This document provides instructions for performing various geometric constructions. It begins with introductory information on points, lines, and common geometric shapes. It then provides step-by-step instructions for constructing angles, triangles, circles, quadrilaterals, regular polygons, tangents to circles, joining circles, ellipses, involutes, and more. The constructions require only a compass and straightedge. Accuracy is emphasized as the key difficulty.
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SHARIGUIN PROBLEMS IN PLANE GEOMETRY
This volume contains over 600 problems in plane geometry and consists of two parts. The first part contains rather simple problems to be solved in classes and at home. The second part also contains hints and detailed solutions. Over 200 new problems have been added to the 1982 edition, the simpler problems in the first addition having been eliminated, and a number of new sections- (circles and tangents, polygons, combinations of figures, etc.) having been introduced, The general structure of the book has been changed somewhat to
accord with the new, more detailed, classification of the problems. As a result, all the problems in this volume have been rearranged.
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SHARIGUIN PROBLEMS IN PLANE GEOMETRY
This volume contains over 600 problems in plane geometry and consists of two parts. The first part contains rather simple problems to be solved in classes and at home. The second part also contains hints and detailed solutions. Over 200 new problems have been added to the 1982 edition, the simpler problems in the first addition having been eliminated, and a number of new sections- (circles and tangents, polygons, combinations of figures, etc.) having been introduced, The general structure of the book has been changed somewhat to
accord with the new, more detailed, classification of the problems. As a result, all the problems in this volume have been rearranged.
Cosmetic shop management system project report.pdfKamal Acharya
Buying new cosmetic products is difficult. It can even be scary for those who have sensitive skin and are prone to skin trouble. The information needed to alleviate this problem is on the back of each product, but it's thought to interpret those ingredient lists unless you have a background in chemistry.
Instead of buying and hoping for the best, we can use data science to help us predict which products may be good fits for us. It includes various function programs to do the above mentioned tasks.
Data file handling has been effectively used in the program.
The automated cosmetic shop management system should deal with the automation of general workflow and administration process of the shop. The main processes of the system focus on customer's request where the system is able to search the most appropriate products and deliver it to the customers. It should help the employees to quickly identify the list of cosmetic product that have reached the minimum quantity and also keep a track of expired date for each cosmetic product. It should help the employees to find the rack number in which the product is placed.It is also Faster and more efficient way.
About
Indigenized remote control interface card suitable for MAFI system CCR equipment. Compatible for IDM8000 CCR. Backplane mounted serial and TCP/Ethernet communication module for CCR remote access. IDM 8000 CCR remote control on serial and TCP protocol.
• Remote control: Parallel or serial interface.
• Compatible with MAFI CCR system.
• Compatible with IDM8000 CCR.
• Compatible with Backplane mount serial communication.
• Compatible with commercial and Defence aviation CCR system.
• Remote control system for accessing CCR and allied system over serial or TCP.
• Indigenized local Support/presence in India.
• Easy in configuration using DIP switches.
Technical Specifications
Indigenized remote control interface card suitable for MAFI system CCR equipment. Compatible for IDM8000 CCR. Backplane mounted serial and TCP/Ethernet communication module for CCR remote access. IDM 8000 CCR remote control on serial and TCP protocol.
Key Features
Indigenized remote control interface card suitable for MAFI system CCR equipment. Compatible for IDM8000 CCR. Backplane mounted serial and TCP/Ethernet communication module for CCR remote access. IDM 8000 CCR remote control on serial and TCP protocol.
• Remote control: Parallel or serial interface
• Compatible with MAFI CCR system
• Copatiable with IDM8000 CCR
• Compatible with Backplane mount serial communication.
• Compatible with commercial and Defence aviation CCR system.
• Remote control system for accessing CCR and allied system over serial or TCP.
• Indigenized local Support/presence in India.
Application
• Remote control: Parallel or serial interface.
• Compatible with MAFI CCR system.
• Compatible with IDM8000 CCR.
• Compatible with Backplane mount serial communication.
• Compatible with commercial and Defence aviation CCR system.
• Remote control system for accessing CCR and allied system over serial or TCP.
• Indigenized local Support/presence in India.
• Easy in configuration using DIP switches.
CFD Simulation of By-pass Flow in a HRSG module by R&R Consult.pptxR&R Consult
CFD analysis is incredibly effective at solving mysteries and improving the performance of complex systems!
Here's a great example: At a large natural gas-fired power plant, where they use waste heat to generate steam and energy, they were puzzled that their boiler wasn't producing as much steam as expected.
