutions uses Bonterra Impact Management (fka Social Solutions Apricot) and automation solutions to integrate data for business workflows.
We believe integration and automation are essential to user experience and the promise of efficient work through technology. Automation is the critical ingredient to realizing that full vision. We develop integration products and services for Bonterra Case Management software to support the deployment of automations for a variety of use cases.
This video focuses on the notifications, alerts, and approval requests using Slack for Bonterra Impact Management. The solutions covered in this webinar can also be deployed for Microsoft Teams.
Interested in deploying notification automations for Bonterra Impact Management? Contact us at sales@sidekicksolutionsllc.com to discuss next steps.
DevOps and Testing slides at DASA ConnectKari Kakkonen
My and Rik Marselis slides at 30.5.2024 DASA Connect conference. We discuss about what is testing, then what is agile testing and finally what is Testing in DevOps. Finally we had lovely workshop with the participants trying to find out different ways to think about quality and testing in different parts of the DevOps infinity loop.
Encryption in Microsoft 365 - ExpertsLive Netherlands 2024Albert Hoitingh
In this session I delve into the encryption technology used in Microsoft 365 and Microsoft Purview. Including the concepts of Customer Key and Double Key Encryption.
Kubernetes & AI - Beauty and the Beast !?! @KCD Istanbul 2024Tobias Schneck
As AI technology is pushing into IT I was wondering myself, as an “infrastructure container kubernetes guy”, how get this fancy AI technology get managed from an infrastructure operational view? Is it possible to apply our lovely cloud native principals as well? What benefit’s both technologies could bring to each other?
Let me take this questions and provide you a short journey through existing deployment models and use cases for AI software. On practical examples, we discuss what cloud/on-premise strategy we may need for applying it to our own infrastructure to get it to work from an enterprise perspective. I want to give an overview about infrastructure requirements and technologies, what could be beneficial or limiting your AI use cases in an enterprise environment. An interactive Demo will give you some insides, what approaches I got already working for real.
Connector Corner: Automate dynamic content and events by pushing a buttonDianaGray10
Here is something new! In our next Connector Corner webinar, we will demonstrate how you can use a single workflow to:
Create a campaign using Mailchimp with merge tags/fields
Send an interactive Slack channel message (using buttons)
Have the message received by managers and peers along with a test email for review
But there’s more:
In a second workflow supporting the same use case, you’ll see:
Your campaign sent to target colleagues for approval
If the “Approve” button is clicked, a Jira/Zendesk ticket is created for the marketing design team
But—if the “Reject” button is pushed, colleagues will be alerted via Slack message
Join us to learn more about this new, human-in-the-loop capability, brought to you by Integration Service connectors.
And...
Speakers:
Akshay Agnihotri, Product Manager
Charlie Greenberg, Host
Epistemic Interaction - tuning interfaces to provide information for AI supportAlan Dix
Paper presented at SYNERGY workshop at AVI 2024, Genoa, Italy. 3rd June 2024
https://alandix.com/academic/papers/synergy2024-epistemic/
As machine learning integrates deeper into human-computer interactions, the concept of epistemic interaction emerges, aiming to refine these interactions to enhance system adaptability. This approach encourages minor, intentional adjustments in user behaviour to enrich the data available for system learning. This paper introduces epistemic interaction within the context of human-system communication, illustrating how deliberate interaction design can improve system understanding and adaptation. Through concrete examples, we demonstrate the potential of epistemic interaction to significantly advance human-computer interaction by leveraging intuitive human communication strategies to inform system design and functionality, offering a novel pathway for enriching user-system engagements.
3. In triangles BEF and BDF, BE = BD (Radii of the same arc) EF = DF (Arcs of equal radii) BF = BF (Common) Therefore, BEF = BDF (SSS rule) This gives EBF = DBF (CPCT)
4. CONSTRUCTION OF THE BISECTOR OF A GIVEN ANGLE Bisecting an angle means drawing a ray in the interior of the angle, with its initial point at the vertex of the angle such that it divides the angle into two equal parts. In order to draw a ray AX bisecting a given angle BAC, we following steps. C Q X R A P B Steps of construction STEPI With centre A and any convenient radius draw an are cutting AB and AC at P and Q respectively. STEPII with centre P and radius more than ½ (PQ) draw an arc.
5. STEP III W ith centre Q and the same radius, as in step II, draw another arc intersecting the arc in step II at R. STEPIV Join AR and produce it to any point X. The ray AX is the required bisector of BAC. Verification : Measure BAX and CAX. You would find that BAX = CAX. Justification : Now let us see how this method gives us the required angle bisector: Join PR and QR. In triangles : APR and AQR, we have [ AP and AQ are radii of the same arc ] AP = AQ [PR and QR are arcs of equal radii] PR = QR [Common] AR = AR So, by SSS congruence criterion, we have APR = AQR PAR = QAR Hence, AR is the bisector of BAC.
