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1.79V Solution 1.79V.
1.79VSolution1.79V.pdf
1.79VSolution1.79V.pdf
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1)It capture leaving on the purpose of the CA documentation: it have near decide involving excellent accessed awful entrance 2)through sufficient crack, some cryptographic system container be there attack effectively. This can cause crash attack 3)since the fundamental vulnerability occur in a cryptographic primordial, explicit development scenario contrast usually depending on the scenery of the data the enemy have the talent to spoof and how it is validate by software 4)sure, Cryptosystem ME 6 9.21it is a Windows program encrypt information in either a only file or in several files therefore to it cannot be understand writing by persons not expressive the key. Data is encrypted use a key 16 to 64 characters lengthy, and a progression of 64 casual bytes 5)The machine be able to exist reconfigured to make use of a extra protected hash algorithm 6)sure and rejection. rejection, since it will entail our Cisco hardware be replace through newer hardware competent of with added safe algorithms. Our present software can be improve though is at rest able of creature compromise lastly. sure, if we create property accessible, we can improve our hardware and software with extra safe gear, and algorithms These would allow to improved make sure we are secure our system 7)No develop has been unconstrained. Researchers cover bent exploit, but they will not release the in sequence as of yet. The examine was planned to supply information to encourage people to upgrade. 8)small, except achievable. An exploit is a part of software, a portion of information, or a order of instructions 9)If attack be to be conduct the answer might be obtain password for user, their individual in sequence, and more. Once provided that genuine but fake certificate to our user they might capture any in sequence they give, as well as provide for them in sequence. 10)MD5 is quickly being replaced. MD5 is an algorithm to is use to confirm information truth during the making of a 128-bit significance process starting information input that is claim to be as sole to that exact information as fingerprint is to exact creature 11)sure, one time it is busted the course can be duplicate noticeably and no spot or official document might really be trust not including intense, exorbitant analysis. 12)Simple figure screening the MD5 course, and the course of its altered form. 13)extra full explanation of the abbreviation, and vocabulary use. full diagram presentation the course MD5 use and how it might be dishonored. use conditions, and reference in a way to narrate the notion to nontechnical experience 14)Vulnerability in this background can be definite as the diminish capability of an personality oppose and get well starting the contact of a usual or man-made dangerimportant and classify network or system property.conveying relation levels of significance to the capital.identify probable pressure to each supply.increasing a policy to deal with the mainly grave possible troubles first.important.
1)It capture leaving on the purpose of the CA documentation it have.pdf
1)It capture leaving on the purpose of the CA documentation it have.pdf
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1). Na+/K+ ATPase pump plays an important role in maintaining membrane potential. Sodium- potassium ATPase (Na+/K+ ATPase) allows the influx of sodium ions and efflux of potassium ions, which results in increased intracellular positive charge. Increased expression of sodium- potassium ATPase (Na+/K+ ATPase) causes decreased extracellular sodium and increased extracellular potassium levels. 2). Substances move into and out of the cell by means of transport vesicles. Exocytosis is the transport of substances or molecules through transport vesicles that cannot pass through the cell membrane. For example, the neurotransmitters present within the synaptic vesicles are released out by exocytosis. This sac like structure id formed from the layer of cell membrane. The transport of larger molecules or other substances into the cell by means of transport vesicles in known as endocytosis. For example, larger vesicles carry liquid or solid material from outside to the inside of the cell. They are formed from the part of cell membrane; they pinch off to release the molecules into the cell interior. Solution 1). Na+/K+ ATPase pump plays an important role in maintaining membrane potential. Sodium- potassium ATPase (Na+/K+ ATPase) allows the influx of sodium ions and efflux of potassium ions, which results in increased intracellular positive charge. Increased expression of sodium- potassium ATPase (Na+/K+ ATPase) causes decreased extracellular sodium and increased extracellular potassium levels. 2). Substances move into and out of the cell by means of transport vesicles. Exocytosis is the transport of substances or molecules through transport vesicles that cannot pass through the cell membrane. For example, the neurotransmitters present within the synaptic vesicles are released out by exocytosis. This sac like structure id formed from the layer of cell membrane. The transport of larger molecules or other substances into the cell by means of transport vesicles in known as endocytosis. For example, larger vesicles carry liquid or solid material from outside to the inside of the cell. They are formed from the part of cell membrane; they pinch off to release the molecules into the cell interior..
1). Na+K+ ATPase pump plays an important role in maintaining membra.pdf
1). Na+K+ ATPase pump plays an important role in maintaining membra.pdf
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total number of moles of the copund remains same when we dilute moles = molarity * volume intial = final M1* V1= M2* v2 M1=6.3 V1= 27.5 ml M2=1.5 V2= 6.3* 27.5/1.5=115.5 ml is the total volume Solution total number of moles of the copund remains same when we dilute moles = molarity * volume intial = final M1* V1= M2* v2 M1=6.3 V1= 27.5 ml M2=1.5 V2= 6.3* 27.5/1.5=115.5 ml is the total volume.