R&R and Tetra Engineering Group Inc. were asked to solve the issue with reduced steam production.
An inspection had shown that a significant amount of hot flue gas was bypassing the boiler tubes, where the heat was supposed to be transferred.
R&R Consult conducted a CFD analysis, which revealed that 6.3% of the flue gas was bypassing the boiler tubes without transferring heat. The analysis also showed that the flue gas was instead being directed along the sides of the boiler and between the modules that were supposed to capture the heat. This was the cause of the reduced performance.
Based on our results, Tetra Engineering installed covering plates to reduce the bypass flow. This improved the boiler's performance and increased electricity production.
It is always satisfying when we can help solve complex challenges like this. Do your systems also need a check-up or optimization? Give us a call!
Work done in cooperation with James Malloy and David Moelling from Tetra Engineering.
More examples of our work https://www.r-r-consult.dk/en/cases-en/
1. Introduction
In the course of engineering drawing, it is often necessary to make a certain
geometrical constructions in order to complete an outline.
There are no projections involved, and no dimensioning problems, the ONLY
GREAT DIFFICULTY IS ACCURACY.
Common geometric shapes
2. PRELIMINARY TECHNIQUES
Geometrical Construction Techniques
LINES
A POINT has noarea,
it indicatesa position,
itcan be indicated bya
dotor thus
A LINE has length but
no area. It may be
curved orstraight.
A STRAIGHT LINE is
the shortest distance
between two points.
GEOMETRICAL TERMS
3. BISECTING/PERPENDICULARS/PARALLELS/DIVISION
1) BISECT A LINE 2) BISECT AN ACUTE ANGLE
1. Set an acute angle (angle less than
90:), and bisect the angle.
3) BISECT OF A GIVEN ARC
1. With a compass opened to a
distancegreater than half AB, strike
arcs from A and B.
2. A line joining the points of
intersection of the arcs is the
bisector.
1. With centre A and radius greater
thanhalf AB, describe an arc.
2. Repeat with the same radius from B,
the arcs intersecting at C and D. Join
C to D to bisect the arc AB.
4) PERPENDICULAR AT A POINT ON A 5) PARALLEL LINE TO A LINE WITH A
GIVEN DISTANCE.
AB is the given line, C is the given distance.
1. From any two points well apart on
AB, draw two arcs of radius equal to
C.
2. Draw a line tangentialto the two
arcs to give required line.
6) DIVISION OF A LINE INTO EQUAL
PARTS
AB is the given line.
1. Drawa line AC at any angle.
2. On line AC, make three convenient
equal divisions.
3. Join the last division with B and draw
parallel lines as shown.
LINE
1. At point O, draw a semicircle of any
radiusto touch the line at a and b.
2. With compass at a greaterradius,
strike arcs from a and b.
4. CONSTRUCTIONS OF ANGLES
TERMINOLOGY
If two lines are pivoted
as sh
. own in the
diagram, as one line
opens they form an
angle. If the rotation is
continued the line will
cover a full circle. The
unit for measuring an
angle is a
NAMES OF ANGLES
7) CONSTRUCTION OF A 60° AND 30° ANGLES
8) CONSTRUCTION OF A 45° AND 90° ANGLES
5. CONSTRUCTION OF TRIANGLES
TERMINOLOGY
A triangle is a plane figure
bounded by three straight
lines.
Triangles are named according
to the length of their sides or
the magnitude of their angles.
EQUILATERAL
All angles 60°.
All sides equal.
ISOSCELES
Base angles equal.
Opposite sides equal
RIGHT ANGLE
One angle is 90°.
All sides of different length.
OBTUSE ANGLE
One angle is greater than 90°. All sides of
differentlength.
SCALENE
All angles different. All sides of
differentlength.
6. CONSTRUCTION OF TRIANGLES
9) TO CONSTRUCT AN EQUILATERAL TRIANGLE 10) TO CONSTRUCT AN ISOSCELES TRIANGLE, GIVEN
BASE AND VERTICAL HEIGHT
1.Draw a line AB, equal to the length of the side.
2.With compass point on A and radius AB, draw an
arc as shown above.
1.Drawline AB.
2.Bisect AB and mark the vertical height.
ABC is the required isosceles triangle.
11) TO CONSTRUCT A RIGHT-ANGLE TRIANGLE
1.Draw AB. From A construct angle CAB.
2.Bisect AB. Produce the bisection to cut AC at O.