6. CONSTRUCTION OF SOME STANDARD ANGLES In this section, we will learn how to construct angles of 60 o ,30 0 ,90 0 ,45 0 and 120 0 with the help of ruler and compasses only. For Example : CONSTRUCTION OF AN ANGLE OF 60 0 In order to construct an angle of 60 0 with the help of ruler and compasses only, we follow the following steps. Steps of construction STEPI Draw a ray OA. STEPII With centre O and any radius draw an arc PQ with the help of compasses, cutting the ray OA at P. STEPIII With centre P and the same radius draw an arc cutting the arc PQ at R. STEPIV Join OR and produce it to obtain ray OB.
7. The angle AOB so obtained is the angle of measure 60 0 . Join PR. Justification : Now, let us see how this method gives us the required angle of 60 0. Join PR. In OPR, we have OP = OR = PR [ See construction of angle of 600] OPR is an equilateral triangle. POR = 60 0 [ POR = AOB] AOB = 60 0
8. SOME CONSTUCTIONS OF TRIANGLES In order to construct a triangle at least three parts must be given. But, all the combinations of three parts out of six parts are not sufficient to construct a triangle. For example, if two sides and an angle (not the included angles) are given, then it is not possible to construct such a triangle. CONSTRUCTION OF AN EQUILATERAL TRIANGLE In order to construct an equilateral triangle when the measure (length) of its side is given we follow the following steps: steps of construction STEP I Draw a ray AX with initial point A. STEP II With centre A and radius equal to length of a side of the triangle draw an arc BY, cutting the ray AX at B.
9. STEP III With centre B and the same radius draw an arc cutting the arc BY at C. STEP IV Join AC and BC to obtain the required triangle. CONSTRUCTION OF A TRIANGLE WHEN ITS BASE, SUM OF THE OTHER TWO SIDES AND ONE BASE ANGLE ARE GIVEN In order to construct a triangle, when its base, sum of the other two sides and one of the base angles are given, we follow the following steps: CONSTRUCTIONS Steps of construction STEPI Obtain the base, base angle and the sum of other two sides. Let AB be the base, A be the base angle and I be the sum of the lengths of other two sides BC and CA of ABC. STEPII Draw the base AB.
10. STEPIII Draw BAX of measure equal to that of A STEPIV From ray AX, cut – off line segment AD equal to 1 (the sum of other two sides). STEPV Join BD. STEPVI Draw the perpendicular bisector of BD meeting AD at C. STEPVII Join BC to obtain the required triangle ABC. Justification : Let us now see how do we get the required triangle: since point Clies on the perpendicular bisector of BD. Therefore, CD = CB Now AC = AD – CD AC = AD – CB [CD = CB] AD = AC + CB
11. CONSTRUCTION OF A TRIANGLE WHEN ITS BASE, DIFFERENCE OF THE OTHER TWO SIDES AND ONE BASE ANGLE ARE GIVEN In order to construct a triangle when its base, difference of the other two sides and one of the base angles are given, we follow the following steps:
12. Steps of construction STEPI Obtain the base, base angle and the difference of two other sides. Let AB be the base, A be the base angle and I be the difference of the other two sides BC and CA of ABC. i.e., I= AC – BC, if AC >BC or, I= BC – AC, if BC >AC STEPII Draw the base AB of given length. STEPIII Draw < BAX of measure equal to that of <A STEPIV If AC>BC, then cut off segment AD = AC – BC from ray AX. (See fig 16.18.(i)) if AC < BC then extend XA to X’ on opposite side of AB and cut off segment AD = BC – AC from ray AX’. (See fig. 16.18 (ii)). STEPV Join BD.
13. STEPVI Draw the perpendicular bisector of BD which cuts AX or AX’, as the case may be, at C. STEPVII Join BC to obtain the required triangle ABC. Justification: Let us now see how do we get the required triangle. Since C lies on the perpendicular bisector of DB. So, CD = CB AD = AC – CD = AC - BC
14. CONSTRUCTION OF A TRIANGLE OF GIVEN PERIMETER AND TWO BASE ANGLES In order to construct a triangle of given perimeter and two base angles, we follow the following steps: Steps of construction STEPI Obtain the perimeter and the base angles of the triangle. Let ABC be a triangle of perimeter p cm and base BC.
15. STEPII Draw a line segment XY equal to the perimeter p of ABC. STEPIII Construct YDX = B and XYE = C. STEPIV Draw bsectors of angles < YXD and XYE and mark their intersection point as A. STEPV Draw the perpendicular bisectors of XA and YA meeting XY in B and C respectively. STEPVI Join AB and AC to obtain the required triangle ABC. Justification : For the justification of the construction, we observe that B lies on the perpendicular bisector of AX. XB = AB < AXB = BAX Similarly, Clies on the perpendicular bisector of AX.
16. YC = AC AYC = YAC Now, XY = XB + BC + CY XY = AB + BC + AC In AXB, we have ABC = AXB + BAX = 2 AXB = BXD = BXY = B. In AYC, we have ACB = AYC + YAC = 2 AYC = CYE = C.