total number of moles of the copund remains same .pdf
total number of moles of the copund remains same .pdf
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#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include \"header.h\" #include \"chrrecksum.h\" #define BCKLG 10 void sgchrrldHndlr(int s) { while(waitpid(-1, NULL, WNOHANG) > 0); } void *get_in_addr(struct sockaddr *sa) { if (sa->SaFamly == AF_INET) { return &(((struct Sckadr_in*)sa)->sin_addr); } return &(((struct Sckadr_in6*)sa)->sin6_addr); } int main(int arc, chrrar**arv) { int prt = 69; chrrar chrr; while ((chrr = gtOpt(arc, arv, \"p:\")) != -1) { switchrr (chrr) { case \'p\': prt = atoi(optarg); break; case \'?\': exit(1); } } chrrar prt[10]; sprintf(prt,\"%d\",prt); int sockfd, newdv; // listen on sock_fd, new connection on newdv struct addrinfo hints, *servinfo, *p; struct sockaddr_storage their_addr; // connector\'s address information socklen_t sin_size; struct sigaction sa; int yes=1; chrrar s[INET6_ADDRSTRLEN]; int rv; memset(&hints, 0, sizeof hints); hints.ai_family = AF_UNSPEC; hints.ai_socktype = SOCK_STREAM; hints.ai_flags = AI_PASSIVE; if ((rv = getaddrinfo(NULL, prt, &hints, &servinfo)) != 0) { fprintf(stderr, \"getaddrinfo: %s\ \", gai_strerror(rv)); return 1; } for(p = servinfo; p != NULL; p = p->ai_next) { if ((sockfd = socket(p->ai_family, p->ai_socktype, p->ai_protocol)) == -1) { perror(\"server: socket\"); continue; } if (setsockopt(sockfd, SOL_SOCKET, SO_REUSEADDR, &yes, sizeof(int)) == -1) { perror(\"setsockopt\"); exit(1); } if (bind(sockfd, p->ai_addr, p->ai_addrlen) == -1) { close(sockfd); perror(\"server: bind\"); continue; } break; } if (p == NULL) { fprintf(stderr, \"server: failed to bind\ \"); return 2; } freeaddrinfo(servinfo); if (listen(sockfd, BCKLG) == -1) { perror(\"listen\"); exit(1); } sa.sa_handler = sgchrrldHndlr; sigemptyset(&sa.sa_mask); sa.sa_flags = SA_RESTART; if (sigaction(SIGchrrLD, &sa, NULL) == -1) { perror(\"sigaction\"); exit(1); } printf(\"server: looking for connections...\ \"); while(1) { accept() loop sin_size = sizeof their_addr; newdv = accept(sockfd, (struct sockaddr *)&their_addr, &sin_size); if (newdv == -1) { perror(\"accept\"); continue; } inet_ntop(their_addr.ss_family, get_in_addr((struct sockaddr *)&their_addr), s, sizeof s); printf(\"server: got connection from %s\ \", s); if (!fork()) { close(sockfd); chrrar buf[PACKET_SIZE]; chrrar databuf[PAYLOAD_SIZE]; int numbytes, ack_bytes; header_t head; packet_t packet; packet_t ackr; int getfilename = 1; chrrar *filename = (chrrar*) \"recvfile.txt\"; FILE * filefd; bzero(buf, PACKET_SIZE); bzero(databuf, PAYLOAD_SIZE); while(getfilename) { if ((numbytes = recv(newdv, buf, PACKET_SIZE, 0)) == -1) { perror(\"recv\"); exit(1); } if(numbytes > 0) { read_header(&head, (packet_t *)buf); read_packet((u_chrrar*) databuf, (packet_t *)buf, (u_short) (numbytes - HEADER_SIZE)); printf(\"Packet \'%d\' received\ \", (int)(head.seq)); if(add_chrrecksum(numbytes, numbytes%2, (u_short *)buf) == 0) { printf(\"chrrecksum OK\ \"); fill_hdr((int)(head.seq).
#include stdio.h #include stdlib.h #include unistd.h #in.pdf
#include stdio.h #include stdlib.h #include unistd.h #in.pdf
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18O is an important precursor for the production offlourodeoxyglucose(FDG) used in PETscans./ PET scans are atechnique which produces a three-dimensional image or picture offunctional processes in the body. In Paleoclimatology they are usedto find out what temperature of earths climate was in the past bycomparing the ratio of oxygen 18 to oxygen 16. Solution 18O is an important precursor for the production offlourodeoxyglucose(FDG) used in PETscans./ PET scans are atechnique which produces a three-dimensional image or picture offunctional processes in the body. In Paleoclimatology they are usedto find out what temperature of earths climate was in the past bycomparing the ratio of oxygen 18 to oxygen 16..
18O is an important precursor for the production offlourodeoxyglucose.pdf
18O is an important precursor for the production offlourodeoxyglucose.pdf
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observed expected O - E (O - E) Solution observed expected O - E (O - E).
observed expected O - E (O - E) Solution observed expect.pdf
observed expected O - E (O - E) Solution observed expect.pdf
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no hydrogen atom is present because its pure carbon compound Solution no hydrogen atom is present because its pure carbon compound.
no hydrogen atom is present because its pure carb.pdf
no hydrogen atom is present because its pure carb.pdf
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Recommended
1.79V Solution 1.79V.
1.79VSolution1.79V.pdf
1.79VSolution1.79V.pdf
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1)It capture leaving on the purpose of the CA documentation: it have near decide involving excellent accessed awful entrance 2)through sufficient crack, some cryptographic system container be there attack effectively. This can cause crash attack 3)since the fundamental vulnerability occur in a cryptographic primordial, explicit development scenario contrast usually depending on the scenery of the data the enemy have the talent to spoof and how it is validate by software 4)sure, Cryptosystem ME 6 9.21it is a Windows program encrypt information in either a only file or in several files therefore to it cannot be understand writing by persons not expressive the key. Data is encrypted use a key 16 to 64 characters lengthy, and a progression of 64 casual bytes 5)The machine be able to exist reconfigured to make use of a extra protected hash algorithm 6)sure and rejection. rejection, since it will entail our Cisco hardware be replace through newer hardware competent of with added safe algorithms. Our present software can be improve though is at rest able of creature compromise lastly. sure, if we create property accessible, we can improve our hardware and software with extra safe gear, and algorithms These would allow to improved make sure we are secure our system 7)No develop has been unconstrained. Researchers cover bent exploit, but they will not release the in sequence as of yet. The examine was planned to supply information to encourage people to upgrade. 8)small, except achievable. An exploit is a part of software, a portion of information, or a order of instructions 9)If attack be to be conduct the answer might be obtain password for user, their individual in sequence, and more. Once provided that genuine but fake certificate to our user they might capture any in sequence they give, as well as provide for them in sequence. 10)MD5 is quickly being replaced. MD5 is an algorithm to is use to confirm information truth during the making of a 128-bit significance process starting information input that is claim to be as sole to that exact information as fingerprint is to exact creature 11)sure, one time it is busted the course can be duplicate noticeably and no spot or official document might really be trust not including intense, exorbitant analysis. 12)Simple figure screening the MD5 course, and the course of its altered form. 13)extra full explanation of the abbreviation, and vocabulary use. full diagram presentation the course MD5 use and how it might be dishonored. use conditions, and reference in a way to narrate the notion to nontechnical experience 14)Vulnerability in this background can be definite as the diminish capability of an personality oppose and get well starting the contact of a usual or man-made dangerimportant and classify network or system property.conveying relation levels of significance to the capital.identify probable pressure to each supply.increasing a policy to deal with the mainly grave possible troubles first.important.