3.With centre O and radius OA, draw semi-circle to
find C.
Completethe triangle
12) TO CONSTRUCT A TRIANGLE, GIVEN THE BASE
ANGLES & THE ALTITUDE
1.Draw a line AB. Construct CD parallel to AB so that the
distance between them is equal to the latitude.
2.From any point E, on CD, draw CÊF & DÊG so that they cut
AB in F & G respectively.
3.Since CÊF = EFG & DÊG = EĜF (alternateangles), then
EFG is the requiredtriangle.
7. THE CIRCLE
PARTS OF A CIRCLE
13) TO FIND THE CENTRE OF A
GIVEN ARC
14) TO FIND THE CENTRE OF
CIRCLES (METHOD 1)
15) TO FIND THE CENTRE OF
CIRCLES (METHOD 2)
1. Draw two chords, AC and BD.
2. Bisect AC and BD as shown. The
bisectors will intersect at E.
3. The centre of the arc is point E.
1. Draw two horizontal lines facing one
another across the circle at a place
approximately halfway from the top to
the centre of the circle. These lines pass
through the circle form points A, B, C
and D.
2. Bisect these two lines. Where these two
bisect lines intersect, thus the centre of
the given circle.
1. Draw a horizontal line across the
circle at a place approx. halfway from
the top to the centre of the circle.
2. Draw perpendicular lines downward
from A and B. Where these lines cross
the circle forms C & D.
3. Draw a line from C to B and from A to
D. Where these lines cross is the exact
centreof the given circle.
8. QUADRILATERALS
TERMINOLOGY
The quadrilateral is a plane figure bounded by four straight sides
SQUARE
All four sides equal.
All angles 90:.
RECTANGLE
Opposite sides of
equal.
All angle90:.
RHOMBUS
All four sides equal.
Opposite angles
equal.
PARALLELOGRAM
Opposite sides
equal.
Opposite angles
equal.
TRAPEZIUM
Two parallel
sides.
Two pairs of
angles equal.
16) TO CONSTRUCT A SQUARE
1.Draw the side AB. From B erect
a perpendicular. Mark off the
length of side BC.
2.With centres A & C draw arcs,
radius equal to the length of the
side of the square, to intersect at
D.
ABCD is the required square.
17) TO CONSTRUCT A
PARALLELOGRAM
1.Draw AD equal to the length of one of
the sides. From A construct the known
angle. Mark off AB equal length to
other known side.
2.With compass pt. at B draw an arc
equal radius to AD. With compass pt. at
D draw an arc equal in radius to AB.
ABCD is the required parallelogram.
18) TO CONSTRUCT A RHOMBUS
1.Drawthe diagonalAC.
2.From A and C draw intersecting
arcs, equal in length to the sides, to
meet at B and D.
ABCD is the required rhombus.
9. REGULARPOLYGONS
TERMINOLOGY
A polygon is a plane figure bounded by more than four straight sides. Regular polygons are named according to the number of their
sides.
PENTAGON
sides
:5 sides HEPTAGON :7 sides NONAGON :9 sides UNDECAGON :11
HEXAGON
sides
:6 sides OCTAGON :8 sides DECAGON :10 sides DODECAGON :12
The regular polygons drawn on this page are the figures most frequently used in geometrical drawing. Particularly the hexagon and the
octagon which can be constructed by using60⁰ or 45⁰ set-square.
REGULAR PENTAGON
Five sides equal.
Five angles equal.
REGULAR HEXAGON
Six sides equal.
Six angles equal.
REGULAR OCTAGON
Eight sides equal.
Eight angles are equal.
IRREGULAR PENTAGON RE-ENTRANT HEXAGON IRREGULAR HEPTAGON
Five sides unequal.
Five angles unequal.
One interior anglegreater than
180:.
Six sides & six angles unequal.
Seven sides unequal.
Seven angles unequal.
10. 19) TO CONSTRUCT A
HEXAGON, GIVEN THE
DISTANCE ACROSS THE
CORNERS (A/C)
20) TO CONSTRUCT A HEXAGON,
GIVEN THE DISTANCE ACROSS THE
FLATS (A/F)
21) TO CONSTRUCT AN
OCTAGON, GIVEN THE DISTANCE
ACROSS CORNERS (A/C)
1.Drawa vertical and horizontal
centre lines and a circle with a
diameter equal to the given
distance.
2.Step off the radius around the
circle to give six equally spaced
points, and join the points to give
the required hexagon.