1)It capture leaving on the purpose of the CA documentation it have.pdf
1)It capture leaving on the purpose of the CA documentation it have.pdf
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1). Na+/K+ ATPase pump plays an important role in maintaining membrane potential. Sodium- potassium ATPase (Na+/K+ ATPase) allows the influx of sodium ions and efflux of potassium ions, which results in increased intracellular positive charge. Increased expression of sodium- potassium ATPase (Na+/K+ ATPase) causes decreased extracellular sodium and increased extracellular potassium levels. 2). Substances move into and out of the cell by means of transport vesicles. Exocytosis is the transport of substances or molecules through transport vesicles that cannot pass through the cell membrane. For example, the neurotransmitters present within the synaptic vesicles are released out by exocytosis. This sac like structure id formed from the layer of cell membrane. The transport of larger molecules or other substances into the cell by means of transport vesicles in known as endocytosis. For example, larger vesicles carry liquid or solid material from outside to the inside of the cell. They are formed from the part of cell membrane; they pinch off to release the molecules into the cell interior. Solution 1). Na+/K+ ATPase pump plays an important role in maintaining membrane potential. Sodium- potassium ATPase (Na+/K+ ATPase) allows the influx of sodium ions and efflux of potassium ions, which results in increased intracellular positive charge. Increased expression of sodium- potassium ATPase (Na+/K+ ATPase) causes decreased extracellular sodium and increased extracellular potassium levels. 2). Substances move into and out of the cell by means of transport vesicles. Exocytosis is the transport of substances or molecules through transport vesicles that cannot pass through the cell membrane. For example, the neurotransmitters present within the synaptic vesicles are released out by exocytosis. This sac like structure id formed from the layer of cell membrane. The transport of larger molecules or other substances into the cell by means of transport vesicles in known as endocytosis. For example, larger vesicles carry liquid or solid material from outside to the inside of the cell. They are formed from the part of cell membrane; they pinch off to release the molecules into the cell interior..
1). Na+K+ ATPase pump plays an important role in maintaining membra.pdf
1). Na+K+ ATPase pump plays an important role in maintaining membra.pdf
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total number of moles of the copund remains same when we dilute moles = molarity * volume intial = final M1* V1= M2* v2 M1=6.3 V1= 27.5 ml M2=1.5 V2= 6.3* 27.5/1.5=115.5 ml is the total volume Solution total number of moles of the copund remains same when we dilute moles = molarity * volume intial = final M1* V1= M2* v2 M1=6.3 V1= 27.5 ml M2=1.5 V2= 6.3* 27.5/1.5=115.5 ml is the total volume.
total number of moles of the copund remains same .pdf
total number of moles of the copund remains same .pdf
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#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include \"header.h\" #include \"chrrecksum.h\" #define BCKLG 10 void sgchrrldHndlr(int s) { while(waitpid(-1, NULL, WNOHANG) > 0); } void *get_in_addr(struct sockaddr *sa) { if (sa->SaFamly == AF_INET) { return &(((struct Sckadr_in*)sa)->sin_addr); } return &(((struct Sckadr_in6*)sa)->sin6_addr); } int main(int arc, chrrar**arv) { int prt = 69; chrrar chrr; while ((chrr = gtOpt(arc, arv, \"p:\")) != -1) { switchrr (chrr) { case \'p\': prt = atoi(optarg); break; case \'?\': exit(1); } } chrrar prt[10]; sprintf(prt,\"%d\",prt); int sockfd, newdv; // listen on sock_fd, new connection on newdv struct addrinfo hints, *servinfo, *p; struct sockaddr_storage their_addr; // connector\'s address information socklen_t sin_size; struct sigaction sa; int yes=1; chrrar s[INET6_ADDRSTRLEN]; int rv; memset(&hints, 0, sizeof hints); hints.ai_family = AF_UNSPEC; hints.ai_socktype = SOCK_STREAM; hints.ai_flags = AI_PASSIVE; if ((rv = getaddrinfo(NULL, prt, &hints, &servinfo)) != 0) { fprintf(stderr, \"getaddrinfo: %s\ \", gai_strerror(rv)); return 1; } for(p = servinfo; p != NULL; p = p->ai_next) { if ((sockfd = socket(p->ai_family, p->ai_socktype, p->ai_protocol)) == -1) { perror(\"server: socket\"); continue; } if (setsockopt(sockfd, SOL_SOCKET, SO_REUSEADDR, &yes, sizeof(int)) == -1) { perror(\"setsockopt\"); exit(1); } if (bind(sockfd, p->ai_addr, p->ai_addrlen) == -1) { close(sockfd); perror(\"server: bind\"); continue; } break; } if (p == NULL) { fprintf(stderr, \"server: failed to bind\ \"); return 2; } freeaddrinfo(servinfo); if (listen(sockfd, BCKLG) == -1) { perror(\"listen\"); exit(1); } sa.sa_handler = sgchrrldHndlr; sigemptyset(&sa.sa_mask); sa.sa_flags = SA_RESTART; if (sigaction(SIGchrrLD, &sa, NULL) == -1) { perror(\"sigaction\"); exit(1); } printf(\"server: looking for connections...\ \"); while(1) { accept() loop sin_size = sizeof their_addr; newdv = accept(sockfd, (struct sockaddr *)&their_addr, &sin_size); if (newdv == -1) { perror(\"accept\"); continue; } inet_ntop(their_addr.ss_family, get_in_addr((struct sockaddr *)&their_addr), s, sizeof s); printf(\"server: got connection from %s\ \", s); if (!fork()) { close(sockfd); chrrar buf[PACKET_SIZE]; chrrar databuf[PAYLOAD_SIZE]; int numbytes, ack_bytes; header_t head; packet_t packet; packet_t ackr; int getfilename = 1; chrrar *filename = (chrrar*) \"recvfile.txt\"; FILE * filefd; bzero(buf, PACKET_SIZE); bzero(databuf, PAYLOAD_SIZE); while(getfilename) { if ((numbytes = recv(newdv, buf, PACKET_SIZE, 0)) == -1) { perror(\"recv\"); exit(1); } if(numbytes > 0) { read_header(&head, (packet_t *)buf); read_packet((u_chrrar*) databuf, (packet_t *)buf, (u_short) (numbytes - HEADER_SIZE)); printf(\"Packet \'%d\' received\ \", (int)(head.seq)); if(add_chrrecksum(numbytes, numbytes%2, (u_short *)buf) == 0) { printf(\"chrrecksum OK\ \"); fill_hdr((int)(head.seq).
#include stdio.h #include stdlib.h #include unistd.h #in.pdf
#include stdio.h #include stdlib.h #include unistd.h #in.pdf
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18O is an important precursor for the production offlourodeoxyglucose(FDG) used in PETscans./ PET scans are atechnique which produces a three-dimensional image or picture offunctional processes in the body. In Paleoclimatology they are usedto find out what temperature of earths climate was in the past bycomparing the ratio of oxygen 18 to oxygen 16. Solution 18O is an important precursor for the production offlourodeoxyglucose(FDG) used in PETscans./ PET scans are atechnique which produces a three-dimensional image or picture offunctional processes in the body. In Paleoclimatology they are usedto find out what temperature of earths climate was in the past bycomparing the ratio of oxygen 18 to oxygen 16..
18O is an important precursor for the production offlourodeoxyglucose.pdf
18O is an important precursor for the production offlourodeoxyglucose.pdf
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observed expected O - E (O - E) Solution observed expected O - E (O - E).
observed expected O - E (O - E) Solution observed expect.pdf
observed expected O - E (O - E) Solution observed expect.pdf
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no hydrogen atom is present because its pure carbon compound Solution no hydrogen atom is present because its pure carbon compound.
no hydrogen atom is present because its pure carb.pdf
no hydrogen atom is present because its pure carb.pdf
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Mg and NaH react with water to give H2. Mg + 2H2O ---> Mg(OH)2 + H2 NaH + H2O ---> NaOH + H2 Solution Mg and NaH react with water to give H2. Mg + 2H2O ---> Mg(OH)2 + H2 NaH + H2O ---> NaOH + H2.
Mg and NaH react with water to give H2. Mg + 2H2.pdf
Mg and NaH react with water to give H2. Mg + 2H2.pdf
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in case of A and D there will be resonance between N-O and O-O . so these are week base. and compared to OH NH2 will be strong base, also C is a alcohol and thus it has more tendancy to release H+ and not to donate its lone pair. HEnce B is the correct answer. ALSO its primary amine. so it has more tendancy to donate so answer is B Solution in case of A and D there will be resonance between N-O and O-O . so these are week base. and compared to OH NH2 will be strong base, also C is a alcohol and thus it has more tendancy to release H+ and not to donate its lone pair. HEnce B is the correct answer. ALSO its primary amine. so it has more tendancy to donate so answer is B.
in case of A and D there will be resonance betwee.pdf
in case of A and D there will be resonance betwee.pdf
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For half life to be independent of Concentration is when n - 1 = 0, that is first order reaction. t(1/2) = 0.693/K NOOOO you can not apply this expression for it because when you have integrated the expression how concentration of A varies with t, then we had a condition that n is not equal to 1. and thus you can not apply this expression.!!! HAVE FUN!! Solution For half life to be independent of Concentration is when n - 1 = 0, that is first order reaction. t(1/2) = 0.693/K NOOOO you can not apply this expression for it because when you have integrated the expression how concentration of A varies with t, then we had a condition that n is not equal to 1. and thus you can not apply this expression.!!! HAVE FUN!!.
For half life to be independent of Concentration .pdf
For half life to be independent of Concentration .pdf
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Mode because mode gives the number which occurs maximum number of time it doesnot give the location of any distribution Solution Mode because mode gives the number which occurs maximum number of time it doesnot give the location of any distribution.
Mode because mode gives the number which occurs maximum number of .pdf
Mode because mode gives the number which occurs maximum number of .pdf
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public class RectangleDemo { private class Rectangle { private double height; private double width; private String color; public Rectangle(double wid, double high){ height = high; width = wid; } public Rectangle(){ height = 1; width = 1; color = \"White\"; } public void setHeight(double high){ height = high; } public void setWidth(double wid){ width = wid; } public void setColor(String col){ color = col; } public double getArea(){ return height*width; } public double getPerimeter(){ return 2*(height + width); } public void getColor(){ System.out.println(\"Color is: \" + color +\"\ \"); return; } } Solution public class RectangleDemo { private class Rectangle { private double height; private double width; private String color; public Rectangle(double wid, double high){ height = high; width = wid; } public Rectangle(){ height = 1; width = 1; color = \"White\"; } public void setHeight(double high){ height = high; } public void setWidth(double wid){ width = wid; } public void setColor(String col){ color = col; } public double getArea(){ return height*width; } public double getPerimeter(){ return 2*(height + width); } public void getColor(){ System.out.println(\"Color is: \" + color +\"\ \"); return; } }.
public class RectangleDemo { private class Rectangle { .pdf
public class RectangleDemo { private class Rectangle { .pdf
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Total assets=Total liabilities+Total equity Hence Total assets=(7970+1920)=$9890 Total assets=Long term assets+Current assets Current assets=(9890-6036)=$3854(million). Solution Total assets=Total liabilities+Total equity Hence Total assets=(7970+1920)=$9890 Total assets=Long term assets+Current assets Current assets=(9890-6036)=$3854(million)..
Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
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The products would be sodium chloride, water and carbon dioxide, and the equation is NaHCO3(s) + HCl(aq)=> NaCl(aq) +H2O(l) +CO2(g). Solution The products would be sodium chloride, water and carbon dioxide, and the equation is NaHCO3(s) + HCl(aq)=> NaCl(aq) +H2O(l) +CO2(g)..
The products would be sodium chloride, water and carbon dioxide, and.pdf
The products would be sodium chloride, water and carbon dioxide, and.pdf
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The answer is c. SrCO3 Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the CO32- ions %Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50% Solution The answer is c. SrCO3 Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the CO32- ions %Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50%.
The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf
The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf
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Technologies would you use to assist in migration Solution Technologies would you use to assist in migration.
Technologies would you use to assist in migrationSolutionTechn.pdf
Technologies would you use to assist in migrationSolutionTechn.pdf
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As Solution As.