1.Draw vertical and horizontal centre
lines and a circle with a diameter equal
to the given distance.
Use a 60: set-square and tee-square as
shown to give the six sides.
1.Draw vertical and horizontal
centre lines and a circle with a
diameter equal to the given
distance.
2.With a 45: set-square, draw
points on the circumference 45:
apart.
Connect these eight points by
straightlines to give the required
octagon.
11. 22) TO CONSTRUCT AN
OCTAGON, GIVEN THE
DISTANCE ACROSS CORNERS (A/C)
1.Draw vertical and horizontal centre lines and a circle with a
diameterequal to the given distance.
2.With a 45: set-square, draw points on the circumference 45:
apart.
3.Connect these eight points by straight lines to give the
requiredoctagon.
23)TO CONSTRUCT AN OCTAGON,
GIVEN THE DISTANCE
ACROSS THE FLATS (A/F
1.vertical and horizontal centre lines and a circle with
a diameter equal to the given distance.
2.Use a 45: set-square and tee-square as shown in
construction of hexagon A/F to give the eight sides.
24) TO INSCRIBE ANY REGULAR POLYGON WITHIN A CIRCLE.
e.g. PENTAGON
12. T
ANGENTS TO CIRCLES
TERMINOLOGY
If a disc stands on its edge on a flat surface it will touch the surface at one point. This point is known as the point of
tangency as shown in the diagram and the straight line which represents the flat plane is known as a tangent. A line
drawn from the point of tangency to the centre of the disc is called normal, and the tangent makes an angle of 90° with
the normal.
13. 25) EXTERNAL TANGENT TO TWO CIRCLES OF
DIFFERENT Ø (OPEN BELT)
1. Join the centres of circles a and b. Bisect ab to obtain the
centre c of the semicircle.
2. From the outside of the larger circle, subtract the radius
r of the smaller circle. Draw the arc of radius ad. Draw
normal Na.
3. Normal Nb is drawn parallel to normal Na. Draw the
tangent.
26) INTERNAL TANGENT TO TWO CIRCLES OF
DIFFERENT Ø (CROSS BELT)
1. Join the centres of circles a and b. Bisect ab to obtain the
centre c of the semicircle.
2. From the outside of the larger circle, add the radius r of the
smaller circle. Draw the arc of radius ad. Draw normal Na.
3. Normal Nb is drawn parallel to normal Na. Draw the
tangent.
14. JOINING OF CIRCLES
27) OUTSIDE RADIUS
Two circles of radii a and b are tangentialto arc of
radiusR.
1. From the centre of circle radius a, describe an arc of R +
a.
2. From the centre of circle radius b, describe an arc of R +
b.
3. At the intersection of the two arcs, draw arc radius R.
28) INSIDE RADIUS
Two circles of radii a and b are tangential to arc of radius
R.
1. From the centre of circle radius a, describe an arc of R - a.
2. From the centre of circle radius b, describe an arc of R - b.
3. At the intersection of the two arcs, draw arc radius R.
15. THE ELLIPSE
TERMINOLOGY
29) CONCENTRIC/AUXILIARY CIRCLE METHOD
1.Draw two circles aroundthe major and minor axis.
2.Divide into twelve equal parts using 30: - 60: set-square.
3.Draw horizontal lines from the minor circle and vertical lines from the major circle.
4.The intersection points between horizontal and vertical lines are points of an ellipse.
16. AN INVOLUTE
TERMINOLOGY
There are several definitions for the involutes, none being particularly easy to follow. An involute is the path of a point
on a string as the string unwinds from a line, polygon, or circle. And it is also the locus of a point, initially on a base circle,
which moves so that its straight line distance, along a tangent to the circle, to the tangential point of contact, is equal to
the distance along the arc of the circle from the initial point to the instant point of tangency.
The involute is best visualized as the path traced out by the end of a piece of cotton when cotton is unrolled from its reel.
30) TO DRAW AN INVOLUTE OF A CIRCLE
Let the diameter of the circle is given
1. Divide the circle into 12 equal parts.
2.Draw tangents at each of the twelve
circumferential divisions point, setting off along each
tangentthe length of the corresponding circular arc.
3.Draw the required curve through the points set off
and can be determined by setting off equal distances 0-1,
1-2, 2-3, and so on, along the circumference.
NOTE:
The involutes of a circle are used in the construction of involutes gear teeth. In this system, the involutes form the face and a part
of the flank of the teeth of gear wheels; the outlines of the teeth of racks are straight lines.