AsSolution As.pdf
AsSolution As.pdf
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Role of biotechnology in bioterrorism: Biotechnology can be employed by terrorist groups to produce microorganisms that are capable of large scale morbidity and mortality resulting in bioterrorism. Techniques used for the development of pathogens and toxins as weapons include different branches of biotechnology like genetic engineering, protein engineering, functional genomics and artificial viruses. Following are the essential characteristics of microorganisms which are used as weapons Techniques used in bioterrorism try to enhance these characteristics (above) of microorganisms. Solution Role of biotechnology in bioterrorism: Biotechnology can be employed by terrorist groups to produce microorganisms that are capable of large scale morbidity and mortality resulting in bioterrorism. Techniques used for the development of pathogens and toxins as weapons include different branches of biotechnology like genetic engineering, protein engineering, functional genomics and artificial viruses. Following are the essential characteristics of microorganisms which are used as weapons Techniques used in bioterrorism try to enhance these characteristics (above) of microorganisms..
Role of biotechnology in bioterrorismBiotechnology can be employe.pdf
Role of biotechnology in bioterrorismBiotechnology can be employe.pdf
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pure water dissociates with a reversible reaction forming H+ and OH- now this H+ gets H-Bonded to H2O to form H3O+ Now a base is added to pure water the concentration of OH- increases by common ion effect and Le-Chatelier\'s principle the reverse reaction is favored and H+ and OH- are converted back to H2O thereby decreasing the net H+ conc. As H+ conc decreases H3O+ decreases. Solution pure water dissociates with a reversible reaction forming H+ and OH- now this H+ gets H-Bonded to H2O to form H3O+ Now a base is added to pure water the concentration of OH- increases by common ion effect and Le-Chatelier\'s principle the reverse reaction is favored and H+ and OH- are converted back to H2O thereby decreasing the net H+ conc. As H+ conc decreases H3O+ decreases..
pure water dissociates with a reversible reaction forming H+ and OH-.pdf
pure water dissociates with a reversible reaction forming H+ and OH-.pdf
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Polymers are constructed from relatively small molecular fragments known as monomers that are joined together. Chemistry: Properties: Applications: Physical properties of polymers The physical properties of a polymer such as its strength and flexibility depend on: Other substances ( besides monomers ) are often needed for polymerisation to occur, for instance initiators, catalysts, and depending on manufacturing process, solvents may also be used. The resulting plastic polymer can be blended with different additives, for instance plasticisers, flame retardants, heat stabilisers, antioxidants, light stabilisers, lubricants, acid scavengers, antimicrobial agents, anti-static agents, pigments, blowing agents and fillers, and is finally processed into a plastic product. There are many different plastic polymers and several thousand different additives, which results in an extremely large variation in chemical composition of plastic products ( Rosato, 1998 ). Inthe polymeric material, however, non-polymeric components such as residual monomers, oligomers, low molecular weight fragments, catalyst remnants, polymerisation solvents and a wide range of additives can be present ( Crompton, 2007 ). Several of these are hazardous to human health and the environment, for instance carcinogenic, mutagenic, toxic for reproduction, sensitising and hazardous to the aquatic environment with long lasting effects. Since the non- polymeric compounds usually are of low molecular weight and are either weakly bound or not bound at all to the polymeric macro-molecules, they, or their degradation products, can be emitted from the plastic product (Crompton, 2007; OECD, 2004) to air, water or other contact media (e.g. food). Many additives are hazardous for human health and the environment. Some are especially hazardous, for instance brominated flame retardants used to retard ignition and prevent fire from spreading; some phthalate plasticizers mainly used to make PVC flexible; and lead heat stabilizers used to prevent degradation of PVC during processing ( Murphy, 2001 ). Several polybrominated flame retardants are very persistent, very bioaccumulating and toxic, and are listed in the Stockholm Convention on Persistent Organic Pollutants (POPs) (Secretary - general UN, 2009). Among the phthalate plasticisers the most hazardous ones, i.e. BBP, DEHP and DBP, are classified as toxic for reproduction (category 1B). BBP is also very toxic to aquatic organisms with long lasting effects ( European Parliament and Council, 2008; European Commission, 2009 ). In addition, these phthalates, as well as DEP ( diethylphthtalate ) and DCHP ( dicyclohexyl phthalate ), are being evaluated for endocrine disrupting properties ( Groshart and Okkerman, 2000; Okkerman and vander Putte, 2002 ). The lead compounds used in heat stabilizers are classified as toxic for reproduction (category 1A), very toxic to the aquatic environment with long lasting effects (both acute and chronic), and may caus.
Polymers are constructed from relatively small molecular fragments k.pdf
Polymers are constructed from relatively small molecular fragments k.pdf
contact34
One of 2 principles of genetic heredity first formulated by Gregor Mendel, elucidated on his genetic experiments with pea plants. He finally described that the homologous chromosomes segregate during meiosis and are distributed to different gametes, thereby the offspring acquires one chromosome from each parent. The chromosomal segregation occurs during anaphase -II of meiosis. The segregated chromosomes reunite randomly during the fertilization process. Solution One of 2 principles of genetic heredity first formulated by Gregor Mendel, elucidated on his genetic experiments with pea plants. He finally described that the homologous chromosomes segregate during meiosis and are distributed to different gametes, thereby the offspring acquires one chromosome from each parent. The chromosomal segregation occurs during anaphase -II of meiosis. The segregated chromosomes reunite randomly during the fertilization process..
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
contact34
Maturity-risk premium = 5.2% - (1.4% + 1.1%) Maturity-risk premium = 2.7% The maturity-risk premium for this 2-year Treasury note is 2.7% Solution Maturity-risk premium = 5.2% - (1.4% + 1.1%) Maturity-risk premium = 2.7% The maturity-risk premium for this 2-year Treasury note is 2.7%.
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
contact34
Intrinsic muscles of the eye are responsible for accommodation. During accommodation, we can observe three adjustments in the eye balls. Convergence is the medial movement of eyeballs and is an important step in accommodation of eye to focus on any object. This convergence reflex is helpful for focussing the eyes on a near object (near vision) present, and helps to observe the nearby surroundings clearly (binocular vision). Over convergence and under convergence causes visual problems. Solution Intrinsic muscles of the eye are responsible for accommodation. During accommodation, we can observe three adjustments in the eye balls. Convergence is the medial movement of eyeballs and is an important step in accommodation of eye to focus on any object. This convergence reflex is helpful for focussing the eyes on a near object (near vision) present, and helps to observe the nearby surroundings clearly (binocular vision). Over convergence and under convergence causes visual problems..
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
contact34
it is a right that comes under property. - the right saves each and every individual people in the world from doing harm to others by their name or sometimes use the others for non legal purpose. - save preserves even after the peoples death and finally that shall be given to their heirs or sold. with the advancements in the science and technology in this digital age all the information can be stored in a computers and can be used in their future.but the problem with this is due to the cyber crime . when we use social media for investigation there may lead to advantages and disadvantages situations because sometimes the provided information may be truth or it may be fake that has to be deeply invested carefully to protect the right people from the criminal cases. Solution it is a right that comes under property. - the right saves each and every individual people in the world from doing harm to others by their name or sometimes use the others for non legal purpose. - save preserves even after the peoples death and finally that shall be given to their heirs or sold. with the advancements in the science and technology in this digital age all the information can be stored in a computers and can be used in their future.but the problem with this is due to the cyber crime . when we use social media for investigation there may lead to advantages and disadvantages situations because sometimes the provided information may be truth or it may be fake that has to be deeply invested carefully to protect the right people from the criminal cases..
it is a right that comes under property. - the right saves each an.pdf
it is a right that comes under property. - the right saves each an.pdf
contact34
I think that cos(2x) Solution I think that cos(2x).
I think that cos(2x)SolutionI think that cos(2x).pdf
I think that cos(2x)SolutionI think that cos(2x).pdf
contact34
God knows. Solution God knows..
God knows.SolutionGod knows..pdf
God knows.SolutionGod knows..pdf
contact34
A bond is ionic if it contains a metal (Group I, II, and the transition metals, some in Group 3, some in Group 4) and a nonmetal. A bond is polar covalent if it contains two different nonmetals (H, some in Group 3, some in Group 4, Group 5, Group 6, Group 7). A bond is covalent if it contains two similar nonmetals (for example, C-C, N-N). Actually, a covalent bond is defined as a bond where both molecules have similar electronegativities. It is very seldom (although in rare cases, it does happen) that two different nonmetals have similar electronegativities, so as a general rule two different nonmetals are usually polar covalent. If you want to know what the rare cases are, you might want to consult a table that lists all the electronegativities (found in some chemistry textbooks). Solution A bond is ionic if it contains a metal (Group I, II, and the transition metals, some in Group 3, some in Group 4) and a nonmetal. A bond is polar covalent if it contains two different nonmetals (H, some in Group 3, some in Group 4, Group 5, Group 6, Group 7). A bond is covalent if it contains two similar nonmetals (for example, C-C, N-N). Actually, a covalent bond is defined as a bond where both molecules have similar electronegativities. It is very seldom (although in rare cases, it does happen) that two different nonmetals have similar electronegativities, so as a general rule two different nonmetals are usually polar covalent. If you want to know what the rare cases are, you might want to consult a table that lists all the electronegativities (found in some chemistry textbooks)..
A bond is ionic if it contains a metal (Group I, .pdf
A bond is ionic if it contains a metal (Group I, .pdf
contact34
This presentation was provided by William Mattingly of the Smithsonian Institution, during the closing segment of the NISO training series "AI & Prompt Design." Session Eight: Limitations and Potential Solutions, was held on May 23, 2024.
Mattingly "AI & Prompt Design: Limitations and Solutions with LLMs"
Mattingly "AI & Prompt Design: Limitations and Solutions with LLMs"
National Information Standards Organization (NISO)
Clear articulation of the 21st century skills in the Matatag curriculum
Matatag-Curriculum and the 21st Century Skills Presentation.pptx
Matatag-Curriculum and the 21st Century Skills Presentation.pptx
JenilouCasareno
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Mg and NaH react with water to give H2. Mg + 2H2O ---> Mg(OH)2 + H2 NaH + H2O ---> NaOH + H2 Solution Mg and NaH react with water to give H2. Mg + 2H2O ---> Mg(OH)2 + H2 NaH + H2O ---> NaOH + H2.
Mg and NaH react with water to give H2. Mg + 2H2.pdf
Mg and NaH react with water to give H2. Mg + 2H2.pdf
contact34
in case of A and D there will be resonance between N-O and O-O . so these are week base. and compared to OH NH2 will be strong base, also C is a alcohol and thus it has more tendancy to release H+ and not to donate its lone pair. HEnce B is the correct answer. ALSO its primary amine. so it has more tendancy to donate so answer is B Solution in case of A and D there will be resonance between N-O and O-O . so these are week base. and compared to OH NH2 will be strong base, also C is a alcohol and thus it has more tendancy to release H+ and not to donate its lone pair. HEnce B is the correct answer. ALSO its primary amine. so it has more tendancy to donate so answer is B.
in case of A and D there will be resonance betwee.pdf
in case of A and D there will be resonance betwee.pdf
contact34
For half life to be independent of Concentration is when n - 1 = 0, that is first order reaction. t(1/2) = 0.693/K NOOOO you can not apply this expression for it because when you have integrated the expression how concentration of A varies with t, then we had a condition that n is not equal to 1. and thus you can not apply this expression.!!! HAVE FUN!! Solution For half life to be independent of Concentration is when n - 1 = 0, that is first order reaction. t(1/2) = 0.693/K NOOOO you can not apply this expression for it because when you have integrated the expression how concentration of A varies with t, then we had a condition that n is not equal to 1. and thus you can not apply this expression.!!! HAVE FUN!!.
For half life to be independent of Concentration .pdf
For half life to be independent of Concentration .pdf
contact34
Mode because mode gives the number which occurs maximum number of time it doesnot give the location of any distribution Solution Mode because mode gives the number which occurs maximum number of time it doesnot give the location of any distribution.
Mode because mode gives the number which occurs maximum number of .pdf
Mode because mode gives the number which occurs maximum number of .pdf
contact34
public class RectangleDemo { private class Rectangle { private double height; private double width; private String color; public Rectangle(double wid, double high){ height = high; width = wid; } public Rectangle(){ height = 1; width = 1; color = \"White\"; } public void setHeight(double high){ height = high; } public void setWidth(double wid){ width = wid; } public void setColor(String col){ color = col; } public double getArea(){ return height*width; } public double getPerimeter(){ return 2*(height + width); } public void getColor(){ System.out.println(\"Color is: \" + color +\"\ \"); return; } } Solution public class RectangleDemo { private class Rectangle { private double height; private double width; private String color; public Rectangle(double wid, double high){ height = high; width = wid; } public Rectangle(){ height = 1; width = 1; color = \"White\"; } public void setHeight(double high){ height = high; } public void setWidth(double wid){ width = wid; } public void setColor(String col){ color = col; } public double getArea(){ return height*width; } public double getPerimeter(){ return 2*(height + width); } public void getColor(){ System.out.println(\"Color is: \" + color +\"\ \"); return; } }.
public class RectangleDemo { private class Rectangle { .pdf
public class RectangleDemo { private class Rectangle { .pdf
contact34
Total assets=Total liabilities+Total equity Hence Total assets=(7970+1920)=$9890 Total assets=Long term assets+Current assets Current assets=(9890-6036)=$3854(million). Solution Total assets=Total liabilities+Total equity Hence Total assets=(7970+1920)=$9890 Total assets=Long term assets+Current assets Current assets=(9890-6036)=$3854(million)..
Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
contact34
The products would be sodium chloride, water and carbon dioxide, and the equation is NaHCO3(s) + HCl(aq)=> NaCl(aq) +H2O(l) +CO2(g). Solution The products would be sodium chloride, water and carbon dioxide, and the equation is NaHCO3(s) + HCl(aq)=> NaCl(aq) +H2O(l) +CO2(g)..
The products would be sodium chloride, water and carbon dioxide, and.pdf
The products would be sodium chloride, water and carbon dioxide, and.pdf
contact34
The answer is c. SrCO3 Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the CO32- ions %Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50% Solution The answer is c. SrCO3 Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the CO32- ions %Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50%.
The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf
The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf
contact34
Technologies would you use to assist in migration Solution Technologies would you use to assist in migration.
Technologies would you use to assist in migrationSolutionTechn.pdf
Technologies would you use to assist in migrationSolutionTechn.pdf
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As Solution As.
AsSolution As.pdf
AsSolution As.pdf
contact34
Role of biotechnology in bioterrorism: Biotechnology can be employed by terrorist groups to produce microorganisms that are capable of large scale morbidity and mortality resulting in bioterrorism. Techniques used for the development of pathogens and toxins as weapons include different branches of biotechnology like genetic engineering, protein engineering, functional genomics and artificial viruses. Following are the essential characteristics of microorganisms which are used as weapons Techniques used in bioterrorism try to enhance these characteristics (above) of microorganisms. Solution Role of biotechnology in bioterrorism: Biotechnology can be employed by terrorist groups to produce microorganisms that are capable of large scale morbidity and mortality resulting in bioterrorism. Techniques used for the development of pathogens and toxins as weapons include different branches of biotechnology like genetic engineering, protein engineering, functional genomics and artificial viruses. Following are the essential characteristics of microorganisms which are used as weapons Techniques used in bioterrorism try to enhance these characteristics (above) of microorganisms..
Role of biotechnology in bioterrorismBiotechnology can be employe.pdf
Role of biotechnology in bioterrorismBiotechnology can be employe.pdf
contact34
pure water dissociates with a reversible reaction forming H+ and OH- now this H+ gets H-Bonded to H2O to form H3O+ Now a base is added to pure water the concentration of OH- increases by common ion effect and Le-Chatelier\'s principle the reverse reaction is favored and H+ and OH- are converted back to H2O thereby decreasing the net H+ conc. As H+ conc decreases H3O+ decreases. Solution pure water dissociates with a reversible reaction forming H+ and OH- now this H+ gets H-Bonded to H2O to form H3O+ Now a base is added to pure water the concentration of OH- increases by common ion effect and Le-Chatelier\'s principle the reverse reaction is favored and H+ and OH- are converted back to H2O thereby decreasing the net H+ conc. As H+ conc decreases H3O+ decreases..
pure water dissociates with a reversible reaction forming H+ and OH-.pdf
pure water dissociates with a reversible reaction forming H+ and OH-.pdf
contact34
Polymers are constructed from relatively small molecular fragments known as monomers that are joined together. Chemistry: Properties: Applications: Physical properties of polymers The physical properties of a polymer such as its strength and flexibility depend on: Other substances ( besides monomers ) are often needed for polymerisation to occur, for instance initiators, catalysts, and depending on manufacturing process, solvents may also be used. The resulting plastic polymer can be blended with different additives, for instance plasticisers, flame retardants, heat stabilisers, antioxidants, light stabilisers, lubricants, acid scavengers, antimicrobial agents, anti-static agents, pigments, blowing agents and fillers, and is finally processed into a plastic product. There are many different plastic polymers and several thousand different additives, which results in an extremely large variation in chemical composition of plastic products ( Rosato, 1998 ). Inthe polymeric material, however, non-polymeric components such as residual monomers, oligomers, low molecular weight fragments, catalyst remnants, polymerisation solvents and a wide range of additives can be present ( Crompton, 2007 ). Several of these are hazardous to human health and the environment, for instance carcinogenic, mutagenic, toxic for reproduction, sensitising and hazardous to the aquatic environment with long lasting effects. Since the non- polymeric compounds usually are of low molecular weight and are either weakly bound or not bound at all to the polymeric macro-molecules, they, or their degradation products, can be emitted from the plastic product (Crompton, 2007; OECD, 2004) to air, water or other contact media (e.g. food). Many additives are hazardous for human health and the environment. Some are especially hazardous, for instance brominated flame retardants used to retard ignition and prevent fire from spreading; some phthalate plasticizers mainly used to make PVC flexible; and lead heat stabilizers used to prevent degradation of PVC during processing ( Murphy, 2001 ). Several polybrominated flame retardants are very persistent, very bioaccumulating and toxic, and are listed in the Stockholm Convention on Persistent Organic Pollutants (POPs) (Secretary - general UN, 2009). Among the phthalate plasticisers the most hazardous ones, i.e. BBP, DEHP and DBP, are classified as toxic for reproduction (category 1B). BBP is also very toxic to aquatic organisms with long lasting effects ( European Parliament and Council, 2008; European Commission, 2009 ). In addition, these phthalates, as well as DEP ( diethylphthtalate ) and DCHP ( dicyclohexyl phthalate ), are being evaluated for endocrine disrupting properties ( Groshart and Okkerman, 2000; Okkerman and vander Putte, 2002 ). The lead compounds used in heat stabilizers are classified as toxic for reproduction (category 1A), very toxic to the aquatic environment with long lasting effects (both acute and chronic), and may caus.
Polymers are constructed from relatively small molecular fragments k.pdf
Polymers are constructed from relatively small molecular fragments k.pdf
contact34
One of 2 principles of genetic heredity first formulated by Gregor Mendel, elucidated on his genetic experiments with pea plants. He finally described that the homologous chromosomes segregate during meiosis and are distributed to different gametes, thereby the offspring acquires one chromosome from each parent. The chromosomal segregation occurs during anaphase -II of meiosis. The segregated chromosomes reunite randomly during the fertilization process. Solution One of 2 principles of genetic heredity first formulated by Gregor Mendel, elucidated on his genetic experiments with pea plants. He finally described that the homologous chromosomes segregate during meiosis and are distributed to different gametes, thereby the offspring acquires one chromosome from each parent. The chromosomal segregation occurs during anaphase -II of meiosis. The segregated chromosomes reunite randomly during the fertilization process..
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
contact34
Maturity-risk premium = 5.2% - (1.4% + 1.1%) Maturity-risk premium = 2.7% The maturity-risk premium for this 2-year Treasury note is 2.7% Solution Maturity-risk premium = 5.2% - (1.4% + 1.1%) Maturity-risk premium = 2.7% The maturity-risk premium for this 2-year Treasury note is 2.7%.
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
contact34
Intrinsic muscles of the eye are responsible for accommodation. During accommodation, we can observe three adjustments in the eye balls. Convergence is the medial movement of eyeballs and is an important step in accommodation of eye to focus on any object. This convergence reflex is helpful for focussing the eyes on a near object (near vision) present, and helps to observe the nearby surroundings clearly (binocular vision). Over convergence and under convergence causes visual problems. Solution Intrinsic muscles of the eye are responsible for accommodation. During accommodation, we can observe three adjustments in the eye balls. Convergence is the medial movement of eyeballs and is an important step in accommodation of eye to focus on any object. This convergence reflex is helpful for focussing the eyes on a near object (near vision) present, and helps to observe the nearby surroundings clearly (binocular vision). Over convergence and under convergence causes visual problems..
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
contact34
it is a right that comes under property. - the right saves each and every individual people in the world from doing harm to others by their name or sometimes use the others for non legal purpose. - save preserves even after the peoples death and finally that shall be given to their heirs or sold. with the advancements in the science and technology in this digital age all the information can be stored in a computers and can be used in their future.but the problem with this is due to the cyber crime . when we use social media for investigation there may lead to advantages and disadvantages situations because sometimes the provided information may be truth or it may be fake that has to be deeply invested carefully to protect the right people from the criminal cases. Solution it is a right that comes under property. - the right saves each and every individual people in the world from doing harm to others by their name or sometimes use the others for non legal purpose. - save preserves even after the peoples death and finally that shall be given to their heirs or sold. with the advancements in the science and technology in this digital age all the information can be stored in a computers and can be used in their future.but the problem with this is due to the cyber crime . when we use social media for investigation there may lead to advantages and disadvantages situations because sometimes the provided information may be truth or it may be fake that has to be deeply invested carefully to protect the right people from the criminal cases..
it is a right that comes under property. - the right saves each an.pdf
it is a right that comes under property. - the right saves each an.pdf
contact34
I think that cos(2x) Solution I think that cos(2x).
I think that cos(2x)SolutionI think that cos(2x).pdf
I think that cos(2x)SolutionI think that cos(2x).pdf
contact34
God knows. Solution God knows..
God knows.SolutionGod knows..pdf
God knows.SolutionGod knows..pdf
contact34
A bond is ionic if it contains a metal (Group I, II, and the transition metals, some in Group 3, some in Group 4) and a nonmetal. A bond is polar covalent if it contains two different nonmetals (H, some in Group 3, some in Group 4, Group 5, Group 6, Group 7). A bond is covalent if it contains two similar nonmetals (for example, C-C, N-N). Actually, a covalent bond is defined as a bond where both molecules have similar electronegativities. It is very seldom (although in rare cases, it does happen) that two different nonmetals have similar electronegativities, so as a general rule two different nonmetals are usually polar covalent. If you want to know what the rare cases are, you might want to consult a table that lists all the electronegativities (found in some chemistry textbooks). Solution A bond is ionic if it contains a metal (Group I, II, and the transition metals, some in Group 3, some in Group 4) and a nonmetal. A bond is polar covalent if it contains two different nonmetals (H, some in Group 3, some in Group 4, Group 5, Group 6, Group 7). A bond is covalent if it contains two similar nonmetals (for example, C-C, N-N). Actually, a covalent bond is defined as a bond where both molecules have similar electronegativities. It is very seldom (although in rare cases, it does happen) that two different nonmetals have similar electronegativities, so as a general rule two different nonmetals are usually polar covalent. If you want to know what the rare cases are, you might want to consult a table that lists all the electronegativities (found in some chemistry textbooks)..
A bond is ionic if it contains a metal (Group I, .pdf
A bond is ionic if it contains a metal (Group I, .pdf
contact34
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in case of A and D there will be resonance betwee.pdf
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For half life to be independent of Concentration .pdf
Mode because mode gives the number which occurs maximum number of .pdf
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Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
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The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf
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AsSolution As.pdf
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pure water dissociates with a reversible reaction forming H+ and OH-.pdf
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Polymers are constructed from relatively small molecular fragments k.pdf
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
it is a right that comes under property. - the right saves each an.pdf
it is a right that comes under property. - the right saves each an.pdf
I think that cos(2x)SolutionI think that cos(2x).pdf
I think that cos(2x)SolutionI think that cos(2x).pdf
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2024_Student Session 2_ Set Plan Preparation.pptx
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This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
Instructions for Submissions thorugh G- Classroom.pptx
Instructions for Submissions thorugh G- Classroom.pptx
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